What is the boiling point of an benzene solution that freezes at 0.3 degrees C? Normal freezing point is 5.5 and the normal boiling point is 80.1 degrees C. Kfp = 5.12 K/m and Kbp = 2.53 K/m. Enter your answer to 2 decimal places.

Answers

Answer 1

Answer: The boiling point of an benzene solution is [tex]82.57^0C[/tex]

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=(5.5-0.3)^0C=5.2^0C=5.2K[/tex] = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

[tex]K_f[/tex] = freezing point constant = [tex]5.12K/m[/tex]

m= molality

[tex]5.2=1\times 5.12\times m[/tex]

[tex]m=1.015[/tex]

Elevation in boiling point is given by:

[tex]\Delta T_b=i\times K_b\times m[/tex]

[tex]\Delta T_b=Tb-Tb^0=(Tb-80.1)^0C[/tex] = elevation in boiling point

i= vant hoff factor = 1 (for non electrolyte)

[tex]K_b[/tex] = boiling point constant = [tex]2.43K/m[/tex]

m= molality = 1.015

[tex](T_b-80.1)^0C=1\times 2.43\times 1.015[/tex]

[tex]T_b=82.57^0C[/tex]

Thus the boiling point of an benzene solution is [tex]82.57^0C[/tex]


Related Questions

A loaf of bread (volume 3100 cm3) with a density of 0.90 g/cm3 is crushed in the bottom of the grocery bag into a volume of 1240 cm3. What is the density of the mashed bread? . g/cm3

Answers

Answer:

2,25 g/cm3

Explanation:

Hi, you have to know one thing for this.. Density = mass/Volume,

When you have the loaf of bread with 3100 cm3 and a density of 0.90 g/cm3, the mass of that bread is 2790 g because of if you isolate the variable mass from the equation you get..  mass= density x volume

Later, have on account the mass never changes, so you crush the bread and the mass is the same.. so when you have the mashed bread.. you know that the mass is 2790 g and the volume of the bag is 1240 cm3, so you apply the main equation.... density=2790 g / 1240 cm3 , so density =  2,25 g/cm3

Final answer:

The density of the mashed bread is 2.25 g/cm³, calculated by dividing the mass of the original loaf (found by multiplying its original density and volume) by the new volume after being crushed.

Explanation:

The density of the original loaf of bread is given as 0.90 g/cm³, and its initial volume is 3100 cm³. When the bread is crushed, its volume is reduced to 1240 cm³. Density is the ratio of the mass of a substance to its volume. Because the mass of the bread remains the same even when it is crushed, we can find the new density by using the mass from the original loaf. The mass can be calculated by multiplying the original density by the original volume. The calculated mass is then divided by the new volume.

Mass = Original density × Original volume = 0.90 g/cm³ × 3100 cm³ = 2790 grams

Now, we divide the mass by the new volume to get the density of the mashed bread:

Density of mashed bread = Mass / New volume = 2790 g / 1240 cm³ = 2.25 g/cm³.

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