Answer:
K = 6.02 × 10⁻¹⁹ J
Explanation:
The momentum (p) of an electron is its mass (m) times its speed (v).
p = m × v
v = p / m = (1.05 × 10⁻²⁴ kg.m/s) / 9.11 × 10⁻³¹ kg = 1.15 × 10⁶ m/s
We can find the kinetic energy (K) using the following expression.
K = 1/2 × m × v²
K = 1/2 × 9.11 × 10⁻³¹ kg × (1.15 × 10⁶ m/s)²
K = 6.02 × 10⁻¹⁹ J
An automotive research facility is testing a new design on bumpers to determine the force at which it will break. The formula for Force is F = 1 2 m v 2 Where m is the mass (weight) and v is the velocity (speed)What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?
What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?
Same
Twice as much
Four times as much
Five times as much
Three 1.2 ohm lamps are connected in series and connected to a 3 volt battery. Calculate the total current in the circuit
Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open, has the same frequency as the second harmonic of pipe
a. how long are (a) pipe a and (b) pipe b? (take the speed of sound to be 343 m/s.)
The intensity of the sun's radiation incident upon the earth is about i=1.4kw/m2. suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. what is the total solar power p absorbed by the panels?
which formula represents Snell's law
Snell's law is used for refraction of light
it is used to find the relation between refractive index of two medium and angle of incidence and angle of refraction.
As per this formula
[tex]n_1 sin\theta_i = n_2 sin\theta_r[/tex]
here [tex]n_1[/tex] = refractive index of first medium
[tex]n_2[/tex] = refractive index of second medium where light go after refraction
[tex]\theta_i[/tex] = angle of incidence
[tex]\theta_r[/tex] = angle of refraction
Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The length of daylight in the Arctic and Antarctic circles is 24 hours. The sun’s vertical rays are striking either 23.5°S or 23.5°N.
Answer: Days and nights are equal in length everywhere.
Explanation:
Equinox means equal night. There are two equinox - vernal equinox and autumnal equinox. When the sun crosses celestial equator, the sun rays fall directly over equator at noon. Thus, there is equal length of day and night in the two hemisphere. It occurs around March 22 and September 22.
Two long parallel wires carry currents of 20 a and 5.0 a in opposite directions. the wires are separated by 0.20 m. what is the magnitude of the magnetic field midway between the two wires?
The magnitude of the magnetic field midway between two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m is 4.5 x 10⁻⁵ T.
Explanation:To find the magnitude of the magnetic field midway between the two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m, we can use the formula for the magnetic field due to a long straight wire. The magnitude of the magnetic field at a distance r from the wire is given by: B = (μ₀ * I) / (2π * r). Since we are looking for the magnetic field midway between the wires, the distance from each wire to the point is half of the total separation, which is 0.10 m. Plugging in the values, we get: B = (4π * 10⁻⁷ T·m/A * (20 A + 5.0 A)) / (2π * 0.10 m) = 4.5 x 10⁻⁵ T.
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The magnitude of the magnetic field midway between two parallel wires carrying currents of 20 A and 5 A in opposite directions and separated by 0.20 m is 3 * 10^-6 T.
Explanation:To find the magnitude of the magnetic field midway between the two wires, we can use the formula for the magnetic field produced by a long straight wire:
B = (μ0 * I) / (2πr)
where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. In this case, we have two wires with currents of 20 A and 5 A, and they are separated by 0.20 m. Since we are interested in the magnetic field midway between the wires, the distance r will be half of the separation between the wires, which is 0.20 m / 2 = 0.10 m.
Plugging in the values, we get:
B = (4π * 10-7 T·m/A * (20 A - 5 A)) / (2π * 0.10 m) = (4 * 10-7 T·m/A * 15 A) / (0.20 m) = 3 * 10-6 T
So, the magnitude of the magnetic field midway between the two wires is 3 * 10-6 T.
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How many new elements (fission fragments, or daughter nuclei) are typically presented as a result of fission?
1
3
2
5
What is the resistance of a resistor if the potential differences across the resistor is 4v when a cirrent of 10 a flow through the resistor?
What is the pressure of the gas in this mercury manometer if h = 63 mm and atmospheric pressure is 773 mmhg?
How many photons per second are emitted by the antenna of a microwave oven if its power output is 1.00 kw at a frequency of 2515 mhz?
To determine the number of photons emitted per second by the antenna of a microwave oven, we need to use the formulas for energy per photon and number of photons.
Explanation:The number of photons emitted by the antenna of a microwave oven can be calculated using the formula:
Number of photons = (Power output / Energy per photon) x frequency
To find the energy per photon, we can use the formula:
Energy per photon = Planck's constant x frequency
Given that the power output is 1.00 kW and the frequency is 2560 MHz, we can convert these values to SI units and calculate the number of photons emitted per second.
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Approximately 6.01 x 10²⁶ photons per second are emitted by the antenna of the microwave oven.
To determine the number of photons emitted per second by a microwave oven, we can use the formula:
Number of Photons per Second (N) = Power Output (P) / Energy per Photon (E)
Given:
Power Output (P) = 1.00 kW (or 1000 W)Frequency (f) = 2515 MHz (or 2.515 x 10⁹ Hz)First, find the energy per photon (E) using the equation:
E = h * f
where h is Planck's constant (6.626 x 10⁻³⁴ Js) and f is the frequency.
Substitute the values:
E = 6.626 x 10⁻³⁴ Js * 2.515 x 10⁹ Hz
E = 1.665 x 10⁻²⁴ J
Next, calculate the number of photons per second:
N = P / E
N = 1000 W / 1.665 x 10⁻²⁴ J
N ≈ 6.01 x 10²⁶ photons per second
Therefore, the antenna of the microwave oven emits approximately 6.01 x 10²⁶ photons per second.
How does natural selection result in adaptations in a species
Light of wavelength 600 nm illuminates a diffraction grating. the second-order maximum is at angle 39.5 ∘. part a how many lines per millimeter does this grating have?
The number of lines per millimeter that the grating has is : ≈ 530 lines
Given data :
light wavelength = 600 nm
second order maximum angle ( x ) = 39.5°
order of maximum = 2
Determine the number of lines the grating will haveWe will apply diffraction equation
[tex]d*sinx = m*wavelength[/tex] --- ( 1 )
where : d = spacing of lines, x = 39.5°, m = 2
Insert values into equation ( 1 ) above
d * Sin ( 39.5 ) = 2 * 600 * 10⁻⁹
therefore ; d = 1.88656 * 10⁻⁶ m
Final step : determine the number of lines per mm
Number of lines per mm
= 0.001 / d
= 0.001 / (1.88656 * 10⁻⁶ ) ≈ 530 lines
Hence we can conclude that The number of lines per millimeter that the grating has is ≈ 530 lines
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which step makes proteins by binding amino acids together
A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. what is the highest frequency associated with this portion of the spectrum? (c = 3.00 × 108 m/s)
The highest frequency associated with the portion of the electromagnetic spectrum ranging from 200 nm to 400 nm is 7.50 × 10^14 Hz.
Explanation:The highest frequency associated with the portion of the electromagnetic spectrum ranging from 200 nm to 400 nm can be determined using the formula c = fλ, where c is the speed of light. In this case, the wavelength is given as 200 nm to 400 nm. Converting the wavelength to meters, we find that it corresponds to 2.00 × 10-7 m to 4.00 × 10-7 m. Using the formula, we can rearrange it to solve for the frequency, f = c/λ. Plugging in the values, we get the highest frequency as 7.50 × 1014 Hz.
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Which lists the amplitudes of sound waves from these sources in order from greatest to least?
busy roadway, kids whispering, average home
chainsaw, diesel truck, rustling leaves
kids whispering, vacuum cleaner, jet airplane
library, conversational speech, music from speaker
The correct answer is option B which is a chainsaw, diesel truck, rustling leaves.
Explanation:The amplitude of the sound wave is the maximum displacement of the particles from their resting position.Higher the amplitude means high sound.So the sound of a chainsaw is high, so its amplitude will be great and after that the amplitude of diesel truck is high and rustling leaves have the lowest amplitude.Answer:
B
Explanation:
Edge :)
What's the pressure and temp of 6694 meters high
Assume that you have two objects, one with a mass of 10 kg and the other with a mass of 18 kg, each with a charge of −0.027 c and separated by a distance of 9 m. what is the electric force that these objects exert on one another? answer in units of n.
Final answer:
Using Coulomb's law, the electric force between two objects with charges of – 0.027 C each and separated by 9 m is 81 N. The force is repulsive since the charges are alike.
Explanation:
To calculate the electric force between two objects using Coulomb's law, one needs to know the charges on the objects and the distance separating them. Coulomb's law is represented by the formula F = k * |q1 * q2| / r2, where F is the force between the charges, k is Coulomb's constant (9.0 × 109 N·m2/C2), q1 and q2 are the amounts of the charges, and r is the distance between them.
In this case, with both objects having a charge of – 0.027 C and separated by a distance of 9 m, the electric force F is calculated as follows:
F = (9.0 × 109 N·m2/C2) * |(– 0.027 C) * (– 0.027 C)| / (9 m)2
Since the charges are like charges, the force will be repulsive and we can ignore the negative sign for the purposes of calculating magnitude:
F = (9.0 × 109 N·m2/C2) * (0.027 C * 0.027 C) / (81 m2) = 9.0 × 109 * 0.000729 / 81 = 8.1 × 101 N
Thus, the electric force between the two objects is 81 N acting to push them apart.
When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.10 ev . part a what is the maximum kinetic energy of the photoelectrons when light of wavelength 295 nm falls on the same surface? emax =?
which form of energy is involved in weighting fruit on a spring scale ?
When a rocket is traveling toward a mountain at 100 m/s, the sound waves from this rocket's engine approach the mountain at speed v. if the rocket doubles its speed to 200 m/s, the sound waves from the engine will now approach the mountain at speed?
Answer:
The sound waves from the engine will approach the mountains at the same speed, no matter if the speed of the rocket is 100m/s or 200 m/s.
Explanation:
The sound wave is a property of the air, which means that the speed of the object producing sound does not matter to the sound of the waves, that is, they are always going to be the same.
So the sound waves from the engine will approach the mountains at the same speed, no matter if the speed of the rocket is 100m/s or 200 m/s.
Calculate the quantity of energy produced per gram of reactant for the fusion of h-3 (atomic mass = 3.016049 amu) with h-1 (atomic mass = 1.007825 amu) to form he-4 (atomic mass = 4.002603 amu).
The energy produced per gram of reactant for the fusion of H-1 with H-3 to form He-4, can be calculated using the difference of total initial and final masses, which is then used in Einstein's mass-energy equivalence principle (E=mc²). The number of such reactions in 1 gram of reactant is used to convert the energy per reaction to energy per gram of reactant.
Explanation:To calculate the energy produced per gram of reactant in fusion reaction, first let's understand what's happening in the fusion reaction of H-3 with H-1. A helium nucleus is formed with a mass that is 0.7% less than that of four hydrogen nuclei. This mass loss is converted into energy.
The masses of the reactants are 3.016049 u for H-3 and 1.007825 u for H-1, giving us a total initial mass of 4.023874 u. The mass of the helium atom produced, He-4, is 4.002603 u. The mass loss during the reaction equals initial mass minus final mass, which is 0.021271 u.]
Applying Einstein's mass-energy equivalence principle E=mc², where E is energy, m is the lost mass and c is the speed of light, the energy produced in the reaction, can be calculated. To convert amu to kilograms, multiply by 1.66054 x 10⁻²⁷. So, the mass lost is 3.53 x 10⁻²⁹ kg.
As speed of light c = 3 x 10^8 m/s, using the equation we get E = 3.53 x 10⁻²⁹ kg x (3 x 10⁸m/s)² = 3.18 x 10⁻¹²Joules.
Finally, to get the energy per gram, we calculate the number of such reactions in 1 gram of reactants. That would be (1 g)/(4.023874 g/mol) x Avogadro's number (6.02 x 10^23). Multiply this number with the energy produced per reaction to get the energy produced by 1 gram of reactant.
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The most common natural fiber found at a crime scene, and thus forensically insignificant (unless it is of a unique color)
What are three benefits of being assertive and what are three tips to help you develop an assertive style of communication? (Site 1)
¿Cuál es la velocidad promedio de un hombre que camina 70m con una rapidez de 1m/s y luego corre 70m con una rapidez de 3m/s?
What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes
1. Which of the following statements about mechanical waves is true?
a. mechanical waves require a medium to travel through
b. mechanical waves do not have amplitude and wavelength
c. mechanical waves do not have frequency
d. mechanical waves can travel through blank space
2. Which waves have the shortest wavelength and highest energy on electromagnetic spectrum?
a. microwaves
b. x-rays
c. infrared
c. gamma rays
3. What is true about infrared and X-Rays?
a. X-Rays have greater longer wavelength than infrared
b. Infrared have shorter wavelength than x-rays
c. x-rays have lower energy than infrared
d. Infrared have lower frequency than x-rays
4. In a longitudinal wave (compression wave_ the particles of a matter move ______
a. perpendicular (at right angles)
b. in a circular direction
c. backwards
d. parallel
5. In regard to spend of sound, sound travels slowest in ____
a. solids
b.liquids
c. gases
Mechanical waves require a medium to travel, gamma rays have the highest energy and shortest wavelength on the electromagnetic spectrum, x-rays have higher frequency than infrared, particles in a longitudinal wave move in parallel, and sound travels slowest in gases.
Explanation:1. The correct statement about mechanical waves is 'a. mechanical waves require a medium to travel through'. Unlike electromagnetic waves, mechanical waves, such as sound or seismic waves, need a medium like air, water, or solids to propagate or move.
2. The waves with the shortest wavelength and highest energy on the electromagnetic spectrum are 'c. gamma rays'.
3. The true statement about infrared and X-Rays is 'd. Infrared has lower frequency than x-rays'. X-rays have a higher frequency and shorter wavelength compared to infrared waves, which directly impacts their energy levels, with X-rays having higher energy.
4. In a longitudinal wave (compression wave), the particles of matter move 'd. parallel' to the direction of the wave's propagation. This is different from transverse waves where particles move perpendicular to the wave direction.
5. Sound travels slowest in 'c. gases'. Sound waves travel the fastest through solids, slower through liquids, and slowest through gases.
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An elephant can hear sound with a frequency of 15 hz. what is the wavelength of this wave if the speed of sound in air is 343 m/s?
The wavelength of a sound wave with a frequency of 15 Hz and a speed of sound in air of 343 m/s is approximately 22.87 meters.
Explanation:To calculate the wavelength of the sound wave, we can use the formula:
Speed of sound (v) = wavelength (λ) x frequency (f)
Given that the frequency of the sound wave is 15 Hz and the speed of sound in air is 343 m/s, we can substitute these values into the formula to solve for the wavelength:
343 m/s = λ x 15 Hz
Dividing both sides of the equation by 15 Hz, we get:
λ = 343 m/s / 15 Hz = 22.87 meters (rounded to two decimal places)
Therefore, the wavelength of the sound wave is approximately 22.87 meters.
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Many __________ cause poor pupil function more quickly than alcohol does.
A. Pain relievers
B. Antihistamines
C. Tranquilizers
D. Benzodiazepines
Answer:
B. Antihistamines
Explanation:
Whenever you have an allergy, your body creates a chemical called histamines. For a short term treatment against there allergies, you can take antihistamines. However, among the side effects of this treatment is poor pupil function.
So the correct answer is:
B. Antihistamines
At what speed does the classical momentum, p=mv, give an error, when compared with the relativistic momentum, of 1.35 % ?
To calculate the speed at which the classical momentum gives an error compared to the relativistic momentum, we need to find the ratio of the two different momenta. This can be done by solving for the velocity using the given equations and approximations.
Explanation:The classical momentum, p=mv, gives an error when compared with the relativistic momentum. The error can be calculated by finding the ratio of the relativistic momentum to the classical momentum. In this case, the error is 1.35%. To find the velocity at which this error occurs, we need to solve for the velocity using the given equations and approximations.
(a) Find the momentum of a 1.00 × 10⁹ kg asteroid heading towards the Earth at 30.0 km/s.
(b) Find the ratio of this momentum to the classical momentum. (Hint: Use the approximation that y = 1+(1/2)v²/c² at low velocities.)