A 0.600 kg mass thrown upward with an initial speed of 75.0 m/s will reach a maximum height of approximately 287.76 meters, ignoring the effects of air resistance. This is determined using the physics formula v² = u² + 2gH (a kinematic equation for motion under gravity).
Explanation:This problem can be solved using the physics concept of motion under gravity. The object is thrown with an initial velocity to reach a maximum height where its velocity becomes zero. In order to find out the maximum height (H) achieved, we can use the kinematic equation: v² = u² + 2gH, where 'v' is the final velocity, 'u' is the initial velocity, and 'g' is the acceleration due to gravity.
Given in the problem, u = 75 m/s (upward direction implies positive value), v = 0 m/s (at maximum height, the final velocity is zero), and g = -9.8 m²/s (downward direction implies negative value).
By substituting these values into the equation, we get 0 = (75 m/s)² + 2(-9.8 m²/s)(H), which yields H = (75 m/s)² / 2(9.8 m²/s) or approximately 287.76 meters.
This means that, ignoring air resistance, an object with a mass of 0.600 kg thrown upward with an initial speed of 75.0 m/s will reach a maximum height of approximately 287.76 meters.
Learn more about Physics of Motion here:https://brainly.com/question/13966796
#SPJ12
HELP!! A car driving down a hill contains many types of energy. DESCRIBE at least 3 types of energy the car has.
1. Kinetic
2. Chemical
3. Potential
What are two examples of common units for each of the above measurements
Density: g/mL, kg/cubic meter
Volume: L, teaspoon
Mass: g, MeV/sq. C
The common units for length, weight, and time in the American system are foot, pound, and second, respectively. In the metric system, the common units for length, weight, and time are meter, kilogram, and second, respectively.
Explanation:In the American system of measurement, the common units for length, weight, and time are foot, pound, and second, respectively. For example, the ton (2240 lb) is a larger unit of weight, the yard (3 ft) is a smaller unit of length, and the minute (60 s) is a smaller unit of time.
In the metric system, the common units for length, weight, and time are meter, kilogram, and second, respectively. For example, the kilometer (1000 m) is a larger unit of length, the gram (0.001 kg) is a smaller unit of weight, and the millisecond (0.001 s) is a smaller unit of time.
Learn more about Units for Measurements here:https://brainly.com/question/18982750
#SPJ3
Which vector should be negative?
any vector whose magnitude is less than 1
a displacement in the direction North
the velocity of a falling object
any vector whose magnitude is greater than 1
Answer:
The velocity of a falling object
Explanation:
The positive X axis is towards right and positive Y axis is towards up, so North direction is positive
A vector with less than 1 magnitude is not negative, because its magnitude may be in between 0 and 1 which is positive vector.
Any vector whose magnitude is greater than 1 is never be a negative vector.
The velocity of a falling object is towards bottom, that is towards negative Y axis. So that vector is negative.
A cheetah can run at a maximum speed 97.8 km/h and a gazelle can run at a maximum speed of 78.2 km/h. If both animals are running at full speed, with the gazelle 96.8 m ahead, how long before the cheetah catches its prey? Answer in units of s.
The cheetah can maintain its maximum speed for only 7.5 s. What is the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape? (After 7.5 s the speed of cheetah is less than that of the gazelle.) Answer in units of m.
(1)
Cheetah speed: [tex]v_c = 97.8 km/h=27.2 m/s[/tex]
Its position at time t is given by
[tex]S_c (t)= v_c t[/tex] (1)
Gazelle speed: [tex]v_g = 78.2 km/h=21.7 m/s[/tex]
the gazelle starts S0=96.8 m ahead, therefore its position at time t is given by
[tex]S_g(t)=S_0 +v_g t[/tex] (2)
The cheetah reaches the gazelle when [tex]S_c=S_g[/tex]. Therefore, equalizing (1) and (2) and solving for t, we find the time the cheetah needs to catch the gazelle:
[tex]v_c t=S_0 + v_g t[/tex]
[tex](v_c -v_g t)=S_0[/tex]
[tex]t=\frac{S_0}{v_c-v_t}=\frac{96.8 m}{27.2 m/s-21.7 m/s}=17.6 s[/tex]
(2) To solve the problem, we have to calculate the distance that the two animals can cover in t=7.5 s.
Cheetah: [tex]S_c = v_c t =(27.2 m/s)(7.5 s)=204 m[/tex]
Gazelle: [tex]S_g = v_g t =(21.7 m/s)(7.5 s)=162.8 m[/tex]
So, the gazelle should be ahead of the cheetah of at least
[tex]d=S_c -S_g =204 m-162.8 m=41.2 m[/tex]
The cheetah catches the prey [tex]\fbox{17.78 s}[/tex] before the gazelle.
The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is [tex]\fbox{40.83 m}[/tex].
Further Explanation:
The speed is the rate of change of the distance and the relative speed is the speed of the one object in respect of another object. If two body moves in same direction then the relative speed in respect of the one body is given by subtract of both speed and it they are moving in opposite direction the relative speed in respect of the one body is given by sum of both speeds.
Given:
The maximum speed of the cheetah is [tex]97.8 km/h[/tex].
The maximum speed of the gazelle is [tex]78.2 km/h[/tex].
The distance between the starting points of cheetah and the gazelle is [tex]96.8 m[/tex].
Concept:
The expression for the position of the cheetah at some time t is:
[tex]{S_1}={v_c}t[/tex] …… (1)
Here, [tex]{S_1}[/tex]the position of the cheetah at some time [tex]t[/tex], [tex]{v_c}[/tex] is the speed of the cheetah and [tex]{S_1}[/tex] is the distance covered at time [tex]t[/tex].
The expression for the position of the gazelle at some time [tex]t[/tex] is:
[tex]{S_2}={S_o}+{v_g}t[/tex] …… (2)
Here, [tex]{S_2}[/tex] the position of the gazelle at some time [tex]t[/tex], [tex]{v_g}[/tex] is the speed of the gazelle, [tex]{S_o}[/tex] is the distance between the starting points of cheetah and the gazelle.
At the time when the cheetah reached the gazelle then [tex]{S_1}={S_2}[/tex].
Equate equation (1) and (2).
[tex]\begin{aligned}{v_c}t&={S_o}+{v_g}t\hfill\\{v_c}t-{v_g}t&={S_o}\hfill\\t\left( {{v_c} - {v_g}}\right)&={S_o}\hfill\\t&=\frac{{{S_o}}}{{\left( {{v_c} - {v_g}} \right)}}\hfill\\\end{aligned}[/tex]
Substitute [tex]97.8 km/h[/tex] for [tex]{v_c}[/tex], [tex]78.2 km/h[/tex] for [tex]{v_g}[/tex] and [tex]96.8 m[/tex] for [tex]{S_o}[/tex] in the above equation.
[tex]\begin{aligned}t&=\frac{{96.8{\text{ m}}}}{{\left( {97.8 - 78.2} \right){\text{km/h}}\left({\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)}}\\&=\frac{{96.8{\text{ m}}}}{{{\text{19}}{\text{.6 m/s}}\left( {\frac{5}{{18}}}\right)}}\\&=17.78{\text{s}}\\\end{aligned}[/tex]
Therefore, the cheetah catches the prey [tex]17.78 s[/tex] before the gazelle.
To calculate the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape we should subtract the distance covered by the cheetah and gazelle in [tex]7.5 s[/tex].
The expression for the distance covered is:
[tex]S = vt[/tex]
Here, [tex]S[/tex] is the distance covered, [tex]v[/tex] is the speed and [tex]t[/tex] is the travel time.
Substitute [tex]97.8 km/h[/tex] for [tex]v[/tex] and [tex]7.5 s[/tex] for [tex]t[/tex] in the above equation.
[tex]\begin{aligned}S&=\left( {97.8{\text{ km/h}}} \right)\left( {\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)\left( {7.5{\text{ s}}} \right)\\&=\left( {97.8{\text{ m/s}}} \right)\left( {\frac{5}{{18}}} \right)\left( {7.5{\text{ s}}} \right)\\&=203.75{\text{m}}\\\end{aligned}[/tex]
Therefore, the distance covered by the cheetah in [tex]7.5 s[/tex] is [tex]203.75 m[/tex].
Substitute [tex]78.2 km/h[/tex] for [tex]v[/tex] and [tex]7.5 s[/tex] for [tex]t[/tex] in the above equation.
[tex]\begin{aligned}S&=\left( {78.2{\text{ km/h}}} \right)\left( {\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)\left( {7.5{\text{ s}}} \right)\\&=\left( {78.2{\text{ m/s}}} \right)\left( {\frac{5}{{18}}} \right)\left( {7.5{\text{ s}}} \right)\\&=162.92{\text{ m}}\\\end{aligned}[/tex]
Therefore, the distance covered by gazelle in [tex]7.5 s[/tex] is [tex]162.92 m[/tex].
The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is:
[tex]\begin{aligned}d&=\left( {203.75 - 162.92} \right){\text{ m}}\\&=40.83{\text{ m}}\\\end{aligned}[/tex]
Therefore, the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is [tex]\fbox{40.83 m}[/tex].
Learn more:
1. Conservation of momentum https://brainly.com/question/7031524.
2. Motion under friction https://brainly.com/question/11023695.
3. Motion under force https://brainly.com/question/4033012.
Answer Details:
Grade: High school
Subject: Physics
Chapter: Kinematics
Keywords:
Cheetah, 97.8 km/h, gazelle, 78.2 km/h, full speed, 96.8 m. ahead, catches, prey, 7.5 s, minimum, ahead, escape, answer, unit, s, m, 40.83 m.
To improve the acoustics in an auditorium, a sound reflector with a mass of 170 kg is suspended by a chain from the ceiling. What is the tension in the chain? Assume that the mass of the chain itself is 8.0 kg.
Remark
Tension is a type of force. In this case the total force is that of the chain and the reflector are both vertical and therefore acted on by gravity.
Step One
Find the total mass
Mass = m = M1 + M2
M1 = 170 kg
M2 = 8.0 kg
m= 178.0
Step Two
Find the tension
m = 178.0 kg
a = 9.81
T = ???
Formula
T = m * a
T = 178 * 9.81
T = 1746 N
Comment
If this seems a little strange to you, remember that you are actually finding the downward force felt by the hook holding up the chain and reflector. That hook is going to experience the weight of both. I think the question used 9.8 rather than 9.81. That's what it did.
Answer
C
Aiden takes 0.10s to throw a baseball, which leaves his hand with a velocity of 49m/s. The balls acceleration is
What should a graph of Force vs. Mass look like to show the direct proportionality between the two? What does the slope of the line represent?
slope= Force/Mass
force is measured in Newtons (N) and mass in kilograms (kg). This means that the units of the slope are N/kg. However a Newton is also equal to one kg*m/s2, so if we divide this by one kg we are left with a slope with units m/s2, which acceleration is measured in!
While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the top of the science building. Determine the distance the bag has traveled after falling for 1.5 seconds assuming it has reach free fall and given the gravitational acceleration of 9.8 m/sec2.
In the experiment of free fall bob released a bag of mass 1 lb
so here we can say that initial speed of the bag is Zero
time taken by the bag to free fall is given as
t = 1.5 s
also the acceleration of free fall is given as
a = 9.8 m/s^2
now we will use kinematics equation here for finding the distance of free fall
[tex]d = v_i * t + \frac{1}{2} at^2[/tex]
[tex]d = 0 + \frac{1}{2}*9.8* 1.5^2[/tex]
[tex]d = 4.9 * 2.25[/tex]
[tex]d = 11.025 m[/tex]
so the bag will fall down by total distance of 11.025 m from its initial released position.
The 1.0 lb bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds, assuming it is in free fall and subject to Earth's gravitational acceleration of 9.8 m/s².
Explanation:To determine the distance the 1.0 lb bag of feathers has traveled after falling for 1.5 seconds, assuming it has reached free fall and is only affected by gravitational acceleration, we can use the formula for the distance covered by an object in free fall:
d = ½ * g * t²,
where g is the acceleration due to gravity (9.8 m/s²) and t is the time in seconds.
Plugging in the values:
d = ½ * 9.8 m/s² * (1.5 s)²
d = ½ * 9.8 * 2.25
d = ½ * 22.05
d = 11.025 meters
Therefore, the bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds.
-What can you say about the snowboarder’s kinetic energy as he moves?
-Similarly, what can you say about the potential energy of the snowboarder?
-Based on your observations, what can you say about your prediction in Parts A and B above concerning the potential and kinetic energy?
Answer:
His kinetic energy increases, potential energy decreases
The sum of kinetic and potential energy is a constant at any instant before he comes to rest.
Explanation:
Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression [tex]\frac{1}{2} mv^2[/tex], so as he moves his kinetic energy increases.
When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.
Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.
mgh+[tex]\frac{1}{2} mv^2[/tex]= Constant
Answer:
Answer:
His kinetic energy increases, potential energy decreases
The sum of kinetic and potential energy is a constant at any instant before he comes to rest.
Explanation:
Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression , so as he moves his kinetic energy increases.
When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.
Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.
Physics Question, Please Help:
Which of the following can you determine from the graph of the force of the sun on a comet?
A) The force increases as the distance decreases.
B) The force is sometimes zero.
C) The force decreases as the distance decreases.
D) The force does not depend on the distance.
From that graph of the force of the sun on a comet, you can see that the force increases as the distance decreases. (A)
Here, we are required to determine the relationship between the force exerted by the sun on a Comet and the distance between the sun and the comet.
From the graph, the force exerted by the sun on the comet increases as the distance between them decreases.
From the graph, it is evident that the slope of the graph is negative.
Although, the slope of the graph is not constant as in the case of linear graphs (equation of a straight line).
However, the positioning of the line joining all points on the graph suggests that the slope of the graph is negative.
Consequently, the parameters ( i.e the force and distance) are inversely proportional to one another.
Therefore, as the force increases, the distance decreases.
Read more:
https://brainly.com/question/20210875
What is the most common mineral in an igneous rock?
What are the three types of sedimentary rocks where you will most likely find fossils?
Usually fossils are formed when a layer of sediment covers dead plants, animals and microorganisms. This makes sedimentary rocks like limestone and shale the best in the formation of fossils.
1.
When driving in rain the road becomes the most slippery:
Just after the rain quits
Right after it starts to rain
After it has rained for 20 minutes
When the wind is blowing at least 25 mph
When driving in rain, the road becomes the most slippery right after it starts to rain.
As the first rainwater hits the road, it mixes with the oil, rubber tire particles, and other gunk on the pavement, forming a very slippery coating on the surface.
After it has rained for a while, a lot of that gunk gets washed away, and most of the slipperiness is just water ... which is pretty slippery on its own, but not as slippery as it is when it has oil and rubber particles in it too.
Briefly describe the history of the metric system as it applies to the meter and how the definition of a meter has changed over time.
Answer and explanation;
In 1670 Gabriel Mouton, Vicar of St. Paul’s Church and an astronomer proposed the swing length of a pendulum with a frequency of one beat per second as the unit of length.
In 1791 the Commission of the French Academy of Sciences proposed the name meter to the unit of length. It would equal one tens-millionth of the distance from the North Pole to the equator along the meridian through Paris.It is realistically represented by the distance between two marks on an iron bar kept in Paris.
In 1889 the 1st General Conference on Weights and Measures define the meter as the distance between two lines on a standard bar that made of an alloy of 90%platinum with 10%iridium.
In 1960 the meter was redefined as 1650763.73 wavelengths of orange-red light, in a vacuum, produced by burning the element krypton (Kr-86).
In 1984 the Geneva Conference on Weights and Measures has defined the meter as the distance light travels, in a vacuum, in 1299792458⁄ seconds with time measured by a cesium-133 atomic clock which emits pulses of radiation at very rapid, regular intervals.
The metric system was first put into practice in 1799, during the French Revolution, when the existing system of measures became impractical for trade and was supplanted by a decimal system based on the kilogram and the meter.
What is metric system?During the French Revolution, the existing system of measures became impractical for trade and was replaced by a decimal system based on the kilogram and the meter, and the metric system was born.
In 1793, the meter was defined as one ten-millionth of the distance from the equator to the North Pole along a great circle, implying that the Earth's circumference is approximately 40000 km.
The meter was redefined in 1799 in terms of a prototype meter bar.
The meter was introduced as a new unit of length, defined as one ten-millionth of the shortest distance between the North Pole and the Equator passing through Paris, assuming an Earth flattening of 1/334.
Thus, this is the history of the metric system as it applies to the meter.
For more details regarding metric system, visit:
https://brainly.com/question/25966695
#SPJ2
A space station has a radius of 200m.
A. What period of rotation is needed to provide an artificial gravity of g at the rim?
For artificial gravity the the position of rim we have to rotate the space station
Due to rotation it will experience centripetal acceleration at the position of rim
Now in order to experience this acceleration to be same as gravity we can say centripetal acceleration must be equal to gravity here
[tex]a_c = g[/tex]
as we know that centripetal acceleration is given as
[tex]a_c = w^2R[/tex]
[tex]a_c = w^2*200 = g[/tex]
[tex]w^2* 200 = 9.8[/tex]
[tex]w = \sqrt{\frac{9.8}{200}}[/tex]
[tex]w = 0.22 rad/s[/tex]
now we know that angular frequency will be related to time period as
[tex]T = \frac{2\pi}{w}[/tex]
[tex]T = \frac{2\pi}{0.22}[/tex]
[tex]T = 28.4 s[/tex]
so it will rotated by time period T = 28.4 s
a train engineer started the train from a standstill and sped up to 5 meters per second, she then rounded a corner at a constant speed. She then sped the train up to 10 meters per second on the next straightaway. Next, the train chugged around another bend at 10 m/sec, and then its speed slowed to 5 meters per second after coming out of the bend. Finally, the train reached the station, and the engineer applied the brakes and brought the engine to a stop. How many times did the train accelerate? Once a carousel is in motion, the constant movement of the carousel horse around the center of the circle can best be described as
The train accelerates four times during its journey, and the examples provided illustrate concepts of acceleration and uniform circular motion as they apply to trains, buses, and rides like the carousel.
The train described in the question undergoes acceleration several times throughout its journey:
When it speeds up from a standstill to 5 m/s.When it increases its speed from 5 m/s to 10 m/s on a straightaway.When it slows down from 10 m/s to 5 m/s after a bend.When it comes to a stop at the station.Overall, the train accelerates a total of four times. On the other hand, uniform circular motion, such as that of a carousel horse moving around the center, involves an object traveling in a circular path at a constant speed. Despite the speed being constant, because the direction is changing, the object is still experiencing a centripetal acceleration towards the center of the circle.
For example 10.2.3 regarding the slow acceleration of trains, we can calculate the train's movement and wheel's angular velocity after 200 revolutions given the wheel radius and angular acceleration. To find out how far the train has moved down the track, we can use the formula for the circumference of a circle (C = 2πr) multiplied by the number of revolutions. To find the final angular velocity, we can use the kinematic equation for rotational motion (ω2 = ω02 + 2αθ), where ω0 is the initial angular velocity (zero in this case), α is the angular acceleration, and θ is the angular displacement (total revolutions times 2π).
The train accelerated twice at two different points in its journey. In the first instance, it accelerated from a standstill to 5 meters per second, and in the second instance, it accelerated from 5 meters per second to 10 meters per second.
Why do atoms bond?
Some atoms are sticky so they stick to other atoms.
They have too many electrons on their inner shell and need to give some away.
They want to fill up their nucleus in order to become stable.
They want to fill up their outer electron shell in order to become stable.
They want to fill up their outer electron shell in order to become stable. All things in life are made from atoms and all atoms want to reside in their lowest energy state because it is most stable. To do so, atom either share, give, or gain electrons to achieve this stability.
If you were standing on the moon and you had a radio signal transmitter, you could send the radio signal to Earth in 1.28 seconds. If radio waves travel at 3.00 X 1018 m/s, what is the distance from the moon to the earth in kilometers?
Answer:
Distance between moon and earth = [tex]3.84*10^{5}km[/tex]
Explanation:
Distance traveled by radio waves = Velocity of radio waves * Time taken by radio waves
Velocity of radio waves = [tex]3*10^{8}m/s[/tex]
Time taken by radio waves = 1.28 seconds
So distance traveled by radio wave = [tex]3*10^{8}*1.28=3.84*10^{8}m[/tex]
Distance between moon and earth = [tex]3.84*10^{8}m[/tex]=[tex]3.84*10^{5}km[/tex]
In electric dryer consumes 6.0×10 6 jewel of energy when operating at 220 V for 30 minutes. During operation the dryer draws a current of approximately?
Final answer:
The electric dryer, which consumes 6.0×10⁶joules of energy at 220 V for 30 minutes, draws an approximate current of 15.15 amperes during operation.
Explanation:
To determine the current drawn by an electric dryer that consumes 6.0×10⁶ joules of energy while operating at a voltage of 220 V for 30 minutes, we use the relationship between power, voltage, and current given by the equation P = IV, where P is power in watts, I is current in amperes, and V is voltage in volts. First, we need to calculate the power used by the dryer. Power is the rate of energy consumption over time, so:
Power (P) = Energy (E) / Time (t)P = 6.0×10⁶ J / (30 * 60 s) = 6.0×10⁶ J / 1800 s = 3333.33 WNext, we can calculate the current using the power:
Current (I) = Power (P) / Voltage (V)I = 3333.33 W / 220 V ≈ 15.15 ATherefore, the electric dryer draws an approximate current of 15.15 amperes during operation.
The current drawn by the electric dryer is approximately [tex]\( {0.00421 \text{ A}} \)[/tex] (or 4.21 mA).
Given:
- Energy consumed [tex]\( E = 6.0 \times 10^6 \)[/tex] joules
- Operating voltage ( V = 220 ) V
- Operating time t = 30 minutes
First, convert the operating time from minutes to seconds:
[tex]\[ t = 30 \text{ minutes} = 30 \times 60 \text{ seconds} = 1800 \text{ seconds} \][/tex]
Next, convert the energy consumed from joules to kilowatt-hours (kWh):
[tex]\[ E_{\text{in kWh}} = \frac{6.0 \times 10^6 \text{ J}}{3600 \text{ s}} \times \frac{1 \text{ kWh}}{3.6 \times 10^6 \text{ J}} \]\[ E_{\text{in kWh}} = \frac{6.0 \times 10^6}{3600 \times 3.6 \times 10^6} \text{ kWh} \]\[ E_{\text{in kWh}} = \frac{6.0}{12960} \text{ kWh} \]\[ E_{\text{in kWh}} \approx 0.000463 \text{ kWh} \][/tex]
Now, calculate the power P in kilowatts (kW):
[tex]\[ P = \frac{E_{\text{in kWh}}}{t_{\text{in hours}}} = \frac{0.000463 \text{ kWh}}{0.5 \text{ hours}} = 0.000926 \text{ kW} \][/tex]
Convert the power from kilowatts to watts (W):
[tex]\[ P = 0.000926 \text{ kW} \times 1000 = 0.926 \text{ W} \][/tex]
Now, use the formula ( P = VI ) to find the current ( I ):
[tex]\[ I = \frac{P}{V} \][/tex]
Substitute [tex]\( P = 0.926 \text{ W} \)[/tex][tex]\( P = 0.926 \text{ W} \)[/tex] P = 0.926 W and [tex]\( V = 220 \text{ V} \)[/tex]:
[tex]\[ I = \frac{0.926}{220} \]\[ I \approx 0.00421 \text{ A} \][/tex]
The current in the circuit shown is 2.0 A.
What is the value of R3?
A) 10 Ω
B) 15 Ω
C) 20 Ω
D) 55 Ω
The value of R3 is A) 10 Ω
Answer:
Resistor R₃ = 10 Ω
Explanation:
It is given that,
Current flowing in the circuit, I = 2 A
Resistors R₁ = 2 Ω
Resistor R₂ = 3 Ω
Voltage, V = 30 V
We have to find the value of R₃. All three resistors are connected in series. In series combination, the current flowing through the all resistors is same. Firstly, calculating equivalent resistance of three resistors as :
[tex]R_{eq}=R_1+R_2+R_3[/tex]
[tex]R_{eq}=2\ \Omega+3\ \Omega+R_3[/tex]
[tex]R_{eq}=5\ \Omega+R_3[/tex]..............(1)
Using Ohm's law : [tex]V=IR_{eq}[/tex]
[tex]30\ V=2\ A\times (5 + R_{3})[/tex]
On solving above equation : [tex]R_3=10\ \Omega[/tex]
Hence, the correct option is (A) " 10 Ω "
Which of these types of rock form near earths surface? Select all that apply.
A. Igneous
B. Sedimentary
C. Metamorphic
A. Igneous
Extrusive igneous rocks cool and solidify quicker than intrusive igneous rocks. They are formed by the cooling of molten magma on the earth's surface.
Sedimentary (sed-uh-MEN-tuh-ree) rocks, unlike the other two kinds of rocks, are formed on or near Earth's surface. They form from sediments eroded from other rocks. The sediments may come from igneous, metamorphic, or other sedimentary rocks.
A car's position in relation to time is plotted on the graph. What can be said about the car during segment B?
A) The car travels for 80 seconds during segment B.
B) The car has come to a stop and has zero velocity.
C) The car is traveling faster during segment B than in segment C.
D) The car is traveling with a constant velocity due to the flat line of the graph.
we know that
the speed is equal to
[tex]speed=\frac{distance}{time}[/tex]
The slope of the line on the graph is equal to the speed of the car
so
during the segment B the slope of the line is equal to zero
that means
the speed of the car is zero
therefore
the answer is the option B
The car has come to a stop and has zero velocity
Option (B) is correct .i.e. the car has come to a stop and has zero velocity.
Further Explanation:
According to the theory of graphs, ‘the straight line parallel to x axis’ means the quantity given on y axis is not changing or is constant with respect to the change in the quantity on x axis. This is why because the slope of that particular straight line is zero.
Concept:
Mathematically, the slope is defined as the tangent (trigonometry) of the angle made by the segment with the x axis or it is also defined as the ratio of change in the quantity on y-axis to change in the quantity on x-axis.
[tex]\boxed{\text{slope}=\tan(\theta)}[/tex]
Here, [tex]\theta[/tex] is the angle made by the segment of graph with x-axis
The slope can also be expressed as:
[tex]\boxed{\text{slope}=\dfrac{\text{change in quantity given on y-axis}}{\text{change in quantity given on x-axis}}}[/tex]
Here, the quantity given on y axis is car’s position and that given on x axis is time taken by the car to travel.
The slope of position-time graph gives velocity. So, by the definition of slope, we have
[tex]{\text{velocity}=\dfrac{\text{change in position}}{{\text{change in time}}}[/tex]
Here, as shown in the graph, the two ends of the segment B have same values of position on y axis. So, change in position will be zero.
Substitute [tex]0[/tex] for [tex]\text{change in position}[/tex] in above expression.
[tex]\text{Velocity}=0\text{ m/s}[/tex]
This shows that the speed of the car in the segment B of the graph will be zero as there is no change in the position of the car with respect to time.
Thus, option (B) is correct .i.e. the car has come to a stop and has zero velocity.
Learn More:
1. A highway patrolman traveling at the speed limit is passed by a car https://brainly.com/question/2456051
2. Head-on collision of the two bodies https://brainly.com/question/2097915
Answer Details:
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords:
Position, car, relation to time, segment B, 80 sec, zero velocity, travelling, faster, graph, position vs time, constant velocity, slope, change in position, change in time.
The decomposition of water into hydrogen gas h2 and oxygen gas o2 can be moldled by the balanced chemical equation
If you had a positive 8 score on the sit-an-reach test you
Answer:you are very flexible
Explanation:
That’s a very high score.
If you drag a sled across the ground, the sled experiences what kind of friction?
A. Kinetic friction
B. rolling friction
C. static friction
D. cohesive friction
Answer: The correct answer is option A.
Explanation:
Kinetic friction is defined as the frictional force acting between the two objects in contact. It resists the motion of one object over the other.
Rolling friction is defined as the frictional force which acts on the rolling object.
Static friction is the frictional force that keeps an object at rest.
Cohesive friction is defined as the frictional force that hold the particles together.
We need to drag a sled across the ground, so the frictional force is acting between two objects. Here, one object is sled and other is the ground. So, in order to move the sled, it must overcome kinetic friction.
Hence, the correct option is A.
Your car is initially at rest when your hit that gas and the car begins to accelerate. The forward force on the car is 2830 N while the resisting forces total 130 N. The car has a mass of 1830 kg and the acceleration lasts for 2.8 s. What is the final speed of the car and how much ground does it cover during this acceleration?
The final speed of the car is 4.131 m/s and it covers 5.78 m during this acceleration .
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given that: The forward force on the car is 2830 N while the resisting forces total 130 N.
Net force acting on the car is = 2830 N - 130 N = 2700 N.
The car has a mass of 1830 kg.
The acceleration of the car is = force/mass = 2700 N / 1830 m/s^2
= 1.475 m/s^2.
The acceleration lasts for 2.8 s.
Hence, the final speed of the car is = 1.475 m/s^2 × 2.8 s = 4.131 m/s.
Hence, it covers during this acceleration = (acceleration × time²)/2
= ( 1.475 × 2.8²)/2 m.
= 5.78 m.
Learn more about acceleration here:
brainly.com/question/12550364
#SPJ3
Which of these experiments would make use of quantitative data?
A
A study of the different amounts of time it takes water to evaporate completely
B
A study of the effects of sunlight on the color of construction paper
C
A study of the differences in cloud shapes on three successive days
a ) study of the different amounts of time it takes water to evaporate completely.
i always end up helping u <3 lol
Answer: A . A study of the different amounts of time it takes water to evaporate completely
Explanation:
The quantitative data can be define as the property or parameter which can be measured in units and counted in numbers. It can be represented in symbols, units and number code.
A is the correct option this is because of the fact that time can be measured in seconds, minutes and hours. Thus different amounts of time it takes water to evaporate completely can be a approach to conduct the experiment using quantitative data.
Four students are comparing vectors and scalars. The chart contains each students statements about vectors and scalars
In summary, vectors are quantities with both magnitude and direction, and their addition and multiplication by scalars follow specific rules. Scalars are quantities with only magnitude and are added by simple arithmetic. The correct option for any statement about vectors and scalars would be the one that accurately reflects these properties
To provide a solution to the question, we need to understand the key differences between vectors and scalars as described by the students in the chart. Here are the typical characteristics that distinguish vectors from scalars:
1. Magnitude and Direction: Vectors have both magnitude and direction, whereas scalars have only magnitude. This is the fundamental difference between the two. For example, velocity is a vector quantity because it describes both the speed (magnitude) and the direction of motion, while speed alone is a scalar quantity.
2. Representation: Vectors are often represented by arrows, where the length of the arrow corresponds to the magnitude and the arrowhead indicates the direction. Scalars are typically represented by a number with units, if applicable.
3. Addition: When adding vectors, both their magnitudes and directions must be considered, which often involves geometric construction or trigonometric calculations. In contrast, scalar addition is straightforward and involves simply adding the numerical values.
4. Multiplication by a Scalar: Multiplying a vector by a scalar changes the magnitude of the vector but not its direction. The result is a vector that is parallel to the original vector.
5. Dimensionality: Vectors can be one-dimensional (straight line), two-dimensional (plane), or three-dimensional (space). Scalars are zero-dimensional, as they are just single values without direction.
6. Physical Quantities: Examples of vector quantities include displacement, velocity, acceleration, and force. Examples of scalar quantities include mass, temperature, energy, and time.
Based on these characteristics, the students' statements can be analyzed to determine if they are correct or incorrect. For instance, if a student says that a vector has only magnitude, this statement is incorrect because vectors must have both magnitude and direction.
To solve the question accurately, we would need to see the specific statements made by each student in the chart. However, without the actual statements, we can only provide a general explanation of the differences between vectors and scalars.
In summary, vectors are quantities with both magnitude and direction, and their addition and multiplication by scalars follow specific rules. Scalars are quantities with only magnitude and are added by simple arithmetic. The correct option for any statement about vectors and scalars would be the one that accurately reflects these properties."
If a 0.200-kilogram ball sits on a shelf 2.00 meters from the floor, how much mechanical energy (me) does it possess? More than 3.92 j exactly 3.92 j less than 3.92 j cannot be determined because kinetic energy cannot be calculated
Answer:
Mechanical energy = 3.92 J
exactly 3.92 j
Explanation:
As we know that mechanical energy is sum of kinetic energy and potential energy of the system
so here we can say that mechanical energy is sum of kinetic energy of ball and its potential energy
Since ball is at rest so kinetic energy of the ball must be ZERO
Now for potential energy we know that
[tex]U = mgh[/tex]
now we know
m = 0.2 kg
h = 2 m
now for potential ene'rgy
[tex]U = (0.20)(9.8)(2)[/tex]
[tex]U = 3.92 J[/tex]
so mechanical energy is given as
Mechanical Energy = 3.92 + 0 = 3.92 J
Answer:
b
Explanation:
What part of a tidal power plant is the tidal water pushed through to generate electricity a.Turbine b.Barrage c.Boat d.Dam
a. Turbine
The turbine converts the kinetic energy of falling water into mechanical energy.
Answer : Turbine is used to generate electricity in tidal power plant.
Explanation :
In tidal power plant, the kinetic energy of moving water is used to generate electricity. It is one of the renewable source of energy.
The turbine is a part of the tidal power plant which is used to generate electricity. It is kept on the floor of the sea where there is a very strong tidal flow.
The turbines used in tidal power plant is very expensive as compared with the wind turbines.
Hence, the correct option is (a) " turbine ".
When the amount of water in a river increases so much that the river overflows its channel, a flood occurs.True or false
That's true, and there are also other mechanisms that can also create floods.