What is the number “4” in SiCl4?

Answers

Answer 1
The '4' tells how many Chlorine are in the compound.
Answer 2
Hello there,

A subscript is the answer.

Hope this answer has helped you.

Related Questions

Using the chemical equation: 4NO2(g) + O2(g) + 2H2O(l) = 4HNO3 (aq) : Calculate the theoretical yield in grams of nitric acid when 2.0 moles nitrogen dioxide react with 2.0 moles of oxygen gas.

Answers

stoichiometry of NO₂ to O₂ is 4:1
4 mol of NO₂ reacts with 1 mol of O₂
we need to first find the limiting reactant. limiting reactant is the reactant that is fully consumed during the reaction and amount of product formed depends on the amount of limiting reactant present.
If limiting reactant is O₂, there are 2 mol of O₂, then NO₂ present should be 8 mol. However only 2 mol of NO₂ is present, therefore NO₂ is the limiting reactant.
the stoichiometry of NO₂ to HNO₃ is 4:4 therefore 1:1
number of NO₂ moles reacted = number of HNO₃ moles 
Number of HNO₃ moles = 2 mol
mass of HNO₃ = 2 mol x 63 g/mol
                        = 126 g

Final answer:

The theoretical yield of nitric acid, when 2.0 moles of nitrogen dioxide react with sufficient oxygen, is calculated using stoichiometry and comes out to be 126.02 grams.

Explanation:

The question involves using a chemical equation and stoichiometry to calculate the theoretical yield of a compound, specifically nitric acid (HNO3), from a given amount of reactants. We start by balancing the chemical equation: 4NO2(g) + O2(g) + 2H2O(l) = 4HNO3(aq). This shows that 4 moles of NO2 react with 1 mole of O2 to produce 4 moles of HNO3. With 2.0 moles of NO2 present, NO2 is the limiting reactant since it reacts in a 4:1 ratio with O2, and there is enough O2 provided (2.0 moles).

To calculate the theoretical yield of nitric acid, we use the molar ratio from the balanced equation. Since 4 moles of NO2 produce 4 moles of HNO3, 2.0 moles of NO2 will produce 2.0 moles of HNO3. Now, we need to convert moles of nitric acid to grams using its molar mass. The molar mass of HNO3 is approximately 63.01 g/mol, so:

Theoretical yield of HNO3 = moles of HNO3 × molar mass of HNO3

Theoretical yield of HNO3 = 2.0 moles × 63.01 g/mol = 126.02 grams

Thus, the theoretical yield of nitric acid when 2.0 moles of nitrogen dioxide react with enough oxygen is 126.02 grams.

the career area of chemistry which is involved in the manufacturing of products is:

Answers

Chemical Production is the answer
Answer: chemical engineering.

Justification:

The core of chemical engineering is the design of processes to manufacture products where chemical changes are involved, using the knowledge on chemistry to set the operating condictions to run the reactions on chemical reactors and to run special operations like distillation, heating, cooling, cristalization, among many others.

Which of the following is a possible application for discoveries made during ocean exploration?

Answers

Final answer:

Ocean exploration can lead to cultural and historical insights through the excavation of shipwrecks, aid in the discovery and mapping of natural resources like oil, and contribute to marine biology by discovering new species, ecosystems, and fossil sites.

Explanation:

A possible application for discoveries made during ocean exploration includes the excavation of historical shipwrecks to shed light on cultural interactions and trade routes of the past. For instance, the excavation of the Byzantine Serçe Limanı Shipwreck provides valuable information about cross-cultural artistic exchanges during the Middle Byzantine period. Similarly, studies of the Battle of Bạch Đằng help map the cultural landscape associated with historical Vietnamese maritime events. Ocean exploration can also lead to the discovery and mapping of natural resources such as oil deposits, which is vital for their utilization, drawing a parallel to the need for exploration before the extraction of resources, much like we can't produce more oil than we discover. Additionally, marine ecologists involved in ocean exploration contribute to the study of marine life and ecosystems, which includes discovering new fossil sites, organizing and classifying organisms, and identifying new species.

Final answer:

Ocean exploration can lead to potential ocean floor colonization, historical insights from shipwrecks, new resource discoveries, and innovations in resource extraction methods. Marine ecologists also benefit from discoveries made, which contribute to scientific and environmental understanding.

Explanation:

Discoveries made during ocean exploration have a multitude of applications, one of which is the possibility of colonizing the ocean floor. This could serve as a precursor to space colonization due to similar challenges faced in both environments, such as the development of sealed-off, self-sustaining habitats. Additionally, research on historic shipwrecks, like the Byzantine Serçe Limanı Shipwreck, provides invaluable insights into historical trade routes and cross-cultural interactions.

Further benefits of ocean exploration include advancements in navigational technology, which were historically influenced by the contributions of Muslim and Chinese inventions. These innovations enabled European explorers to sail across the Atlantic Ocean, leading to the discovery of new trade routes and the establishment of new markets. Ocean exploration also plays a critical role in uncovering new natural resources, like oil deposits, and in the development of innovative methods to extract and utilize these resources effectively.

Moreover, a marine ecologist might conduct studies to discover new fossil sites, classify organisms, or name new species, underlining the scientific and environmental significance of oceanic discoveries.

Draw one of the isomeric c5h12o alcohols that can be prepared by lithium aluminum hydride reduction of a ketone.

Answers

Hello!

The Lithium Aluminum hydride (LiAlH₄) reduction of a ketone is a process in which the ketone is reduced and the Lithium Aluminum hydride is oxidized. The general chemical reaction for this kind of reduction is:

              1)LiAlH₄
R(C=O)R ---------→R(C-OH)R 
              2)H₃O⁺

The structure for one of the isomeric C₅H₁₂O alcohols that can be prepared by lithium aluminum hydride reduction of a ketone is shown in the attached image, the compound is called 3-Pentanol:

Have a nice day!

a lemon with mass 0.3 kg falls out of a tree from a height of 18 m. how much mechanical energy does the lemon have just before it hits the ground?

Answers

Answer is: the objects mechanical energy is 52,92 J.
m(object) = 0,3 kg.
h(object) = 18 m.
g = 9,8 m/s².
E(object) = m·g·h.
E(object) = 0,3 kg · 9,8 m/s² · 18 m.
E(object) = 52,92 N·m = 52,92 J..
g - the acceleration of free fall.
mg - weight of the object.

What is the total number of valence electrons for cesium?​?

Answers

it's an alkali metal so one, they sit on the very first of the column in the periodic table :DDDD

One Valence electron

Consider the fructose-1,6-bisphosphatase reaction. calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 24.3, and the temperature is 37.0 °c? δg°\' for the reaction is –16.7 kj/mol. the constant r = 8.3145 j/(mol·k)

Answers

Let me work this one out and I’ll let you know what I survive afterwards

What is the ph of a solution whose hydroxide ion concentration, [oh−], is 4.3 × 10−4 m? mastering chemistry?

Answers

The hydroxide ion concentration = 4.3 X 10^-4 M

so we will calculate pOH first

pOH = -log[OH-] = - log (4.3 X 10^-4) = 3.37

we know that

pH +pOH = 14

so pH = 14-3.37 = 10.63

Ph = 14 - POH = 14 - (- log 4.3 × 10 - 4)
Ph = 14 - 3.37 = 10.63

10.63 is the answer
Brainliest pts

Determine the limiting reactant. 2al(s)+3br2(g)→2albr3(s)

Answers

Missing question: For each of the following reactions, 25.0 g of each reactant is present initially.
m(Al) = 25 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 25 g ÷ 27 g/mol.
n(Al) = 0,926 mol.
m(Br₂) = 25 g.
n(Br₂) = 25 g ÷ 160 g/mol.
n(Br₂) = 0,156 mol.
Bromine is the limiting reactant, because it has less amount of substance.
Final answer:

The limiting reactant in a chemical reaction is determined by calculating the amount of product (AlBr3 in this case) that would be produced from the complete reaction of each of the reactants separately. The reactant yielding the lesser amount of product is the limiting reactant.

Explanation:

To determine the limiting reactant in a chemical reaction, you can use a method where you compare the amount of each reactant to the amount of product expected from its complete reaction. Taking the given equation, 2Al(s)+3Br2(g)→2AlBr3(s), we would calculate the amount of the product AlBr3 that would be formed from the complete reaction of each reactant, Al and Br2, separately. The reactant that yields the lesser amount of the product AlBr3 is the limiting reactant. This concept can be understood using a simple analogy. Let's think of making a sandwich: 2 slices of bread + 1 slice of cheese yields 1 sandwich. If you have an excess of bread but only one slice of cheese, you can only make one sandwich. The cheese is the limiting reactant as it limits the yield of sandwich and the amount of bread left unreacted is the excess reactant. Similarly, in the chemical reaction given above, the reactant that produces less amount of product (AlBr3) acts as the limiting reactant.

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how many moles are there in 78.3g of CO2?

Answers

The molar mass of CO2 can be calculated as follows;
CO2 — 12 + (16x2) = 12+ 32 = 44 g
Therefore molar mass of CO2 is 44 g/mol
In 44 g of CO2 there’s 1 mol of CO2
Then 1 g of CO2 there’s 1/44 mol of CO2
Therefore in 78.3 g of CO2 there’s — 1/44 x 78.3 =1.78 mol of CO2

Calculate the enthalpy change for the thermite reaction: 2al(s)+fe2o3(s)→2fe(s)+al2o3(s), δh∘rxn=−850 kj when 10.0 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3.

Answers

From the balanced equation for this reaction: 
2Al(s) + Fe2O3(s) → 2Fe(s) + Al2O3(s)
so from this balanced equation, we can know that:
2 moles of Al react with 1 mole of FeO3 to give 850 Kj 
So the energy is given by 10 mol of Al should be calculated from
2 mol Al → -850 KJ
10 mol Al→ ???
and it is obvious that as the number of moles increases so the energy will be higher. 
∴ ΔH°rxn= -850 kj * 10 mol of Al / 2 mol of Al
            = -4250 KJ

Problem page liquid hexane ch3ch24ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 1.72 g of hexane is mixed with 1.8 g of oxygen. calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. be sure your answer has the correct number of significant digits.

Answers

hexane formula is C₆H₁₄
combustion reaction with O₂ is as follows;
C₆H₁₄ + 19/2O₂ ----> 6CO₂ + 7H₂O
to get whole number coefficients lets multiply by 2
2 C₆H₁₄ + 19 O₂ ----> 12 CO₂ + 14 H₂O
the stoichiometry of C₆H₁₄ to O₂ is 2 :19
2 moles of C₆H₁₄ reacts with 19 mol of O₂
both of these 2 reactants could be fully used up if the amounts are present in the correct stoichiometry or one reactant could be in excess and other could be the limiting reactant. Limiting reactant is when the reactant is fully consumed, products formed depends on this reactant.
amount of C₆H₁₄ moles - 1.72 g / 86.18 g/mol = 0.0200 mol
amount of O₂ moles - 1.8 g / 32 g/mol = 0.056 mol
if hexane is limiting reactant 
2:19 ratio , number of O₂ moles - 0.0200/2 *19 = 0.19
but 0.19 moles of O₂ aren't present, this means that O₂ is limiting reactant

stoichiometry of O₂ to CO₂ is 19:12
if 19 moles of O₂ is consumed - 12 mol of CO₂ produced 
then 1 mol of O₂ - gives 12/19 mol of CO₂
therefore 0.056 of O₂ - gives 12/19 * 0.056 mol 
                                  = 0.035 mol of CO₂
then mass of CO₂ = 0.035 mol * 12 g/mol 
                             = 0.42 g

Answer:

[tex]m_{CO_2}=1.6gCO_2[/tex]

Explanation:

Hello,

In this case, hexane's combustion is stood for the following chemical reaction:

[tex]C_6H_{14}+\frac{19}{2} O_2-->6CO_2+7H_2O[/tex]

Now, we need to identify the limiting reactant for which we compute both hexane's and oxygen's moles as shown below:

[tex]n_{C_6H_{14}}=1.72g\frac{1molC_6H_{14}}{86gC_6H_{14}}=0.02molC_6H_{14}\\n_{O_2}=1.8g\frac{1molO_2}{32gO_2}=0.056molO_2[/tex]

Afterwards, we compute the moles of hexane that completely react with 0.056 moles of oxygen via the stoichiometry:

[tex]n_{C_6H_{14}}^{reacting}=0.056molO_2\frac{1molC_6H_{14}}{\frac{19}{2}molO_2}=0.0059molC_6H_{14}[/tex]

Now, since 0.02 moles of hexane are available but just 0.0059 moles react, the hexane is in excess and the oxygen is the limiting reactant, thus, the maximum mass of carbon dioxide is computed as shown below with two significant figures (due to the significant figures of the oxygen's initial mass) by using the moles of oxygen as the limiting reactant:

[tex]m_{CO_2}=0.056molO_2*\frac{6molCO_2}{\frac{19}{2}molO_2}*\frac{44gCO_2}{1molCO_2} \\m_{CO_2}=1.6gCO_2[/tex]

Best regards.

An analysis reveals that a substance consists of 26.7% of carbon, 2.24% of hydrogen and 71.1% of oxygen, If the molar mass of the compound is 270.1 g/mol, what is the MOLECULAR Formula?

Answers

 the   molecular  formula    is  calculated  as  follows 
find  the  mole  of  each  molecule 
that  is   for  carbon = 26.7/12=  2.23  moles
                   hydrogen=  2.24/1=2.24  moles
                 oxygen=  71.1/16=4.44  moles
find  the   mole  ratio  of  each  element
that  is  divide  all  moles  by  the  smallest  mole(  2.23)

for  carbon=2.23/2.23=1,
  hydrogen =  2.24/2,23=1
  oxygen= 4.44/2.23=  2
the   empirical  formula  = CHO2
therefore  the  molecular  formula=(CHO2)n=270.1
                 { ( 12x 1)  + 1x1) +(16x2)}n=270.1
45n=270.1 
n=6
molecular  formula  is  therefore=(CHO2)6=C6H6O12

A flask contains 0.230 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.

Answers

the amount of bromine present in the flask = 0.230 moles
Avagadro's number states the number of units present in a single mole.
Avagadro's number is 6.022 x 10²³ units, these could be atoms in the case of elements or molecules in compounds. 
the number of bromine molecules in 1 mol = 6.022 x 10²³ molecules of Br bromine molecules in 0.230 mol = 6.022 x 10²³ molecules/mol x 230 mol

number of bromine molecules in the flask = 1.385 x 10²⁶ Br₂ molecules

Answer:

There are [tex]1.38506\times 10^{23} [/tex] of bromine molecules present in the flask.

Explanation:

Moles of liquid bromine in the flask = 0.230 mol

As we know that 1 mole is equal to the Avogadro number.

[tex]1 mol=6.022\times 10^{23}[/tex] atoms/ molecules

So, number of bromine molecules in 0.230 moles of liquid bromine is:

[tex]=0.230\times 6.022\times 10^{23}=1.38506\times 10^{23} molecules[/tex]

There are [tex]1.38506\times 10^{23} [/tex] of bromine molecules present in the flask.

How many grams of silver chloride (AgCl) can be produced if you start with 12.5 grams of barium chloride (BaCl2)?

2AgNO3 + BaCl ==> 2AgCl + Ba(No3)2

Answers

the balanced equation for the above reaction is;
2AgNO₃ + BaCl₂ ==> 2AgCl + Ba(No₃)₂
stoichiometry of BaCl₂ to AgCl is 1:2
number of BaCl₂ moles reacted - 12.5 g / 208.23 g/mol = 0.06 mol
number of AgCl moles produced - 0.06 mol x 2 = 0.12 mol
Therefore mass of AgCl produced - 0.12 mol x 143.32 g/mol = 17.2 g 

The thermodynamic law that explains the movement of heat energy during the refrigeration cycle is the first/zeroth/second.

Answers

second
is the answer to this queston
Second (there ya go, bud)

Which of the following elements makes up the tissues and organs of animals? A.Carbon B.Hydrogen C. Nitrogen D.Oxygen

Answers

Hydrogen if im wrong by texting me 

Answer:

A. Carbon

Explanation:

Carbon is one of the most important elements for the structure of living things. It is responsible for 19% of the body composition of animals, behind only oxygen, which contributes 61%. The head is one of the main elements that make up the tissues and organs of animals.

Carbon has a special property: it can make four different chemical bonds. This means that, in addition to being able to bond with atoms of other elements such as hydrogen, oxygen, nitrogen, sulfur and phosphorus, carbon can also bond in different ways with other carbon atoms.

The result is the formation of thousands of carbon compounds that are present in nature, rocks, minerals, products made in industries, plastics, smoke, oil, plants, animals and within our own bodies.

Consider the unbalanced equation for the combustion of hexane: αc6h14(g)+βo2(g)→γco2(g)+δh2o(g) part a balance the equation. give your answer as an ordered set of numbers α, β, γ, ... use the least possible integers for the coefficients. α, β, γ, δ = request answer part b determine how many moles of o2 are required to react completely with 6.4 moles c6h14. express your answer using two significant figures. n = mol

Answers

Answer :

Part A : The value of [tex]\alpha, \beta, \gamma \text{ and }\delta[/tex] are 2, 19, 12 and 14 respectively.

Part B : [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].

Solution :

Part A :

The given unbalanced equation is,

[tex]\alpha C_6H_{14}(g)+\beta O_2(g)\rightarrow \gamma CO_2(g)+\delta H_2O(g)[/tex]

The balanced equation is,

[tex]2C_6H_{14}(g)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(g)[/tex]

Part B :

From the balanced equation, we conclude that

2 moles of [tex]C_6H_{14}[/tex] react with 19 moles of [tex]O_2[/tex]

6.4 moles of [tex]C_6H_{14}[/tex] react with [tex]\frac{19moles}{2moles}\times 6.4moles=60.8moles=6.0\times 10^1moles[/tex] of [tex]O_2[/tex]

Therefore, [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].


Final answer:

The balanced equation is 2C3H7(g) + 9O2(g) → 6CO2(g) + 7H2O(g), therefore the coefficients α, β, γ, δ are 2,9,6,7, respectively. And 29 moles of O2 are required to react completely with 6.4 moles of C6H14.

Explanation:

For part a, to balance the equation for the combustion of hexane, we have to adjust the coefficients in the equation C6H14(g) + αO2(g) → βCO2(g) + γH2O(g) such that the number of atoms of each element on both sides of the equation are equal. The balanced equation becomes: 2C3H7(g) + 9O2(g) → 6CO2(g) + 7H2O(g) . It means that α, β, γ, δ = 2, 9, 6, 7 respectively.

For part b, according to the balanced equation, 9 moles of O2 are required to react completely with 2 moles of C6H14. So, if there are 6.4 moles of C6H14, you will need: (6.4 moles C6H14 * 9 moles O2) / 2 moles C6H14 = 28.8 ≈ 29 moles of O2. In this case  'n' equals 29 moles.

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Label each description as ionic, covalent, or both.

Atoms share pairs of electrons:
Atoms transfer electrons:
Atoms have electrostatic attraction:
Atoms bond together:

Answers

Atoms share pairs of electrons: covalent
Atoms transfer electrons: ionic
Atoms have electrostatic attraction:
Atoms bond together:Both

Answer :

Atoms share pairs of electrons :  Covalent

Atoms transfer electrons :  Ionic

Atoms have electrostatic attraction :  Ionic

Atoms bond together : Both

Explanation :

Covalent compound : The compounds where the atoms are covalently bonded.  

Covalent bonds are formed by the equal sharing of electrons. These bonds are commonly formed between two non-metals.

Ionic compound : The compounds where the atoms are bonded through ionic bond and atoms are bonded by the electrotstatic attraction.

Ionic bonds are formed by the complete transfer of electrons. The atom which looses the electron is considered as an electropositive atom and the atom which gains the electron is considered as electronegative atom. These bonds are formed between one metal and one non-metal.

Use the word part meanings to figure out which term describes a desert plant, such as a cactus.
a. mesophyte
b. hydrophyte
c. xerophyte

Answers

Your answer is A. Mesophyte

The part of the flower responsible for producing pollen (sperm) is the _______.



filament


anther


stigma


style

Answers

Hello,

Here is your answer:

The proper answer to this question is option C "stigma".

Here is how:

The stigma is responsible for producing pollen in a plant.

Your answer is C.

If you need anymore help feel free to ask me!

Hope this helps!

17.g to mL
Density= 3.291g/mL

Answers

density is defined as mass per unit volume 
therefore density = mass ÷ volume

volume = mass÷density
volume in ml = 17 ÷ 3.291

A 45-g aluminum spoon (specific heat 0.88 j/g °c) at 24 °c is placed in 180 ml (180 g) of coffee at 85 °c andthe temperature of the two become equal.(a) what is the final temperature when the two become equal? assume that coffee has the same specific heat aswater.

Answers

when Heat lost by coffee -q= m( coffee) * C (coffee) * ΔT

and Heat gained by spoon q = m (spoon) * C (spoon) * ΔT

when q = -q 
∴ m(coff)* C(coff) * ΔT (coff) = m(sp)* C(sp)*ΔT(sp)
when the final tempreature of both will be the same so,
m(coff) * C(coff) * ( Tf - Ti(coff)) = m(sp) * C(sp) * (Tf- Ti(sp)

by substitution:
note: as the coffe will reduce heat so, ΔT = (85-Tf)
and the spoon will gain heat so ΔT = (Tf-24)
180 g * 4.186 * (85-Tf) = 45 * 0.88 * (Tf- 24)
∴Tf = 81 °C 
Final answer:

The final equilibrium temperature when a 45-g aluminum spoon at 24 °c is placed in 180 ml of coffee at 85 °c, can be calculated using the heat transfer formula. Equating the heat lost by the coffee to the heat gained by the spoon, and substituting the given values will help you solve for the final temperature.

Explanation:

In this problem, you are being asked to solve for the final equilibrium temperature of a system that consists of a hot coffee and a cool aluminum spoon. The heat lost by the hotter object (coffee) is equal to the heat gained by the colder object (spoon), assuming no energy is lost to the surroundings. This situation is a classical problem of heat transfer which can be addressed by use of the formula Q = mcΔT, where Q is the heat transferred, m is mass, c is specific heat and ΔT is temperature change.

The equation becomes Qcoffee = Qspoon, resulting in mcoffeeccoffee (Tinitial, coffee - Tfinal) = mspooncspoon(Tfinal - Tinitial, spoon). With the given values, we can solve for Tfinal. Solving this equation will yield your desired final equilibrium temperature.

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Wade thinks it would be really cool to become a radiologist. Which two skills are important for him to have in order to excel in this career?

A-leadership skills to help oversee the members of the staff within the hospital
B- physical strength to lift heavy equipment and machinery
C-interpersonal skills to talk to patients and help them feel comfortable
D-technical skills to know how to use the machinery and equipment needed for the job
E-public speaking skills to announce research findings in conferences

Answers

Final answer:

To excel in radiology, Wade needs to develop strong interpersonal skills to communicate effectively with patients and excellent technical skills for using and understanding complex radiological equipment and procedures. So the correct options are C and D.

Explanation:

For Wade to excel as a radiologist, there are two essential skills that are particularly important. One of these skills is interpersonal skills, which would allow him to communicate effectively with patients, help them to relax, and explain procedures to provide a comfortable experience. The other key skill is technical skills relating to the use of radiological machinery and equipment. These skills are necessary for accurately performing and interpreting medical imaging, such as computed tomography (CT), magnetic resonance imaging (MRI), and mammography which involves complex operation of medical devices and analysis of the resulting images for diagnostic purposes.

While leadership skills and public speaking abilities can be beneficial in any profession, they are not as central as interpersonal and technical skills for the day-to-day responsibilities of a radiologist. Physical strength is generally less critical, given that lifting heavy equipment is not a common task for radiologists.

Thorium-234 undergoes beta decay to form a daughter nuclide and a beta particle. what are the mass number and atomic number for the daughter nuclide?

Answers

Radioactive decay in this case is the beta decay. Where Thorium will give out a beta particle and decay into the daughter nuclide. 
Beta particles are β⁻, a neutron in the nucleus is converted to a proton and an electron is released. Beta particles are therefore negatively charged and have no mass.
from the parent nuclide to daughter nuclide, there is no change in mass number , however in the parent a neutron converted to proton so there's an additional proton, this means that atomic number also increases by 1. then the daughter nuclide is the element with the corresponding atomic number 

²³⁴₉₀Th -------> ²³⁴₉₁Pa + ₋₁⁰β

Th atomic number - 90 , after beta decay proton increases by 1, atomic number of daughter nuclide is 91, the element with atomic number 91 is protactinium.
As neutron converts to proton no net change in mass.


What are the 3 parts of the modern cell theory

Answers

1. All living things are made up of cells.
2. Cells are the basic unit of life.
3. All cells come from pre-existing cells.

ben helps his dad make chicken soup. their recipe makes 15 cups of soup. if they each eat 2 cups and freeze the rest will the leftovers fit in a 64 ounce container? 1 cup = 8 ounces

Answers

no ,8 x 15 is 90,90-4 is 86

Write the atomic cores for potassium and chloride ions

Answers

This question is part of a bigger question.

The target is to determine the Lewis structer for the ionic compound KCl.

The atomic cores are the electrons but the outermost shell (i.e. valence electrons).

Potassium has atomic number (Z) 19.

So, its electron distribution is 1s2 2s2 2p6 3s2 3p6 4s

The valence electron is 4s, so the atomic core is 1s2 2s2 2p6 3s2 3p6.

Potassium ion, K+, has lost one electron, the outermost electron, so it has the same electrons as the atomic core of K.

Chlorine has atomic number 17.

The electron distribution of chlorine is 1s2 2s2 2p6 3s2 3p5.

The valence eletrons are 3s2 3p5, so the atomic core of chlorine is 1s2 2s2 2p6.

The ion Cl- has gained one electron so its electron configuration is 1s2 2s2 2p6 3s2 3p6.

To represent the Lewis structure you only use the valence electrons, so the representation is:

             **
K(+)  +*Cl(-) **
             **

Where the * marks represent the 7 valence electrons of chloride atom and the + mark represent the electron gained by chloride and released by potassium.

So, the ion K(+) has lost its only valence electron and the ion Cl(-) has increased its valence electrons to 8. In this way both have the stable configuration of a noble gas.
Final answer:

The atomic core for a potassium ion (K+) is [Ar]4s¹ without the one electron it loses to become an ion. The atomic core for a chloride ion (Cl-) is [Ne]3s² 3p⁵ with an extra electron gained to fill its 3p orbital.

Explanation:

The atomic cores for potassium and chloride ions are represented by their respective electron configurations and their charges after ion formation. Potassium (K) has an atomic number of 19, which means it has 19 electrons. The electron configuration is [Ar]4s¹. When potassium forms an ion, it loses one electron to achieve a noble gas configuration, making it a potassium ion with a charge of +1, represented as K⁺.

Chlorine (Cl) has an atomic number of 17, which means it has 17 electrons. The electron configuration is [Ne]3s² 3p⁵. When chlorine forms an ion, it gains one electron to fill its 3p orbital, becoming a chloride ion with a charge of -1, represented as Cl⁻.

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_____________ means that animals within a population have a variety of strengths.

Answers

Genetic diversity is probably the answer you're looking for.
Genetic diversity means that animals within a population have a variety of strengths. Plz give brainliest it would help me out when I Just helped you out :)

what happens when you put on deodorant? does it absorb heat and give off thermal energy

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it absorbs heat and give off thermal energy just saying i think its right
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