what is the value of x?

Answer: -6

Step-by-step explanation:

-5x = 30

x = 30/-5

x = -6

Hope it helped!

Answer:

[tex]\large\boxed{y-8=-\dfrac{2}{3}(x+3)}[/tex]

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

We have the equation of a line in the slope-intercept form

[tex]y=-\dfrac{2}{3}x+6\Rightarrow m=-\dfrac{2}{3}[/tex]

and the point (-3, 8).

Substitute:

[tex]y-8=-\dfrac{2}{3}(x-(-3))\\\\y-8=-\dfrac{2}{3}(x+3)[/tex]

Answer:

subtract 2 from each side and o think u decide the last two numbers

Answer:

Step-by-step explanation:2-10x=7

First you have to subtract you 2 on both sides so it would 7-2= 5

You are left with -10x =5

Then you divide your -10x by -10 to get rid of your x

Last you divide 5/-10

Answer:

The answer is B. 20in.

Step-by-step explanation:

The parallel sides have to be the two bases (b1 and b2) = 80in.  

h = height or altitude.  

h = 2(800)/b1+b2  

h = 1600/80  

h = 20 in.

Answer:

The height of the Trapezoid is 20 inches

Step-by-step explanation:

Given Parameters

Shape: Trapezoid

Area of the Trapezoid = 800in²

Sum of opposite parallel sides = 80 in

Required: Height of the Trapezoid...

Are of trapezoid is calculated using the following formula:

A = ½(a + b) * h

Where a + b = sum of the opposite parallel sides

h = height.

A = Area.

By comparison, we have that

A = 800 in²

a + b = 80 in

By substituton, we have that

A = ½(a + b) * h becomes

800 = ½(80)h

800 = ½ * 80 * h

800 = 40 h---- divide through by 40

800/40 = 40h/40

20 = h --- reordsr

h = 20in

Hence, the height of the Trapezoid is 20 inches

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept → (0, b)

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

From the graph we have the points (0, -2) and (6, 7).

(0, -2) → b = -2

Calculate the slope:

[tex]m=\dfrac{7-(-2)}{6-0}=\dfrac{9}{6}=\dfrac{9:3}{6:3}=\dfrac{3}{2}[/tex]

Put the value of b and m to the equation of the line in the slope-intercept form:

[tex]y=\dfrac{3}{2}x-2[/tex]

=====================================

<, > - dotted line

≤, ≥ - solid line

<, ≤ - shaded region below the line

>, ≥ - shaded region above the line

======================================

We have the soli line (≤ or ≥).

Shaded region is above the line (> or ≥)

Therefore we have the answer: [tex]y\geq\dfrac{3}{2}x-2[/tex]

Convert to the standard form: [tex]Ax+By=C[/tex]

[tex]y\geq\dfrac{3}{2}x-2[/tex]            multiply both sides by 2

[tex]2y\geq3x-4[/tex]             subtract 3x from both sides

[tex]-3x+2y\geq-4[/tex]          change the signs

[tex]3x-2yleq4[/tex]

Final answer:

The algebraic expression for the reduced price of the game system is p - $99, where p represents the original price in dollars.

Explanation:

To express the reduced price of the game system algebraically, we start with the original price, represented by the variable ( p ), and subtract the reduction amount of $99. Mathematically, this can be represented as p - $99.

This expression signifies that we are taking the original price ( p ) and reducing it by $99 to find the new price after the discount. It's essential to understand that algebraic expressions provide a concise and general way to represent mathematical relationships.

In this case, the expression p - $99 encapsulates the idea of reducing the original price by $99, allowing us to calculate the reduced price for any given original price represented by the variable ( p ). This algebraic representation is flexible and can be applied to various scenarios involving discounts or reductions.

Answer:

-19/10,-18/10,-17/10

Step-by-step explanation:

multiply the both numbers up and down by 10.

then find the numbers

Answer:-1, 0, -1.33

Step-by-step explanation: Rational numbers include those with repeating decimals, natural, counting, etc.

Answer:

Step-by-step explanation:

Remember that polynomials involve ONLY integer powers of x.  x^(3/2) does not satisfy that criterion.  

Answer: OPTION B.

Step-by-step explanation:

In order to write a polynomial in Standard form you must arrange the terms by decreasing order of degree.

Then, given the polynomial:

[tex]\frac{x}{4} -2x^5 +\frac{x^3}{2}+1[/tex]

You must observe the exponent of each term of the polynomial and then arrange them from highest degree to lowest degree. Then, this polynomial written in Standard form is:

 [tex]-2x^5 +\frac{x^3}{2}+\frac{x}{4}+1[/tex]

Answer:

1 to 1

Step-by-step explanation:

8 to 8 = 8:8 = 8/8

You can treat a ratio as a fraction. Reduce the fraction 8/8 by dividing the numerator and denominator by 8.

8/8 = 1/1

8 to 8 = 1 to 1

Answer:

1:1

Step-by-step explanation:

A ratio says that "for every _ of this quantity, you have _ of another quantity". This is just saying for every 8 of one thing, you have 8 of another. And then you can simplify, just like a fraction.

Answer:-11x+6

Step-by-step explanation:

(-7x+1)-(4x-5)

collect the like terms and then calculate the sum

-7x+1-4x+5

-11x+1+5

-11x+6

Answer:

-11x +6​

Step-by-step explanation:

(- 7x + 1) - (4x - 5)​

Distribute the minus sign

(- 7x + 1) - 4x + 5

Combine like terms

-11x +6​

Answer:

.7995 rounded to the nearest cent is 0.80 cents

Answer:

.7995 rounded to the nearest cent is .80.

Step-by-step explanation:

Rounding with numbers higher than 4 makes them round up, lower than 5 makes them round down.

Answer:

(0, 3 , -2)

Step-by-step explanation:

X-y+2z=-7  ------------------ equ 1

y+z=1            ------------------ equ 2

x-2y-3z=0      ------------------ equ 3

 equ 1                   X -  y + 2z = -7

equ 3                    x - 2y - 3z = 0

                           -     + __+_____

equ 1 - equ 3 ⇒      y    + 5z = -7  -------------- equ 4

equ 2                 y + z   = 1      

equ 4                 y + 5z = -7

                          -   -      = +

equ 2 - equ 4       -4z =8

                                z = 8/ -4 = -2

Put z = -2 in equ 2,

                            y + z   = 1      

                            y - 2 = 1

                               y = 1 + 2 =3

                          y = 3

Put z = -2 & y = 3 in equ 1

                     X -  y + 2z = -7

                x  - 3 + 2* (-2) = -7

                       x  - 3 - 4  = -7

                              x -7   = -7

                                    x  = -7 + 7  =0

                   x = 0

To solve the system of equations, you can use the method of substitution or elimination. Let's use the method of substitution to find the solution. First, solve for y in the second equation and substitute this value into the other equations. Simplify and solve the resulting equations to find the values of x and z.

To find the solution to the given system of equations:

x - y + 2z = -7

y + z = 1

x - 2y - 3z = 0

You can use the method of substitution or elimination to solve the system. Let's use the method of substitution.

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Answer:

a=3 b=-2 c=4

Step-by-step explanation:

Answer: Option A

[tex]x=\frac{1+\sqrt{83}i}{6}[/tex] or [tex]x=\frac{1-\sqrt{83}i}{6}[/tex]

Step-by-step explanation:

Use the quadratic formula to find the zeros of the function.

For a function of the form

[tex]ax ^ 2 + bx + c = 0[/tex]

The quadratic formula is:

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

In this case the function is:

[tex]3x^2-x+7=0[/tex]

So

[tex]a=3\\b=-1\\c=7[/tex]

Then using the quadratic formula we have that:

[tex]x=\frac{-(-1)\±\sqrt{(-1)^2-4(3)(7)}}{2(3)}[/tex]

[tex]x=\frac{1\±\sqrt{1-84}}{6}[/tex]

[tex]x=\frac{1\±\sqrt{-83}}{6}[/tex]

Remember that [tex]\sqrt{-1}=i[/tex]

[tex]x=\frac{1\±\sqrt{83}*\sqrt{-1}}{6}[/tex]

[tex]x=\frac{1\±\sqrt{83}i}{6}[/tex]

[tex]x=\frac{1+\sqrt{83}i}{6}[/tex] or [tex]x=\frac{1-\sqrt{83}i}{6}[/tex]

Final answer:

The solutions to the equation 3x² - x + 7 = 0 are complex numbers. Using the quadratic formula, we find the solutions to be x = (1 + i√83) / 6 and x = (1 - i√83) / 6.

Explanation:

The solutions of the quadratic equation 3x² - x + 7 = 0 cannot be real numbers because the discriminant (b² - 4ac), in this case, is negative ((-1)² - 4(3)(7) = 1 - 84 = -83). Therefore, we need to use the quadratic formula to find the complex solutions. This formula is given by x = (-b ± √(b² - 4ac)) / (2a). By substituting the values from the equation into the quadratic formula, we obtain the complex solutions.

Quadratic formula application:

x = (-(-1) ± √((-1)² - 4(3)(7))) / (2(3))

x = (1 ± √(-83)) / 6

Therefore, the two complex solutions are x = (1 + i√83) / 6 and x = (1 - i√83) / 6, where i is the imaginary unit.

To confirm these answers, we can substitute each value back into the original equation and verify by simplification that each results in an identity.

Answer:

A. glide reflection

Step-by-step explanation:

This is a glide reflection since the figure has been both reflected over a line and transported downwards.

Answer:

a) glide reflection

Step-by-step explanation:

An isometry is a transformation of a figure in the plane that preserves lenght, it could be reflections, rotations, or translations, in the figure you can se what is called a glide reflection, which is a reflection of the figure over a line, and then a translation of the same figure.

Answer:

[tex]y = 18x + 45[/tex]

Step-by-step explanation:

You can use a linear equation of the form

[tex]y = mx + b[/tex] to represent the situation.

where b is the constant amount represented by the intercept with the y-axis, in this case b e is the cost of membership.

m is the slope, and in this case it is the cost per day of renting a team for x days.

y is  the total cost of membership at the club, when renting equipment for X days

So the linear equation is:

[tex]y = 18x + 45[/tex]

Answer:

D

Step-by-step explanation:

a= 350 minus every 13 cents per mile

Answer:

Events E and F are not independent if the probability of event E occurring is affecting the probability of event F occurring.

Step-by-step explanation:

Two events are independent when the probability of one event occurring has no connection with that of the other event.

Example, when you toss a coin and roll a six sided die, the probability of getting a head or a tail has no connection with the probability of getting any number face.A real life example will be the probability going to the mall and owning a cat at home.These two have no influence on one another.

Mathematically independent events can be calculated as;

P(E∩F)=P(E)-P(F)

Answer:

(5,7)

Step-by-step explanation:

4x+y=27

5x-y=18

Since we want to solve this by elimination we need the lines to be in the same form, and a column with opposite variables or same variables. We actually have both of these.

Both equations are in the form ax+by=c.

The column that contains the y's, we have opposites there. That is the opposite of y is -y.  When you add opposites, you get 0.

So we just add vertically now.

4x+y=27

5x-y=18

--------------Add

9x+0=45

9x    =45

Divide both sides by 9:

x      =45/9

Simplify:

x       =5

Now to find y, you just need to use one of your equations (just pick one) along with x=5.

I guess I will choose 4x+y=27 with x=5.

4x+y=26 with x=5

4(5)+y=27

20+y=27

Subtract 20 on both sides:

y=27-20

y=7

So the solution (x,y) is (5,7).

Answer:

Prime

Step-by-step explanation:

x² + 25 is prime (unfactorable).

Here's what the other options come out to:

(x + 5)(x + 5) = x² + 10x + 25

(x + 5)(x − 5) = x² − 25

(x − 5)(x − 5) = x² − 10x + 25

The correct option is option D: x²+25 is prime.

The algebraic expressions are factorized by taking common factors from the terms and using algebraic properties like a²-b²=(a+b)(a-b), (a+b)²=a²+2ab+b², etc.

The expression which can not be factorized is called prime i.e. unfactorizable.

Here x²+25 is unfactorizable so it is prime.

Also by checking each option

Therefore x²+25 is prime.

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Answer:

x = 142

Step-by-step explanation:

We are given the following expression for which we are to find the solution:

[tex] \sqrt { x + 2 } - 1 5 = - 3 [/tex]

Rearranging the equation to get:

[tex] \ sqrt { x + 2 } = - 3 + 1 5 [/tex]

Taking square root on both sides of the equation to get:

[tex](\sqrt{x+2} )^2=(12)^2[/tex]

[tex]x+2=144[/tex]

x = 142

[tex]\displaystyle\\\sqrt{x+2}-15=-3\\\\\sqrt{x+2}=-3+15\\\\\sqrt{x+2}=12~~\Big|~^2\\\\x+2=144\\\\x=144-2\\\\\boxed{x=142}[/tex]

.

Quotient is division,

Writing the equation out you get:

3x/4 ≥ -16

Now we can solve by x.

First multiply both sides by 4:

3x ≥ -64

Now divide both sides by 3:

x ≥ -64/3

Answer:

8/17

Step-by-step explanation:

Since this is a right triangle, we can use the trigonometric identities

sin Y = opposite side/ hypotenuse

         = 16/34

Dividing the top and bottom by 2

          = 8/17

The most significant number of homerooms that can be created with an equal number of boys and girls in each is 6.

To answer this question, we need to find the greatest common divisor (GCD) for the number of boys and girls. The GCD is the most significant number that can divide both numbers equally. The GCD of 42 (number of boys) and 48 (number of girls) is 6.

 Therefore, the sixth grade's most significant possible number of homerooms would be 6, with each homeroom having seven boys and eight girls.

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Answer:

B

Step-by-step explanation:

A secant is a line which intersects a circle at 2 points

From the diagram this is XY → B

The correct option is option B: The line segment XY is a secant.

Line segment which intersects the circle at two points is called secant.

We are given circle with center at O.

From the options,

1.  Line UZ :

   UZ intersects the circle at one point. So it can't be secant.

2. Line XY:

    XY intersects the circle at TWO points. So it is a secant.

3. Line XO :

   XO intersects the circle at one point. So it can't be secant.

Therefore the line segment XY is a secant.

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Answer:

z=275

Step-by-step explanation:

it has a ratio 1:11

that must be it

Answer:

275

Step-by-step explanation:

z is directly proportional to x:

z = kx

When x is 15, z is 165.

165 = k × 15

k = 11

When x = 25:

z = 11 × 25

z = 275

Answer:

[tex]f(x)=10(5^{2})^{\frac{x}{2}}[/tex]  (first option)

Step-by-step explanation:

we have

[tex]f(x)=10(5)^{x}[/tex]

where

x ----> is the time in years

we know that

Crista wants to manipulate the formula to an equivalent form that calculates every half-year

The exponent will be

x/2 -----> the time every half year

To find an equivalent form

[tex]f(x)=10(5^{a})^{\frac{x}{2}}[/tex]

[tex]10(5)^{x}=10(5^{a})^{\frac{x}{2}}[/tex]

[tex]10(5)^{x}=10(5)^{a\frac{x}{2}}[/tex]

so

[tex]x={a\frac{x}{2}}[/tex]

[tex]a=2[/tex]

The equivalent form is

[tex]f(x)=10(5^{2})^{\frac{x}{2}}[/tex]

Answer:

***********o                                                         o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

x>4 or x<-4

Step-by-step explanation:

You are looking for numbers that give you a distance, x, greater than 4 from 0. That wouldn't be anything between -4 and 4 because these would all give you a distance less than 4 from 0. So the answer would be to shade everything greater than 4 while also shading everything less than -4.

Here is a number line <-----|-----|-----|-----|-----|-----|-----|-----|-->

                                          -6    -4   -2    0     2     4    6    8

Let's think about this more which of these numbers on this number line would satisfy |x|>4?

Numbers inside the numbers -4 and 4.

Or the numbers on the outside.

Let's try the inside numbers:

-2,02

|-2|>4

 2>4 is false which means -2 doesn't satisfy |x|>4

|0|>4

 0>4 is false which means 0 doesn't satisfy  |x|>4

|2|>4

 2>4 is false which means 2 doesn't satisfy  |x|>4

We could also try -4 and 4... but these will both give you a distance equal to 4 from 0.  And we are looking for greater than.

|-4|>4

 4>4 is false which mean -4 doesn't satisfy |x|>4

|4|>4

 4>4  is false which means 4 doesn't satisfy |x|>4

Now let's try the numbers on the outside:

-6,6,8

|-6|>4

 6>4 is true so -6 does satisfy |x|>4

|6|>4

 6>4 is true so 6 does satisfy |x|>4

|8|>4

 8>4 is true so 8 does satisfy |x|>4

So what I'm trying to do is convince you more that the only numbers that would satisfy |x|>4 are numbers outside the interval from -4 to 4.

So x>4 or x<-4.

On a number line the solution would look like this:

***********o                                                         o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

We have holes at -4 and 4 to mean we do not include those numbers.  We would have if the inequality read [tex]|x| \ge 4[/tex].  The line underneath this inequality means to include or equals.  We do not want to include; we did not have the equal sign.   The only difference between the two solutions would be to fill the holes if you [tex]|x| \ge 4[/tex].

***********o                                                         o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->