Answer:
Na20
Explanation:
I did a quick google search and it was right there lol
Answer:
It would be Na20 please mark brainliest have a nice day
What happens to the equilibrium shift when NaOH is added to ammonium?
Answer:
I believe it goes to the left
Explanation:
GOOGLE it or ask me for more questions :)
the balloon is inflated outdoors on a cold day in North Dakota at a temperature of -35°C to a volume of 3.0 L. The pressure remains constant. What is the volume of the balloon indoors at a temperature of 25°C?
3.75 litres is the volume of the balloon indoors at a temperature of 25°C.
Explanation:
Data given:
initial temperature of the gas in balloon = -35°C or 238.15 K
initial volume = 3 litres
final temperature = 25 °C or 298.15 K
final volume =?
pressure remains constant
From the data given when pressure is constant Charles' law is applied.
[tex]\frac{V1}{T1}[/tex] = [tex]\frac{V2}{T2}[/tex]
Rearranging the equation to know the final volume of the gas in balloon
V2 = [tex]\frac{V1T2}{T1}[/tex]
V2 = [tex]\frac{3 X 298.15}{238.15}[/tex]
V2 = 3.75 Litres
when the temperature of a gas is increased and pressure remains constant the volume of the gas increases.
The Volume of the balloon indoors in increased by 3.8 L.
Explanation:
As per the Charles law, at constant pressure the volume of the gas is in direct proportion with the temperature measured in Kelvin. As temperature increases, the volume expands that is increases and vice-versa.
[tex]$\frac{V1}{T1} = \frac{V2}{T2}[/tex]
T1 = -35° C + 273 K = 238 K
T2 = 25° C + 273 K = 298 K
V1 and T1 are the Volume and the temperature of the balloon inflated outdoors.
V2 and T2 are the Volume and the temperature of the balloon inflated indoors.
V2 can be found by rearranging the above equation as,
[tex]$V2 = \frac{V1 T2}{T1}\\[/tex]
[tex]$V2 = \frac{3 L \times 298 K}{238 K}[/tex]
= 3.8 L
So the Volume of the balloon indoors in increased by 3.8 L.
what are 5 things in our house that uses electrical energy and how
Answer:
Heating.
Cooling.
Water Heater.
Washer and Dryer.
Lights.
Refrigerator.
Electric Oven.
Dishwasher.
Charging devices
Explanation:
People use electricity for lighting, heating, cooling, and refrigeration and for operating appliances, computers, electronics, machinery, and public transportation systems.
How it works is a current of electricity is a steady flow of electrons. When electrons move from one place to another, round a circuit, they carry electrical energy from place to place like marching ants carrying leaves. Instead of carrying leaves, electrons carry a tiny amount of electric charge
Hope this helped some!
Answer: microwave, TV, lamps, refrigerator, and last but not least a stove.
Which elements have high densities, strength, and resistance to corrosion?
10 points
alkali metals
alkaline earth metals
metalloids
transition elements
Answer:
transition elements
Explanation:
Metalloids are elements that have properties intermediate between those of metals and nonmetals. They are sometimes referred to as semi-metals. These materials have recently found great application in materials science and information technology.
Transition elements are however renowned for high densities and tensile strength. The transition elements have the highest density of all the element groups in the periodic table and also have resistance to corrosion. Transition metals such as gold silver and lead are coinage metals because they are resistant to corrosion.
Alkali and alkaline earth metals tarnish easily due to their high reactivity. They are usually very soft metals.
Answer:
Transition elements
Explanation:
Transition elements occupies the middle section of the periodic table. Generally, transition elements are metallic in nature. Examples of transition elements are scandium, titanium , vanadium, copper, cobalt, zinc , chromium, manganese , iron etc. Since transition elements are all metallic they are hard , lustrous , are good conductor of electricity and heat and have a high melting and boiling points .
Transition metals are also used as catalyst in many reactions. Transition metals have high densities compare to alkali and alkali earth metals. Transition element are less reactive compare to other metallic elements like the alkali and alkaline earth metals .
Transition metals are usually less reactive and they rarely react with oxygen in air . This resistance account for it noncorrosive nature. Example of this noncorrosive transition metals are silver, Titanium, chromium, manganese, copper etc .
Alkali and alkali earth metals are very reactive so they are likely corrosive. Metalloids don't have high densities and strength.
What happened as Leah and Isaac moved down the small slope from point C to D?
A.
Their kinetic energy decreased.
B.
Their kinetic energy changed to potential energy.
C.
Their potential energy increased.
D.
Their potential energy changed to kinetic energy.
Answer:
D
Explanation:
As you move down anything, towards the earth, (gravitational) potential energy decreases. This eliminates options B and C.
By the law of conservation of energy, the energy of the system stays the same. However the energy may be converted into different forms. In this case, the potential energy is converted into kinetic energy - this is what makes people move faster as they go down the slope. This makes option A wrong and option D right.
STOICHIOMETRY! ASAP PLEASE! What mass of carbon dioxide is produced when 6.2
moles of propane (C3H8) is burned in oxygen?
_C3H8 + _ 02 → __ CO2 + _H20
When 6.2 moles of propane is burned in oxygen, it produces approximately 818.4 g of carbon dioxide.
Explanation:Here, stoichiometry (a branch of Chemistry) is used to determine the product generated from a known quantity of reactants. The balanced equation for the combustion of propane is C3H8 + 5O2 → 3CO2 + 4H2O. This shows that 1 mole of propane (C3H8) produces 3 moles of carbon dioxide (CO2). So, it's a 1:3 ratio. Given that the molar mass of CO2 is approximately 44 g/mol, you can first find how many moles of CO2 are produced by multiplying the given moles of propane by 3 (6.2 × 3 = 18.6 moles CO2). Then, determine the mass by multiplying the moles of CO2 by the molar mass of CO2 (18.6 × 44 = 818.4 g). Thus, the combustion of 6.2 moles of propane yields 818.4 g of carbon dioxide.
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How many calories must be absorbed by 20.0 g of water to increase its temperature from 383.0 C to 303.0 C
Answer:
1600 calories
Explanation:
Data obtained from the question include:
M (mass of water) = 20g
T1 (initial temperature) = 383°C
T2 (final temperature) = 303°C
ΔT (change in temperature) = T1 - T2 = 383 - 303 = 80°C
C (specific heat capacity of water) = 1 calorie/g°C
Q (heat) =?
Using the the equation Q = MCΔT, the heat in calories absorbed by the water can be obtained as follow:
Q = MCΔT
Q = 20 x 1 x 80
Q = 1600 calories
Therefore, the heat absorbed by the water is 1600 calories
Name the ions in water acidified with dilute sulphuric acid
Answer:
H + ions are attracted to the cathode , gain electrons and form hydrogen gas. OH - ions are attracted to the anode , lose electrons and form oxygen gas.
How many grams of sodium bromide must be dissolved in 400.0 g of water to produce a 0.500 molar solution?
A20.0 g
B52.18
C2.00 g
D20.6 g
Answer:
D. 20.6g
Explanation:
Molarity is defined as ratio between moles of solute (sodium bromide, NaBr) per liter of water.
As density of water is 1g/mL; volume of 400.0g of water is 400.0mL = 0.4000L.
That means 0.400L of 0.500M solution contains:
0.400L × (0.500mol / 1L) = 0.200moles of sodium bromide.
In mass (NaBr = 102.9g/mol):
0.200mol NaBr × (102.9g/mol) = 20.6g of NaBr
Right answer is:
D. 20.6g
4. A solution contains 4.5 x 10^-5 M HCl. Determine the following:
a. [H3O+] b. [OH-] c. pH
Answer:
[H3O+] = 4.5 x 10^-3 M
[OH-] = 1.0 x 10^-14 / 4.5 x 10^-3 =2.2 x 10^-12 M
pH = - log [H3O+]= - log 4.5 x 10^-3 =2.3
A solution contains 4.5 × 10⁻⁵M HCl so the concentration of hydronium ion is 4.5 × 10⁻⁵M, pH of the solution is 4.34 and concentration of hydroxide ion is 2.2 × 10⁻⁸M.
How do we calculate pH?pH of any solution will be calculated as pH = -log[H⁺], where
[H⁺] = concentration of H⁺ or H₃O⁺ ion
Given concentration of HCl = 4.5 × 10⁻⁵M
HCl is a strong acid so that it completely dissociates into their ions as:
HCl → H⁺ + Cl⁻
From the stoichiometry, 1 mole of HCl produces 1 mole of H⁺ ion.
Concentration of H⁺ ion = 4.5 × 10⁻⁵M
Now we calculate pH by using the concentration value as:
pH = -log(4.5 × 10⁻⁵)
pH = -(-4.34) = 4.34
Also we know the relation:
[H⁺][OH⁻] = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ / 4.5 × 10⁻⁵ = 2.2 × 10⁻⁸M
Hence required values are (a)4.5 × 10⁻⁵M, (b)4.34 and (c)2.2 × 10⁻⁸M.
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How many grams of magnesium(Mg, 24.30 g/mol) are in 7.43×10^22 atoms Mg?
Final answer:
To find the number of grams of magnesium in 7.43×10²² atoms, convert the number of atoms to moles and then to grams using the molar mass of magnesium.
Explanation:
To calculate how many grams of magnesium are in 7.43×10²² atoms of Mg, you need to convert the number of atoms to moles and then to grams. The molar mass of magnesium is 24.30 g/mol, which means that one mole of magnesium atoms weighs 24.30 grams.
First, calculate the number of moles of magnesium using the Avogadro's number and the given number of atoms: (7.43×10²² atoms) / (6.02×10²³ atoms/mol) = 0.123 moles of Mg.
Next, multiply the number of moles by the molar mass to get the grams of magnesium: 0.123 moles × 24.30 g/mol = 2.992 grams of Mg.
All minerals are made up of ____________(elements or rocks).
Answer:
elements
Explanation:
You have a balloon filled with hydrogen gas
which keeps it at a constant pressure,
regardless of its volume. The initial volume of
the gas is 736 mL at 15.0°C. The gas is heated
until its volume is 2.28 L, what is its final
temperature in degrees Celsius?
Answer:
619.2 K
Explanation:
We can solve this problem by using Charle's Law, which states that:
"For a fixed mass of an ideal gas kept at constant pressure, the volume of the gas is directly proportional to its absolute temperature"
Mathematically:
[tex]V\propto T[/tex]
where
V is the volume of the gas
T is the absolute temperature
The equation can be rewritten as follows for a gas that undergoes a transformation at constant pressure:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where in this problem:
[tex]V_1=736 mL = 0.736 L[/tex] is the initial volume of the gas
[tex]T_1=15.0C+273=288 K[/tex] is the initial temperature
[tex]V_2=2.28 L[/tex] is the final volume of the gas
Solving for T2, we find the final temperature:
[tex]T_2=\frac{V_2 T_1}{V_1}=\frac{(2.28)(288)}{0.736}=892.2 K[/tex]
Converting into Celsius degrees,
[tex]T_2=892.2-273=619.2 K[/tex]
Answer:
619
Explanation:
it takes of the 0.2 on CK12
Kinetic molecular theory makes several assumption about
Answer:
Explanation:
The KM Theory is the 'micro' molecular description of the behavior of matter. That is, the theory takes into account particle-particle interactions. This is contrast with the 'macro' molecular description of matter that is based upon empirical relationships without taking into account particle - particle interactions.
For example, Charles Law defines the relationship of gas volume as a function of temperature as being direct. That is, an increase in temperature results in an increase in volume of gas. No mention is made of the fact that the increasing temperature is increasing the kinetic energy content of the particles causing an increase in velocity of the particles.
However, application of the principles of the KM Theory takes into account the relationship between kinetic energy and particle velocity in terms of increasing temperature and transfer of energy to specific quantities of matter. Such results are based upon probability concepts that 4 primary reaction factors must come together simultaneously to effect a chemical reaction. These are ...
1. reactive concentration of reactants => C
2. effective collisions occurring (orientation of particles on collisions) => E
3. the interaction of reactive structures by nature => N
4. temperature - energy conditions initiate reaction (activation energy point) => T
These are assumptions are 'reaction factors' (=> C.E.N.T for memory purposes) that must come together simultaneously to effect a reaction. The greatest probability of this occurring is at the temperature condition called the 'Activation Energy'. The relationship that defines this probability is called the Arrhenius Equation k = Ae^-ΔEₐ/RT where k is the kinetic rate constant, A is a proportionality constant, ΔEₐ the Activation Energy and T the Kelvin Temperature.
PLEASEEEE HELPPPP I BEGG FOR HELPPP PLEASE
________________ are powered by redox reaction.
A) diesel engines B) steam engines C) rocket engines D) gasoline engines
Answer:
I beleive its diesel engines
Explanation:
The positive and negative ions in two compounds switch places is ______________ *
fill in the blank:
synthesis
decomposition
combustion
single replacement
double replacement
Answer: double-replacement reaction
Explanation:
Given the balanced ionic equation:
3Pb2+(aq) + 2Cr(s) ---> 3Pb(s) + 2Cr3+(aq)
what is the number of moles of electrons gained by 3.0 moles of lead ions?
1. 5.0 mol
2. 2.0 mol
3. 3.0 mol
4. 6.0 mol
Answer : The correct option is, (4) 6.0 mol
Explanation :
The given balanced chemical equation is,
[tex]3Pb^{2+}+2Cr\rightarrow 3Pb+2Cr^{3+}[/tex]
In this reaction, lead undergoes reduction and chromium undergoes oxidation.
Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.
Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.
Half reactions of oxidation-reduction are :
Oxidation : [tex]2Cr\rightarrow 2Cr^{3+}+6e^-[/tex]
Reduction : [tex]3Pb^{2+}+6e^-\rightarrow 3Pb[/tex]
From the reduction reaction, we conclude that 6 moles of electrons gained by the 3 moles of lead ions.
Hence, the correct option is, (4) 6.0 mole
explain why the formation of sand is a physical change
Answer:
Sand is still sand but if you were to change the feel of sand it would not be sand
Explanation:
Why do you need to know the balanced chemical equation before calculating the amount of a compound needed to neutralize an acid or a base?
Answer: To determine the mole ratio
Explanation:
A balanced chemical equation is needed ,because it helps to determine the mole ratio of acid and base.
The mole ratio ensures that the number of moles of H+ provided by the acid is equal to number of moles of OH- ion provided by the base, For neutralization to occur, this must be the case.
What are the functional groups in oxybenzone?
Answer:
Oxybenzone contains ether, phenol and ketone (-CO) functional group alonq with two aromatic rings.
Explanation:
Answer: apply to almost every part of your body especially like
Explanation: the ears , scalp, back of the neck , and top of the feet , and back of heels.
What is the name of S2Br6
Answer:
disulfur hexabromide
Explanation:
First, identify the element names using your periodic table.
"S" means sulfur. "Br" means bromine. The second element drops the ending and adds "-ide".
S₂Br₆
sulfur bromide
Decide if the compound is ionic or covalent.
Since there are two non-metals, this is a covalent compound. So, will use Greek prefixes for the number of atoms. You can see the list below and find "2" and "6".
S₂Br₆
disulfur hexabromide
List of Greek number prefixes:
1 mono
2 di
3 tri
4 tetra
5 penta
6 hexa
7 hepta
8 octa
9 nona
10 deca
The name of S₂Br₆ is disulfur hexabromide.
4.How many grams of NaCl would need to be added to 1001 g of water to increase the boiling temperature of the solution by 1.500 °C? (Kb for water is 0.5100 °C/m)
5. A solution is made using 80.1 g of toluene (MM = 92.13 g/mol) and 80.0 g of benzene (MM = 78.11 g/mol). What is the molality of the toluene in the solution?
Answer :
(4) The mass of NaCl needed would be, 172.2 grams.
(5) The molality of toluene in the solution is, 10.9 mol/kg
Explanation :
Part 4:
[tex](K_b)[/tex] for water = [tex]0.5100^oC/m[/tex]
[tex]\Delta T_b=1.500^oC[/tex]
Mass of water (solvent) = 1001 g = 1.001 kg
Molar mass of NaCl = 58.5 g/mole
Formula used :
[tex]\Delta T_b=i\times K_b\times m\\\\\Delta T_b=i\times K_b\times\frac{\text{Mass of NaCl}}{\text{Molar mass of NaCl}\times \text{Mass of water in Kg}}[/tex]
where,
[tex]\Delta T_b[/tex] = change in boiling point
i = Van't Hoff factor = 2 (for NaCl electrolyte)
[tex]K_b[/tex] = boiling point constant for water
m = molality
Now put all the given values in this formula, we get
[tex]1.500^oC=2\times (0.5100^oC/m)\times \frac{\text{Mass of NaCl}}{58.5g/mol\times 1.001kg}[/tex]
[tex]\text{Mass of NaCl}=172.2g[/tex]
Therefore, the mass of NaCl needed would be, 172.2 grams.
Part 5:
Formula used :
[tex]\text{Molality}=\frac{\text{Mass of toluene}\times 1000}{\text{Molar mass of toluene}\times \text{Mass of benzene (in g)}}[/tex]
Given:
Mass of toluene = 80.1 g
Mass of benzene = 80.0 g
Molar mass of toluene = 92.13 g/mol
[tex]\text{Molality}=\frac{80.1g\times 1000}{92.13g/mole\times 80.0g}=10.9mole/kg[/tex]
Therefore, the molality of toluene in the solution is, 10.9 mol/kg
The combustion of 1.760 g of propanol (C3H7OH) increases the temperature of a bomb calorimeter from 298.00K to 302.15K. The heat capacity of the bomb calorimeter is 14.24 kJ/K. Determine ΔH for the combustion of propanol to carbon dioxide gas and liquid water in kJ/mol.
Final answer:
To find the ΔH for the combustion of propanol, the heat released is calculated with the calorimeter's heat capacity and temperature change, and then scaled to a per-mole basis.So,combustion of propanol to carbon dioxide gas and liquid water in kJ/mol was -2012.45 kJ/mol.
Explanation:
The question involves finding the ΔH (enthalpy change) for the combustion of propanol (C3H7OH). To calculate the enthalpy change of the reaction, we first need to calculate the heat released (q) during the combustion using the formula: q = C × ΔT, where C is the heat capacity of the calorimeter and ΔT is the change in temperature.
Using the provided data, the heat released by the combustion is:
q = 14.24 kJ/K × (302.15K - 298.00K)
This results in q = 59.288 kJ (rounded to three decimal places), which is the heat released when 1.760 grams of propanol are burned. To find ΔH per mole of propanol, we need the molar mass of propanol (C3H7OH), which is approximately 60.10 g/mol. Thus, we can calculate ΔH using the proportion:
ΔH (per mole) = q (per 1.760 g) × (60.10 g/mol / 1.760 g).
The final calculation yields ΔH as -2012.45 kJ/mol (rounded to two decimal places).
The heat of vaporization AHv, of ammonia (NH3) is 23.4 kJ/mol. Calculate the change in entropy AS when 23. g of ammonia boils at -33.5 °C.
Be sure your answer contains a unit symbol and the correct number of significant digits.
Answer:
ΔS(23g NH₃) = 132.2 j/K ≅ 130 j/K (~2 sig. figs. based on 2 sig. figs. in 23 grams NH₃).
Explanation:
Given ΔHv(NH₃) = 23.4 Kj/mol = 23,400 joules/mole
T = -33.5°C = (-33.5 + 273)K = 239.5K
molar ΔS (at boiling) = ΔHv/T = 23,400 j/mol / 239.5K = 97.70 j/mol·K
ΔS(23g NH₃) = molar ΔS (at boiling) x (moles NH₃) = 97.70j/mol·K x (23g/17g·mol⁻¹) = 132.2 j/K ≅ 130 j/K (~2 sig. figs. based on 2 sig. figs. in 23 grams NH₃).
The change in entropy when 23 g of ammonia boils at -33.5 °C is 0.178 kJ/K. To find this, the mass of ammonia was converted to moles, the given temperature was converted to Kelvin, and then the heat of vaporization was divided by the temperature.
Explanation:To calculate the change in entropy (ΔS) when 23 g of ammonia boils at -33.5 °C, we'll use the heat of vaporization (ΔHv) of ammonia, which is 23.4 kJ/mol. First, we convert the given mass of ammonia to moles by using its molar mass (17.03 g/mol for NH3). This gives us:
23 g / 17.03 g/mol = 1.351 moles of ammonia.
Next, we use the formula ΔS = ΔHv / T, where T is the temperature in kelvin.
Since the boiling occurs at -33.5 °C, we first need to convert this temperature to Kelvin:
T = -33.5 °C + 273.15 = 239.65 K.
The total change in entropy for the vaporization of ammonia is then:
ΔS = (23.4 kJ/mol × 1.351 mol) / 239.65 K,
ΔS = 31.61 kJ / 239.65 K = 0.1318 kJ/K × 1.351 = 0.178 kJ/K (or 178 J/K).
This is the change in entropy for the given amount of ammonia with the correct number of significant digits and units.
What 3 things must occur for a reaction to successfully take place
Answer:
So, the three conditions for a chemical reaction to occur are: Temperature should be above absolute zero. Chemical reactants must be in close, proximate, physical contact. The reaction must have negatie free energy (exergonic) and the system must provide it sufficient energy to overcome the Activation Energy Barrier.
What is the Law of Conservation of Mass? 60g + 40g = 100g
Answer:
100g like you answered it yourself
Explanation:
The two main postulates that was given by Antoine Lavoisier are, oxygen play an important role in combustion and the other is mass of the reactant and product is conserved. The total mass of reactant must be equal to total mass of product.
What is law of conservation of mass?According to Law of conservation of mass, mass can neither be created nor be destroyed. Mass can only be transformed from one form to another. The law of conservation of mass was given by Antoine Lavoisier.
Every reaction in nature follow the law given by Antoine Lavoisier that is mass is always conserved. Another postulated that was given by Antoine Lavoisier is the role of oxygen in combustion reaction. total mass of reactant must be equal to total mass of product.
Therefore, the total mass of reactant must be equal to total mass of product.
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How many moles are equal to 5.82 x 10^23 atoms of tungsten (w)
Answer:
0.97 mole
Explanation:
1 mole will give 6.02×10^23 atoms
Xmole of tungsten will give 5.82×10^23 atom of tungsten
X= 5.82×10^23/ 6.02×10^23
X = 0.97 moles of tungsten
Answer:
0.967 moles
Explanation:
number of moles = number of atoms / avogadro's number
We are given;
Number of atoms = 5.82×10^23
Avogadro's number = 6.02×10^23
Therefore, number of moles
= (5.82×10^23)/(6.02×10^23)
=0.967mol
Therefore, 0.967 moles are equal to 5.82×10^23 atoms
3.200 x 109 has how many sig figs?
Answer:
It has 4 significant figures
Explanation:
Notice the use of scientific notation to indicate that there are two zeros which should be significant. If this number were to be written without scientific notation (3,200,000,000) the significance of those two zeros would be lost and you would - wrongly - say that there were only two significant figures.
Water forms according to the equation below:
2H2(g) + O2(g) -> 2H2O(g) ΔHrxn = -483.64 kJ
How much energy is released during the formation of 1 mol H2O(g)?
__kJ
Answer:
241.82 kJ is released
Explanation:
The reaction indicates that 483.64 kJ of energy is released when TWO moles of H2O(g) is formed. You're looking to find the amount of energy released when only ONE mole of H2O forms, so that would be half the amount of energy released in the reaction (as one mole is a half of two).
483.64 / 2 = 241.82 kJ
So, your answer would be 241.82 kJ is released.
The formation of 1 mole of water (H_2O) in the given chemical reaction releases 241.82 kJ of energy.
The reaction described in the question, 2H_2(g) + O_2(g) -> 2H_2O(g) with ΔHrxn = -483.64 kJ, shows that the formation of 2 moles of water (H_2O) releases 483.64 kJ of energy.
It's an exothermic reaction, meaning energy is released. That said, if we want to find out the amount of energy released during the formation of 1 mole of water, we divide the total energy by 2.
Thus, the formation of 1 mole of water (H_2O) releases 483.64 kJ / 2 = 241.82 kJ of energy.
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why does chocolate melt faster when crushed?
Answer:
It is because when a chocolate is crushed, it will be smaller pieces which exerts a larger surface area. So that it can easily take in heat to give out reaction.