What is the de broglie wavelength of a 0.17-kg hockey puck moving at 37 m/s ?

Answers

Answer 1
Im taking lambda as x (wavelength)

m = 0.17 kg

v=37m/s

h=6.62*10^-34m²kg/s

x= h/mv


[tex]x = 6.62 \times 10 ^{ - 34} \div 0.17 \times 37[/tex]
[tex]x =1.05 \times {10}^{ - 34} m[/tex]
Answer 2

The wavelength of a hockey of mass 0.17kg traveling at a speed of37 m/s can be calculated by using De Broglie's equation and it comes out to be  1.05m×10⁻³⁴m.

What is De Broglie's equation?

The De Broglie's equation is an equation which shows that a particle has a wave length and hence particle can show wave nature. Any matter can have two nature one is particle nature and other is wave nature.

The wave nature in a particle was given by De Broglie Particle nature of a matter can be described by the phenomenon of black body radiation. Photoelectric effect two shows particle nature nature of light.

Mathematically,

[tex]{\lambda}=\frac{h}{mv}[/tex]

where,

[tex]{\lambda}[/tex]=wavelength=?

m=mass of hockey=0.17kg

h=Plank's constant

v=velocity of hockey=37 m/s

Substituting all given values in the equation

[tex]\lambda[/tex]= (6.626×10⁻³⁴)÷(0.17kg ×37 m/s )=1.05m×10⁻³⁴m

Thus the wavelength of motorcycle is 1.05m×10⁻³⁴m.

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Related Questions

Why are ionic compounds brittle

Answers

Ionic compounds are brittle because due to the strong bond between the positive and negative ions that formed the molecules. These positive and negative bonds produce crystals in rigid, lattice structures.

What are ionic compound ?

The term ionic compound is defined as the compounds made up of ions that produce charged particles when an atom or group of atoms gains or loses electrons.

Because of their electrostatic attractions, ionic compounds are brittle. These forces keep anions and cations in specific positions in a crystal lattice. Metals, on the other hand, are malleable because the atoms can roll over and create new positions, thereby maintaining their bonds.

Thus, ionic compounds are brittle.

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Calculate the mass of Octane needed to release 6.20 mol Co2

Answers

Final answer:

To find the mass of octane required to produce 6.20 mol CO2, we use the stoichiometry of the combustion reaction and the molar mass of octane, resulting in a requirement of 88.56 grams of octane.

Explanation:

To calculate the mass of octane (C8H18) needed to produce 6.20 mol CO2, we first need the balanced chemical equation for the combustion of octane:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

This equation tells us that 2 moles of octane produce 16 moles of CO2. From this, we can find the molar ratio between octane and CO2, which is 2 moles of octane per 16 moles of CO2, or 1 mole of octane for every 8 moles of CO2.

Next, we use the molar mass of octane, which is 114.23 g/mol (C=12.01 g/mol x 8 + H=1.008 g/mol x 18). Given that we have 6.20 moles of CO2, we can calculate the moles of octane needed:

6.20 mol CO2 x (1 mol C8H18 / 8 mol CO2) = 0.775 mol C8H18

Finally, we convert moles of octane to mass:

0.775 mol C8H18 x 114.23 g/mol = 88.56 g C8H18

Therefore, 88.56 grams of octane are needed to produce 6.20 moles of CO2.

Ethyl acetate is a sweet-smelling solvent used in varnishes and fingernail polish remover. it is produced industrially by heating acetic acid and ethanol together in the presence of sulfuric acid, which is added to speed up the reaction. the ethyl acetate is distilled off as it is formed. the equation for the process is as follows.

Answers

Final answer:

Ethyl acetate is a solvent used in varnishes and nail polish remover, and it is produced by heating acetic acid and ethanol in the presence of sulfuric acid. It is also used to extract caffeine from coffee and to remove nail polish and paint.

Explanation:

Ethyl acetate is a sweet-smelling solvent used in varnishes and fingernail polish remover. It is produced industrially by heating acetic acid and ethanol together in the presence of sulfuric acid, which is added to speed up the reaction. The ethyl acetate is distilled off as it is formed.

Ethyl acetate (CH, CO₂C₂H5) is the solvent in many fingernail polish removers and is used to decaffeinate coffee beans and tea leaves. It is prepared by reacting ethanol (C₂H5OH) with acetic acid (CH₂CO₂H); the other product is water. A small amount of sulfuric acid is used to accelerate the reaction, but the sulfuric acid is not consumed and does not appear in the balanced chemical equation.

Esters are common solvents. Ethyl acetate is used to extract organic solutes from aqueous solutions-for example, to remove caffeine from coffee. It also is used to remove nail polish and paint.

Which statement is true regarding methane and ammonia?

Answers

The options for given question are as follow,

1) Methane molecules show hydrogen bonding. 
2) Ammonia molecules show hydrogen bonding. 
3) Methane has stronger hydrogen bonding than ammonia. 
4) Both the compounds do not show hydrogen bonding. 
5) Both the compounds have strong hydrogen bonding.

Answer:
            Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).

Explanation:
                   Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
The answer is B. Trust me!!!

Ionic bonds are stronger, and one atom gives an electron to the other atom.

True
False

Answers

True, ionic bonds are known to be the type of bond where one atom gives it's electron(s) to the other atom causing the one that gave the electron to become positively charged and the one to receive the atom negatively charged.

What are some of the solutes in low-fat chocolate milk?

Answers

water, proteins, fats, lactose and minerals and vitamins.

Answer:

 

Explanation:

The lowfat chocolate milk is a milk which can be prepared by using milk of low fat or skimmed milk, in which chocolate syrup and sugar syrup can be added additionally.

The main solutes in low-fat milk will be chocolate syrup that contains cocoa powder, some fat, calcium and vitamin D.  

This composition will be tasty and people of age groups can drink this. It is good for providing instant energy to athletes after work out.  

Which of the following gases will have the highest velocity at a given temperature? (3 points)
A .Ne
B. O2
C .He
D. Cl2

Answers

The correct option is C.
Helium gas will have the highest velocity at a given temperature because it has the lowest atomic mass of all the gases given. The atomic mass of gases affect their rate of movement. The lower the atomic mass, the faster the gas molecules moves and the higher the atomic mass, the slower the gas molecules move. 

Answer:

Option-(C)-  

Helium, He is the most lightest among the given four elements. As the molecular mass of helium,He is about  4.002602 u. It is considered the second most lightest element inside the periodic table after the hydrogen,H atom which is the lightest of all.

Explanation:

Velocity dependence upon the molecular weight of the element:

The molecular weight of the different elements gives them the very specific features including the ability to travel fast in a given space. While the helium,He is considered one of the lightest elements in the universe so, it has a greater velocity among the four options.

For example:

A person with less weight will run much faster as compared to a person having more weight.

The half-life of a particular element is 280 days. what is its decay constant?

Answers

The formula for decay is
                                      N' = Ne^(-kt)
with N as the initial amount, k as the decay constant, and N' as the final amount. For decay, 280 days is the time it takes for the initial amount N to decay to 1/2N (half its original mass).
                                 1/2A = Ae^(-280k)
                                 1/2    =   e^(-280k)
Solving for k, we will yield
                                 ln(1/2) = -280k
                                          k = ln(2) / 280 day^-1
                                          k ≈ 2.5 × 10^-3 day^-1

a weather balloon contains 8.80 moles of helium at a ppressure of 0.992 atm and a temperature os 25 C at ground level. What is the volume of the balloon under these conditions?

Answers

we can use the ideal gas law equation to find the volume of the balloon.
PV = nRT 
where 
P - pressure - 0.992 atm x 101 325 Pa/atm = 100 514 Pa
V - volume 
n - number of moles - 8.80 mol 
R - universal gas constant  - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 25 °C + 273 = 298 K
Substituting these values in the equation 
100 514 Pa x V = 8.80 mol x  8.314 Jmol⁻¹K⁻¹ x 298 K
V = 217 L
volume of balloon is 217 L
Final answer:

By using the Ideal Gas Law and the given conditions, we can calculate the volume of the weather balloon to be approximately 221.4 liters.

Explanation:

The volume of a gas can be determined by using the Ideal Gas Law: PV = nRT. Here, P is the Pressure, V is the Volume, n is the number of moles, R is the universal gas constant and T is the absolute Temperature. The constants provided in the question are the moles of Helium (8.80 moles), the Pressure (0.992 atm) and the Temperature (25 C).

Firstly, we need to convert the temperature from Celsius to Kelvin. The conversion formula is: T(K) = T(C) + 273.15. Thus, T(K) = 25 + 273.15 = 298.15 K.

Now, we use these values in the Ideal Gas Law to find the volume. We rearrange the formula to solve for volume: V = nRT / P. Substituting the given values and the gas constant R as 0.0821 atm L/mol K, we get:

V = (8.80 moles * 0.0821 L atm / (mol K) * 298.15 K) / 0.992 atm = 221.4 L

Therefore, the volume of the weather balloon under the given conditions is approximately 221.4 Liters.

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List the number of each type of atom on the left side of the equation hbr(aq)+2naoh(aq)→2nabr(s)+h2o(l)

Answers

In this unbalanced chemical reaction, on the left side, there are:
1) three hydrogen atoms, one in molecule HBr and two in two molecules of sodium hydroxide (NaOH).
2) one bromine atom (Br) in hydrobromic acid (HBr).
3) two sodium atoms (Na) in two molecules of NaOH.
4) two oxygen atoms in two melecules of sodium hydroxide.

The left side of the equation HBr(aq) + 2NaOH(aq) includes a total of three hydrogen (H) atoms, one bromine (Br) atom, two sodium (Na) atoms, and two oxygen (O) atoms.

To list the number of each type of atom on the left side of the chemical equation [tex]HBr(aq) + 2NaOH(aq) \rightarrow 2NaBr(s) + H_2O(l)[/tex], we first need to identify each atom present in the reactants. For HBr, we have one hydrogen (H) atom and one bromine (Br) atom. Then, for 2NaOH, since it has a coefficient of two, we count two sodium (Na) atoms, two oxygen (O) atoms, and two hydrogen (H) atoms. Therefore, the total count of each type of atom on the left side is:

Hydrogen (H) atoms: 1 (from HBr) + 2 (from NaOH) = 3Bromine (Br) atoms: 1 (from HBr)Sodium (Na) atoms: 2 (from NaOH)Oxygen (O) atoms: 2 (from NaOH)

When potassium-40 undergoes decay by electron capture the product is?

Answers

Electron capture decay is a decay process. In this process electron is captured and a proton is converted into a neutron. Hence, mass number remains same but atomic number is lowering by 1 in daughter atom. 

K has atomic number 19. Hence daughter atom should have 19 - 1 = 18 as the atomic number. Hence, produced particle is Ar. but the mass number of Ar remains as same as 40.

The equation is,
₁₉⁴⁰K + ₋₁⁰e → ₁₈⁴⁰Ar

Write and balance a net ionic equation for the reaction between iron(ii) chloride and potassium hydroxide to form iron(ii) hydroxide and potassium chloride.

Answers

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of iron (II) chloride and potassium hydroxide is given as:

[tex]FeCl_2(aq.)+2KOH(aq.)\rightarrow Fe(OH)_2(s)+2KCl(aq.)[/tex]

Ionic form of the above equation follows:

[tex]Fe^{2+}(aq.)+2Cl^-(aq.)+2K^+(aq.)+2OH^-(aq.)\rightarrow Fe(OH)_2(s)+2K^+(aq.)+2OH^-(aq.)[/tex]

As, potassium and hydroxide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

[tex]Fe^{2+}(aq.)+2OH^-(aq.)\rightarrow Fe(OH)_2(s)[/tex]

Hence, the net ionic equation is written above.

Final answer:

Iron(II) chloride reacts with potassium hydroxide to form iron(II) hydroxide and potassium chloride. The net ionic equation, which only includes the particles that participate in the reaction, is: Fe2+(aq) + 2 OH-(aq) → Fe(OH)2(s). Potassium and chloride ions are spectator ions and aren't included.

Explanation:

The reaction between iron(II) chloride (FeCl2) and potassium hydroxide (KOH) produces iron(II) hydroxide (Fe(OH)2) and potassium chloride (KCl). The balanced chemical equation for this reaction is:

FeCl2(aq) + 2 KOH(aq) → Fe(OH)2(s) + 2 KCl(aq).

The net ionic equation only includes the ions and molecules directly involved in the reaction, which are Fe2+, Cl-, K+, and OH-. Therefore, the net ionic equation will look like this:

Fe2+(aq) + 2 OH-(aq) → Fe(OH)2(s).

The potassium ions (K+) and chloride ions (Cl-) do not participate directly in the reaction so they are not included. They are known as the spectator ions.

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Malonic ester (diethyl malonate) is treated successively with sodium ethoxide (1 eq.), ethyl bromide, potassium tert-butoxide, isobutyl chloride, hot aqueous naoh, hcl, and heat. what is the final product?

Answers

In first step the acidic proton at alpha position is abstracted by NaOEt and forms Enolate.
The resulting enolate undergoes SN² reaction with Ethyl Bromide.
The resulting product again on treatment with Potassium tertiary Butoxide gives corresponding Enolate.
This second enolate on treatment with Isobutyl Chloride undergo SN² reaction.
At last treatment with NaOH (aq) and HCl at high temperature yield 2-Ethyl-4-methylpentanoic Acid.

Final answer:

Malonic ester synthesis converts alkyl halides to carboxylic acids with two additional carbons.

Explanation:

Malonic ester synthesis involves a series of reactions converting an alkyl halide into a carboxylic acid with two additional carbons. The final product after treating malonic ester successively with sodium ethoxide, ethyl bromide, potassium tert-butoxide, isobutyl chloride, hot aqueous sodium hydroxide, hydrochloric acid, and heat would be a carboxylic acid with a methyl group attached.

What body of water is located between 30°N and 40°N latitude of africa

Answers

Final answer:

The Mediterranean Sea is the body of water between 30°N and 40°N latitude of Africa, bordering countries such as Egypt, Libya, and Tunisia.

Explanation:

The body of water located between 30°N and 40°N latitude of Africa is the Mediterranean Sea. This sea is situated to the north of the African continent and it borders several African countries including Egypt, Libya, and Tunisia within the specified latitudinal range. To its north are southern European countries, and to the east, it connects with the Middle East. The Nile River, one of the longest rivers in the world, empties into the Mediterranean Sea after flowing north through Egypt.

Iodine-131 decays with a half-life of 8.02
d. in a sample initially containing 5.00 mg of 131i, what mass remains after 6.01 d

Answers

Final answer:

The question is about the decay of radioactive isotope Iodine-131 over time, using the concept of half-life. It's calculated that after 6.01 days, approximately 3.18mg of the initial 5.00mg of Iodine-131 remains.

Explanation:

The question is about the decay of the Iodine-131 isotope, a nuclear physics concept, using the half-life theory. The half-life is the time it takes for half of a radioactive substance to decay. In this case, the half-life of Iodine-131 is 8.02 days. After 6.01 days, the question asks how much of an initial 5.00 mg sample remains.

First, we need to determine how many half-lives have passed during the 6.01 days. We can calculate this by dividing the overall time elapsed by the half-life of the isotope (6.01 / 8.02). This gives us approximately 0.75 half-lives.

Now, for each half-life, the substance will halve in quantity. So, we can calculate the remaining mass by multiplying the initial mass by (0.5) raised to the power of the number of half-lives (0.75). So, (5.00 mg) * (0.5)^0.75 = 3.18 mg.

So, after 6.01 days, approximately 3.18 mg of the original Iodine-131 remains.

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To calculate the remaining mass of iodine-131 after 6.01 days with a half-life of 8.02 days, use the decay formula. For an initial 5.00 mg sample, approximately 2.58 mg of iodine-131 would remain after 6.01 days.

Iodine-131 decays with a half-life of 8.02 days. To calculate the mass remaining after 6.01 days, we use the formula: Final mass = Initial mass x (1/2)^(time elapsed/half-life).

Given an initial mass of 5.00 mg of 131I and a decay time of 6.01 days, the mass remaining can be calculated as follows:

Final mass = 5.00 mg x (1/2)^(6.01/8.02)Final mass = 5.00 mg x (1/2)^(0.7494)Final mass = 5.00 mg x 0.5158 = 2.58 mg

An element's atomic number is the _____?

Answers

number of protons found in the nucleus of an atom.
An element's atomic number is the protons with positive charge from the nucleus atom.

Hope it helped you.

-Charlie

Question 19 Unsaved
Which of the following is NOT one of the warning signs used to predict a volcanic eruption?


1)

changing chemistry of volcanic gas


2)

development and widening of surface cracks on the volcano


3)

earthquake activity


4)

the activity of animals

Answers

The volcanic eruption warning sign has not been the widening of the surface and cracks in the volcano. Thus, option 2 is correct.

Volcanic eruptions can be defined as the coming out of the lava and the magma from the earth's crust. The volcanic eruptions have consisted of magma along with several gases.

The change in the chemistry of the volcanic gas has been the warning sign of the eruption as there has been a change in the pressure and temperature of the gases that results in the explosion.

The volcanic eruption has been mediated by the shift in the earth's crust leading to earthquake activity.

The volcanic eruption has also been mediated with the warning sign as the activity of the animals, as some animals have been capable of listening to the waves that have been the indication of the volcanic eruption.

In the volcanic eruption, there has been no widening of the earth's surfaces or cracks in the volcano. However, this has been an alarming sign of the movement of the tectonic plate. Thus, option 2 is correct.

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Final answer:

The activity of animals is not a scientific indicator for predicting volcanic eruptions, unlike seismic activity, gas emissions, and geological changes.

Explanation:

The question asks which of the following is NOT a warning sign used to predict a volcanic eruption. Changing chemistry of volcanic gas, development and widening of surface cracks on the volcano, and earthquake activity are all regarded as warning signs of a potential volcanic eruption. However, the activity of animals is not considered a reliable scientific indicator for predicting volcanic eruptions. Animal behavior can be influenced by many factors, and while there are anecdotal reports of animals acting unusually before an eruption, it is not used as a primary method of prediction by volcanologists. Instead, they rely on more measurable signs like seismic activity, gas emissions, and geological changes.

What is the [pb2+] in a solution made by adding 100 g of pbcl2(s) (mm = 278.1 g/mol) to a 5.4 m solution of nacl and allowing it to come to equilibrium? ignore any changes to solution volume due to the addition of pbcl2(s). once solution reaches equilibrium, it is noticed that some solid pbcl2 remains undissolved. the ksp for pbcl2 is 1.6 × 10−5?

Answers

                    PbCl₂ ⇄ Pb²⁺ + 2 Cl⁻
Initially                         0         5.4 M
Change          -x         + x        + 2x
Equilibrium                  x          5.4 + 2x

Ksp = [Pb²⁺] [Cl⁻]²
1.6 x 10⁻⁵ = x (5.4 + 2x)²
since x <<<< 5.4 so 2x + 5.4 = 5.4
1.6 x 10⁻⁵ = x (5.4)²
x = 5.48 x 10⁻⁷
[Pb²⁺] = 5.48 x 10⁻⁷ M

Calculate the energy transferred in joules when 29.5g of liquid water decreases from 14c to 0.0c

Answers

The  energy transferred  in joules  is   calculated  using the below  formula

Q(heat energy) =  M(mass)  x C (specific  heat capacity )  x  delta T(change  in  temperature
delta T =  0. 0c-  14 c  =  -14 c
M= 29.5 g
C of  water is always =  4.18  j/g/c

= 29.5 g x  -14 c x 4.18 j/g/c =-1726.34  joules are  needed when  29.5 g  of  liquid  water  decrease  from  14 c  to  0.0  C

The alkali metals react with the halogens to form ionic metal halides. what mass of potassium chloride forms when 5.11 l of chlorine gas at 0.943 atm and 286 k reacts with 29.0 g potassium?

Answers

ideal gas law: PV = nRT so ..... V = PV/(RT) 

Initial number of moles of Cl, n = 0.943*5.11/(0.08206 × 286) mol = 0.2053 moles.

We know the molar mass of K (potassium) = 39.0 g/mol 
sooo....
The Initial number of moles of K = 29.0 g/(39.0 g/mol) = 0.7436 moles

Find the balanced equation for the reaction : 2K + Cl2 → 2KCl 
Mole ratio of K:Cl = 2:1 

So after the reaction, the amount of K needed = (0.2053 mol) × 2 = 0.4106 mol which is less than 0.7436 mol 

This means that K is in excess but Cl completely reacts. 

 So we know the mole ratio is  Cl:KCl = 1 : 2 

Number of moles of Cl (completely) reacted = 0.2053 mol which means the number of moles of KCl formed = (0.2053 mol) × 2 = 0.4106 mol 

Molar mass of KCl = (39.0 + 35.5) g/mol = 74.5 g/mol 
Mass of KCl formed = 0.4106 mol * 74.5 g/mol = 30.6 g

The mass of  potassium chloride formed is 31.5 g

The number of moles of chlorine gas  is obtained from the ideal gas equation;

P = 0.943 atm

V = 5.11 l

T = 286 K

n = ?

R = 0.082 atm L K-1mol-1

From;

PV = nRT

n = PV/RT

n =  0.943 atm * 5.11 l/0.082 atm L K-1mol-1 * 286 K

n =4.819 /23.452

n = 0.21 moles of Cl2

Number of moles of K = mass/molar mass = 29.0 g/39 g/mol = 0.74 moles

Equation of the reaction is;

2K + Cl2 ----> 2KCl

Since the reaction is 2:1

1 mole of Cl2 reacts with 2 moles of K

0.21 moles of Cl2 reacts with 0.21 * 2/1 = 0.42 moles of K

This means that K is the reactant in excess.

1 mole of Cl2 yields 2 moles of KCl

0.21 moles of Cl2 yields  0.21 * 2/1 = 0.42 moles of KCl

Molar mass of KCl = 75 g/mol

Mass of KCl = 0.42 moles of KCl * 75 g/mol

Mass of KCl = 31.5 g of KCl

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The concentration of kbr in a solution prepared by dissolving 2.10 g of kbr in 897 g of water is __________ molal.

Answers

Final answer:

To find the molality of a KBr solution, divide the mass of KBr (2.10 g) by its molar mass (119.0 g/mole) to get moles, and then divide by the mass of the solvent in kilograms (0.897 kg of water).

Explanation:

The concentration of KBr in a solution prepared by dissolving 2.10 g of KBr in 897 g of water is calculated using the molality formula. Molality is defined as the number of moles of solute per kilogram of solvent. First, we need to find the number of moles of KBr by dividing the mass (2.10 g) by its molar mass (119.0 g/mole), which gives us the number of moles. Then, we divide the number of moles by the mass of the solvent (water) in kilograms to obtain the molality of the solution.

The calculation is as follows:

Number of moles of KBr = 2.10 g / 119.0 g/moleMolality (m) = Number of moles of KBr / 0.897 kg (mass of water)

By performing these calculations, we can determine the molality of the KBr solution.

A compound contains 64.27% carbon, 7.19% hydrogen, and 28.54% oxygen. the molar mass is 168.19 g/mol. what is the molecular formula

Answers

empirical formula is the simplest ratio of whole numbers of components in a compound 
calculating for 100 g of compound 
                                             C                             H                             O
mass                                  64.27 g                   7.19 g                     28.54 g
number of moles        64.27 g / 12 g/mol      7.19 g/1 g/mol     28.54 g / 16 g/mol 
                                        = 5.356 mol           = 7.19 mol           = 1.784 mol 
divide by least number of moles  
                                     5.356 / 1.784            7.19 / 1.784         1.784 / 1.784
                                      = 3.002                     4.03                     = 1.000
rounded off to nearest whole number 
 C - 3
 H - 4
 O - 1
empirical formula - C₃H₄O
 
 mass of empirical formula = 12 g/mol  x 3 + 1 g/mol x 4 + 16 g/mol x 1 = 56 g
molecular mass = 168.19 g/mol 
molecular formula is the actual ratio of elements making up the compound 
number of empirical units = molar mass of molecule / empirical mass
      empirical units = 168.19 g/mol  / 56 g = 3.00
there are 3 empirical units making up the molecular formula 
molecular formula = 3 x C₃H₄O

molecular formula = C₉H₁₂O₃

                 
Final answer:

The molecular formula for a compound with 64.27% carbon, 7.19% hydrogen, and 28.54% oxygen with a molar mass of 168.19 g/mol is C9H12O3.

Explanation:

First, we assume 100g of the compound is present so the percentages can be taken as the mass in grams of each element. This gives us 64.27g of carbon, 7.19g of hydrogen, and 28.54g of oxygen. Then, we convert grams to moles using each element's molar mass (C=12.01g, H=1.01g, and O=16.00g).

So, for Carbon we get:

64.27g/12.01g = 5.349 moles

For Hydrogen we get:

7.19g/1.01g = 7.119 moles

For Oxygen we get:

28.54g/16.00g = 1.784 moles.

Now, we divide each mole number by the smallest number of moles calculated in the previous step (1.784) to determine the mole ratio, rounding to the nearest whole number. This will give us C3H4O1. Thus, our empirical formula (the formula in its lowest terms) is C3H4O1.

The next step is to determine the molecular formula, which tells us the actual number of atoms of each element in a molecule of the compound. To find the molecular formula, we compare the empirical formula mass to the molar mass of the compound to find a multiple which we then use to multiply the subscripts in our empirical formula. Therefore, with a molar mass of 168.19 g/mol and an empirical formula weight of 56.06 g/mol (C3H4O1), we find our multiple to be 3 (around 168/56).

The resulting molecular formula would be C9H12O3, meaning our compound consists of 9 carbon atoms, 12 hydrogen atoms, and 3 oxygen atoms.

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The coolest and dimmest space objects emit radiation of longer wavelengths than those we can see. A detector for which type of electromagnetic radiation is most suitable to study cool dim stars?

Answers

Answer: Infrared detectors.

Explanation:


1) Remember the relation between the wavelength and the frequency: they are inversely related. The longer the wavelength the higher the frequency.

2) Infrared radiaton is the electromagnetic radiation with longer wavelength than the visible light and is next to it in the spectrum.

3) Infrared detectors use the properties of some materials to detect the infrared light (waves) either by their effect in the temperature or by capturing the photons emitted by the object analyzed.

4) The effects that are most used to analyze the radiaton are 1) that the change of temperature induces changes in resistance (thermal detectors) and 2) the photons excite the atoms (photodetectors).

Answer:

infared detectors

Explanation:

What is the percent of MgSO4 in magnesium sulfate heptahydrate?

48.83 %
51.17 %
95.43 %
86.98 %

Answers

Molecular weight of MgSO4.7H2O is = 246.47 g
Molecular weight of MgSO4 is = 120.36 g

Hence, per cent of MgSO4 present in MgSO4.7H2O is,
=[tex] \frac{\text{Molecular weight of MgSO4}}{\text{Molecular weight of MgSO4.7H2O}} [/tex] X 100
= [tex] \frac{120.36}{246.47} [/tex] X 100
= 48.83 %

Answer:

48.83

Explanation:

on edge

Why is the bond between two single hydrogen atoms stable?
A. It is not stable, each hydrogen only has 1 electron and they need 8 electrons to be stable.
B. Hydrogen only uses the first energy shell, which holds 2 electrons, not 8.
C. Each hydrogen donates more electrons in their lower energy shells to get to 8 but only to other hydrogen atoms.
D. Each hydrogen has 4 electrons to share for a total of 8 when 2 hydrogens bond.

Answers

B ia the correct one .

Hydrogen only uses the first energy shell, which holds 2 electrons, not 8.

Answer:

B. Hydrogen only uses the first energy shell, which holds 2 electrons, not 8.

Explanation:

As hydrogen is the first element in the periodic table and has the atomic number it can mix with a variety of elements, including itself, when two atoms of Hydorgen bond the bond they create fills up the first level of energy which only uses 2 electrons in order to be completed, which makes the bond stable by filling up the energy level.

Define solubility (in science)

Answers

Solubility is the property of a solid, liquid or gaseous chemical substance called solute to dissolve in a solid, liquid or gaseous solvent.

Write a balanced equation for the combustion of propane. (be sure to include states of matter in your equation.)

Answers

[tex]C_{3}H_{8} (g) + 5O_{2}(g) --\ \textgreater \ 3CO_{2}(g)+4H_{2}O(l)[/tex]

Does the structure below exhibit geometric isomerism? ch3 tally1 ch3― c ―ch═ch―ch3 tally1 ch3

Answers

Answer:
             YES! The given compound exhibit Geometrical Isomerism.

Explanation:
                      In Geometrical Isomerism or Cis-Trans Isomerism, isomers possess same molecular formula, same structural formula with a double bond and with a only difference in the arrangement of atoms or group of atoms about the double bond in three dimensional space.
                      4,4-dimethylpent-2-ene (given problem) has two groups about the double bond i.e. Methyl (CH₃-) and tertiary Butyl [(CH₃)₃-C-]. In cis configuration both groups are at same side of the double bond, while in trans configuration both groups are located opposite to each other as shown below;

If the ph of hc3h5o2 is 4.2 and the ka 1.34x10^-5, what is the equilibrium concentration

Answers

Following equilibrium is upon dissociation of propanoic acid,

HC3H5O2    ⇄     H+    +    C3H5O2-

Thus, dissociation constant of acid can be mathematically expressed as,
Ka = [tex] \frac{[H+]{C3H5O2-}}{[HC3H5O2]} [/tex]

Given:  pH of HC3H5O2 = 4.2 and Ka = 1.34x10^-5
We know that, pH = -log[H+]  = 4.2
∴ [H+] = 6.31 x 10^-5

From the reaction it can be seen that [H+] = [C3H5O2-]

∴ [HC3H5O2] = [H+] [C3H5O2-] /Ka  = (6.31 x 10^-5)^2 / 1.34x10^-5 = 2.97 x 10^-4 M

Thus, equilibrum conc. of HC3H5O2 is 2.97 x 10^-4 M.

Why is potassium nitrate classified as aj electrolyte?

Answers

Final answer:

Potassium nitrate is classified as an electrolyte because it dissociates into electrically charged ions, potassium (K+) and nitrate (NO3-), which allow it to conduct electricity when dissolved in water.

Explanation:

Potassium nitrate is classified as an electrolyte because it dissociates into ions when dissolved in water. Potassium (K), with an atomic number of 19, easily donates its one valence electron, resulting in a positively charged potassium ion, K+. This ion is a cation. Similarly, the polyatomic nitrate ion, NO3-, which is held together by polar covalent bonds, combines with the potassium cation to form the ionic compound potassium nitrate, KNO3. The dissociation of potassium nitrate in water into K+ and NO3- ions enables it to conduct electricity, a characteristic behavior of electrolytes.

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