What is the equation of the following line written in slope-intercept form

To honor 50 years of business, All Strikes Bowling is having an anniversary special. The game he can bowl is 25.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

To honor 50 years of business, All Strikes Bowling is having an anniversary special.

Shoes rent for $1.25 and each game is $0.75. If Charlie has $20 and needs shoes.

Charlie can bowl 25 games.

= 20 - 1.25

= 18.75

So, he can bowl game

= 18.75/ 0.75

= 25 games

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Answer:

27 cm2

Step-by-step explanation:

The answer is 27 cm 2 because if you use length x base x height you would get your answer. So 6 x 3 x 3 = 54 and then if you divide that by 2 you would get 27

Answer:

the answer is C), 27 cm2

Step-by-step explanation:

Step-by-step explanation:

y^b^4=1/y^24

y^b^4xy^24=1

b^4y^25=1

b^4=1/y^25

√b^4=√1/y^25

b=√1/y^25

It's B. -6

apparently i have to write at least 20 characters so,,,, sorry yall.

Answer:

P(red or blue) = 5/18 + 6/18 = 11/18

The solution is:

H(w) gets very small when w gets very large .

In mathematics, the graph of a function f is the set of ordered pairs, where {\displaystyle f(x)=y.} In the common case where x and f(x) are real numbers, these pairs are Cartesian coordinates of points in two-dimensional space and thus form a subset of this plane.

Here, we have,

Considering the graph H(w),

As w gets larger, H(w) continues to approach a horizontal asymptote.

we know that,

A horizontal asymptote of a graph is a horizontal line y = b where the graph approaches the line as the inputs approach ∞ or –∞. A slant asymptote of a graph is a slanted line y = mx + b where the graph approaches the line as the inputs approach ∞ or –∞.

Hence, H(w) gets very small.

Therefore, the correct option is option D

Hence, The solution is:

H(w) gets very small when w gets very large .

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It is given in the question that

The school is 625 meters far from Alex house. It took him 15 minutes to go from home to school, and run back to home in 10 minutes.

Total distance is 625 meters and total time taken is

[tex] (10+15) minutes=25minutes [/tex]

Average speed is

[tex] \frac{total \ distance \  travelled}{total \ time \ taken} [/tex]

[tex] = \frac{625}{25}meter/minute = 25 meter/minute [/tex]

Answer:

25 minutes

Step-by-step explanation:

As hamster wheel is circular so for revolution we will find the circumference.

Diameter of the Hamster wheel = 8.5 in

One revolution of the wheel = circumference of the wheel

Circumference = π × d

π = 3.14 and d = 8.5

So, Circumference = 3.14 × 8.5

Circumference = 26.69 in

So in one revolution the hamster wheel travels a distance of 26.69 in

The correct option is B. 81 mm, 7 mm, 72 mm could be the lengths of the sides of a triangle.

To determine if a set of numbers could be the lengths of the sides of a triangle, the Triangle Inequality Theorem must be satisfied. The theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

Let's apply this theorem to each set of numbers:

A. 81 mm, 7 mm, 6 mm

- The sum of the two smallest sides is 81 + 6 = 87 mm, which is greater than the third side, 7 mm. However, the sum of the two smallest sides, 7 + 6 = 13 mm, is not greater than the largest side, 81 mm. Therefore, these lengths cannot form a triangle.

B. 81 mm, 7 mm, 72 mm

- The sum of the two smallest sides is 7 + 72 = 79 mm, which is greater than the third side, 81 mm. This set satisfies the Triangle Inequality Theorem.

C. 81 mm, 7 mm, 88 mm

- The sum of the two smallest sides is 81 + 7 = 88 mm, which is equal to the third side, 88 mm. According to the Triangle Inequality Theorem, the sum must be strictly greater than the third side, so these lengths cannot form a triangle.

D. 81 mm, 7 mm, 77 mm

- The sum of the two smallest sides is 7 + 77 = 84 mm, which is greater than the third side, 81 mm. However, the sum of the two smallest sides, 81 + 7 = 88 mm, is not greater than the third side, 77 mm. Therefore, these lengths cannot form a triangle.

Based on the Triangle Inequality Theorem, the only set of lengths that can form a triangle is option B: 81 mm, 7 mm, 72 mm.

Answer:

74.29%

Step-by-step explanation:

A student passed 60%, or a proportion of 0.60 of the 20 quizzes he's written so far. This means he has passed [tex]0.60*20=12[/tex] quizzes so far.

Now he has written 50 quizzes and passed 80% of them, or [tex]50*.8=40[/tex] quizzes.

To find the success rate, take the number of quizzes passed and divide by total number of quizzes.

[tex]\frac{Passed}{Total}[/tex]=[tex]\frac{12+40}{20+50}[/tex]=[tex]\frac{52}{70}[/tex]=.7429

To get a percentage, multiply this proportion by 100 to get 74.29%

Answer:

Option A  [tex]\frac{4}{30}=0.13333...=0.1\bar3[/tex]

Step-by-step explanation:

Given : Expression [tex]\frac{4}{30}[/tex]

To find : What is the decimal equivalent of the fraction?

Solution :

Step 1 - Write the fraction

[tex]\frac{4}{30}[/tex]

Step 2 - Divide the numerator by denominator,

[tex]\frac{4}{30}=0.13333...[/tex]

or [tex]\frac{4}{30}=0.13333...=0.1\bar3[/tex]

Therefore, Option A is correct.

Final answer:

To find cot a when cos a = 3/5 in the first quadrant, we first determine the length of the opposite side using the Pythagorean theorem, which gives us 4. Subsequently, cot a is calculated as the ratio of the adjacent to the opposite side, resulting in cot a = 3/4.

Explanation:

If cos a = 3/5 in the first quadrant, we use trigonometric identities to find cot a. First, recognize that in a right triangle, the Pythagorean theorem states a² + b² = c². Given cos a = adjacent/hypotenuse = 3/5, and the fact that we are in the first quadrant (where all trigonometric values are positive), we can solve for the opposite side using the Pythagorean theorem.

Let the opposite side be b, the adjacent side (corresponding to cos a) be 3, and the hypotenuse be 5. The equation becomes b² + 3² = 5² which simplifies to b² = 25 - 9 = 16, giving b = 4.

We know that cot a = adjacent/opposite = cos a / sin a. Thus, sin a = b / hypotenuse = 4/5. Therefore, cot a = 3/4.

The fact that Anthony repeats the test [tex]n[/tex] times doesn't change anything, because he already know that you have a 50/50 chance of turning left of right.

Given that, Anthony observes that when people are leaving class, about 50% turn left and about 50% turn right.

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

H represent turning left when leaving class and T represent turning right,

Both of them have a 50% probability of happening and he wants to know the probability of less than 3 turn left so we want to know the probability for only one to turn left and the probability for only two.

Only one:

If you use the fact that we have a binomial distribution, then the possibility that only one turns left is:

So, [tex]P(1)=\frac{4!}{3!} \times0.5^{4[/tex]

= 4×0.0625 = 0.25

Only two with the same reasoning.

[tex]P(2) = \frac{4!}{(2!\times2!)} \times0.0625=6\times0.0625 = 0.375[/tex]

Here you can see that the probability is bigger because here are mass  combinations that in the previous case.

So the total probability is 0.25 + 0.375 = 0.625.

The fact that he repeats the test [tex]n[/tex] times doesn't change nothing, because he already know that you have a 50/50 chance of turning left of right.

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In this detailed answer, the probabilities of drawing two coins from Kevin's pocket - with 6 nickels and 4 dimes - are explained. The probabilities of both coins being nickels and dimes are 0 due to the lack of replacement, while the probability of one nickel and one dime is 4/15.

To calculate the probabilities of drawing coins from Kevin's pocket, where he has 6 nickels and 4 dimes:

Probability both coins are nickels: Since each draw affects the remaining number of nickels and dimes, the probability is 0.

Probability both coins are dimes: Similarly, as the draws are not independent, the probability here is also 0.

Probability of one nickel and one dime: Since Kevin has 6 nickels and 4 dimes, the probability of drawing a nickel first is 6/10 (6 nickels out of 10 coins) and drawing a dime second is 4/9 (4 dimes remaining out of 9 coins), which equals 24/90 or 4/15.

Answer:

Step-by-step explanation:

Alright, lets get started.

The given expression is :

[tex]2x^3+10x^2+4x+20[/tex]

taking 2 common factor

[tex]2(x^3+5x^2+2x+10)[/tex]

[tex]2(x^3+2x+5x^2+10)[/tex]

[tex]2[(x+5)(x^2+2)][/tex]

So, the correct answer is option B :    answer

Hope it will help :)