Answer:
The Answer is C. magnesium hydroxide
Explanation:
The process that changes a solid directly into a gas is called sublimation. A solid that begins with a mass of 450 g will sublime to give off a gas with a mass of _______ g.
Answer:
The answer is 450 g
Explanation:
When the solid sublimes, it gives the same mass of gas because sublimation is a physical change, and it is valid the energy and mass conservation law (mass cannot be destroyed or created in a chemical or physical process). If sublimation is complete, all the molecules changes its physical state from solid to gas.
Sublimation is the process where a solid changes directly into a gas without passing through the liquid phase. The mass of the substance remains unchanged, so a solid with a mass of 450 g will yield a gas with a mass of 450 g.
The process that changes a solid directly into a gas is called sublimation. In this process, a solid transitions to a gas phase without passing through the liquid phase. Importantly, the mass of the substance remains constant during this phase change. Therefore, if you start with a solid that has a mass of 450 g, the resulting gas will also have a mass of 450 g. This is in accordance with the law of conservation of mass which suggests that mass can neither be created nor be destroyed.
An example of sublimation occurs with dry ice (solid CO₂), which transitions directly from a solid to a gas at standard temperature and pressure.
Draw the two chair conformations of cis 1 chloro 2 methylcyclohexane
The two chair conformations of cis 1 chloro 2 methylcyclohexane are shown in the image attached.
Due to the cyclohexane ring's capacity for ring flipping, isopropyl chloro-2-methylcyclohexane displays two chair conformations. The methyl group is positioned equatorially in the first conformation, while the chlorine atom is located in the axial position.
The chlorine atom is in the equatorial position and the methyl group is in the axial position in the second conformation, which has the substituents arranged in reverse order. These conformations show the dynamic character of cyclohexane rings, where substituents can be positioned in either an axial or an equatorial orientation to minimize steric hindrance between them by ring flipping.
When a stable diatomic molecule spontaneously forms from its atoms, what are the signs of δh°, δs°, and δg°?
The formation of a stable diatomic molecule from atoms typically results in a negative ">δH°<", a negative ">δS°<", and a negative ">δG°<". This reflects an exothermic reaction with decreased entropy, leading to spontaneity under the right temperature conditions.
When a stable diatomic molecule forms from its atoms, there are typical changes in enthalpy (">">δH°"), entropy (">">δS°"), and Gibbs free energy (">">δG°"). The formation of a stable molecule from atoms is typically exothermic, which means that energy is released, and ">">δH°" would be negative. As atoms come together to form a molecule, the system becomes more ordered, and thus, the change in entropy, ">δS°<", is negative.
According to the Gibbs free energy equation, ">δG° = δH° - TδS°<", and at a temperature (T) where this process is spontaneous, the sign of ">δG°<" would be negative because loss of heat (">">exothermic reaction") and orderliness in system (">">decreased entropy") favor the formation of the molecule.
The rate constant for a second-order reaction is 0.54 m-1s-1. what is the half-life of this reaction if the initial concentration is 0.30 m?
The correct answer is: 6.173 seconds.
Explanation:
The formula for half life (of reaction) is:
Half-life = [tex]\frac{1}{K*I}[/tex] --- (A)
Where,
K = Rate constant = 0.54 [tex]\frac{1}{ms}[/tex]
I = Initial concentration = 0.30 m
Plug in the values in equation (A):
Half-life = [tex]\frac{1}{0.54*0.30} = 6.173[/tex]
Hence, the half life is 6.173 seconds.
The half-life of a second-order reaction is [tex]\boxed{{\text{6}}{\text{.173 seconds}}}[/tex]
Further explanation:
Second-order reaction:
A reaction is said to be of second-order if its rate is proportional to the square of the concentration of one reactant. The general example of second-order reaction is,
[tex]2{\text{A}}\to{\text{P}}[/tex]
Here,
A is the reactant.
P is the product.
The rate is calculated by using the following equation:
[tex]{\text{Rate}}={\text{k}}{\left[{\text{A}}\right]^2}[/tex]
Another form of second-order reaction is as follows:
[tex]{\text{A}}+{\text{B}}\to{\text{P}}[/tex]
Here,
A and B are the two different reactants.
P is the product.
The rate is calculated by using the following equation:
[tex]{\text{Rate}}={\text{k}}\left[{\text{A}}\right]\left[{\text{B}}\right][/tex]
Half-life:
Half-life is defined as the time required to reduce the concentration of reactant to half of its initial value. It is denoted by [tex]{{\text{t}}_{1/2}}[/tex] . The general expression to calculate [tex]{{\text{t}}_{1/2}}[/tex] of second-order reaction is,
[tex]{{\text{t}}_{1/2}}=\frac{1}{{{\text{k}}{{\left[{\text{A}}\right]}_{\text{0}}}}}[/tex] …… (1)
Here,
[tex]{{\text{t}}_{1/2}}[/tex] is the half-life of the reaction.
k is the rate constant for the reaction.
[tex]{\left[ {\text{A}}\right]_{\text{0}}}[/tex] is the initial concentration of the reactant.
The rate constant for the given reaction is [tex]0.54\;{{\text{M}}^{-1}}{{\text{s}}^{-1}}[/tex] .
The initial concentration of the given reaction is 0.30 M.
Substitute these values in equation (1).
[tex]\begin{aligned}{{\text{t}}_{1/2}}&=\frac{1}{{\left({0.54\;{{\text{M}}^{ - 1}}{{\text{s}}^{ - 1}}}\right)\left( {{\text{0}}{\text{.30 M}}}\right)}}\\&=\frac{1}{{0.162\;{{\text{s}}^{ - 1}}}}\\&=6.1728\;{\text{s}}\\&\approx 6.173\;{\text{s}}\\\end{aligned}[/tex]
So, the half-life of a second-order reaction is 6.173 seconds.
Learn more:
1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603
2. Calculate the moles of ions in the solution: https://brainly.com/question/5950133
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Chemical Kinetics
Keywords: second-order reaction, half-life, initial, half, 6.173 seconds, 0.30 m, k, A0, A, B, P, 2A, reactant, product, t1/2.
Match the formula for the following compound: iron (III) sulfate
FeSO4
Fe3SO4
Fe(SO4)3
Fe2(SO4)3
Answer:
D. Fe2(SO4)3
is the answer
Explanation:
Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1." Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃
Answer:
blank, 2, blank, 2
A fatty acid with 10 carbons will be absorbed via the
What is the structural formula of 2-methylbutan-2-ol (sometimes called 2-methyl-2-butanol)?
A 15.0 kg chunk of ice falls off the top of an iceberg. If the chunk of ice falls 8.00m to to the surface of the water, what is the kinetic energy of the chunk of ice when it hits the water, and what is its velocity
A sample of gas has a volume of 5.58 l at a pressure of 715 mm hg. what is the volume of the gas when the pressure of the gas is increased to 755 mm hg?
What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.884 M with a k value of 5.42 × 10–2 M/s?
Answer:
The half-life (in seconds) of a zero-order reaction is 8.15 seconds.
Explanation:
Initial concentration of the of the reactant = [tex][A_o]=0.884 M[/tex]
The value of rate constant = [tex]k=5.42\times 10^{-2} M/s[/tex]
The half life for zero order reaction is given as:
[tex]t-{\frac{1}{2}}=\frac{[A_o]}{2k}=\frac{0.884 M}{2\times 5.42\times 10^{-2} M/s}=8.15 s[/tex]
The half-life (in seconds) of a zero-order reaction is 8.15 seconds.