What is the critical path?
A. The path from resource to task that passes through all critical components of a project plan
B. The path between tasks to the projects finish that passes through all critical components of a project plan
C. The path from start to finish that passes through all the tasks that are critical to completing the project in the shortest amount of time
D. The path from start to finish that passes through all the tasks that are critical to completing the project in the longest amount of time

Answer:

#include <iostream>

#include <string>

using namespace std;

int

stringLength (string str)

{

 int i = 0;

 int count = 0;

 while (0 == 0)

   {

     if (str[i])

{

  i++;

  count++;

}

     else

{

  break;

}

   }

 return count;

}

int

main ()

{

 string userinput;

 cout << "Enter string ";

 getline (cin, userinput);

 int string_length = stringLength (userinput);

 int vowels=0;int numeric=0;int consonants=0;int special = 0;

 for (int i = 0; i < string_length; i++)

   {

     if (userinput[i] == 'a' ||

  userinput[i] == 'e' ||

  userinput[i] == 'i' ||

  userinput[i] == 'o' ||

  userinput[i] == 'u' ||

  userinput[i] == 'y' ||

  userinput[i] == 'A' ||

  userinput[i] == 'E' ||

  userinput[i] == 'I' ||

  userinput[i] == 'O' || userinput[i] == 'U' || userinput[i] == 'Y')

{

  vowels++;

}

    else if (userinput[i] - 48 > 0 && userinput[i] - 48 <= 9)

{

  numeric++;

}

     else if (userinput[i] == '~' ||

  userinput[i] == '!' ||

  userinput[i] == '@' ||

  userinput[i] == '#' ||

  userinput[i] == '$' ||

  userinput[i] == '%' ||

  userinput[i] == '^' ||

  userinput[i] == '&' ||

  userinput[i] == '*' ||

  userinput[i] == '(' ||

  userinput[i] == ')' ||

  userinput[i] == '_' ||

  userinput[i] == '+' ||

  userinput[i] == '-' ||

  userinput[i] == '+' ||

  userinput[i] == ':' ||

  userinput[i] == ':' ||

  userinput[i] == '?' ||

  userinput[i] == '/' || userinput[i] == '<' || userinput[i] == '>')

{

  special++;

}

     else

{

  consonants++;

}

}

cout << vowels << " vowels and " << consonants << " consonants and " << special

 << " special characters and " << numeric << " numbers." << endl;

return 0;

}

Explanation:

Answer:

list1 = [1, 2, 3]

list2 = [4, 5, 6]

list3 = []

newlist = []

for i in list1:

   for j in list2:

       if list1.index(i) == list2.index(j):

           newlist.append(j)

           newlist.append(i)

           break

for i in reversed(newlist):

   list3.append(i)

print(list3)

Explanation:

The programming language used is python.

List 1 and 2 are initialized, and two empty lists are initialized too, these two lists are going to be used in generating the new list.

Two FOR loops are used for both list one and two respectively, to iterate through their content, the IF statement and the break is placed within the for loop to ensure that there is no repetition.

The index of list 1 and list 2 are appended (added) to a new list one at a time.

The new list is then reversed and its content are added to list 3 to give the final solution.

NOTE: The reason a separate list was created was because the reversed() function does not return a list, so in order to get the list, it must be added to an empty list as you reverse it.

Answer:

Following are the program in the Python Programming Language:

1.)

l=['Ruby','Dale','Kate']

n=input('Enter the name: ')

if(n in l):

   print('Hello {}'.format(n))

else:

   print('No {}'.format(n))

Output:

Enter the name: Dale

Hello Dale

2.)

file=open("text1.txt", "r+") #open file

str=file.read()  #read file

txt=str.replace('\n', ' ') #replace spaces

word=txt.split(' ') #split words in ' '

for words in word: #set for loop

   word2=' '

   for i in range(len(words)):  #set for loop

       if(words[i].isalpha()):  #set if statement

           word2 += words[i].lower()

   word[word.index(words)]=word2

while(' ' in word):  #set while loop

   word.remove(' ')  #remove spaces

st=set(word)

print('The ', len(st),' unique words which appears in document are ' \

     '(in no particular order): ')

for words in st:  #set for loop

   print('-', word)

file.close()  #close file

3.)

file=open("text1.txt", "r+") #open file

str=file.read()  #read file

txt=str.replace('\n', ' ') #replace spaces

word=txt.split(' ') #split words in ' '

for words in word: #set for loop

   word2=' '

   for i in range(len(words)):  #set for loop

       if(words[i].isalpha()):  #set if statement

           word2 += words[i].lower()

   word[word.index(words)]=word2

while(' ' in word):  #set while loop

   word.remove(' ')  #remove spaces

dic={}  #set dictionary

for words in word:  #set for loop

   if(words not in dic):  #set if statement

       dic[words]=1

   else:

       dic[words] +=1

print('\033[4m' + 'word   frequency' + '\033[0m')

for words in dic:

   print(format(words, '15s'), format(dic[words], '5d'))

file.close() #close file

Explanation:

1.) Here, we define the list data type variable 'l' then, set the variable 'n' and assign value by get input from the user,

2.) Here, we define the variable "file" in which we open file and save that file in it.

Then, we set variable st which read the file then we set the variable in which we apply the replace().

Then. we set variable in which we split the by suing split()

2.) Here, we define the variable "file" in which we open file and save that file in it.

Then, we set variable st which read the file then we set the variable in which we apply the replace().

Then. we set variable in which we split the by suing split()

Then, we apply all that given in the question.

Answer:AEIOU

Explanation:

Answer:

The correct option to the following question is an option (D).

Explanation:

Because RPO(Recovery point objective) is the objective in which we getting the greatest level of the privacy. confidence and the important thing is security for our resources.

The best thing is that the center of activity of the RPO in on the data and the overall elasticity of the loss of your company.

Answer:

The code to this question can be given as:

Second constructor code:

PhonePlan(int min,int messages) //define parameterized constructor and pass integer variables.

{  

freeMinutes = min;   //variable holds value of parameter.  

freeMessages = messages;  //variable holds value of parameter.

}

Explanation:

In the question, It is given that write a second constructor. So, the code for this question is given above that can be described as:

In the code above, the second constructor is added with numMinutes and numMessages parameters. Inside the constructor, the values of freeMinutes and freeMessages are initialized with the values passed as parameters.

The modified PhonePlan class with the second constructor that takes minutes and messages as parameters:

Write a second constructor, as instructed in the question. The code for this question is therefore given above and is as follows:

This code defines a constructor with parameters called "PhonePlan()". The two integer variables message and min are passed to this constructor. There is no value returned by the constructor, which has the same name as the class.  

We use the variable "freeMinutes and freeMessages" from the PhonePlan class, which is defined in this constructor. This variable stores the value of the parameter variable.

Learn more about Constructor here:

https://brainly.com/question/32203928

#SPJ3

Answer:

The correct program to this question can be given as:

Program:

//import package.

import java.util.Scanner; //scanner package.

public class CheckingPasscodes //define class.

{

//all the code run here.

public static void main (String [] args) //define main method

{

Scanner scnr = new Scanner(System.in); //create Scanner class Object

boolean hasDigit; //define variable.

String passCode; //define variable.

hasDigit = false; //assign value.

passCode = scnr.next(); //taking user input.

int let0 = passCode.charAt(0); //assign value in integer variable

int let1 = passCode.charAt(1); //assign value in integer variable

int let2 = passCode.charAt(2); //assign value in integer variable

//conditional statement.

if ((Character.isDigit(let0)||Character.isDigit(let1)||Character.isDigit(let2))) //if block

{

hasDigit = true; //assign value.

}

if (hasDigit) //if block

{

System.out.println("Has a digit."); //message.

}

else //else block

{

System.out.println("Has no digit.");  //message.

}

}

}

Output:

AB1

Has a digit.

Explanation:

In the given question there are many mistakes so we provide the correct solution to this question that can be described as follows:

To make corrections to your code, implies that we debug the code. The following are the reasons why your code is not working

The corrections to your code are:

The complete correct code is as follows:

import java.util.Scanner;

public class CheckingPasscodes {

   public static void main (String [] args) {

       Scanner scnr = new Scanner(System.in);

       boolean hasDigit;

       String passCode;

       hasDigit = false;

       passCode = scnr.next();

       char let0 = passCode.charAt(0);

       char let1 = passCode.charAt(1);

       char let2 = passCode.charAt(2);

       if (Character.isDigit(let0) || Character.isDigit(let1) || Character.isDigit(let2)){

           hasDigit = true;}

       if (hasDigit) {

           System.out.println("Has a digit.");}

       else {System.out.println("Has no digit.");}

   }

}

Read more about debugging at:

https://brainly.com/question/23527739

Answer:

The output of the given code is "AB-2".

Explanation:

The description of the java program can be given as:

That's why the output of this program is "AB-2".

Answer:

def nounToplural(tex):

   import re

   text = tex.split()

   new = []

   for word in text:

       if re.findall(r"y\b", word):

           word = re.sub(r"y\b", 'ies' ,word)

           new.append(word)

       elif re.findall(r"ch\b", word):

           word = re.sub(r"ch\b", 'ches' ,word)

           new.append(word)

       elif re.findall(r"sh\b", word):

           word = re.sub(r"sh\b", 'shes' ,word)

           new.append(word)

       elif re.findall(r"s\b", word):

           word = re.sub(r"s\b", 'ses' ,word)

           new.append(word)

       else:

           word = word + 's'

           new.append(word)

   result = []

   for i in text:

       for j in new:

           if new.index(j) == text.index(i):

               result.append( (i,j) )

   print(result)

str = "chair dairy boss circuis fly dog church clue dish"

nounToplural(str)

Explanation:

We made use or Regular Expressions which is simply a special sequence of characters that helps you match or find other strings or sets of strings, by using a specialized syntax held in a pattern.

Firstly, define the function and import the regular expression module, split the text into a list and create an empty list to hold the plural list.

For every word in the list  we check with IF statements and regular expressions to find out what they end with.

 if re.findall(r"y\b", word):

           word = re.sub(r"y\b", 'ies' ,word)

           new.append(word)

The above IF block checks if a noun ends with 'y', if it does it replaces the 'y' with 'ies' and ads it to the new list.

If it does not, ot moves to the next IF/ELIF block.

In the ELIF blocks carry out a  a similar operation for "s", "ch", or "sh", in order to add "es".

Finally, 's' is added to all other cases using the ELSE block which traps any noun that did not fall under the IF or any of the ELIF blocks.

This last part of the code prints both list side by side and passes them to a new list result which is printed to the screen

result = []

   for i in text:

       for j in new:

           if new.index(j) == text.index(i):

               result.append( (i,j) )

   print(result)

I called the function and passed the string you provided in your question and attached the result of the code.

Answer:

The following are the program in the C++ Programming Language:

#include <iostream> //header file

#include <string>  //header file

#include <vector>  //header file

//name space

using namespace std;

//main function

int main() {

  vector<string> word; //set variable

  vector<int> c;  //set variable

  int s, counts = 0; //set variable

  string strng;  //set variable

  cout<<"Enter the size of string: "; //print message

  cin >> s; //get input

  cout<<"Enter the string: "; //print message

  for(int i = 0; i < s; ++i) {  //set for loop

     cin >> strng; //get input

     word.push_back(strng);

  }

  for(int i = 0; i < s; ++i) { //set for loop

         counts = 0;

         for(int j = 0;j<word.size();j++){ //set for loop

       if(word[j] == word[i]){ //set if statement

          counts++; //increament in counts

       }        

     }

      c.push_back(counts);

  }

  for(int i = 0; i < s; ++i) {

      cout << word[i] << " " << c[i] << endl;//print result

  }

  return 0;

}

Output:

Enter the size of string: 2

Enter the string: hello  sir

hello 1

sir 1

Explanation:

Here, we define three header files <iostream>, <String>, <vector> and namespace "std" after that we define main() method inside it.

In this exercise we have to write a C++ code requested in the statement, like this:

find the code in the attached image

We can write the code in a simple way like this below:

#include <iostream>

#include <string>

#include <vector>

using namespace std;

//main function

int main() {

 vector<string> word; //set variable

 vector<int> c;  //set variable

 int s, counts = 0; //set variable

 string strng;  //set variable

 cout<<"Enter the size of string: "; //print message

 cin >> s; //get input

 cout<<"Enter the string: "; //print message

 for(int i = 0; i < s; ++i) {  //set for loop

    cin >> strng; //get input

    word.push_back(strng);

 }

 for(int i = 0; i < s; ++i) { //set for loop

        counts = 0;

        for(int j = 0;j<word.size();j++){ //set for loop

      if(word[j] == word[i]){ //set if statement

         counts++; //increament in counts

      }        

    }

     c.push_back(counts);

 }

 for(int i = 0; i < s; ++i) {

     cout << word[i] << " " << c[i] << endl;//print result

 }

 return 0;

}

See more about C++ at brainly.com/question/19705654

Mostly the spyware and malware protection for desktop and laptop or workstations are to protected with anti-virus regular updates. All workstation or desktop or laptops are to updated operating systems patches.

If any operating systems patched update to be schedule and checked regularly. Schedule scanning by virus scanner to be made for desktop and laptop or workstations in regular interval basis

There are third parties tools such as malware and ADWCLEANER are also available free scanner software through internet where end user can download and scanner so software will clean the malware.

Mostly end user do mistake keep the files in desktop. Most of the malware software will affect the desktop folder only.

It will also affect c:\users folder and register enter keys.

Final answer:

The safeOpen() function in Python is used to open a file while handling exceptions. It returns the file object on success, or None if an error occurs, thus ensuring that the program can continue to run without crashing.

Explanation:

The function safeOpen() is designed to handle file operations within a Python program safely by attempting to open a file and returning a file object if successful, or None if an exception occurs. This function makes use of Python's built-in exception handling mechanisms to provide a secure way of accessing files. Here's an example of how you can define the safeOpen() function:
def safeOpen(filename):
   try:
       file = open(filename, 'r')
       return file
   except Exception as e:
       print("An error occurred: ", e)
       return None
In this code snippet, the try block attempts to open the specified file in read mode. If the file is opened successfully, the file object is returned. If any exception, such as FileNotFoundError or PermissionError, is raised during the attempt, the except block is executed, printing out the error message and returning None.

Answer:

A friend asks you for help writing a computer program to calculate the square yards of carpet needed for a dorm room. The statement "the living room floor is rectangular" is an example of a(n) assumption . The length and width of the room are examples of known information, which you can obtain as input from the user.

Explanation:

The given question is a Problem statement.

Problem statement can be defined as the brief description of an issue that needs to be focused in order to reach the require goal.

So the parts that a problem statement may have include:

So the attributes to be filled into blanks of given statement are assumption, known, input.

i hope it will help you!

Answer:

1. A

2. B

Explanation:

1. For an AND truth table to output true, all it input must be true. If one or any of the input is false, the output will be false. The truth table for AND is written below:

INPUT      INPUT      OUTPUT

FALSE      FALSE      FALSE

FALSE      TRUE        FALSE

TRUE        FALSE      FALSE

TRUE        TRUE        TRUE

2. The Internal Revenue Service web site is a good search tool when looking for income tax information. The federal government main web site might look like a correct option but one must understand that the federal government will only make the policy while the Internal Revenue Service will implement the policy.

Here's a C++ program that reads two rectangles' lengths and widths as integer values and tests if they are similar:

#include <iostream>

#include <cmath>

using namespace std;

bool areSimilar(int length1, int width1, int length2, int width2) {

   float lengthRatio = static_cast<float>(length1) / static_cast<float>(length2);

   float widthRatio = static_cast<float>(width1) / static_cast<float>(width2);

   return lengthRatio == widthRatio;

}

int main() {

   int length1, width1, length2, width2;

   cout << "Enter the length and width of the first rectangle: ";

   cin >> length1 >> width1;

   cout << "Enter the length and width of the second rectangle: ";

   cin >> length2 >> width2;

   if (areSimilar(length1, width1, length2, width2)) {

       cout << "The two rectangles are similar." << endl;

   } else {

       cout << "The two rectangles are not similar." << endl;

   }

   return 0;

}

This program defines a function areSimilar that takes the lengths and widths of two rectangles as input and returns a boolean value indicating whether the rectangles are similar. The function calculates the ratios of the lengths and widths and checks if they are equal. If the ratios are equal, the rectangles are considered similar, and the function returns true. Otherwise, the rectangles are not similar, and the function returns false.

Answer:

fav_number=26

guess=0

while 0==0:

   try:

       guess=int(input('Enter your guess: '))

   except:

       print ('You have entered an invalid value.')

   else:

       if guess == fav_number:

           break

       elif guess>fav_number:

            print ('Try a smaller number.')

       elif guess<fav_number:

           print ('Try a larger number')

Explanation:

define a variable fav_number and set it to number. write an infinite while loop to read input from user. In try block get input from user, if user enters invalid input code in except block will be executed. For valid input

Loop-tee-loop LOL

...

Not funneh...

Answer:

A) expert user

Explanation:

An expert user is an experienced user who has spent considerable time using specific application programs and, therefore, it is fair to assume that this user is likely to become comfortable and familiar with the terminal's operation.

A casual user is a less experienced computer user who will generally use a computer less frequently and thus is not likely to become comfortable and familiar with the terminal's operation.

System owners and system builders are not technically users.

Therefore, the answer is A) expert user

Answer:  Database Architect

Explanation:

Answer:

Answer:

'''

This is script makes use of dictionaries to get all the words in a file and the

number of times they occur.

'''

#section 1

import string

dic = {}

textFile=open("Text.txt","r")

# Iterate over each line in the file

for line in textFile.readlines():

   tex = line

   tex = tex.lower()

   tex=tex.translate(str.maketrans('', '', string.punctuation))#removes every punctuation  

#section 2

   new = tex.split()

   for word in new:

           if word not in dic.keys():

               dic[word] = 1

           else:

               dic[word] = dic[word] + 1

for word in sorted(dic):

   print(word, dic[word], '\n')

textFile.close()

Explanation:

The programming language used is python.

#section 1

The string module is imported because of the string operations that need o be performed. Also, an empty list is created to hold the words and the number of times that they occur and the file is opened in the read mode, because no new content is going to be added to the file.

A FOR loop is used to iterate through every line in the file and assigns each line to a variable one at a time, and each line is converted to lowercase and  punctuation is stripped off every word in each line.

This processing is needed in order for the program o accurately deliver the number of occurrences for each individual word in the text.

#section 2

Each line is converted to a list using the split function, this is done so that a FOR loop can iterate over each word. The FOR loop, iterates over each word in the list and the IF statement checks if the word is already in the dictionary, if the word id in the dictionary, it increases the number of occurrences, if it is not in the dictionary, it adds it to the dictionary and assigns the number 1 to it.

The words are then sorted just to make it look more organised and the words and the number of times that they occur is printed to the screen.

Here's a Python program that reads the contents of a text file, creates a dictionary with word frequencies, and then displays the frequency of each word:

```python

def count_word_frequency(file_path):

   word_frequency = {}

   # Open the file for reading

   with open(file_path, 'r') as file:

       # Iterate through each line in the file

       for line in file:

           # Split the line into words

           words = line.split()

           # Iterate through each word

           for word in words:

               # Remove any punctuation characters

               word = word.strip('.,!?;:"()[]{}')

               # Convert the word to lowercase

               word = word.lower()

               # Increment the count for this word in the dictionary

               word_frequency[word] = word_frequency.get(word, 0) + 1

   return word_frequency

def display_word_frequency(word_frequency):

   # Iterate through the dictionary and print each word and its frequency

   for word, frequency in word_frequency.items():

       print(f"{word}: {frequency}")

def main():

   file_path = input("Enter the path to the text file: ")

   word_frequency = count_word_frequency(file_path)

   display_word_frequency(word_frequency)

if __name__ == "__main__":

   main()

```

To use this program:

1. Save the code into a Python file (e.g., `word_frequency.py`).

2. Run the program.

3. Enter the path to the text file you want to analyze.

This program will read the text file, count the frequency of each word, and then display the frequency of each word in the console.

1. `count_word_frequency(file_path)` function:

  - This function takes a file path as input.

  - It initializes an empty dictionary called `word_frequency` to store word frequencies.

  - It opens the file specified by the file path in read mode using a `with` statement, ensuring that the file is properly closed after reading.

  - It iterates through each line in the file.

  - For each line, it splits the line into individual words using the `split()` method.

  - It then iterates through each word, strips any punctuation characters from the word, converts it to lowercase, and updates the count for that word in the `word_frequency` dictionary.

  - If the word is not already in the dictionary, it initializes its count to 1; otherwise, it increments its count by 1.

  - After processing all lines in the file, it returns the `word_frequency` dictionary containing the word frequencies.

2. `display_word_frequency(word_frequency)` function:

  - This function takes the `word_frequency` dictionary as input.

  - It iterates through the dictionary and prints each word along with its frequency.

3. `main()` function:

  - This function serves as the entry point of the program.

  - It prompts the user to enter the path to the text file they want to analyze.

  - It calls the `count_word_frequency()` function with the provided file path to calculate word frequencies.

  - It then calls the `display_word_frequency()` function to display the word frequencies to the user.

4. `if __name__ == "__main__":` block:

  - This block ensures that the `main()` function is only executed when the script is run directly, not when it's imported as a module in another script.

Overall, this program reads a text file, counts the frequency of each word, and displays the frequency of each word to the user.

Answer:

The correct option to the following question is option:

(C).

29. (A).

Explanation:

Cloud firms or companies are those that provides us the facilities to store our important data and kept it in safety, they also provides more facilities such as storage, networking, intelligence, database, etc.

Cloud computing are the facility in which we keep our data safe and confidential by saving our data in drives.

Operating System are software which manages the software as well as hardware also, that's why this option is correct

Answer:

Please see the explanation

Explanation:

ACM professional code has following characteristics:

Genaral moral Imperative- This further consists of:

Contribute to society and human well being

Avoid harm to others

Be honest and trustworthy

Honor property rights including copyrights and patent

Respect the privacy of other

2) Professional responsibilities

Acquire and maintain professional coompetence

Achieve the highest quality

Accept and provide appropriate professional review

Respect the existing laws

Access computing and communication resources only when authorized to do so.

3) Organizational leadership

Articulate social responsibilities of members of an organizational unit and encourage full acceptance of those responsibilities.

Manage personnel and resources to design and build information systems that enhance the quality of working life.

Ensure that users and those who will be affected by a system have their needs clearly articulated during the assessment and design of requirements; later the system must be validated to meet requirements.

Create opportunities for members of the organization to learn the principles and limitations of computer systems.

4) Compliance with Code

Uphold and promote the principles of this Code.

Treat violations of this code as inconsistent with membership in the ACM.

Software Engineering Code of Ethics and Professional Practice

In accordance with their commitment to the health, safety and welfare of the public, software engineers shall adhere to the following Eight Principles:

Public: Software engineers shall act consistently with the public interest.

Client and Employer: Software engineers shall act in a manner that is in the best interests of their client and employer, consistent with the public interest.

Product: Software engineers shall ensure that their products and related modifications meet the highest professional standards possible.

Judgement: Software engineers shall maintain integrity and independence in their professional judgment.

Management: Software engineering managers and leaders shall subscribe to and promote an ethical approach to the management of software development and maintenance.

Profession: Software engineers shall advance the integrity and reputation of the profession consistent with the public interest.

Colleagues: Software engineers shall be fair to and supportive of their colleagues.

Self: Software engineers shall participate in lifelong learning regarding the practice of their profession and shall promote an ethical approach to the practice of the profession.

Australian Code of Professional Conduct

As an ACS member you must uphold and advance the honour, dignity and effectiveness of being a professional. This entails, in addition to being a good citizen and acting within the law, your conformance to the following ACS values.

1. The Primacy of the Public Interest

You will place the interests of the public above those of personal, business or sectional interests.

2. The Enhancement of Quality of Life

You will strive to enhance the quality of life of those affected by your work.

3. Honesty

You will be honest in your representation of skills, knowledge, services and products.

4. Competence

You will work competently and diligently for your stakeholders.

5. Professional Development

You will enhance your own professional development, and that of your staff.

6. Professionalism

You will enhance the integrity of the ACS and the respect of its members for each other.

In a situation of conflict between the values, The Primacy of the Public Interest takes precedence over the other values.

This Code of Professional Conduct is aimed specifically at you as an individual practitioner, and

is intended as a guideline for your acceptable professional conduct. It is applicable to all ACS

members regardless of their role or specific area of expertise in the ICT industry

All the three codes focus on the public interest, honestl, loyalty, ensuring quality of life, and professional development.

In Australian Code of conduct, in a situation of conflict between the values, The Primacy of the Public

Interest takes precedence over the other values, while there is no such thing in other two codes.

Software Engineering Code of Ethics and Professional Practice includes development of self, that is, Software engineers shall participate in lifelong learning regarding the practice of their profession and shall promote an ethical approach to the practice of the profession, which is not usually seen in other two codes.

Answer:

Following are the program in c++ language

#include<iostream> // header file

using namespace std; // using namespace

void swapvalues(int&  userVal1, int& userVal2);// fucnction declaration

int main() // main method

{

   int x,y; // variable declaration

   cout<<"Enter the two value before swapping:\n";

   cin>>x>>y; // read the two input

  cout<<"before swapping:";

  cout<<x<<y; // display the value before swapping

   swapvalues(x, y);

   cout << "\nAfter swapping:";

   cout<<x<<y; // display the value after swapping

   return 0;

}

void swapvalues(int&  userVal1, int& userVal2) // function definition

{

   int t; // variable declaration

   t = userVal1; // assign the value userval1 to variable t

   userVal1 = userVal2; // assign the value userval2 to userval1

   userVal2 = t; // assign the value of variable t to userval2

}

Output:

Enter the two value before swapping:

3

8

before swapping:3 8

After swapping   :8 3

Explanation:

Following are the description of the program

Following are C++ programs on Swapping values:

#include <iostream>//header file

using namespace std;

void SwapValues(int& userVal1, int& userVal2)//defining the method SwapValues that takes two integer variable

{

   int t;//defining integer variable t

   //performing the swapping

   t=userVal1;//using t variable that holds userVal1 value

   userVal1=userVal2;//using userVal1 variable that holds userVal2 value

   userVal2=t;//holding the t value in userVal2

   cout<<"After swapping value: "<<userVal1<<" "<<userVal2;//printing the swapped value

}

int main()//defining the main method

{

   int x,y;//defining integer variable that inputs value

   cout<<"Input first number: ";//print message

   cin>>x;//input value

   cout<<"Input second number: ";//print message

   cin>>y;//input value

   cout<<"Before swapping value: "<<x<<" "<<y<<endl;//printing value

   SwapValues(x,y);//calling method SwapValues

   return 0;

}

Program Explanation:

Output:

Please find the attached file.

Find out more information about the swapping here:

brainly.com/question/19665043

Answer:

See the code snippet in the explanation section

Explanation:

import java.util.Scanner;

public class Question {

 public static void main(String[] args) {

   Scanner scan = new Scanner(System.in);

   System.out.println("Enter temperature in Fahrenheit: ");

   int inputTemperature = scan.nextInt();

   fahrenheitTemperatureToCelsius(inputTemperature);

 }

public static void fahrenheitTemperatureToCelsius(int fahrenheitTemperature){

   int celsiusTemperature = ((fahrenheitTemperature - 32)*5)/9;

   System.out.println("Temperature in Celsius = " + temperature);

}

}

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = [tex]\frac{1}{(1-f)+ \frac{f}{k} }[/tex]      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = [tex]\frac{1}{(1-f)+ \frac{f}{k} }[/tex]  

1.25 = [tex]\frac{1}{(1-0.6)+ \frac{0.6}{k} }[/tex]  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = [tex]\frac{1}{(1-f)+ \frac{f}{k} }[/tex]  

1.25 = [tex]\frac{1}{(1-0.4)+ \frac{0.4}{k} }[/tex]  

solve we get

k = 2

so here disk need 100% much faster

Final answer:

To achieve a 25% speedup in overall system performance, we use Amdahl's Law. The CPU must become 50% faster, while the disk must become 100% faster.

Explanation:

To achieve an overall system speedup of 25%, we can use the principle known as Amdahl's Law, which provides a way to calculate the improvement to overall system performance when only part of the system is improved. Given that processes spend 60% of their time on the CPU and 40% on I/O, we can define these as fractions of the total execution time (0.60 and 0.40 respectively).

To solve these related questions, we first need to turn the desired speedup into its equivalent 'slowness' fraction. If we want a speedup of 25%, the new execution time should be 1 / (1 + speedup), which is 1 / 1.25 or 0.80 of the original execution time. This is the target 'slowness' of the improved system.

For the CPU, which currently accounts for 60% of the execution time, its improved slowness should be S_CPU * 0.60 + 0.40 (unchanged I/O slowness) = 0.80. Solving for S_CPU, we get S_CPU = (0.80 - 0.40) / 0.60 = 2/3. Therefore, to achieve the overall improvement, the CPU needs to become 1/(2/3) = 1.5 times faster.

For the disk I/O, which accounts for 40% of the execution time, its improved slowness should be 0.60 (unchanged CPU slowness) + S_IO * 0.40 = 0.80. Solving for S_IO, we get S_IO = (0.80 - 0.60) / 0.40 = 1/2. Hence, to achieve the desired system speedup, the disk needs to be 1/(1/2) = 2 times faster.

In summary:

Answer:

nest an else clause within an elif clause

Explanation:

in python Programming, we cannot nest an else clause within an elif clause. elif is actually else if condition. we cannot nest another else with in elif clause.

Answer: SQL Injection

Explanation:

The SQL injection is one of the type of attack which is used in the database management system for sending the commands by adding the structured query (SQL) language statement in the form of input data.

Therefore, The SQL injection is the correct option.

Answer:

def gradeAverage():

   grades = []

   i = 0

   while i < 5:

       a = int(input('enter score ' + str(i + 1) + ': '))

       grades.append(a)

       i = i+1

   #print(grades)

   average = sum(grades)/len(grades)

   #print(average)

   return average

def lettergrade(a):

   letter = 'A'

   if a < 60:

       letter = 'F'

   elif 59 < a < 63:

       letter = 'D-'

   elif 62 < a < 67:

       letter = 'D'

   elif 66 < a < 70:

       letter = 'D+'

   elif 69 < a < 73:

       letter = 'C-'

   elif 72 < a < 77:

       letter = 'C'

   elif 76 < a < 80:

       letter = 'C+'

   elif 79 < a < 83:

       letter = 'B-'

   elif 82 < a < 87:

       letter = 'B'

   elif 86 < a < 90:

       letter = 'B+'

   elif 89 < a < 94:

       letter = 'A-'

   elif 93 < a < 101:

       letter = 'A'

   return letter

numOfStudents = int(input('How many students: '))

names = []

aver = []

grade =[]

while numOfStudents > 0:

   studentName = input('Enter students name: ')

   names.append(studentName)

   a = gradeAverage()

   aver.append(a)

   grade.append(lettergrade(a))

   numOfStudents = numOfStudents - 1

for name in names:

       for score in aver:

           for letter in grade:

               if names.index(name) == aver.index(score) == grade.index(letter):

                   print('%s : Average =  %d  Letter Grade:  %s \n' %(name, score, letter))

                   break

Explanation:

The programming language used is python.

Two functions were created, the first function gradeAverage() was used to calculate the average values of the scores.

The second function lettergrade(a) was used to get the letter grade i.e(A, A-, C, D, e.t.c.) and it takes its argument from the average.

The main block of code asks for how many students are there and prompts the user to input their names and scores for all the students.

It takes that data calculates the average and the letter grade and prints out the names of the students, their average and their letter grade.

Answer:

Assembly line.

Explanation:

The interchangeable parts was a game-changing concept for the manufacturing industry during the Industrial Revolution.

It was first introduced by Eli Whitney, also the inventor of the Cotton Gin, and later was perfected by Henry Ford, who was the first to create a continuous moving assembly line. The Interchangeable parts are identical pieces created from a master model and are so similar to each other, that they can fit into any line of production of the same kind.

Thanks to these advances, the manufacturing process across all industries could be now faster, more cost-efficient, and profitable.

Answer:

The code to this question can be given as:

Code:

//define code.

//conditional statements.

   if (Character.isLetter(passCode.charAt(0))) //if block

   {

       System.out.println("Alphabetic at 0"); //print message.

   }

   if (Character.isLetter(passCode.charAt(1))) //if block

   {

       System.out.println("Alphabetic at 1"); //print message.

   }

Explanation:

In this code, we define conditional statement and we use two if blocks. In both if blocks we use isLetter() function and charAt() function. The isLetter() function checks the inserted value is letter or not inside this function we use charAt() function that checks inserted value index 1 and 2 is the character or not.

The code segment is an illustration of conditional statements

Conditional statements are statements whose execution depends on the truth value of the condition.

The code segment in Java, where comments are used to explain each line is as follows:

//This checks if the first character is an alphabet.

if (Character.isLetter(passCode.charAt(0))){

   //If yes, this prints alphabetic at 0

   System.out.println("Alphabetic at 0");

}

//This checks if the second character is an alphabet.

if (Character.isLetter(passCode.charAt(1))){

   //If yes, this prints alphabetic at 1

   System.out.println("Alphabetic at 1");

}

Read more about similar programs at:

https://brainly.com/question/14391069