Answer:
Quality of vapor is equal to 17.3%.
Explanation:
We know that if we know only one property in side the wet region then we will find the other property by using steam property table.
So pressure at saturation temperature 20°C
[tex]v_f= 0.001\frac{m^3}{Kg} ,v_g= 57.76\frac{m^3}{Kg}[/tex]
So specific volume v
[tex]v=v_f+x(v_g-v_f)\frac{m^3}{Kg}[/tex]
Where x is quality of mixture
Now putting the values ,given that [tex]v=10m^3/kg[/tex]
[tex]10=0.001+x(57.76-0.001)\frac{m^3}{Kg}[/tex]
x=0.173
So quality of vapor is equal to 17.3%.
An electric heater draws 12 A from a 120 V power source. How much powe heater dissipate? (a) 10 W (b) 1200 W (c) 1440 W (d) 17,280 W
Answer:
c) 1440 W
Explanation:
P = V*i = (12A)*(120V) = 1440W
According to the scenario, the amount of power that is dissipated by the heater is 1440 W. Thus, the correct option for this question is C.
What is Power?Power may be defined as the amount of energy that is significantly transferred or converted per unit of time. The unit of power is the watt (W). It may be typically calculated with the help of the given formula:
P = W/Δt.According to the context of this question, the amount of power that is dissipated within the heater is calculated by the following formula:
P = V × i = 12 × 120 = 1440 W.Therefore, according to the scenario, the amount of power that is dissipated by the heater is 1440 W. Thus, the correct option for this question is C.
To learn more about Power, refer to the link:
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What is/are the benefit(s) of short fibre reinforcements? A)Increased stiffness only. B)Increased strength and increased Toughness. C) Increased Toughness and increased flexibility. D) None of the above.
Answer: B) Increased strength and increased toughness
Explanation: Short fibre reinforcement has the major property of being tough and has high strength. Short fibre reinforcement is basically a process of addition of the short fibre to the thermoplastic materials to make the improvement in their quality and working by increasing their strength.They also have application in many areas because of their hardness property as well as being cost -effective. Thus, the option (b) is the correct option.
If the compound swivel base is set on 60 degrees at the lathe centerline index, how many degrees will the reading be at the cross slide index? A. 45 B. 150 C. 30 D. 90
Answer:
C.30°
Explanation:
Given that compound swivel base is set on 60° at the lathe center line index.
We need to find reading on cross slide index
We know that relationship between center line index and cross slide index in angle 2∝=β
Where ∝ Angle of swivel and β is the reading on cross line index.
So by using above relationship between center line index and cross slide index
2∝=60°⇒∝=30°
So our option is C.
Harvesting wind energy using kites is: a) possible but currently very expensive. b) possible and currently inexpensive compared to wind turbines c) possible using a single kite.
Answer: b) possible and currently inexpensive as compared to wind turbines.
Explanation: Wind harvesting through kites is a process that will require less expenses in making and maintenance of it .Kites can be termed as the wind generator that is unconventional. The set up for the kite wind generator is also easy to install and also less costly as compared with turbines. So the correct option is option(a) .
A lake contains water at a maximum depth of 237.3 meters. This water has a density of 989 kg/m3 and the acceleration due to gravity at this location is 9.806 m/s2. The air above the water has a barometric pressure of 29.83 in of Hg where the altitude correct for pressure is -1.87 in of Hg to get absolute pressure. What is the absolute pressure at the bottom of the lake?
Answer:690.21 mm of Hg
Explanation:
Given data
depth of lake[tex]\left (h\right )[/tex]=237.3m
density of lake water[tex]\left ( \rho\right )[/tex]=[tex]989kg/m^3[/tex]
acceleration due to gravity[tex]\left ( g\right )[/tex]=[tex]9.806m/s^2[/tex]
air above water has a barometric pressure of 29.83in of Hg=711.2 mm of Hg
Altitude correct for pressure=1.87in of Hg=47.5 mm of Hg
Absolute pressure above water =711.2-47.5mm of Hg=663.7 mm of Hg
Absolute pressure at bottom of Lake=Pressure at surface level +[tex]\left ( \rho \times g\times h\right )[/tex]
Absolute pressure at bottom of Lake=663.7+[tex]\frac{989\times 9.81\273.3}{10^{5}}[/tex]
Absolute pressure at bottom of Lake=690.21 mm of Hg
A pendulum has an oscillation frequency (T) which is assumed to depend upon its length (L), load mass (m) and the acceleration of gravity (g). Determine the relationship between oscillation frequency, length, load mass and acceleration of gravity. Differentiate as well which variable does not affect the oscillation frequency.
Answer:
Mass does not affect oscillation frequency.
Explanation:
Let the bob of the pendulum makes a small angular displacement θ. When the pendulum is displaced from the equilibrium position, a restoring force tries to act upon it and it tries to bring the pendulum back to its equilibrium position. Let this restoring force be F.
Therefore, F = -mgsinθ
Now for pendulum, for small angle of θ,
sinθ[tex]\simeq[/tex]θ
Therefore, F = -mgθ
Now from Newton's 2nd law of motion,
F = m.a = -mgθ
[tex]\Rightarrow m.\frac{d^{2}x}{dt^{2}} = - mg\Theta[/tex]
Now since, x = θ.L
[tex]\Rightarrow L.\frac{d^{2}\Theta }{dt^{2}}= -g\Theta[/tex]
[tex]\Rightarrow \frac{d^{2}\Theta }{dt^{2}}= -\frac{g}{L}.\Theta[/tex]
[tex]\Rightarrow \frac{d^{2}\Theta }{dt^{2}}+\frac{g}{L}.\Theta =0[/tex]
Therefore, angular frequency
[tex]\omega ^{2}[/tex] = [tex]\frac{g}{L}[/tex]
ω = [tex]\sqrt{\frac{g}{L}}[/tex]
Also we know angular frequency is , ω = 2.π.f
where f is frequency
Therefore
2πf = [tex]\sqrt{\frac{g}{L}}[/tex]
f = [tex]\frac{1}{2 \pi }\sqrt{\frac{g}{L}}[/tex]
So from here we can see that frequency,f is independent of mass, hence it does not affect frequency.
Microchips found inside most electronic devices today are examples of what material A. Polymers B. Alloys C. Composites D. None of the above. E. Metals
Answer: A
Explanation:
Microchips are made out of silicone witch is a polymer.
Answer:
its a
Explanation:
What are units for heating capacity? Mark all that apply: a)- Tons b)- kJ/kg c)- kW d)- Btu
Answer:
(b) kJ/kg
Explanation:
The ratio of amount of energy required to change the temperature of the substance by certain magnitude and this magnitude of temperature change is known as heat capacity of the substance.
The expression for Heat capacity is:
C=E/ΔT
Where,
C is the Heat capacity
E is the energy absorbed/released
ΔT is the change in temperature
The SI unit of heat capacity is J/K.
(a) Tons represents the unit of mass (1000 kg)
(c) kW represents the unit of power (1000 W)
(d) Btu represents the unit of heat (1055 J)
The units from the options that can be a unit of heat capacity is (b) kJ/kg.
An electric motor is to be supported by four identical mounts. Each mount can be treated as a linear prevent problems due required that the amplitude of motion should not exceed 0.1 mm per 1 N of unbalance force. The mass of the motor is 120 kg and the operating speed is 720 rpm Use the concept of transfer function to determine the required stiffhess coefficient of each mount.
GIVEN:
Amplitude, A = 0.1mm
Force, F =1 N
mass of motor, m = 120 kg
operating speed, N = 720 rpm
[tex]\frac{A}{F}[/tex] = [tex]\frac{0.1\times 10^{-3}}{1} = 0.1\times 10^{-3}[/tex]
Formula Used:
[tex]A = \frac{F}{\sqrt{(K_{t} - m\omega ^{2}) +(\zeta \omega ^{2})}}[/tex]
Solution:
Let Stiffness be denoted by 'K' for each mounting, then for 4 mountings it is 4K
We know that:
[tex]\omega = \frac{2 \pi\times N}{60}[/tex]
so,
[tex]\omega = \frac{2 \pi\times 720}{60}[/tex] = 75.39 rad/s
Using the given formula:
Damping is negligible, so, [tex]\zeta = 0[/tex]
[tex]\frac{A}{F}[/tex] will give the tranfer function
Therefore,
[tex]\frac{A}{F}[/tex] = [tex] \frac{1}{\sqrt{(4K - 120\ ^{2})}}[/tex]
[tex]0.1\times 10^{-3}[/tex] = [tex] \frac{1}{\sqrt{(4K - 120\ ^{2})}}[/tex]
Required stiffness coefficient, K = 173009 N/m = 173.01 N/mm
The specific heat of aluminum is approximately 900 J/kg°C. If the temperature of a 5 kg specimen needs to be raised from 30°C to 1000°C, the amount of heat required will be equal to Select one: a)- 4365 kJ b)- 4365 Btu c)- 4365W d)- None of the above
Answer:
a) 4365 kJ
Explanation:
In any thermodynamic system, any heat change is accompanied by the change in temperature. The relation between heat released/gained in a system and the temperature is:
Q=mcΔT
where,
Q is the amount of heat absorbed or released
m is the mass
ΔT is the change in temperature
c is called the specific heat.
Specific heat is defined as heat gained by 1 unit mass of any sample to raise the temperature of the sample by 1 °Celsius.
Thus, from the question:
Mass of aluminum =5 kg
Final temperature = 1000°C
Initial temperature = 30°C
ΔT = (1000 -30)°C = 970°C
Specific heat of aluminum = 900 J/kg°C
Thus, Amount of heat required:
Q = 5 kg×900 J/kg°C×970°C = 4365000 J
The conversion of J into kJ is shown below:
1 J = 10⁻³ kJ
Thus, Heat gained by aluminum =4365000 ×10⁻³ J = 4365 kJ
A gas contained within a piston-cylinder undergoes the follow change in states: Process 1: Constant volume from p1 = 1 bar V1 = 2.6 m3 to state 2 with p2 = 2.7 bar Process 2: Compression to V3 = 1.5 m3, which the pressure-volume relationship is pV = constant. Process 3: Constant pressure to state 4, where V4 = 0.5 m3. Sketch the processes on p-V graph and evaluate the work for each process in kJ.
Answer:
Process 1:W=0
Process 2:W= -386.13 KJ
Process 3:W= -468 KJ
Explanation:
Process 1:[tex]P_1=1 bar,V_1=2.6m^3[/tex]
Process 2:[tex]P_2=2.7bar,V_2=2.6m^3[/tex]
Process 3:[tex]V_3=1.5 m^3[/tex]
[tex]V_4=0.5 m^3[/tex]
Process 1:
Work (W)=0 ,because it is constant volume process.
Process 2:
It is constant temperature process so PV=C
[tex]P_2V_2=P_3V_3[/tex]
[tex]P_3=\dfrac{P_2V_2}{V_3}[/tex]
[tex]P_3=\dfrac{2.7\times 2.6}{1.5}[/tex]
[tex]P_3=4.68 [/tex]bar
So work in constant temperature process
W=[tex]P_2V_2\ ln\dfrac{V_3}{V_2}[/tex]
W=[tex]270\times 2.6\ ln\dfrac{1.5}{2.6}[/tex] (1 bar=100KPa)
W= -386.13 KJ
Negative sign means it is compression process.
Process 3:
It is a constant pressure.
So work W=[tex]P_3(V_4-V_3)[/tex]
W=468(0.5-1.5) KJ
W= -468 KJ
Negative sign means it is compression process.
In the SI system of units, the absolute temperature is measured to be 303 K Its value in Fahrenheit is a-) 76 F b)- 86F c)-79 F d)- 82 F
Answer:
The correct answer is option B i.e. 86 f
Explanation:
The freezing point of water is 32°f and boiling point is 212 °f. Thus difference in boiling and freezing point is exactly come out to be 180°. therefore fahrenheit scale is 1/180 interval of both scale ( freezing and boiling point)
given data:
absolute temperature is 303 K
We know by general formula of temperature in fahrenheit
°F = [tex]\frac{9}{5}[/tex] × (K-273) +32
°F = [tex]\frac{9}{5}[/tex] × (303-273) +32
°F = 86 F
The pressure at any point in a static fluid depends only on the Select one a)- depth, surface pressure, and specific weight. b)- specific weight. c)- surface pressure and depth. d)- depth and container shape
Answer:
c). surface pressure and depth
Explanation:
We know that fluid pressure is measured in two different ways namely --
1. Pressure measured above complete vacuum or absolute zero is called Absolute Pressure.
2.Pressure measured above atmospheric pressure is called Gauge Pressure.
In the figure below, we can find the pressure at the point A in the static fluid inside the tank which is at a depth of h from the water surface.
Let the atmospheric pressure which is acting on the water surface be [tex]P_{atm}[/tex].
Let ρ be the density of water and g be the acceleration due to gravity.
Therefore we know that pressure at a point in a fluid is
P = ρ[tex]\times[/tex]g[tex]\times[/tex]h
Therefore total pressure acting on the point A in a fluid is
[tex]P_{tot}[/tex] = [tex]P_{atm}[/tex] + P
[tex]P_{tot}[/tex] = [tex]P_{atm}[/tex] + ρ[tex]\times[/tex]g[tex]\times[/tex]h
Thus, pressure at a point A in a static fluid depends on the surface pressure and the depth of the point from the free surface.
A roller support acts like a contact boundary condition as it can produce a reaction force as a push response to a body but will not produce a pull force to hold a body from moving away. a)True b)- False
Answer:
a) True
Explanation:
Roller can provide reaction for push support but it can not provide reaction for pull support.
From the free body diagram of roller and hinge support we can easily find that ,Roller providing vertical reaction and can not provide horizontal reaction.
On the other hand hinge support can provide reaction in both the direction.
So we can say that roller can not proved reaction for pull support.
The resistivity of mercury drops suddenly to zero at a critical temperature, maki mercury a superconductor below that temperature. ( True , False )
Resistance zero meaning superconductor, so True.
A plate clutch is used to connect a motor shaft running at 1500rpm to shaft 1. The motor is rated at 4 hp. Using a service factor, k=2.75 specify the torque rating for the clutch in lb-in.
Answer:
[tex](M_t)_{rated}=61.11lb-in[/tex]
Explanation:
speed of motor (N)=1500 rpm
power=4 hp = [tex]4 \times 0.7457 [/tex] =2.9828 KW
service factor(k)= 2.75
now,
[tex]KW=\frac{2\pi n M_t}{60 \times 10^6} \\2.9828=\frac{2\pi \times 1500 M_t}{60 \times 10^6}\\M_t=\frac{2.9828\times 60 \times 10^6}{2\pi \times 1500 }[/tex]
[tex]M_t= 18,989.09 \ N-mm= 168.06 lb-in[/tex]
torque rating
[tex](M_t)_{design}=k_s\times (M_t)_{rated}\\168.06= 2.75\times (M_t)_{rated}\\(M_t)_{rated}=\frac{168.06}{2.75} \\(M_t)_{rated}=61.11lb-in[/tex]
An aircraft increases its speed by 2% in straight and level flight. If the total lift remains constant determine the revised CL as a percentage of its original value to three significant figure
Answer:
96.1%
Explanation:
We know that lift force
[tex]F_L=\dfrac{1}{2}C_L\rho AV^2[/tex]
------------(1)
Where [tex]C_L[/tex] is the lift force coefficient .
ρ is the density of fluid.
A is the area.
V is the velocity.
Now when speed is increased by 2 % and all other parameter remains constant except [tex]C_L[/tex] .
Let;s take new value of lift force coefficient is [tex]C_L'[/tex] .
[tex]F_L=\dfrac{1}{2}C_L'\rho A(1.02V)^2[/tex]
-----------(2)
Now from equation 1 and 2
[tex]C_L\times V^2=C_L'\times1.0404 V^2[/tex]
⇒[tex]C_L'=0.961C_L[/tex]
So we can say that revised value of lift force coefficient is 96.1% of original value.
Give two methods on how powder is produced in powder metallurgy.
Answer:
Explanation:
Atomization using gas streamMolten metal is forced through a small orifice and is shatter by a jet of compressed air,inert gas .
In Atomization, the particles shape is analysed by the rate of solidification and varies from spherical to highly irregular shape.
Reductionoxide of metals are transformed to pure metal powder when undefended to under melting point gases results in a product of spongy material.
It is used for Iron,copper,tungsten,Nickel etc.
Answer:
(1)Atomizing process
(2)Gaseous reduction
Explanation:
The first step in powder metallurgy is the production of powder,because the property of the final product depends on the powder.
The methods for the production of powder are as follow
(1)Atomizing process
(2)Gaseous reduction
(1)Atomizing process:
In the Atomizing process the molten metal is passing through an orifice into a stream of inert gas.Due to this rapid cooling of metal occurs and then it will in very fine particle .
(2)Gaseous reduction:
In this process powder is producing by grinding of metallic oxide to a fine state,after that reducing it by carbon mono oxide.
In a quasi-static process, the system remains infinitesimally close to equilibrium throughout the process. a)True b) False
Answer:
It is True that in a quasi static process, the system remains infinitesimally close to equilibrium state throughout the process.
Explanation:
The literal meaning of the word "quasi" is 'almost' and static is 'rest', so quasi static state means almost at rest state of the system
It can be further explained as the process, in thermodynamics which allows the system to be carried to slowly to maintain its equilibrium or to remain in its internal equilibrium state. Such a process is known as quasi-static process. Such processes also allow all isothermal and adiabatic processes to operate slowly so as not to disturb their internal equilibrium. this makes the system to always remain in thermal equilibrium
The difference between absolute viscosity and kinematic viscosity is a. the absolute viscosity is the mass density divided by the kinematic viscosity c. absolute viscosity relates absolute pressure, film thickness and velocity while kinematic viscosity b. the kinematic viscosity is the absolute viscosity divided by the mass density relates shear stress and relative pressure e. all of the above
Answer:
b).the kinematic viscosity is absolute viscosity divided by mass density
Explanation:
Viscosity is a fluid property that offers resistance or obstruction to deformation or fluid flow.
Viscosity is of two types--
1. Absolute viscosity , μ
2. Kinematic viscosity, ν
Absolute viscosity :
Absolute viscosity is also called the dynamic viscosity. It is the internal resistance of the fluid to flow.
Kinematic viscosity :
Kinematic viscosity is the ratio of dynamic viscosity to the density of the fluid.
Absolute viscosity measures a fluid's internal friction, while kinematic viscosity is the ratio of absolute viscosity to the fluid's density. Viscosity affects how easily a liquid flows; higher intermolecular forces lead to higher viscosity, and this property is critical in fluid dynamics studies.
Explanation:The difference between absolute viscosity and kinematic viscosity is that absolute viscosity, often referred to simply as viscosity, represents the fluid's resistance to flow and is a measure of the internal friction within the fluid. Kinematic viscosity, on the other hand, takes the fluid's density into account and is the ratio of the fluid's absolute viscosity to its density. While absolute viscosity is measured in units like Pascal-seconds (Pa·s), kinematic viscosity is measured in square meters per second (m²/s).
Viscosity is influenced by intermolecular forces; liquids that can flow easily, such as ethanol, have lower viscosities, while substances like motor oil with higher intermolecular forces have higher viscosities. Measuring the time it takes for steel balls to fall through a fluid or for a fluid to flow through a narrow tube helps determine the fluid's viscosity. In other words, absolute viscosity is concerned with the sheer strength and flow resistance of a fluid, while kinematic viscosity relates to the movement of the fluid under the force of gravity considering its volume.
A horizontal jet of water strikes a vertical surface on a stationary cart that has a mass of 2.8 kg. The jet has a mass flow rate of 0.13 kg/s. The force required to hold the cart in place is 8N. What is the diameter of the nozzle? a. 1.6 mm b. 5.1 mm c. 3.4 mm d. 7.3 mm
Answer:
option a is correct answer i.e. d = 1.6 mm
Explanation:
From conservation principle
force by jet = force required to hold the jet
force by the jet is written as
[tex]force = \dot{m}(v_{1}-v_{2})\[/tex]
force required to hold the jet = 8N
[tex]\dot{m}(v_{1})\ = 8[/tex]
[tex]\dot{m}=0.13 kg/s[/tex]
[tex]v_{1} = 61.58 m/s[/tex]
we know that mass flow rate is given as
[tex]\dot{m}=\rho Av_{1}[/tex]
substituting value to get required diameter of the nozzle
[tex]0.13=1000*\frac{\pi }{4}d^{2}*61.58[/tex]
d = 1.6 mm
A(n)_____ is a device that provides the power and motion to manipulate the moving parts of a valve or damper used to control fluid flow. A. actuator B. pilot-operated regulator C. ratio regulator D. sliding stem
Answer:
Out of the four options provided
option A. actuator
is correct
Explanation:
An actuator is the only device out of the four mentioned devices that provides power and ensures the motion in it in order to manipulate the movement of the moving parts of the damper or a valve used whereas others like ratio regulator are used to regulate air or gas ratio and none mof the 3 remaining options serves the purpose
Is it possible that two types of dislocation coexist. a)-True b)- False
Answer:
yes it is possible
Explanation:
dislocation are if two type edge and screw dislocations
edge dislocation is a defect where an extra half plane is inside the lattice.
and screw dislocation is one in which can be assumed as the first half of the crystal slips over another.
These dislocation can coexist together where the line direction and burger vectors are neither parallel nor perpendicular then at that condition both dislocation screw and edge will coexist
Intrinsic semiconduction is a property of a pure material. (True , False )
True.
An intrinsic semiconductor is a pure semiconductor. At room temperature it behaves as an insulator because it only has a few free and hollow electrons due to thermal energy.
In an intrinsic semiconductor there are also electron fluxes and gaps, although the total current resulting is zero. This is because the action of thermal energy produces free electrons and gaps in pairs, so there are as many free electrons as there are gaps with which the total current is zero.
From your cooling load (8890.007 Btu/hr = 2.605kW, determine mass flow rate of refrigerants. Use the following "rule of thumb" estimate of a standard room of size 180 ft^2: 1 ton of refrigerant = 12,000Btu = 3.517 kW Rule of thumb: 1 ton cooling load = 300-400 ft^2
Answer:
0.740833917 ton/hr
Explanation:
Given:
Cooling load, 8890.007 Btu/hr = 2.605 kW
Room size = 180 [tex]ft^{2}[/tex]
According to the thumb rule
1 ton of refrigerant = 12000Btu
Hence for 8890.007 Btu/hr,
the mass flow rate of the refrigerant is =8890.007 / 12000
= 0.740833917 ton per hr
Hence, mass flow rate is 0.740833917 ton/hr
Heat conduction is a function of material property, temperature difference and fluid the geometry of the object. a) True b) False
Answer:
a)True
Explanation:
According to Fourier's law,It states that Heat transfer is directly proportionate to the temperature gradient.For unidirectional conduction
[tex]q''\alpha\dfrac{dT}{dx}[/tex]
Where q'' is the heat flux.
When This directly proportionate is remove then one constant will on that place and that constant is called conductivity of material.
[tex]q''=K\dfrac{dT}{dx}[/tex]
So total heat transfer Q
[tex]Q=KA\dfrac{dT}{dx}[/tex]
When conductivity (K) of material is not constant
K=[tex]K_0[/tex](a+bT) where a,b are constant.
So from the above expression we can say that heat transfer in material will depend on temperature difference,material property and on on geometry of object.
Give two causes that can result in surface cracking on extruded products.
Answer:
1. High friction
2. High extrusion temperature
Explanation:
Surface cracking on extruded products are defects or breakage on the surface of the extruded parts. Such cracks are inter granular.
Surface cracking defects arises from very high work piece temperature that develops cracks on the surface of the work piece. Surface cracking appears when the extrusion speed is very high, that results in high strain rates and generates heat.
Other factors include very high friction that contributes to surface cracking an d chilling of the surface of high temperature billets.
In shaft design, this of the following has the least influence on the shaft diameter to be determined: (a) Shaft deflection (b) Bearing type (c) Factor of safety (d) Rotational speed of the shaft
Answer: (d)Rotational speed of the shaft
Explanation: Shaft design is the design of a shaft that is used for defining the stresses at certain critical part of shaft. The shaft design has shaft diameter as a major part and this is determined by several factors like type of bearing , deflection, torque,safety factor etc.
But the least important factor for determining of the diameter is the rotational speed because it defines the rotation of an object around a particular axis, where is it states about the number of turns divisible by time. Therefore option(d) is the correct option.
Define spring stiffness and damping constant.
Answer Explanation:
SPRING STIFFNESS :The stiffness of a body is a measure of resistance offered by an elastic body to deformation.it is denoted by K every object has some stiffness for spring the spring stiffness is the force required to cause unit deflection
DAMPING CONSTANT: the damping constant is a number decided by manufacturer that describes the material property. Damping is an influence within an oscillatory system that has the effect of restricting its oscillation
If the specific gravity of a fluid is 0.721, its mass density is a. 44.99 lb/ft3 -b. 44.99 slugs/ft. c. 1.397 lb/ft d. 1.397 slugs/t e. none of these 11. A fluid a. is a gas. b. is a liquid. _c. is incompressible d. has a definite volume regardless of the size of the container e. a. and b. above.
Answer:
mass density of fluid is = 1000*0.721 = 721 kg/m3
so option e is correct
11. option e is correct ( a and b).
Explanation:
given data
specific gravity of fluid = 0.721
we know that mas density of water [tex]{\gamma _{water}}[/tex] is 1000 kg/m3
specific gravity of water is given as S.G
[tex]S.G = \frac{\gamma _{fluid} }{\gamma _{water}}[/tex]
mass density of fluid is = 1000*0.721 = 721 kg/m3
A fluid is combined form used for gas and liquid.
it offer negligible resistance to stress (shear stress)