Answer:
111
Step-by-step explanation:
a1 = -12
a27 = 66
Now using the formula an = a1+(n-1)d we will find the value of d
here n = 27
a1 = -12
a27 = 66
Now substitute the values in the formula:
a27 = -12+(27-1)d
66= -12+(26)d
66 = -12+26 * d
66+12 = 26d
78 = 26d
now divide both the sides by 26
78/26= 26d/26
3 = d
Now put all the values in the formula to find the 42 term
an = a1+(n-1)d
a42 = -12 +(42-1)*3
a42 = -12+41 *3
a42 = -12+123
a42 = 111
Therefore 42 term is 111....
Answer:
Assuming it is arithmetic, the 42nd term is 111.
Assuming it is geometric, the conclusion says it isn't geometric.
Step-by-step explanation:
Let's assume arithmetic first.
Arithmetic sequences are linear. They go up or down by the same number over and over. This is called the common difference.
We are giving two points on our line (1,-12) and (27,66).
Let's find the point-slope form of this line.
To do this I will need the slope. The slope is the change of y over the change of x.
So I'm going to line up the points and subtract vertically, then put 2nd difference over 1st difference.
(1 , -12)
-(27,66)
------------
-26 -78
The slope is -78/-26=78/26=3. The slope is also the common difference.
I'm going to use point [tex](x_1,y_1)=(1,-12)[/tex] and [tex]m=3[/tex] in the point-slope form of a line:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-(-12)=3(x-1)[/tex]
Distribute:
[tex]y+12=3x-3[/tex]
Subtract 12 on both sides:
[tex]y=3x-3-12[/tex]
[tex]y=3x-15[/tex]
So we want to know what y is when x=42.
[tex]y=3(42)-15[/tex]
[tex]y=126-15[/tex]
[tex]y=111[/tex]
So [tex]a_{42}=111[/tex] since the explicit form for this arithmetic sequence is
[tex]a_n=3n-15[/tex]
-----------------------------------------------------------------------------------------
Let's assume not the sequence is geometric. That means you can keep multiplying by the same number over and over to generate the terms given a term to start with. That is called the common ratio.
The explicit form of a geometric sequence is [tex]a_n=a_1 \cdot r^{n-1}[/tex].
We are given [tex]a_1=-12[/tex]
so this means we have
[tex]a_n=-12 \cdot r^{n-1}[/tex].
We just need to find r, the common ratio.
If we divide 27th term by 1st term we get:
[tex]\frac{a_{27}}{a_1}=\frac{-12r^{27-1}}{-12r^{1-1}}=\frac{-12r^{26}}{-12}=r^{26}[/tex]
We are also given this ration should be equal to 66/-12.
So we have
[tex]r^{26}=\frac{66}{-12}[/tex].
[tex]r^{26}=-5.5[/tex]
So the given sequence is not geometric because we have an even powered r equaling a negative number.
Country days scholarship rounds receive a gift of $135000. The money is invested in stock, bonds, and CDs. CDs pay 2.75% interest, bonds pay 4.5% interest, and stocks pay 10.4% interest. Country days invests $70000 more in bonds than CDs. If the annual income from the investments is $8555, how much was invested in stocks, bonds, and CDs?
Answer:
CDs — $10,000bonds — $80,000stocks — $45,000Step-by-step explanation:
Let the variables c, b, s represent the dollar amounts invested in CDs, stocks, and bonds, respectively. Then the problem statement gives us 3 relations between these 3 variables:
c + b + s = 135000 . . . . . . . . . . . . . . . . . total invested
0.0275c +.045b +0.104s = 8555 . . . . . total income earned
-c + b = 70000 . . . . . . . . . . . . . . . . . . . . . 70,000 more was in bonds than CDs
Using the third equation to write an expression for b, we can substitute into the other two equations.
b = 70000 +c . . . . . . . . . . . . . . . . expression we can substitute for b
c + (70000 +c) +s = 135000 . . . . substitute for b in the first equation
2c +s = 65000 . . . . . . . . . . . . . . . . [eq4] simplify
.0275c +.045(70000 +c) +.104s = 8555 . . . . . substitute for b in 2nd eqn
.0725c +.104s = 5405 . . . . . . . . . . [eq5] simplify
Using [eq4], we can write an expression for s that can be substituted into [eq5].
s = 65000 -2c . . . . . . . expression we can substitute for s
0.0725c +0.104(65000 -2c) = 5405
-0.1355c = -1355 . . . . . . . . . . . . . . . . . . . . subtract 6760, simplify
c = 1355/.1355 = 10,000
s = 65000 -2×10000 = 45,000
b = 70000 +10000 = 80,000
The amounts invested in stocks, bonds, and CDs were $45,000, $80,000, and $10,000, respectively.
_____
Alternatively, you can reduce the augmented matrix for this problem to row-echelon form using any of several calculators or on-line sites. That matrix is ...
[tex]\left[\begin{array}{ccc|c}1&1&1&135000\\0.0275&0.045&0.104&8555\\-1&1&0&70000\end{array}\right][/tex]
The average NBA ticket price for the 2018-2019 season is up 14.01% from the average ticket price of $78 during the 2015-2016 season. what is the average ticket price in 2018-2019? Round to the nearest penny.
The average ticket price in 2018-2019 by calculating increase and add it to previous year ticket price and rounded it to the nearest penny is $88.93
Given that the average NBA ticket price for the 2018-2019 season is up 14.01% from the average ticket price of $78 during the 2015-2016 season.
To find the average ticket price in 2018-2019 by calculating increase and add it to previous year ticket price and rounded it to the nearest penny.
Step 1: Find the increase ticket price by multiplying the increase % with the previous ticket price:
Increase ticket price = increase % x previous ticket price
Plugging the given data:
Increase ticket price = 14.01 % x 78
Convert percent into decimal:
Increase ticket price = 0.1401 x 78
On multiplying gives:
Increase ticket price = $10.9278
Step 2: Find the average ticket price in 2018-2019 by add it to previous year ticket price :
average ticket price= previous ticket price +Increase ticket price
Plugging the given data:
average ticket price=78 + 10.9278
On adding gives:
average ticket price=88.9278
Round to the nearest penny
average ticket price = $88.93
Therefore, the average ticket price in 2018-2019 by calculating increase and add it to previous year ticket price and rounded it to the nearest penny is $88.93
Learn more about average here:
https://brainly.com/question/34397603
#SPJ4
Final answer:
The average NBA ticket price for the 2018-2019 season, based on a 14.01% increase from the 2015-2016 average of $78, is approximately $88.93 after rounding to the nearest penny.
Explanation:
To calculate the average NBA ticket price in the 2018-2019 season, we can use the percentage increase from the 2015-2016 season ticket price. We start with the average ticket price of $78 during the 2015-2016 season. According to the question, the ticket prices have increased by 14.01%. This percentage needs to be converted into a decimal (by dividing by 100) and then multiplied by the original average price to find the increase amount.
The calculation for the increase amount will be:
Convert the percentage increase into a decimal: 14.01% ÷ 100 = 0.1401.
Multiply this decimal by the original average price: 0.1401 × $78 = $10.9278.
Add this increase to the original average price to get the new average price: $78 + $10.9278 = $88.9278.
When we round this to the nearest penny, the new average ticket price for the 2018-2019 season is approximately $88.93.
2x + y = 8 x + y = 4 The lines whose equations are given intersect at (4, 0) (0, 4) all points on the line
Answer:
(4,0)
Step-by-step explanation:
Plug them into see:
Check (4,0)
In order for the lines to intersect at (4,0) it must be on both lines.
2(4)+0=8 is true because it is saying 8=8
4+0=4 is true because 4=4
So (4,0) is a intersection point.
Check (0,4)
2(0)+4=8 is not true because it is saying 4=8
0+4=4 is true so it's on this line while not on the other line.
So (0,4) is not an interestion point for the mentioned lines.
Well all points can't be on the line since (0,4) is not on both lines but just one of them.
We could have solve this out instead plugging in but the problem gave us the option here with the choices.
The system of linear equations given intersects at the point (4, 0), and since these equations represent distinct lines, they only intersect at this single point.
The question involves solving a system of linear equations to find the point of intersection. The system given is:
2x + y = 8x + y = 4Let's solve the equations step by step:
Subtract the second equation from the first to eliminate y, getting 2x - x + y - y = 8 - 4, which simplifies to x = 4.Substitute x = 4 into the second equation: 4 + y = 4, solving for y, which gives y = 0.Therefore, the lines intersect at the point (4, 0).
To determine whether the lines intersect at all points on a line, note that these equations represent distinct lines with different slopes, meaning they only intersect at one point, facing the choice given, (4, 0) is correct.
PLEASE HELP ME 20 POINTS !! tyvm
ASAP
Answer:
[tex]\large\boxed{m\angle S=78^o}[/tex]
Step-by-step explanation:
[tex]\text{If}\ \triangle MNP\cong\triangle QST,\ \text{then corresponding angles}\\\text{and corresponging sides are congruent.}\\\\\angle M\cong\angle Q\\\angle N\cong\angle S\\\angle P\cong\angle\\\\m\angle N=78^o,\ \text{therefore}\ m\angle S=78^o[/tex]
factor the expression 6g^3 + 8g^2 - 15g - 20
Answer:
(3g+4) (2g^2-5)
Step-by-step explanation:
6g^3 + 8g^2 - 15g - 20
Lets factor by grouping
Taking a 2 g^2 out of the first two terms and -5 out of the last two terms
2g^2 (3g+4) -5(3g+4)
Factoring out (3g+4)
(3g+4) (2g^2-5)
Answer:
The factors are (3g+4)(2g^2-5)....
Step-by-step explanation:
The expression is:
6g^3 + 8g^2 - 15g - 20
Make a group of the first two terms and last two terms:
(6g^3 + 8g^2) - (15g + 20)
Now factor out the common from each group:
2g^2(3g+4)-5(3g+4)
(3g+4)(2g^2-5)
Therefore the factors are (3g+4)(2g^2-5)....
What theorem or postulate can be used to justify that AHIG EAFIE?
A. SAS
B. ASA
C. AAS
D. SSS
Answer:
ASA
Step-by-step explanation:
There is an included side in between both angles in each triangle.
I hope this helps you out, and as always, I am joyous to assist anyone at any time.
Which expression has the same value as -18-(-9)?
0 -18+2
9 -12-(-3)
-10-5
Answer:
None of the given option is correct.
Step-by-step explanation:
The expression given is:
-18-(-9)
= -18+9
= -9
Now checking the options, which will have -9 as answer
1) 0 -18+2
= -18+2
= -16
As answer is not -9, so this is not a correct option
2) 9 -12-(-3)
= 9 - 12 + 3
= 0
As answer is not -9, so this is not a correct option
3) -10-5
= -10-5
= -15
As answer is not -9, so this is not a correct option
So, None of the given option is correct.
Multiply. Express your answer in simplest form. 9 1/6 × 1 1/11
Answer:
10
Step-by-step explanation:
First convert the fractions.
9 1/6 to 55/6 and 1 1/11 to 12/11
With these fractions, you can cross out 11 and 6.
55 times 12 5 × 2
6 11 1 × 1
This equals 10/1 or 10
Final answer:
To multiply 9 1/6 by 1 1/11, first convert them to improper fractions, 55/6 and 12/11 respectively. Multiply the numerators together to get 660, and the denominators together to get 66. Simplify by dividing both by their greatest common divisor, which is 66, to get the simplest form, which is 10.
Explanation:
The question asks to multiply 9 1/6 by 1 1/11 and express the answer in simplest form. First, we will convert these mixed numbers to improper fractions. For the first number, 9 1/6, we multiply the whole number part by the denominator of the fractional part and add the numerator: (9 × 6) + 1 = 54 + 1 = 55, thus we get 55/6. For the second number, 1 1/11, we follow the same process: (1 × 11) + 1 = 11 + 1 = 12, resulting in 12/11.
Next, we multiply the resulting improper fractions. The numerators are multiplied together, and the denominators are multiplied together yielding 55 × 12 over 6 × 11 which equals 660/66. Simplifying by common factors, we notice that both the numerator and denominator have a common factor of 66. Dividing the numerator and denominator by 66 gives us the simplest form, which is 10/1 or simply 10.
Which two operations are needed to write the expression that represents "eight more than the product of a number and
two"?
Answer:
Addition and Multiplication
Step-by-step explanation:
The keywords more than in this case means "addition", and the keyphrase product of a number and two means "multiplication". Here is what your expression should look like:
2n + 8
I am joyous to assist you anytime.
Triangle JKL is transformed to create triangle J'K'L'. The angles in both triangles are shown.
J = 90° J' = 90°
K = 65° K' = 65°
L = 25° L' = 25°
Which statement is true about this transformation?
Answer:
It can be a rigid or a nonrigid transformation depending on whether the corresponding side lengths have the same measures.
Step-by-step explanation:
Answer:C
Step-by-step explanation:
I know
A mixture of 50 liters of paint is 25% red tint, 30% yellow tint and 45% water. 7 liters of yellow tint is added to the original mixture. What percent of yellow tint is in the new mixture? Answer must be correct to 1 decimal place.
Final answer:
To find the percent of yellow tint in the new mixture, we need to consider the original mixture and the additional 7 liters of yellow tint that was added. The new mixture has a percent of yellow tint of 38.6%.
Explanation:
To find the percent of yellow tint in the new mixture, we need to consider the original mixture and the additional 7 liters of yellow tint that was added.
The original mixture contains 30% yellow tint, which is equivalent to 30% of 50 liters, or 0.3 * 50 = 15 liters of yellow tint.
When the 7 liters of yellow tint is added, the total amount of yellow tint in the new mixture is 15 liters + 7 liters = 22 liters.
The new mixture has a total volume of 50 liters + 7 liters = 57 liters.
To find the percent of yellow tint in the new mixture, we divide the amount of yellow tint (22 liters) by the total volume (57 liters) and multiply by 100:
Percent of yellow tint = (22 liters / 57 liters) * 100 = 38.60% (rounded to 1 decimal place).
Final answer:
After adding 7 liters of yellow tint to the mixture, the new total volume of yellow tint is 22 liters, and the total volume of the mixture is 57 liters. Calculating the percentage, the mixture now consists of 38.6% yellow tint.
Explanation:
To calculate the new percentage of yellow tint in the mixture after adding 7 liters, we first need to determine how much of each component there was in the original mix.
Original amount of red tint: 25% of 50 liters = 12.5 litersOriginal amount of yellow tint: 30% of 50 liters = 15 litersOriginal amount of water: 45% of 50 liters = 22.5 litersAfter adding 7 liters of yellow tint, the new total amount of yellow tint becomes 15 liters + 7 liters = 22 liters. The total volume of the mixture is now 50 liters + 7 liters = 57 liters.
The new percentage of yellow tint is calculated as follows:
(Amount of yellow tint / Total volume) × 100 = (22 liters / 57 liters) × 100
This calculation gives us the new yellow tint percentage in the mixture:
(22 / 57) × 100 ≈ 38.6%
Therefore, the mixture now contains 38.6% yellow tint.
What type of function is represented by the table of values below?
8
12
16
20
Answer:
To be precise, I think it's a pattern question, where you have to add 4 to each number. I'm not very sure though.
18. One biker rode at an average speed of 10.1 kilometers per hour. How far did
bikes
he ride in 5 hours?
Answer:
50.5 km
Step-by-step explanation:
If speed=distance/time, then distance=time*speed.
So we have the time and the speed to find the distance.
We just need to multiply 5 hours and 10.1 km/hour.
distance=(5 hours)(10.1 km/hour)
The time unit cancels and you are just left with the distance unit.
distance=50.5 km
Answer:50.5 km
Step-by-step explanation:
Two angles of a triangle have the same measure and the third one is 15 degrees greater than the measure of each of the other two. Find the measure of the LARGEST angle in the triangle.
The LARGEST angle has a measure of _____ degrees.
Answer:
70°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
let the equal angles be x then the third angle = x + 15
Sum the 3 angle and equate to 180
x + x + x + 15 = 180
3x + 15 = 180 ( subtract 15 from both sides )
3x = 165 ( divide both sides by 3 )
x = 55
Hence
The largest angle = x + 15 = 55 + 15 = 70°
A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is the number of 3-point questions and y is the number of 5-point questions, the system shown represents this situation. x + y = 24 3x + 5y = 100 What does the solution of this system indicate about the questions on the test? A] The test contains 4 three-point questions and 20 five-point questions. B]The test contains 10 three-point questions and 14 five-point questions. C]The test contains 14 three-point questions and 10 five-point questions. D]The test contains 20 three-point questions and 8 five-point questions.
Answer:
B. The test contains 10 three-point questions and 14 five-point questions.
Step-by-step explanation:
Let us first find the solution to the system of equations.
x+y= 24
3x+5y= 100
We use substitution method.
x=24-y
Replacing the value of x in the second equation.
3(24-y)+5y=100
Then solve for y.
72-3y+5y=100
2y=100-72
2y=28
y=14
To find x let us replace the value of y in x=24-y
x=24-14
x=10
This means that the test has 14 five-point questions and 10 three point questions.
Please help me solve this problem !
[tex]f(3)=2^3=8[/tex]
Answer:
D. 8
Step-by-step explanation:
The value of f(3) in f(x)=2x is 8.
f(3)=2^3=8
what is 2% out of 3000
Answer:
It would be 60.
Answer:
Step-by-step explanation:
(3000×2)/100 = 6000/100 = 60
solve the equation
log(5x)-log(x-3)=1
Answer:
x = 6
Step-by-step explanation:
Using the rules of logarithms
• log x - log y ⇔ log ([tex]\frac{x}{y}[/tex] )
• [tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]
Given
log(5x) - log(x - 3) = 1
log ( [tex]\frac{5x}{x-3}[/tex] ) = 1, then
[tex]\frac{5x}{x-3}[/tex] = [tex]10^{1}[/tex] = 10 ( cross- multiply )
10(x - 3) = 5x
10x - 30 = 5x ( subtract 5x from both sides )
5x - 30 = 0 ( add 30 to both sides )
5x = 30 ( divide both sides by 5 )
x = 6
Answer:
x =6
Step-by-step explanation:
log(5x) - log(x - 3) = 1
Recall that the logarithm of a fraction is the difference of the logarithms,
so, the difference between two logarithms is logarithm of the fraction. Then,
[tex]\begin{array}{rcll}\\\\\log \dfrac{5x}{x-3} & = & 1 &\\\\\dfrac{5x}{x - 3} & = & 10 & \text{Took the antilogarithm of each side}\\\\5x & = & 10(x - 3) & \text{Multiplied each side by x - 3}\\5x & = & 10x - 30 & \text{Distributed the 10}\\-5x & = & -30 & \text{Subtracted 10 x from each side}\\x & = & \mathbf{6} & \text{Divided each side by -5}\\\end{array}[/tex]
Check:
[tex]\begin{array}{rcl}\log(5\times6) - \log (6 - 3) & = & 1\\\log 30 - \log 3 & = &1\\\\\log \dfrac{30}{3} & = & 1\\\\\log 10 & = & 1\\1 & = & 1\\\end{array}[/tex]
OK.
PLEASE HELP, I NEED TO BE HELPED WITH THESE QUESTIONS
Answer:
[tex](f+g)(x)=\sqrt{3x+7}+\sqrt{3x-7}[/tex]
[tex]f(g(x))=x+1[/tex]
[tex]f(x)=x+9 \text{ and } g(x)=\frac{4}{x^2}[/tex]
[tex]f^{-1}(x)=\frax{x+2}{3}[/tex]
Let me know if you have any questions about any of my work.
Step-by-step explanation:
You are given the following:
[tex]f(x)=\sqrt{3x+7} \text{ and } g(x)=\sqrt{3x-7}[/tex]
and asked to find [tex](f+g)(x) \text{ which means } f(x)+g(x)[/tex].
If you add those because we are asked to find f(x)+g(x) you get:
[tex]\sqrt{3x+7}+\sqrt{3x-7}[/tex]
----------------------------------------------------------
You are given the following:
[tex]f(x)=x^2+3 \text{ and } g(x)=\sqrt{x-2}[/tex]
and asked to find [tex]f(g(x))[/tex].
[tex]f(g(x))[/tex]
[tex]f(\sqrt{x-2})[/tex] I replaced g(x) with sqrt(x-2) because that is what it equals.
Now this last thing means to replace old input in x^2+3 with new input sqrt(x-2) giving us:
[tex](\sqrt{x-2})^2+3[/tex]
[tex]x-2+3[/tex]
[tex]x+1[/tex]
------------------------------------------------------------
We are given [tex]y=\frac{4}{x^2}+9[/tex] and asked to find g(x) and f(x) such that y=f(g(x)).
We have choices so let's use the choices:
Choice A:
[tex]f(g(x))[/tex]
[tex]f(\frac{4}{x^2}){/tex] I replace g(x) with 4/x^2:
[tex]\frac{4}{x^2}+9[/tex] I replaced the old input x with new input 4/x^2.
This was actually the desired result.
-----------------------------------------------------------
To find the inverse of f(x)=3x-2 or y=3x-2, your objective is to swap x and y and then remake y the subject.
y=3x-2
Swap x and y:
x=3y-2
Now solve for y.
Add 2 on both sides:
x+2=3y
Divide both sides by 3:
(x+2)/3=y
y=(x+2)/3
[tex]f^{-1}(x)=\frax{x+2}{3}[/tex]
A 12-volume numbered set of books is placed randomly on a shelf. What is the probability that the books will be numbered in the correct order from left to right?
Answer:
Step-by-step explanation:
There is a 1/12 probability that volume 1 will be correctly put in position 1.
If we assume that volume 1 is right, then since there are then only 11 books left to choose from, there is then a 1/11 prob that volume 2 will be in position 2. And so on. By the same reasoning there is 1/10 prob that volume 3 is then right, 1/9 prob for volume 4, 1/8 prob for volume 5, and 1/7 prob for volume 6,
and 1/6 prob for volume 7,and 1/5 prob for volume 8,and 1/4 prob for volume 9,and 1/3 prob for volume 10,and 1/2 prob for volume 11,and 1/1 prob for volume 12.
So the probability is 1 /(12*11*10*9*8*7*6*5*4*3*2*1) = 1 / 479,001,600 ....
I really need help with 9 and 10 please.
Answer:
9) The equation that represents our monthly bill is y=20+0.05m.
10) The equation that gives us the cost for the month is y=5+0.1m.
Step-by-step explanation:
9) So if we are trying to find how much our monthly bill is where the monthly fee is 20 and we are charged $.05 per minute, then:
For 0 minutes, we spend 20 dollars in the month.
For 1 minute, we spend 20+.05=20.05 dollars in the month.
For 2 minutes, we spend 20+.05+0.05 or 20+2(.05)=20+.1=20.10 dollars in the month.
For m minutes, we spend 20+.05m.
The equation that represents our monthly bill is y=20+0.05m.
They gave us the y-intercept (the initial amount=20) and the rate (the slope=.05).
Remember: slope-intercept form is y=mx+b.
10) I'm going to shorten number 10.
They give us the rate=$.1/min and the initial cost=5 dollars.
The equation that gives us the cost for the month is y=5+0.1m.
which statements must be true about ru reflection of xyz across mn? select 3 options
Answer:BZ congruent to BZ'
XY congruent to X'Y'
X'Z'Y' 90 degrees
Step-by-step explanation:
Answer:
(1). m∠X'Z'Y'=90°
(2). m∠MCY=90°,
(3). Line segment BZ'≅ line segment BZ
Step-by-step explanation:
Line MN is reflecting line for ΔXYZ. Triangle X'Y'Z' is formed after reflection of ΔXYZ about a line MN. Therefore the line MN works like a symmetric axis of the given figure.
Hence
(1). m∠X'Z'Y'=90°, because ∠XYZ=90° and figure are symmetric about line MN.
(2). m∠MCY=90°, because figure is symmetric ,so line segment YY'⊥ line MN.
(3). Line BZ' ≅line BZ, because figure is symmetric about about symmetric axis line MN and Line BZ'= line BZ.
I ONLY HAVE TILL TONIGHT PLZ SAVE ME I WILL MARK YOU THE BRAINLEST IF YOU ANSWER MY FULL QUESTION
Answer:
This graph is a not a Function because it doesn't pass the vertical line test. The opened and closed circles are not in relation to the y-value and the x-value. This function also doesn't corresponds to one another, which messes up the domain and range.
Step-by-step explanation:
Which expression is equivalent to the following complex fraction?
2-1/y / 3+ 1/y
Answer:
[tex]\frac{2-\frac{1}{y} }{3+\frac{1}{y} }[/tex] is equivalent to [tex]\frac{2y-1}{3y-1}[/tex]
Step-by-step explanation:
The given expression is :[tex]\frac{2-\frac{1}{y} }{3+\frac{1}{y} }[/tex].
We collect LCM in both the numerator and the denominator to obtain:
[tex]\frac{\frac{2y-1}{y} }{\frac{3y-1}{y} }[/tex]
Change to the normal division sign;
[tex]\frac{2y-1}{y} \div \frac{3y-1}{y}[/tex]
Multiply by the reciprocal of the second fraction:
[tex]\frac{2y-1}{y} \times \frac{y}{3y-1}[/tex]
Cancel out the common factors
[tex]\frac{2y-1}{3y-1}[/tex]
Therefore [tex]\frac{2-\frac{1}{y} }{3+\frac{1}{y} }[/tex] is equivalent to [tex]\frac{2y-1}{3y-1}[/tex]
Q: Which best describes the demand for consumer goods in the 1920's.
Select one:
a. people were less likely to buy new goods.
b. the demand for consumer goods declined during the 1920's.
0 C. all of these are correct
d. people began buying more than they had the cash to pay for becaus
could access loans and buy things on credit.
NE
Answer:
d. people began buying more than they had the cash to pay for because they
could access loans and buy things on credit.
Step-by-step explanation:
In the 1920's, it was a period of prosperity and people in the middle class began to have more income available to purchase products. Also, there were more products available because of the assembly line production and the credits expanded which resulted in people being able to buy things that they couldn't purchase paying the full price. According to this, the answer is that the statement that best decribes the demand for consumer goods in the 1920's is that people began buying more than they had the cash to pay for because they could access loans and buy things on credit.
Which of the fractions listed below are equal to 2⁄3?
Check all that are true.
6⁄9
1⁄3
3⁄2
4⁄6
1⁄6
What is 72/5 in decimal form
Answer:
14.4
Step-by-step explanation:
72/5 in decimal form equals 14.4
[tex]\frac{72}{5}[/tex] in decimal form is 14.4
[tex]\frac{72}{5}[/tex] is the same as 72 ÷ 5
72 ÷ 5 = 14.4
All we have to do to turn this fraction into a decimal is divide the fractions numerator by its denominator and we will get our decimal.
Evaluate the expression
a-b/c*d
when a=48, b=18, c=3, and d=2
[tex]\huge{\boxed{36}}[/tex]
Substitute the values. [tex]48 - 18 \div 3 * 2[/tex]
Follow PEMDAS and multiply and divide first. [tex]48 - 6 * 2[/tex]
[tex]48 - 12[/tex]
Continue following PEMDAS and subtract. [tex]\boxed{36}[/tex]
What is the product?
(x^2-16)/(2x+8) x (x^3-2x^2+x)/(x^2+3x-4)
a. x(x-4)(x-1)/2(x+4)
b. x(x-1)/2
c. (x+4)(x-4)/2x(x-1)
d. (x-4)(x-1)/2x(x+4)
Answer:
Option A is correct.
Step-by-step explanation:
We need to find the product of
[tex]\frac{(x^2-16)}{(2x+8)} * \frac{(x^3-2x^2+x)}{(x^2+3x-4)}[/tex]
We know (a^2-b^2) = (a+b)(a-b)
so, (x^2-16) = (x)^2-(4)^2 = (x-4)(x+4)
2x+8 Taking 2 common from this term:
2x+8 = 2(x+4)
(x^3-2x^2+x) Taking x common from this term
x(x^2-2x+1) = x(x-1)^2 = x(x-1)(x-1)
(x^2+3x-4) factorizing this term
x^2+4x-x-4 = x(x+4)-1(x+4)
= (x-1)(x+4)
Now, Putting these simplified terms in the given equation:
[tex]\frac{(x-4)(x+4)}{2(x+4)}*\frac{x(x-1)(x-1)}{(x-1)(x+4)}[/tex]
Now cancelling the same terms that are in numerator and denominator
[tex]=\frac{(x-4)}{2}*\frac{x(x-1)}{(x+4)}\\=\frac{(x-4)(x)(x-1)}{2(x+4)}\\=\frac{x(x-4)(x-1)}{2(x+4)}[/tex]
So, Option A is correct.
Answer:
=x(x-4)(x-1)/2(x+4)
Step-by-step explanation:
=x^2-4^2/2(x+4) * x^3-2x^2+x/x^2+3x-4
=(x+4)(x-4)/2(x+4) * x(x^2-2x+1)/x^2+3x-4
Factor x^2-2x+1 using the perfect square root
=(x+4)(x-4)/2(x+4) * x(x-1)^2/x^2+3x-4
Factor x^2+3x-4 using AC method.
=(x+4)(x-4)/2(x+4) * x(x-1)^2/(x-1)(x+4)
Cancel the common factor of x+4 and x-1
=(x-4)/2(x+4) * x(x-1)/1
=(x-4)x(x-1)/2(x+4)
Reorder the terms
=x(x-4)(x-1)/2(x+4)
Indicate which property is illustrated in step 8. A. Subtraction property of equality B. Simplification C. Distributive property D. Division property of equality
step 8: -3x/-3 = -7/3
Answer: Option 'D' is correct.
Step-by-step explanation:
Since we have given that
[tex]-3x=7[/tex]
After Step 8 it becomes,
[tex]\dfrac{-3}{-3}=\dfrac{-7}{3}[/tex]
It indicated the Division property of equality.
To find the value of x, we need to divide the left hand side and right hand side by -3.
So, this property is known as "Division property of equality":
Hence, Option 'D' is correct.
Answer:
Option D - Division property of equality
Step-by-step explanation:
Given : Step 8 - [tex]\frac{-3x}{-3}=-\frac{7}{3}[/tex]
To find : Indicate which property is illustrated in step 8 ?
Solution :
Step 8 - [tex]\frac{-3x}{-3}=-\frac{7}{3}[/tex]
In step 8 we have seen that -3 is divided both side,
So, The division property of equality is applied to get the result.
[tex]\frac{-3x}{-3}=-\frac{7}{3}[/tex]
[tex]x=-7[/tex]
Therefore, Option D is correct.
Division property of equality