What is the name of solution who’s classification of salute is equal to the maximum concentration

Moles are the number of particles in a given weight. So unless you state the amount of water, aluminum, salt, and baking soda no one can not consider which contain the most moles.

Answer:

Explanation:

Heat = m*c * deltat

m = 20 grams

c = 4.19 J/g*C

deltaT = 30 - 10 = 20

Heat = 20 * 4.19 * 20

Heat = 1676 joules or 1.7 kJ depending on what you need.

Answer:

The correct answer for plato/edmentum is C). 1700 joules

Answer:

B

Explanation:

If the concentration is increased, there are more particles to collide with each other, increasing the rate of the reaction.

The concentration of reactants affect the rate of a reaction by increasing the concentration increasing the collision of molecular frequency.

The reaction rate refers to how quickly the concentration of such a particular reactant as well as product changes during a chemical reaction.

The abundance of an ingredient divided by the volume of a combination is called concentration. Mass concentration, molar concentration, number concentration, as well as volume concentration are all examples of mathematical descriptions.

The concentration of reactants affect the rate of a reaction by increasing the concentration increasing the collision of molecular frequency.

Therefore, the correct answer will be option B

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Answer:

8856joules

Explanation:

Energy= MC. ©

energy = 123.00*1*(97-25)

energy =8856joules//

Answer: The amount of energy required will be 8856 Joules.

Explanation:

To calculate the amount of heat absorbed, we use the equation:

[tex]Q=mc\Delta T[/tex]

where,

Q = heat absorbed or released

m = Mass of the substance = 123 kg

c = specific heat capacity of water = [tex]1J/kg.K[/tex]

[tex]\Delta T[/tex] = change in temperature = [tex](97-25)^oC=72^oC=72K[/tex]  (change remains the same)

Putting values in above equation, we get:

[tex]Q=123kg\times 1J/kg.K\times 72K\\\\Q=8856J[/tex]

Hence, the amount of energy required will be 8856 Joules.

Answer:

Na₂CO₃•H₂O

Explanation:

After it is heated, the remaining mass is the mass of sodium carbonate.

30.2 g Na₂CO₃

Mass is conserved, so the difference is the mass of the water:

35.4 g − 30.2 g = 5.2 g H₂O

Convert masses to moles:

30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃

5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O

Normalize by dividing by the smallest:

0.285 / 0.285 = 1.00 mol Na₂CO₃

0.289 / 0.285 = 1.01 mol H₂O

The ratio is approximately 1:1.  So the formula of the hydrate is Na₂CO₃•H₂O.

Na₂CO₃•H₂O

Given:

Question:

What is the formula for the hydrate?

Problem-solving:

We will solve problems related to The Law of Definite Proportion (Proust's Law).

"The ratio of the masses of elements in each compound is always constant. Put differently, a given compound invariably contains a similar proportion of elements by mass."

The heating reaction of the hydrate of sodium carbonate is as follows:

[tex]\boxed{ \ Na_2CO_3.nH_2O \xrightarrow{\text{heat}} Na_2CO_3 + nH_2O \ }[/tex]

Condition:

[tex]\boxed{ \ Na_2CO_3.nH_2O \xrightarrow{\text{heat}} Na_2CO_3 + nH_2O \ }[/tex]

         35.4 g                 30.2 g       5.2 g

We want to determine the amount of water (with the symbol n) so that the formula for the hydrate can be known.

Recall that [tex]\boxed{ \ Moles = \frac{Mass \ (g)}{Mr} \ }[/tex]

Let us prepare the number of moles of Na₂CO₃ and H₂O respectively.

Finally, we use the mole ratio to write the formula. Find the water-to-anhydrate mole ratio.

[tex]\boxed{ \ Na_2CO_3 \ : \ H_2O = 1 \ : \ n  \ }[/tex]

[tex]\boxed{ \ H_2O \ : \ Na_2CO_3 = n \ : \ 1  \ }[/tex]

[tex]\boxed{ \ n \ : \ 1 = 0.289 \ : \ 0.285 \ }[/tex]

[tex]\boxed{ \ n = \frac{0.289}{0.285} \times 1 \ }[/tex]

Thus, the value of n after rounding is [tex]\boxed{ \ n = 1 \ }[/tex]

Substitute n = 1 into Na₂CO₃•nH₂O.

Therefore, the formula for the hydrate is [tex]\boxed{\boxed{ \ Na_2CO_3.H_2O \ }} [/tex]

Keywords: 35.40 gram, hydrate of sodium carbonate, Na₂CO₃•nH₂O, heating, a constant mass, its final weight, 30.2 g, what is the formula for the hydrate? the law of definite proportion, Proust's law, anhydrate, the mole ratio

Answer:

10 electrons 8 protons

Explanation:

p +8 - e10- equals -2

Explanation:

The total mass is:

100 g + 200 g

= 300 g

The mass of salt is:

0.20 (100 g) + 0.10 (200 g)

= 20 g + 20 g

= 40 g

So the concentration is:

40 g / 300 g

≈ 13.33%

Round as needed.

Answer:

False

Explanation:

Compounds are chemically combined

lemonade is not

If the squeezed lemonade is made by squeezing lemons to extract the juice and mixing it with water and sugar, it would be a homogenous mixture.

If it contains a pulp than it would be heterogeneous

Answer:

Reactivity

Explanation:

The scenario shows that baking soda is reactive enough to produce bubbles with vinegar but not enough to do so in pure water.

Flammability, color change, and boiling point are all wrong.  The scenario says nothing about these properties.

Answer:

Reactivity (Znk Elite Answerer is right)

Explanation:

I just took a test and I got it right. Even if the question says select all that apply there is only 1 answer and it is reactivity

Answer:

This one is easy. It's the Avogadros' Hypothesis or Avogadros' Law, where the equal volumes of gases in SAME conditions have an equal amount of molecules!

Answer:

Avagadro’s law states at constant temperature and pressure, volume is directly proportional to the number of molecules of the gas.

For example  

At STP that is standard temperature and pressure at which T = 273K and P = 1 atm

Volume occupied by 1 mole ([tex]6.022\times 10^{23}[/tex] gas molecules) of any gas is equal to 22.4L

That is

1 mole = 22.4L

2 mole = 44.8 L

3 mole = 67.2 L

So 1 mole of [tex]CO_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)

1 mole of [tex]H_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)

1 mole of [tex]Cl_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)

The temperature 12.17º C rounded to three significant figures is 12.2º C, taking into account the fourth figure which is a 7. This causes an upward rounding due to the rule of significant figures.

To round off the temperature of 12.17º C to three significant figures, we look at the fourth figure which is a 7. Since 7 is greater than 5, we round the third significant figure up, which results in a rounded temperature of 12.2º C.

In the context of rounding based on significant figures, the temperature value is often dependent on the least precise measurement in a data set or calculation. As an example, if we had another measurement of 13.7 kg, which is to the 0.1 decimal place, any resultant calculation would need to be rounded to the tenths place for consistency, giving us a hypothetical final answer of 15.2 kg, to match the precision of 13.7 kg.

Answer:

Explanation:

For any system in equilibrium, the molar concentration of all the species on the reactant side are related to those on the product side by a constant known as the equilibrium constant [tex]K_{eq}[/tex].

For a given reaction:

              aA + bB ⇄ cC

 [tex]K_{eq}[/tex] =   [tex]\frac{[C]^{c} }{[A]^{a} [B]^{b} }[/tex]

The reaction equation is given as:

     [tex]CO_{g}[/tex] + 2H₂[tex]_{g}[/tex] ⇆CH₃OH [tex]_{g}[/tex]

Note: All the species are in gaseous phase.

            [tex]K_{eq}[/tex] = [tex]\frac{[CH_{3}OH ]}{[CO] [H_{2}] }[/tex]

Answer: [tex]K_c=\frac{[CH_3OH]{[CO][H_2]^2}[/tex]

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. It is expressed as [tex]K_{eq}[/tex]

[tex]CO(g)+2H_2(g)\rightarrow CH_3OH(g)[/tex]

The equilibrium constant in terms of concentration is written as :

[tex]K_eq=\frac{[CH_3OH]{[CO][H_2]^2}[/tex]

Thus the correct answer choice is B.

Answer:

An insulated container that measures temperature change is a calorimeter. It is used to calculate change in enthalpy (which is ΔH.)

Explanation:

Enthalpy characterize a system from the energy point of view and it depends on the changes in the temperature of the system, the pressure (which is held constant) and the volume of the system (you know this because is an isolated system. Using a calorimeter is a key step in calculating the enthalpy, let's say for a chemical reaction.

Answer:

A pie chart

Explanation:

A pie chart would be the ideal type of chart to create this visual aid. A pie chart is simpler visually and easily understood. It can show data as portions or percentages of a whole. Since what they want is to present the different gases found in Earth's atmosphere, they can show what percentage of the different gases make up the atmosphere.

It is simpler because the size of each portion or "slice" of the pie chart itself can reveal a lot about the data without even reading the numbers.

Answer:

Pie chart

Explanation:

Answer:

2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction

Explanation:

2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction

Rb is a +1 cation, NO3 is a -1 anion, Be is a +2 cation and F is a -1 anion.

In writing an ionic compound the charge of the cation becomes the subscript of the anion and the charge of the anion becomes the subscript of the cation.  

So the ionic compound formed between Be2+ and F- is BeF2. The ionic compound formed between Be2+ and NO3- is Be(NO₃)₂.  

As there are two NO₃ on the product side it is balanced by writing a 2 coefficient before RbNO₃ on the reactant side.  

And as there are two F on the reactant side it is balanced by writing a 2 coefficient before RbF on the product side.  

Answer:

2RbNO3 + BeF2 → Be(NO3)2 + 2RbF, because Be keeps a 2+ charge throughout the reaction

Answer:

9.02×10⁻¹¹ mol NH₃

Explanation:

Convert nanograms to grams:

1.56 ng NH₃ × (1 g / 10⁹ ng) = 1.56×10⁻⁹ g NH₃

Convert grams to moles:

1.56×10⁻⁹ g NH₃ × (1 mol NH₃ / 17.3 g NH₃) = 9.02×10⁻¹¹ mol NH₃

The answer is 9.02×10⁻¹¹ mol NH₃

Convert nanograms to grams:

1.56 ng NH₃ × (1 g / 10⁹ ng) = 1.56×10⁻⁹ g NH₃

Convert grams to moles:

1.56×10⁻⁹ g NH₃ × (1 mol NH₃ / 17.3 g NH₃) = 9.02×10⁻¹¹ mol NH₃

A mass of a substance in grams is numerically equal to its molecular weight. Example: A gram-mole of salt (NaCl) is 58.44 grams.

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Na2C03 is formed through the reaction of

NaOH and H2CO3 namely sodium hydroxide and carbonic acid

NaOH -> strong base

H2CO3-> weak acid

Answer:

A. a weak acid and a strong base

Explanation:

An acid-base reaction is a chemical reaction between an acid and a base to form salt and water. The reaction is also known as a neutralization reaction.

An acid is a compound that when in aqueous solution it dissociate to form an hydrogen ion(H+).

A base is a compound that when in aqueous solution it produces an hydroxide ion(OH-) .

A strong acid is an acid that completely dissociate in an aqueous solution.

A strong base is a base that completely dissociate in an aqueous solution.

The reaction that produce a salt like sodium carbonate is a chemical reaction between a weak acid and a strong base. The chemical reaction can be represented as follows

H2CO3 + 2NaOH → Na2CO3 + 2H2O

H2CO3 is a weak acid as it partially dissociate in aqueous solution.

NaOH is a strong base as it completely dissociate in aqueous solution.

Answer:

Radiocarbon dating can be used to determine the age of a sample less than 50,000 years old - C

Answer:

Isotopes

Explanation:

We call atoms of the same elements with different mass numbers isotopes.

Answer:

Approximately 0.074 grams.

Explanation:

How does the electroplating works for copper? Copper exists as copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] in the copper(II) nitrate [tex]\rm Cu{(NO_3)}_2[/tex] solution. It takes two moles of electrons to reduce one mole of copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] to metallic copper [tex]\rm Cu[/tex].

[tex]\rm Cu^{2+}\;(aq) + 2\;e^{-} \to Cu\;(s)[/tex]. (Reduction half of the ionic equation.)

Start by finding the charge on the electrons that have been supplied to this electrochemical cell. After that,

For a constant direct current [tex]I[/tex], the charge [tex]Q[/tex] that has been delivered in time [tex]t[/tex] is equal to

[tex]Q = I \cdot t[/tex].

In case

[tex]Q[/tex] will be in Coulombs [tex]\mathrm{C}[/tex] (which is the same as [tex]\mathrm{A\cdot s}[/tex].)

For this electrochemical cell,

[tex]Q = I\cdot t = \rm 0.75\;A \times 300\;s = 225\;C[/tex].

The Faraday's Constant gives the size of charge (in Coulombs) on one mole of electrons.

[tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex].

[tex]\displaystyle n(\mathrm{e^{-}}) = \frac{Q}{F} = \rm \frac{225\;C}{96485.33212\;C\cdot mol^{-1}}\approx 0.00233196\;mol[/tex].

Assume that copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] are in excess. Refer to the reduction half-equation, it takes two moles of electrons to deposit one mole of metallic copper.

[tex]\displaystyle \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \frac{1}{2}[/tex].

[tex]n(\mathrm{e^{-}})=\rm 0.00233196\;mol[/tex]. As a result,

[tex]\displaystyle n(\mathrm{Cu}) = n(\mathrm{e^{-}})\cdot \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \rm 0.00233196\;mol\times \frac{1}{2} = 0.00116598\; mol[/tex].

The Relative atomic mass of copper is [tex]63.546[/tex].

[tex]\begin{aligned}m(\mathrm{Cu})& = n(\mathrm{Cu}) \cdot M(\mathrm{Cu})\\& = \rm 0.00116598\; mol\times 63.546\; g\cdot mol^{-1}\\&\rm \approx 0.074\;g\end{aligned}[/tex].

Final answer:

The mass of copper that can be plated from a 1.0 M Cu(NO3)2 solution using 0.75 A for 5 minutes is calculated by converting the charge passed to moles of electrons, determining the moles of copper, and then converting it to mass, resulting in approximately 0.0740 grams.

Explanation:

To calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes, we apply Faraday's laws of electrolysis and use the molar mass of copper.

Firstly, calculate the total charge passed through the solution using the formula Q = It, where Q is the charge in Coulombs, I is the current in Amperes, and t is the time in seconds. For 0.75 A over 5.0 minutes (or 300 seconds), we obtain Q = (0.75 A) × (300 s) = 225 Coulombs.

Next, convert the charge to moles of electrons using the charge of one mole of electrons, known as Faraday's constant (approximately 96485 C/mol). Thus, moles of electrons = 225 C / 96485 C/mol ≈ 0.00233 mol.

Since the copper plating involves Cu2+ ions gaining two electrons to become copper atoms (Cu2+ + 2e− → Cu), the moles of copper plated will be half the moles of electrons. So, 0.00233 mol / 2 = 0.001165 mol of copper.

Finally, calculate the mass of copper by multiplying the moles of copper by its molar mass (63.55 g/mol for Cu). Thus, mass of copper = 0.001165 mol × 63.55 g/mol ≈ 0.0740 g.

Therefore, the mass of copper that can be plated out using these conditions is approximately 0.0740 grams.

Answer:

[tex]\boxed{\text{ 93 \%}}[/tex]

Explanation:

[tex]\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}[/tex]

Data:

[tex]\begin{array}{rcr}\text{Actual yield} & = & \text{74.3 T}\\\text{Theoretical yield} & = & \text{80 T}\\\end{array}[/tex]

Calculation:

[tex]\text{\% yield} = \dfrac{\text{74.3 T}}{\text {80 T}} \times\text{100 \%} = \textbf{93 \%}}\\\\\text{The percent yield was } \boxed{\textbf{93 \%}}[/tex]

Answer:

-65.897°C.

Explanation:

where, ΔTf is the depression in freezing point of chloroform solution.

Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).

m is the molality of the solution (m = 0.51 m).

∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.

∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.

Answer:

-65.9 and 100.9

Explanation:

Hope this helps

Answer:

Explanation:

Specific heat capacity can be defined as the heat required to raise the temperature of a unit mass of a substance by 1kelvin.

The heat capacity on the other hand, expresses the heat required to raise the temperature of  asubstance by 1kelvin.

When we use specific heat capacity, we are particular about the amount of heat that would be needed to actually cause a temperature change in a unit of a substance. This suggests that even if we don't have a complete substance, we can be sure that by knowing the mass of a unit of a body one can easily estimate how much heat is required to raise its temperature. The specific heat is fundamental in calculating the heat capacity of a body. Without the value of the specific heat, we cannot evalutate the heat capacity of a body.

Answer:

0.0057034 or 5.7034 * 10^-3

Answer:

False

Explanation:

All Arrhenius acids and bases are also Bronsted-Lowry acids and bases.

An Arrhenius base is a compound that dissociates to form hydroxide ions in water.

NaOH(s) → Na^+(aq) +OH^-(aq)

A Bronsted-Lowry base is a proton acceptor.

NaOH is a Bronsted-Lowry base because the hydroxide on can accept a proton from HCl to form water.

Thus, all Arrhenius bases are Bronsted-Lowry bases.

First we look at the chemical reaction:

2 Na + Br₂ → 2 NaBr

number of moles = mass / molecular weight

mass = number of moles × molecular weight

number of moles of Na = 1000 / 23 = 43.48 moles

number of moles of Br₂ = 3000 / 160 = 18.75 moles

from the reaction:

if        2 moles of Na are reacting with 1 mole of Br₂

then   X moles of Na are reacting with 18.75 moles of Br₂

X = (18.75 × 2) / 1 = 37.5 moles of Na

The limiting reactant is bromine Br₂.

After the reaction is complete you remain with Na as excess reagent.

moles of Na = 43.48 - 37.5 = 5.98 moles

mass of Na =  5.98 × 23 = 137.54 g

if        reacting 1 mole of Br₂  produces 2 moles of NaBr

then  reacting 18.75 moles of Br₂  produces Y moles of NaBr

Y  = (18.75 × 2) / 1 = 37.5 moles of NaBr

mass of NaBr = 37.5 × 103 = 3862.5 g

Answer:

Explanation:

Given parameters:

Mass of Na = 1kg = 1000g

Mass of Br = 3kg = 3000g

Unkown:

Limiting reagent =?

Amount of excess reagent = ?

Quantity of NaBr formed = ?

Solution

The reaction equation can be expressed as:

                 2Na + Br₂ → 2NaBr

To find the limiting reagent

The limiting reagent is the reagent that is in short supply and it determines the amount of products that can be formed in the reaction.

To find the limiting the reagent, we establish a mole relationship between the reactants. We then check their stoichoimetric expression to see the one in excess and the limiting reagent.

Number of moles of Na = [tex]\frac{mass of Na}{molar mass of Na}[/tex]

   molar mass is expressed as g/mol and the Na should also be in grams

Number of moles = [tex]\frac{1000}{23}[/tex] = 43.48mol

Number of moles of Br₂ =  [tex]\frac{mass}{molar mass}[/tex]

    Number of moles = [tex]\frac{3000}{2x80}[/tex] = 18.75mol

From the balanced reaction equation:

     2 mole of Na combines with 1 mole of Br₂

     43.48mole of Na would require 43.48/2 mole = 21.74mole of Br₂ to react with.

But the given amount of Br we have is 18.75mole.

Therefore, the reagent in short supply is Bromine. It is the limiting reagent

Quantity of NaBr formed

To find the quantity of NaBr formed, we use the known reagent which is the limiting one to determine its number of moles and eventually the mass. The limiting reagent determines the extent of the reaction.

 From the stoichiometric equation:

          1 mole of Br₂ will produce 2 mole of NaBr

  19.23 mole Br₂ would now yield  (18.75 x2)= 37.5mole  of NaBr

Mass of NaBr = number of moles of NaBr x molar mass of NaBr

Molar mass of NaBr = 23 + 80 = 103g/mol

      Mass of NaBr = 37.5 x 103 = 3862.5g = 3.86Kg

Amount of excess reagent remaining after the complete reaction:

The amount of excess reagent would be derived from the reagent that occurs in excess which is Na:

1 mole of Br₂ reacts with 2 moles of Na

18.75mole of Br₂  will require 2x 18.75 = 37.5mole of Na

Excess mole of Na = (43.48 - 37.5)mole = 5.98mole

Mass of excess Na = number of moles of excess Na x molar mass of Na

Mass of excess Na = 5.98 x 23

Mass of excess Na = 137.54g or 0.14g

Answer:

A. Deposition Occurs

Explanation:

When a gas becomes ionized, deposition occurs.

Answer: Option (D) is the correct answer.

Explanation:

A plasma is defined as the state of matter in which gas exists in hot ionized formed that has similar number of positively charged ions and negatively charged electrons.

Whereas deposition is the change from gaseous to liquid or solid state in which particles come closer to each other.

Sublimation means direct conversion of solid into gaseous phase without undergoing liquid phase.

Thus, we can conclude that when a gas becomes ionized then a plasma is formed.

Answer:

2SO2 + 02 ====>2SO3

Explanation:

SO2 + O2 ===> SO3

The only thing you can do is balance the oxygens that are on the sulfurs. When you do that the oxygen (O2) can make the difference.

SO2 + O2 ===> 2SO3

Bring the oxygen on the right up to 6. When you do that, the sulfurs are out of balance. So balance the sulfurs.

2SO2 + 02 ====>2SO3

Your equation is now balanced. The trick is not to leave the number of oxygens on the right as an odd number. When you fix that problem, the equation will balance easily.

Species           S                 O

Left                  2                  2+4=6

Right                2                  2*3 =6

Balanced.

Answer:

The correct answer is Cirrocumulus.

Explanation:

Cirrocumulus : Clouds forming broken layer of small fleecy clouds at higher altitudes.

Cumulonimbus  : Clouds forming a towering mass with flat base with flat base at lower altitude

Cumulus  : Cloud forming rounded masses heaped or stacked on each other above a flat base , fairly at lower altitudes.

Stratus : Clouds forming continuous horizontal gray sheet, usually during rain or snow.

The given image corresponds to description given as Cirrocumulus.

Answer: A

Explanation: