What is the value of h when the function is converted to vertex form?

Note: Vertex form is p(x)=a(x−h)^2+k .
p(x)=x^2−14x+29

H = ___

Answers

Answer 1
h=7.

To convert to vertex form, we complete the square.  This means we move the constant, c, to the other side.

y=x²-14x+29
y-29 = x²-14x+29-29
y-29=x²-14x

To find the number that we then add to both sides, we look at the value of b (coefficient of x).  We take half of that number; -14/2 = -7.  Then we square it; (-7)²=49.  This means we add 49 to both sides:

y-29+49=x²-14x+49

Now we combine like terms on the left:
y+20=x²-14x+49

Write the right hand side as a square:
y+20 = (x-7)²

Now move the 20 on the left back to the right by subtracting it from both sides:
y+20-20=(x-7)²-20
y=(x-7)²-20

The value of h is 7.

Related Questions

Which equation has a slope of 3 and a y intercept of 4?

A.y = 3x - 4
B.y = 3x + 4
C.y = 4x - 3
D.y = 4x + 3

Answers

the answer to this question is B

The general equation in slope intercept form is given by:

[tex] y=mx+b [/tex]

where m is the slope and b is the y intercept.

Now we are given slope as 3 and y intercept as 4, plugging these values in the slope intercept form, we get

[tex] y=3x+4 [/tex]

Now if we compare the two equations, we see that option (b) y=3x+4 matches our requirement.

So answer is the equation with slope 3 and y intercept 4 is y=3x+4.

The shorter leg of a right triangle is 1414 feet less than the other leg. find the length of the two legs if the hypotenuse is 3434 feet.

Answers

let the width be x ft
the length will be (x+14) ft
hypotenuse is 34 ft
given that our triangle is right triangle, using Pythagorean theorem?
c^2=a^2+b^2
substituting our values in the formula we get:
34^2=x^2+(x+14)^2
1,156=x^2+x^2+28x+196
simplifying this we get
0=2x^2+28x-960
solving the quadratic equation we get:
x=16 or x=-30
therefore the width is 16 ft and the length is 16+14=30

15 4/5% of 50

A. .79 B. 79

C. 790 D. 7.9

Answers

15 4/5 is 15.8.  The word "of" means to multiply, and of course we have to change that percent into a decimal to use it in an equation.  .158 × 50 = x is our equation.  Doing the multiplication on the left will give us our x.  x = 7.9, D from above.

"The correct answer is B. 79.

To solve the given problem, we need to calculate 15 4/5 percent of 50. First, let's convert the mixed number to an improper fraction to make the calculation easier.

 15 4/5% as a fraction is 15 + 4/5, which can be written as 75/5 + 4/5 = 79/5.

Now, to find the percentage of 50, we multiply 50 by the fraction representing the percentage:

[tex]\[ \frac{79}{5} \times 50 = \frac{79 \times 50}{5} \][/tex]

Next, we simplify the multiplication:

[tex]\[ \frac{79 \times 50}{5} = \frac{3950}{5} \][/tex]

Now, we divide 3950 by 5:

[tex]\[ \frac{3950}{5} = 790 \][/tex]

However, since we are looking for 15 4/5 percent and not 15 4/5 times 50, we need to adjust our calculation by dividing by 100 to get the correct percentage:

[tex]\[ \frac{790}{100} = 79 \][/tex]

Therefore, the final answer is B. 79."

A ball made out of a special material is inflated such that its diameter changes from 12inches to 15 inches. What is the approximate change in the volume of the ball?

Answers

A ball should give you the idea that we’re dealing with spheres. The volume of a sphere is:

V = (4/3) • π • r^3

The initial radius is 6 inches (radius is half of diameter)
Plug in to get its volume:

V = (4/3) • π • (6)^3

V is about 904.7787 in^3

Now do the same for the enlarged sphere, with radius 7.5 inches

V = (4/3) • π • (7.5)^3

V is about 1767.1459 in^3

To find the change, get the difference between the two volumes:

(New Volume) - (Old Volume)

1767.1459 - 904.7787

The change is around 862.3672 in^3

Raj is 3 years older than Zia. The sum of the squares of their ages is 369. How old are they?

Answers

Let
x--------------> ages of Raj
y--------------> age of Zia

we know that
x=y+3-------------> equation 1
x²+y²=369-----------> equation 2

I substitute 1 in 2

(y+3)²+y²=369----------> y²+6y+9+y²=369---------> 2y²+6y-360=0
2y²+6y-360=0
using a graph tool-----------> to calculate the quadratic equation
see the attached figure

the solution is
y=12
x=y+3--------> x=12+3--------> x=15

the answer is
Raj is 15 years old
Zia is 12 years old

Final answer:

Zia's age is 12 and Raj's age is 15

Explanation:

To solve this problem, we can set up two equations using the given information. Let's assume Zia's age is x. Since Raj is 3 years older than Zia, Raj's age can be represented as x + 3.

The first equation is [tex]x^2 + (x + 3)^2 = 369.[/tex]

Simplifying this equation, we get [tex]x^2 + x^2 + 6x + 9 = 369.[/tex]

Combining like terms, we have [tex]2x^2 + 6x + 9 = 369.[/tex]

Next, we can rearrange the equation by subtracting 369 from both sides and combining like terms to get [tex]2x^2 + 6x - 360 = 0.[/tex]

Now, we can solve this quadratic equation for x using factoring, completing the square, or the quadratic formula. The solutions are x = -15 and x = 12.

Since age cannot be negative, Zia's age is 12 and Raj's age is 12 + 3 = 15.

if (1+sina)(1+sinb)(1+sinc)=(1-sina)(1-sinb)(1-sinc)=k then value of k=?
a. (cosacosbcosc)
b.(sinasinbsinc)
c. (3sinasinbsinc),

Answers

k = (1+sina)(1+sinb)(1+sinc) = (1-sina)(1-sinb)(1-sinc) Multiply both entities, k x k = (1+sina)(1+sinb)(1+sinc) x (1-sina)(1-sinb)(1-sinc) That gives k^2 = (1 - sin^2a)(1 - sin^2b)(1 - sin^2c) k^2 = (cos^2a) x (cos^2b) x (cos^2c) k = sqrt ((cos^2a) x (cos^2b) x (cos^2c)) k = cosacosbcosc option a is correct.

Carlos’s credit card has an APR of 14.78% and a grace period of 18 days, and Carlos pays his balance in full every month. If his last billing cycle ended on March 28, 2010, and he made his payment on April 13, 2010, Did he owe any interest on his last statements balance?

Answers

If Carlo’s last billing cycle ended on March 28, 2010, and he made his payment on April 13, 2010, he didn’t owe any interest on his last statement's balance because he paid within the grace period. 
THE ANSWER IS ......no, because he paid within the grace period

Bars of soap come in packages of 6 and packages of 8. The 6-bar pack costs $7.86, and the 8-bar pack costs $8.88. Which is the better deal? What is the
price per bar of the better deal?

Answers

7.86 / 6 = 1.31 per unit
8.88 / 8 = 1.11 per unit

the 8-bar pack is the better deal

HELPP needed due today !!

Answers

1. Negative linear association

Describe the vertical asymptotes and holes for the graph of y=x-4/x^2+3x+2,

Answers

You have a vertical asymptote at those points where the denominator is equal to zero, you have holes at those points where both the nominator and the denominator are equal to zero at the same time.

Therefore:
x - 4 = 0  
x = 4

x² + 3x + 2 = 0
(x + 2)(x + 1) = 0
x = -2 and x = -1

There are no points in which both numerator and denominator are equal to zero, therefore there are no holes, while x = -2 and x = -1 are vertical asymptotes.


Describe the graph of the following inequality: 2x - 5y ≤ 6

Answers

Final answer:

To graph the inequality 2x - 5y ≤ 6, plot the line 2x - 5y = 6 with a solid boundary, test a point to determine the solution region, and shade the region that satisfies the inequality, which is below and to the right of the boundary line.

Explanation:

To graph the inequality 2x - 5y ≤ 6, you must first draw the boundary line of the inequality. This line is created by graphing the equation 2x - 5y = 6.

Start by finding the intercepts. For the x-intercept, set y to 0 and solve for x, which gives x = 3. For the y-intercept, set x to 0 and solve for y, which gives y = -6/5. These two points can be used to draw the boundary line. Since the inequality is '≤', this line will be solid to show that points on the line satisfy the inequality.

Now you must determine which side of the line contains the solutions to the inequality. You can do this by choosing a test point that is not on the line, like (0,0). Substitute this point into the inequality: 2(0) - 5(0) ≤ 6 is true, so the area containing (0,0), which is below and to the right of the line, is the solution region. Shade this area to show all points that satisfy the inequality 2x - 5y ≤ 6.

The sum of 3 consecutive even numbers of 78

Answers

26, 24, 28 could be the answer
x+x+2+x+4=78
3x+6=72
3x=72
x=72/3
x=24

HELP!! ASAP!!!!! Which system of equations below has infinitely many solutions?
a) y = –3x + 4 and y = –3x – 4
b) y = –3x + 4 and 3y = –9x + 12
c) y = –3x + 4 and y = -1/3+ 4
d) y = –3x + 4 and y = –6x + 8

Answers

Hello,

Answer B since
(y=-3x+4)* 3==> 3y=-9x+12 which is the second equation ==>infinity many solutions.

Answer:

The correct option is B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

Step-by-step  explanation:

Consider the two linear equation:

[tex]a_1x+b_1y+c_1=0\ \text{and}\ \ a_2x+b_2y+c_2=0[/tex]

The pair of linear equation has infinitely many solutions when:

[tex]\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}[/tex]

Now consider the option.

Option a) [tex]y=-3x+4 \ \text{and}\ \ y=-3x-4[/tex]

The above equation can be written as:

[tex]y+3x-4=0 \ \text{and}\ \ y+3x+4=0[/tex]

Therefore,

[tex]\frac{1}{1}=\frac{3}{3}\neq\frac{-4}{4}[/tex]

Thus, this pair has no solution.

Now consider the option B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

The above equation can be written as:

[tex]y+3x-4=0 \ \text{and}\ \ 3y+9x-12=0[/tex]

Therefore,

[tex]\frac{1}{3}=\frac{3}{9}=\frac{-4}{-12}[/tex]

Thus, this pair has infinitely many solution.

Hence, the correct option is B. [tex]y=-3x+4 \ \text{and}\ \ 3y=-9x+12[/tex]

A plane flies round-trip to Philadelphia. It flies to Philadelphia at 220 miles per hour and back home with a tailwind at 280 miles per hour. If the total trip takes 6.5 hours, how many miles does the plane fly round-trip? 560 miles 800.8 miles 1,300 miles 1,601.6 miles

Answers

 1,601.6 miles is correct

What is the solution of log6x+log6(x+5)=2?

Answers

Answer:4

Step-by-step explanation:just did it on edge

To solve log6(x) + log6(x + 5) = 2, combine the logarithms, rewrite in exponential form, and solve the resulting quadratic equation. The solutions are x = -9 and x = 4, but since logarithms of negative numbers are undefined, the final answer is x = 4.

To solve this logarithmic equation, follow these steps:

Combine the logarithms: Use the property of logarithms that states logb(a) + logb(c) = logb(a × c).
So, we have: log6(x) + log6(x + 5) = log6(x(x + 5)).
This simplifies to log6(x² + 5x).Set the logarithmic expression equal to 2: log6(x² + 5x) = 2.Rewrite the equation in exponential form: Using the definition of a logarithm, a logarithm logb(y) = c can be rewritten as [tex]b^{\\c[/tex] = y. Thus, we get 6² = x² + 5x.
This simplifies to 36 = x² + 5x.Solve the quadratic equation: Rewrite the quadratic equation in standard form: x² + 5x - 36 = 0.
Then, factor the quadratic: (x + 9)(x - 4) = 0.Find the solutions: Set each factor to zero and solve for x.
x + 9 = 0 → x = -9
x - 4 = 0 → x = 4.Check the solutions in the original equation: Since the logarithm of a negative number is undefined, discard x = -9.
Therefore, the solution to the equation is x = 4.

Final Answer: x = 4.

In a class, every student knows French or German (or both). 15 students know French, and 17 students know German. What is the largest possible number of students in that class?

Answers

Solution:

we are given that

In a class, every student knows French or German (or both).

15 students know French, and 17 students know German.

Suppose there are x student who knows both French and German.

Then Total number of student in the class will be [tex] (15+17-x)=32-x [/tex]

But to guess the largest possible number of student in the class we can assume x=0

Hence the largest Possible number of Student in the class=32

In a billiards game, Pete hits a ball that is 20in. from a wall. The ball travels 34 in. until it hits the wall and bounces to a position that is 16 in. from the wall. What proportion can be used to find the distance, x, the ball traveled after it bounces off the wall to get to the ending position? CHECK ALL THAT APPLY!

options

34/x =20/16

20/16 = 34/x

16/20 = x/34

20/16 = x/34

Answers

Hello,

Using Thales, 34/x=20/16

Answer A

To find the distance the ball traveled after it bounces off the wall, we can use the proportion 34/x = 20/16, which simplifies to x = 27.2 inches.

To find the proportion that can be used to find the distance, x, the ball traveled after it bounces off the wall, we can use the equation:

34/x = 20/16

After cross multiplying, we get:

34 × 16 = 20x

Simplifying further:

544 = 20x

Dividing both sides by 20, we find:

x = 27.2

Therefore, the distance the ball traveled after it bounces off the wall is 27.2 inches.

What is the average of the first n positive even numbers?

Answers

The average of all of them is the same as the average of the first and last, the same as the middle number in the group:
  1 + n

Solution:

we have been asked to find the average of the first n positive even numbers.

Let the firm n positive even numbers be

[tex] 2,4,6,8,10,12,.........2(n-1), 2n [/tex]

As we know that average of numbers[tex] =\frac{\text{Sum of Numbers }}{Total number of Numbers}\\ [/tex]

Required Average[tex] =\frac{2+4+6+2(n-1)+2n}{n}\\ [/tex]

Required Average[tex] =\frac{2(1+2+3+....+(n-1)+n)}{n} [/tex]

As we know the sum of first n terms[tex] =\frac{n(n+1)}{2} [/tex]

Required Average[tex] =\frac{2n(n+1)}{2n}=n+1 \\ [/tex]


A line includes the points (2, 10) and (1, 4). what is its equation in slope-intercept form?

Answers

Hi!

This problem has two parts. First you need to find the slope, so let's do that. The equation for the slope is m = y2-y1/x2-x1

We can now plug the two given points into the equation. 
m = 10-4/2-1
m = 6/1
m = 6

Now that we know the slope, and one point we can put this in slope intercept form. Slope intercept form is y=mx + b

So now we can plug in one point and the slope to find b

10 = 6(2) + b
10 = 12 + b
-2 = b

Now that we know both m and b, we can plug only those two into the equation y=mx + b, and we have the equation.

The equation is y = 6x - 2

If x = 12.8, what is the value of 2(z - 4)? [Type your answer as a number.]
need help

Answers

If the z is supposed to be an x then the answer is 17.6

"Hope this is your question, if not I think you will, still be able to find an answer of your question based on this solution"

The expression is :

2(z-4)

so we may think that the given value is z = 12.8 instead of x=12.8, then only we can plug it in given expression.

so plugging z=12.8 in the expression:

2(12.8-4)

We will use PEMDAS rule here,

So simplifying parenthesis first,

12.8-4 = 8.8

Now multiplying the result 8.8 with 2 to get the answer,

8.8 *2 = 17.6

Answer : 2(z-4) = 17.6 for z=12.8

"hope this helps"

Which of the symbols correctly relates the two numbers below? Check all that apply.

55 ? 35

A.
B.
C. <
D.
E. =
F. >
The other symbols dont want to show so if its another on plz tell me or add me on fb if you guys wanna help me i need to finish this,

Answers

>
55>35

The correct answer is > because 55 is larger than 35 and that is the sign for larger than
                                                                                                                  

In a tessellation, what must the sum of the angles be where the vertices meet?
90° 180° 360° 60°

Answers

the interior angles must add up to 360°
C (360 degrees) is your answer

sum of 2x 2 + 3x - 4, 8 - 3x, and -5x 2 + 2.

Answers

 (2x² + 3x - 4) +  (8 - 3x) + (-5x² + 2)

=  2x² + 3x - 4 +  8 - 3x - 5x² + 2

= -3x² + 6

= 3(-x² + 2)

Final answer:

To sum the given polynomials, you combine like terms, resulting in the final expression of -3x^2 + 6.

Explanation:

The sum of the polynomials 2x2 + 3x - 4, 8 - 3x, and -5x2 + 2 can be found by combining like terms. This process involves adding the coefficients of terms with the same power of x.

Step 1: Identify and arrange like terms.

Terms with x2: 2x2 and -5x2Terms with x: 3x and -3xConstant terms: -4, 8, and 2

Step 2: Combine like terms.

For x2 terms: 2x2 + (-5x2) = -3x2For x terms: 3x - 3x = 0x (This term will cancel out)For constant terms: -4 + 8 + 2 = 6

Step 3: Write the sum of the polynomials.
The sum is: -3x2 + 6.

What is the perimeter of the triangle expressed as a polynomial? 8x-2 5x-4 9x-3

Answers

Add up the three expressions to get the perimeter. The perimeter is simply the sum of all sides.

(8x-2)+(5x-4)+(9x-3)
8x-2+5x-4+9x-3
(8x+5x+9x)+(-2-4-3)
22x-9

Answer: 22x-9

Solve this easy question and get points!!!

There are two trains. Both trains are going to the same place, taking the same stops, and are going the exact same speed. But one train arrives in
80 Mins and the other train arrives in 1 Hour and 20 Mins. How is this possible?

Answers

They arrive at the same time, for:

1 hour = 60 minutes

60 + 20 = 80 minutes

80 minutes = 80 minutes

Therefore, your answer is "yes it is possible"

hope this helps

Using the law of cosines, in triangle RST, if r=14 yd, s=9 yd, t=16 yd find m angle s


Help? Thank you

Answers

check the picture below.

[tex]\bf \textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)cos(C)\implies c = \sqrt{a^2+b^2-(2ab)cos(C)} \\\\\\ \cfrac{a^2+b^2-c^2}{2ab}=cos(C)\implies cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C\\\\ -------------------------------[/tex]

[tex]\bf s^2=r^2+t^2-2rt\cdot cos(S)\implies s^2-r^2-t^2=-2rt\cdot cos(S) \\\\\\ \cfrac{s^2-r^2-t^2}{-2rt}=cos(S)\implies \cfrac{r^2+t^2-s^2}{2rt}=cos(S) \\\\\\ cos^{-1}\left( \cfrac{r^2+t^2-s^2}{2rt} \right)=\measuredangle S\implies cos^{-1}\left( \cfrac{14^2+6^2-9^2}{2(14)(6)} \right)=\measuredangle S[/tex]

make sure your calculator is in Degree mode if you need ∡S in degrees.
10.05 I’m pretty sure

Multiple Choice
You can model the population of a certain city between 1945-2000 by the radical function P(x)=55,000 sqrt x-1945. Using this model, in which year was the population of that city 165,000?
A)1948
B)1951
C)1954
D)1957,

Answers

The answer is 1954. Letter C is correct
Solution:
If P(x) =  165,000
Then 
165,000 = 55,000(x - 1945)^(1/2)
 x= 1954

to check it, substitute x
165,000 = 55,000(1954 - 1945)^(1/2)
165,000 =165,000 

If exy = 3, then what is dy/dx at the point (1, ln3)?

Answers

if exy=3, then dy/dx will be found as follows:
differentiating our expression implicitly we get:
(x(dy/dx)+y)e^(xy)=0
N/B
when differentiating e^(xy) we apply chain rule. When differentiating xy, we use product rule. 
next, we substitute (1, ln(3)) and solve for dy/dx
(1(dy/dx)+ln(3))^(1ln(3))=0
((dy/dx)+ln(3))e^(ln(3))=0
but
e^(ln3)=3, this is because e and ln  are inverse of each other.

3((dy/dx)+ln(3))=0
dy/dx+ln (3)=0
dy/dx=-ln(3)
The answer is :
dy/dx=-ln(3)

Solve the system of equations and choose the correct ordered pair. 2x + 6y = 6 3x – 2y = 20

Answers

(6,-1)
Multiply each equation by the value that makes the coefficients of xx opposite.(−3)⋅(2x+6y)=(−3)(6)(-3)⋅(2x+6y)=(-3)(6)(2)⋅(3x−2y)=(2)(20)(2)⋅(3x-2y)=(2)(20)Simplify.−6x−18y=−18-6x-18y=-186x−4y=406x-4y=40Add the two equations together to eliminate xx from the system.Divide each term by −22-22 and simplify.Tap for more steps...y=−1y=-1Substitute the value found for yy into one of the original equations, then solve for xx.Tap for more steps...x=6x=6The solution to the independent system of equations can be represented as a point.(6,−1)

Answer:

solution is (6,-1)

Step-by-step explanation:

[tex]2x + 6y = 6[/tex]

[tex]3x – 2y = 20[/tex]

WE use elimination method to solve for x  and y

Multiply the second equation by 3

[tex]3x – 2y = 20[/tex] times 3

[tex]9x – 6y = 60[/tex]

[tex]2x + 6y = 6[/tex] , add both equations

------------------------------

[tex]11x = 66[/tex]

Divide both sides by 11

[tex]x=6[/tex]

Plug in 6 for x in first equation

[tex]2x + 6y = 6[/tex]

[tex]2(6) + 6y = 6[/tex]

[tex]12 + 6y = 6[/tex], subtract 12 on both sides

[tex]6y = -6[/tex]

divide both sides by 6

[tex]y=-1[/tex]

[tex]x=6  \ and \ y= -1[/tex]

A customer buys an apple pie for $8.04, 6 cloves of garlic for $0./9 each, and a quarts of milk for $1.31. You are working the cash register. The customer gives you a $5 bill, six $1 bills, and a quarter. The register tells you that you ow the customer $0.16 . Round the price of each item to the nearest $0.10 to estimate how much the customer owes.

Answers

Round 0.30 each (or $1.80 for all 6 of them), the milk is $1.30. Total of estimates is $11.10
 
 The customer gave you 5 + 6 + 0.25 or $11.25, which is very close (and slightly higher) than the total of your estimates. I'd guess the register is correct.
 
Actual value is $8.04 + 6*0.29 + 1.31 = 8.04 + 1.74 + 1.31 = $11.09. The register is definitely correct.

Final answer:

To estimate the total cost, round each item to the nearest $0.10, sum them up, and subtract from the amount given by the customer. The estimated total cost is $9.80, and the estimated change to be returned is $1.45.

Explanation:

To estimate the total amount the customer owes after rounding to the nearest $0.10, we need to perform the following calculations:

Apple pie: $8.04, rounded to $8.00

6 cloves of garlic: $0.09 each, so $0.09 x 6 = $0.54, rounded to $0.50

Quart of milk: $1.31, rounded to $1.30

The estimated total cost is $8.00 (apple pie) + $0.50 (garlic) + $1.30 (milk) = $9.80.

The customer gives a total of $5 + $6 + $0.25 = $11.25.

Subtracting the estimated total cost from the amount given by the customer:
$11.25 - $9.80 = $1.45, which is the estimated change to be returned to the customer.

Other Questions
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