what is the value of cos (L)?​

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that [tex]A \cap B[/tex] = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

[tex]A + (A \cap B) = 0.40[/tex]

[tex]A + 0.17 = 0.40[/tex]

[tex]A = 0.23[/tex]

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

[tex]B + (A \cap B) = 0.35[/tex]

[tex]B + 0.17 = 0.35[/tex]

[tex]B = 0.18[/tex]

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

Answer:

(a) Not a group

(b) Not a group

(c) Abelian group

Step-by-step explanation:

In order for a system <G,*> to be a group, the following must be satisfied

(1) The binary operation is associative, i.e., (a*b)*c = a*(b*c) for all a,b,c in G

(2) There is an identity element, i.e., there is an element e such that a*e = e*a = a for all a in G

(3) For each a in G, there is an inverse, i.e, another element a' in G such that a*a' = a'*a = e (the identity)

If in addition the operation * is commutative (a*b = b*a for every a,b in G), then the group is said to be Abelian

(a)  

The system <G,*> is not a group since there are no identity.  

To see this, suppose there is an element e such that  

a*e = a

then  

a-e = a which implies e=0

It is easy to see that 0 cannot be an identity.

For example  

2*0 = 2-0 = 2

Whereas

0*2 = 0-2 = -2

So 2*0 is not equal to 0*2

(b)

The system <G,*> is not a group either.

If A is a matrix 2x2 and the determinant of A det(A)=0, then the inverse of A does not exist.

(c)

The table of the operation G is showed in the attachment.

It is evident that this system is isomorphic under the identity map, to the cyclic group

[tex]\mathbb{Z}_{5}[/tex]

the system formed by the subset of Z, {0,1,2,3,4} with the operation of addition module 5, which is an Abelian cyclic group

We conclude that the system <G,*> is Abelian.

Attachment: Table for the operation * in (c)

Answer:

The equilibrium point is (3, 3620)

Step-by-step explanation:

We set the supply and the demand equation equal to each other and solve:

[tex]-338q+4634=400q^2+20\\400q^2+338q-4614=0[/tex]

We can solve by factoring:

[tex]2(q-3)(200q+769)=0[/tex]

Setting each factor equal to zero we get:

[tex]q=3\text{ or }q=\displaystyle-\frac{769}{200}[/tex]

Only a positive quantity makes sense, so q=3 is the equilibrium quantity.

To get the equilibrium price we just plug 3 in place of q in any of the functions. Let us use the demand function which is easier to handle:

[tex]D(3)=-338(3)+4634=3620[/tex]

Therefore the equilibrium price is p=3620

In ordered pair form the equilibrium point is (3, 3620)

Answer:

Step-by-step explanation:

Given that t A, B, and C are invertible matrices of the same

size.

To pr that [tex](ABC)^{-1} = C^{-1}B^{-1}A^{-1}.[/tex]

to pr that  [tex]( ABC) (C^{-1}B^{-1}A^{-1})=e[/tex]

LS=[tex]( AB(C (C^{-1})B^{-1}A^{-1})\\=ABIB^{-1}A^{-1})\\=A(BB^{-1})A^{-1})\\=AA^{-1})\\=I[/tex]

Thus proved

To show that the product of invertible matrices A, B, and C (ABC) is invertible and that its inverse is (ABC)-1 = C-1B-1A-1, we use the property that the inverse of a product is the product of inverses in reverse order, and the associativity of matrix multiplication.

A student asked to show that if A, B, and C are invertible matrices of the same size, the product ABC is invertible, and that the inverse of this product is (ABC)-1 = C-1B-1A-1.

To prove this, we can use the properties of matrix multiplication and inverses:

This completes the proof that the product ABC is invertible and its inverse is C-1B-1A-1

same as before here, the bird is up above and from there goes down, so we sum up both amounts.

[tex]\bf \stackrel{mixed}{528\frac{1}{5}}\implies \cfrac{528\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{2641}{5}}~\hfill \stackrel{mixed}{89\frac{3}{5}}\implies \cfrac{89\cdot 5+3}{5}\implies \stackrel{improper}{\cfrac{448}{5}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{2641}{5}+\cfrac{448}{5}\implies \stackrel{\textit{using an LCD of 5}}{\cfrac{(1)2641+(1)448}{5}}\implies \cfrac{3089}{5}\implies 617\frac{4}{5}[/tex]

Answer:

[tex]617\frac{4}{5}[/tex]

Step-by-step explanation:

We have been given that a bird flies from its nest [tex]528\frac{1}{5}[/tex] to the bottom of the canyon [tex]-89\frac{3}{5}[/tex].

First of all, we will convert both mixed fractions into improper fraction.

[tex]528\frac{1}{5}\Rightarrow \frac{2640+1}{5}=\frac{2641}{5}[/tex]

[tex]89\frac{3}{5}\Rightarrow \frac{445+3}{5}=\frac{448}{5}[/tex]

To solve our given problem, we will find difference of both elevations as:

[tex]\frac{2641}{5}-(-\frac{448}{5})[/tex]

[tex]\frac{2641}{5}+\frac{448}{5}[/tex]

[tex]\frac{2641+448}{5}[/tex]

[tex]\frac{3089}{5}[/tex]

[tex]617\frac{4}{5}[/tex]

Therefore, the bird flown [tex]617\frac{4}{5}[/tex] units.

Answer:

The number of seniors who scored above 96% is 1.

Step-by-step explanation:

Consider the provided information.

Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.

Now we need to find the number of seniors who scored above 96%

For this we need to find the two percent of 50.

2% of 50 can be calculated as:

[tex]\frac{2}{100}\times50[/tex]

[tex]\frac{100}{100}[/tex]

[tex]1[/tex]

Hence, the number of seniors who scored above 96% is 1.

Answer:

x = tex]5\frac{\textup{7}}{\textup{8}}\ in[/tex]

Step-by-step explanation:

Given:

Total height of the bench = 18 in

Depth of the stone bench = [tex]3\frac{\textup{3}}{\textup{8}}\ in[/tex] = [tex]\frac{\textup{27}}{\textup{8}}\ in[/tex]  = 3.375 in

Measure of stones = [tex]3\frac{\textup{1}}{\textup{2}}\ in[/tex] = [tex]\frac{\textup{7}}{\textup{2}}\ in[/tex]  = 3.5 in

measure of another stone =  [tex]5\frac{\textup{1}}{\textup{4}}\ in[/tex] = [tex]\frac{\textup{21}}{\textup{4}}\ in[/tex]  = 5.25 in

let the height of the third stone be 'x'

Now,

The total height of the bench = depth of bench + Measure of two stones + x

18 = 3.375 + 3.5 + 5.25 + x

or

x = 18 - 12.125

or

x = 5.875 in

or

x = tex]5\frac{\textup{7}}{\textup{8}}\ in[/tex]

Answer:

No, because these events are independent.

Step-by-step explanation:

When we roll one die (a fair die), we will have outcomes in the numbers from 1 to 6.

And when we flip a coin, we will have either a heads or a tails.

Now these two events are independent events as the occurrence of any result in one event is not affecting the result of second event,

Hence, these two are independent events. So, the answer is no, the occurrence of a particular outcome on the die will not affect the probability of a particular outcome on the coin.

Final answer:

The outcomes of a die roll and a coin toss are independent events, meaning the result of the die does not affect the result of the coin toss.

Explanation:

The occurrence of a particular outcome on the die does not affect the probability of a particular outcome on the coin because each event is independent of the other.

For example, if you roll a die and flip a coin, the result of the die does not influence the result of the coin toss as they are separate events.

Additionally, the concept of independence in probability states that the outcomes of the coin toss and die roll do not impact each other.

Answer:

16.

Step-by-step explanation:

The largest numerical value present in the set P is 10, then x is 4+10 = 14. Then the set P is

P = {14, 4, 6, 10, -2, 14, 6, 1, 14}.

Now, the range is the difference between the greatest and the smallest element in the set. The greatest number is 14 and the smallest is -2, then the range is

14-(-2) = 14+2 = 16.

Then the range of the set P is 16.

Answer:

Your column vector is:

[tex]\left[\begin{array}{c}15&10&5&0&-5&-10&-15&-20&-25\end{array}\right][/tex]

Step-by-step explanation:

The first step to solve your problem is knowing what is a column vector:

A column vector is a matrix that only has one column, and multiple rows.

The problem wants the vector to range from 15 to -25.

It means that the biggest value in the vector is 15, and the smallest is -25. Since it is from 15 to -25, the first element of your column vector is 15, and the last element is -25.

With a step size of 5

At each element, you decrease 5. So you have: 15,10,..,-20,-25.

The vector is:

[tex]\left[\begin{array}{c}15&10&5&0&-5&-10&-15&-20&-25\end{array}\right][/tex]

Answer with Step-by-step explanation:

We are given that two matrices A and B are square matrices of the same size.

We have to prove that

Tr(C(A+B)=C(Tr(A)+Tr(B))

Where C is constant

We know that tr A=Sum of diagonal elements of A

Therefore,

Tr(A)=Sum of diagonal elements of A

Tr(B)=Sum of diagonal elements of B

C(Tr(A))=[tex]C\cdot[/tex] Sum of diagonal elements of A

C(Tr(B))=[tex]C\cdot[/tex] Sum of diagonal elements of B

[tex]C(A+B)=C\cdot (A+B)[/tex]

Tr(C(A+B)=Sum of diagonal elements of (C(A+B))

Suppose ,A=[tex]\left[\begin{array}{ccc}1&0\\1&1\end{array}\right][/tex]

B=[tex]\left[\begin{array}{ccc}1&1\\1&1\end{array}\right][/tex]

Tr(A)=1+1=2

Tr(B)=1+1=2

C(Tr(A)+Tr(B))=C(2+2)=4C

A+B=[tex]\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]+\left[\begin{array}{ccc}1&1\\1&1\end{array}\right][/tex]

A+B=[tex]\left[\begin{array}{ccc}2&1\\2&2\end{array}\right][/tex]

C(A+B)=[tex]\left[\begin{array}{ccc}2C&C\\2C&2C\end{array}\right][/tex]

Tr(C(A+B))=2C+2C=4C

Hence, Tr(C(A+B)=C(Tr(A)+Tr(B))

Hence, proved.

Closure Property for the set of integers for Subtraction

Take two integers,

A=6

B=9

A-B

=6-9

= -3

Which is also an Integer.Hence Closure Property is satisfied by Integers with respect to Subtraction.

⇒Closure Property for the set of integers for Division

Take two integers,

A=6

B=9

[tex]\rightarrow \frac{A}{B}\\\\=\frac{6}{9}\\\\=\frac{2}{3}-----\text{Not an Integer}[/tex]

Which is not an Integer.Hence Closure Property is not satisfied by Integers with respect to Division.

To find the specific circle passing through points (2,3), (-3,2), and (0,0), we started by substituting these coordinates in the general circle equation. This gave us a system of equations, which when solved, resulted in the coefficients for the circle equation. The equation of the circle we were seeking is (x^2 + y^2)/13 - (3x/32) + (15y/32) = 0.

In order to find the equation for a specific circle we need to plugin the coordinates for (x, y) in the general equation a(x^2+ y^2) + bx + cy + d = 0 which represent three points on the circle. Let's start to solve this system using the points (2,3), (−3,2), and (0,0).

Now, we have a system of three equations with three variables that we can solve. By subtracting the second from the first to eliminate d and simplifying, we obtain 5b + c = 0. Substituting d = 0 into the first and second equations, we get 13a + 2b + 3c = 0 and 13a - 3b + 2c = 0. Solving this system gives a = 1/13, b = -3/32 and c = 15/32.

Therefore, the equation of the circle is (x^2 + y^2)/13 - (3x/32) + (15y/32) = 0.

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Answer:

8 rental movies will make the costs of the two stores be the same

Step-by-step explanation:

- Mr Cosgrove is comparing movie rentals deals

- Netflix charge a flat rate of $8.50

- Blockbuster charge $4.50 plus a $0.50 per movie

- We need to find how many movie rental make the costs of the two

  stores will be the same

- Assume that the number of rental movies is m

∵ Blockbuster charge $4.50 plus a $0.50 per movie

∴ Blockbuster cost = 4.50 + 0.50 m

∵ The cost of Netflix = 8.50

- Equate the two costs to find the number of the rental movies

∵ 4.50 + 0.50 m = 8.50

- Subtract 4.50 from both sides

∴ 0.50 m = 4

- Divide both sides by 0.50

∴ m = 8 movies

8 rental movies will make the costs of the two stores be the same

Answer: The proof is done below.

Step-by-step explanation:  Given that the square matrix  A is called orthogonal provided that [tex]A^T=A^{-1}.[/tex]

We are to show that the determinant of such a matrix is either +1 or -1.

We will be using the following result :

[tex]|A^{-1}|=\dfrac{1}{|A|}.[/tex]

Given that, for matrix A,

[tex]A^T=A^{-1}.[/tex]

Taking determinant of the matrices on both sides of the above equation, we get

[tex]|A^T|=|A^{-1}|\\\\\Rightarrow |A|=\dfrac{1}{|A|}~~~~~~~~~~~~~~~~~~~~[\textup{since A and its transpose have same determinant}]\\\\\\\Rightarrow |A|^2=1\\\\\Rightarrow |A|=\pm1~~~~~~~~~~~~~~~~~~~~[\textup{taking square root on both sides}][/tex]

Thus, the determinant of matrix A is either +1 or -1.

Hence showed.

Answer:

A) [tex]\frac{2469}{20000}[/tex]

B)  [tex]\frac{54321}{100000}[/tex]

Step-by-step explanation:

To answer this question first we define what are rational numbers.

A rational number is a number that can be expressed in the form of a fraction [tex]\frac{x}{y}[/tex], where x and y are integers and y ≠ 0.

a) 0.12345

This can be written in fraction form as

[tex]\frac{12345}{100000}[/tex]

Now, we simplify this fraction to lowest form. Simplified form of the above fraction is [tex]\frac{2469}{20000}[/tex]. This simplified form was obtained by dividing both numerator an denominator by 5.

b) This number can be written in fraction form as [tex]\frac{54321}{100000}[/tex]

Now, we simplify this fraction.

The simplified form of the above fraction is [tex]\frac{54321}{100000}[/tex] as the numerator and denominator have no common factor.

Answer: $59313.58

Step-by-step explanation:

Formula to find the accumulated amount of the annuity is given by :-

[tex]FV=A(\frac{(1+\frac{r}{m})^{mt})-1}{\frac{r}{m}})[/tex]

, where A is the annuity payment deposit, r is annual interest rate , t is time in years and m is number of periods.

Given : m= $2000 ; m= 1   [∵ its annual] ;   t= 10 years ;   r= 0.06

Now substitute all these value in the formula , we get

[tex]FV=(4500)(\frac{(1+\frac{0.06}{1})^{1\times10})-1}{\frac{0.06}{1}})[/tex]

⇒ [tex]FV=(4500)(\frac{(1.06)^{10})-1}{0.06})[/tex]

⇒ [tex]FV=(4500)(\frac{0.79084769654}{0.06})[/tex]

⇒ [tex]FV=(4500)(13.1807949423)[/tex]

⇒ [tex]FV=59313.5772407\approx59313.58 \ \ \text{ [Rounded to the nearest cent]}[/tex]

Hence, the accumulated amount of the annuity= $59313.58

Answer:

If x = -4, then -x = 4.

Step-by-step explanation:

The procedure for answering this question is straightforward, you just have to substitute the value of x, when you write -x:

If x = -4, then -x = -(-4) = 4 (remember the law of signs)

Therefore: -x = 4.

It actually holds for any real number.

The probability of selecting a red marble from the jar of marbles is 2/17.

To calculate the probability of selecting a red marble from the jar, we need to determine the total number of marbles in the jar and the number of red marbles.

Total number of marbles = 2 (red) + 3 (white) + 5 (blue) + 7 (green) = 17

Number of red marbles = 2

Now, the probability of selecting a red marble is given by:

Probability = (Number of red marbles) / (Total number of marbles) = 2 / 17

So, the correct probability of selecting a red marble from the jar is 2/17.

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Final answer:

The probability of selecting a red marble from the jar is [tex]\frac{2}{17}[/tex] since there are 2 red marbles out of a total of 17 marbles.

Explanation:

The probability of selecting a red marble from a jar of marbles containing two red marbles, three white marbles, five blue marbles, and seven green marbles can be calculated by dividing the number of red marbles by the total number of marbles in the jar. First, we determine the total number of marbles: 2 (red) + 3 (white) + 5 (blue) + 7 (green) = 17 marbles. Next, we calculate the probability of selecting a red marble by dividing the number of red marbles (2) by the total (17).

Therefore, the probability of selecting a red marble is [tex]\frac{2}{17}[/tex].

Answer:

The range represents the number of users each month for 24 months

Step-by-step explanation:

The range depends on the y axis. Looking at the y axis we see the number of users for each month. Looking at the x axis we see that it's 24 months not 20 months

From the graph, we can interpret the range represents the number of users each month for 24 months. Therefore, option B is the correct answer.

We need to find what can be interpreted from the range of the given graph.

The range is the difference between the smallest and highest numbers in a list or set. To find the range, first put all the numbers in order. Then subtract (take away) the lowest number from the highest.

From the given graph, we can see the x-axis represents the number of months and the y-axis represents the number of users.

So, the range represents the number of users each month for 24 months

20-15.8=4.2

Therefore, option B is the correct answer.

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Answer:

Claim : The average time spent on a delivery does not exceed 25 minutes.

n = 21

We are given that  p-value for the test was found to be .0284.

Now we are supposed to state the conclusions

a) At α = .025, we fail to reject [tex]H_0[/tex].

p value = 0.0284

α = 0.025

P value > α

So, we accept the null hypothesis i.e. we fail to reject null hypothesis.

b)At α = .05, we fail to reject [tex]H_0[/tex].

p value = 0.0284

α = 0.025

P value < α

So, we reject the null hypothesis

c)At α =.03, we fail to reject [tex]H_0[/tex].

p value = 0.0284

α = 0.025

P value < α

So, we reject the null hypothesis

d)At α =.02, we reject [tex]H_0[/tex].

p value = 0.0284

α = 0.025

P value > α

So, we accept the null hypothesis i.e. we fail to reject null hypothesis.

Answer: The attendance before the increase was 4712.

Step-by-step explanation:

Let the attendance before the increase be 'x'.

Rate of increment = 5%

so, Attendance after increment becomes

[tex]\dfrac{100+5}{100}\times x = 4948\\\\\dfrac{105}{100}\times x=4948\\\\1.05\times x=4948\\\\x=\dfrac{4948}{1.05}\\\\x=4712.38\\\\x=4712[/tex]

Hence, the attendance before the increase was 4712.

Final answer:

To find the original attendance, an equation was formulated where the original attendance (x) increased by 5% equals 4,948. By solving for x, the original attendance before the increase was determined to be approximately 4,712 when rounded to the nearest whole number.

Explanation:

The question asks to find the original attendance before a 5% increase that resulted in a final attendance of 4,948. To calculate the initial attendance, you can set up an equation where the original attendance (which we will call 'x') plus 5% of the original attendance equals the final attendance (4,948).

This can be expressed algebraically as:
x + 0.05x = 4948

Solving for x gives you:
1.05x = 4948
x = 4948 / 1.05
x = 4,712 (rounded to the nearest whole number)

Therefore, the attendance before the increase was approximately 4,712.

Answer:

[tex]52\times \frac{7}{6}[/tex]

[tex]60\frac{2}{3}\text{ pounds}[/tex]

Step-by-step explanation:

Given,

The total pounds eaten by cat in 3 weeks = [tex]3\frac{1}{2}[/tex]= [tex]\frac{7}{2}[/tex]

∵ Each day the pounds of eaten is same,

⇒ Total pounds eaten in each week = [tex]\frac{7}{6}[/tex]

∵ 1 year = 52 weeks,

So, the pounds eaten in 52 weeks or 1 year = 52 × pounds eaten in each week

= 52 × [tex]\frac{7}{6}[/tex]

Which is the required expression,

By solving it,

The number of pounds eaten by cat in a year

[tex]=\frac{364}{6}[/tex]

[tex]=60\frac{2}{3}[/tex]

Answer:

5000kg = 5.5 short tons

Step-by-step explanation:

This can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

Each kg has 0.0011 short tons. How many short tons are there in 5000 kg. So?

1kg = 0.0011 short tons

5000kg - x short tons

[tex]x = 5000*0.0011[/tex]

[tex]x = 5.5[/tex] short tons.

5000kg = 5.5 short tons

To convert 5000 kg to short tons, multiply by the conversion factor and round up.

The conversion factor between kilograms and short tons is 0.00110231. To convert 5000 kg to short tons, we multiply by the conversion factor:

5000 kg * 0.00110231 = 5.51155 short tons

Rounding up to the nearest 100th gives us 5.52 short tons.

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Sets and set operations are ways of organizing, classifying and obtaining information about objects according to the characteristics they possess, as objects generally have several characteristics, the same object can belong to several sets, an example is the subjects of a school , where students (objects) are classified according to the subject they study (set).

The intersection of sets is a new set consisting of those objects that simultaneously possess the characteristics of each intersected set, the intersection of two subjects will be those students who have both subjects enrolled.

The union of sets is a new set consisting of all the objects belonging to the united sets, the union of two subjects will be all students of both courses.

In this case there are three sets B, C and S of which we are given the following information:

Answer

n(BꓵSꓵC)=5

n(BꓵS)=10 – 5 = 5

n(BꓵC)=12 – 5 = 7

n[(BꓵC)ꓴ(BꓵS)ꓴ(CꓵS)]=21  – 5 – 5 – 7 = 4

n(B)=36 – 5 – 5 – 7 = 19

n(S)=30 – 5 – 5 – 4 = 16

n(C)=34 – 5 – 7 – 4 = 18

Answer:

(a) symmetric

(b) The mean, median, and mode may be the same value.

and, The mode is the tallest bar in a histogram.

(c) variance

Step-by-step explanation:

Data is said to be symmetric if it is not skewed. i.e. if it has peaked at the center of the distribution.

Skewness gives us an idea about the shape of the curve.

Kurtosis enables us to have an idea about the flatness and peakedness of the frequency.

Mode represents the highest repetition of the observation.

The mean, median, and mode can have the same value.

The histogram represents the frequency of observation by the length of the bar this is the same as Mode. Thus, the mode is the tallest bar in a histogram.

Variance is the square of standard deviation and it is defined as, the sum of the square of the distance of an observation from the mean.

So, Variance is the correct option.

Answer:

240

Step-by-step explanation:

Given:

The cost function for canoes, c(x) = 24,000 + 100x

Revenue function for canoes, R(x) = 200x

here, x is the number of canoes sold

Fixed cost = $24,000

Cost of production = $100

now at break even point, Revenue = cost

thus,

200x = 24,000 + 100x

or

100x = 24,000

or

x = 240 canoes

Hence, at breakeven, the number of canoes sold is 240

Answer:

[tex]\mathbb{Z}\times \mathbb{Z}=\{(a,b)\lvert a, b\in \mathbb{Z}\}[/tex]

Step-by-step explanation:

In general, the Cartesian product of two sets [tex]A,B[/tex] is a new set defined by

[tex]A\times B=\{(a,b)\lvert a\in A,b\in B\}[/tex]

The pair [tex](a,b)[/tex] is ordered pair because the order is important, that is to say, in general [tex](a,b)\neq (b,a)[/tex].

One of the most important Cartesian products in mathematics is [tex]\mathbb{R}\times \mathbb{R}=\{(x,y) \lvert x,y \in \mathbb{R}\}[/tex] which is precisely the Cartesian Plane xy. The set [tex]\mathbb{Z}\times \mathbb{Z}[/tex] is a subset of [tex]\mathbb{R}\times \mathbb{R}[/tex] which is the set of all the points in the Cartesian plane whose coordinates are integers numbers. So, sketching the set [tex]\mathbb{Z}\times \mathbb{Z}[/tex] we have a picture as the shown below.

The probability of selecting a cookie with either chocolate chips or pecans from a plate of 50 cookies is 36%.

The question asks about the probability of selecting a cookie with either chocolate chips or pecans from a plate of 50 cookies, with some overlapping flavors. Given the information:

Total cookies: 50

Chocolate chip cookies: 10

Pecan cookies: 14

Cookies with both flavors: 6

To calculate the probability of choosing a cookie with either chocolate chips or pecans (or both), we can use the formula:

P(C OR N) = P(C) + P(N) \'u2013 P(C AND N)

where:

P(C) is the probability of choosing a chocolate chip cookie,

P(N) is the probability of choosing a pecan cookie, and

P(C AND N) is the probability of choosing a cookie with both flavors.

Thus:

P(C) = 10/50 = 0.20,

P(N) = 14/50 = 0.28, and

P(C AND N) = 6/50 = 0.12.

Therefore:

P(C OR N) = 0.20 + 0.28 - 0.12 = 0.36 or 36%.

This is the probability that a randomly selected cookie from the plate will have either chocolate chips, pecans, or both.

Answer:

false

Step-by-step explanation: