What id the volume if a gas if I have 0.215 moles if gas at a temperature of 75 K and a pressure if 182.34KPa?

Density = mass/volume

Since there was no condition of unit attached to the question...

Density = 100g/25.0ml

Density = 4g/mL.......

Hydrogen fusion is the answer. It is also known as hydrogen burning. 

Answer:

39.98 liters

Explanation:

The first you should know:  At STP , 1 mole of any  gas takes up 22.4 Liters of volume.

After, you will find the molecular weight (MW) of N2 with help of a periodic table.

Then N= 14,007 g      

So:  

N2 = 14,007 * 2      

MW =28,014 g/ mol N2  

Now you will start with the data of 50 grams of N2 and you obtain:    

50 g N2  x 1 mol N2    x  22.4 L N2      =  39.98 L at STP                                 28,014 g N2        1 mol N2      

50 g of nitrogen, N₂ has a volume of 40 L at standard temperature and pressure (stp)

We'll begin by calculating the number of mole in 50 g of N₂. This can be obtained as follow:

Mass of N₂ = 50 g

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mole of N₂ =?

Mole = mass / molar mass

Mole of N₂ = 50 / 28

Mole of N₂ = 1.786 mole

Finally, we shall obtain the volume occupied by 1.786 mole of N₂ at STP. This can be obtained as follow:

At standard temperature and pressure (STP)

1 mole of N₂ = 22.4 L

Therefore,

1.786 mole of N₂ = 1.786 × 22.4

1.786 mole of N₂ = 40 L

Therefore, 50 g of N₂ occupies 40 L at standard temperature and pressure (STP).

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The frequency of a wave represents the number of wave cycles that pass through a specific point within a given time period.

its actually answer 2

I think it is one-half meter in front of the source because this is the nearest distance of the source and thus the sensor will register a higher concentration. 
At the nearest point the sensor will be able sense the high concentrations of the mercaptan which are nasty smelling sulfur compounds that are added to the natural gas piped to our houses.

Chemical reaction: 2PCl₃ + O₂ → 2POCl₃.
m(PCl₃) = 194 g.
n(PCl₃) = m(PCl₃) ÷ M(PCl₃).
n(PCl₃) = 194 g ÷ 137,33 g/mol.
n(PCl₃) = 1,412 mol.
From chemical reaction: n(PCl₃) : n(POCl₃) = 1 : 1.
n(POCl₃) = 1,412 mol.
V(POCl₃) = n(POCl₃) · Vm.
V(POCl₃) = 1,412 mol · 22,4 mol/dm³.
V(POCl₃) = 31,64 dm³ at normal pressure and temperature.

Answer:

V = 2.28 L

Explanation:

What volume of pocl3 gas can be produced in theory when 194 g of pcl3 gas reacts with excess oxygen? at STP

1. Determine moles PCl3.

The reaction

2PCl3+O2--------->PClO3

mole =mass/molecular mass

194 grams/137.3334 grams/mole  =

0.102 moles PCl3

2. Get the moles of POCl3 produced from 0.102 moles PCl3.

from the reaction above

2 moles PCl3 produce 2 moles POCl3

PClO3=0.102mole

3. Find the  volume PClO3 using ideal-gas equation: PV = nRT

where:

P = pressure = 1 atm (standard pressure)

V = volume ?

n = moles PClO3 = 0.102 moles PClO3

R = gas constant = 0.08206 L*atm/mol*K

T = temperature = 273.15 K (standard temperature)

(1 atm)*V = (0.102 moles)*(0.08206 L*atm/mol*K)*(273.15 K)

V = 2.28 L

From the equation for molarity (number of moles of a substance dissolved in one liter of solution), we can get an equation for determining the number of moles:

c=n/V   ⇒   n=c×V

Now, we can write required equations:

A   n(NaOH)=c(NaOH)×V(NaOH)

B    n(H₂SO₄)=c(H₂SO₄)×V(H₂SO₄) 

From the reaction, we can conclude that NaOH and H₂SO₄ have following stoichiometric ratio:

2NaOH + H₂SO₄ ⇒ Na₂SO₄ + 2H₂0

n(NaOH) : n(H₂SO₄) = 2 : 1

So, we can write:

n(NaOH) = 2 × n(H₂SO₄)

And if we connect the above equations, we get the equation for solving c(H2SO4):

c(NaOH)×V(NaOH) = 2×c(H₂SO₄)×V(H₂SO₄)

c(H₂SO₄) = (c(NaOH)×V(NaOH)) / (2×V(H₂SO₄))

The concentration of [H2SO4] is obtained from; [NaOH] × VNaOH/ 2× VH2SO4

The equation of the reaction is;

2NaOH(aq) + H2SO4(aq) ------>  Na2SO4(aq) + 2H2O(l)

Number of moles of H2SO4(nH2SO4) = [H2SO4] × VH2SO4

Number of moles of NaOH(nNaOH) = [NaOH] × VNaOH

Where;

[H2SO4] = concentration of H2SO4

VH2SO4 = volume of H2SO4

[NaOH]  = concentration of NaOH

VNaOH = volume of NaOH

From the balanced reaction equation;

2 moles of NaOH reacts with 1 mole of H2SO4

2nH2SO4 = nNaOH

2[H2SO4] × VH2SO4 =  [NaOH] × VNaOH

[H2SO4] =   [NaOH] × VNaOH/ 2× VH2SO4

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Ans-A
In CaF2, the oxidation number of Ca is +2,& that of F is -1.

Ans-B
In H2SO4, the oxidation number of H is +1, that of S is +6,& that of O is -2.

Ans-C
In CaSO4, the oxidation number of Ca is +2, that of S is +6,& that of O is -2.

Ans-D
In HF, the oxidation number of H is +1,& that of F is -1.

Explanation:
Oxidation number is a number that is assigned to an element in a compound, which shows the number of electrons gained or lost by an atom.

Rules:
1. If the element is ALONE in the chemical equation, and it is NOT an ION, its oxidation number will ALWAYS be zero.

2. When there is an ION in the equation, its oxidation number will ALWAYS be its ionic number.

A(2 parts):
The oxidation number of Ca & F?

In what group Ca lies? Well in group 2 in the periodic table.
Is it alone? No, it is not. It's with Florine F.
Is it multiple of itself? No.

The second element is Florine(F).
In what group F lies? Well in group 17(in halogens) in the periodic table.
Is it multiple of itself? Yes. There are 2 Florine atoms.

Is there any net charge on the compound? No.

Blank 2: The oxidation number of F2 = 2 * (-1) = -2. Since the oxidation number of the single atom F is -1 for the halogens(group-17 members). In this compound there are 2 Florine atoms, therefore it should be -2. Although the F2 has the oxidation number of -2, the single atom of F has the oxidation number -1.

Blank 1: The oxidation number of Calcium= +2. Since the oxidation number of the single atom Ca is +2 for the group-2 members. Also, we can recheck it by using the Rule-2, mentioned above, but for compound. As I mentioned before, the net charge on the CaF2 is zero; therefore, the sum of the oxidation number of Ca and that of F2 has to be zero. Since the oxidation number of F2 is -2, the oxidation number of Ca has to be +2 to make the net charge equals to zero. Therefore, the oxidation number of Ca is +2.

B(3 parts):
The oxidation number of H, S & O?

In what group Hydrogen(H) lies? Well in group 1 in the periodic table.
Is it alone? No, it is not. It's with Sulfur(S) and Oxygen(O) .
Is it multiple of itself? Yes. It's H2; therefore, there are two hydrogen atoms.

The second element is Sulfur(S).
In what group S lies? Well in group 16(in chalcogens) in the periodic table.
Is it multiple of itself? No.

The third element is Oxygen(O).
In what group Oxygen(O) lies? Well in group-16 in the periodic table.
Is it alone? No, it is not. It's with Sulfur(S) and Hydrogen(H) .
Is it multiple of itself? Yes. It's O4; therefore, there are four oxygen atoms.

Is there any net charge on the compound? No.

Blank 3: The oxidation number of O4 = 4 * (-2) = -8. Since the oxidation number of the single atom O is -2 for the chalcogens (group-16 members). In this compound there are 4 Oxygen atoms, therefore it should be -8. Although the O4 has the oxidation number of -8, the single atom of O has the oxidation number -2.

Blank 1: The oxidation number of H2 = 2 * (+1) = +2. Since the oxidation number of the single atom H is +1 for the group-1 members. In this compound there are 2 hydrogen atoms, therefore it should be +2. Although the H2 has the oxidation number of +2, the single atom of H has the oxidation number +1.

Blank 2: As I mentioned before, the net charge on the H2SO4 is zero; therefore, the sum of the oxidation number of H2, S and that of O4 has to be zero. Since the oxidation number of H2 is +2, and the oxidation number of O4 is -8, the oxidation number of Sulfur has to be +6 to make the net charge equals to zero. Therefore, the oxidation number of S is +6.

C(3 parts):

Blank 3: The oxidation number of O4 = 4 * (-2) = -8. Since the oxidation number of the single atom O is -2 for the chalcogens (group-16 members). In this compound there are 4 Oxygen atoms, therefore it should be -8. Although the O4 has the oxidation number of -8, the single atom of O has the oxidation number -2.

Blank 1: The oxidation number of Calcium= +2. Since the oxidation number of the single atom Ca is +2 for the group-2 members. Although Sulfur in the compound is also a single element, but as Calcium comes first, therefore, we would consider Ca as an independent element. Hence, Ca has the oxidation number +2.

Blank 2: As I mentioned before, the net charge on the CaSO4 is zero; therefore, the sum of the oxidation number of Ca, S and that of O4 has to be zero. Since the oxidation number of Ca is +2, and the oxidation number of O4 is -8, the oxidation number of Sulfur has to be +6 to make the net charge equals to zero. Therefore, the oxidation number of S is +6.

D(2 parts):

Blank 2: The oxidation number of F =  -1. Since the oxidation number of the single atom F is -1 for the halogens(group-17 members).

Blank 1: The oxidation number of Hydrogen H = +1. As I mentioned before, the net charge on the HF is zero; therefore, the sum of the oxidation number of H and that of F has to be zero. Since the oxidation number of F is -1, the oxidation number of H has to be +1 to make the net charge equals to zero. Therefore, the oxidation number of H is +1.

The oxidation number is defined as the total number of electrons gained or lost in a chemical bond with another atom.

The oxidation number of the given elements are:

Ca is +2 and F is -1. H is +1, S is +6, and O is -2.Ca is +2, S is +6, and O is -2.H is +1, and F is -1.

1. CaF₂ or calcium fluoride is an ionic bond. The oxidation number of Calcium is +2 and that of Flourine is -1. The net charge on the compound is zero.

2. Sulfuric acid is a type of covalent bond. The oxidation number of Hydrogen is +1, Sulfur is +6, and that of Oxygen is -2. The net charge on the compound is zero.

3. Calcium sulfate is a type of covalent bond and ionic bond. The oxidation number of Calcium is +2, Sulfur is +6, and that of Oxygen is -8. The net charge on the compound is zero.

4. Hydrogen Flouride is a type of covalent bond. The oxidation number of Hydrogen is +1 and that of Flourine is -1. The net charge on the compound is zero.

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Answer is: there are 5,275·10²³ hydrogen atoms in methane.
m(CH₄) = 3,50 g.
n(CH₄) = m(CH₄) ÷ M(CH₄).
n(CH₄) = 3,5 g ÷ 16 g/mol.
n(CH₄) = 0,219 mol.
n(CH₄) : n(H) = 1 : 4.
n(H) = 4 · 0,219 mol = 0,876 mol.
N(H) = n(H) · Na.
N(H) = 0,876 mol · 6,022·10²³ 1/mol.
N(H) = 5,275·10²³.
Na - Avogadro number.

Answer: Chemical composition modification (or, physical signal would be color).

Explanation:

When iron reacts with the moisture present in air then an oxide layer tends to develop on the surface of iron. This process is known as rusting of iron.

Chemical formula of rust is [tex]Fe_{2}O_{3}.xH_{2}O[/tex]. This layer of oxide on the surface of iron is orange-brown in color.

This change is a chemical change as a new compound iron oxide has formed in this process of rusting.

Hence, this orange-brown color on the surface of iron helps us to know that rusting has taken place.

 The reaction of Butanoic acid and excess ethanol occurs as shown in the equation;
 CH₃CH₂CH₂COOH + CH₃CH₂OH = CH₃CH₂CH₂COOCH₂CH₃ + H₂O
1 mole of butanoic acid contains 88g/mol
Thus, 7.35 g of butanoic acid contains; 
  = 7.35/88
  = 0.0835 moles
The mole ratio of butanoic acid and ethylbutyrate is 1:1
Thus moles of ethyl butyrate produced is 0.0835 moles
But 1 mole of ethyl butyrate contains 116 g/mol
Hence, the mass of ethyl butyrate will be
=0.0835 × 116 
=9.686 g

Answer is: 9,69 grams ethyl butyrate would be synthesized.
Chemical reaction: C₃H₇COOH + C₂H₅OH → C₃H₇COOC₂H₅ + H₂O.
m(C₃H₇COOH) = 7,35 g.
n(C₃H₇COOH) = m(C₃H₇COOH) ÷ M(C₃H₇COOH).
n(C₃H₇COOH) = 7,35 g ÷ 88,11 g/mol.
n(C₃H₇COOH) = 0,0834 mol.
From chemical reaction: n(C₃H₇COOH) : n(C₃H₇COOC₂H₅) = 1 : 1.
n(C₃H₇COOC₂H₅) = 0,0834 mol.
m(C₃H₇COOC₂H₅) = 0,0834 mol · 116,16 g/mol.
m(C₃H₇COOC₂H₅) = 9,69 g.

45 liter = 45,000 ml x 0.65 gm/ml = 29,250 grams 
454 gms = 1 lb 
29,250 gms = x lb 
x = 64.4 lbs

The mass of a substance can be determined from the density and volume of the substance. The mass of gasoline with 0.65 g/ml density and 45 L volume is 29.25 Kg.

What is density?

Density of a substance is the measure of its mass per volume. Thus it is the ratio of its mass to the volume. Density of a substance depends on the temperature, pressure, bond type etc other than mas and volume.

Mass of the substance is the total amount of the substance expressed in g, kg or mg. The mass multiplied by the gravity experienced by the body is called its weight.

Volume of a substance is the total space occupied by the substance. Volume is expressed in cm³, Liter, milliliter etc.

Here the density of the substances is given 0.65 g/ml and volume is 45 liter or 45000 ml. Mass can be calculated by multiplying density with volume.

Mass = density × volume.

         =  0.65 g/ml ×  45000 ml

         = 29250 g

         = 29.25 g.

Hence, mass of the substance is 29.25 g.

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I believe the main goal is to feed a growing world without damaging the ecosystem. Sustainable agriculture involves the production of food, fiber, or other plant or animal products using farming techniques that protect the environment, public health, human communities and animal welfare. It integrates thee main goals; environmental health, economic profitability, and social and economic equity.

In order to practice sustainable agriculture, less external energy must be used, and renewable energy sources must take their place. To feed a growing world without damaging the ecosystem is the goal of sustainable agriculture. The correct option is C.

Crop rotation, the process of rotating various crops in the same area, helps maintain the soil's health and productivity by creating a mix of nutrients. This may lessen the need for pesticides and fertilizers to kill weeds and insects.

Agriculture that is sustainable generates a lot of food without consuming too many resources or harming the environment. Agriculture develops self-sustaining agricultural and livestock-raising systems that are, like nature, based on natural principles.

Thus the correct option is C.

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Answer: [tex]3.13\times 10^{23}molecules[/tex]

Explanation: To calculate the moles, we use the formula:

[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{9.34g}{18g/mol}=0.52mol[/tex]  

1 mole of water contains=[tex]6.023\times 10^{23}molecules[/tex] of water

0.52 moles of water contain=[tex]\frac{6.023\times 10^{23}}{1}\times 0.52=3.13\times 10^{23}molecules[/tex] of water

One or more than one atoms bonds and makes up the molecules, it can be the same or different atoms that make up the compounds. Molecules present in the 9.34 gm of water are [tex]\rm 3.13 \times 10^{23}[/tex].

What is the formula for calculating molecules?

Given,

Mass of the water (m) = 9.34 gm

The molar mass of the water (M)= 18 g/mol

From the mass and the molar mass number of the moles can be estimated:

[tex]\rm Moles (n) = \dfrac{\;\rm Mass}{\rm Molar \;mass}[/tex]

Substituting values in the above formula:

[tex]\begin{aligned}\rm n &= \dfrac{9.34\;\rm g}{18\;\rm g/mol}\\\\&= 0.52\;\rm mol\end{aligned}[/tex]

We know that,

1 mole of water = [tex]\rm 6.023 \times 10^{23}[/tex] molecules of water

0.52 moles of water = X molecules

Solving for X:

[tex]\begin{aligned} \rm X &= 0.52 \times \rm 6.023 \times 10^{23}\\\\&= \rm 3.13 \times 10^{23}\end{aligned}[/tex]

Therefore, [tex]\rm 3.13 \times 10^{23}[/tex] molecules are present.

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Answer;

A teacher takes the cap off a permanent marker. A few minutes later, students at the back of the classroom complain about the odor of the marker.A cooking school student burns a piece of toast. Soon, the entire kitchen smells like burnt toast.Toxic fumes produced by a chemical factory are detected in the air in a town several miles away.Explanation;Diffusion is a type of passive transport that involves the movement of particles from a region of high concentration to a region of low concentration. Diffusion takes place in liquids and gases, since their particles can move randomly from one region to another.Therefore, diffusion results from the random movement of particles in which the net movement is down the concentration gradient  that is, from a region of high concentration to a region of low concentration.

3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)

This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.

Hope this helped!

balanced because the total number of oxygen atoms is 3.

The balanced chemical equation has been [tex]\rm 3\;CaCO_3\;\rightarrow\;3\;CaO\;+\;3\;CO_2[/tex].

The balanced equation can be given to follow the law of conservation of mass. with equal  number of atoms of each elements has been present on the product and the reactant side.

The given equation has been written with addition of 3 as a coefficient to the carbon dioxide has been:

[tex]\rm CaCO_3\;\rightarrow\;CaO\;+\;3\;CO_2[/tex]

The number of elements of oxygen on product side has been 6 atoms for carbon dioxide and 1 oxygen atom for calcium oxide. The total oxygen on product side has been 7. The reactant has the presence of 3 oxygen atoms.

The reaction has been balanced with equal atoms on both the sides as:

[tex]\rm 3\;CaCO_3\;\rightarrow\;3\;CaO\;+\;3\;CO_2[/tex]

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To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:
Let 1 = argon gas      2 = unknown gas
r2 = 0.91r1r1/r2 = 1/0.91
1/0.91 = √M2/M1 = √M2/40M2 = 48.30 g/mol

Answer : The molar mass of a gas is, 48.3 g/mole

Solution : Given,

Molar mass of argon gas = 40 g/mole

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

[tex]R\propto \sqrt{\frac{1}{M}}[/tex]

or,

[tex]\frac{R_1}{R_2}=\sqrt{\frac{M_2}{M_1}}[/tex]

where,

[tex]R_1[/tex] = rate of effusion of a gas

[tex]R_2[/tex] = rate of effusion of argon gas

[tex]M_1[/tex] = molar mass of a gas

[tex]M_2[/tex] = molar mass of argon gas

As per question,

[tex]R_1=0.91\times R_2[/tex]

Now put all the given values in the above formula, we get the molar mass of a gas.

[tex]\frac{0.91\times R_2}{R_2}=\sqrt{\frac{40g/mole}{M_1}}[/tex]

[tex]M_1=48.30g/mole[/tex]

Therefore, the molar mass of a gas is, 48.3 g/mole

The philosopher Socrates was condemned to death for impiety. He was executed via Hemlock Poisoning. Hemlock is a flowering plant, related to carrots. It is known to affect the nervous system resulting to paralysis. The paralysis includes the paralysis of respiratory muscles which will impede respiration and result in death. The most potent part of the plant is the seeds and roots.

Answer:

Hemlock poison is your answer

Answer is: In such conditions, oxygen was available in abundance. 
Because in such conditions there was no or very little oxygen. If there was oxygen the organic matter would not decomposed and formed oil and gas, because there would be reaction of oxidation.
Petroleum is used primarily as a fuel in combustion engines.

the answer is: in such conditions, oxygen was available in abundance.

hello
the answer is c
have a nice day

The appropriate answer is B. decreasing the surface area. A solute is a component that dissolves in a solvent to form a solution. Increasing the surface area means making more of the surface of the solid available to be dissolved.
For example, it would be difficult to dissolve a a Lego sized cube of sugar in a liter of water. Crushing the same cube into smaller fragments increases the surface area and would speed up the rate of dissolution.

The answer is B. The carrying capacity will decrease, forcing the population to decrease as well.

The correct answer is B. The carrying capacity will decrease and the owl population will decrease.

Explanation:

In ecology, the carrying capacity refers to the number of organisms an ecosystem or area can sustain because it provides water, shelter, food, etc. This carrying capacity decreases due to the destruction of habitat or natural disasters that reduces the resources or habitable area.

This implies, in the case presented, the carrying capacity of the forest will decrease because the resources on in for owls are reduced to half due to housing development. Besides this, it is expected the owl population decreases because with less food, water, and other resources such as trees to nest ess owls will survive and reproduce. Thus, in this case, "the carrying capacity will decrease and the owl population will decrease".

Answer : Option B) Air

Explanation : As the speed of light depends on the refractive index of the medium; then according to Snell's law (refer the attachment) Air is the medium that would have the longest wavelength amongst the given options.

As the refractive indexes of water is 1.33, glass is 1.5 and diamond 2.42 are much higher than air. Therefore, it will be the medium which will allow maximum light to pass through it easily and hence, will be the medium with longest wavelength.

The correct answer is air.  

The refractive indexes of air, water, glass and diamond are1.0003, 1.33, 1.5 and 2.42 respectively. The refractive index of air is the lowest so it is the medium through which light will travel faster with the longest wavelength. The higher the refractive index the denser the medium and the slower is the speed with which light will travel through this medium.  

To decide the outcome of this reaction, we need to know the state of the products, as in if they are solid, liquid, gaseous, aqueous, etc. The proper reaction is as follows:

CoCl₂ (aq) + Na₂SO₄ (aq) → CoSO₄ (aq) + 2NaCl (aq)

If we were to look up the species CoSO₄ and NaCl, we would find that both of these species are also aqueous. Therefore, neither CoSO₄ or NaCl will precipitate from the solution, so we can ignore options A and B. Neither species formed is gaseous either, therefore, it cannot be option C. That leaves us with option D as the answer.

D is the correct answer because the product of the double displacement is the formation of two more aqueous species which will remain dissociated in the aqueous solution leading to no chemical reaction overall.

missing in your question the K constant value =2.99X10^-7
The reaction equation:
         SOCl2 ⇄ SO2 +Cl2
initial 0.195          0        0
         -X             +X      +X
final  (0.195-X)      X        X

K= [SO2][Cl2]/SOCl2
by substitution
2.99X10^-7 = (X)(X)/(0.195-X)
2.99X10^-7 = X^2 / (0.195-X) by solving this equation 
∴X = 0.00024 = 2.4 X10^-4 
∴[Cl2] = 2.4X10^-4 m

The equilibrium concentration of cl2 at 227C is mathematically given as

[Cl2] = 2.4X10^-4 m

Equilibrium concentration

Question Parameters:

If a reaction mixture initially contains 0.195 m so2cl2

concentration of cl2 at 227

Generally the equation for the Chemical Reaction  is mathematically given as

SOCl2 ⇄ SO2 +Cl2

Therefore

[tex]K=\frac{ [SO2][Cl2]}{SOCl2}[/tex]

2.99X10^-7 = (X)(X)/(0.195-X)

X = 0.00024 = 2.4 X10^-4

[Cl2] = 2.4X10^-4 m

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Answer;

Ge and As.

Explanation;

Elements Ge and As belong in the same period as krypton.

Each row of the periodic table is called the period.

Elements in each period have the same number of electron shells.

These elements in the same period do not have similar properties- the properties change greatly across every period. Krypton is in period four therefore all the elements in period 4 have four electrons shells.

Answer:

CaCl2

Explanation:

Calcium: Ca

Chloride or chlorine: Cl

Chloride: it is name of chlorine when it has a ion

calcium has a charge of +2 and  Chlorine has a charge of -1

this is a ionic bond, so the charges of the two atoms have to equal or cancel out, so u need two  Chlorine

and then it will be calcium +2 and chloride -2

2-2=0, they are neutral and we are right

CaCl2

The correct answer is Fusion Curve

25 kj  absorbed  by  dissolving  1 mole of  NH4NO3

1kj  is   absorbed  by  dissolving =  1/25.7 =  0.03891  moles
what  about  73  kj  absorbed  by  dissolving

0.03891  x73=  2.8404 moles

Answer:

2.84 mol

Explanation:

Mgs is the compound that has the greatest percent composition by mass of sulfur.