what is the value of x?

What Is The Value Of X?

Answers

Answer 1

[tex]x^2=40^2+9^2\\x^2=1600+81\\x^2=1681\\x=\sqrt{1681}=41[/tex]

Answer 2

To solve this you must use Pythagorean theorem:

[tex]a^{2} +b^{2} =c^{2}[/tex]

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 9

b = 40

c = x

^^^Plug these numbers into the theorem

[tex]9^{2} +40^{2} =x^{2}[/tex]

simplify

81 + 1600 = [tex]x^{2}[/tex]

1681 = [tex]x^{2}[/tex]

To remove the square from x take the square root of both sides to get you...

41 = x  

Hope this helped!

~Just a girl in love with Shawn Mendes


Related Questions

Find the range of the following set of data.
23,50, 49, 48, 49, 32, 37, 40, 41, 42, 41, 41, 43​

Answers

Answer:

27

Step-by-step explanation:

The range is the greatest value subtract the smallest value

greatest value = 50 and smallest value = 23, so

range = 50 - 23 = 27

Answer:

27

Step-by-step explanation:

23,32,37,40,41,41,41,42,43,48,49,49,50.

Range=50-23=27

Find the area of the shaded region if the dimensions of the unshaded region are 20ft x 35ft.

Answers

Answer:

The correct answer option is A. 1397.46 ft^2.

Step-by-step explanation:

We are to find the area of the shaded region. For that, we will divide the figure into smaller shapes, find their areas separately and then add them up.

From the given figure, we can see that there are two semi circles )or say one whole circle if we combine them) at the ends while 2 rectangles at the top and bottom.

Radius of circle = [tex]\frac{20+7+7}{2} [/tex] = 17

Area of circle = [tex]\pi r^2 = \pi \times 17^2[/tex] = 907.92 square ft

Area of rectangles = [tex]2(l \times w) = 2(35 \times 7)[/tex] = 490 square ft

Area of shaded region = 907.9 + 490 = 1397.46 ft^2

Answer:

A.) 1,397.46 ft²

Step-by-step explanation:

I got it correct on founders edtell

joseph had started saving quarters,dimes,nickel and penny but is unable to give the
exact change for a hamburger costing $3.50.What the greatest amount of money he could have in coins.

Answers

Answer:

$3.49

12 quarters,4 dimes,1 nickle, 4 pennies

Step-by-step explanation:

First remember that;

Quarter=25 pennies

Dime=10 pennies

Nickel =4 pennies

I cent =0.01$

Given the amount as $3.50

Assume you use 4 quarters, this means a whole dollar, so it will be;

1 dollar = 4quarters

3 dollars=?

cross multiply

3×4=12 quarters

The remaining $0.49

Here identify 40 cents, which is 40 pennies

But 10 pennies=1 dime

so 40 pennies=?

cross-multiply

(40×1)÷10=4 dimes

and a nickel for 4 pennies.

When is a rhombus a rectangle?
À. When its sides are parallel
B. When its angles are convex angles
C. When its angles are right angles
D. When its sides are congruent

Answers

Answer:

c. when all angles are right angles

Step-by-step explanation:

C. When it’s angles are right angles

Find the value of the missing coefficient in the factored form of 27f^3 + 125g^3. 27f^3+125g^3=(3f+5g)(9f^2-?fg + 25g)^2

Answers

Answer:

15

Step-by-step explanation:

The formula for factoring a sum of cubes is:

[tex]a^3+b^3=(a+b)(a^2-ab+b^2)[/tex]

We have a=3f and b=5g here.

So a*b in this case is 3f*5g=15fg.

The ? is 15.

The value of the missing coefficient in the factored form of the sum of cubes 27f³ + 125g³ is 15, resulting in the complete factorization being (3f+5g)(9f² -15fg+25g²).

The expression 27f³ + 125g³ can be factored using the sum of cubes formula, which is a³ + b³ = (a + b)(a² - ab + b²).

Given [tex]27f^3+125g^3[/tex], we have [tex]a=3f[/tex] and [tex]b=5g[/tex]

Applying the sum of cubes formula, we get:

[tex]27f ^3+125g ^3 =(3f+5g)((3f) ^2 -(3f)(5g)+(5g)^ 2 )[/tex]

[tex]27f ^3 +125g ^3=(3f+5g)(9f ^2-15fg+25g ^2 )[/tex]

So, the missing coefficient in the factored form is 15.

Therefore, the factored form is,

[tex]27f ^3+125g ^3[/tex] is [tex](3f+5g)(9f^ 2-15fg+25g ^2 )[/tex]

The complete question is:

Find the value of the missing coefficient in the factored form of 27f³ + 125g³ .

27f³ + 125g³ =(3f+5g)(9f² -?fg+25g² )

The value of ? =

If the point (a,3) lies on the graph of the equation 5x + y = 8, then a= 1 -1 -7

Answers

So if x=a, then y is 3
5a+3=8
5a=5
a=1

Answer:

a=1

Step-by-step explanation:

Let's find out!

So we have the point (x,y)=(a,3) is on the equation 5x+y=8.

Let's replace x with a and y with 3. This gives us:

5x+y=8

5a+3=8

Subtract 3 on both sides:

5a    =5

Divide both sides by 5:

a     =5/5

a     =1

So the point has to be (1,3)

The circumference of a circle is 30t. What is its area? ​

Answers

Answer:

[tex]A=\frac{225t^2}{\pi}[/tex] given the circumference is 30t.

Step-by-step explanation:

The circumference of a circle is [tex]C=2\pi r[/tex] and the area of a circle is [tex]A=\pi r^2[/tex] assuming the radius is [tex]r[/tex] for the circle in question.

We are given the circumference of our circle is [tex]2 \pi r=30t[/tex].

If we solve this for r we get: [tex]r=\frac{30t}{2\pi}[/tex].  To get this I just divided both sides by [tex]2\pi[/tex] since this was the thing being multiplied to [tex]r[/tex].

So now the area is [tex]A=\pi r^2=\pi (\frac{30t}{2 \pi})^2[/tex].

Simplifying this:

[tex]A=\pi (\frac{30t}{2 \pi})^2[/tex].

30/2=15 so:

[tex]A=\pi (\frac{15t}{\pi})^2[/tex].

Squaring the numerator and the denominator:

[tex]A=\pi (\frac{(15t)^2}{(\pi)^2}[/tex]

Using law of exponents or seeing that a factor of [tex]\pi[/tex] cancels:

[tex]A=\frac{(15t)^2}{\pi}[/tex]

[tex]A=\frac{15^2t^2}{\pi}[/tex]

[tex]A=\frac{225t^2}{\pi}[/tex]

Which of the following is in the solution set of y < 8x + 3?
(10, 84)
(7, 52)
(7, 69)
(9, 88)

Answers

Answer:(7,52)

Step-by-step explanation:plug those values into the equation.

52<8(7)+3.

52<59.

Which value for y makes the sentence true? 8 - y = 9 - 3

Answers

Answer:

y=2

Step-by-step explanation:

8 - y = 9 - 3

Combine like terms

8 - y = 6

Subtract 8 from each side

8-8 - y = 6-8

-y = -2

Multiply each side by -1

-1 * -y = -2 *-1

y =2

Express the hcf of 234 and 111 as 234x and111y.where x and y are integers

Answers

Answer:

The HCF = 3.

Step-by-step explanation:

The prime factors of

234 = 2*3*3*13,

and of 111 = 3*37.

The only common factor is 3.

Answer:

(- 9 × 234 ) + (19 × 111 )

Step-by-step explanation:

Using the division algorithm to find the hcf

If a and b are any positive integers, then there exists unique positive integers q and r such that

a = bq + r → 0 ≤ r ≤ b

If r = 0 then b is a divisor of a

Repeated use of the algorithm allows b to be found

here a = 234 and b = 111

234 = 2 × 111 + 12 → (1)

111 = 9 × 12 + 3 → (2)

12 = 4 × 3 + 0 ← r = 0

Hence hcf = 3

We can now express the hcf (d) as

d = ax + by where x, y are integers

From (2)

3 = 1 × 111 - 9 × 12

From (1)

3 = 1 × 111 - 9( 1 × 234 - 2 × 111)

   = 1 × 111 - 9 × 234 + 18 × 111

   = - 9 × 234 + 19 × 111 ← in required form

with x = - 9 and y = 19

find the distance between the points (-3,2) and (0,3).

Answers

Answer:

The distance between (-3, 2) and (0,3) is √10.

Step-by-step explanation:

As we go from (-3,2)  to  (0,3), x increases by 3 and y increases by 1.

Think of a triangle with base 3 and height 1.  Use the Pythagorean Theorem to find the length of the hypotenuse, which represents the distance between the points (-3, 2) and (0, 3):

distance = √(3² + 1²) = √10

The distance between (-3, 2) and (0,3) is √10.

For this case we have that by definition, the distance between two points is given by:

[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]

We have the following points:

[tex](x_ {1}, y_ {1}): (- 3,2)\\(x_ {2}, y_ {2}) :( 0,3)[/tex]

Substituting:

[tex]d = \sqrt {(0 - (- 3)) ^ 2+ (3-2) ^ 2}\\d = \sqrt {(3) ^ 2 + (1) ^ 2}\\d = \sqrt {9 + 1}\\d = \sqrt {10}[/tex]

Answer:

The distance between the points is [tex]\sqrt {10}[/tex]

solve ABC
c=10, B=35°, C=65%​

Answers

Answer:

Part 1) The measure of angle A is [tex]A=80\°[/tex]

Part 2) The length side of a is equal to [tex]a=10.9\ units[/tex]

Part 3) The length side of b is equal to [tex]b=6.3\ units[/tex]

Step-by-step explanation:

step 1

Find the measure of angle A

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

[tex]A+B+C=180\°[/tex]

substitute the given values

[tex]A+35\°+65\°=180\°[/tex]

[tex]A+100\°=180\°[/tex]

[tex]A=180\°-100\°=80\°[/tex]

step 2

Find the length of side a

Applying the law of sines

[tex]\frac{a}{sin(A)}=\frac{c}{sin(C)}[/tex]

substitute the given values

[tex]\frac{a}{sin(80\°)}=\frac{10}{sin(65\°)}[/tex]

[tex]a=\frac{10}{sin(65\°)}(sin(80\°))[/tex]

[tex]a=10.9\ units[/tex]

step 3

Find the length of side b

Applying the law of sines

[tex]\frac{b}{sin(B)}=\frac{c}{sin(C)}[/tex]

substitute the given values

[tex]\frac{b}{sin(35\°)}=\frac{10}{sin(65\°)}[/tex]

[tex]b=\frac{10}{sin(65\°)}(sin(35\°))[/tex]

[tex]b=6.3\ units[/tex]

cos^2a/(1-tana)+sin^3a/(sina-cosa)=sina+cosa

Answers

Answer:

a=2*n*pi where n is an integer

Step-by-step explanation:

[tex]\frac{\cos^2(a)}{1-\tan(a)}+\frac{\sin^3(a)}{\sin(a)-\cos(a)}[/tex]

The denominators are different here so I'm going to try to make them the same.

I'm going to write everything in terms of sine and cosine.

That means I'm rewriting tan(a) as sin(a)/cos(a)

[tex]\frac{\cos^2(a)}{1-\frac{\sin(a)}{\cos(a)}}+\frac{\sin^3(a)}{\sin(a)-\cos(a)}[/tex]

I'm going to multiply top and bottom of the first fraction by cos(a) to clear the mini-fraction from the bigger fraction.

[tex]\frac{\cos^2(a)}{1-\frac{\sin(a)}{\cos(a)}} \cdot \frac{\cos(a)}}{\cos(a)}+\frac{\sin^3(a)}{\sin(a)-\cos(a)}[/tex]

Distributing and Simplifying:

[tex]\frac{\cos^3(a)}{\cos(a)-\sin(a)}+\frac{\sin^3(a)}{\sin(a)-\cos(a)}[/tex]

Now I see the bottom's aren't quite the same but they are almost... They are actually just the opposite. That is -(cos(a)-sin(a))=-cos(a)+sin(a)=sin(a)-cos(a).

Or -(sin(a)-cos(a))=-sin(a)+cos(a)=cos(a)-sin(a).

So to get the denominators to be the same I'm going to multiply either fraction by -1/-1... I'm going to do this to the second fraction.

[tex]\frac{\cos^3(a)}{\cos(a)-\sin(a)}+\frac{\sin^3(a)}{\sin(a)-\cos(a)} \cdot \frac{-1}{-1}[/tex]

[tex]\frac{\cos^3(a)}{\cos(a)-\sin(a)}+\frac{-\sin^3(a)}{\cos(a)-\sin(a)}[/tex]

The bottoms( the denominators) are the same now.  We can write this as one fraction, now.

[tex]\frac{\cos^3(a)-\sin^3(a)}{\cos(a)-\sin(a)}[/tex]

I don't know if you know but we can factor a difference of cubes.

The numerator is in the form of a^3-b^3.

The formula for factoring that is (a-b)(a^2+ab+b^2).

[tex]\frac{(\cos(a)-\sin(a))(\cos^2(a)+\cos(a)\sin(a)+\sin^2(a)}{\cos(a)-\sin(a)}[/tex]

There is a common factor of cos(a)-sin(a) on top and bottom you can "cancel it".  

So we now have

[tex]\cos^2(a)+\cos(a)\sin(a)+\sin^2(a)[/tex]

We can actually simplify this even more.

[tex]\cos^2(a)+\sin^2(a)=1[/tex] is a Pythagorean Identity.

So we rewrite [tex]\cos^2(a)+\cos(a)\sin(a)+\sin^2(a)[/tex]

as [tex]1+\cos(a)\sin(a)[/tex]

So that is what we get after simplifying left hand side.

So I guess we are trying to solve for a.

[tex]1+\cos(a)\sin(a)=\sin(a)+\cos(a)[/tex]

Subtract sin(a) and cos(a) on both sides.

[tex]\cos(a)\sin(a)-\sin(a)-\cos(a)+1=0[/tex]

This can be factored as

[tex](\sin(a)-1)(\cos(a)-1)=0[/tex]

So we just need to solve the following two equations:

[tex]\sin(a)-1=0 \text{ and } \cos(a)-1=0[/tex]

[tex]\sin(a)=1 \text{ and } cos(a)=1 \text{ I just added one on both sides}[/tex]

Now we just need to think of the y-coordinates on the unit circle that are 1

and the x-coordinates being 1 also (not at the same time of course).

List thinking of the y-coordinates being 1:

a=pi/2 , 5pi/2 , 9pi/2 , ....

List thinking of the x-coordinates being 1:

a=0, 2pi, 4pi,...

So let's come up with a pattern for these because there are infinite number of solutions that continue in this way.

If you notice in the first list the number next to pi is going up by 4 each time.

So for the first list we can say a=(4pi*n+pi)/2 where n is an integer.

The next list the number in front of pi is just even.

So for the second list we can say a=2*n*pi where n is an integer.

So the solutions is a=2*n*pi   ,    a=(4pi*n+pi)/2

We really should make sure if this is okay for our original equation.

We don't have to worry about the second fraction because sin(a)=cos(a) only when a is pi/4 or pi/4+2pi*n OR (pi+pi/4) or (pi+pi/4)+2pi*n.

Now the second fraction we have 1-tan(a) in the denominator, and it is 0 when:

tan(a)=1

sin(a)/cos(a)=1                       =>              sin(a)=cos(a)

So the only thing we have to worry about here since we said sin(a)=cos(a) doesn't hurt our solution is the division by the cos(a).

When is cos(a)=0?

cos(a)=0 when a=pi/2 or any rotations that stop there (+2npi thing) or at 3pi/2 (+2npi)

So the only solutions that work is the a=2*n*pi where n is an integer.

Answer:

[tex]\large\boxed{a=2k\pi\ for\ k\in\mathbb{Z}}[/tex]

Step-by-step explanation:

[tex]\bold{a=x}[/tex]

[tex]\text{The domain:}\\\\1-\tan x\neq0\ \wedge\ \sin x-\cos x\neq0\ \wedge\ x\neq\dfrac{\pi}{2}+k\pi\ (from\ \tan x)\\\\\tan x\neq1\ \wedge\ \sin x\neq\cos x\\\\x\neq\dfrac{\pi}{4}+k\pi\ \wedge\ x\neq\dfrac{\pi}{4}+k\pi\ for\ k\in\mathbb{Z}[/tex]

[tex]\dfrac{\cos^2x}{1-\tan x}+\dfrac{\sin^3x}{\sin x-\cos x}=\sin x+\cos x[/tex]

[tex]\text{Left side of the equation:}[/tex]

[tex]\text{use}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\dfrac{\cos^2x}{1-\tan x}=\dfrac{\cos^2x}{1-\frac{\sin x}{\cos x}}=\dfrac{\cos^2x}{\frac{\cos x}{\cos x}-\frac{\sin x}{\cos x}}=\dfrac{\cos^2x}{\frac{\cos x-\sin x}{\cos x}}=\cos^2x\cdot\dfrac{\cos x}{\cos x-\sin x}\\\\=\dfrac{\cos^3x}{\cos x-\sin x}\\\\\dfrac{\cos^2x}{1-\tan x}+\dfrac{\sin^3x}{\sin x-\cos x}=\dfrac{\cos^3x}{\cos x-\sin x}+\dfrac{\sin^3x}{\sin x-\cos x}\\\\=\dfrac{\cos^3x}{\cos x-\sin x}+\dfrac{\sin^3x}{-(\cos x-\sin x)}[/tex]

[tex]=\dfrac{\cos^3x}{\cos x-\sin x}-\dfrac{\sin^3x}{\cos x-\sin x}\\\\=\dfrac{\cos^3x-\sin^3x}{\cos x-\sin x}\qquad\text{use}\ a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=\dfrac{(\cos x-\sin x)(\cos^2x+\cos x\sin x+\sin^2x)}{\cos x-\sin x}\qquad\text{cancel}\ (\cos x-\sin x)\\\\=\cos^2x+\cos x\sin x+\sin^2x\qquad\text{use}\ \sin^2x+\cos^2x=1\\\\=\cos x\sin x+1[/tex]

[tex]\text{We're back to the equation}[/tex]

[tex]\cos x\sin x+1=\sin x+\cos x\qquad\text{subtract}\ \sin x\ \text{and}\ \cos x\ \text{from both sides}\\\\\cos x\sin x+1-\sin x-\cos x=0\\\\(\cos x\sin x-\sin x)+(1-\cos x)=0\\\\\sin x(\cos x-1)-1(\cos x-1)=0\\\\(\cos x-1)(\sin x-1)=0\iff \cos x-1=0\ or\ \sin x-1=0\\\\\cos x=1\ or\ \sin x=1\\\\x=2k\pi\in D\ or\ x=\dfrac{\pi}{2}+2k\pi\notin D\ for\ k\in\mathbb{Z}[/tex]

what is the p(x) and profit for selling 100 tickets

Answers

Answer:

P(x) is the profit amount from selling tickets.

P(100) = $160

Step By Step Explanation:

First, plug in r(x) and c(x) into the p(x) equation:

p(x) = r(x) - c(x)

p(x) = (10x) - (8x+40)

Then simplify it:

p(x) = 10x - 8x - 40 {just distribute a +1 into the parentheses}

p(x) = 2x - 40 {combine like terms}

Now substitute 100 for x:

p(100) = 2(100) - 40

Then solve:

p(100) = 200 - 40

p(100) = 160

x to the 2nd power + 3=12

Answers

Answer:

x = ±3

Step-by-step explanation:

x^2 +3 = 12

Subtract 3 from each side

x^2 +3-3 = 12-3

x^2 = 9

Take the square root of each side

sqrt(x^2) =±sqrt(9)

x = ±3

Which of the following shows the solution set of the inequality
1/2x<-3?​

Answers

Answer:

B

Step-by-step explanation:

1/2x < -3

Multiply each side by 2

1/2x *2 < -3*2

x < -6

Since x is less than -6, there is an open circle at -6

Less than means the line goes to the left

What is the measure of angle x, in degrees

Answers

Option C ,

40 degrees

Because angle Z was 70 (isosceles triangle)

Then 180-140=40 degrees

Graph the pair of equations on the same axes and state whether they are parallel, perpendicular, or neither.

Answers

Answer:

Parallel

Step-by-step explanation:

Instead of putting this and slope intercept form.  I'm going determine the

x-intercept and the y-intercept of both.

The x-intercept can be found by setting y to 0 and solving for x.

The y-intercept can be found by setting x to 0 and solving for y.

So let's look at 3x-2y=5.

x-intercept?

Set y=0.

3x-2(0)=5

3x       =5

 x       =5/3

y=intercept?

Set x=0.

3(0)-2y=5

     -2y=5

        y=-5/2

So we are going to graph (5/3,0) and (0,-5/2) and connect it with a straightedge.

Now for 6y-9x=6.

x-intercept?

Set y=0.

6(0)-9x=6

     -9x=6

        x=-6/9

        x=-2/3

y-intercept?

Set x=0.

6y-9(0)=6

6y        =6

 y        =1

So we are going to graph (-2/3,0) and (0,1) and connect it what a straightedge.

After graphing the lines by hand you can actually do an algebraic check to see if they are parallel (same slopes), perpendicular (opposite reciprocal slopes), or neither.

Let's find the slope by lining up the points and subtracting then putting 2nd difference over 1st difference.

So the points on line 1 are: (5/3,0) and (0,-5/2)

 (5/3 ,  0  )

- (0   ,-5/2)

-----------------

5/3       5/2

The slope is (5/2)/(5/3)=(5/2)*(3/5)=3/2.

The points on line 2 are: (-2/3,0) and (0,1)

 (-2/3 , 0)

- (   0  ,  1)

-----------------

 -2/3      -1

The slope is -1/(-2/3)=-1*(-3/2)=3/2.

The slopes are the same so they are parallel. The line lines are definitely not the same; if you multiply the top equation by -3 you get -9x+6y=-15 which means the equations are not the same.  Also they had different x- and y-intercepts.  So these lines are parallel.

This is what we should see in our picture too.

The lines 3x - 2y = 5 and 6y - 9x = 6 are parallel lines

How to find if the lines are parallel

The lines 3x - 2y = 5 and 6y - 9x = 6 are parallel lines if their their slopes are equal

Lets rewrite the equation to be in slope intercept form: y = mx + b. where m is the slope

3x - 2y = 5

2y = 3x - 5

y = 3x/2 - 5/2. slope is 3/2

6y - 9x = 6

6y = 9x + 6

y = 3x/2 + 1. slope is 3/2

Comparing the equations with equal slope of 3/2, and from the graph shows that they are parallel lines

Learn more about parallel lines

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The blue segment below is a diameter of O. What is the length of the radius of the circle?

Answers

Diameter= 2 times the radius

2r=d
2r=10.2
R= 10.2/2
R=5.1

Therefore, the radius is 5.1 units which makes the answer choice C correct.

Hopefully, this helps!

Answer:

c 5.1

Step-by-step explanation:

The diameter of the circle is 102.

The radius is half of the diameter

r =d/2

r =10.2 /2 =5.1

What is the median of the following data set?
{5, 2, 9, 7, 4}

5

7

8

9

Answers

The answer is five
1) put the numbers in order
2) find the middle number

Answer:

a

Step-by-step explanation:

In 1989 a locally-owned car company sold 2,881 cars. 

In 2002, the car sales rose to 4,232. 

What was the average rate of change for the total number of cars sold?

 A. 

1,351 cars per year

 B. 

9.62 cars per year

 C. 

3,557 cars per year

 D. 

104 cars per year​

Answers

D. 103 12/13 or about 104

First sort the data into two sets of points, (1989,2881), (2002, 4232).

Now use the slope equation with your numbers.

(y2-y1)/(x2-x1)

(4232-2881)/(2002-1989)

1351/13=

103 12/13 or about 104

Scientists released 6 rabbits into a new habitat in year 0. Each year, there were four times as
many rabbits as the year before. How many rabbits were there after x years? Write a function
to represent this scenario.

Answers

The function that represents the given scenario is; f(x) = 6(4)ˣ

How to create an exponential growth function?

We know the general formula for this population function is;

f(x) = abˣ

where;

a is initial population

b is the common ratio

x is number of years

We are given;

a = 6

b = 4

Thus;

f(x) = 6(4)ˣ

Read more about exponential function at; https://brainly.com/question/11464095

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Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located.
x2 +3x -4 = 0

Answers

Answer:

x = -4 and x=1

Step-by-step explanation:

The solutions to the equation x^2 +3x -4 = 0 will be given by the points at which the graph intercepts the x-axis.

By looking at the graph, we can clearly see that the graph intercepts the x-axis at x=-4 and x=1.

One of the roots is located between -4 and -3, and the other one between 0 and 1.


20 = –d + 16

–4

–6

4

–10

Answers

Answer:

d=-4

Step-by-step explanation:

20 = –d + 16

Subtract 16 from each side

20-16 = –d + 16-16

4 = -d

Multiply each side by -1

-1 *4 = -1 * -d

-4 =d

Megan paints her locker red, white, and blue.
She paints 9/20 of the locker red, 15% of the
locker white, and 0.4 of the locker blue.
Complete the table below.​

Answers

Answer:

red: 9/20, 0.45, 45%

White: 15%, 0.15, 3/20

Blue: 0.4, 2/5, 40%

Step-by-step explanation:

For red: you start with 9/20. It’s best to get to a denominator of 10. So divide each number by 2. You would get 4.5/10. Then change to a percent by moving the decimal of the numerator one to the right and changing it to percent. 4.5 -> 45. -> 45%. Then for the decimal, divide 45 by 100. 45/100 = 0.45.

For white: you start with 15%. Divide by 100. 15/100=0.15. Put into a fraction with a denominator of 100. It would be 15/100. Simplify. Each number can be divided by 5, so your fraction would be 3/20.

For blue: you start with 0.4. Turn this into a fraction. Since there is one decimal place, it can have a denominator of 10. The fraction is 4/10, simplified to 2/5. Using the fraction 4/10, the percent would be 40%.

I hope this helps!

Carrie has 300 marbles 25 of the marbles are green 15% of the marbles are red and the rest of the marbles are blue how many blue marbles does he have​

Answers

Answer:

230.

Step-by-step explanation:

[tex] \: \: \: \: 300 - 25 - \frac{15}{100} \times 300 = \\ = 275 - 45 = \\ = 230[/tex]

Hope this helps!

Answer:

230 blue marbles

Step-by-step explanation:

In order to answer this question, we need to find how many marbles are red.

We know that 25 marbles are green

15% of the marbles are red.

There are a total of 300 marbles.

We would multiply 300 by 0.15 to find how many marbles are red.

[tex]300*0.15=45[/tex]

45 marbles are red.

In the question, it says the rest of the marbles are blue.

This means that we would subtract 300 by 25 and 45 to find how many marbles are blue.

[tex]300-25-45=230[/tex]

This means that 230 marbles are blue.

I hope this helps!Best regards,MasterInvestor

WHOEVER ANSWERS FIRST GETS BRAINLIEST!!!!

Which statements are true regarding the sequence below?

Check all that apply.


A: The domain is a set of natural numbers

B: The range is a set of natural numbers

C: The recursive formula representing the sequence is f(x + 1) = 3/2(f(x )) when f(1) = 4.

D: An explicit formula representing the sequence is

f(x) = 4 (3/2)^x

E: The sequence shows exponential growth.

Answers

Answer:

A, C and E are true.

Step-by-step explanation:

The domain is a set of natural numbers.

The recursive formula is correct:

When x = 1, f(x) = 4 and f(x + 1) = f(2) = 3/2 f(x) = 3/2 * 4 = 6.

It is also true for the other points on the graph.

D is  incorrect.

E is correct exponential growth with the formula  4(3/2)^(x-1).

Answer:

A and C

Step-by-step explanation:

10/3 x 6/5 is 4                                                                                                                      

It can be represented using the formula f(x + 1) = Six-fifths(f(x)) when f(1) = Ten-thirds

It can be represented using the formula f (x) = ten-thirds (six-fifths) Superscript x minus 1. edge 2020-2021

What is the slope-intercept form of y + 6 = 2(x + 2)?

Answers

Answer:

y=2x-2

Step-by-step explanation:

in slope intercept form we need make in this formula..

y=Mx+c

Answer:

y = 2x - 2

Step-by-step explanation:

Given

y + 6 = 2(x + 2) ← distribute

y + 6 = 2x + 4 ( subtract 6 from both sides )

y = 2x - 2 ← in slope- intercept form

What is the value of y in this simplified expression?
k + m 10

Answers

Answer:

y=5

x=7

Step-by-step explanation:

When given an expression in the form a⁻ᵇ the expression is the same as 1/aᵇ where  a and b are integers.

Solving the question by giving the equivalents of the expression:

Therefore (-j)⁻⁷ is the same as 1/j⁷

The value of x=7

k⁻⁵+m⁻¹⁰=1/k⁵+1/m¹⁰

Therefore the value of y is 5.

Question 1:

For this case we have that by definition of properties of powers it is fulfilled that:

[tex]a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}[/tex]

So, if we have the following expression:

[tex](-j) ^ {- 7}[/tex]

We can rewrite it as:

[tex]\frac {1} {(- j) ^ 7}[/tex]

So we have to:

[tex]x = 7[/tex]

ANswer:

[tex]x = 7[/tex]

Question 2:

For this case we have that by definition of properties of powers it is fulfilled that:

[tex]a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}[/tex]

If we have the following expression:

[tex]k^{-5}+m^{-10}[/tex]

We can rewrite it as:

[tex]\frac {1} {k ^ 5} + \frac {1} {m ^ {10}}[/tex]

So we have[tex]y = 5[/tex]

Answer:

[tex]y = 5[/tex]

5/7 = y/6
Solve the following proportion for y
Round your answer to the nearest tenth

Answers

Answer:

The value of y = 4.3

Step-by-step explanation:

It is given that,

5/7 = y/6

To find the value of y

We have, 5/7 = y/6

(5 * 6) = (y * 7)

y * 7 = 5 * 6

y = (5 * 6)/7

 = 30/7

 = 4.29

 ≈ 4.3

Therefore the correct answer, the value of y = 4.3

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