what is the 5% of 300

Answers

Answer 1

15
300*5/100 =15
That's all

Answer 2

15.
the best way to do it is see the % as a decimal in my opinion, then plug it into a calculator. just move the decimal over to the left 2 times, then multiply the number you're taking the percent out of. So, in this case it would be:
300x.05
which is 15

Related Questions

Jim and his dad are building a rectangular flower bed. They have a total of 35 feet of landscaping timber to use, and they want to use all of it. However, they are not sure what width and length they want the flower bed to be. In this activity, you will write a function in which the width of the flower bed, w, is the input, and the length, l, is the output. The perimeter of a rectangle is given by the equation 2l + 2w = p. Part A Jim and his dad want to find the length of the garden once they decide its width. Use function notation to write a function that represents its length in terms of the width.

Answers

The perimeter is 35 hope it helps

The perimeter of a rectangle is 35.

So the function that represents the length of the flower bed in terms of its width is:

l(w) = (35 - 2w) / 2.

What is a rectangular perimeter?

The whole distance that a rectangle's borders, or its sides, cover is known as its perimeter. Given that a rectangle has four sides, the perimeter of the rectangle will be equal to the total of its four sides.

To write a function that represents the length of the flower bed in terms of its width, we can use the equation for the perimeter of a rectangle:

2l + 2w = p

where l is the length, w is the width, and p is the perimeter. We know that the perimeter is 35 feet, so we can substitute that into the equation:

2l + 2w = 35

We want to solve this equation for l, so we can isolate the variable on one side of the equation:

2l = 35 - 2w

Dividing both sides by 2 gives:

l = (35 - 2w) / 2

So the function that represents the length of the flower bed in terms of its width is:

l(w) = (35 - 2w) / 2

where l(w) is the length of the flower bed for a given width w.

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The Silver Town people went to a fancy restaurant after the big event. Grammy gave the server a $15 tip. If the tip was 20% of the cost of dinner, how much was dinner? Choose Answer:A.$60 B.$45 C.$75 D.$50

Answers

The sender is $75 because 75X.20 is 15 so 75 is the answer

Find y'' by implicit differentiation. 5x2 + y2 = 3

Answers

Final answer:

To find y'' by implicit differentiation, differentiate the equation 5x^2 + y^2 = 3 twice with respect to x. Simplify and isolate y'' to find the second derivative of y.

Explanation:

To find y'' by implicit differentiation, we differentiate the equation 5x^2 + y^2 = 3 with respect to x twice.

Step 1: Differentiate both sides of the equation with respect to x using the chain rule.

Step 2: Simplify the equation and isolate y'' to find the second derivative of y.

Step 3: Rewrite the equation with the second derivative of y isolated on one side.

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Corey drew a sketch of a paper hat as shown below.
If a = 4 in and b = 3 in, what is the area of the sketch?

A.84 in squared
B.60 in squared
C.30.5 in squared
D.40 in squared

Answers

4(3) = 12 x 3 = 36

2(4) = 8 +4 = 12/2 = 6*4 = 24

36 +24 = 60

Answer is B

Do the rectangle first.
Area = L * W
L = 4b
W = b
Area = 4b * b
Area = 4 *3 * 3
Area = 36 square inches.

Do the trapezoid next
b1 = a
b2 = 2a
h = a
Formula
Area = (b1 + b2) * h / 2
Area = (a + 2a) * a / 2
Area = (3a) * a / 2
a = 4
Area = (3*4) * 4 / 2
Area = 12 * 4/2
Area = 48 /2
Area = 24

Total Area
Area = 24 + 36
Area = 60 in^2

B <<<< answer

12÷0.5 explain the division expression in terms of bags of almonds

Answers

You have a total of $12. Each bag of almonds cost $0.50, how many bags of almonds can you buy with your $12?

A flagpole 3 meters tall casta a shadow of 4 meters long at the same time a nearby building casts a shadow of 62 meters long. How tall is the building

Answers

To answer this question, you will set up a proportion of the flagpole actual height to the height of the shadow: 3m/4m. Then set up an equivalent ratio of x meters (height of the building)/62m (height of the shadow of the building). I would use cross products to solve this proportion. Please see the attached picture to see the work. The final answer is that the building is 46.5 meters tall.

Suppose x follows a distribution with density function: \begin{equation} f\left(x\right) = \left\{\begin{array}{rl} c\left|x - 2\right|,& 0 \le x \le 3\\ 0, & \text{otherwise}\\ \end{array}\right. \end{equation} (note: for this question you can enter your answer in decimals as well as fractions.) what must the value of c be so that f(x) is a probability density function? tries 0/5 find the cumulative distribution function of f(x) for $ 2 \leq x \leq 3 $. [ the accepted form of answer is an algebraic expression in terms of "x". all algebraically equivalent expressions to the correct answer are accepted. write product as *
e.g 2*3 or 3*x, index/power as superscript,
e.g 2^3 for 2 raised to the power 3, the exponential function as exp(x), the logarithm function as log(x) (and not as ln(x)) ] tries 0/5 find the median of the probability distribution of x tries 0/2 find e(x) tries 0/5 find the cumulative distribution function of f(x) for $ 0 \leq x \leq 2 $. [ the accepted form of answer is an algebraic expression in terms of "x". all algebraically equivalent expressions to the correct answer are accepted. write product as *
e.g 2*3 or 3*x, index/power as superscript,
e.g 2^3 for 2 raised to the power 3, the exponential function as exp(x), the logarithm function as log(x) (and not as ln(x)) ]

Answers

The question is a bit of a mess, so here's an attempt at parsing out the relevant information.

Given the PDF of a random variable [tex]X[/tex]:

[tex]f_X(x)=\begin{cases}c|x-2|&\text{for }0\le x\le3\\0&\text{otherwise}\end{cases}[/tex]

Find [tex]c[/tex], the CDF, the median of [tex]X[/tex], and the expectation of [tex]X[/tex] (in no particular order).

For [tex]f_X(x)[/tex] to be valid PDF, we require

[tex]\displaystyle\int_{-\infty}^\infty f_X(x)\,\mathrm dx=1[/tex]

Note that

[tex]|x-2|=\begin{cases}x-2&\text{for }x\ge2\\2-x&\text{for }x<2\end{cases}[/tex]

We have

[tex]\displaystyle\int_{-\infty}^\infty f_X(x)\,\mathrm dx=c\int_0^3|x-2|\,\mathrm dx=c\int_0^2(x-2)\,\mathrm dx+c\int_2^3(2-x)\,\mathrm dx[/tex]
[tex]\implies\dfrac{5c}2=1\implies c=\dfrac25[/tex]

The CDF is defined by

[tex]F_X(x)=\mathbb P(X\le x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt[/tex]

To find the CDF, we compute the integral above for the four possible cases:

[tex]x<0\implies\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=0[/tex]
[tex]0\le x<2\implies\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=c\int_0^x|t-2|\,\mathrm dt=\frac{4x-x^2}5[/tex]
[tex]2\le x<3\implies\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\frac45+c\int_2^x|t-2|\,\mathrm dt=\frac45-c\int_2^x(2-t)\,\mathrm dt=\frac{8-4x+x^2}5[/tex]
[tex]x\ge3\implies\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=1[/tex]

So the CDF is

[tex]F_X(x)=\begin{cases}0&\text{for }x<0\\\\\dfrac{4x-x^2}5&\text{for }0\le x<2\\\\\dfrac{8-4x+x^2}5&\text{for }2\le x<3\\\\1&\text{for }x\ge3\end{cases}[/tex]

The median is the value [tex]M[/tex] such that [tex]\mathbb P(X\le M)=\dfrac12[/tex]. From the PDF, we can gather that the median must fall somewhere in [tex]0\le x\le2[/tex]. The CDF then tells us that

[tex]\mathbb P(X\le M)=F_X(M)=\dfrac12=\dfrac{4M-M^2}5\implies M=2-\sqrt{\dfrac32}\approx0.775[/tex]

The expected value of [tex]X[/tex] is given by

[tex]\mathbb E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx[/tex]

We have

[tex]\mathbb E[X]=\displaystyle\frac25\int_0^2x(x-2)\,\mathrm dx+\frac25\int_2^3x(2-x)\,\mathrm dx=\frac{16}{15}[/tex]

Can someone help me with these two questions?

Answers

1. use 6,8, 10 and then 7, 9,13

2. A=30, B= 70, b = 4

Rob cuts a 15-foot wire into 8 equal pieces. About how long is each piece ? 1.) Between 1 and 2 feet 2.) Between 3 and 4 feet 3.)Between 2 and 3 feet 4.) Between 2 and 3 feet

Which one is the answer?

Answers

Since 15/8=1.875, the answer would be #1 because 1.875 is more than 1 but less than 2

Can you square a negative number

Answers

Yes, you can square a negative, however it can only give you a positive answer

however, you cannot root a negative number (if that was what you wanted)

hope this helps

Yes, you can square a negative number; however, the product will be a positive integer as a negative multiplied by a negative will result in a positive.

For example;
(-2) * (-2) = 4.

Edit: Seeing that you meant to square root a negative number-- no, you cannot square root a negative number as you cannot multiply a negative number by a negative number to get a negative product; it will always be positive.

I hope this helps!

S22 for 161+147+133+119+...

Answers

The arithmetic sequence of 161,147,133,119
Compute the general progression formula of 161,147,133,119 d=-14, a↓n+175
Compute ᵃ₂₂ = -133

Final answer:

The 22nd term of the arithmetic progression in the series 161, 147, 133, 119.... is -133.

Explanation:

This question involves finding the 22nd term in a series of numbers where each term is 14 less than the preceding term. This is an arithmetic progression where the first term, 'a' is 161 and the common difference, 'd' is -14.

The formula for the nth term in an arithmetic progression is: a + (n - 1)*d.

Substituting the given values into the formula, we get:

'a' + (22 - 1)*'d' = 161 + (21)*(-14) = 161 - 294 = -133

So, S22 for 161+147+133+119+... = -133.

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In certain county, the number of charter schools is 4 less than twice the numbervof alternative schools. We know that there are 48 charter schools in the county. How many alternative schools are in the county?

Answers

1. Let's call the number of carter school: "x" and "y" the number of alternative school. Then, you have that:

- The number of charter schools is 4 less than twice the number of alternative schools.
- There are 48 charter schools in the country.

2. So, you have:

x=2y-4 (i)

x=48 (ii)

3. Then, when you substitute x=48 into the equation (i), you obtain:

x=2y-4
48=2y-4

4. Now, you must clear "y, as below:

48+4=2y
2y=52
y=52/2
y=26

How many alternative schools are in the county?

The answer is: There are 26 alternative schools.

Can you explain how you got it as well?

Answers

Let "a" represent the percentage of acid in the mixture.
.. 15*40% +25*20% = (15+25)*a
.. 6 +5 = 40a
.. a = 11/40 = 27.5% . . . . . . selection C

I don’t know what todo someone help me

Answers

Try this solution (this is one way):
1. The area of the shaded region is the area of the shaded triangle.
2. SΔ=0.5*(14-8)*8=0.5*6*8=24 m².

Let y=3t+6 be a linear function representing the distance from home for an ant t minutes after starting out from a location near its home. What does the number 3 represent in this function?

Answers

The direction from home to the ants current location.

The answer is the ant is crawling at 3 feet per minute

Which of the following is the inverse of y=6^x ?
A. Y=log 6x
B. Y=Log x6
C. YLog1/6X
D. Y=Log 6. 6x

Answers

we have that
y=6^x
we know
to find the inverse
replace x with y and y with x,
x=6^y

we know that
y=logb(x)----------> x=b^y

therefore
x=6^y---------------> y=log6(x)

the answer is the option A.) Y=log 6x

y=6^x
log y = log 6^x
log y = x log 6
(log y) / (log 6) = x
Inverse: y = (log x) / (log 6)

The box plots display the same data for the number of crackers in each snack bag, but one includes the outlier in the data and the other excludes it. 4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21 Number of Crackers in Each Bag, with Outlier Number of Crackers in Each Bag, without Outlier Which statement comparing the box plots is true? Both the median and the range changed. Both the range and the lower quartile changed. Both the median and the interquartile range changed. Both the interquartile range and the lower quartile changed.

Answers

Answer:

Both the median and the range changed.

Step-by-step explanation:

We first ensure this data set is from least to greatest. This one is.

Next we find the median. This is the middle value; in this set, it is 16.

Next we find Q1, the lower quartile. This is the middle of the lower set of data (once the data is "split" by the median). This is 15.

Next we find Q3, the upper quartile. This is the middle of the upper set of data (once the data is "split" by the median). This is 20.

The IQR is Q3-Q1, or 20-15 = 5.

The range is the max subtracted by the min, or 21-4 = 17.

Any outlier will be 1.5 times the IQR below Q1 or 1.5 times the IQR above Q3.

1.5(5) = 7.5; 15-7.5 = 7.5. Any lower outlier would be below this value; this makes 4 an outlier.

20+7.5 = 27.5. Any upper outlier would be above this value; this means there are no outliers on the upper end.

Taking the data value 4 out, the median is now 17. Q1 would still be 15 and Q3 would still be 20; this means the IQR would still be 5.

The range would now be 21-14 = 7.

This means the median and the range have changed.

The true statement comparing the box plots is that Both the median and the range changed.

What are quartiles?

When we get data that can be compared relatively with each other, for finding quartiles, we arrange them in ascending or descending order.

Quartiles are then selected as 3 points such that they create four groups in the data, each group approximately possessing 25% of the data.

The box plots display the same data for the number of crackers in each snack bag, but one includes the outlier in the data and the other excludes it.

4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21 Number of Crackers in Each Bag, with Outlier Number of Crackers in Each Bag, without Outlier

The median in this set is 16.

Q1, the lower quartile. This is the middle of the lower set of data.

This is 15.

Q3, the upper quartile. This is the middle of the upper set of data. This is 20.

The IQR is Q3-Q1

20-15 = 5.

The range will be

21-4 = 17.

Any outlier will be 1.5 times the IQR below Q1 or 1.5 times the IQR above Q3.

1.5(5) = 7.5

15-7.5 = 7.5.

Any lower outlier would be below this value, this makes 4 an outlier.

20+7.5 = 27.5.

Any upper outlier would be above this value, this means there are no outliers on the upper end.

Taking the data value 4 out, the median is now 17.

Q1 would still be 15 and Q3 would still be 20; this means the IQR would still be 5.

The range would now be 21-14 = 7.

Thus, This means the median and the range have changed.

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Point P (-3,-1) is the preimage. Point P’(3,-1) is the image after a reflection is performed. Give the line of reflection.

Answers

The perpendicular bisector of these two points is the vertical line x = 0.

x = 0 is the line of reflection.

A Punnett square is used to _______.

predict the genotypic and phenotypic probabilities of possible offspring

determine if a trait runs in a family

track inherited traits through many generations

identify organisms that are carriers of a specific trait

Answers

Hello,

The answer is option A "predict the genotypic and phenotypic probabilities of possible offspring".

Reason:

A Punnett square is used to determine (predict) the genotype, and phenotype of a organism. Phenotype is the physical features of a organism fur, ears, nose, etc.... Genotype is most likely the height, eye color, etc....

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

Final answer:

A Punnett square is used to predict the genotypic and phenotypic probabilities of possible offspring. It helps in illustrating how combinations of alleles might come together during fertilization. However, it cannot determine if a trait runs in a family or track inherited traits through generations.

Explanation:

A Punnett square is a common tool used in genetic studies to predict the genotypic and phenotypic probabilities of possible offspring when the genetic information of both parents is known. It is not used to determine if a trait runs in a family, track inherited traits through many generations, or identify organisms that are carriers of a specific trait. A Punnett square can help illustrate how different combinations of alleles might come together during fertilization and what traits these combinations could produce. For instance, if both parents carry a recessive trait, a Punnett square can show the possibility of their offspring inheriting that trait.

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Hey guys 25 points!! to help me out
In △DEF, DF = 16 and m∠F=45. Find the length of a leg. Leave your answer in simplest radical form.

Answers

the answer is 8 root 2

we have here an isosceles right triangle because there is a right angle and a 45 degree angle, and the m<D=45 as well
the hypotenuse is 16
we use the formula c^2=a^2+b^2
now we have a=b because the triangle is isosceles
c^2=2(a^2)
256=2(a^2)
256/2=a^2
128=a^2
a= 11.31 and b=11.31

lotA has 4,000 spaces. Today Lot A has 2,500 cars in Lot A. Lot B has 2,000 spaces. If both lots have the same ratio of cars to spaces, how many cars are in parking lot B

Answers

Lot B has half the spaces of lot A, so will have half the cars: 1,250.

Brad has two lengths of copper pipe to fit together one has a length of 2 5/12 feet and the other has a length of 3 7 12 ft how many feet of Pop does he have

Answers

To find the total length of the two copper pipes, we need to add them together.

2 5/12 + 3 7/12 = 5 12/12

Since 12/12 = 1 or a whole, we can simplify this further.

5 12/12 = 6

Hope this helps!

Jordan places two boards end to end to make one shelf. The first one is 47/100 meter long. The second board is 5/10 meter long. What is the total length, in meters, of the two boards

Answers

The total length of the two boards will be given by:
Total=(length of board A)+(length of board B)
=47/100+5/10
making the fractions have the same denominator we multiply the numerator and denominator of the second fraction by 10, this will giv us the expression of:
47/100+50/100
=97/100 m

Final answer:

To calculate the total length of the boards, the first board at 47/100 meters (0.47 meters) is added to the second board at 5/10 meters (0.5 meters), resulting in a total length of 0.97 meters.

Explanation:

To find the total length of the two boards placed end to end, we simply add the lengths of the individual boards. The first board is 47/100 meters long, and the second board is 5/10 meters long.

The second board's length can be simplified as 5/10 is equivalent to 1/2, which is 0.5 in decimal form. Adding the lengths together, we get:

Length of board 1: 47/100 meters (or 0.47 meters)
Length of board 2: 5/10 meters (or 0.5 meters)

Total length = 0.47 meters + 0.5 meters
Total length = 0.97 meters

Therefore, the total length of the two boards when placed end to end is 0.97 meters.

Jan and Jo live 1,170 miles apart. At the same time, they start driving toward each other on the same road. Jo’s constant rate is 60 mph. Jan’s is 70 mph. How long will it take them to meet?

Answers

Answer:

the answer is 9 hours

Step-by-step explanation:

I got it right on the test

The time taken by Jan and Jo with constant rate of 70 mph and 60 mph respectively, will meet in 9 hours while driving towards each other along a 1,170-mile road.

To find out how long it will take Jan and Jo to meet, you can use the formula:

Time = Distance / Speed

Since they are driving toward each other, their combined speed is the sum of their individual speeds:

Combined Speed = Jan's Speed + Jo's Speed

Combined Speed = 70 mph + 60 mph

Combined Speed = 130 mph

Now, you can use this combined speed to calculate the time it will take for them to meet:

Time = Distance / Combined Speed

Time = 1,170 miles / 130 mph

Time = 9 hours

Therefore, time taken by Jan and Jo is 9 hours to meet while driving toward each other on the same road.

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Find the mode for the following distribution. Number Frequency 220 6 230 7 240 3 250 1 260 0 270 1 No mode 220 230 260 250 and 270

Answers

They do not occur more frequently than any other value in the distribution, the values 220, 260, 250, and 270 are not modes.

How to finding the value that appears the most frequently will help us determine the mode of a distribution.?

Distributed mode is the most common value. From the given frequency distribution we can see that both the values 220 and 230 occur with the highest frequencies of 6 and 7 respectively. Therefore, both 220 and 230 are modes of this distribution.

that the values 260, 250, and 270 are not modes, as they all have frequencies of 0 or 1. Also, the No Mode value is not a valid value in the distribution, indicating that there is no single mode value.

The values 220, 230, 240, 250, 260, and 270 all appear six times in this distribution, seven times each for values 230, seven times for values 240, one for value 250, zero for values 260, and one for value 270.

As a result, the value with the highest frequency—230—is the mode. Therefore, 230 is the mode for this distribution.

Due to the fact that they do not occur more frequently than any other value in the distribution, the values 220, 260, 250, and 270 are not modes.

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At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 10 cubic feet per minute. the diameter of the base of the cone is approximately three times the altitude. at what rate is the height of the pile changing when the pile is 12 feet high?

Answers

1. You have that the rate is10 ft³/min. Then:

dV/dt=10

2. The formula for calculate the volume of a cone, is:

V=1/3(πr²h)

"r" is the radius and "h" is the height.

3. The diameter of the base of the cone is approximately 3 times the altitude. Then, the radius is:

r=diameter/2

diameter=3h

r=3h/2

4. When you susbstitute r=3h/2 into the formula V=πr²h/3, you have:

V=1/3(πr²h)
V=1/3(π(3h/2)²(h)
V=1/3(π9h²/4)(h)
V=9πh³/12

5. Therefore:

dV/dt=(9πh²/4)dh/dt

h=12

dV/dt=10

6. When you substitute the values of dV/dt and h into dV/dt=(9π(12)²/4)dh/dt, you have:

dV/dt=(9π(12)²/4)dh/dt
10=(1017.876)

7. Finally, you obtain:

dh/dt=10/1017.876
dh/dt=9.82x10^-3 ft/min

Final answer:

The problem involves the concept of related rates in Calculus. By using the relationship between the height and radius of the cone and the rate of change of the volume, we set up a differential equation. Upon solving, we find the rate at which the height of the pile changes is 5/(18π) feet per minute when the pile is 12 feet high.

Explanation:

The subject matter of this question is related to Calculus, specifically the concept of related rates. In this scenario, sand is falling off a conveyor and onto a conical pile at a rate of 10 cubic feet per minute. Here, the given rate is the rate of change of the volume of the sand pile. The diameter of the base of the cone is approximately three times the altitude, which gives the relationship between the height and the radius of the cone: r=h/3. The student is asked to find at what rate the height of the pile is changing when the pile is 12 feet high.

First, let's recall the formula for the volume of a cone, which is V=(1/3)*π*r²*h. Based on the relationship between the radius and the height, we can substitute r with h/3. Therefore, the volume V=(1/3)*π*(h/3)²*h = (1/27)*π*h³. By differentiating this equation with respect to time t, we get dV/dt = (1/9)*π*h²*dh/dt.

We are given that dV/dt is 10 cubic feet per minute, and we want to find dh/dt when h = 12 feet. Substituting these values into the differentiated equation, we get 10 = (1/9)*π*(12²)*dh/dt. Solving this for dh/dt, we find that dh/dt = 10 / [(1/9)*π*(12²)] = 5/(18π) feet per minute.

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Team tool Bella canoed 15 3/4 miles in 5 1/4 hours. What was their average rates of speed in miles per hour?

Answers

you would divide the distance by the time and then you would get 3 because 15 3/4 divided by 5 1/4 in 3

Answer:

3 miles per hour

Step-by-step explanation:

Using speed formula:

[tex]\text{Speed} = \frac{\text{Distance}}{\text{Time}}[/tex]

As per the statement:

Team tool Bella canoed 15 3/4 miles in 5 1/4 hours.

⇒[tex]\text{Distance} = 15\frac{3}{4} = \frac{63}{4}[/tex] miles and

[tex]\tetx{Time} = 5\frac{1}{4} = \frac{21}{4}[/tex] hours

Using speed formula we have;

[tex]\text{Speed}= \frac{\frac{63}{4} }{\frac{21}{4}} = \frac{63}{4} \cdot \frac{4}{21} = \frac{63}{21}[/tex]

Simplify:

[tex]\text{Speed} =3[/tex] miles per hour

Therefore, their average rates of speed in miles per hour is, 3 miles per hour

Choose the correct simplification of the expression g5h4/g2h3

Answers

the answer is
[tex]g ^{3} h [/tex]
because you subtract exponents

0/17 into a decimal using long division

Answers

The decimal would be 0 because it doesn't have anything to give.

Brainliest please?

0 divided by 17 would result in 0. Therefore, not resulting in a decimal.

Chord AC intersects chord BD at point P in circle Z.

AP=3.5 in.
DP=4 in.
PC=6 in.

What is BP?

Enter your answer as a decimal in the box.

Answers

The answer to this is 5.25.

Answer: The value of BP is 5.25.

Step-by-step explanation:

Here's why:

Find the ratio between the two different groups of line segments. If you do it in decimal or fraction, it's the same. So, 4/6 = 0.666666667. Then you must find the number that when 3.5 is divided by it, gives you 0.666666667. So that number is 5.25.

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