What is the maximum amount of kcl that can dissolve in 200 g of water? (the solubility of kcl is 34 g/100 g h?

Answers

Answer 1

the answer is 68 g
hope this helps!!

Related Questions

In the reactions of glycolysis, acetyl-coa formation and the citric acid cycle, chemical energy is transferred to the bonds in:

Answers

The energy gets stored in two molecules:
NADH and ATP.

NAD+ recieves an H, and the energy is stored in that bond.
ADP recieves a P (phosphate) and the energy is stored in that bond.

ATP can then be used as an energy source in the cell, but NADH gets used to make more ATP in the oxidative phosphorylation.

A theory which repeatedly fails to confirm the expected predictions:

probably needs to be developed into a law
probably should be discarded
requires more research time
should be maintained indefinitely,

Answers

A theory which repeatedly fails to confirm the expected predictions probably should be discarded. If the given theory is failing once or twice, then the facts and figures can be researched much more to understand the real cause of the error caused. But in case, the theory is again and again fails to confirms the expected predictions, then there is a gap in the facts and figures and the theory being studied and hence it should be discarded.

Answer:

Probably should be discarded.

Explanation:

Will vote brainliest on all questions. I have to do them in a series cause this j e r k moderator seems to not like me.
1. A mountain biker goes for a ride in the desert. The air temperature is 21°C at the start of the ride, but the temperature in the desert will reach a peak of 51°C. The tires on the bike hold 15.6 L of nitrogen gas at a starting pressure of 249 kPa. The tires will burst when the internal pressure (Pb) reaches 269 kPa. Answer the following questions and show your work.
• How many moles of nitrogen gas are in each tire?
• What will the tire pressure be at the peak temperature in the desert?
• Will the tires burst at the peak temperature? Explain.
• To what pressure should the tire pressure be reduced before starting the ride to avoid bursting of the tires in the desert heat? (Assume no significant change in tire volume.)

Answers

1) Data:

T₁ = 21°C

T₂ = 51°C.

V₁ = V₂ = 15.6 L

P₁ = 249 kPa.

Pb = 269 kPa.

Questions:

• n = ?
• P₂ = ?
• Will the tires burst at the peak temperature? Explain.
• To what pressure should the tire pressure be reduced before starting the ride to avoid bursting of the tires in the desert heat? (Assume no significant change in tire volume.)
Pi = ?

2) Formula:

PV = nRT
P₁ / T₁ = P₂ / T₂

3) Solution

i) n

P₁V₁ = nRT ⇒ n = P₁V₁ / [RT₁]

n = 249 kPa × 15.6 liter / [8.314 (liter-kPa / mol-K) × (21 + 273.15K) ] =

n = 1.588 mol

ii) P₂

P₂ = P₁ T₂ / T₁ = 249 kPa (50 + 273.15 K) / (21 + 273.15K) = 273.5 kPa

iii) Tires will burst, since P₂ > Pb

iv) Pi

Pi / T₁ = Pb / T₂

Pi = Pb T₁ / T₂ = 269 kPa (21 + 273.15K) / (50 + 273.15K) = 244.9 kPa

The pressure shoul to be reduced to less than 244.9 kPa before starting to avoid the bursting of the tires in the desert heat.

Using the ideal gas law, the number of moles, final pressure at peak temperature, burst likelihood, and reduced starting pressure before the desert ride can be calculated to ensure the mountain biker's tires do not burst.

To solve these problems involving a mountain biker's tire pressure in the desert, one would use the ideal gas law, which is PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin. Given this equation and the conditions provided, we can make some calculations.

How many moles of nitrogen gas are in each tire?

We are given the initial conditions: pressure (P) = 249 kPa, volume (V) = 15.6 L, and temperature (T) = 21°C. However, we need to convert these to SI units: P in Pa, V in m³, T in K. To calculate n, the number of moles of nitrogen gas in each tire, we rearrange the ideal gas law to n = PV/(RT).

What will the tire pressure be at the peak temperature in the desert?

To find the final pressure, we will assume the volume of the tires and the amount of nitrogen remain constant. We thus use the equation P₁/T₁ = P₂/T₂, where P₁ and T₁ are the initial pressure and temperature, and P₂ and T₂ are the final pressure and temperature.

Will the tires burst at the peak temperature?

By calculating P₂, we can determine whether the final pressure exceeds the burst pressure of 269 kPa.

To what pressure should the tire pressure be reduced before starting the ride to avoid bursting of the tires in the desert heat?

We need to work backwards using the ideal gas law to determine the reduced pressure that will not exceed 269 kPa when at peak temperature conditions.

Sugar cubes are placed in water. how will the mixture be affected by stirring the water, by breaking apart the sugar cubes, or by raising the temperature? each action will increase the speed that the sugar dissolves in the water. each action will increase the solubility of sugar in water. each action will increase the concentration of sugar that eventually is reached in the solution.

Answers

Each action will increase the speed that the sugar dissolves in the water.

if a solution has a hydronium ion concentration of 1x10^-9 m the solution is
a) acidic and has a pH of 5
b) basic and has a pH of 9
c) basic and has a pH of 5
d) acidic and has a pH of 9

Answers

b) basic and has a pH of 9

The acidity or alkalinity of a solution depends upon the hydronium ion concentration and hydroxide ion concentration. If a solution has a hydronium ion concentration of 1x10⁻⁹ m the solution is basic. The correct option is B.

What is pH of a solution?

The pH of a solution is defined as the negative logarithm to the base 10 of the value of the hydronium ion concentration in moles per litre. The pH scale introduced by Sorensen is more convenient in expressing the hydronium ion concentration of a solution.

The pH can be calculated as:

pH = -log [H₃O⁺]

If the concentration of [H₃O⁺] is less than 10⁻⁷ M, then the solution is found to be basic.

Here pH is:

pH = - log [1 x 10⁻⁹]

= 9

So the pH of the solution is 9.

Thus the correct option is B.

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particle will balance the following nuclear equation?

234/91 Pa --> 234/92 U

Answers

The balance equation will be
234/91 Pa --> 234/92 U + a beta particle

An example of it is potassium-40 nucleus. A beta particle has a high-energy and high-speed electron in the radioactive decay. These particles ranges from 0 MeV to 4 MeV. It carry one charge only and it is positively charge, it is called positron.

Answer : Beta particle will balance the following nuclear equation.

Explanation :

The nuclear reaction is,

[tex]^{234}_{91}Pa\rightarrow ^{234}_{92}U+^{-1}_0\beta[/tex]

Beta particle : It forms when a neutron changes into a proton and a high-energy electron.

When the nucleus emits the beta particle, the mass number remains same and the atomic number increases by 1 and the nuclear charge increases by 1.

Hence, the Beta particle will balance the following nuclear equation.

"when a hydrogen atom is covalently bonded to either oxygen"

Answers

Hydrogen Bonds is the strongest Intermolecular Force, its a super Dipole-dipole interaction, only present when hydrogen atom is covalently bonded to either Oxygen, Nitrogen, Or Fluorine (F). This creates a large polarity. Then, the hydrogen interacts with the lone pair of electrons on a nearby Fluorine, Oxygen, or Nitrogen atoms.

You are asked to bring the pH of 0.500L of 0.550 M NH4Cl to 7.00. Which of the following solutions would you use: 12.0 M HCl or 12.0 M NH3? How many drops (1 drop 0.05 mL ) of this solution would you use?
The answer to part one is 12.0 M NH3 but how do you answer the second part?

Thank you

Answers

1 drop is approximately 0.05mL. Since 0.500L of 0.550M NH4Cl contains 0.275mol of substance (calculated by using c=n/V formula), equal amount of substance of NH3 is needed to neutralize this solution (since pH of 7 is neutral solution). Thus, we need 0.0275L of NH3, i.e. around 550 drops.

The ksp of zinc carbonate (znco3 is 1.0 × 10–10. what is the solubility concentration of carbonate ions in a saturated solution at 25°c? 1.4 × 10–5m 7.1 × 10–6m 1.7 × 10–5m 1.0 × 10–5m

Answers

ksp - solubility product constant is equivalent to equilibrium constant, except this constant is used to determine the solubility of ions of a solid in a solution.
ksp is the product of the soluble ions in the compound. Higher the ksp value, higher the degree of solubility.
ZnCO₃ (s) ---> Zn²⁺ (aq) + CO₃²⁻ (aq)
n n
ksp = [Zn²⁺][CO₃²⁻]
In the equation equal amounts of ions Zn²⁺ and CO₃²⁻ ions are soluble.
amount of ions soluble = n
ksp is therefore equal to;
ksp = n x n
ksp = n²
ksp = 1 * 10⁻¹⁰ M
therefore
1 * 10⁻¹⁰ M = n²
n = 1 x 10⁻⁵ M
therefore concentration of CO₃²⁻ = 1 x 10⁻⁵ M

Answer is: 1.0 × 10–5m.
Chemical reaction: ZnCO₃(s) ⇄ Zn²⁺(aq) + CO₃²⁻(aq).
[Zn²⁺] = [CO₃²⁻] = x; equilibrium concentration of zinc cation and carbonate anion.
Ksp = [Zn²⁺] · [CO₃²⁻].
1·10⁻¹⁰ = x².
x = [CO₃²⁻] = √1·10⁻¹⁰.
[CO₃²⁻] = 1·10⁻⁵ M.

What is the total pressure in a 6.00-l flask which contains 0.127 mol of h2(g) and 0.288 mol of n2(g) at 20.0°c?

Answers

Answer: 1.66 atm

Data:

P = ?
V = 6.00 liter
n1 = 0.127 mol of H2(g)
n2 = 0.288 mol of N2(g)
T = 20.0°C

Formula:

PV = n RT

Solution:

1) Conversion of units:

= 20 + 273.15 K = 293.15 K

2) n = n1 + n2 = 0.127 mol + 0.288 mol = 0.415 mol

3) PV = nRT => P = nRT / V

R = 0.0821 atm*liter / (K*mol)

P = 0.415 mol * 0.0821 atm * liter / (K*mol) * 293.15 K / 6 liter = 1.66 atm

Answer: 1.66 atm

Final answer:

The total pressure in a 6.00-L flask with a mixture of 0.127 mol H₂ and 0.288 mol N₂ at 20.0°C is calculated using the ideal gas law PV = nRT. After converting the temperature to Kelvin and determining the total moles of gas, the pressure is found to be approximately 1.68 atm.

Explanation:

To calculate the total pressure in a 6.00-L flask containing 0.127 mol of H₂(g) and 0.288 mol of N₂(g) at 20.0°C, we can use the ideal gas law, which is PV = nRT. Here, P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

First, convert temperature from Celsius to Kelvin: T = 20.0 + 273.15 = 293.15 K.

Next, use R = 0.0821 L·atm/(K·mol), which is the ideal gas constant appropriate when pressure is in atmospheres and volume is in liters.

Combine the moles of gases: total moles (n₂₄₂al) = 0.127 mol H₂ + 0.288 mol N₂ = 0.415 mol.

Then calculated the pressure using the ideal gas law: P = (nRT)/V = (0.415 mol * 0.0821 L·atm/(K·mol) * 293.15 K) / 6.00 L = 1.68 atm (rounded to two decimal places).

The total pressure in the flask at 20.0°C is therefore approximately 1.68 atmospheres.

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He balanced equation for the reaction of acetylene, c2h2, and oxygen in an acetylene torch is 2 c2h2 + 5 o2 → 4 co2 + 2 h2o. in this reaction the number of grams of oxygen required to react with 0.13 g of acetylene is ________.

Answers

Answer: 0.4 g

Explanation:

1) Balanced chemical equation:

2) 2C2H2 + 5 O2 → 4CO2 + 2 H2O

3) mole ratios:

2 mol C2h2 : 5 mol O2

4) Convert 0.13 g C2H2 into number of moles

n = mass in grams / molar mass

molar mass C2H2 = 2 *12g/mol + 2*1 g/mol = 26 g/mol

n = 0.13 g / 26 g/mol = 0.005 mol

5) Set the proportion with the unknown

5 mol O2 x
----------------- = ---------------
2 mol C2H2 0.005 mol C2H2

x = 0.005 mol C2H2 * 5 mol O2 / 2 mol C2H2 = 0.0125 mol O2

6) Convert 0.0125 mol O2 to grams

mass = number of moles * molar mass

molar mass of O2 = 32 g/mol

mass = 0.0125 mol * 32 g/mol = 0.4 g

Answer: 0.4 g

To react with 0.13 g of acetylene, 0.399 grams of oxygen are needed based on the molar masses and the balanced chemical equation 2 C2H2 + 5 O2
ightarrow 4 CO2 + 2 H2O.

To find the number of grams of oxygen required to react with 0.13 g of acetylene, we need to use the balanced chemical equation for the reaction and the molar mass of acetylene (C2H2) and oxygen (O2). The balanced chemical equation is 2 C2H2 + 5 O2
ightarrow 4 CO2 + 2 H2O. First, we calculate the molar mass of acetylene, which is (2 imes 12.01 g/mol for carbon) + (2 imes 1.008 g/mol for hydrogen) = 26.04 g/mol. Next, we determine how many moles of acetylene 0.13 g corresponds to by using the molar mass:

moles of C2H2 = 0.13 g / 26.04 g/mol = 0.00499 mol

According to the balanced equation, 2 moles of C2H2 react with 5 moles of O2. Therefore, for 0.00499 moles of C2H2, the moles of O2 required are (0.00499 mol C2H2 imes 5 moles O2) / 2 moles C2H2 = 0.012475 moles O2.

The molar mass of O2 is (2 imes 16.00 g/mol) = 32.00 g/mol. Now, we'll convert moles of O2 to grams:

grams of O2 = 0.012475 moles imes 32.00 g/mol = 0.399 grams of O2

Therefore, 0.399 grams of oxygen are required to react with 0.13 grams of acetylene.

What does a positive standard reduction potential mean about a given element?

The element is more readily oxidized than hydrogen.

The element is more readily oxidized than most other elements.

The element is more readily reduced than hydrogen.

The element is more readily reduced than most other elements.

Answers

When a positive standard reduction potential is stated, it means that a given element is more readily reduced than most other elements. It measures the ability of a molecule to be negatively charged by taking up new electrons.This only mean that it can easily add electrons than other elements.

The correct statement is " The element is more readily reduced than hydrogen." A hydrogen electrode is always attached to the rod of the element being investigated to obtain the electrode potential. It is called a standard hydrogen electrode, because the conditions are standard with pressure at 1 atm and the concentration of [tex]H^+[/tex] ions at 1M. A positive standard reduction potential means the element's electrode forms its metal ions less readily than hydrogen, which leads to the electrode being reduced by gaining electrons and the potential difference giving a positive value.

At standard pressure the boiling point of an unsaturated nano3(aq) solution increases when

Answers

Missing question:
(1) the solution is diluted with water.
(2) some of the NaNO3(aq) solution is removed.
(3) the solution is stirred.
(4) more NaNO3(s) is dissolved in the solution.
Answer is: (4) more NaNO3(s) is dissolved in the solution.
Unsaturated solution means that more of a substance can be dissolve (in this case sodium nitrate). If more sodium nitrate is dissolved, molality of solution is increased, eo ipso boiling point of solution.

Answer:

Explanation:

A gas has a volume of 111 ml at a temperature of 32°c. What volume will the gas occupy at standard temperature?

Answers

From Charle's law the volume of a fixed mass of a gas is directly proportional to the absolute temperature at constant pressure.
Therefore V = kT where k is a constant
V1/T1=V2/T2
For standard conditions the temperature is 0 degrees celcius;
Thus; V1= 111 ml, T1 = 32 +273= 305 K, V2= ? T2= 273
Hence; 111/305=V2/ 273
V2= (111× 273)/305
= 99.354 ml

The correct answer is that the gas will occupy a volume of approximately 99.53 ml at standard temperature.

To solve this problem, we will use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, provided the pressure remains constant. The formula for Charles's Law is:

[tex]\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \][/tex]

where [tex]$ V_1 $ and $ T_1 $[/tex] are the initial volume and temperature of the gas, and [tex]$ V_2 $ and $ T_2 $[/tex] are the final volume and temperature.

First, we need to convert the given temperatures from Celsius to Kelvin:

[tex]\[ T_1 = 32^\circ C + 273.15 = 305.15 \text{ K} \][/tex]

[tex]\[ T_2 = 0^\circ C + 273.15 = 273.15 \text{ K} \] (standard temperature)[/tex]

Now we can rearrange Charles's Law to solve for [tex]$ V_2 $:[/tex]

[tex]\[ V_2 = V_1 \times \frac{T_2}{T_1} \][/tex]

Substitute the known values into the equation:

[tex]\[ V_2 = 111 \text{ ml} \times \frac{273.15 \text{ K}}{305.15 \text{ K}} \][/tex]

[tex]\[ V_2 = 111 \text{ ml} \times \frac{273.15}{305.15} \][/tex]

[tex]\[ V_2 \approx 111 \text{ ml} \times 0.896 \][/tex]

[tex]\[ V_2 \approx 99.5315 \text{ ml} \][/tex]

However, we must note that the standard pressure is typically considered to be 1 atmosphere (atm), and since the problem does not specify a change in pressure, we assume that the pressure remains constant. Therefore, the final volume at standard temperature and pressure (STP) is:

[tex]\[ V_2 \approx 99.5315 \text{ ml} \][/tex]

But, to be more precise, we should consider that STP is defined as 0°C (273.15 K) and 1 atm, where the molar volume of an ideal gas is 22.414 liters per mole. Since we are not given the moles of gas or the pressure, we will assume that the pressure is 1 atm, and thus the volume will change only due to temperature.

Given that the initial volume is 111 ml, and we have already calculated the ratio of the temperatures, the final volume at STP is:

[tex]\[ V_2 = 111 \text{ ml} \times 0.896 \][/tex]

[tex]\[ V_2 \approx 99.5315 \text{ ml} \][/tex]

Rounding to two decimal places, we get:

[tex]\[ V_2 \approx 99.53 \text{ ml} \][/tex]

However, there seems to be a discrepancy between the initially stated answer of 95.66 ml and the calculated answer of 99.53 ml. To ensure accuracy, let's re-evaluate the calculation:

[tex]\[ V_2 = 111 \text{ ml} \times \frac{273.15 \text{ K}}{305.15 \text{ K}} \][/tex]

[tex]\[ V_2 \approx 111 \text{ ml} \times 0.896 \][/tex]

[tex]\[ V_2 \approx 99.5315 \text{ ml} \][/tex]

a gas at a pressure of 501 kpa

Answers

Use the combined gas law. It's (P1V1)/T1 = (P2V2)/T2.

P1 = 501 kPa, V1 = 5.2 L, T1 = 298 K*; P2 is your unknown, V2 = 7 L, T2 = 372 K*.

*In problems like this, you must always convert Celsius to Kelvin by adding 273 - or 273.15 if you want to be more specific. I used 273.

you should get 465.8387 kPa.

#1: A gas effuses 4.0 times faster than oxygen (O2). What is the molecular mass of the gas?

A. 1.0 g/mol

B. 2.0 g/mol

C. 4.0 g/mol

D. 7.67 g/mol

**not sure... i think it's either B or C... what do u thinK? @Mertsj :),

Answers

From Graham's law of diffusion
R1/R2 = √M2/M1 where R1 and R2 is the rate of diffusion of Oxygen and
unknown gas respectively
M1 and M2 is the molar mass of Oxygen and unknown gas respectively
So R2 = 4 * R1
M1 = 32 and M2 = ?
So we have R1/ 4 R1 = √ x/32
(1/16) = x/32
X = 32 /16 = 2 g/mol

If a gas effuses 4.0 times faster than oxygen (O2), the molecular mass of the gas is 2.0 g/mol.

HOW TO USE GRAHAM LAW OF DIFFUSION?

The molecular mass of a gas can be calculated using Graham's equation of diffusion as follows:

R1/R2 = √M2/M1

Where R1 and R2 are the rate of diffusion of oxygen and unknown gas respectivelyM1 and M2 is the molecular mass of oxygen and unknown gas respectively

Since the gas effuses 4.0 times faster than oxygen;

R1 = ?R2 = 4R1M1 = 32g/molM2 = ?

R1/4R1 = ✓32/M2

(1/16) = x/32

16x = 32

x = 2g/mol

Therefore, If a gas effuses 4.0 times faster than oxygen (O2), the molecular mass of the gas is 2.0 g/mol.

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The empirical formula of a ompound is c2h5 and its formula mass is 58 amu. what is the molecular formula

Answers

the empirical formula of the compound is C₂H₅. Empirical formula is the simplest ratio of whole numbers of components in a compound.
the mass of one empirical unit = (12 x 2) + (1 x 5)= 29
the molecular mass of the compound - 58 a.m.u
the number of empirical units = molecular mass/mass of empirical unit
= 58 / 29 = 2
There are 2 empirical units
Molecular formula - 2(C₂H₅)
therefore molecular formula - C₄H₁₀

SOMEONE PLEASE HELP ME! MEDAL, FAN, AND TESTIMONIAL

K3PO4 + Al(NO3)3 → 3KNO3 + AlPO4

How many moles of potassium nitrate are produced when 2.5 moles of potassium phosphate react?

Round final answers to the tenth position, one place after the decimal. Please remember your units.,

Answers

As we can see the chemical equation is balanced.K3PO4 + Al(NO3)3 → 3KNO3 + AlPO4

So, by principle of conservation of mass when 1 mole of K3PO4 reacts with 1 mol of Al(NO3)3 , it peoduces 3 mol of KNO3 and 1 mol of AlPO4

So, when 2.5 moles of potassium phosphate react and Al(NO3)3 is present in excess , 2.5*3= 7.5 mol of KNO3 is formed

If a particular utility burned 2.90 million tons of coal that was 2.00% sulfur by weight, how many tons of sulfur dioxide was emitted?

Answers

Answer is: 116000 tons of sulfur dioxide was emitted.
Chemical reaction: S + O₂ → SO₂.
m(S) = m(coal) · ω(S).
m(S) = 2,9·10⁶ t · 0,02.
m(S) = 58000 t · 10⁶ g/t = 5,8·10¹⁰ g.
n(S) = m(S) ÷ M(S).
n(S) = 5,8·10¹⁰ g ÷ 32 g/mol.
n(S) = 1,8125·10⁹ mol.
From chemical reaction: n(S) : n(SO₂) = 1 : 1.
n(SO₂) = 1,8125·10⁹ mol.
m(SO₂) = 1,8125·10⁹ mol · 64 g/mol.
m(SO₂) = 1,16·10¹¹ g = 116000 t.

When 0.040 mol of propionic acid, c2h5co2h, is dissolved in 750 ml of water, the equilibrium concentration of h3o+ ions is measured to be 1.84 x 10-3 m. what is ka for this acid?

Answers

Answer is: Ka for propanoic acid is 6,57·10⁻⁵.
Chemical reaction: C₂H₅COOH(aq) + H₂O(l) ⇄ C₂H₅COO⁻(aq) + H₃O⁺(aq).
n(C₂H₅COOH) = 0,04 mol.
V(C₂H₅COOH) = 750 mL = 0,75 L.
c(C₂H₅COOH) = 0,04 mol ÷ 0,75 L.
c(C₂H₅COOH) = 0,053 mol/L = 0,053 M.
[C₂H₅COO⁻] = [H₃O⁺] = 1,84·10⁻³ M = 0,00184 M.
[HCN] = 0,053 M - 0,00184 M = 0,0515 M.
Ka = [C₂H₅COO⁻] · [H₃O⁺] / [C₂H₅COOH].
Ka = (0,00184 M)² / 0,0515 M.
Ka = 6,57·10⁻⁵.

What are the balanced chemical equations for Hydrochloric acid and potassium hydroxide?

Answers

HCl(aq) + KOH(s) --> KCl(aq) + H2O(l)

The balanced chemical equation for the reaction between Hydrochloric acid (HCl) and potassium hydroxide (KOH) is: HCl + KOH → KCl + H₂O.

A student has asked for the balanced chemical equations for Hydrochloric acid and potassium hydroxide. The balanced chemical equation for the reaction between Hydrochloric acid (HCl) and potassium hydroxide (KOH) is:

HCl + KOH → KCl + H₂O

In this neutralization reaction, Hydrochloric acid (a strong acid) reacts with potassium hydroxide (a strong base) to produce potassium chloride (a salt) and water. This type of reaction is typical between acids and bases where the hydrogen ion (H⁺) from the acid combines with the hydroxide ion (OH⁻) from the base to form water.

It contains 36 protons and 48 neutrons. What is its mass number?

Answers

The mass number would be 84.

Which of the following correctly describes the size of meteoroids?

Answers

meteoroids are smaller than comets and asteroids.

Answer:

The correct answer is C. Meteoroids are smaller than comets and asteroids

Explanation: Asteroids go as far as a kilometer in size while meteoroids can be as big as a house. Comets are out of all comparison as they can be up to 80 000 km long.

Molecule: Br2 and Br2.
Is it polar or nonpolar?

Answers

This combination in non polar.

Final answer:

The Br2 molecule is nonpolar because it consists of two identical bromine atoms sharing electrons equally, leading to no permanent dipole moment.

Explanation:

When determining if a molecule such as Br2 is polar or nonpolar, molecular symmetry plays a key role. The molecule Br2 consists of two bromine atoms covalently bonded together. Since both atoms are the same and share electrons equally, the bond between them is nonpolar. Furthermore, because the molecule is made up of only two identical atoms, it has no molecular geometrical complexity that could lead to an uneven distribution of charge. In contrast, molecules like CO2 and H2O have polar bonds, but CO2 is nonpolar due to its linear shape causing the bond moments to cancel, while H2O is polar due to its bent shape and the presence of lone pairs on the oxygen atom which do not allow the bond moments to cancel out.

"what percentage of the solar nebula's mass consisted of elements besides hydrogen and helium gases?"

Answers

Your answer would be 2%

What is the name of the ionic compound CaO?

Answers

name: calcium oxide
obviously since it consists of calcium and oxygen

Final answer:

The ionic compound CaO, composed of calcium and oxygen ions, is named calcium oxide. Calcium typically forms a Ca2+ ion and oxygen forms an O2- ion, resulting in a neutral compound. The naming process is straightforward for binary ionic compounds, using the metal's name and the nonmetal's name with an '-ide' suffix.

Explanation:

The ionic compound CaO is composed of calcium (Ca2+) and oxygen (O2-) ions. In naming ionic compounds, we typically use the name of the metal (calcium) followed by the name of the nonmetal with an '-ide' suffix. So the name of the ionic compound CaO is calcium oxide.

When forming ionic compounds, calcium, which is a group 2 element, will typically lose two electrons to form a Ca2+ ion. Oxygen, being in group 16, will typically gain two electrons to form an O2- ion. The positive and negative charges of these ions balance each other, resulting in a neutral compound.

The naming of other ionic compounds also follows this simple process when dealing with binary compounds – those containing only two elements. For example, Li2S would be named lithium sulfide, since it is composed of lithium ions and sulfide ions. When dealing with transition metals, which can have more than one ionic charge, roman numerals are used to indicate the charge of the metal, e.g., cobalt(III) oxide for Co2O3.

How did john dalton explain a chemical reaction using his atomic theory?

Answers

Hi! Dalton said that the atoms of reactants are rearranged to form new substances as products.

What determines if an element is a solid or liquid at room temperature? this isn't a test question BTW.,

Answers

Two things primarily affect the state of an element at room temperature:

a) the distance between the ions or molecules

b) the extent to which the ions or molecules move

Check my answers?

Which of the following best describes the motion of the particles in a piece of steel?
None are moving
A few are moving
X All are moving (my choice)
Most are moving

Most solids_____
X are dense and difficult to compress (my answer)
are able to flow
are amorphous
have a disorderly structure

Cyrstals are classified into how many different crystal systems?
4
5
6
X 7 (my answer)

Thanks!

Answers

The answers are the following:
1.All are moving
2. are dense and difficult to compress
3. 7

Your answers are correct.

1. All are moving

2. Are dense and difficult to compress

All are correct... 3/3 100%

Help. Please.

Calculate the percent of acetic acid in the vinegar. (The density of vinegar is 1.002 g/ml.) How would I do this?,

Answers

The way you can solve this, is by using this equation to solve for percent acidity:

%acidity = (grams of acetic acid / grams of vinegar) * 100.

Hope this helps!

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