Answer:
Limiting reactant is H2.
Excess reactant is O2.
Maximum 5.6 mol of H2O can be produced.
Explanation:
2H2 + O2 ----> 2 H2O
from reaction 2 mol 1 mol
given 5.6mol 4.7mol
calculated 5.6mol 2.8 mol
We can see that for 5.6 mol H2 only 2.8 mol O2 needed, but we have 4.7 mol O2 given, so we have excess of O2.
Then limiting reactant is H2.
Excess reactant is O2.
2H2 + O2 ----> 2 H2O
from reaction 2 mol 2 mol
given 5.6 mol x mol = 5.6 mol
Final answer:
The maximum number of moles of H₂O that can be produced from 5.6 mol H₂ and 4.7 mol O₂ is 5.6 mol H₂O, with hydrogen (H₂) as the limiting reactant and oxygen (O₂) as the excess reactant.
Explanation:
To answer the question of the maximum number of moles of H₂O that can be produced from the reaction of 5.6 mol H₂ and 4.7 mol O₂, we must first look at the balanced chemical equation for the reaction which is 2H₂ + O₂ ightarrow 2H₂O. From this equation, we can see that every 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water.
Now, let's see if we have enough of each reactant:
Hydrogen: 5.6 moles H₂ is available
Oxygen: 4.7 moles O₂ is available
According to the stoichiometry of the equation, oxygen will run out first since 4.7 moles of oxygen can react completely with (4.7 times 2) = 9.4 moles of hydrogen. But only 5.6 moles of hydrogen are available, which is less than 9.4 moles, so actually, hydrogen will limit the reaction.
Thus, the limiting reactant is hydrogen (H₂) and the excess reactant is oxygen (O₂). The maximum number o2f moles of water that can be produced is therefore equal to the moles of hydrogen available, which is 5.6 moles of H₂, resulting in 5.6 moles of H₂O being produced.
Consider the equation ; N₂ + 3 H₂ → 2 NH₃ What is the mole ratio of hydrogen to ammonia (NH₃)?
1. 1:1
2. 1:2
3. 3:2
4 5:4
Answer:
3. 3:2
Explanation:
in the reactants, 3 is the coefficient for the hydrogen atoms.
In the products, 2 is the coefficient for the ammonia atoms.
The diagram shows a pump. Which labels can replace
X and the Y in the diagram?
X: potassium, Y: sodium
X: sodium, Y potassium
X: sodium, Y: calcium
X: calcium, Y: potassium
Answer: The Answer is B. X: Sodium, Y: Potassium
Explanation: No Explanation I just Guessed. Hope This Help's Someone
Answer:
The answer is
X:Sodium Y:Potassium
Explanation:
I took the course and got it right
A neutral solution has a pH =
When a solution is basic, the pH is always greater than
When a solution is basic, the pOH is always less than
Answer:
7.
Explanation:
A neutral solution has a pH=7.
A basic solution has a pH>7.
An acidic solution has a pH<7.
Answer:
7,7,7
Explanation:
Which element will have the following property in the periodic table 1)Largest atomic size 2) Highest electron affinity 3) lowest ionisation enthalpy in group II 4) gaseous form at room temperature
In the periodic table, Francium has the largest atomic size, Chlorine has the highest electron affinity, Barium has the lowest ionization enthalpy in Group II, and gaseous elements at room temperature include noble gases and some non-metals like Fluorine and Oxygen.
The periodic table organizes elements in such a way that we can predict their properties based on their position. These properties, including atomic size, electron affinity, and ionization enthalpy, show clear patterns or trends within the table. As a tutor from the Brainly platform, let's address the specific properties asked in the question.
The element with the largest atomic size is typically found at the bottom left of the periodic table. Francium (Fr) is generally considered to have the largest atomic radius because it belongs to Group 1 and is the heaviest alkali metal. The atomic size increases down a group and decreases across a period from left to right.Highest electron affinity is generally observed in halogens. Chlorine (Cl), being very eager to gain an electron to achieve a noble gas electron configuration, has one of the highest electron affinities.The element with the lowest ionization enthalpy in Group II is expected to be at the bottom of the group. Barium (Ba), being at the lower part of Group II, has lower ionization energy compared to its counterparts up the group.Gases at room temperature from Group II are notable as they are non-existent; however, elements that are in gaseous form at room temperature from the periodic table include the noble gases such as Radon (Rn), Xenon (Xe), Krypton (Kr), Argon (Ar), Neon (Ne), Helium (He), and some non-metals like Fluorine (F), Chlorine (Cl), Oxygen (O), Nitrogen (N), and Hydrogen (H).If 35 mL of 0.10 Macid solution is neutralized by 21.8 mL of a basic solution, what is the molarity
of the base? MaVa = MbVb
How many moles of O_{2} molecules are present in a 0.301 L sample of dry air at 0.0395 atm and 23.8 °C? (Oxygen constitutes 20.94% of the molecules in dry air.) (Enter your answer using either standard or scientific notation. For scientific notation, 6.02 x 10^{23} is written as 6.02E23.)
To determine the number of moles of O2 molecules in the given sample of dry air, we need to use the ideal gas law equation PV = nRT. We are given the pressure (P), volume (V), and temperature (T) of the sample, and we can calculate the number of moles (n) of oxygen molecules.
Explanation:To determine the number of moles of O2 molecules in the given sample of dry air, we need to use the ideal gas law equation PV = nRT. We are given the pressure (P), volume (V), and temperature (T) of the sample, and we can calculate the number of moles (n) of oxygen molecules.
First, we need to calculate the partial pressure of oxygen in the air using the percent content in the mixture. Oxygen constitutes 20.94% of the molecules in dry air, so the partial pressure of oxygen (PO2) is calculated as PO2 = (Patm) X (percent content of oxygen). Given that the atmospheric pressure (Patm) is 0.0395 atm, the partial pressure of oxygen is PO2 = (0.0395 atm) X (0.2094).
Once we have the partial pressure of oxygen, we can use PV = nRT to calculate the number of moles of oxygen molecules (n). Rearranging the equation, n = PV / RT, where P is the partial pressure of oxygen, V is the volume of the sample, R is the ideal gas constant, and T is the temperature in Kelvin. Plugging in the values, we get n = (PO2)(V) / (RT).
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NEED HELP WITH CHEM :)
What volume of a 3.70 M NaCl solution is needed for a reaction that requires 118 g of NaCl?
Answer:
volume of solution L =0.54 L
Explanation:
Given data:
Molarity of NaCl solution = 3.70 M
Mass of NaCl = 118 g
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/ molar mass
Number of moles = 118 g/ 58.5 g
Number of moles = 2 mol
Now we will calculate the volume from molarity formula:
Molarity = number of moles / volume of solution L
3.70 M = 2 mol / volume of solution L
volume of solution L = 2 mol / 3.70 M
volume of solution L =0.54 L
If 2.87 g of aluminum are reacted with excess copper (II) sulfate and 9.2 g of copper are produced what is the percent yield
92.8 % is the percent yield when 2.87 g of aluminum are reacted with excess copper (II) sulfate and 9.2 g of copper are produced.
Explanation:
Mass of aluminum = 2.87 grams
mass of copper produced = 9.2 grams ( actual yield)
the balanced chemical reaction is given as:
2 Al + 3 CuSO4 ⇒ ( AL2(SO4)3 +3 Cu.
from the reaction it is found that
2 moles of aluminum reacted to give 3 moles of copper
so converting them in to mass.
number of moles of copper in 2.8 grams = [tex]\frac{2.8}{63.4}[/tex]
number of moles = 0.104 moles of copper
atomic mass of aluminum = 26.98 grams/mole
atomic mass of copper = 63.54 grams/mole
From the given data
2.87 grams Al gives 9.2 grams of Cu.
2 moles of aluminum reacted to give 3 moles of copper
0.104 moles of aluminum will give
[tex]\frac{3}{2}[/tex] =[tex]\frac{x}{0.104}[/tex]
2x = 0.132
x = 0.156 moles of Cu will be formed.
Hence theoretical yield should be = 0.156 x 63.54
= 9.91 grams
Percent yield = [tex]\frac{actual yield}{theoretical yield}[/tex] x 100
= [tex]\frac{9.2}{9.91}[/tex] x 100
percent yield = 92.8 % is the yield percent.
Which process is used to determine the concentration of an acid?
Answer:
testing
Explanation:
some scientist somewhere made acid and probably forgot the recipe/ingredients so they kept making it and used plastic to see if it would melt it
For a reaction system at equilibrium, LeChatelier's principle can be used to predict the A) activation energy for the system B) type of bonds in the reactants C) effect of a stress on the system D) polarity of the product molecules
For a reaction system at equilibrium, LeChatelier's principle can be used to predict the "effect of a stress on the system".
Option: C
Explanation:
Le Chatelier's theory can be implemented to forecast a system's behavior due to variations in pressure, temperature, or concentration that will lead in predictable and contested variations in the system adjustments to establish a new state of equilibrium. This means that adding heat to a process would favor the endothermic path of a reaction, because this decreases the amount of heat generated in the system.
Here shift in equilibrium take place when volume increase, the total pressure decreases, which have potential to reverse the reaction, while on increasing pressure of system, the total volume decreases of the gaseous system, which can shift an equilibrium in the direction of the fewer molecules.
For a reaction system at equilibrium, the Le principle can be used to predict the effect of a stress on the system.
The Le principle is an observation about chemical equilibria of reactions. Le principle can be used to predict the effect of a stress like changing concentration of a substance has on a reaction system at equilibrium.
If the concentration of a reaction species is increased at constant Temperature and Volume, the equilibrium system will shift in the direction that reduces the concentration of that substance so we can conclude that the Le principle can be used to predict the effect of a stress on the system.
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11. A wasp lays its eggs on a caterpillar. When the wasp eggs hatch, the larva will eat the caterpillar
and kill it. *
(2 Points)
O
A. Parasitism
O
B. Mutualism
O
C. Commensalism
Answer:
A
Explanation:
That is the only one that makes sense. Parasitism harms the the host while the parasite gains.
how is temperature related to the physical change of a substance ?
Answer: Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.
Explanation:
The reduction potential (E0′) of a substance reflects its tendency to donate or accept electrons. The larger the difference (ΔE0′) between the reduction potentials of the electron donor and the electron acceptor, __________.A) the greater the change in free energy (ΔG0′), and the less energy is releasedB) the closer the substances are on the electron towerC) the more enzymes will be required to catalyze the reaction(s)D) the greater the change in free energy (ΔG0′), and the greater the energy released
Answer:
The greater the change in free energy (ΔG0′), and the greater the energy released
Explanation:
Recall that the change in free energy is given by:
∆G°'= nFE°'
But E° is given by E°acceptor - E°donor
Hence the greater the difference between E°acceptor and E°donor, the greater the value of E° and consequently the greater the value of ∆G° and the energy released.
Note: E°acceptor and E°donor refer to reduction potentials of donor and acceptor
You purchase several rolls of fiberglass insulation and pay extra for installation. Have you purchased a product or a service?
You purchase several rolls of fiberglass insulation and pay extra for installation. This is a service.
What is fiberglass insulation?The majority of homes include fibreglass, an insulation substance made of incredibly thin glass fibres. It is frequently used in two forms of insulation: loose-fill and batts and rolls. Additionally, rigid boards or duct insulation are both options.
In accordance with the U.S. Department of Energy, manufacturers already make medium- and high-density fibreglass batt insulation materials with a little better R-Value than regular batts. Unfinished floors, ceilings, and walls can all be filled with fibreglass. It is set in place between beams, joists, and studs. You purchase several rolls of fiberglass insulation and pay extra for installation. This is a service.
Therefore, fiberglass insulation is a service.
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Carbon-14 is an element which loses exactly half of its mass every 5730 years. The mass of a sample of
carbon-14 can be modeled by a function, M, which depends on its age, t (in years).
We measure that the initial mass of a sample of carbon-14 is 741 grams.
Answer:
[tex]M=741\times (0.5)^{\frac{t}{5730}}[/tex]
Explanation:
by using well known formula for disintegration
[tex]M=M_0\times (0.5)^{\frac{t}{T}}[/tex]
Final answer:
To calculate the original mass of carbon-14 in an artifact aged 10,670 years, given it now contains 8.4 × 10⁽⁻⁹⁾ grams of carbon-14, we use the half-life of carbon-14 (5,730 years) and the formula for exponential decay. The original mass is found to be 33.6 × 10⁽⁻⁹⁾ grams.
Explanation:
The subject of the question involves using exponential decay to calculate the original mass of carbon-14 in an archaeological artifact, taking into account the half-life of carbon-14, which is 5,730 years. Given that a sample now contains 8.4 × 10-9 grams of carbon-14 and its age is 10,670 years, we can calculate the original amount of carbon-14 it contained. To find the original mass of carbon-14, we can use the formula for exponential decay, M = M0(1/2)t/T, where M is the final mass, M0 is the original mass, t is the time elapsed, and T is the half-life of the substance.
Since 10,670 years is exactly two half-lives of carbon-14 (2 × 5,730), we can calculate that the artifact originally contained 8.4 × 10-9 grams × 22 = 33.6 × 10-9 grams of carbon-14.
Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat is absorbed (3) reaction is exothermic (4) reaction is endothermic (5) products have higher enthalpy content than reactants (6) reactants have higher enthalpy content than products A) 1, 3, and 5 B) 1, 3, and 6 C) 2, 4, and 6 D) 2, 4, and 5
Answer:
D) 2, 4, and 5
Explanation:
In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.
If heat is absorbed in a reaction, that reaction is endothermic.
Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.
Answer:
D
Explanation:
How many moles are there in 24.00 g of NaCl
Answer:
The answer to your question is 0.41 moles
Explanation:
Data
moles of NaCl = ?
mass of NaCl = 24 g
Process
To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.
1.- Calculate the molar mass
NaCl = 23 + 35.5 = 58.5 g
2.- Use proportions and cross multiplication
58.5 g of NaCl ------------------- 1 mol
24.0 g ------------------- x
x = (24 x 1) / 58.5
x = 0.41 moles
Heat transfer focuses on transfers between the system and _____
A. accessories
B. universe
C. phases
D. surroundings
A mixture of 8.0 mol Ne and 8.0 mol Xe are at STP in a rigid container. Which of the following statements is TRUE?
A) Both gases have the same average kinetic energy.
B) Both gases contribute equally to the density of the mixture under these conditions.
C) Both gases have the same molecular speed.
D) The mixture has a volume of 22.4 L
E) All of the above are TRUE.
OPTION A. A) Both gases have the same average kinetic energy.
In the given gas mixture of Neon (Ne) and Xenon (Xe) at Standard Temperature and Pressure (STP), both gases only share the same average kinetic energy. However, they do not contribute equally to the mixture's density, they do not share the same molecular speed, and the total volume of the mixture is not 22.4L.
Explanation:The TRUE statement among the options given is A) Both gases have the same average kinetic energy. The average kinetic energy of gas molecules is determined by temperature, not the type of gas, according to kinetic molecular theory. Therefore, since both gases are at the same temperature (Standard Temperature and Pressure, STP), they will have the same average kinetic energy.
B) is incorrect since each gas contributes to the mixture's density based on its own molar mass, and Xenon's molar mass is much greater than Neon's.
Option C is not correct because molecular speed is influenced by molar mass. Neon, having a smaller molar mass, will have a higher average speed than Xenon.
Statement D) is incorrect because according to Avogadro's law, one mole of any gas at STP occupies a volume of 22.4L, and we have a total of 16 moles of gas (8.0 mol of Ne and 8.0 mol of Xe) which will occupy a volume of 16 times 22.4L.
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Chemistry: Gas Laws Problems!
Answer : The final volume at STP is, 1000 L
Explanation :
According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure = 1520 mmHg = 2 atm (1 atm = 760 mmHg)
[tex]P_2[/tex] = final pressure at STP = 1 atm
[tex]V_1[/tex] = initial volume = 500.0 L
[tex]V_2[/tex] = final volume at STP = ?
Now put all the given values in the above formula, we get:
[tex]2atm\times 500.0L=1atm\times V_2[/tex]
[tex]V_2=1000L[/tex]
Therefore, the final volume at STP is, 1000 L
The volume of the gas at STP is [tex]\(1000.0 \, \text{L}\)[/tex].
1. Convert initial pressure to atm:
[tex]\[ P_1 = \frac{1520 \, \text{mm Hg}}{760 \, \text{mm Hg/atm}} = 2 \, \text{atm} \][/tex]
2. Apply the Combined Gas Law:
[tex]\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \][/tex]
Given:
[tex]\[ V_1 = 500.0 \, \text{L} \][/tex]
[tex]\[ P_1 = 2 \, \text{atm} \][/tex]
[tex]\[ P_2 = 1 \, \text{atm} \][/tex]
[tex]\[ T_1 = T_2 \][/tex] (temperature does not change)
Substituting the values, we get:
[tex]\[ \frac{(2 \, \text{atm} \cdot 500.0 \, \text{L})}{T} = \frac{(1 \, \text{atm} \cdot V_2)}{T} \][/tex]
3. Solve for [tex]\(V_2\)[/tex]:
Cross-multiply and solve for [tex]\(V_2\)[/tex]:
[tex]\[ 2 \cdot 500.0 = 1 \cdot V_2 \][/tex]
[tex]\[ V_2 = \frac{2 \cdot 500.0}{1} \][/tex]
[tex]\[ V_2 = 1000.0 \, \text{L} \][/tex]
At room temperature, which answer is the most compressible?
one liter of water, a liquid
one liter of oxygen, a gas
one liter of iron, a solid
one liter of mercury, a liquid
Answer:
i think its 1 liter of oxygen , a gas
Final answer:
One liter of oxygen gas is the most compressible among the options given, due to the significant spaces between gas molecules allowing for easier compression.
Explanation:
When considering the compressibility of various substances at room temperature, gases such as oxygen are the most compressible due to the large spaces between their molecules. In comparison, liquids like water and mercury are less compressible because their molecules are closer together, but they still offer some degree of compressibility. Solids like iron, however, are much less compressible because their atoms are tightly packed in a lattice structure. Of the options provided, one liter of oxygen gas would be the most compressible, as the spacing between gas molecules allows them to be pushed closer together far more easily than molecules in a liquid or atoms in a solid.
Liquid A has a vapor pressure of 7.37 kPa at 40C. Liquid B has a vapor pressure of 18.04kPa at 40C. Which liquid would evaporate faster at 40C? Explain your answer.
Answer:
Liquid B because of its higher vapor pressure due to the fact that evaporation rate is directly proportional to vapor pressure
Explanation:
The vapor pressure of liquid at equilibrium is a function to the liquid's rate of evaporation. The evaporation rate and hence the vapor pressure is a measure of the propensity of the particles of the liquid to leave the surface of the liquid and exist as vapor directly above the liquid. As high evaporation rate leads to high vapor pressure, a liquid with a higher vapor pressure will evaporate faster than one with a lower vapor pressure at the same temperature and pressure.
Therefore, liquid B with a vapor pressure of 18.04 kPa at 40° C will evaporate faster than liquid A with a lower vapor pressure of 7.37 kPa at the same 40°C.
Liquid B with a higher vapor pressure of 18.04 kPa at 40°C would evaporate faster than liquid A with 7.37 kPa, as higher vapor pressure indicates that the liquid is more volatile and its molecules can more easily escape into the gas phase.
Explanation:At 40°C, between liquid A with a vapor pressure of 7.37 kPa and liquid B with a vapor pressure of 18.04 kPa, liquid B would evaporate faster. This is because vapor pressure is a measure of the tendency of molecules to escape from a liquid and enter the gas phase. A higher vapor pressure indicates that molecules can break away from the surface of the liquid more easily, which is indicative of a more volatile liquid. Therefore, liquid B, with its higher vapor pressure at the same temperature, is the more volatile and will evaporate more rapidly than liquid A.
Vapor pressure of a liquid is directly related to its intermolecular forces; liquids with weaker intermolecular forces have higher vapor pressures, and hence they evaporate faster. Conversely, greater intermolecular forces result in a lower vapor pressure and slower evaporation rate. For volatile liquids in a mixture, adding their partial pressures yields the total vapor pressure of the mixture
What volume of water should be used to dissolve 19.6 g of LiF to create a 0.320 M solution?
Answer:
2.4 L
Explanation:
Given data:
Mass of LiF = 19.6 g
Molarity of solution = 0.320 M
Volume of water used = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 19.6 g/ 26 g/mol
Number of moles = 0.75 mol
Volume required:
Molarity = number of moles/ volume in L
0.320 M = 0.75 mol / volume in L
Volume in L = 0.75 mol /0.320 M
M = mol/L
Volume in L = 2.4 L
2. If 6.0g of carbon is heated in air, the mass of the product obtained could be either 22.0g or 14.0g depending on the amount of air present. Show that this verifies the law of multiple proportions.
3. Alaxin, (C5H8)nO5, is a new malaria drug. Determine the molecular formula of alaxin if its relative molecular mass is 284.
(H = 1, C = 12, O = 16)
i dont seem to remeber
2 . The ratio of 1:2 in the mass of second element, oxygen in CO and CO2 verifies the law of proportion.
3. [tex]C_{15}[/tex][tex]H_{24}[/tex][tex]O_{5}[/tex] is the molecular formula of the new malaria drug given.
Explanation:
Balanced chemical reaction:
C + O ⇒ C0
C + O2 ⇒ CO2
law of multiple formulation states that when two elements combine to form a compound the ratio of the mass of elements is a whole number.
Carbon reacts with oxygen to produce:
Mass of carbon mass of oxygen ratio of O in CO2 to O in CO
CO = 12 16 3:4
CO2 = 12 32 3:8
CO 6 gm 8 3:4
CO2 6 16 3:8
The ratio of the mass of the second element i.e oxygen is CO:CO2 is 1:2, hence it shows law of multiple proportions.
3. given,
(C5H8)nO5 = emperical formula
relative molecular mass = 284
molecular formula= ?
The value of n will be calculated as:
(12x5)+ (1x8)n + (16x5) = 284
(60 +8)n + 80 = 284
68n + 80 = 284
68n = 284 - 80
68n = 204
n = 3
Multiplying the emperical formula by n
(C5H8)3O5
[tex]C_{15}[/tex][tex]H_{24}[/tex][tex]O_{5}[/tex] is the molecular formula of the drug.
The formation of different carbon oxide compounds with differing masses of oxygen that combine with a fixed mass of carbon demonstrates the law of multiple proportions with a small whole number ratio. To find the molecular formula of Alaxin, the relative molecular mass is divided by the mass of its empirical formula, yielding a molecular formula of C10H16O10.
Explanation:The law of multiple proportions states that when two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in the ratio of small whole numbers. To verify this with carbon and oxygen, we consider the two cases: carbon dioxide (CO2) and carbon monoxide (CO).
When 6.0g of carbon reacts with oxygen, we can get either 22.0g of carbon dioxide or 14.0g of carbon monoxide. The mass of oxygen that combines with the 6.0g of carbon can be calculated for each compound:
For carbon dioxide: Mass of oxygen = 22.0g (total mass) - 6.0g (carbon) = 16.0gFor carbon monoxide: Mass of oxygen = 14.0g (total mass) - 6.0g (carbon) = 8.0gThe ratio of the mass of oxygen in carbon dioxide to the mass of oxygen in carbon monoxide is 16.0g : 8.0g = 2:1, which is a small whole number ratio, thus verifying the law of multiple proportions.
To determine the molecular formula of Alaxin, given its relative molecular mass is 284:
Calculate the relative molecular mass of the empirical formula (C5H8O5): (12*5) + (1*8) + (16*5) = 60 + 8 + 80 = 148 g/mol.Divide the relative molecular mass of Alaxin by the empirical formula mass to find n: 284 / 148 = 1.92, approximately 2.The molecular formula is (C5H8O5)2, or C10H16O10.
The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224 g of this metal by 71°C.
Answer:
Preceding accumulative aggregate of energy indispensable is disseminated as 5455 J.
Explanation:
Allotted the contiguous information:
Q: Not identified.
M: 224 g
S: 0.343 J/g°C
Final thermodynamics: 71°C
Initial thermodynamics: 0°C
ΔT = 71°C
We can equate as imminent:
Q = 224 g · 0.343 J/g°C · 71°C
Q ⇒ 5455 J
Hence, the pertaining preeminent albeit paramount indispensable consignment or quantity of energy obligated, concerning an augmentation in thermodynamics subject to the undisclosed metal by 71°C is 5,455 J.
The energy required to raise the temperature of the metal is 5365.256 J.
Explanation:To calculate the energy required to raise the temperature of a substance, we use the formula:
q = m * c * ΔT
The energy required to raise the temperature of a substance can be calculated using the formula: q = mcΔT where q is the energy in joules, m is the mass in grams, c is specific heat capacity in J/(g•°C), and ΔT is the change in temperature in °C.
Given that the mass (m) of the metal is 224 g, the specific heat capacity (c) is 0.343 J/(g•°C), and the temperature change (ΔT) is 71°C, you can substitute these values into the formula:
Plugging in the values given:
q = (224 g) * (0.343 J/(g•°C)) * (71°C)
Simplifying the equation gives:
q = 5365.256 J
Therefore, the energy required to raise the temperature of 224 g of this metal by 71°C is 5365.256 J.
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how many moles are in 10.0 grams of sodium hydroxide?
Which word equation shows lithium oxide being formed from the reaction between oxygen and lithium? oxygen + lithium oxide Right arrow. Lithium lithium + oxygen Right arrow. Lithium oxide oxygen + lithium Right arrow. Lithium + oxide lithium oxide Right arrow. Lithium + oxygen
Answer: lithium + oxygen Right arrow. lithium oxide
lithium + oxygen proper arrow. lithium oxide This equation indicates lithium oxide is formed from the reaction between oxygen and lithium.
what is lithium oxide used for?
Lithium oxide is used as a flux in ceramic glazes and creates blues with copper and pinks with cobalt. Lithium oxide reacts with water and steam, forming lithium hydroxide, and needs to be isolated from them.
wherein is Lithium Oxide found?Lithium Oxide is an extraordinarily insoluble thermally stable Lithium source suitable for glass, optic, and ceramic programs. Lithium oxide is a white stable also referred to as lithia, it is produced whilst lithium metallic burns inside the presence of oxygen.
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How many dots should be shown in the Lewis dot diagram of carbon?
1
2
3
4
Answer:
Im 90% sure its 3.
Explanation:
Answer:
4
Explanation:
C. Describe ONE way in which relocation diffusion resulted in the cultural landscapes shown in both photographs.
D. Explain how the cultural landscapes shown in the photographs represent more than one culture,
Answer:
Explanation:
THIS IS THE COMPLETE QUESTION
A)Identify TWO cultural traits shown in one or both of the photographs that are indicative of ethnicity.
B)Describe the process of relocation diffusion.
C)Describe ONE way in which relocation diffusion resulted in cultural landscapes shown in both photographs.
D)explain how the cultural landscapes shown in the photographs represent more than one culture.
EXPLANATION:
A)the two cultural traits shown in the photographs that are indicative of ethnicity are;
1) the torri
2)the logograms
B)The process of relocation diffusion provide an idea as a result of people moving from one place to another especially the adopters, they move from their base to new place.
C)Relocation diffusion resulted in the cultural landscapes that is shown in both photographs just gave the intance of migration process.
for instance, those that migrated to CALI and UK from china came along with their cultural trait too. As well as their custom
D)The cultural landscapes that is shown in the photographs gives the representation of multiple culture through displaying of
architectural styles from different culture.
Cultural landscapes display a linguistic features of more than one languages.
Relocation diffusion contributes to cultural landscapes by introducing new cultural elements through migration. Such landscapes often represent multiple cultures, as both local and migrated cultures can leave their imprint on the environment.
Explanation:Relocation diffusion refers to the spread of a cultural trait by individuals who migrate and carry this trait with them to new locales. For example, when individuals who practice a particular religion migrate to a new location, they might build places of worship resembling those in their homeland, thus altering the cultural landscape of their new locale.
Cultural landscapes can often represent more than one culture because both the local and migrated cultures influence the landscapes. For example, in a cultural landscape where a McDonald's (representing American fast food culture) is situated next to a Buddhist temple (representing Asian religious culture), it is evident that more than one culture is influencing the setting.
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Ozone reacts completely with NO, producing NO2 and O2. A 13.0 L vessel is filled with 1.30 mol of NO and 1.30 mol of O3 at 401.0 K. Find the partial pressure of each product and the total pressure in the flask at the end of the reaction.
Answer:
6.58 atm total
3.29 atm NO2
3.29 atm O2
Explanation:
Balanced equation:
O3 + NO → NO2 + O2
There are equal numbers of moles of both reactants, so neither is in excess and either could be considered the limiting reactant.
( 1.30 mol NO) x (1 mol NO2 / 1 mol NO) = 1.30 mol NO2
( 1.30 mol NO) x (1 mol O2 / 1 mol NO) = 1.30 mol O2
Total pressure by using the formula;
P = nRT / V
= ( 1.30 mol + 1.30 mol) x (0.08205746 L atm/K mol) x (401.0 K) / (13.0 L)
= 6.58 atm
Partial pressure for NO2;
(6.58 atm) x (1.30 mol NO2) / (1.30 mol + 1.30 mol)
= 3.29 atm NO2
Partial pressure for O2
6.58 atm total - 3.29 atm NO2
= 3.29 atm O2
1. The partial pressure of nitrogen dioxide ([tex]NO_2[/tex]) is equal to 3.29 atm.
2. The partial pressure of oxygen gas ([tex]O_2[/tex]) is equal to 3.29 atm.
3. The total pressure in the flask at the end of the chemical reaction is 6.58 atm.
Given the following data:
Volume of flask = 13.0 LitersNumber of moles of NO = 1.30 moles.Number of moles of [tex]O_3[/tex] = 1.30 moles.Temperature = 401.0 K.Scientific data:
Ideal gas constant, R = 0.0821L⋅atm/mol⋅KTo determine the partial pressure of each product and the total pressure in the flask at the end of the chemical reaction:
First of all, we would write a balanced chemical equation for the chemical reaction as follows:
[tex]O_3 + NO \rightarrow NO_2+O_2[/tex]
Since the numbers of moles of reactants are equal, the total number of moles of products is:
[tex]n=1.3+1.3[/tex]
n = 2.6 moles
Now, we can find the total pressure in the flask at the end of the chemical reaction by using the ideal gas law equation;
[tex]PV=n RT[/tex]
Where;
P is the pressure.V is the volume.n is the numbers of moles of gas.R is the ideal gas constant.T is the temperature.Making P the subject of formula, we have;
[tex]P=\frac{nRT}{V}[/tex]
Substituting the parameters into the formula, we have;
[tex]P=\frac{2.6 \times 0.0821 \times 401}{13}\\\\P=\frac{85.597}{13}[/tex]
Total pressure, P = 6.58 atm.
Next, we would determine the partial pressure of each product:
[tex]Molefraction \;of \;a \;substance =\frac{No.\; of \; moles \;of \;substance}{Total \;no. \;of \; moles \;of \;substances}[/tex]
[tex]Molefraction \;of \;a \;substance =\frac{1.3}{2.6} \\\\Molefraction \;of \;a \;substance =0.5[/tex]
For [tex]NO_2[/tex]:
[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]
Partial pressure of [tex]NO_2[/tex] = 3.29 atm.
For [tex]O_2[/tex]:
[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]
Partial pressure of [tex]O_2[/tex] = 3.29 atm.
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