what is an example of a cation

what’s an example of a cation

Answer:

R = 0.083 atm .L /  mol.K

Explanation:

Given data:

Pressure of gas = 259,392.00 Pa

Temperature = 2.0 °C

Moles = 1 mol

Volume = 8.8 dm³

R = ?

Solution:

First of all we will convert the units.

Pa to atm

259,392.00 /101325 = 2.56 atm

dm³ to L

8.8 dm³ = 8.8 L

2.0 °C to K

2+273 = 275 K

Now we will calculate the R:

PV = nRT

R = PV/ nT

R =  2.56 atm . 8.8 L / 1 mol. 275 K

R = 22.528  atm .L / 1 mol. 275 K

R = 0.083 atm .L /  mol.K

Answer:

individual ancient shark vertebra

Explanation:

it ask for a body fossil and that is the only body fossil

One of the example that falls under classification of body fossil is C:

individual ancient shark vertebra

The main types of fossil are:

Most of the  body fossils usually have a hard parts these part could be

Therefore, option C is right

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Answer:

B.False

Explanation:

Volume is used in 3D shapes, 2D is found by area.

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3, 2, 1, 6

Explanation:

To balance the chemical equation the number of atoms of each element  

entering the reaction have to be equal to the number of atoms of each  

element leaving the reaction, in order to conserve the mass.

In our case we have:

3 CaCl₂ + 2 Na₃PO₄ → Ca₃(PO₄)₂ + 6 NaCl

So the stoechiometric coefficients will be:

3, 2, 1, 6

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Answer:

The temperature range in the Mesosphere 15 degrees Celsius (5 degrees Fahrenheit) to negative 120 degrees Celsius (negative 184 degrees Fahrenheit)

Explanation:

The mesosphere lies above the stratosphere and extends over the Earth's surface to 85 kilometers (53 miles). The temperature at the mesosphere limit drops from negative 15 degrees Celsius (5 degrees Fahrenheit) to negative 120 degrees Celsius (negative 184 degrees Fahrenheit) at the base of the thermosphere.

Meteors vaporize in mesosphere, giving metallic ions a higher concentration than other layers of atmosphere.

Final answer:

The temperature in the mesosphere ranges from about 0°C at its lower boundary to as low as -100°C at the mesopause, its upper boundary. The mesosphere's low temperatures are due to its very thin air and lack of water vapor and ozone to absorb heat from the sun.

Explanation:

The temperature range in the mesosphere varies significantly with altitude. At the lower boundary, directly above the stratosphere (starting around 50 km above Earth's surface), temperatures can be around 0°C. As altitude increases within the mesosphere, temperatures drop sharply, reaching the mesosphere's lowest temperatures at the mesopause, which lies at the top of the mesosphere, around 85 km above the surface. Here, temperatures can plunge to as low as -100°C (-148°F).

The mesosphere is warmed from the bottom by the stratosphere below. The air in the mesosphere is very thin, and its density is approximately 1/1000th of that at the surface, which makes this atmospheric layer quite cold. This temperature decrease with altitude is due to the minimal amounts of water vapor and ozone that would otherwise help to absorb the sun's rays and heat the air.

Its molecule contains one oxygen and two hydrogen atoms.

Explanation:

Water is a chemical substance with the chemical formula H2O. Water is a chemical substance with the chemical formula H2O. Its molecule contains one oxygen and two hydrogen atoms connected by covalent bonds.

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Answer:

ester C6H5CH2OC2H5 is formed.

Explanation:

C6H5CH2OH + C2H5OH ---> C6H5CH2OC2H5 + H2O

Esterification reaction of benzoic acid with ethanol in presence of concentrated sulfuric acid​ is C₆H₅CH₂OH + C₂H₅OH → C₆H₅CH₂OC₂H₅ + H₂O.

Esterification is the process of combining an organic acid (RCOOH) with an alcohol (ROH) to produce an ester (RCOOR) and water, or a chemical reaction that produces at least one ester product. Ester is formed by the esterification of an alcohol and a carboxylic acid.

An acid catalyst, typically sulfuric acid, is added to speed up the reaction while also acting as a dehydrating agent.

Benzoic acid (a carboxylic acid) is esterified with methanol (an alcohol) in the presence of sulfuric acid (an acid catalyst) in this Fischer esterification reaction to produce methyl benzoate (an ester).

Thus, C₆H₅CH₂OH + C₂H₅OH → C₆H₅CH₂OC₂H₅ + H₂O.

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Answer:

0.326338 kcal

Explanation:

Data given:

Value in Joules = 1365.4 joules

Value in Kilocalories (kcal) =  to find

Solution:

Joule and Kilocalori both are the unit of energy

Relation of kilocalori

                   1 joule = 0.000239 kcal

so now to find

1365.4 joules equals to how much kilocalories

if

                                 1 joule = 0.000239 kcal

then                1365.4 joules = ? Kilocalories

by cross multiplication

          1 joule x ? Kilocalories = 0.000239 kcal x 1365.4 joules

By rearranging

           Kilocalories = 0.000239 kcal x 1365.4 joules / 1 joule

         Kilocalories = 0.000239 kcal x 1365.4 joules / 1 joule

         Kilocalories = 0.32633 kcal

So

         1365.4 joules = 0.32633 kcal  

[tex]1365.4 \ joules[/tex] is approximately [tex]0.3264\ kilocalories.[/tex]

To convert energy from joules to kilocalories, we use the conversion factor:

[tex]\[ 1 \, \text{kilocalorie} = 4184 \, \text{joules} \][/tex]

Given:

[tex]\[ 1365.4 \, \text{joules} \][/tex]

We convert joules to kilocalories as follows:

[tex]\[ \text{kilocalories} = \frac{\text{joules}}{\text{joules per kilocalorie}} = \frac{1365.4 \, \text{joules}}{4184 \, \text{joules per kilocalorie}} \][/tex]

Perform the calculation:

[tex]\[ \text{kilocalories} = \frac{1365.4}{4184} \][/tex]

[tex]\[ \text{kilocalories} = 0.3264 \][/tex]

Similar rocks found on different continents, Mountains created by colliding continents, Evidence of glaciers in unexpected places are the evidences to support the idea that all the continents were once joined together.

Option D, All the above.

Earth did not have seven continents but only one, nearly 300 million years ago. There was one "massive super continent", called the Pangaea. The Pangaea was also surrounded by the ocean named panthalassa. Experts say that the formation of the seven continents happened due to the movement in the tectonic plates.

Similar kinds of rocks were found on different continents, it is also believed that the Aps were formed due to the separation of continents, coal deposits of the same constituents were also found on different continents.

Answer:

all of the above

Explanation:

The correct answer to the question is Option 2. Br

Electronegativity is simply defined as the ability of an atom to attract electron(s)

Non metals are more electronegative than metals.

Krypton, Kr is a group 18 element which have completely filled outermost shell. They do not involve in bond formation.

Calcium, Ca and Barium, Ba are group 2 metals. They form bond by losing their 2 valence electrons.

Bromine, Br is a group 17 element which have 7 valence electrons. It is difficult for Br to lose its valence electron(s) and as such, it will form bond by either gaining 1 electron or sharing 1 electron.

With the above information, we can conclude that Option 2. Br gives the correct answer to the question.

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It total there are 18 atoms.

Iron (Fe) is a metal.

Sulfur (S) is a nonmetal.

Oxygen (O) is a nonmetal.

Explanation:

We have the chemical formula of iron (III) sulfate Fe₃(SO₄)₃.

It total there are 18 atoms, 3 iron (Fe) atoms, 3 sulfur (S) atoms and 12 oxygen (O) atoms.

Iron (Fe) is a metal.

Sulfur (S) is a nonmetal.

Oxygen (O) is a nonmetal.

Iron is found as Fe²⁺ cation while the sulfate group SO₄⁻ as an anion.

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There are a total of 17 atoms in Fe2(SO4)3.

A compound is formed when atoms of elements combine chemically together. A compound is defined as a group of elements which are chemically combined together.

In the compound Fe2(SO4)3, there are;

This makes a total of 17 atoms in the compound Fe2(SO4)3. Iron is a metal while oxygen and sulfur are nonmetals.

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Answer:

Q and R are most likely to form an ionic bond.

Explanation:

Ionic bond is formed between two elements which have huge difference in their electronegativities.

     According to the given question the electronegativity difference of QR is greater than that of PQ, RS and SP.

   From this point of view it can be stated that Q and R are most likely to form an ionic bond.

Answer:

Q and R

Explanation:

Answer:

13. Na  14. Ne. 15. U. 16. Ca. 17. C. l 18. O.  19. Cl. 20. Si  21. U  22. N.

23. Na 24. Ne. 25. U 26. Sc. 27. N 28. O 29. Cl 30. Si 31. U 32. N.

Explanation:

The general trend as you go to the right in any one period is for the size to decrease.

The general trend is that the size increases as you go down a Group.

The general trend as you go from the bottom left to the top right is a decrease in size.

Ionization energy increases as we move to the right in a period.

It decreases as we move down a group.

Going from the bottom left to top right - the ionization increases.

Answer:

6 moles of CuCl₂  will produced 4 moles of  AlCl₃ .

Explanation:

Given data:

Moles of CuCl₂ = 6 mole

Moles of AlCl₃ produced = ?

Solution:

3CuCl₂ + 2Al → 2AlCl₃ + 3Cu

Now we will compare the moles of CuCl₂ with AlCl₃ .

            CuCl₂        :        AlCl₃

                3            :          2

                6           :         2/3 ×6 = 4 mol

So, 6 moles of CuCl₂  will produced 4 moles of  AlCl₃ .

Answer:

D. bromine (Br)

Explanation:

Bromine is an element of halogen group.

Halogens, or "salt-formers," are located in group 17 of the periodic table. The halogens have  the following properties:

1) They have low melting points and low boiling points.

2) They exist as diatomic molecules in the gas phase.

3) They have seven electrons in their outermost shell, which means they have seven valence

electrons.

4) They are highly reactive nonmetals.

5) They tend to gain electrons and form negative ions.

Thus the given properties are of Bromine.

Explanation:

The formula for tryptophan is [tex]C_{11}H_{12}N_{2}O_{2}[/tex]

Mass of [tex]C[/tex] in tryptophan is [tex]11\times 12=132g[/tex]

Mass of [tex]H[/tex] in tryptophan is [tex]12\times 1=12g[/tex]

Mass of [tex]N[/tex] in tryptophan is [tex]2\times 14=28g[/tex]

Mass of [tex]O[/tex] in tryptophan is [tex]2\times 16=32g[/tex]

So,[tex]\text{total mass}=132+12+28+32=204g[/tex]

[tex]\text{mass of carbon}=132g[/tex]

[tex]\text{mass percent of carbon}=\frac{\text{mass of carbon}}{\text{total mass}}\times 100 =\frac{132}{204}\times 100 =64.7[/tex]%

Final answer:

The mass percent of carbon in tryptophan is approximately 64.68%, calculated by determining the total mass of carbon.

Explanation:

By using the atomic masses of carbon (C), hydrogen (H), nitrogen (N), and oxygen (O), we can calculate the molar mass of tryptophan. After that, we determine the total mass contributed by carbon atoms (by multiplying the number of carbon atoms by the atomic mass of carbon) and then divide this by the molar mass of tryptophan to get the mass percent of carbon.

So, the mass of carbon in tryptophan is 11 × 12.01 g/mol = 132.11 g/mol.

The molar mass of tryptophan is approximately 204.23 g/mol. The mass percent of carbon in tryptophan can thus be calculated as (132.11 g/mol) / (204.23 g/mol) × 100%, which yields approximately 64.68%.

This value indicates that carbon makes up about 64.68% of the mass of a tryptophan molecule. Understanding these kinds of compositions is important for fields like biochemistry and nutrition where the analysis of the biochemical roles of various compounds is crucial.

Answer:

d) Chlorine

Explanation:

when an atom form ion its atomic radius changed from neutral atomic radius.

if the atom form cation its atomic radius is smaller than neutral atomic radius.

If atom form anion its anionic radius is larger than the neutral atomic radius.

The reason is that when electron is remove energy shell deduced so cation get smaller ionic radii while in case of anion electron is added and size increase.

In given list of elements potassium, zinc and chromium form cation while chlorine form anion.

That's why its ionic radius will larger than atomic radius.

The element with an ion that has a larger radius than its atomic radius is potassium (K).

Based on the information provided, the ion with a radius larger than its atomic radius is K (potassium). This is because potassium loses an electron to form a cation (K+), which has a larger radius than its neutral atomic form. The loss of one electron reduces the attractive force between the electrons and the nucleus, causing the electron cloud to expand, resulting in a larger radius.

There are five significant figures in the measurement 0.023040 cm.

To determine the number of significant figures in a given measurement, one must follow these rules:

1. Non-zero digits are always significant. In the measurement 0.023040 cm, the digits 2, 3, and 4 are non-zero and thus significant.

2. Zeros between non-zero digits are significant. Here, the zero between the 3 and the 4 is significant because it is sandwiched between two non-zero digits.

3. Leading zeros, which are zeros before the first non-zero digit in a number less than one, are not significant. In this case, the two zeros after the decimal point and before the 2 are leading zeros and are not significant.

4. Trailing zeros, which are zeros at the end of a number, are significant if the number has a decimal point. In the measurement 0.023040 cm, the zero at the end is after the decimal point and is therefore significant.

Applying these rules, we count the significant figures in 0.023040 cm as follows:

- The first two zeros after the decimal point are not significant (leading zeros).

- The digit 2 is significant.

- The digit 3 is significant.

- The zero between the 3 and the 4 is significant (it is between two non-zero digits).

- The digit 4 is significant.

- The last zero is significant (trailing zero after the decimal point).

Therefore, the measurement 0.023040 cm has five significant figures.

Answer:

The line drawn through points D and E.

Explanation:

Y is a horizontal line and D and E are both on the same line. If a line were drawn it would be within the Y plane.

Answer:

B. The line that can be drawn through points D and E is contained in plane Y.

Explanation:

Answer:if you could be more spesific id be happpy to help

Explanation:

thanks sm.

Answer:

The density of the material is 7.5 g/m^3

Explanation:

The volume of a rectangle is:

Volume = Length*Height*Width

Replacing with data:

Volume = 5 m * 2 m * 4 m = 40 m^3

Density is computed as follows:

Density = Mass/Volume

Replacing with data:

Density = 300 g/40 m^3

Density = 7.5 g/m^3

Answer: Cement is a mixture.

Explanation: It is composed of different types of compound particles. Each of the components of concrete by themselves would be pure substances. For example, a sample of just calcium oxide would be a pure substance because the particles in the sample would all be identical calcium oxide compounds.

Concrete is a heterogeneous mixture comprised of cement, water, sand, and gravel, retaining the individual properties of its components and can be separated physically.

Concrete is a mixture, not a pure substance. Pure substances are materials made up of only one type of matter, either a single element or a single compound, with a constant composition and set of properties throughout. In contrast, mixtures are combinations of two or more pure substances that retain their individual identities and can be separated by physical methods. Concrete is specifically a heterogeneous mixture as it consists of several different components such as cement, water, sand, and gravel that are not uniform throughout. These components can be identified and, in theory, could be separated by physical means.

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Answer:

V = 6.17 L

Explanation:

Given data:

Volume = ?

Number of moles = 0.382 mol

Pressure = 1.50 atm

Temperature = 295 k

R = 0.0821 L. atm. /mol. k

Solution:

According to ideal gas equation:

PV= nRT

V = nRT/P

V = 0.382 mol × 0.0821 L. atm. /mol. k ×295 k / 1.50 atm

V = 9.252  L. atm.  / 1.50 atm

V = 6.17 L

Final answer:

Using the ideal gas law, the volume of 0.382 moles of hydrogen gas at 1.50 atmospheres pressure and 295 K is approximately 6.17 L.

Explanation:

Using the ideal gas law, PV = nRT, we can calculate the volume of 0.382 moles of hydrogen gas at 1.50 atmospheres pressure and 295 K temperature. where T is the temperature, R is the ideal gas constant, n is the number of moles, V is the volume, and P is the pressure.

The provided values are: P = 1.50 atm, n = 0.382 moles, R = 0.0821 L•atm/mol•K, and T = 295 K. When we enter these numbers into the ideal gas law, we obtain:
V = nRT/PV = (0.382 mol) × (0.0821 L•atm/mol•K) × (295 K) / (1.50 atm)

Calculating this, we find the volume (V) of hydrogen gas:

V ≈ 6.17 L

Answer:

Therefore F ∠ 2.5N

Explanation:

Definition of Work:

It is the amount of energy transferred.

Mathematical expression:

W = F × d

By taking the friction into count it will define as:

Input work = work against friction ×  output work

No we will put the values:

25 J = w + 10 m

j = kg m²/s²

25 kg m²/s² =  w + 10 m

when friction is exist then w > 0

25 kg m²/s² - 10 m  > 0

15 N > 0

Therefore F ∠ 2.5N

Answer:

[tex]Zn^{0} --->Zn^{2+} +2e^{-}[/tex]

Explanation:

[tex]Zn^{0} --->Zn^{2+} +2e^{-}[/tex]

Final answer:

A Lucas reagent is a mixture of zinc chloride and concentrated hydrochloric acid that is used to distinguish between primary, secondary, and tertiary alcohols.

Explanation:

A Lucas reagent is a mixture of zinc chloride (ZnCl2) and concentrated hydrochloric acid (HCl) that is used to distinguish between primary, secondary, and tertiary alcohols.

When the Lucas reagent is added to an alcohol, a reaction occurs where a cloudy precipitate of alkyl chlorides is formed. The rate at which the precipitate forms depends on the type of alcohol:

Answer:

A.   The new molarity of the diluted solution is 1.0176 M

B.   The new molarity of the diluted solution is 0.9947  M

C.   20 mL of volume is required to prepare 100ml of 1 M NaOH

Explanation:

Part A:

___________

This problem will be solved by using the following formula

                               M₁V₁ =  M₂V₂                        (1)

Given Data:

Initial Molarity of Solution M₁ = 3.24 M

Initial volume V₁ = 1.25 L

Initial volume V₂ = 3.98 L

Final Molarity M₂= ?

Put the values in formula 1

                          3.24 M x 1.25 L = M₂ x 3.98 L

By Rearranging

                         M₂  =  3.24 M x 1.25 L / 3.98 L

                         M₂  =  4.05 / 3.98

                          M₂  =  1.0176 M

The new molarity of the diluted solution is 1.0176 M

_________________

Part B:

This problem will be solved by using the following formula

                               M₁V₁ =  M₂V₂                        (1.1)

Given Data:

Initial Molarity of Solution M₁ = 7.0 M

Initial volume V₁ = 270 mL

As the initial volume is in ml and final volume in Litre (L)

So we have to convert mL to L

       1000ml= 1L

       270 ml = ? L

       1 x 270/ 1000 = 0.27 L

So

Initial volume V₁ = 0.27 L

Initial volume V₂ = 1.9 L

Final Molarity M₂= ?

Put the values in formula 1.1

                                               M₁V₁ =  M₂V₂  

                            7.0 M x 0.27 L = M₂ x 1.9 L

By Rearranging

                         M₂  =    7.0 M x 0.27 L / 1.9 L

                         M₂  =  1.89 / 1.9

                          M₂  =  0.9947 M

The new molarity of the diluted solution is 0.9947  M

_________________

Part 3

This problem will be solved by using the following formula

                               M₁V₁ =  M₂V₂                        (1.2)

Given Data:

Initial Molarity of Solution M₁ = 5 M

Initial volume V₁ = ? mL

Initial volume V₂ =  100 mL

Final Molarity M₂= 1 M

Put the values in formula 1.2

                                               M₁V₁ =  M₂V₂  

                            5 M x V₁ = 1 M x 100 mL

By Rearranging

                         V₁  =   1 M x 100 mL/ 5 M

                         V₁  =   100 / 5

                          V₁  =   20

20 mL of volume is required to prepare 100ml of 1 M NaOH

Answer:

R = 0.064 dm³ atm K⁻¹ mol⁻¹

Explanation:

Data Given:

volume of gas V = 8.8 dm³

no. of mole of gas (n) = 1 mole

Pressure P = 259,392.00 Pa

Convert Pascal (Pa) to atm (atmospheric pressure)

As,

101,325 Pa = 1 atm

So,

259,392.00 Pa = 2 atm

Then Pressure (P) = 2 atm

Temperature T = 2.00 °C

change the temperature from °C to K

As to convert °C to K the below formula used

                       0°C + 273.15 = 273.15K

So, for 2 °C

                      2°C + 273.15 = 275.15 K

So,

Temperature T = 275.15 K

ideal gas constant = ?

formula used for Ideal gases

                           PV = nRT

as we have to find R of the gas:

we will rearrange the ideal gas equation as below:

                           R = PV / nT ........................................... (1)

Put value in equation (1)

                             R = 2atm x 8.8 dm³ / 1 mole x 275.15 K

                             R = 17.6 atm. dm³ / 275.15 mol. K

                             R = 0.064 dm³ atm K⁻¹ mol⁻¹

So the value of R is 0.064 dm³ atm K⁻¹ mol⁻¹

and the unit of R (ideal gas constant) is dm³ atm K⁻¹ mol⁻¹

Answer:

Electronic Configuration of calcium ion: Ca²⁺

1s², 2s², 2p⁶, 3s², 3p⁶

Explanation:

Calcium belong to group IIA and known as alkaline earth metals.

Electronic Configuration of calcium atom: ²⁰Ca

1s², 2s², 2p⁶, 3s², 3p⁶, 4s²

When calcium ion is form it loses two electron and have 2+ charge on it.

and have total of 18 electrons

So,

Electronic Configuration of calcium ion: Ca²⁺

the last filled orbital will be 3p⁶

1s², 2s², 2p⁶, 3s², 3p⁶

Explanation:

[tex]\text{number of moles}=\frac{\text{given mass}}{\text{molar mass}}[/tex]

For [tex]NH_{3},[/tex]

[tex]\text{given mass}=3g[/tex]

[tex]\text{molar mass}=14+3=17g[/tex]

[tex]n_{NH_{3}}=\frac{3}{17}=0.176[/tex]

For [tex]HCl,[/tex]

[tex]\text{given mass}=5g[/tex]

[tex]\text{molar mass}=1+35.5=36.5g[/tex]

[tex]n_{HCl}=\frac{5}{36.5}=0.136[/tex]

The reaction between [tex]NH_{3}[/tex] and [tex]HCl[/tex] is

[tex]NH_{3}+HCl[/tex]→[tex]NH_{4}Cl[/tex]

So,one mole of [tex]NH_{3}[/tex] requires one mole of [tex]HCl[/tex]

[tex]0.176[/tex] moles of [tex]NH_{3}[/tex] requires [tex]0.176[/tex] moles of [tex]HCl[/tex]

But there are only [tex]0.136[/tex] moles of [tex]HCl[/tex] available.

[tex]HCl[/tex] will be consumed first.

So,[tex]HCl[/tex] is the limiting reagent.