what is rolling friction

Answers

Answer 1
When something rubs on a object with friction and negative charges react so for instance if you had a furry dog with a lot of hair and he rolled on a hairy carpet he would get negative charges.
Answer 2

Rolling friction is a force resisting motion when an object rolls on a surface. An example could be a ball rolling or a tire.


Related Questions

A circular loop of wire with a radius of 4.0 cm is in a uniform magnetic field of magnitude 0.069 t. the plane of the loop is perpendicular to the direction of the magnetic field. in a time interval of 0.46 s, the magnetic field changes to the opposite direction with a magnitude of 0.044 t. what is the magnitude of the average emf induced in the loop?

Answers

The magnitude of the average emf induced in the loop is given by (we ignore the signs since we are interested only in the magnitude)
[tex]\epsilon = \frac{\Delta \Phi_B}{\Delta t} [/tex]
where [tex]\Delta \Phi_B[/tex] is the variation of magnetic flux through the area enclosed by the loop, and [tex]\Delta t[/tex] is the time interval.

The magnetic flux is given by
[tex]\Phi _B = BA\cos \alpha[/tex]
where B is the intensity of the magnetic field, A is the area enclosed by the loop and [tex]\alpha[/tex] is the angle between the perpendicular to the area and the magnetic field. In our problem, this angle is zero because the loop is perpendicular to the magnetic field, so the cosine is 1. The area of the loop is fixed, and it is
[tex]A=\pi r^2[/tex]
where [tex]r=4.0 cm=0.04 m[/tex] is the radius of the loop. The only element which is variable in the formula is B, which changes from 0.069 T to -0.044 T (opposite direction). So we can rewrite the flux variation as
[tex]\Delta \Phi_B = A \Delta B [/tex]
where [tex]\Delta B = 0.069 T-(-0.044 T)=0.113 T[/tex]
By using [tex]\Delta t=0.46 s[/tex], we can find the magnitude of the emf induced:
[tex]\epsilon = \frac{A \Delta B}{\Delta t}= \frac{(\pi (0.04 m)^2)(0.113 T)}{0.46 s}=1.2 \cdot 10^{-3}V [/tex]

A diver who is 10.0 meters underwater experience has a pressure of 202 kPa. If the diver’s surface area is 1.50 meters squared, with how much total force does the water push on the diver?

Answers


Force = 202,200 x 1.5 ms.q
Force = 303,000 newtons 

Final answer:

To determine the total force exerted on the diver, multiply the pressure (in pascals) by the surface area. The total force is 303,000 newtons.

Explanation:

To calculate the total force exerted by the water on a diver who is 10.0 meters underwater, we need to apply the concept of pressure which is defined as force per unit area. Given the pressure experienced by the diver is 202 kPa and the diver's surface area is 1.50 meters squared, we can use the formula Force = Pressure × Area.

First, we need to convert the pressure from kilopascals to pascals since one kilopascal equals 1,000 pascals:

202 kPa × 1,000 = 202,000 Pa

Then, we multiply the pressure by the diver's surface area to find the total force:

Total Force = 202,000 Pa × 1.50 m² = 303,000 N

Therefore, the water pushes on the diver with a total force of 303,000 newtons.

what was perphaps the greatest challenge of human space flight?

Answers

Space is more hostile to the human body.

the risk of human lifes

Rocket engineers use newton's third law during launch. identify the action force.
A. exhaust gases push down on the earth
B. rocket travels upward
C. earth pushes back on the exhaust gases

Answers

The answer is A. Newton's third law of motion states that for every action, there is an equal and opposite reaction. A rocket exerts a large force on the gas that is in the rocket chamber (action). The gas thus exerts a large reaction force forward on the rocket (reaction). The large reaction force is called thrust.
Final answer:

The action force in this scenario is earth pushes back on the exhaust gases.

Explanation:

The action force in this scenario is option C: earth pushes back on the exhaust gases.

Newton's third law states that for every action, there is an equal and opposite reaction. In this case, the action force is the exhaust gases pushing downward on the earth as the rocket launches. The reaction force is the earth pushing back on the exhaust gases with an equal force in the opposite direction.

So, while the rocket is traveling upward, the action force is the exhaust gases pushing downward on the earth and the reaction force is the earth pushing back on the exhaust gases.

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Using Figure 25-2, determine how Giant stars differ from main sequence stars.

Answers

Main sequence stars lay on a diagonal going from upper left angle to lower right angle. Part of main sequence is our Sun.

When we observe this diagram we need to compare giant stars and main sequence stars. GIant stars are positioned to upper right when compared to main sequence. From labels on coordinate axis we can see that giant stars generaly have lower temperature than main sequence stars. They also have higher brightness and lower magnitude (meaning that they are more bright in night sky).

Answer:

Giant stars differ from main sequence stars in having greater absolute magnitudes for the same temperatures.

What does 34.9cL equal in hL

Answers

Hello,

The answer is "0.00349 hL".

Reason:

34.9cL=0.00349hL

(Remember to go left 6 places when doing this question)

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit 


A 0.70 kg teddy bear is nudged off a window sill and falls 3.35 m to the ground. what is its kinetic energy at the instant it hits the ground?

Answers

This question can be solved by using kinetic-potential energy postulate. It states that for any point sum of potential and kinetic energy of a body is same.

[tex] E_{sum} = E_{kinetic}+ E_{potential}[/tex]

At the given height potential energy is:
[tex]E_{potential} =m*g*h \\ E_{potential} =0.70*3.35*9.81 \\ E_{potential} =23J[/tex]

When the body reaches ground height is 0m and the potential energy is 0J. This means that all potential energy is transformed into kinetic energy.
[tex]E_{kinetic} =23J[/tex]

At the moment when body hits the ground the kinetic energy is 23J.

Final answer:

The kinetic energy of the teddy bear at the point of impact is calculated using the conservation of energy principle, which yields 22.883 Joules.

Explanation:

The question asks for the kinetic energy of a 0.70 kg teddy bear at the instant it hits the ground after falling from a window sill 3.35 m high. To solve this, we can use the principle of conservation of energy, specifically that the potential energy of the teddy bear at the height from which it is dropped is fully converted into kinetic energy at the moment it hits the ground.

The formula for kinetic energy (KE) is KE = 1/2 m v^2, where m is mass and v is velocity.

However, since the velocity at the moment of impact is not directly provided, we use the gravitational potential energy formula :

PE = mgh, where g is the acceleration due to gravity 9.8 m/s2 and h is the height to find the energy involved.

Because PE at the height is equal to KE at the ground, KE = mgh. Substituting the given values: KE = 0.70 kg * 9.8 m/s2 * 3.35 m.

Thus, the kinetic energy at the instant the teddy bear hits the ground is 22.883 J (Joules).

a rectangular garden has a perimeter of 54 feet. it's length is 3 less than twice its width. write and solve an equation to solve for the gardens dimensions

Answers

2(L+W)=54
L=2W-3
Substitute L in the first equation:
2((2W-3)+W)=54. 
Divide by 2:
(2W-3)+W=27
Simplify by collecting like terms:
3W-3=27. 
Add 3:
3W=30.
Divide by 3 to get that 
W=10. 
Substitute the L and W relations to get 
L=2W-3
L=2*10-3
L=17. 
The answers are length is 17 and width is 10.

Convection currents occur in fluids because of temperature and______ differences. Convection currents transfer ______ energy throughout a fluid. They continue until all of the fluid is at the same temperature

Answers

Solution: (i) Density (ii) thermal

Liquids at lower temperatures have greater density when compared to liquids at higher temperatures.This is because, at higher temperatures, molecules have greater kinetic energy and hence they are spaced farther apart, when compared to molecules at lower temperatures. Thus, the colder layers of liquids are heavier than the warmer layers, which causes then to move down due to gravity. For the same reason, the hotter layers move upwards through the liquid.

When a liquid is heated, the molecules closest to the heat source have greater energy, their density becomes less and they move upwards. The colder layers sink downwards. The layers of the liquid which were cold initially, get heated and they travel upwards. As the process repeats, convection currents are set up in the liquid.

These currents transfer the thermal energy derived from the source throughout the liquid. The process stops when the entire liquid is at the same temperature.

Thus, convection currents occur in liquids due to temperature and density differences. Convection currents transfer thermal energy throughout a fluid.

Convection currents occur in fluids because of temperature and density differences. Convection currents transfer thermal energy throughout a fluid. They continue until all of the fluid is at the same temperature.

What is the relation between kinetic energy and density?

As we know about the relationship between kinetic energy and density. Density is inversely proportional to the temperature while the temperature is directly proportional to kinetic energy showing that kinetic energy is inversely proportional to density.

This is because, at higher temperatures, molecules have greater kinetic energy and the colder layer has less density than the hotter layer due to the density difference under the influence of density the colder layer moves downward resulting in the setup of convective heat transfer.

Due to the movement of molecules and its process repetition and temperature difference convective current transfer takes place and it will continue until the equilibrium process is not achieved.

Hence it shows the relationship between temperature and density. density is inversely proportional to the temperature.

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A transformer changes the 10,000 v power line to 120 v. if the primary coil contains 750 turns, how many turns are on the secondary?

Answers

For a transformer, the ratio between the number of turns of primary and secondary coil is the same as the ratio between the voltages on the two coils:
[tex] \frac{N_p}{N_s}= \frac{V_p}{V_s} [/tex]
Where [tex]N_p[/tex] and [tex]N_s[/tex] are the number of turns in the primary and secondary coils, while [tex]V_p[/tex] and [tex]V_s[/tex] are the voltages on the two coils.

Using the data of the problem: [tex]N_p=750[/tex], [tex]V_p=10000 V[/tex] and [tex]V_s=120 V[/tex], we can find [tex]N_s[/tex], the number of turns of the secondary coil:
[tex]N_s=N_p \frac{V_s}{V_p}=750 \frac{120 V}{10000 V}=9 [/tex]

The standard unit of work in the metric system is named after the scientist _____. 1 Albert Einstein 2 James Joule 3 Isaac Newton 4 James Watt

Answers

James Prescott Joule
I think the answer should be B. James Joule. The standard unit of work in the metric system is named after the scientist it is James Joule.

Hope it helped!

Which graphic design tools help you draw circles and rectangles?

Freehand tool

Geometric Shape tools

Vector Splines

Drawing tool

Answers

drawing tool im not sure if im right but hopes this helps


Geometric shape tools help you draw circles and rectangles. Option B is correct.

What is graphic design?

Graphic design is the practice of using words, pictures, and other visual elements to communicate ideas to an audience, often in order to achieve a certain result.

In other words, graphic design serves as a tool for communicating ideas through imagery and design.

For those with imaginative thinking skills who appreciate art, technology, and communication, graphic design is a terrific job.

Every business has a need for design, therefore graphic designers have a lot of opportunities to work on a variety of brand-new, fascinating projects.

You can draw circles and rectangles using geometric form tools.

Hence, option B is correct.

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the applied force required to push something across a surface as friction increases is what?

Answers

is proportional to the value of the normal force acting on the object.

if you conduct an expiriment that uses lots of paper and plastic how can you practice good science ethics ?

Answers

by recycling all of the unused paper and plastic

A lunar exploration vehicle was created by a research team. It weighs 3,000 kg on the earth. It needs an acceleration of 10 m/s2 on the moon. In order to have the same acceleration, what will be the net force acting on the vehicle on the earth?

Answers

Answer = 30,000 N

EXPLANATION

Applying Newton’s second of law of motion, which in summary, states that the acceleration of an object... is directly proportional to the magnitude of the net force... and inversely proportional to the mass of the object.

Therefore, Force = Mass * Acceleration
F = ma

Mass, m = 3,000 kg
Acceleration, a = 10 m/s²
Force, F = 3,000 × 10
= 30,000 N

The national grid supplied a house with 18000000 J of energy in 1 hour. What was the average current supplied to the house in that hour? Write any equations that you use.

Answers

Electrical power  =  (voltage) x (current)

Electrical energy  =  (power) x (time)

Combine those definitions:

             Energy  =  (voltage) x (current) x (time)

Divide each side by (voltage x time), and we have

             Current  =  Energy / (voltage x time)

You told us that

             Energy = 1.8 x 10⁷ joules

             Time  =  1 hour  =  3,600 seconds

so we have 

             Current  =  (1.8 x 10⁷) / (voltage x 3,600).

If you live in the US, Canada, or Mexico, your voltage is 120 volts.

             Current = (1.8 x 10⁷) / (120 x 3,600)  =  41-2/3 Amperes

If you live practically anywhere else in the world, your voltage is 240 volts.

              Current = (1.8 x 10⁷) / (240 x 3,600)  =  20-5/6 Amperes
Final answer:

The average current supplied to the house in one hour can be found by dividing the energy supplied by the voltage. In this case, the average current is 5 Amperes.

Explanation:

To find the average current supplied to the house, we can use the equation: I = Q / t, where I is the current, Q is the charge, and t is the time. In this case, the energy supplied is 18,000,000 J, so we can find the charge using the equation: Q = E / V, where E is the energy and V is the voltage. Given that the time is 1 hour, we can calculate the average current using the equation: I = Q / t.

First, we need to convert the energy from joules to kilowatt-hours: 1 kWh = 3,600,000 J. So, the energy supplied to the house is 5 kWh.

The average current can now be calculated as follows: I = E / V = 5 kWh / 1 hour = 5 A. Therefore, the average current supplied to the house in that hour is 5 Amperes.

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the potential energy of an apple is 6.00 joules. the apple is 3.00 meters high. what is the mass of the apple?

Answers

By rearranging the formula for gravitational potential energy, we calculate that the mass of the apple is approximately 0.2041 kg when its potential energy is 6.00 joules at a height of 3.00 meters.

To calculate the mass of the apple using its potential energy (PE) and the height (h) at which it is located, we use the formula for gravitational potential energy:

PE = mgh

where:

m is the mass in kilograms,g is the acceleration due to gravity (9.8 m/s² on Earth), andh is the height in meters.

Given that PE = 6.00 Joules and h = 3.00 meters, we rearrange the formula to solve for m:

m = PE / (gh)

Substituting in the known values:

m = 6.00 J / (9.8 m/s² * 3.00 m) = 0.2041 kg

Therefore, the mass of the apple is approximately 0.2041 kg.

3. If you send a sound wave of the same wavelength (λ = 2.00 m) through air, helium, and carbon dioxide, describe how the pitch of the sound will compare through each medium. Use calculations and your data to explain

Answers

The speed of sound is in the gas is given with this formula:
[tex]v=\sqrt{\frac{\gamma RT}{M}}[/tex]
Where T is the temperature, M is the molar mass of the gas, R is universal gas constant and [tex]\gamma[/tex] is heat capacity ratio.
We can find the speed of the sound in different gasses online ( you could also calculate it using above formula). 
[tex]Helium: v_h=1007\frac{m}{s}\\ Air: v_a=343 \frac{m}{s}\\ Carbon Dioxide: v_c=267\frac{m}{s}[/tex]
We know that pitch, wavelength, and speed of the sound are related:
[tex]v=f\lambda[/tex]
Because our wavelentgh is the same the frequency must be different.
[tex]v=f \lambda\\ f=\frac{v}{\lambda}[/tex]
[tex]Helium: f_h=\frac{1007}{2}=503.5Hz\\ Air: f_a=\frac{343}{2}=171.2Hz \\ Carbon Dioxide: f_c=\frac{267}{2}=133.5Hz [/tex]

Answer:

F = v / w

Air: 343m/s  /  2.0 m = 171.5/s

Helium: 1007m/s / 2.0 m = 503.5/s

Carbon Dioxide: 267m/s  /  2.0 m = 133.5 /s

Explanation:

describe the difference between mechanical and electromagnetic waves. Give an example of each kind of wave related to telecommunications.

Answers

The main difference between mechanical and electromagnetic waves is that mechanical waves require a medium in order to propagate, while electromagnetic waves can propagate also in vacuum.

Examples of telecommunication via mechanical waves are sound waves (so, two people speaking to each other, for instance), while examples of telecommunication via electromagnetic waves are the radio waves that transmit the TV signals to the houses.

Which type of waves are whale songs in an ocean?

Answers

Whale songs in an ocean in sound waves frequencies between 30 Hertz (Hz) and around 8,000 Hz (8 kHZ).

What is  sound?

The sound is described in physics as: a pressure wave of vibration that travels through a gas, liquid, or solid medium and is audible.

Moans, groans, grunts, blasts, and shrieks are made by humpback whales. Sound waves make up each section of their song. These sound waves include some high frequency ones. These noises would resemble tall, sharp mountains if you could see them. Low frequency sound waves are also emitted by whales. These waves resemble far-flung hills in their spacing. Without losing energy, these sound waves can travel a great distance through water. Various of these low frequency sounds, according to researchers, can travel more than 10,000 miles in some ocean depths.

Hertz units are used to measure sound frequency. Whales use frequencies between 30 Hertz (Hz) and around 8,000 Hz (8 kHZ). The whales' songs are only partially audible to humans.

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Final answer:

Whale songs in the ocean are sound waves, specifically low-frequency aural signals that can travel vast distances underwater, facilitated by the SOFAR channel. Unfortunately, noise pollution seriously impacts these marine communications.

Explanation:

The whale songs that are transmitted in the ocean are a form of sound waves. These low-frequency sound waves are capable of traveling long distances underwater, allowing whales to communicate over hundreds of kilometers. This is possible due to the unique properties of water, especially in a layer known as the SOFAR channel, where sound speed is the slowest and allows for minimal attenuation of these aural signals.

However, contemporary issues such as noise pollution from ships pose a threat to this natural communication system, substantially reducing the ability of cetaceans to transmit their songs over long distances.

A two-phase, liquid–vapor mixture of h2o, initially at x 5 30% and a pressure of 100 kpa, is contained in a piston– cylinder assembly, as shown in fig p3.77. the mass of the piston is 10 kg, and its diameter is 15 cm. the pressure of the surroundings is 100 kpa. as the water is heated, the pressure inside the cylinder remains constant until the piston hits the stops. heat transfer to the water continues at constant volume until the pressure is 150 kpa. friction between the piston and the cylinder wall and kinetic and potential energy effects are negligible. for the overall process of the water, determine the work and heat transfer, each in kj.

Answers

Final answer:

In this scenario, the work done by the external agent can be calculated using the change in volume, and no heat is exchanged during this process.

Explanation:

Work: In the given scenario, since the gas volume doubles at constant temperature, the work done by the external agent can be calculated using the formula W = -PΔV, where P is the pressure and ΔV is the change in volume.

Heat Transfer: As the gas volume doubles at constant temperature, no heat is exchanged during this process. Hence, the heat exchanged is zero.

Which statements describe chemical changes? Check all that apply.
The after-rain smell is produced by an interaction between rain and the oils released by plants.
A homemade volcano can be created by combining baking soda and vinegar. When it erupts, carbon dioxide gas is released.
Sheep are sheared for their wool. The wool is cleaned and twisted into yarn. The yarn is dyed and used to knit clothing.
The Statue of Liberty has turned green over time due to the reaction of copper with carbon dioxide and water.
Mosaic art is created by smashing colored glass tiles and rearranging them to form a picture or design.

Answers

The answers are a,b and d

Answer: A, B, and D

Determine the sign (+ or −) of the torque about the elbow caused by the biceps, τbiceps, the sign of the weight of the forearm, τforearm, and the sign of the weight of the ball, τball. express your answers as using + and - separated by commas.

Answers

Ans: 
1.  τbiceps = +(Positive)
2.  τforearm = -(Negative)
3.  τball = -(Negative)

Explanation:

The figure is attached down below.

1. Torque about the elbow caused by the biceps, τbiceps:
Since Torque = r x F (where r and F are the vectors)
Where r is the vector from elbow to the biceps.

We can see in the figure that F(biceps) is in upward direction, and by applying the right hand rule from r to F, we get the counterclockwise direction. The torque in counterclockwise direction is positive(+). Therefore, the sign would be +.

2. Torque about the the weight of the forearm, τforearm:
Since Torque = r x (where r and F are the vectors)
Where r is the vector from elbow to the forearm.

Also weight is the special kind of Force caused by the gravity.

We can see in the figure that W(forearm) is in downward direction, and by applying the right hand rule from r to F, we get the clockwise direction. The torque in clockwise direction is negative(-). Therefore, the sign would be -.

3. Torque about the the weight of the ball, τball:
Since Torque = r x (where r and F are the vectors)
Where r is the vector from elbow to the ball.

Also weight is the special kind of Force caused by the gravity.

We can see in the figure that W(ball) is in downward direction, and by applying the right hand rule from r to F, we get the clockwise direction. The torque in clockwise direction is negative(-). Therefore, the sign would be -.

What is the minimum amount of energy required to move the satellite from this orbit to a location very far away from the earth?

Answers

The minimum amount of energy required to move the satellite from its orbit to a location very far away from Earth is approximately [tex]\( 6.245 \times 10^{11} \, \text{J} \)[/tex]

To move a satellite from a stable orbit around the Earth to a location very far away, such as into deep space, we need to provide enough energy to overcome the gravitational pull of the Earth and to accelerate the satellite to a speed sufficient to escape Earth's gravitational field entirely. This energy required to escape Earth's gravitational field is called the escape velocity.

The escape velocity, [tex]\( v_{\text{escape}} \)[/tex], is given by the formula:

[tex]\[ v_{\text{escape}} = \sqrt{\frac{2GM}{R}} \][/tex]

Where:

- [tex]\( G \)[/tex] is the gravitational constant [tex](\( 6.67430 \times 10^{-11} \, \text{m}^3/\text{kg/s}^2 \))[/tex],

- [tex]\( M \)[/tex] is the mass of the Earth [tex](\( 5.972 \times 10^{24} \, \text{kg} \))[/tex],

- [tex]\( R \)[/tex] is the distance from the center of the Earth to the satellite's initial orbit.

The minimum amount of energy required to move the satellite from its orbit to a location very far away would be the kinetic energy required to achieve this escape velocity.

The kinetic energy [tex]\( KE \)[/tex] required to achieve a velocity [tex]\( v \)[/tex] for an object of mass [tex]\( m \)[/tex] is given by the formula:

[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]

Therefore, to calculate the minimum energy required, we need to find the escape velocity and then calculate the kinetic energy corresponding to that velocity.

Keep in mind that in real-world scenarios, additional energy may be required to maneuver the satellite and account for factors such as atmospheric drag and gravitational influences from other celestial bodies. However, for the sake of simplicity, we will focus on the minimum energy required to achieve escape velocity from Earth's gravity.

Let's proceed with the calculations using the known values for [tex]\( G \)[/tex], [tex]\( M \)[/tex], and [tex]\( R \)[/tex].

Let's calculate the escape velocity [tex]\( v_{\text{escape}} \)[/tex] first:

Given:

- [tex]\( G = 6.67430 \times 10^{-11} \, \text{m}^3/\text{kg/s}^2 \)[/tex],

- [tex]\( M = 5.972 \times 10^{24} \, \text{kg} \)[/tex],

- [tex]\( R \)[/tex] (distance from the center of the Earth to the satellite's initial orbit).

Assuming the satellite is in a low Earth orbit, where [tex]\( R \)[/tex] is approximately the radius of the Earth, [tex]\( R \approx 6.371 \times 10^6 \, \text{m} \)[/tex].

Let's calculate [tex]\( v_{\text{escape}} \)[/tex]:

[tex]\[ v_{\text{escape}} = \sqrt{\frac{2 \times 6.67430 \times 10^{-11} \times 5.972 \times 10^{24}}{6.371 \times 10^6}} \][/tex]

[tex]\[ v_{\text{escape}} = \sqrt{\frac{2 \times 6.67430 \times 5.972}{6.371}} \times 10^{11} \][/tex]

[tex]\[ v_{\text{escape}} = \sqrt{\frac{2 \times 39.83416}{6.371}} \times 10^{11} \][/tex]

[tex]\[ v_{\text{escape}} = \sqrt{\frac{79.66832}{6.371}} \times 10^{11} \][/tex]

[tex]\[ v_{\text{escape}} \approx \sqrt{12.513} \times 10^{11} \][/tex]

[tex]\[ v_{\text{escape}} \approx 3.537 \times 10^4 \, \text{m/s} \][/tex]

Now, we'll calculate the kinetic energy [tex]\( KE \)[/tex] required to achieve this velocity using the formula:

[tex]\[ KE = \frac{1}{2} m v_{\text{escape}}^2 \][/tex]

Given that the mass m, of the satellite is not specified, we'll assume a typical satellite mass of [tex]\( 1000 \, \text{kg} \)[/tex] for illustrative purposes.

[tex]\[ KE = \frac{1}{2} \times 1000 \times (3.537 \times 10^4)^2 \][/tex]

[tex]\[ KE = \frac{1}{2} \times 1000 \times 1.249 \times 10^9 \][/tex]

[tex]\[ KE \approx 6.245 \times 10^{11} \, \text{J} \][/tex]

So, the minimum amount of energy required to move the satellite from its orbit to a location very far away from Earth is approximately [tex]\( 6.245 \times 10^{11} \, \text{J} \)[/tex].

The minimum amount of energy required to move the satellite very far away from earth is approximately 3.124 x 10¹³ Joules.

To find the minimum amount of energy required to move a satellite from its orbit to a location very far away from Earth (essentially to infinity), we need to calculate the difference in gravitational potential energy between its current orbit and a point infinitely far away.

The satellite has a mass m, the Earth has a mass M, and the radius of the Earth is R. The distance of the satellite from the center of the Earth is 2R. The gravitational potential energy U of the satellite in its current orbit is given by:

[tex]U = -\frac{G \cdot M \cdot m}{2R}[/tex]

where G is the gravitational constant (6.67 × 10⁻¹¹ Nm²/kg²).

At a distance infinitely far away, the gravitational potential energy U∞ is zero because the gravitational influence of the Earth becomes negligible:

U∞ = 0

The minimum energy ΔE required to move the satellite from its orbit to infinity is the difference in gravitational potential energy:

[tex]\Delta E = U_\infty - U = 0 - \left(-\frac{G \cdot M \cdot m}{2R}\right) = \frac{G \cdot M \cdot m}{2R}[/tex]

In numerical terms, for a 1000 kg satellite, Earth's mass M = 5.97 × 10²⁴kg, and Earth’s radius R = 6.371 × 10⁶ m, the energy required is:

[tex]\Delta E = \frac{(6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2) \times (5.97 \times 10^{24} \, \text{kg}) \times (1000 \, \text{kg})}{2 \times 6.371 \times 10^{6} \, \text{m}}[/tex]

[tex]&= \frac{(6.67 \times 5.97 \times 1000) \times 10^{-11 + 24 + 3}}{2 \times 6.371 \times 10^{6}} \\[/tex]

[tex]&= \frac{39819.9 \times 10^{16}}{12.742 \times 10^6} \\[/tex]

[tex]&= \frac{39819.9}{12.742} \times 10^{16 - 6} \\[/tex]

[tex]&= 3.124 \times 10^{13} \, \text{Nm}[/tex]

After calculation, the minimum energy required is approximately 3.124 x 10¹³ Joules.

Typical fears in children include the fear of A. failure. B. heights. C. jumping. D. the dark.

Answers

Obviously it's the dark.
It could be the dark or heights.

2. A 500.0 g metal block absorbs 3.25 × 103 J of heat to raise its temperature by 50.0 K. What is the substance? Show your work.

Answers

The amount of heat Q absorbed by a substance is related to its increase of temperature [tex]\Delta T[/tex] by the following relationship:
[tex]Q=mC_s \Delta T[/tex]
where m is the mass of the substance and [tex]C_s [/tex] is its specific heat.

Using [tex]m=500 g=0.5 kg[/tex], [tex]Q=3.25 \cdot 10^3 J[/tex] and [tex]\Delta T=50 K[/tex], we can find the specific heat of the substance by re-arranging the formula:
[tex]C_s = \frac{Q}{m \Delta T} = \frac{3.25 \cdot 10^3 J}{(0.5 kg)(50 K)}=130 J/(KgK) [/tex]

and looking at the table of specific heat values for various substance, we find that this value corresponds to lead.

Answer:

Q = m x C x T

C = Q / m x T

C = 3.25 x 10^3 /0.5kg  x  50K = 130 J/kgK

The substance is gold.

Explanation:

You are riding your bike to the mall. You travel the first mile in 10 minutes. The last mile takes you 15 minutes. This is an example of

Answers

If the person if slowing down, then this would mean that this would actually be "negative acceleration". Sense this person first did a mile in 10 minutes, and then the next mile that this person did was actually 15 minutes, then this shows you that they actually went a lot slower. And this is why this would be a great example of "negative acceleration".

Answer:

negative exccalarion

Explanation:

The current in a hair dryer measures 15 amps. The resistance of the hair dryer is 14 ohms. What is the voltage?

i'm pretty terrible at math, if you could explain how to found the correct answer to help future problems i would greatly appreciate it!

Answers

We have that there is a formula connecting these three. V=I*R where V is voltage, I is the current and R is the resistance. Substituting, we get that V=210 Volta, which is the unit of measurement for voltage. You can think of the relationship in the following way : The energy of the field is equal to the flow of the field times the resistance that it meets.

Calculate the average translational kinetic energy (sometimes just called average kinetic energy)⦠for one mole of gas at 827 k. and... for a single gas molecule at 827 k.

Answers

Final answer:

The average translational kinetic energy, or thermal energy, of a molecule can be found using the equation KE = 3/2kT. For one mole of gas at 827K, you multiply the single particle kinetic energy by Avogadro's number. For a single gas molecule at 827K, add its temperature into the equation to find its kinetic energy.

Explanation:

The average translational kinetic energy of a molecule, also known as thermal energy, can be calculated using the equation KE = 3/2kT, where 'k' is the Boltzmann's constant (1.38 x 10^-23 J/K), 'T' is the absolute temperature in Kelvin, and KE is the average kinetic energy.

Now to calculate for one mole of gas at 827 K, multiply the single particle kinetic energy by Avogadro's number since one mole consists of Avogadro's number of particles. Hence, KE of one mole= NA * KE of one particle = 6.022 x 10^23 * KE of one particle. This answers the first part of your question.

In the case of a single gas molecule, using the temperature of 827 K, substitute this into the equation KE = 3/2kT to find the kinetic energy for an individual molecule. Remember the unit for your answer is Joules. This addresses the second part of your question.

Learn more about Average Translational Kinetic Energy here:

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Which word equation is used to calculate the acceleration of an object? A. Subtract the initial velocity from the final velocity and multiply the result by the time. B. Subtract the initial velocity from the final velocity and divide the result by the time. C. Add the initial velocity and the final velocity and divide the result by the time. D. Add the initial velocity and the final velocity and multiply the result by the time.

Answers

Correct answer is: 
B. Subtract the initial velocity from the final velocity and divide the result by the time

In fact, the formula to calculate the acceleration is
[tex]a= \frac{v_f-v_i}{t} [/tex]
where vf is the final velocity, vi the initial velocity, and t the time.

Final answer:

The correct word equation to calculate the acceleration of an object is to subtract the initial velocity from the final velocity and then divide the result by the time.

Explanation:

To calculate the acceleration of an object, you would use the following word equation: Subtract the initial velocity from the final velocity and divide the result by the time. This represents the average acceleration, where acceleration is defined as the change in velocity (∆v) divided by the change in time (∆t).

It is crucial to ensure that all units are consistent, typically using meters for distance and seconds for time. An example of calculating acceleration would be: If an object's initial velocity is 5 m/s, its final velocity is 20 m/s, and the time taken to change velocity is 3 seconds, the acceleration a is (20 - 5) / 3 = 15 / 3 = 5 .

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