What is the measure of each base angle on an isosceles triangle it it's vertex angle measures 28 degrees and it's 2 congruent sides measure 12 units

Answer:

(2,3)

Step-by-step explanation:

Given : [tex]x + y = 5[/tex]

           [tex]y=\frac{x}{2}+2[/tex]

To find: what point do the lines representing the two equations intersect

Solution:

[tex]x + y = 5[/tex]

[tex]y=\frac{x}{2}+2[/tex]

Plot the lines on the graph

Green line denotes  [tex]x + y = 5[/tex]

Purple line denotes [tex]y=\frac{x}{2}+2[/tex]

So, Intersection point = (2,3)

Refer the attached figure

So, option C is true

Hence Intersection point is (2,3)

On first day the tank had 8000 liters of water.

Half is removed so half of 8000 is 4000.

Subtracting 8000-4000 =4000

So at the end of first day 4000 liters of water is there.

Water in the tank at the end of second day:

Again half of 4000 is removed.

half of 4000 is 2000.

subtracting 4000-2000 =2000.

At the end of second day 2000 l of water is present in tank.

At the end of third day:

Again half of 2000 is removed.

half of 2000 is 1000.

subtracting 2000-1000 =1000.

At the end of third day 1000 l of water is present in tank.

At the end of fourth day:

Again half of 1000 is removed.

half of 1000 is 500.

subtracting 1000-500 =500.

At the end of fourth day 500 l of water is present in tank.

At the end of fifth day:

Again half of 500 is removed.

half of 500 is 250.

subtracting 500-250=250.

At the end of fifth day 250 l of water is present in tank.

At the end of sixth day:

Again half of 250 is removed.

half of 250 is 125.

subtracting 250 - 125 =125.

At the end of sixth day 125 l of water is present in tank.

At the end of seventh day:

Again half of 125 is removed.

half of 125 is 62.5.

subtracting 125-62.5 =62.5.

At the end of seventh day 62.5 l of water is present in tank.

At the end of eighth day:

Again half of 62.5 is removed.

half of 62.5 is 31.25

subtracting 62.5 - 31.25 =31.25.

At the end of eighth day 31.25 l of water is present in tank.

Final answer:

After calculating the expenses, the Choir Booster Club has D. $456.77 left in their budget. This is determined by subtracting the costs of t-shirts, lost uniforms, and the holiday party from their starting budget of $1,300.00.

Explanation:

The Choir Booster Club started the year with a budget of $1,300.00 and spent money on various items. To calculate how much of the budget remains, we need to subtract the costs of the t-shirts, lost uniforms, and the holiday party from the starting budget:

Now, subtract the total expenditures from the starting budget:

$1,300.00 - $225.30 - $482.25 - $135.68 = $456.77 remaining

Therefore, the correct answer is: D. $456.77

Answer: 48 pounds

Step-by-step explanation:

Given: A person who weighs 240 pounds burns 180 calories per mile of running.

There is a direct relation ship between the weight of the person and the calories burn.

If a person burns thirty-six calories by running one mile.

Let x be the weight of the person then

[tex]\frac{x}{36}=\frac{240}{180}\\\Rightarrow\ x=\frac{240\times36}{180}\\\Rightarrow\ x=48[/tex]

The weight of the person is 48 pounds.

Answer:  The correct option is

(C) Rational, because it is a fraction.

Step-by-step explanation:  We are given to choose the best description for the real number 34 over 3.

The given real number can be written as :

[tex]f=\dfrac{34}{3}.[/tex]

We know that

a number of the form [tex]\dfrac{p}{q},~q\neq 0[/tex] is a rational number. That is, a fraction with non zero denominator is a rational number.

Since the given number can be written as a fraction, so it is a rational number.

Thus, option (C) is CORRECT.

Answer:

c

Step-by-step explanation:

Answer:

Step-by-step explanation:

Final answer:

The probability of selecting five defective batteries from a set of seven batteries, five of which are defective, is calculated by multiplying the individual probabilities of each selection. This results in an approximate probability of 0.048.

Explanation:

The probability of selecting all defective batteries from a group where 7 batteries are available and 5 are defective is obtained by calculating the probability of selecting a defective battery five times in a row without replacement.

The probability of the first battery being defective is 5/7, as there are 5 defective out of 7 total. If the first one is defective, there are now 4 defective batteries left out of 6. This makes the probability of the second being defective 4/6. We continue this pattern until we have:

Probability of 1st defective battery = 5/7

Probability of 2nd defective battery = 4/6

Probability of 3rd defective battery = 3/5

Probability of 4th defective battery = 2/4

Probability of 5th defective battery = 1/3

To find the overall probability of all being defective, we multiply these probabilities together:

P(all defective) = (5/7) × (4/6) × (3/5) × (2/4) × (1/3)

When we calculate this, we get:

P(all defective) = (5×4×3×2×1) / (7×6×5×4×3) = 120 / 2520 = 0.0476

Therefore, the probability is approximately 0.048 (rounded to three decimal places).

Answer:

a0 - 8.0

a1 - mean

a2 - 15.7

We have been given that Tina's favorite shade of teal is made with 7 ounces of blue paint for every 5 ounces of green paint and Tyler's favorite shade of teal is made with 5 ounces of blue paint for every 7 ounces of green paint.

We can express the ratio of blue paint to green paint for both Tina as well as Tyler's favorite shades of teal as shown below.

For Tina: [tex]\frac{7}{5}[/tex]

For Tyler: [tex]\frac{5}{7}[/tex]

In order to compare the two ratios, we will have to make the denominators equal. Let us make denominators equal for both these ratios.

For Tina: [tex]\frac{7\cdot7}{5\cdot7}=\frac{49}{35}[/tex]

For Tyler: [tex]\frac{5\cdot5}{7\cdot5}=\frac{25}{35}[/tex]

Therefore, we can see that for equal amount of Green paint, Tina's favorite shade of teal contains [tex]\frac{49}{25}[/tex] times, that is almost twice the Blue paint that Tyler's favorite shade of teal contains.

Tina's favorite shade is more blue than Tyler's

The expression 40t - 16 is factored completely by first identifying the greatest common factor, which is 8, then factoring it out to get the result 8(5t - 2).

To factor the expression 40t - 16 completely, we need to find the greatest common factor (GCF) of the terms. The GCF of 40t and 16 is 8. Therefore, we can factor out 8 from both terms:

40t - 16 = 8(5t) - 8(2) = 8(5t - 2)

So, the completely factored form of the expression 40t - 16 is 8(5t - 2).

Answer: There are 40 times that Mathieu can expect to choose a multiple of 5.

Step-by-step explanation:

Since we have given that

Numbers between 1 to 20 = 20

Numbers which are divisible by 5 = 4

i.e. {5,10,15,20}

So, Probability that getting a number divisible by 5 is given by

[tex]\dfrac{4}{20}=\dfrac{1}{5}[/tex]

If the number of trials = 200

Then, Number of times Mathieu expect to choose a multiple of 5 is given by

[tex]\dfrac{1}{5}\times 200\\\\=40[/tex]

Hence, there are 40 times that Mathieu can expect to choose a multiple of 5.

double x + 3= 2x + 6. double four is 8. 8 * 2x + 6 = 16x + 48