what is the net force if you push a cart to the right with 5N of force, and a friend pushes the cart to the left with 5N of force?..​

Answer:

Mg is the symbol for Magnesium. Atomic #- 12

Explanation:

Answer:

The gravity pulls the sun and the planets together, while keeping them apart. The inertia provides the tendency to maintain speed and keep moving. The planets want to keep moving in a straight line because of the physics of inertia. However, the gravitational pull wants to change the motion to pull the planets into the core of the sun. Together, this creates a rounded orbit as a form of compromise between the two forces.

Final answer:

Gravity acts as a centripetal force pulling the Moon towards Earth, while inertia gives the Moon its straight-line momentum. Together, they balance each other out, keeping the Moon in a stable elliptical orbit around Earth. The gravity gradient also affects the Moon's rotation and contributes to the equilibrium between Earth and the Moon.

Explanation:

Gravity and Inertia in Maintaining the Moon's Orbit

The Moon remains in orbit around the Earth due to the combined effects of gravity and inertia. Gravity, a fundamental force discovered by Isaac Newton, acts as a centripetal force that pulls the Moon towards the center of the Earth. Without this force, the Moon would move in a straight line into space. On the other hand, inertia is the tendency of an object to maintain its state of motion unless acted upon by an external force. The Moon has a momentum perpendicular to the gravitational pull of the Earth which would allow it to move in a straight line. These two forces together create a delicate balance that results in the Moon's smooth, elliptical orbit around the Earth.

The gravity gradient also plays a role in the Moon's rotation and orbital characteristics. This gradient explains why the Moon is slightly elongated towards the Earth and contributes to maintaining its stable orbit. Furthermore, the Earth and Moon stay in equilibrium since the gravitational force of attraction between them is perfectly balanced by the centrifugal force, stemming from their relative motion.

In summary, gravity acts to pull the Moon towards the Earth, while inertia contributes to the Moon's tendency to move forward. Together, these forces create the conditions for a stable, synchronous orbit, manifesting in phenomena such as synchronous rotation and the consistent face of the Moon that is always directed towards Earth.

Answer:

-5.06 m/s

Explanation:

The formula to calculate average speed is

V = x2 - x1 / t2 - t1

The start point of the tumbleweed is 25.6m and the final point is -14.4 m

The start time is 0s and the final time is 7.9s

Replacing the values the result is -5.06m/s.

The result of the speed is negative because the direction of the speed is opposite to the direction of the tumbleweed.

Answer:

85 ÷ 0.50÷340=z z is the answer

Sound energy cannot travel through a vacuum.

Explanation:

Waves are periodic disturbance of the space, which travel carrying energy but not matter.

There are two types of waves:

In this problem, we are analyzing sound energy, which is the energy carried by sound waves. Sound waves are mechanical waves, so they need a medium to propagate: therefore, they cannot travel through a vacuum, since there is no medium.

So, sound energy cannot travel through a vacuum.

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Final answer:

The specific heat capacity of the metal can be calculated using the equation q = m*c*ΔT. By substituting the given values into the equation and rearranging, we can find that the specific heat capacity of the metal is approximately 0.33 J/g°C.

Explanation:

The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1°C. In this question, we can use the equation:

q = m*c*ΔT

Where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Given that the metal has a mass of 15.3 grams and the temperature rises by 4.3°C, and the water has a mass of 80.2 grams and the temperature rises by 4.3°C, we can substitute these values into the equation to find the specific heat capacity of the metal:

qmetal = mmetal * cmetal * ΔTmetal

qwater = mwater * cwater * ΔTwater

The specific heat capacity, cmetal, can then be calculated by rearranging the equation:

cmetal = (qmetal - mwater * cwater * ΔTwater) / (mmetal * ΔTmetal)

Plugging in the given values, we find that the specific heat capacity of the metal is approximately 0.33 J/g°C.

Answer:

this is a trap ur done  

Answer:

i think its B

Answer:

B. both air and space

Explanation:

Electromagnetic waves propagate through an oscillation of electric and magnetic fields. Therefore, they do not need a material means to propagate, thanks to this we can observe the light emitted by a distant star. In other words, they can travel through vaccum space or a medium like air.

Answer:

Option C. The chloroplasts contain chlorophyll pigments requires for photosynthesis.

The cell structure that is considered the site of photosynthesis is known as chloroplasts. Hence, option C is the correct answer.

Photosynthesis is a significant process that takes place in plants. The process in which light energy obtained from the sun is converted into sugar molecules for the utilization by plants cells is known as Photosynthesis.  

Photosynthesis occurs at chloroplasts. Some of the significant features of the chloroplasts are listed as follows:

Thus, we can conclude that the chlorophyll present in chloroplasts is vital for photosynthesis and hence, chloroplasts are the cell structure that acts as the site of photosynthesis. Therefore, option C is the correct answer.

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The minimum power is 490 W

Explanation:

The work that needs to be done by the robot in order to climb the shelves is equal to the gain in gravitational potential energy of the robot + object, therefore:

[tex]W=mg \Delta h[/tex]

where

m = 15 kg + 5 kg = 20 kg is the total mass of the system

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

[tex]\Delta h = 20 m[/tex] is the change in height

Substituting,

[tex]W=(20)(9.8)(20)=3,920 J[/tex]

Now we can calcualte the power (wattage) that the robot must have, using the equation

[tex]P=\frac{W}{t}[/tex]

where

W = 3,920 J is the work done

t = 8 s is the time interval

Substituting,

[tex]P=\frac{3920}{8}=490 W[/tex]

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The gravitational force on the second satellite is 1/8 of the force exerted on the 1st satellite.

Explanation:

The magnitude of the gravitational force exerted by the Earth on the satellite is given by:

[tex]F=G\frac{Mm}{r^2}[/tex]

where

G is the gravitational constant

M is the Earth's mass

m is the mass of the satellite

r is the radius of the orbit of the satellite

Let's call F the gravitational force on the first satellite, of mass m, with an orbit of radius r.

The second satellite has mass

[tex]m'=\frac{m}{2}[/tex]

and the radius of its orbit is

[tex]r'=2r[/tex]

So, the gravitational force exerted on the second satellite is

[tex]F'=G\frac{M(\frac{m}{2})}{(2r)^2}=\frac{1}{8}(\frac{GMm}{r^2})=\frac{1}{8}F[/tex]

Therefore, the force on the second satellite is 1/8 of the force exerted on the 1st satellite.

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The two models used to describe light are the ray model, which is useful in geometric optics for large surfaces, and the wave model, which explains diffraction and color. At the atomic level, the particle model describing light as photons is also used.

The two models used to describe how light behaves are the ray model and the wave model. The ray model of light simplifies its behavior to straight-line paths, which is particularly useful in geometric optics, where light's interaction with large surfaces—such as reflections from mirrors and refractions through lenses—is considered. The wave model, on the other hand, is essential for explaining phenomena like diffraction and the observation of colors, representing light as electromagnetic waves with different frequencies.

Furthermore, at the scale where light interacts on the level of individual atoms, the particle model of light, which describes light as photons, becomes more apparent. This model is crucial for understanding concepts like the photoelectric effect. Therefore, depending on the scale of the interaction and the nature of the observation, either model—or sometimes both—may be more appropriate for describing the behavior of light.

-271.96 °C

We are given;

we are required to calculate the temperature of the gas.

Moles = Mass ÷ Molar mass

Molar mass of nitrogen gas = 28.0 g/mol

Therefore;

Moles of N₂ = 92.5 g ÷ 28.0 g/mol

                   = 3.304 moles

According to the ideal gas equation;

PV = nRT , where n is the number of moles and R is the ideal gas constant, 0.082057 L.atm/mol.K

Rearranging the formula;

T = PV ÷ nR

  = ( 5.17 atm × 0.0625 L) ÷ (3.304 moles × 0.082057)

  = 1.19 K

But, °C = K - 273.15

Therefore;

T = 1.19 K - 273.15

  = -271.96 °C

Thus, the temperature of the gas will be -271.96 °C

Answer:

the answer is C

Explanation:

The average speed of the car is 28 mph

Explanation:

The average speed of an object is equal to the ratio between the total distance covered by the object (regardless of its direction) and the time taken. Therefore:

[tex]speed = \frac{d}{t}[/tex]

where

d is the total distance

t is the time taken

The car in this problem travels 5 miles north and 2 miles south, so the total distance covered is

d = 5 + 2 = 7 miles

While the time taken is

t = 1/4 h = 0.25 h

Therefore, the average speed is

[tex]speed = \frac{7}{0.25}=28 mph[/tex]

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Answer:

Its A.

Explanation:

Answer:

See the explanation below.

Explanation:

Circulation of blood and oxygen is possible in body when circulatory system work along with respiratory system. Through tranche air moves in and out from lungs, whereas, through pulmonary arteries and veins (both connected to heart) blood moves in and out from the lungs. As Lucille is facing problem in his respiratory and circulatory system hence, it is difficult for him to play soccer because under normal circumstances when there is increase in physical activity then muscle cell respire more as compare to when the body is on rest. So, with increase of physical activity there is also increase in the rate of breathing which result in more absorption of oxygen and more removal of carbon dioxide but if there is problem in respiratory and circulatory system, for example, infection in throat due to pollution,etc. then this normal process of breathing gets affected which sometime may prove fatal to the person.

Lucille's cells require oxygen for cellular respiration to produce energy, and issues with her respiratory or circulatory systems can impair oxygen delivery and carbon dioxide removal, causing difficulties in playing soccer.

In order for Lucille's body to function properly, her cells need oxygen to run the oxidative stages of cellular respiration, which produces energy in the form of adenosine triphosphate (ATP). Problems with Lucille's respiratory system or circulatory system could hinder the delivery of oxygen to her cells and removal of carbon dioxide from her body, which is critical for maintaining energy levels necessary for activities like playing soccer. Both systems work in tandem to ensure oxygen is inhaled into the lungs, transferred to the red blood cells, and delivered to body tissues, while carbon dioxide, a by-product, is picked up and exhaled.

The respiratory system includes the lungs where gas exchange occurs, and any condition like asthma, emphysema, COPD, or lung cancer can impair this function. Similarly, the circulatory system, consisting of the heart, blood, and blood vessels, is responsible for transporting gases to and from the lungs and body tissues. If the circulatory system is impaired, it can result in inadequate oxygen supply to muscles and organs, making it difficult for Lucille to sustain the physical exertion needed for soccer.

The weight of the object is 679.1 N

Explanation:

The weight of an object is given by:

[tex]W=mg[/tex]

where

W is the weight

m is the mass of the object

g is the acceleration of gravity

For an object near the Earth's surface, the acceleration of gravity is

[tex]g=9.8 m/s^2[/tex]

The mass of the object in this problem is

m = 69.3 kg

Therefore, its weight is

[tex]W=(69.3)(9.8)=679.1 N[/tex]

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Answer:

The answer i believe is A..

Explanation:

.

Answer:

Distance does not take direction of motion into account, but displacement does.

Explanation:

Distance is said to be how much ground an object covers during motion. Distance is a scalar quantity. Distance has magnitude but no direction. It only concerns how much ground an object covers without considering the start or end points. For example a person covering a distance from point A to B can be computed without considering it starting and ending point. The distance from A to B can be computed as 100 meters.The change in position is not considered, only the distance it covered(100 meters)

While

Displacement is the change in position of an object. Displacement is a vector quantity as it incorporates both direction and magnitude. Displacement considers the starting and ending points of an object in motion.  Example a person moving from point A to B, the change in position from point A to B shows their is a displacement.

Answer:

1 second

Explanation:

Assuming that the force is in the same direction as speed we can do the graphic.

Answer:

[tex]3.9m/s^{2}[/tex]

Explanation:

Using second law of motion

[tex]a =\frac {m1 * g - \frac {T}{r}}{m1 + 0.5 * m2}[/tex] where m1 is mass of block, m2 is mass of flywheel, g is acceleration due to gravity whose value is taken as [tex]9.81 m/s^{2}[/tex], T is torque and r is radius

Substituting 5.5 Kg for m1, 13 Kg for m2, 0.33 m for r, 2.5 Nm for T we obtain

[tex]a = \frac {5.5 \times 9.81 - \frac {2.5}{0.33}}{(5.5 + 0.5 \times13)}=3.9m/s^{2}[/tex]

To find the acceleration of the 5.5 kg block, we consider both gravitational force and frictional torque acting on a 13 kg flywheel. The calculated acceleration of the block is approximately 2.73 m/s².

To determine the magnitude of the acceleration of the 5.5 kg block as it falls, we need to consider several forces and torques involved in the system. These include the gravitational force on the block, the tension in the rope, the rotational inertia of the flywheel, and the frictional torque opposing the motion.

First, let’s identify the key forces:

The rotational inertia (I) of the flywheel (a disk) is given by:

I = 0.5 * mflywheel * r² = 0.5 * 13 kg * (0.33 m)² = 0.70785 kg·m²

Applying Newton’s second law for rotation, we have:

∑τ = I * α → τtension - τfriction = I * α

Here, τtension is the torque due to the tension in the rope, which is equal to T * r. Hence, we have:

T * r - τfriction = I * α

Also, the linear acceleration (a) of the block is related to the angular acceleration (α) of the flywheel by the equation:

a = α * r

Combining these equations, we get:

T * r - τfriction = I * (a / r)

Solving for T in terms of a:

T = (I * a / r²) + (τfriction / r)

Newton’s second law for the falling block gives us:

mblock * g - T = mblock * a

Substitute T from the earlier equation into this one and solve for a:

mblock * g - [(I * a / r²) + (τfriction / r)] = mblock * a

Rearranging terms to isolate a:

a = [mblock * g - (τfriction / r)] / [mblock + (I / r²)]

Substitute the known values:

a = [5.5 kg * 9.8 m/s² - (2.5 Nm / 0.33 m)] / [5.5 kg + (0.70785 kg·m² / (0.33 m)²)]

a ≈ 2.73 m/s²

Thus, the magnitude of the acceleration of the block as it falls is approximately 2.73 m/s².

Answer:

[tex]7.3 ms^{-1}[/tex]

Explanation:

Consider the motion of the ball attached to string.

In triangle ABD

[tex]Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50[/tex]

height gained by the ball is given as

[tex]h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m[/tex]

[tex]M[/tex]  = mass of the ball attached to string = 110 g

[tex]V[/tex] = speed of the ball attached to string just after collision

Using conservation of energy

Potential energy gained = Kinetic energy lost

[tex]Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}[/tex]

Consider the collision between the two balls

[tex]m[/tex]  = mass of the ball fired = 26 g

[tex]v_{o}[/tex] = initial velocity of ball fired before collision = ?

[tex]v_{f}[/tex] = final velocity of ball fired after collision = ?

using conservation of momentum

[tex]m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85[/tex]

Using conservation of kinetic energy

[tex]m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}[/tex]

At a maximum angle of 50°, the initial velocity ([tex]V_0[/tex]) of the ball is equal to 7.3 m/s.

Given the following data:

Mass of ball 1 = 26.0 g.

Mass of ball 2 = 110.0 g.

Length = 1.10 m.

Maximum angle = 50°

First of all, we would determine the height of the ball in motion through this derivation:

[tex]h = L-Lcos\theta\\\\h = 1.10-1.10cos50\\\\h = 1.10-0.7071[/tex]

Height, h = 0.3929 meter.

Next, we would determine the velocity of the ball by applying the law of conservation of energy:

[tex]P E=KE\\\\mgh=\frac{1}{2} mv^2\\\\V=\sqrt{2gh} \\\\V=\sqrt{2 \times 9.8 \times 0.3929 }[/tex]

V = 2.7750 m/s.

Also, we would determine the final velocity by applying the law of conservation of momentum:

[tex]m_1v_o=m_1vf+m_2V\\\\26v_0=26v_f+110(2.7750)\\\\26v_f=26v_0-305.25\\\\v_f=(v_0-11.7404)\;m/s[/tex]

Now, we can determine the initial velocity:

[tex]m_1v_o^2=m_1v_f^2+m_2V^2\\\\26v_0^2=26(v_0-11.7404)^2+110(2.7750)^2\\\\26v_0^2=26(v_0-11.7404)^2-847.0688\\\\V_0=7.3\;m/s[/tex]

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Answer: equal in magnitude but opposite in direction to the force that it exerts.

Explanation:

Answer:

The second object exert a force that is equal in magnitude and opposite in direction.

Explanation:

Newton's third law of motion states that for every action there is a reaction which is equal in magnitude to the action but acts in opposite directions as the action.

Answer:

The force acting on a body is always equal to the product of the mass of the body and its acceleration.

Explanation:

The force of a body is defined as the product of mass and acceleration of the body.

According to Newton's second law, wherever there is a change in momentum of the body for an interval of time, there is a force acting on it.

                         F = (mv - mu) / t

                             = m (v -u) /t

                              = m a

Where,

                                 (v - u)/t - is the change in velocity of the body in the interval of time. It is equal to the acceleration of the body.

Hence, the equation for the force for any body becomes, F = m x a

Answer:

slower

Explanation:

Due to the fact that it is falling, the object experiences an acceleration due to gravity, so this acceleration will make the car go faster every moment, so the speed at the top will be lower than the speed at the bottom.

The situation can also be thought of as a transaction of potential energy (energy due to the mass of an object and its position on the ground) and kinetic energy (energy due to movement). At the top is the point where the object has the greatest potential energy, and as it moves down this potential energy is exchanged for kinetic energy. The kinetic energy increases while going down the ramp, so it will have greater speed as it falls.

The answer is: the speed at the top of the ramp will be slower than the speed at the bottom.

Answer:1. Roche limit

2.hydrogen

3.atmosphere

4.mercury

5.venus

6.when an object passes the Roche limit, the strength of gravity on the object increases. If the density of the planet is higher, then the object can break up farther away from the planet. If the density is lower, then the Roche limit is located closer to the planet

7.Farther our in the solar system, beyond the frost line, hydrogen was at a low enough temperature that it could condense. This allowed hydrogen to accumulate under gravity, eventually forming the Jovian planets

Explanation:

An object breaks apart at a planet's Roche limit; Jovian planets mainly consist of hydrogen and helium. Earth's atmosphere lacks these gases due to weaker gravity. Mercury, close to the sun, has little atmosphere, and Venus has a hot, dense atmosphere.

An object can be broken up by a planet's gravity once it passes the Roche limit. The Jovian planets are composed primarily of hydrogen and helium. Hydrogen and helium don't exist in Earth's atmosphere because the terrestrial planets of Mercury, Venus, Earth, and Mars couldn't exert a strong gravitational pull on hydrogen and helium gas within the nebula. Mercury is the planet closest to the sun, has almost no atmosphere, and what little atmosphere exists is constantly getting blown away by solar wind. The atmosphere of Venus is very hot and dense, comprised of approximately 95 percent carbon dioxide, and the surface is composed of molten bedrock.

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Answer:

The lose of thermal energy is, Q = 22500 J

Explanation:

Given data,

The mass of aluminium block, m = 1.0 kg

The initial temperature of block, T = 50° C

The final temperature of the block, T' = 25° C

The change in temperature, ΔT = 50° C - 25° C

                                                     = 25° C

The specific heat capacity of aluminium, c = 900  J/kg°C

The formula for thermal energy,

                             Q = mcΔT

                                 = 1.0 x 900 x 25

                                 = 22500 J

Hence, the lose of thermal energy is, Q = 22500 J

The thermal energy loose by the aluminum block will be Q = 22500 J

It is given that Given data,

The mass of the aluminum block, m = 1.0 kg

The initial temperature of the block, T = 50° C

Since the temperature of the block is halved then,

The final temperature of the block,  T' = 25° C

The change in temperature, ΔT = 50° C - 25° C = 25° C

The specific heat capacity of aluminum,

c = 900  J/kg°C

The formula to find out the thermal energy will be

[tex]Q=m\times c\times\Delta T[/tex]  

[tex]Q=1.0\times 900\times 25[/tex]    

[tex]Q= 22500J[/tex]  

Thus the thermal energy loose by the aluminum block will be Q = 22500 J

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A) The net force on the motorbike is 205.9 N

B) The acceleration of the motorbike is [tex]1.37 m/s^2[/tex]

C) The final speed is 5.2 m/s

D) The elapsed time is 3.80 s

Explanation:

A)

There are two forces acting on the motorbike:

- The applied force, F = 250 N, forward

- The frictional force, [tex]F_f[/tex], backward

The frictional force can be written as

[tex]F_f = \mu mg[/tex]

where

[tex]\mu=0.03[/tex] is the coefficient of kinetic friction

[tex]m=150 kg[/tex] is the mass of the motorbike

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

Therefore the net force is given by

[tex]\sum F = F - F_f = F - \mu mg[/tex]

And substituting, we find

[tex]\sum F=250 - (0.03)(150)(9.8)=205.9 N[/tex]

2)

The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:

[tex]\sum F = ma[/tex]

where

m is the mass

a is the acceleration

In this problem, we have

[tex]\sum F = 205.9 N[/tex] is the net force

m = 150 kg is the mass

Solving for a, we find the acceleration:

[tex]a=\frac{\sum F}{m}=\frac{205.9}{150}=1.37 m/s^2[/tex]

C)

Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For this motorbike, we have:

u = 0 (it starts from rest)

[tex]a=1.37 m/s^2[/tex]

s = 350 m

Solving for v,

[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(1.37)(9.8)}=5.2 m/s[/tex]

4)

For this part of the problem, we can use the following suvat equation:

[tex]v=u+at[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the elapsed time

Here we have:

v = 5.2 m/s

u = 0

[tex]a=1.37 m/s^2[/tex]

Solving for t, we find

[tex]t=\frac{v-u}{a}=\frac{5.2-0}{1.37}=3.80 s[/tex]

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Answer:

This is a great question

*copy and paste for my physics homework* lol

Answer:

nice, thats a fast rabbit

Explanation:

Answer:

Angular Velocity at 2 s= 13 rad/s

Explanation:

∅(t)=2[tex]t^{2}[/tex] + 5t + 5

where represents angular displacement at any given time t

Angular Velocity (ω)= [tex]\frac{\textrm{d ∅(t) }}{\textrm{dt}}[/tex]

ω=4t+ 5

Putting in t=2

ω=8+5=13 rad/s