What is required for real-time surveillance of a suspects computer activity?/p Group of answer choices a. Blocking data transmissions between a suspect’s computer and a network server. b. Poisoning data transmissions between a suspect’s computer and a network server. c. Preventing data transmissions between a suspect’s computer and a network server. d. Sniffing data transmissions between a suspect’s computer and a network server.

Answer:

Check the explanation

Explanation:

# include <iostream>

#include<iomanip>

using namespace std;

int main ()

{double start,balance,rate,deposit=0,withdraw=0,amt,sum,totInterest=0,interest;

int i;

cout<<setprecision(2)<<fixed;

cout<<"Enter starting balance: ";

cin>>balance;

start=balance;

cout<<"Enter annual interest rate: ";

cin>>rate;

rate/=12.;

for(i=1;i<=3;i++)

  {cout<<"For month "<<i<<endl;

  sum=balance;

   cout<<"Enter total amount deposit: ";

   cin>>amt;

   while(amt<0)

       {cout<<"Must not be negative-retry\n";

       cout<<"Enter total amount deposit: ";

       cin>>amt;

       }

   deposit+=amt;

   balance+=amt;

   cout<<"Enter total amount withdrawn: ";

   cin>>amt;

   while(amt<0||amt>balance)

       {cout<<"Must not be negative, or greater than balance ($"<<balance<<")-retry\n";

       cout<<"Enter total amount withdrawn: ";

       cin>>amt;

       }

   withdraw+=amt;

   balance-=amt;

   interest=(sum+balance)/2.*rate;

   totInterest+=interest;

   balance+=interest;

}

cout<<"Starting balance at the beginning of the three month period: $"<<start<<endl;

cout<<"total deposits made during the three months: $"<<deposit<<endl;

cout<<"total withdrawals made during the three months: $"<<withdraw<<endl;

cout<<"total interest posted to the account during the three months $"<<totInterest<<endl;

cout<<"final balance: $"<<balance<<endl;

system("pause");

return 0;

}

Kindly check the output in the attached image below.

Answer:

Answer is in the attached screenshot!

Explanation:

Iterate through the given input strings, create a student class with the given name, assign the output array to the value of the class created from the given input string. Finally, return the array.

An E-R diagram for a library database would include entities for books, publishers, authors, and series, with relationships defined between them. A many-to-many relationship between authors and books, as well as books and series, requires the use of Junction Tables to effectively manage these complex relationships.

Development of an E-R Diagram Based on a Description

A book is identified by its ISBN number, and it has a title, price, and date of publication. Each book is published by a publisher that has a unique ID number and name. There is a one-to-many relationship between publishers and books since each book has exactly one publisher, but a publisher can publish multiple books. Conversely, a book is written by authors, and each author has an author number, name, and date of birth, indicating a many-to-many relationship between authors and books. To address this, we introduce a Junction Table to split the many-to-many into two one-to-many relationships. Each author could have written multiple books, and each book could have multiple authors.

Furthermore, books can be part of a series, with a series being identified as a book with its own ISBN number. A single book can belong to multiple series, creating a many-to-many relationship between books and series. Again, a Junction Table is needed to properly manage this relationship. The database also includes information about prospective authors who haven't published books yet, signifying the importance of having an authors' table regardless of publication status.

The Entity Relationship Modeling (ERM) process begins with determining the purpose of the database and listing all the necessary entities. These entities are then connected through relationships, with Junction Tables being used to resolve many-to-many relationships. Important attributes and keys for each entity are identified, ensuring that adequate information is recorded and can be retrieved effectively.

Answer:

Check the explanation

Explanation:

If raw_input() shows some error in Python v3 then call input() instead of raw_input().

def menu():

              option = 'n'

              while option not in ['r','p','d','h','l','q']:

                             print("Menu of choices:")

                             print("\t(r)ead employee data")

                             print("\t(p)rint employee payroll")

                             print("\t(d)isplay an employee by name")

                             print("\tfind (h)ighest paid employee")

                             print("\tfind (l)owest paid employee")

                             print("\t(q)uit")

                             option = input("Please enter your choice: ")

                             if option not in ['r','p','d','h','q']:

                                                                          print("Invalid choice. Please try again\n")

                             return option

def readEmployees(names,wages,hours):

              fileRead = 0

              try:

                             filename = input("Enter the file name: ")

                             f = open(filename,"r")

                             for line in f:

                                            values = line.split("\t")

                                            names.append(values[0])

                                            wages.append(float(values[1]))

                                            i=0

                                            total = 0

                                            while i < 5:

                                                           total = total + float(values[2+i])

                                                           i = i+1

                                            hours.append(total)

                             fileRead = 1

                             f.close()

              except ValueError:

                             print("Bad data in file " + filename)

              except IOError:

                             print("Error reading file " + filename)

              return fileRead

def printPayroll(names,wages,hours):

              print("")

              print("Name"+"    "+"Hours"+"    "+"Pay")

              print("----"+"    "+"-----"+"    "+"---")

              i = 0

              sortedNames = names

              sortedNames.sort()

              totalpay = 0

              for name in sortedNames:

                             i = names.index(name)

                             pay = hours[i] * wages[i]

                             name = names[i]

                             totalpay = totalpay + pay

                             name = repr(name).ljust(10)

                             name = name.replace("'","")

                             print( name + repr(hours[i]).ljust(9) + repr(pay).ljust(6))

                             i = i + 1

              print("\nTotal payroll = $" + str(totalpay))

def displayName(names,wages,hours):

              name = ""

              i=0

              size = len(names)

              name = input("Enter the employee's name: ")

              while i < size:

                             if names[i].lower() == name.lower():

                                            wage = wages[i]

                                            hour = hours[i]

                                            break

                             i = i +1

              if i == size:

                             print("Employee not found")

              else:

                             print(name + " worked " + str(hour) + " hours at $" + str(wage) + " per hour, and earned $" + str(wage * hour) + "\n")

def showHighLow(names,wages,hours, ind):

              highestIndex = 0

              if ind == 'h':

                             i =1

                             size = len(names)

                             wage = 0;

                             while i < size:

                                            wage = hours[i] * wages[i]

                                            if wage > (hours[highestIndex] * wages[highestIndex]):

                                                           highestIndex = i

                                            i = i + 1

                             print(names[highestIndex] + " earned $" + str(hours[highestIndex] * wages[highestIndex]) + "\n")

              elif ind == 'l':

                             lowestIndex = 0;

                             i =1

                             size = len(names)

                             wage = 0;

                             while i < size:

                                                                          wage = hours[i] * wages[i]

                                                                          if wage < (hours[lowestIndex] * wages[lowestIndex]):

                                                                                                                                      lowestIndex = i

                                                                          i = i + 1

                             print(names[lowestIndex] + " earned $" + str(hours[lowestIndex] * wages[lowestIndex]) + "\n")

def main():

              option = 'n'

              names    = list()

              wages    = list()

              hours    = list()

              fileRead = 0

              while option != 'q':

                             option = menu()

                             if option == 'r':

                                            fileRead = readEmployees(names,wages,hours)

                             elif option == 'p':

                                            if fileRead == 0:

                                                           print("Employee data has not been read.")

                                                           print("Please read the file before making this choice")

                                            else:

                                                           printPayroll(names,wages,hours)

                             elif option == 'd':

                                            if fileRead == 0:

                                                           print("Employee data has not been read.")

                                                           print("Please read the file before making this choice")

                                            else:

                                                           displayName(names,wages,hours)

                             elif option == 'h':

                                            if fileRead == 0:

                                                           print("Employee data has not been read.")

                                                           print("Please read the file before making this choice")

                                            else:

                                                           showHighLow(names,wages,hours,'h')

                             elif option == 'l':

                                            if fileRead == 0:

                                                           print("Employee data has not been read.")

                                                           print("Please read the file before making this choice")

                                            else:

                                                           showHighLow(names,wages,hours,'l')

                             elif option == 'q':

                                            print("GoodBye")

if __name__ == "__main__":

              main()

Kindly check the OUTPUT in the attached image below.

Answer:

import java.util.Scanner;

public class num8 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter first number");

       int X = in.nextInt();

       System.out.println("Enter second number");

       int Y = in.nextInt();

       int Z;

       if(X <= Y){

           Z = 0;

       }

       else if(X >= Y){

           Z = 1;

       }

   }

}

Explanation:

Answer:

#The program sets Z to 0 if the X <= Y. otherwise sets Z to 1 , if the X > Y.

clear Z; # sets Z to 0

clear U; # sets U to 0

clear V; # sets v to 0

clear T; # sets T to 0

while Y not 0 # repeat until Y times

# process to decrement Y by 1

while Y not 0

incr U;

decr Y;

decr U;

while U not 0

incr Y;

decr U;

#process to decrement X by 1

while X not 0

incr V

decr X;

while V not 0

decr V;

while V not 0

incr T;

decr V;

while T not 0

incr X

decr T

#end of main while loop

#after running the main while loop, X will be positive and non - zero number, # #if X > Y. otherwise X and Y will be zero.

#process to increment Z by 1, if X is positive and non - zero number

while X not 0

while X not 0

decr X;

incr Z;

#end of while

Explanation:

The program is totakes in as input two variables X and Y.

The main function of the program is to return or place a 0 in the variable Z if the variable X is less than or equal to Y, and place a 1 in the variable Z if the variable X is greater than Y.

When these conditions are met, end program.

Answer:

='[Finance.xlsx]Fall2018'!$D$20

Explanation:

The formula that will correctly links to cell D20 in the Fall 2018 worksheet within the Finance workbook is given as:

='[Finance.xlsx]Fall2018'!$D$20

This will perform the operation and produce the required output.

Answer:

See attached solution

Explanation:

Answer:

see explaination

Explanation:

#include <iostream>

#include <fstream>

#include <iomanip>

using namespace std;

int main()

{

string filename, file1, file2, file3, file4;

cout << "Enter the filename : ";

getline(cin, filename);

int row, col;

ifstream ifile;

ifile.open(filename.c_str());

if(!ifile)

{

cout << "File does not exist." << endl;

}

else

{

ifile >> row >> col;

float mat[row][col], diag[row][col];

for(int i=0; i<row; i++)

{

for(int j=0; j<col; j++)

ifile >> mat[i][j];

}

cout << "Enter the filename to save averages : ";

getline(cin, file1);

ofstream avgFile(file1.c_str(), std::fstream::in | std::fstream::out | std::fstream::app);

float t_avg = 0, avg = 0;

for(int i=0; i<row; i++)

{

avg = 0;

for(int j=0; j<col; j++)

{

avg += mat[i][j];

}

t_avg += avg;

avg = avg/col;

avgFile << std::fixed << std::setprecision(1) << "Row " << i+1 << " average: " << avg << endl;

}

t_avg = t_avg / (row*col);

avgFile << std::fixed << std::setprecision(1) << "Total average: " << t_avg << endl;

cout << "Enter the filename to store reverse matrix : ";

getline(cin, file2);

ofstream revFile(file2.c_str(), std::fstream::in | std::fstream::out | std::fstream::app);

for(int i=0; i<row; i++)

{

for(int j=col-1; j>=0; j--)

{

revFile << std::fixed << std::setprecision(1) << mat[i][j] << " ";

}

revFile << endl;

}

cout << "Enter the filename to store flipped matrix : ";

getline(cin, file3);

ofstream flipFile(file3.c_str(), std::fstream::in | std::fstream::out | std::fstream::app);

for(int i=row-1; i>=0; i--)

{

for(int j=0; j<col; j++)

{

flipFile << std::fixed << std::setprecision(1) << mat[i][j] << " ";

}

flipFile << endl;

}

cout << "Enter the filename to store diagonal matrix : ";

getline(cin, file4);

ofstream diagFile(file4.c_str(), std::fstream::in | std::fstream::out | std::fstream::app);

for(int i=0; i<row; i++)

{

for(int j=0; j<col; j++)

{

diag[j][i] = mat[i][j];

}

}

for(int i=0; i<col; i++)

{

for(int j=0; j<row; j++)

{

diagFile << std::fixed << std::setprecision(1) << diag[i][j] << " ";

}

diagFile << endl;

}

}

return 0;

}

Answer:

see explaination and attachment

Explanation:

We can say that a Gantt chart is a visual view of tasks scheduled over time. Gantt charts are used for planning projects of all sizes and they are a useful way of showing what work is scheduled to be done on a specific day.

see attachment for the detailed step by step solution.

Answer:

is_isbn = True

total = 0

number = input("Enter the ISBN: ")

if len(number) != 10:

   is_isbn = False

for i in range(9):

   if 0 <= int(number[i]) <= 9:

       total += int(number[i]) * (10 - i)

   else:

       is_isbn = False

if number[9] != 'X' and int(number[9]) > 9:

   is_isbn = False

if number[9] == 'X':

   total += 10

else:

   total += int(number[9])

if total % 11 != 0:

   is_isbn = False

if is_isbn:

   print("It is a valid ISBN")

else:

   print("It is NOT a valid ISBN")

Explanation:

Initialize the variables, total and is_isbn - keeps the value for the number if it is valid or not

Ask the user for the ISBN number

If number's length is less than 10, it is not valid, set is_isbn to false

Then, make calculation to verify the ISBN

Check the last digit, if it is not "X" and greater than 10, it is not valid, set is_isbn to false

Again, check the last digit, if it is "X", add 10 to the total, otherwise add its value

Check if total can divide 11 with no remainder. If not, it is not valid, set is_isbn to false

Finally, depending on the is_isbn variable, print the result

Answer:

See explaination

Explanation:

The program code

PastPresentFuture.java

import java.util.*;

import java.time.LocalDate;

public class PastPresentFuture

{

public static void main(String args[])

{

/*Initializing an array with days of month in a sequence, february with 28 days - it would be changed afterwards if the year entered is a leap year.*/

int daysOfmonth[]={31,28,31,30,31,30,31,31,30,31,30,31};

LocalDate today=LocalDate.now();

int mo,da,yr;

int todayMo,todayDa,todayYr;

//storing the values of today's day,month & year in 3 variables

todayMo=today.getMonthValue();

todayDa=today.getDayOfMonth();

todayYr=today.getYear();

//taking inputs of day,month & year from console which would be used later for checking

Scanner input=new Scanner(System.in);

System.out.println(":::Program to find whether a date is in past/present/future:::");

System.out.print("Enter month::");

mo=input.nextInt();

System.out.print("Enter day::");

da=input.nextInt();

System.out.print("Enter year::");

yr=input.nextInt();

/*finding whether the entered year is leap year or not based on standard logic and making the days of february to 29 if it is a leap year.*/

if(yr%100==0)

{

if(yr%400==0)

daysOfmonth[1]++;

}

else

{

if(yr%4==0)

daysOfmonth[1]++;

}

System.out.print("The date you entered -- ");

/*checking if the month value is between 1 to 12 and day entered is with in the boundary limits of the respective month using the array initialized above.

if the date entered is invalid, we are informing the user about the same and stopping the program.*/

if(!(mo>=1 && mo<=12 && da>=0 && da<=daysOfmonth[mo-1]))

{

System.out.println("invalid !!");

System.exit(0);

}

//logic to print the 4 statements as per the question

if(yr!=todayYr)

System.out.println(yr+" not this year.");

else

if(mo<todayMo)

System.out.println("month "+mo+" in an earlier month this year.");

else

if(mo>todayMo)

System.out.println("month "+mo+" in a later month this year.");

else

System.out.println("month "+mo+" is this month.");

}

}

Final answer:

The provided transaction log represents updates made to the 'Part' table in a database, recording the details of each transaction and the changes made to specific rows.

Explanation:

The transaction log provided represents a series of updates made to the 'Part' table in a database. Each transaction is recorded with a unique 'TRL_ID' and 'TRX_ID'. The 'OPERATION' column indicates the type of operation performed (e.g., START, UPDATE, COMMIT). The 'TABLE' column specifies the table that was updated, and the 'ROW ID' column represents the specific row that was modified. The 'BEFORE VALUE' and 'AFTER VALUE' columns show the original and final values of the updated attribute.

Answer:

See explaination

Explanation:

A protocol in computing can be defined as a standard set of rules that allow electronic devices to communicate with each other. These rules include what type of data may be transmitted, what commands are used to send and receive data, and how data transfers are confirmed. You can think of a protocol as a spoken language.

Please kindly check attachment for for the details of the answer.

Here, A-->B : ID means protocol is issued authentic A to B.

(b). According to the question it is based on asymmetric key encryption technique, Let us assume any third-party K could use the given below assumption:

Learn more about:

https://brainly.com/question/17495888

Answer:

Technology is the skills, methods, and processes used to achieve goals. People can use technology to: Produce goods or services. Carry out goals, such as scientific investigation or sending a spaceship to the moon. Solve problems, such as disease or famine.

Explanation:

Good Luck!

Technology refers to the application of scientific knowledge, tools, and techniques for practical purposes.

Technology involves the creation, development, and utilization of various systems, methods, processes, and devices to solve problems, improve efficiency, enhance productivity, and achieve specific goals in different domains.

Technology encompasses a wide range of fields and disciplines, including engineering, computer science, electronics, telecommunications, biotechnology, information technology, and more. It involves the design, production, and utilization of tangible and intangible artifacts, such as machinery, software, infrastructure, systems, algorithms, and networks.

Technology is constantly evolving and advancing, driven by research, innovation, and human creativity. It plays a significant role in shaping societies, economies, and cultures, influencing various aspects of our lives.

Overall, technology encompasses the tools, knowledge, and systems that enable the practical application of scientific understanding to address challenges, improve efficiency, and enhance human experiences in the modern world.

Learn more about Technology here:

https://brainly.com/question/9171028

#SPJ6

Answer:

Check the explanation

Explanation:

using System;

using System.IO;

public class Program

{

  public static void Main()

  {

      string[] lines;

      Console.WriteLine("enter name of the file");

      String fileName=Console.ReadLine();

      Console.WriteLine("enter path of the file");

      String filePath=Console.ReadLine();

      using (StreamReader streamReader = File.OpenText(filePath))

      {

          String text = streamReader.ReadToEnd();

          lines = File.ReadAllLines(filePath);

      }

      Console.WriteLine("Enter path of the file to write");

      String outputFilePath = Console.ReadLine();

      bool fileExist = File.Exists(outputFilePath);

      if (fileExist)

      {      

                  overWriteOrChangeFileName(outputFilePath);          

      }

      else

      {

          File.Create(outputFilePath);

          File.WriteAllLines(outputFilePath, lines);

      }

      Console.Write("Input file Path"+filePath);

      Console.Write("output file path"+outputFilePath);

      void overWriteOrChangeFileName(String filePathtoCheck){

          Console.WriteLine("File exists. Do you want to overwrite the file or do you want to change the location and file name of the new file.Press Y to overwrite and press C to change the location and filename");

          String userInput=Console.ReadLine();

          if(userInput.Equals("Y")){

File.WriteAllLines(outputFilePath, lines);

          }else{

              Console.WriteLine("enter new path of the file including filename");

              String NewFileName=Console.ReadLine();

              outputFilePath=NewFileName;

              if(File.Exists(outputFilePath)){

                  overWriteOrChangeFileName(outputFilePath);                  

              }

              else

      {

          File.Create(outputFilePath);

          File.WriteAllLines(outputFilePath, lines);

      }

          }

      }

  }

}

Answer:

seeexplaination

Explanation:

Code(header file):

#ifndef THROTTLESHIFTLVEL_H

#define THROTTLESHIFTLVEL_H

class throttle

{

int position;

public:

throttle()

{

position = 0;

}

// specify the number of shift levels when creating objects

throttle(int level)

{

position = level;

}

void shut_off()

{

position = 0;

}

void shift(int amount)

{

if(amount >= 0)

position = position + amount;

}

double flow() const

{

return position;

}

bool is_on() const

{

if (position > 0)

return true;

else

false;

}

};

#endif

Please kindly check attachment for screenshot

Final answer:

To create a new throttle ADT with a customizable number of shift levels, define the class with an additional parameter in the constructor. Provide methods for shifting the throttle to a specific level and releasing it.

Explanation:

The modified definition of the throttle class to create a new throttle ADT, which allows the user to specify the number of shift levels, can be written as follows:

class Throttle:

   def __init__(self, shift_levels):
       self.shift_levels = shift_levels

   def shift(self, level):
       # shift the throttle to the specified level
       pass

   def release(self):
       # release the throttle
       pass

Answer:

Windows includes a tool called Microsoft System Information (Msinfo32.exe). This tool gathers information about your computer and displays a comprehensive view of your hardware, system components, and software environment, which you can use to diagnose computer issues.

Explanation:

Answer:

#include <stdio.h>

int main()

{

//Store temp in Fahrenheit

int temp_fahrenheit;

//store temp in Celsius

float temp_celsius;

printf("\nTemperature conversion from Fahrenheit to Celsius is given below: \n\n");

printf("\n%10s\t%12s\n\n", "Fahrenheit", "Celsius");

//For loop to convert

temp_fahrenheit=0;

while(temp_fahrenheit <= 212)

{

temp_celsius = 5.0 / 9.0 *(temp_fahrenheit - 32);

printf("%10d\t%12.3f\n", temp_fahrenheit, temp_celsius);

temp_fahrenheit++;

}

return 0;

}

Explanation:

The program above used a while loop for its implementation.

It is a temperature conversion program that converts integer Fahrenheit temperatures from 0 to 212 degrees to floating-point Celsius temperatures with 3 digits of precision.

This can be calculated or the calculation was Perform using the formula celsius = 5.0 / 9.0 * ( fahrenheit - 32 ).

The expected output was later printed in two right-justified columns of 10 characters each, and the Celsius temperatures was preceded by a sign for both positive and negative values.

Answer:

Explanation:

CHECK THE ANSWER IN THE ATTACHMENT CORNNER

Answer:

Explanation:

K- is the working procedure:

It takes n no. of predefined cluster as input and data points.

It also randomly initiate n centers of the clusters.

In this case the initial centers are given.

Steps you can follow

Step 1. Find distance of each data points from each centers.

Step 2. Assign each data point to the cluster with whose center is nearest to this data point.

Step 3. After assigning all data points calculate center of the cluster by taking mean of data points in cluster.

repeat above steps until the center in previous iteration and next iteration become same.

A1(4,8), A2(2, 4), A3(1, 7), B1(5, 4), B2(5,7), B3(6, 6), C1(3, 7), C2(7,8)

Centers are X1=A1, X2=B1, X3=C1

A1 will be assigned to cluster1, B1 will be assigned to cluster2 ,C1 will be assigned to cluster3.

Go through the attachment for the solution.

The k-means algorithm is used to cluster data points into partitions based on their attributes, using the Euclidean distance function. After the first round of execution, the cluster centers are A1(4, 8), B1(5, 4), and C1(3, 7). The final points in the three clusters after the algorithm stops may include A1(4, 8), A2(2, 4), A3(1, 7), B1(5, 4), B2(5, 7), B3(6, 6), C1(3, 7), and C2(7, 8).

The k-means algorithm is used to cluster data points into partitions based on their attributes. In this case, we are clustering points in a two-dimensional space (x, y) into three clusters using the Euclidean distance function. The k-means algorithm involves initializing the cluster centers, iteratively recalculating the centroids, and reassigning the data points to the new centroids. The algorithm continues until convergence or a certain number of iterations.

(a) After the first round of execution, the three cluster centers are A1(4, 8), B1(5, 4), and C1(3, 7).

(b) The final points in the three clusters after the algorithm stops might be A1(4, 8), A2(2, 4), A3(1, 7) in one cluster, B1(5, 4), B2(5, 7), B3(6, 6) in another cluster, and C1(3, 7), C2(7, 8) in the third cluster. The exact assignment of points to clusters may vary depending on the distance calculations and convergence criteria used in the algorithm.

Answer:

According to IEEE-754 standard,equivalent  decimal of 32 bit floating point number is 78.1025390625

Explanation:

To convert the 32 bit floating point number from hexadecimal to decimal, following steps will be completed.

1. Convert this hexadecimal value "C29C3480" into binary number. Each digit in hexadecimal will convert into 4 bits of binary.

There

C= 1100

2 = 0010

9 =  1001

C = 1100

3 = 0011

4= 0100

8 = 1000

0 = 0000

So the number will be converted as given below:

1100 0010 1001 1100 0011 0100 1000 0000

2. Arrange the bits in order

1   = Sign bit = 32nd bit                 

10000101 = Exponent bits = From 31st to 23rd bits

00111000011010010000000 = Fraction bits= From 22nd to 0th bit

As the 32nd  bit, which is sign bit, is 1, so given number is negative.

3. Convert the Exponent bits into decimal values

10000101 = 1x2⁷+0x2⁶+0x2⁵+0x2⁴+0x2³+1x2²+0x2¹+1x2⁰

               = 1x2⁷ + 1x2² + 1x2⁰

               = 128 + 4 + 1 =  133

4. Calculate Exponent Bias

      exponent bias = 2ⁿ⁻¹ - 1

there n is total number of bits in exponent value of 32 bit number, Now in this question n=8, because there are total 8 bits in exponent.

 so,       exponent bias = 2⁸⁻¹ - 1 = 2⁷-1= 128-1= 127

         e = decimal value of exponent - exponent bias

          e  =     133 - 127 = 6

5.  Convert Fraction part into Decimal

 Mantissa=0x2⁻¹+0x2⁻²+1x2⁻³+1x2⁻⁴+1x2⁻⁵+0x2⁻⁶+0x2⁻⁷+0x2⁻⁸+0x2⁻⁹+1x2⁻¹⁰+1x2⁻¹¹+0x2⁻¹²+1x2⁻¹³+0x2⁻¹⁴+0x2⁻¹⁵+1x2⁻¹⁶+0x2⁻¹⁷+0x2⁻¹⁸+0x2⁻¹⁹+0x2⁻²⁰+0x2⁻²¹+0x2⁻²²+0x2⁻²³

              = 1x2⁻³+1x2⁻⁴+1x2⁻⁵+1x2⁻¹⁰+1x2⁻¹¹+1x2⁻¹³+1x2⁻¹⁶

              =  0.125 + 0.0625 + 0.03125 + 0.0009765625 + 0.00048828125 +                     0.00012207031 + 0.00001525878

Mantissa = 0.22035217284

6. Convert the number into decimal

Decimal number = (-1)^s x (1+Mantissa) x 2^e

there

s is the sign bit which is 1,

and

e =6.

so,

decimal number = (-1)^1 x (1+0.22035217284 ) x 2⁶

                           = -1 x 1.22035217284 x 64

                           = -78.1025390625

Answer:

Check the explanation

Explanation:

class CitiesAndCountries:

   """

   This is the class which maintains a dictionary of the Countries with the cites in them.

   """

   def __init__(self):

       """

       Constructor for the class CitiesAndCountries.

       It defines a dictionary to store the names of the countries and a list of the cities which are in them

       Example of the the following dictionary when it is populated:

       citiesandcountries = {"india":["bhopal", "mumbai", "nagpur"], "usa":["new york", "seatlle"]

       Keeping the names in lowercase helps in search

       """

       self.citiesandcountries = {}  # This is the dictionary which stores the information

   def add_country(self, country_name):

       """

       The add_country function to add countries to our list.

       :param country_name: Name of the country to add to the dictionary

       :return: True if added to the dictionary, False if it is already present in the dictionary

       """

       if country_name.lower() not in self.citiesandcountries.keys():

           self.citiesandcountries[country_name.lower()] = [] # Storing the country name in lower case helps in

           # searching

           return True

       else:  # You could omit the else statement and directly return False, but it adds to readability.

           return False

   def add_city(self, country_name, city_name):

       """

       This function adds the cities names to the dictionary corresponding to their countries.

       :param country_name: Country to which the city belongs

       :param city_name:  Name of the city to be added

       :return: True if the country is present in the dictionary and the city is added to the list, else False

       """

       if country_name.lower() in self.citiesandcountries.keys():

           self.citiesandcountries[country_name.lower()].append(city_name.lower())

           return True

       else:

           return False

   def find_city(self, city_name):

       """

       This function is used to retrive a list of countries where the city with the given name is present

       :param city_name: Name of the city.

       :return: A list of all the countries where the city if present.

       """

       countries_with_city = []

       for country in self.citiesandcountries.keys():

           if city_name.lower() in self.citiesandcountries[country]:

               countries_with_city.append(country.title())

       return countries_with_city

Answer:

Check the explanation

Explanation:

Please find the sql statements (as numbered in the question) below:

1. DEPARTMENT TABLE

CREATE TABLE DEPARTMENT (

DepartmentName varchar (50),

BudgetCode varchar (50),

OfficeNumber varchar (50),

OfficeNumber varchar (50),

Phone varchar (50)

);

2. EMPLOYEE TABLE

CREATE TABLE EMPLOYEE (

EmployeeNumber varchar (50),

FirstName varchar (50),

LastName varchar (50),

Phone varchar (50),

Email varchar (50) NOT NULL UNIQUE,

DepartmentName varchar (50) FOREIGN KEY REFERENCES DEPARTMENT(DepartmentName) ON UPDATE CASCADE

);

3. PROJECT TABLE

CREATE TABLE PROJECT (

ProjectID varchar (50),

Name varchar (50),

MaxHours FLOAT,

Date() AS StartDate,

Date() AS EndDate,

DepartmentName varchar (50) FOREIGN KEY REFERENCES DEPARTMENT(DepartmentName) ON UPDATE CASCADE

);

Answer:

This question is incomplete, here's the complete question:

1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute. 3. Use the single-server drive-up bank teller operation referred to in Problems 1 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Explanation:

Arrival rate \lambda = 24 customers per hour or 0.4 customers per minute

Service rate \mu​ = 36 customers per hour or 0.6 customers per minute (from problem 1)

a.) The probability that no customers are in the system , P0 = 1 - \lambda / \mu

= 1 - (24/36) = 1/3 = 0.3333

b.) The average number of customers waiting

Lq = \lambda^2 / [\mu(\mu - \lambda)] = 242 / [36 * (36 - 24)] = 1.33

c.) The average number of customers in the system.

L = Lq + \lambda / \mu = 1.33 + (24/36) = 2

d.) The average time a customer spends waiting.

Wq = \lambda / [\mu(\mu - \lambda)] = 24 / [36 * (36 - 24)] = 0.0555 hr = 3.33 min

e.) The average time a customer spends in the system

W = Wq + 1/\mu = 0.0555 + (1/36) = 0.0833 hr = 5 min

f.) The probability that arriving customers will have to wait for service.

= 1 - P0 = 1 - 0.3333 = 0.6667

Answer:

def str_replace(int_list, index):

   if int_list[index] < 7:

       int_list[index] = "small"

   elif int_list[index] > 7:

       int_list[index] = "large"

   return int_list

Explanation:

I believe you forgot to mention the comparison value. I checked if the integer at the given index is smaller/greater than 7. If that is not your number to check, you may just change the value.

Create a function called def str_replace that takes two parameters, an integer list and an index

Check if the number in given index is smaller than 7. If it is replace the number with "small".

Check if the number in given index is greater than 7. If it is replace the number with "large".

Return the list

The str_replace function replaces an integer in a list with 'small' or 'large' depending on the value. It demonstrates basic list manipulation and conditional logic in programming.

The str_replace function is designed to take a list of integers and an index. The function will check the value at the given index, and if the integer is less than 5, it will be replaced with the string "small"; if the integer is 5 or greater, it will be replaced with the string "large". This is a basic operation in programming, often related to the concept of list manipulation and conditional statements. Here's a step-by-step example in Python:

To check for a matching pair of nuts and bolts in O(n) time, perform a linear scan using two indices since the arrays are sorted. Increment the indices appropriately and return true if a match is found before either index exceeds n, otherwise return false.

To solve the problem of finding if there is a matching pair of nuts and bolts in an O(n) time complexity, you can employ a simple linear scan. Since the arrays NUTS and BOLTS are both sorted in increasing order, you can iterate over them simultaneously to check for a match.

Algorithm:

This algorithm is guaranteed to run in O(n) since each list is traversed at most once.

Answer:

We will use hierarchical concepts,superclass and manager interference and use of object oriented programing in python and java and we need to create and call functions as well to solve that problem.

Answer:

see explaination please

Explanation:

a. Install a faster CPU. Answer:NO

Optional: a faster CPU reduces the CPU utilizationfurther since the CPU will spend more time waiting for a process toenter in the ready queue.

b. Install a bigger paging disk. Answer:NO

Optional: the size of the paging disk does not affect theamount of memory that is needed to reduce the pagefaults.

c. Increase the degree of multiprogramming Answer:NO

Since each process would have fewer frames available andthe page fault rate would increase

d. Decrease the degree of multiprogramming.Answer: YES

Optional: by suspending some of the processes, the otherprocesses will have more frames in order to bring their pages inthem, hence reducing the page faults.

e. Install more main memory. Answer:Likely

Optional: more pages can remain resident and do notrequire paging to or from the disks.

f. Install a faster hard disk or multiplecontrollers with multiple hard disks. Answer:Likely

(Optional)

g. Add prepaging to the page-fetchalgorithms.Answer: Likely

(Optional.)

h. Increase the page size. Answer:NO

Since each process would have fewer frames available and the page fault rate would increase

Answer:

We will use script in oracle and SQl(Structured Query Language) and use of algorithms like cipher for encryption to insert a new flight into the flights table for the flight number 165 and that Cipher will show the desired message.