What is the daily cost of incandescent lamp

Answer: 41.2 atm

Explanation

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]

where,

[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.

[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.

We are given:

[tex]P_1=30.0atm\\T_1=20.3^0C=(20.3+273)=293.3K\\P_2=?\\T_2=130^0C=(130+273)K=403K[/tex]

Putting values in above equation, we get:

[tex]\frac{30.0}{293.3K}=\frac{P_2}{403}\\\\P_2=41.2atm[/tex]

The maximum pressure (in atm) that will be attained in the tank before the plug melts and releases gas is 41.2

The maximum pressure (in atm) that will be attained in the tank before the plug melts and releases gas is 41.22 atm

From the question given above, the following data were obtained:

Initial pressure (P₁) = 30 atm

Initial temperature (T₁) = 20.3 °C = 20.3 + 273 = 293.3 K

Final temperature (T₂) = 130 °C = 130 + 273 = 403 K

The final pressure can be obtained as illustrated below:

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\\\frac{30}{293.3} = \frac{P_{2}}{403}\\\\[/tex]

Cross multiply

293.3 × P₂ = 30 × 403

293.3 × P₂ = 12090

Divide both side by 293.3

[tex]P_{2} = \frac{12090}{293.3} \\\\[/tex]

Therefore, the maximum pressure (in atm) that will be attained in the tank before the plug melts and releases gas is 41.22 atm

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Answer:

Approximately [tex]0.47\; \rm mol \cdot L^{-1}[/tex] (note that [tex]1\; \rm M = 1 \; \rm mol \cdot L^{-1}[/tex].)

Explanation:

The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this [tex]\rm NaNO_3[/tex] solution in water,

Let [tex]n[/tex] be the number of moles of the solute in the whole solution. Let [tex]V[/tex] represent the volume of that solution. The formula for the molarity [tex]c[/tex] of that solution is:

[tex]\displaystyle c = \frac{n}{V}[/tex].

In this question, the volume of the solution is known to be [tex]1250\; \rm mL[/tex]. That's [tex]1.250\; \rm L[/tex] in standard units. What needs to be found is [tex]n[/tex], the number of moles of [tex]\rm NaNO_3[/tex] in that solution.

The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of [tex]\rm NaNO_3[/tex] is [tex]85\; \rm g \cdot mol^{-1}[/tex] means that the mass of one mole of

[tex]\displaystyle n = \frac{m}{M}[/tex].

For this question,

[tex]\begin{aligned}&n\left(\mathrm{NaNO_3}\right) \\ &= \frac{m\left(\mathrm{NaNO_3}\right)}{M\left(\mathrm{NaNO_3}\right)}\\&= \frac{50\; \rm g}{85\; \rm g \cdot mol^{-1}} \\& \approx 0.588235\; \rm mol\end{aligned}[/tex].

Calculate the molarity of this solution:

[tex]\begin{aligned}c &= \frac{n}{V} \\&= \frac{0.588235\; \rm mol}{1.250\; \rm L} \\&\approx 0.47\;\rm mol \cdot L^{-1}\end{aligned}[/tex].

Note that [tex]1\; \rm mol \cdot L^{-1}[/tex] (one mole per liter solution) is the same as [tex]1\; \rm M[/tex].

Answer:

.47

Explanation:

just did it on CK-12

Answer:

58.72 mL

Explanation:

The chemical equation for the neutralization reaction is :

H₂SO₄(aq) + Na₂CO₃(s)  --------------> Na₂SO₄(aq) + H₂O(l) + CO₂(g)

where;

M₁ = Molarity of H₂SO₄

M₂= Molarity of Na₂CO₃

V₁= Volume of H₂SO₄

V₂ = Volume of Na₂CO₃

Given that :

M₁ = 18.4 M

V₁= 0.3 mL

10% Na₂CO₃ means 100 g of solution contain 10 g of Na₂CO₃

i.e. 10 g Na₂CO₃ dissolved and diluted to 100 mL water.

Molar mass of Na₂CO₃ = 106 g/mol

106 g Na₂CO₃ dissolved in 100 mL will give 0.1 M Na₂CO₃ solution.

However;

If, 106 g Na₂CO₃ ≡ 0.1 M Na₂CO₃

Then, 10 g Na₂CO₃ ≡  'A' M  of Na₂CO₃

By cross multiplying; we have:

106 × A = 10 × 0.1

106 × A = 1

A = (1/106) M/100 mL

A = 10 x (1/106)) M/L

A = (10/106) M

A = 0.094  M

Therefore,the molarity of 10% Na₂CO₃ solution is 0.094 M.

For the Neutralization equation, we have:

M₁V₁ = M₂V₂

18.4×0.3 = 0.094×V₂

Making V₂  the subject of the formula;we have:

[tex]V_2 = \frac{18.4*0.3}{0.094}[/tex]

V₂ = 58.72 mL

Answer:

pH= 13.03

Explanation:

Since dissociation of Sr(OH)2= Sr2+ + 2[OH-]

[OH-]=2×0.0538 = 0.1076M

pOH= -log[0.1076]= 0.97

pH= 14-pOH = 14-0.97= 13.03

Answer:

The empirical formula is C3H6O

Explanation:

Step 1: Data given

Mass of the sample =2.088 grams

The mass contains carbon, hydrogen, and oxygen

Mass of CO2 produced = 4.746 grams

Mass of H2O produced = 1.943 grams

Molar mass of CO2 = 44.01 g/mol

Molar mass of H2O = 18.02 g/mol

Atomic mass of C = 12.01 g/mol

Atomic mass of H = 1.01 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 4.746 grams/ 44.01 g/mol

Moles CO2 = 0.1078 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.1078 moles CO2 we'll have 0.1078 moles C

Step 4: Calculate mass C

Mass C: moles C * atomic mass C

Mass C: 0.1078 moles * 12.01 g/mol

Mass C= 1.295 grams

Step 5: Calculate moles H2O

Moles H2O = 1.943 grams / 18.02 g/mol

Moles H2O = 0.1078 moles

Step 6: Calculate moles H

For 1 mol H2O we'll have 2 moles H

For 0.1023 moles H2O we'll have 2*0.1078 = 0.2156 moles H

Step 7: Calculate mass H

Mass H = 0.2046 moles * 1.01 g/mol

Mass H = 0.218 grams

Step 8: Calculate mass O

Mass O = 2.088 grams - 1.295 grams - 0.218 grams

Mass O = 0.575 grams

Step 9: Calculate moles O

Moles O = 0.575 grams / 16.0 g/mol

Moles O = 0.0359 moles

Step 10: Calculate the mol ratio

We divide by the smallest amount of moles

C: 0.1078 moles / 0.0359 moles = 3

H: 0.2156 moles / 0.0359 moles = 6

O: 0.0359 moles / 0.0359 moles =1

The empirical formula is C3H6O

The empirical formula of the compound is C₃H₆O

We'll begin by calculating the mass of C, H and O in the compound. This can be obtained as follow:

Mass of CO₂ = 4.746 g

Molar mass of CO₂ = 44 g/mol

Molar mass of C = 12 g/mol

Mass of C = 12/44 × 4.746

Mass of H₂O = 1.943 g

Molar mass of H₂O  = 18 g/mol

Molar mass of H₂ = 1 × 2 = 2 g/mol

Mass of H = 2/18 × 1.943

Mass of C = 1.294 g

Mass of H = 0.216 g

Mass of compound = 2.088 g

Mass of O = (Mass of compound ) – (mass of C + mass of H)

Mass of O = 2.088 – (1.294 + 0.216)

C = 1.294 g

H = 0.216 g

O = 0.578 g

Divide by their molar mass

C = 1.294 / 12 = 0.108

H = 0.216 / 1 = 0.216

O = 0.578 / 16 = 0.036

Divide by the smallest

C = 0.108 / 0.036 = 3

H = 0.216 / 0.036 = 6

O = 0.036 / 0.036 = 1

Therefore, the empirical formula of the compound is C₃H₆O

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Answer:

28.58 g of NaOH

Explanation:

The question is incomplete. The missing part is:

"Calculate the mass of sodium hydroxide that the chemist must weigh out in the second step"

To do this, we need to know how much of the base we have to weight to prepare this solution.

First we know that is a sodium hydroxide aqueous solution so, this will dissociate in the ions:

NaOH -------> Na⁺ + OH⁻

As NaOH is a strong base, it will dissociate completely in solution, so, starting with the pH we need to calculate the concentration of OH⁻.

This can be done with the following expression:

14 = pH + pOH

and pOH = -log[OH⁻]

So all we have to do is solve for pOH and then, [OH⁻]. To get the pOH:

pOH = 14 - 13.9 = 0.10

[OH⁻] = 10⁽⁻⁰°¹⁰⁾

[OH⁻] = 0.794 M

Now that we have the concentration, let's calculate the moles that needs to be in the 900 mL:

n = M * V

n = 0.794 * 0.9

n = 0.7146 moles

Finally, to get the mass that need to be weighted, we need to molecular mass of NaOH which is 39.997 g/mol so the mass:

m = 39.997 * 0.7146

Answer:

a) Pamela's shortbread cookies has 117,471.3 calories = 117.5 kcal

Elaine's popcorn has 166,515.3 calories = 166.5 kcal

b) Pamela had the smaller net gain of calories after snacking and walking.

Explanation:

- Pamela's snack was a small bag of shortbread cookies composed of 2.6 grams fat, 21 grams carbohydrates, and 2.1 grams protein.

- Elaine had a bag of popcorn composed of 2.9 grams fat, 31 grams carbohydrates, and 3.5 grams protein.

Nutrient | Fuel value (kJ/g):

Carbohydrate | 17

Fat | 38

Protein | 17

Noting that instead of Carbs, Protein was intended to be written.

a) For Pamela

Carbohydrates = (21 g) × (17 KJ/g) = 357 KJ

Fats = (2.6 g) × (38 KJ/g) = 98.8 KJ

Protein = (2.1 g) × (17 KJ/g) = 35.7 KJ

Total fuel value = 357 + 98.8 + 35.7 = 491.5 KJ = 491,500 J

Note that 1 cal = 4.184 J

491,500 J = (491,500/4.184) = 117,471.3 calories = 117.5 kcal

Carbohydrates = (31 g) × (17 KJ/g) = 527 KJ

Fats = (2.9 g) × (38 KJ/g) = 110.2 KJ

Protein = (3.5 g) × (17 KJ/g) = 59.5 KJ

Total fuel value = 527 + 110.2 + 59.5 = 696.7 KJ

Note that 1 cal = 4.184 J

696,700 J = (696,700/4.184) = 166,515.3 calories = 166.5 kcal

b) Suppose the friends took a 15-minute walk after snacking. If Pamela burned 43 kcal and Elaine expended 48 kcal, who had the smaller net gain of calories after snacking and walking?

Pamela gains 117.5 kcal

And loses 43 kcal

Net gain = 117.5 - 43 = 74.5 kcal

Elaine gains 166.5 kcal

And loses 48 kcal

Net gain = 166.5 - 48 = 118.5 kcal

Pamela had the smaller net gain of calories after snacking and walking.

Hope this Helps!!!

Answer:

A) That resistance in bacteria is produced due to inactivation of ampicillin by the beta lactamase enzyme. This enzyme is expressed by the bla gene found in the plasmid. This enzyme is secreted into the culture medium, thereby inactivating ampicillin. Thanks to this inactivation, the bacteria colonies will be able to develop. After a day of incubation, only those bacteria that took the plasmid that gives them resistance to ampicillin will grow after transformation. After prolonged incubation, two types of colonies can be observed in the culture medium. One large colony with ampicillin resistance, and another small colony, both of which are sensitive to ampicillin.

B) Large colonies are characterized by being resistant to ampicillin. When Ramón isolates the plasmid, he will have the gene that provides resistance to antibiotics. Said plasmid can be used again on those bacteria that are sensitive to ampicillin.

On the other hand, satellite colonies are sensitive to ampicillin. These types of colonies do not have the plasmid that contains the gene that gives ampicillin resistance. It is not possible to isolate any plasmids from these satellite colonies. These satellite bacteria will not be able to grow if they are transferred to a plate containing fresh ampicillin, while large colonies, which possess the plasmid that gives them resistance to ampicillin, will be able to grow on that plate.

Explanation:

Answer:

8.969×10²⁶ photons

Explanation:

From the question,

Using,

E = hc/λ........................... Equation 1

Where E = Energy of the photon, h = Planck's constant, c = speed of light, λ = wave length of the photon.

Given: h =  6.626×10⁻³⁴ J.s, c = 3×10⁸ m/s, λ = 0.297 m

Substitute into equation 1

E = 6.626×10⁻³⁴(3×10⁸)/0.297

E = 6.69×10⁻²⁵ J.

The energy of the photon in one seconds = 6.69×10⁻²⁵ J/s

If the power of the microwave oven  = 600 J/s

Then,

Number of photons emitted per seconds = 600/(6.69×10⁻²⁵)

Number of photons emitted per seconds = 8.969×10²⁶ photons

Answer:

See attachment for mechanism.

Explanation:

The Fischer esterification reaction is a nucleophilic substitution in the acyl group of a carboxylic acid, catalyzed by an acid.

1) The protonation of the oxygen of the carbonyl group activates the carboxylic acid...

2) ... against a nucleophilic attack by the alcohol, and produces a tetrahedral intermediate.

3) The transference of a proton from an oxygen atom to another produces a second tetrahedral intermediate and converts the -OH into a good leaving group.

4) The loss of a proton and the expulsion of H₂O regenerates the acid catalyzer and gives an ester as a product.

The Fischer esterification reaction involves reacting a carboxylic acid with an alcohol to form an ester. The reaction is driven to completion by using an excess of alcohol or by distilling off the product.

In the

Fischer esterification reaction

, an alcohol (for example, ethanol) reacts with a carboxylic acid (like acetic acid) to form an ester. The carbonyl carbon of the acid is protonated to make it a better electrophile that can react with the alcohol's oxygen. Here's a simplified version of what happens:

R-C-0-H (a carboxylic acid) + :O: (the oxygen of an alcohol) -> R-C(=O)-O-R' (an ester)

, where R and R' represent any organic groups. The reaction is balanced by distilling off the ester product or using an excess of the alcohol solvent. In a more detailed mechanism, curved arrows would be used to show the movement of electrons, but those can't be represented in text form.

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Answer:

Explanation:

the question has been solve below

The balanced overall reaction is Mn(s) + Pb²⁺ (aq) → Mn²⁺ (aq) + Pb(s) with a standard cell potential of 1.050 V, making option a) the correct choice.

To answer this, let's first identify the standard cell potential (E°) for the given half-reactions:

Mn²⁺ (aq) + 2 e⁻ → Mn(s); E° = –1.180 V

Pb²⁺ (aq) + 2 e⁻ → Pb(s); E° = –0.130 V

In an electrochemical cell, the half-reaction with the more positive reduction potential acts as the cathode (reduction), and the one with the less positive potential acts as the anode (oxidation). Here, E° for Pb²⁺/Pb is more positive (-0.130 V) than E° for Mn²⁺/Mn (-1.180 V).

Therefore, the cell setup will be:
Manganese will be oxidized: Mn(s) → Mn²⁺ (aq) + 2 e⁻ (oxidation at the anode)
Lead will be reduced: Pb²⁺ (aq) + 2 e⁻ → Pb(s) (reduction at the cathode)

The balanced overall reaction:

Mn(s) + Pb²⁺ (aq) → Mn²⁺ (aq) + Pb(s)

Calculating the Cell Potential:

The standard cell potential (E°cell) is calculated as follows:

E°cell = E°cathode - E°anode
E°cell = (-0.130 V) - (-1.180 V) = 1.050 V

So, the correct answer is:

a) Pb²⁺(aq) + Mn(s) → Pb(s) + Mn²⁺(aq); E° = 1.050 V

Complete question:

Which of the following is the balanced overall reaction and standard cell potential of an electrochemical cell constructed from half-cells with the given half reactions? Mn 2+(aq) + 2 e−→Mn(s); E° = –1.180 V Pb2+(aq) + 2 e−→ Pb(s); E° = –0.130 V Group of answer choices

a) Pb 2+(aq) + Mn(s) →Pb(s) + Mn2+(aq); = 1.050 V

b) Pb(s) + Mn2+(aq) →Pb2+(aq) + Mn(s); = −1.050 V

c) Pb 2+(aq) + Mn2+(aq) →Pb(s) + Mn(s); = –1.310 V

d) Pb 2+(aq) + Mn(s) →Pb(s) + Mn2+(aq); =0.525 V

e) Pb(s) + Mn2+(aq) →Pb2+(aq) + Mn(s); = −0.525 V

Answer:

Ni^2+ is most likely

Ti^3+ is very unlikely

Explanation:

The Crystal Field Stabilization Energy almost always favors octahedral over tetrahedral in very many cases, but the degree of this favorability varies with the electronic configuration. In other words, for d1 there is only a small gap between the octahedral and tetrahedral lines, whereas at d3 and d8 is a very big gap. However, for d0, d5 high spin and d10, there is no crystal field stabilization energy difference between octahedral and tetrahedral. The ordering of favorability of octahedral over tetrahedral is:

d3, d8 > d4, d9> d2, d7 > d1, d6 > d0, d5, d10. This explains the answer choices above.

Ti^3+ being a d1 specie is least likely to exist in octahedral shape while Ni2+ a d8 specie is more likely to exist in octahedral shape.

Answer:

-- 5.8×10⁻⁹ of the H is in 2P states at T=5900 K, a typical Sun surface temperature.

-- 3.3×10⁻¹² of the H is in 2P states at T=4300 K, a typical Sunspot temperature.

Explanation:

Answer:

Explanation:

your question seems to be  uncompleted , but however i have a solution to a similar question, check the attachment and follow the format to evaluate your question.

check the attachement

Answer:

T= 257.36 k

Explanation:

using the ideal gas law

pv=nRt

first, convert pressure from mmhg to kpa

312 x (101.3\760)= 41.58 kpa

R is constant= 8.31

to get n(number of moles)

n=m\M          (m is mass, M is molar mass)

molar mass of argon is 39.948

n= 2.33\39.948

n=0.0583

substitute;

41.58 x 3 = 0.0583 x 8.31 x T

T= (41.58 x 3)\ (0.0583 x 8.31)

T= 257.36 k

The temperature of the gas under ideal conditions is 257.36K

In order to get the temperature of the gas, we will use the ideal gas equation expressed according to the formula:

[tex]PV = nRT[/tex]

P is the pressure of the gas = 312mmHg = 41.58KPa

V is the volume of the gas = 3.00L

n is the moles of the gas =  0.1165moles

R is boltzmann constant = 8.31

T is the required temperature

Mole = mass/molar mass

Mole = 2.33/40

Mole of argon = 0.05825moles

Substitute the given parameters into the formula

[tex]T=\frac{PV}{nR}\\ T=\frac{41.58 \times 3}{0.05825\times8.31}\\T=257.36K[/tex]

Hence the temperature of the gas under ideal conditions is 257.36K

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Answer:

21,976 J

Explanation:

In order to increase the temperature of a certain amount of a substance by [tex]\Delta T[/tex], the amount of heat that must be supplied to the substance must be:

[tex]Q=mC\Delta T[/tex]

where

m is the mass of the substance

C is the specific heat capacity of the substance

[tex]\Delta T[/tex] is the increase in temperature

For the sample of water in this problem we have:

[tex]m=150.0 g[/tex] is the mass

[tex]C=4.186 J/g^{\circ}C[/tex] is the specific heat capacity of water

[tex]\Delta T=60.0-25.0=35.0^{\circ}C[/tex] is the increase in temperature

Therefore, the amount of heat that must be supplied is

[tex]Q=(150.0)(4.186)(60-0-25.0)=21,976 J[/tex]

To heat 150.0 g of water from 25.0°C to 60.0°C, approximately 21885 joules of heat must be absorbed, calculated using the formula q = mcΔT with the values m = 150.0 g, c = 4.18 J/gK, and ΔT = 35.0°C.

The amount of heat required to raise the temperature of 150.0 g of water from 25.0°C to 60.0°C can be calculated using the formula q = mcΔT, where q is the heat absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Using the given values, the mass m = 150.0 g, specific heat capacity c = 4.18 J/gK, and the temperature change ΔT = (60.0 - 25.0)°C = 35.0°C, we get:

q = (150.0 g)(4.18 J/gK)(35.0 K)

q = 150.0 g * 4.18 J/g°C * 35.0°C

q = 21885 J

Therefore, the water must absorb approximately 21885 joules of heat for the temperature to increase from 25.0°C to 60.0°C.

Answer:

Explanation:

Check below for the answer in the attachment.

Find figure in the attachment

Answer:

Explanation:

solution to the question is found below

d. HF is an acid and  [tex]F^-[/tex] is its conjugate base.

What is acid/ base and its conjugate acid/base?

Given chemical reaction:

[tex]HF(aq) + HPO_4^{2-}(aq)----> F^-(aq) + H_2PO_4^-(aq)[/tex]

In this reaction, HF is an acid and its conjugate base is [tex]F^-[/tex].

Thus out of all the options; the correct option is d.

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In the reaction HF(aq) + HPO4^2-(aq) = F^-(aq) + H2PO4^-(aq), HF is the acid and F^- is the conjugate base, making the correct answer (d).

In the given reaction HF(aq) + HPO42-(aq) = F-(aq) + H2PO4-(aq), we need to identify the correct acid-base pairs. When looking at this reaction, HF donates a proton (H+) to form its conjugate base F-, which makes HF the acid. On the other hand, since HPO42- receives a proton (H+) to become H2PO4-, HPO42- clearly acts as the base in this reaction and H2PO4- is its conjugate acid, which shows that it is amphoteric.

Based on this explanation, the correct answer is (d) HF is an acid and F- is its conjugate base.

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Answer:

S = 0.00014 moles /L = 1.4 * 10^-4 moles/L

Explanation:

Step 1: Data given

Temperature = 25.0 °C

Ksp = 1.1 * 10^-11

Step 2: The balanced equation

Mg(OH)2(s) ⇆ Mg^2+(aq) + 2OH-(aq)

Step 3: Define Ksp

[Mg(OH)2 = 1.11 * 10^-11 = S

[Mg^2+] = S

[OH-] = 2S

Ksp = [Mg^2+]*[OH-]²

Ksp = S * (2S)²

1.1 * 10^-11 = 4S³

S³ = 2.75 * 10^-12

S = 0.00014 moles /L

Answer:

group

Explanation:

elements in the same group have the same number of valence electrons

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Therefore, the correct option is option C.

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

Periodic table help a scientist to know what are the different types of elements are present in periodic table so that they can discover the new elements that are not being discovered yet.

Within each group in the periodic table, elements have similar properties because they have the same number of valence electrons.

Therefore, within each group in the periodic table, elements have similar properties because they have the same number of valence electrons. The correct option is option C.

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Answer: the effects of cholera toxin on cAMP in the intestinal cells is that it INCREASES cAMP production.

Explanation:

Vibrio cholerae is a gram negative bacterium which produces a protein cholera toxin that is responsible for the characteristic symptoms of cholera such as

watery diarrhea, vomiting, rapid heart rate, loss of skin elasticity, low blood pressure, thirst, and muscle cramps. There is need for body fluids and Na replacement to avoid severe dehydration results which may lead to death.

Cyclic adenosine monophosphate( cAMP) is a derivative used for intracellular signal transduction in organisms. The cholera toxin produced by the bacteria INCREASES the production of cAMP through its polypeptides( which consist of active protomer and binding protomer). The cholera toxin first binds to cell surface receptors, the protomer then enters the cell and bind with and activate the adenylate cyclase. Increasing adenylate cyclase activity will INCREASE cellular levels of cAMP, increasing the activity of ion pumps that remove ions from the cell. Due to osmotic pressure changes, water also must flow with the ions into the lumen of the intestinal mucosa, dehydrating the tissue. I hope this helps, thanks.

Answer:

Ice and water on the ground affect incoming solar radiation by reflecting 4 percent of solar radiation that reaches the surface.

Explanation:

Answer:

ice and water on the ground affect incoming solar radiation by reflecting 4 percent of solar radiation that reaches the surface. the state of water and the sun angle are vital in determining the amount of reflection that take place. at low sun angle and at times when the surface is ice, more reflection occurs.

Explanation:

None

Answer:

Ethylene diamine will bond to the Central metal via a lone pairs of electrons on nitrogen

Explanation:

Complexes are formed by coordinate bond formation. Before a coordinate bond is formed, one of the species must have a lone lair of electrons available for donation into empty orbitals on the central metal.

Ethylene diammine contains nitrogen which has a lone pair of electrons. The two lone pairs on the two nitrogen atoms can bond with the central metal. This makes ethylene diammine a bidentate ligand (two bonding atoms).

Ethylenediamine will bond to a metal ion through both of its nitrogen atoms, forming a chelate complex.

Answer:

Explanation:

Using Dalton's law of partial pressure

P total pressure = Pressure of helium + Pressure of neon + Vapor pressure of water

P = 28.3 mmHg, Pressure of helium = 381 mmHg, Vapor pressure of water at 28°C

791 mmHg - 381 mmHg - 28.3 mmHg = Pressure of neon

Pressure of neon = 381.7 mmHg

Answer:

28.6 mL

Explanation:

Step 1: Write the balanced neutralization reaction between acetic acid and sodium hydroxide

CH₃COOH(aq) + NaOH(aq) = CH₃COONa(aq) + H₂O(l)

Step 2: Calculate the moles of acetic acid

The molar mass of acetic acid is 60.05 g/mol. The moles corresponding to 0.120 g are:

[tex]0.120g \times \frac{1 mol}{60.05g} =2.00 \times 10^{-3} mol[/tex]

Step 3: Calculate the moles of sodium hydroxide

The molar ratio of CH₃COOH to NaOH is 1:1. The reacting moles of NaOH are 2.00 × 10⁻³ mol.

Step 4: Calculate the volume of the 0.0700 M NaOH solution

[tex]2.00 \times 10^{-3} mol \times \frac{1L}{0.0700mol} =0.0286 L = 28.6 mL[/tex]

Answer:

We have to add 286 mL of NaOH

Explanation:

Step 1: Data given

Mass of acetic acid (CH3COOH)= 0.120 grams  

Volume of acetic acid = 250 mL = 0.250 L

Molarity of NaOH = 0.0700 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles acetic acid

Moles acetic acid = mass / molar mass

Moles acetic acid = 0.120 grams / 60.05 g/mol

Moles acetic acid = 0.00200 moles

Step 4: Calculate molarity acetic acid

Molarity acetic acid = moles / volume

Molarity acetic acid = 0.00200 moles /0.250 L

Molarity acetic acid = 0.008 M

Step 5: Calculate the volume of solution the student will need to add to reach the equivalence point

C1*V1 = C2*V2

⇒with C1 = the molarity of acetic acid = 0.008 M

⇒with V1 = the volume of acetic acid = 0.250 L

⇒with C2 = the molarity of NaOH = 0.0700 M

⇒with V2 = the volume of NaOH neede = TO BE DETERMINED

0.008 M * 0.250 L = 0.0700 M * V2

V2 = (0.008M * 0.250 L) / 0.0700 M

V2 = 0.286 L = 286 mL

We have to add 286 mL of NaOH

Answer:

All of the choices.

Explanation:

As the reaction is involving with a mixture of H₂O and CH₃OH, these two reagents can work as nucleophyle of the reaction. Both of them, are polar and promoves a Sn1/E1 reaction. When it reacts with water it will produce product B); it will form product C) when it reacts with methanol, and product A) will be formed when the reaction undergoes an E1 reaction.

In this case, the only way to show you this, it's doing the mechanism of reaction for each product. Picture attached show the mechanism for the formation of all these products.

Treating (CH3)3C-Cl with H2O and CH3OH usually results in the formation of tert-butyl alcohol, (CH3)3COH, through a nucleophilic substitution reaction, making option B the correct answer.

Treating (CH3)3C-Cl with a mixture of H2O and CH3OH at room temperature typically involves a nucleophilic substitution reaction where the chloride ion (Cl-) is replaced by the nucleophile. In this case, the nucleophiles are water (H2O) and methanol (CH3OH). The product of this reaction would be (CH3)3COH, also known as tert-butyl alcohol, as both water and methanol could act as nucleophiles to perform the substitution, but water is generally a better nucleophile than methanol. Hence, option B is the correct answer.

Answer: Number of balloons that can be filled with He are 1397.

Explanation:

The given data is as follows.

      V = 25 L He ,          P = 131 atm

      T = [tex]19^{o}C[/tex] = (19 + 273) K

          = 292 K

According to ideal gas equation,

            PV = nRT

where,     n = [tex]\frac{PV}{RT}[/tex]

                   = [tex]\frac{131 \times 25}{0.082 \times 292}[/tex]

                   = 136.76 mol of He

The data for small balloons is given as follows.

        T = [tex]27^{o}C[/tex] = (27 + 273) K

                   = 300 K

        P = 732 = 0.963 atm

        V = 2.50 L

Now, we will calculate the number of moles as follows.

       n = [tex]\frac{PV}{RT}[/tex]

          = [tex]\frac{0.963 \times 2.50}{0.082 \times 300}[/tex]

         = 0.098 mol

So, number of balloons that can be filled with He are calculated as follows.

         n = [tex]\frac{N_{1}}{N_{2}}[/tex]

            = [tex]\frac{136.76}{0.098}[/tex]

            = 1397.60 balloons

or,        = 1397 balloons (approx)

Thus, we can conclude that number of balloons that can be filled with He are 1397.

Final answer:

The E2 reaction is a type of elimination mechanism where a base removes a proton from a carbon adjacent to one with a leaving group, leading to the creation of a double bond. It requires the bonds to be anti-aligned and uses a bulky base to favor the formation of more highly substituted alkenes, with no intermediates formed.

Explanation:

The E2 elimination reaction is a concerted process where a base removes a proton (H) adjacent to a carbon with a leaving group (often denoted as 'X'), resulting in the formation of a double bond. The key characteristics of the E2 mechanism include the requirement for the C-H and C-X bonds to be in an anti-periplanar arrangement, ensuring they are aligned properly for the elimination to occur. Additionally, the use of a bulky base typically leads to the formation of the more highly substituted alkene product, favoring the more stable Zaitsev product. There is also no carbocation intermediate in the E2 mechanism; instead, the reaction proceeds through a single concerted step without intermediates. The E2 mechanism is typically observed with secondary and tertiary substrates where steric hindrance inhibits SN2 reactions.

Answer:

27.60 g urea

Explanation:

The freezing-point depression is expressed by the formula:

In this case,

m is the molality of the urea solution in X (mol urea/kg of X)

First we calculate the molality:

Now we calculate the moles of urea that were dissolved:

550 g X ⇒ 550 / 1000 = 0.550 kg X

Finally we calculate the mass of urea, using its molecular weight:

Answer:

5:22 am

Explanation:

The gas X decays following a first-order reaction.

The half-life ([tex]t_{1/2}[/tex]) is 25 min. We can find the rate constant (k) using the following expression.

[tex]k = \frac{ln2}{t_{1/2}} =\frac{ln2}{25min} = 0.028 min^{-1}[/tex]

We can find the concentration of X at a certain time ([tex][X][/tex]) using the following expression.

[tex][X] = [X]_0 \times e^{-k \times t}[/tex]

where,

[tex][X]_0[/tex]: initial concentration of X

t: time elapsed

[tex]\frac{[X]}{[X]_0}= e^{-k \times t}\\\frac{1/10[X]_0}{[X]_0}= e^{-0.028min^{-1} \times t}\\t=82min[/tex]

The earliest time Professor Utonium can come back to do experiments in the lab is:

4:00 + 82 = 5:22 am

Final answer:

The earliest Professor Utonium can return to the lab after a radioactive release is approximately 5:15 am, based on the half-life of 25 minutes and the requirement for the concentration of the gas to drop by a factor of 10, corresponding to just over 3 half-lives.

Explanation:

The question asks for the earliest time Professor Utonium can return to the lab after a release of a radioactive gas, X, which has a half-life of 25 minutes, and the lab is considered safe when its concentration drops by a factor of 10. Understanding that the decay of the radioactive element follows first-order kinetics, we can calculate the time required for the concentration to drop by this factor.

First-order decay implies that the time it takes for a substance to decay to half its initial amount is constant, known as the half-life. To reduce the concentration of a substance by a factor of 10, we need to go through a certain number of half-lives. The formula for calculating the amount of substance remaining after a given time is N = N0,[tex](1/2)^{(t/t1/2)}[/tex] where N is the remaining amount, N0 is the initial amount, t is time, and t1/2 is the half-life.

To reduce the concentration by a factor of 10, we effectively need the substance to go through just over 3 half-lives (since (1/2)³ = 1/8, which is just a bit more than one-tenth). Therefore, the calculation is 3 * 25 = 75 minutes after the initial release. Since the accident happened at around 4:00 am, adding 75 minutes means the earliest Professor Utonium can return to the lab is approximately 5:15 am.