A reactant decomposes with a half-life of 137 s when its initial concentration is 0.165 m. when the initial concentration is 0.722 m, this same reactant decomposes with the same half-life of 137 s.
Balance the reactions which form ions. Choose "blank" if no other coefficient is needed. Writing the symbol implies "1."
1) (NH4)2CO3 ____ NH4 +_____ + CO3 -2
2) PbI2 _____ Pb+2 +______ I+1
3) (NH4)3PO4 ______ NH4 + _____ + PO4 +3
Which of the following would be expected to form ionic solutions in water?
CO2
C
NaI
CCl4
O2
NaI-Sodium Iodide
Explanation;Ionic solutions are solutions that are formed when ionic compounds dissolve in a solvent such as a water.Ionic compounds are compounds that are formed as a result of transfer of electrons between non metal atoms and metal atoms, thus forming an ionic bond. When an ionic compound such as sodium iodide dissolves in water, it dissociates into cations, sodium ions, and anions, iodide ions.How much heat is evolved in converting 1.00 mol of steam at 155.0 ∘c to ice at -50.0 ∘c? the heat capacity of steam is 2.01 j/(g⋅∘c) and of ice is 2.09 j/(g⋅∘c)?
A certain compound is made up of one carbon (c) atom, two bromine (br) atoms, and one oxygen (o) atom. what is the chemical formula of this compound
Answer:
The chemical formula of the compound will be COBr2.
Further details:
• The chemical formula of the compound is COBr2.
• The IUPAC name is Carbonic Dibromide
• The common name of the compound is Bromophosgene
As we know Carbon has the propensity to form four covalent bonds, Oxygen can form two covalent bonds and Bromine can form a single bond. Keeping this in mind we can say that in given compound carbon are making two single bonds with two bromine atoms and a double bond with oxygen atom. So, the valencies of all essentials in the given compound are fulfilled and accomplished.
Formation of Carbon dibromide:
Carbonyl bromide is made when carbon tetrabromide is melted and concentrated sulfuric acid is added.
In compare to phosgene, carbonyl bromide cannot be twisted efficiently from carbon monoxide and bromine. A complete alteration is not possible due to thermodynamic causes. Additionally, the reaction
CO + Br2 ⇌ COBr2
Answer details:
Subject: Chemistry
Level: College
Keywords:
Carbon dibromideFormation of carbon dibromideCarbon Bromine OxygenLearn more to evaluate:
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One of these substances is a liquid at room temperature. which one? one of these substances is a liquid at room temperature. which one? sih4 co2 nh2oh cf4
Among the substances SiH4, CO2, NH2OH, and CF4, it is Hydroxylamine (NH2OH) which is the liquid at room temperature due to its hydrogen bonding.
Explanation:Among the substances SiH4, CO2, NH2OH, and CF4, it is NH2OH (Hydroxylamine) which is a liquid at room temperature. This is due to the variations in the intermolecular forces among these substances:
SiH4(Silane) and CF4(Tetrafluoromethane) are gases at room temperature because their molecules are held together by weak Van der Waals' forces which require less thermal energy to overcome. CO2 (Carbon Dioxide) is well known to be a gas at room temperature and atmospheric pressure. NH2OH(Hydroxylamine) on the other hand, exhibits hydrogen bonding (a strong type of dipole-dipole interaction). This bonding causes an increased boiling point, making it a liquid at room temperature.Learn more about Phases of Matter here:
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The standard reduction potential for I2/I –is +0.54V, and the standard reduction potential for Br2/Br -is +1.07V. Which reaction occurs when bromine is added to an aqueous solution of iodide ions?
1. 2I –+ 2Br –→ I2+ Br2
2. I2+ 2Br –→ Br2+ 2I –
3. I2+ Br2→ 2I –+ 2Br –
4. 2I –+ Br2→ I2+ 2Br –
Final answer:
When bromine is added to an aqueous solution of iodide ions, the reaction that occurs is the oxidation of iodide ions to iodine and the reduction of bromine to bromide ions, as bromine has a higher standard reduction potential and will thus be reduced. Hence, the reaction that occurs is 2I⁻ + Br₂ → I₂ + 2Br⁻.
Explanation:
To determine which reaction will occur when bromine is added to an aqueous solution of iodide ions, we can compare the standard reduction potentials of the Br₂/Br⁻ and I₂/I⁻ couples. The standard reduction potential for Br₂/Br⁻ is +1.07V, and for I₂/I⁻ it is +0.54V. Given that a higher potential indicates a greater tendency to gain electrons (undergo reduction), we can infer that Br₂ will be reduced (gain electrons) rather than I₂.
Therefore, iodide ions (I-) will be oxidized by bromine (Br₂) to form iodine (I₂) and bromide ions (Br⁻). The balanced half-reactions are:
Br₂ + 2e⁻ → 2Br− (Reduction)2I− → I₂ + 2e− (Oxidation)Overall, the reaction that occurs is 2I⁻ + Br₂ → I₂ + 2Br⁻, which correlates to option 4 in the list provided by the student. This is because the reaction can only occur in the direction that allows bromine to be reduced since it has a higher reduction potential.
A 10.0-ml sample of 0.200 m hydrocyanic acid (hcn) is titrated with 0.0998 m naoh. what is the ph at the equivalence point? for hydrocyanic acid, pka = 9.31
The pH at the equivalence point of the titration can be calculated using the Henderson-Hasselbalch equation. The pH at the equivalence point is 9.31.
Explanation:The pH at the equivalence point of the titration can be calculated using the Henderson-Hasselbalch equation. The equivalence point occurs when the moles of hydrocyanic acid (HCN) is equal to the moles of sodium hydroxide (NaOH).
In this case, the hydrocyanic acid (HCN) is a weak acid, and the sodium hydroxide (NaOH) is a strong base. At the equivalence point, the weak acid is completely neutralized by the strong base, forming the conjugate base of the acid.
Using the Henderson-Hasselbalch equation, we can calculate the pH at the equivalence point:
pH = pKa + log([A-]/[HA])
The concentration of the hydrocyanic acid (HCN) is 0.200 M, and since hydrocyanic acid is a weak acid, its concentration can be assumed to remain nearly constant during the titration. Therefore, the concentration of the conjugate base at the equivalence point is also 0.200 M.
Plugging in the values, we have:
pH = 9.31 + log(0.200/0.200) = 9.31
So, the pH at the equivalence point is 9.31.
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A 90.00 mL solution of NaCl and ethyl alcohol has 7.83 g of salt dissolved in the alcohol. Calculate the molar concentration of the solution. Remember to use significant digit rules.
Answer:
The molar concentration of the solution is calculated as follows
find the moles of NaCl used to make the solution
moles = mass/molar mass
mass =7.83 g
molar mass =58.5 g/mol
moles = 7.83 g/ 58.5 g/mol = 0.134 moles
molarity ( concentration in mol/l) = number of moles/volume in liters
volume in liters = 90ml/1000 =0.09 liters
molarity is therefore = 0.134 moles/0.09 L =1.49 M
Explanation:
Which substance yields hydroxide ion as the only negative ion in aqueous solution?
According to the balanced chemical equation, how many atoms of silver will be produced from combining 100 g of copper with 200 g of silver nitrate?
Final answer:
The balanced chemical equation reveals that 100g of copper reacting with 200g of silver nitrate yields 6.022 × 10^23 atoms of silver.
Explanation:
The balanced chemical equation for the reaction between copper (Cu) and silver nitrate (AgNO3) is:
Cu (s) + 2AgNO₃ (aq) → Cu(NO₃)² (aq) + 2Ag (s)
From the equation, when 100g of copper reacts with 200g of silver nitrate, it will produce 6.022 × 10²³ atoms of silver.
___ + ___ = H2O + LiBrO3 Complete and balance the equation representing neutralization reaction.
The complete and balanced neutralization reaction is HBrO₃(aq) + LiOH(aq) → H₂O(l) + LiBrO₃(aq), where hydrobromic acid reacts with lithium hydroxide to produce water and lithium bromate.
Explanation:
The student's question pertains to completing and balancing a chemical equation for a neutralization reaction. In a neutralization reaction, an acid and a base react to form water and a salt. To complete and balance the given equation ___ + ___ = H₂O + LiBrO₃, we need to identify the acid and the base that will produce lithium bromate (LiBrO₃) and water.
The balanced equation for this reaction is:
HBrO₃(aq) + LiOH(aq) → H₂O(l) + LiBrO3(aq)Here, hydrobromic acid (HBrO₃) reacts with lithium hydroxide (LiOH), producing water (H₂O) and lithium bromate (LiBrO₃). This equation is balanced as written, with one mole of HBrO₃ reacting with one mole of LiOH to produce one mole of water and one mole of LiBrO₃.
What type of bond would form between two atoms of phosphorus?
A. Triple covalent bond
B. Single ionic bond
C. Double covalent bond
D. Single covalent bond
Answer: Option (A) is the correct answer.
Explanation:
Non-metals are the substances which tend to gain electrons from a donor atom in order to attain stability.
For example, atomic number of phosphorous is 15 and its electronic distribution is 2, 8, 5.
As it contains 5 valence electrons electrons therefore, it needs 3 more electrons in order to attain stability.
Hence, when one phosphorous atom combines with another phosphorous atom then it results in sharing of electrons. So, there will be formation a triple bond between the two phosphorous atoms.
Also, there will be one lone pair of electron on each phosphorous atom.
Thus, we can conclude that triple covalent bond would form between two atoms of phosphorus.
The mineral enargite is 48.41% cu, 19.02% as, and 32.57% s by mass. what is the empirical formula of enargite?
which element does not contain neutrons
iron
carbon
oxygen
hydrogen
How much energy is required to vaporize 185 g of butane at its boiling point? the heat of vaporization for butane is 23.1 kj/mol?
Approximately 73.5 kJ of energy is required to vaporize 185 g of butane at its boiling point.
Explanation:The amount of energy required to vaporize a substance can be calculated using the formula Q = n * ΔHvap, where Q is the amount of energy required, n is the number of moles of the substance, and ΔHvap is the heat of vaporization. To calculate the number of moles of butane, we divide the mass of butane by its molar mass. Using the given heat of vaporization for butane (23.1 kJ/mol), we can calculate the amount of energy required. First, we calculate the number of moles of butane:
n = 185 g / 58.12 g/mol = 3.18 mol
Next, we calculate the amount of energy required:
Q = 3.18 mol * 23.1 kJ/mol ≈ 73.5 kJ
Therefore, approximately 73.5 kJ of energy is required to vaporize 185 g of butane at its boiling point.
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Sodium is an atom represented as na+. what does the "+" represent?
The '+' in Na+ represents a positive charge which indicates that the sodium atom has lost one electron and has become a sodium cation with more protons than electrons.
Explanation:The "+" in a sodium atom represented as Na+ signifies that the atom has lost an electron and, therefore, has a net positive charge. In its neutral state, a sodium atom has 11 protons and 11 electrons, giving it no overall charge. However, when a sodium atom loses an electron, as in the case of the sodium cation (Na+), it then has one more proton (11) than electrons (10), resulting in an overall positive charge, which is indicated by the plus sign. This positively charged sodium is referred to as a sodium cation.
Sodium cations are common in many chemical reactions and play significant roles in biological systems, such as in nerve impulse transmission and muscle contraction. The propensity for sodium to lose an electron and form a Na+ cation is due to the energy consideration that it's easier for sodium to lose one electron from its outermost shell than to gain seven more in order to fill it.
Jaina just got home from a difficult workout. She is complaining of muscle soreness and cramps. Which waste product of fermentation caused the soreness and cramps?
At 7 degrees Celsius the volume of gas is 49 liters. At the same pressure its volume is 74 mL at what temperature
What are the concentrations of hydrogen ion and hydroxide ion in household ammonia, an aqueous solution of nh3 that has a ph of 11.50?
Note: hydrogen ion concentration = 3.16 x 10⁻¹² M
hydroxide ion concentration = 3.16 x 10⁻³ M
pH NH₃ = 11.50
Asked: concentrations of hydrogen ions and hydroxide ions in household ammonia?
Answer: pH (NH₃) = 11.50.
pH = -log [H⁺]
[H⁺] = 10∧ (-pH)
[H⁺] = 10∧ (-11.5)
[H⁺] = 3.16 · 10⁻¹² M
[H⁺] x [OH⁻] = 10⁻¹⁴ M²
[OH⁻] = 10⁻¹⁴ M² ÷ 3.16 x 10⁻¹² M
[OH⁻] = 0.00316 M = 3.16 x 10⁻³ M
Thus, the concentration of hydrogen ions and hydroxide ions in household ammonia is 3.16 · 10⁻³M
Further ExplanationIn chemistry, concentration is a measure that describes the amount of substance in a mixture divided by the total volume of the mixture. There are four kinds of quantitative descriptions of concentration, namely mass concentration, molar concentration, total concentration, and volume concentration. The term concentration can be applied to all types of mixtures, but it is most often used to describe the amount of solute in the solution. Molar concentrations have variations such as normal concentration and osmotic concentration.
Solution Concentration
Concentration is a way to express the quantitative relationship between solute and solvent. Expressing the concentration of the solution there are several types, including:
1. MOL FRACTION
The mole fraction is the ratio between the number of moles of a component with the number of moles of all components contained in a solution.
The mole fraction is denoted by X.
2. PERCENT WEIGHT
Percent weight states the gram weight of the solute in 100 grams of solution.
3. MOLALITY (m)
Molality states the mole of solute in 1000 grams of solvent.
4. MOLARITY (M)
Molarity states the number of moles of solute in 1 liter of solution.
5. NORMALITY (N)
Normality represents the number of moles equivalent of solute in 1 liter of solution. For acids, 1 mole is equivalent to 1 mole of H + ions. For bases, 1 mole is equivalent to 1 mole of OH- ion.
Between Normality and Molarity there is a relationship:
N = M x valence
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Grade: College
Subject: Chemistry
keywords: concentration
Which of the following statements is true?
A. Delocalized electrons conduct electricity poorly.
B. There is a strong attraction between positively charged metal ions and the sea of electrons.
C. Metals with a delocalized electron sea break apart when struck instead of bending.
D. Metals have high melting points and low boiling points.
Answer: B. There is a strong attraction between positively charged metal ions and the sea of electrons.
Explanation: Delocalized electrons conduct electricity with high potentil as the electrons are not localized in on place. Thus statement A is wrong.
Metals with a delocalized electron sea doesnot break apart when struck instaed of bending. Thus statement C is also wrong.
Metals donot have high melting point rather they have low melting point.
Statement B is true as there is a strong attraction beween positively charged metal ions and the sea of electrons.
Write a balanced half-reaction for the reduction of dichromate ion cr2o−27 to chromium ion cr 3 in basic aqueous solution. be sure to add physical state symbols where appropriate.
Explanation:
When electrons are added in a reaction then it means reduction is taking place. Whereas removal of electrons from a chemical reaction is known as oxidation.
Oxidation state of chromium in [tex]Cr_{2}O^{2-}_{7}[/tex] is +6. So, its reduction half-reaction will be as follows.
[tex]Cr_{2}O_{7}^{2-} + 3e^{-1} \rightarrow Cr^{3+}[/tex]
Since it is given that reaction is taking place in basic solution. So, we add [tex]H_{2}O[/tex] on reactant side and [tex]OH^{-}[/tex] on the product side.
[tex]Cr_{2}O_{7}^{2-} + 3e^{-1} + H_{2}O \rightarrow Cr^{3+} + OH^{-}[/tex]
Now balancing Cr atom and charges on both sides, we get the following.
[tex]Cr_{2}O_{7}^{2-} + 6e^{-1} + 7H_{2}O \rightarrow 2Cr^{3+} + 14OH^{-}[/tex]
The balanced half-reaction for the reduction of dichromate ion Cr2O2−7 to chromium ion Cr3+ in basic aqueous solution is:
Cr2O2−7(aq) + 14 OH−(aq) + 6 e− → 2 Cr3+(aq) + 7 H2O(l)
What's the reaction about?Balance the chromium atoms. There are 2 chromium atoms on the left side and 2 on the right, so the equation is already balanced for chromium.
The final balanced equation is:
Cr2O2−7(aq) + 14 OH−(aq) + 6 e− → 2 Cr3+(aq) + 7 H2O(l)
The physical state symbols are also included in the balanced equation. The dichromate ion and the chromium ion are aqueous, the hydroxide ions are aqueous, and the water molecules are liquid.
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how many molecules of dinitrogen pentoxide are in 1.39 moles of dinitrogen pentoxide
Explanation:
According to Avogadro's number, it is known that there are [tex]6.023 \times 10^{23}[/tex] atoms present in 1 mole of a substance.
Therefore, molecules or atoms present in 1.39 moles will be as follows.
No. of atoms = no. of moles × Avogadro's number
= [tex]1.39 moles \times 6.023 \times 10^{23}\text{atoms/mol}[/tex]
= [tex]8.37 \times 10^{23}[/tex] atoms
Thus, we can conclude that there are [tex]8.37 \times 10^{23}[/tex] atoms of dinitrogen pentoxide in 1.39 moles.
Calculate the equilibrium constant for the reaction between fe2+(aq) and zn(s) under standard conditions at 25∘c.
The equilibrium constant for the reaction between Fe2+(aq) and Zn(s) under standard conditions at 25∘C is equal to 1.
Explanation:The equilibrium constant for the reaction between Fe2+(aq) and Zn(s) under standard conditions at 25∘C can be calculated by using the formula:
Kc = ([Fe2+]/[Zn])
Since Fe2+ is an aqueous ion and Zn is a solid, their concentrations are not included in the equation. Therefore, the equilibrium constant is equal to 1.
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The equilibrium constant for the reaction between Fe²+(aq) and Zn(s) at 25°C is approximately 7.06 x 10¹⁰.
Step-by-Step Explanation:
1. Write the overall balanced redox reaction:
Fe²⁺(aq) + Zn(s) → Fe(s) + Zn²⁺(aq)2. Determine the standard reduction potentials (E°) for each half-reaction:
Fe²⁺(aq) + 2e⁻ → Fe(s), E° = -0.44 V Zn²⁺(aq) + 2e⁻ → Zn(s), E° = -0.76 V3. Calculate the standard cell potential (E°cell):
E°cell = E°cathode - E°anode = (-0.44 V) - (-0.76 V) = 0.32 V4. Use the Nernst equation to relate E°cell to the equilibrium constant (K):
E°cell = (RT/nF) * ln(K)Where R = 8.314 J/(mol·K), T = 298 K, n = 2 (number of electrons transferred), F = 96485 C/mol.
5. Rearrange and solve for K:
0.32 V = (8.314 J/(mol·K) * 298 K / (2 * 96485 C/mol)) * ln(K) 2477.172 * ln(K) = 61870.4 ln(K) ≈ 24.98K = [tex]e^{24.98[/tex] ≈ 7.06 x 10¹⁰Thus, the value of equilibrium constant comes out to be 7.06 x 10¹⁰
List the following compounds in decreasing electronegativity difference. cl2 hcl nacl
The decreasing electronegativity difference in the compounds is NaCl > HCl > Cl2. NaCl has the highest electronegativity difference, forming an ionic compound, then HCl forms a polar covalent bond, and Cl2, made of two identical atoms, has no electronegativity difference.
Explanation:The compounds Cl2, HCl, and NaCl possess varying degrees of electronegativity difference depending on the atoms involved. Electronegativity is the ability of an atom to attract shared electrons in a bond. In NaCl (sodium chloride), the electronegativity difference is very high as it consists of a metal (sodium) and a non-metal (chlorine).
This forms an ionic compound, which is generally formed when there is a high electronegativity difference. On the other hand, Cl2 (chlorine gas) possesses no electronegativity difference as it is a molecule composed of two identical atoms. Finally, HCl (hydrogen chloride) has a considerable but not extreme electronegativity difference because it consists of two non-metals. This forms a polar covalent bond.
In summary, the decreasing electronegativity difference would be: NaCl > HCl > Cl2.
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How many helium atoms are in a 12.0 g sample?
Answer: The number of helium atoms present are [tex]18.066\times 10^{23}[/tex]
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of helium = 12.0 g
Molar mass of helium = 4 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of helium}=\frac{12.0g}{4g/mol}=3mol[/tex]
According to mole concept:
1 mole of an element contains [tex]6.022\time 10^{23}[/tex] number of atoms.
So, 3 moles of helium will contain = [tex]3\times 6.022\times 10^{23}=18.066\times 10^{23}[/tex] number of atoms.
Hence, the number of helium atoms present are [tex]18.066\times 10^{23}[/tex]
To find the number of helium atoms in a 12.0 g sample, convert the grams into moles using the molar mass of helium (4 g/mol), then multiply the number of moles by Avogadro's number (6.022 x 10^23). The result is approximately 1.807 x 10^24 helium atoms.
Explanation:To calculate the number of helium atoms in a 12.0 g sample, you need to use Avogadro's number, which states that one mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.). Molar mass of helium is approximately 4 g/mol. So first, we need to convert the number of grams into moles.
12.0 g / 4 g/mol = 3 moles of helium.
To find out how many atoms this is, we multiply the number of moles by Avogadro's number:
3 moles * 6.022 x 10^23 atoms/mole = 1.807 x 10^24 helium atoms.
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What volume of chlorine is required to produce 25.4?
Write the balanced chemical equation for the reaction of the weak acid hcn with water. include the phase of each species.
The weak acid HCN reacts with water through acid ionization, forming hydronium ions and cyanide ions. This reaction can be represented with the balanced chemical equation: HCN(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CN⁻(aq).
Explanation:
The weak acid HCN (hydrogen cyanide) reacts with water through a process called acid ionization. In this reaction, a hydrogen ion (H+) is transferred from the weak acid to a water molecule, leading to the formation of hydronium ions (H3O+), and the cyanide ion (CN-). The balanced chemical equation outlining this reaction is:
HCN(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CN⁻(aq)
In this equation, the (aq) annotation indicates that the species is in the aqueous - or water - phase, while (l) indicates the liquid phase for water.
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What concentration of the lead ion, pb2+, must be exceeded to precipitate pbf2 from a solution that is 1.00×10−2 m in the fluoride ion, f−? ksp for lead(ii) fluoride is 3.3×10−8 ?
Answer is: concentration of Pb²⁺ must be exceeded is 3.3·10⁻⁴ M.
Chemical reaction : Pb²⁺(aq) + 2F⁻(aq) → PbF₂(s).
Ksp(PbF₂) = 3.3·10⁻⁸.
c(F⁻) = 0.01 M.
Ksp(PbF₂) = c(Pb²⁺) ·
c(F⁻)².
c(Pb²⁺) = Ksp(PbF₂) ÷ c(Cl⁻)².
c(Pb²⁺) = 3.3·10⁻⁸ ÷ (0.01 M)².
c(Pb²⁺) = 0.000000033 M³ ÷ 0.0001 M².
c(Pb²⁺) = 0.00033 M = 3.3·10⁻⁴ M.
The concentration of Pb²⁺ must be exceeded is 3.3 × 10⁻⁴ m.
Ksp value of PbF₂ = 3.3 × 10⁻⁸
Concentration of fluoride ion = 1.00 × 10⁻²
It is required to calculate the concentration of lead ion.
What is a solubility product?
The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution.
A chemical reaction between lead ion and fluoride ion occurs as
Chemical reaction :
Pb²⁺(aq) + 2F⁻(aq) → PbF₂(s).
Ksp(PbF₂) = 3.3 × 10⁻⁸
Ksp(PbF₂) = c(Pb²⁺) · c(F⁻)²
c(Pb²⁺) = Ksp(PbF₂) ÷ c(Cl⁻)²
c(Pb²⁺) = 3.3×10⁻⁸ ÷ (0.01 m)²
c(Pb²⁺) = 0.000000033 m³ ÷ 0.0001 m²
c(Pb²⁺) = 0.00033 m = 3.3·10⁻⁴ m
Hence, the concentration of Pb²⁺ must be exceeded is 3.3 × 10⁻⁴ m.
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A compound is found to contain 49.5% carbon, 5.19% hydrogen, 16.5% oxygen, and 28.9% nitrogen. its molecular mass is 194.2 g/mol. what is its empirical formula? what is its molecular formula? explain what each of these formulas tells us about the molecule. (lesson 6)