What is the x-component of vector E⃗  of the figure in terms of the angle θ and the magnitude E?

Answer:

Nucluas

Explanation:

Answer:

C. light energy

Explanation:

In all these plants the energy is converted from the photosynthesis process. As per this photosynthesis phenomenon plants get energy by the light received from the sun.

This will help to make the plants to grow and make fruits in the plant.

in this word photosynthesis we can see it is combination of photo + synthesis

which clearly means that this energy synthesis is with the help of photons received from the sun.

These photons are light photons

So here correct answer will be

C. light energy

Answer:

light energy

Explanation:

D.  For any projectile motion, there is a constant downwards acceleration due to gravity at all instances.  This not to be confused with velocity, which changes due to gravity at every moment along the object's path.

The primary energy exhibited is:

friction:  Heat energy

Due to friction. there is heat loss in mostly all machines.

nuclear power plant:  Nuclear energy

In nuclear power plant, fission or fusion of radio-active substances produces large amount of nuclear energy.

toaster element:  Heat energy

Heat energy is produced in the toaster when electricity passes through the element. This is used to heat the toasts.

welding torch:  Heat energy

The heat energy produced in the welding torch is used in welding.

eraser sitting on a desk edge:  Potential energy

Potential energy is possessed by a body due to virtue of its height.

light bulb:  Heat energy and light energy.

The element inside the bulb gets heated first and then light energy is produced.

campfire:  Heat energy

Heat is produced and then light energy in case of campfire.

moving car:  Kinetic energy

A moving body has kinetic energy.

lump of coal in a storage bin:  Potential energy

A lump of coal in a storage bin has potential energy.

stick of TNT: potential energy

Stick of TNT is formed of explosive mixture. It contains potential energy.

Answer:

• Friction ( heat )

• Nuclear power plant ( nuclear )

• Toaster element ( heat )

• welding torch ( heat )

• eraser sitting on a desk edge (potential)

• light bulb ( light )

• campfire ( heat )

• moving car ( kinetic )

• lump of coal in a storage bin ( potential )

• stick of tent ( potential)

Explanation: hope this helps !

Hi, the answer is A) +2.90%.

The answer would be A or D. The most appropriate answer would be D. Hope I helped :)

Kinetic energy of anything is (1/2) (mass) (speed)² .

Your kinetic energy just before you snap back up (? ?) is

(1/2) (your mass in kilograms) (50 m/s)² =

(1/2) (your mass in kilograms) (2,500 m²/s²) =

(1,250 x your mass in kilograms) .  The unit is Joules.

Part a)

acceleration is defined as rate of change in velocity

so we can write

[tex]a = \frac{v_f - v_i}{t}[/tex]

here we know that

finally it will stop so vf = 0

initial speed is given as 9m/s

and the time to stop is 0.2 s

[tex]a = \frac{0 - 9}{0.2}[/tex]

[tex]a = -45 m/s^2[/tex]

Part b)

Now by 2nd law of Newton

[tex]F = ma[/tex]

given that

m = 100 kg

a = 45 m/s^2

so now using above equation

[tex]F = 100 * 45[/tex]

[tex]F = 4500 N[/tex]

so it will exert 4500 N force to stop

A. The deceleration of Alex is 45 m/s²

B. The force of impact is 4500 N

From the question given above, the following data were obtained:

a = (v – u) / t

a = (0 – 9) / 0.2

a = –9 / 0.2

a = –45 m/s²

The, negative sign indicate that the Alex is coming to rest.

F = ma

F = 100 × 45

F = 4500 N

Learn more about acceleration:

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given that initial speed of the car is

[tex]v_i = 8.9 m/s[/tex]

now after travelling the distance d = 1.8 * 10^1 m the car will stop

so here we can use kinematics to find the acceleration of car

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

[tex]0 - 8.9^2 = 2 a d[/tex]

here we have

[tex]- 79.21 = 2*(18)*a[/tex]

[tex]a = -2.2 m/s^2[/tex]

net force applied due to brakes of car is given by Newton's II law

[tex]F = ma[/tex]

here we have

mass = 1.2 * 10^3 kg

[tex]F_{net} = 1.2 * 10^3 * 2.2[/tex]

[tex]F_{net} = 2.64 * 10^3 N[/tex]

now we can say

[tex]F_{net} = F_1 + F_2[/tex]

[tex]2.64 * 10^3 = 1.8 * 10^3 + F_2[/tex]

[tex]F_2 = 8.4 * 10^2 N[/tex]

So the force applied due to brakes is given as above

it is the process by which important molecules enter the body cells and waste products are removed from cells.  is why it is important because your body kills off the stuff that's  not supposed to be in it and makes sure all the good cells are  where they're supposed to be

Answer:

Mass of toddler = 12.5 kg

Explanation:

 The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

 Potential energy = 187.5 J

 Height = 1.5 m

 Substituting

     187.5 = m * 10 * 1.5

     m = 12.5 kg

So mass of toddler = 12.5 kg

The mass of the baking soda was 80 g

Answer: the mass is 80g

Explanation: In a solution of 140g, we knot that there are 60g of vinegar, the only other component in the solution is baking soda.

Now we want to find the mass of the baking soda in the solution.

Because there are only two components in the solution, if we remove the 60g of vinegar, the residue mass is the mass of the baking soda.

then we need to calculate:

Mass = 140g - 60g = 80g

So the mass of baking soda in the solution is 80g.

The car's (average) acceleration would be

[tex]a=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.4\,\mathrm s}=11.5\,\dfrac{\mathrm m}{\mathrm s^2}[/tex]

The car's position over time would be given by

[tex]x=v_0t+\dfrac12at^2[/tex]

so that after 2.4 seconds, the car will have traveled a distance of

[tex]x=\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)(2.4\,\mathrm s)+\dfrac12\left(11.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm s)^2[/tex]

[tex]\implies x=77.5\,\mathrm m[/tex]

Hello!

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled.

* Determine the acceleration of the car....

We have the following data:

V (final velocity) = 46.1 m/s

Vo (initial velocity) = 18.5 m/s

ΔV  (speed interval)  = V - Vo → ΔV  = 46.1 - 18.5 → ΔV  = 27.6 m/s

ΔT (time interval) = 2.4 s

a (average acceleration) = ? (in m/s²)

Formula:

[tex]\boxed{a = \dfrac{\Delta{V}}{\Delta{T^}}}[/tex]

Solving:  

[tex]a = \dfrac{\Delta{V}}{\Delta{T^}}[/tex]

[tex]a = \dfrac{27.6\:\dfrac{m}{s}}{2.4\:s}[/tex]

[tex]\boxed{\boxed{a \approx 11.5\:m/s^2}}\longleftarrow(acceleration)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

* The distance traveled ?

We have the following data:

Vi (initial velocity) = 18.5 m/s

t (time) = 2.47 s

a (average acceleration) = 11.5 m/s²

d (distance interval) = ? (in m)

By the formula of the space of the Uniformly Varied Movement, it is:

[tex]d = v_i * t + \dfrac{a*t^{2}}{2}[/tex]

[tex]d = 18.5 * 2.4 + \dfrac{11.5*(2.4)^{2}}{2}[/tex]

[tex]d = 44.4 + \dfrac{11.5*5.76}{2}[/tex]

[tex]d = 44.4 + \dfrac{66.24}{2}[/tex]

[tex]d = 44.4 + 33.12[/tex]

[tex]\boxed{\boxed{d = 77.52\:m}}\longleftarrow(distance)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

________________________________  

[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]

I think its 60. I think you would subtract 144-84 to get the mass of the vinegar molecule.

Answer:

m = 60 amu

Explanation:

As we know that total mass is always conserved

So here we know that compound is of mass 84 amu initially

after reaction with vinegar molecule the total mass is given as

[tex]M_{total} = M + m[/tex]

here we know that

[tex]M = 84 amu[/tex]

so we will have

[tex]M_{total} = 144 amu[/tex]

so we have

[tex]144 = 84 + m[/tex]

[tex]m = 60 amu[/tex]

The "waning gibbous" begins immediately after the Full Moon and lasts about a week.

At the end of the week, the moon is no longer gibbous, but it's still waning.  At the instant it's exactly half-illuminated, it's called "Third Quarter", and then it continuous to wane for another week.

So 3 to 4 days after the END of the waning gibbous phase, it's a Waning Crescent. It still has another 3 to 4 days of waning to go, before it wanes away to nothing and we have the next New Moon.

The waning gibbous phase is the phase between the full and last quarter moon late at night or in the early morning . The waning crescent is the phase that occurs 3-4 days later a waning gibbous.

The waning gibbous phase is the phase between the full and last quarter moon late at night or in the early morning.

The waning gibbous phase moon appears more than half-lighted but less than the full moon. A full sunset is a time when the full moon rises. The rising time of the waning gibbous moon is late at night.

It looks red like a  full moon when it’s near the horizon.

To learn more about the waning gibbous refer to the link ;

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The kinetic energy of the roller coaster at the bottom of the hill is 1800 joules, which is indeed twice the kinetic energy at the top of the hill (450 joules). This confirms the statement that the car has joules of kinetic energy at the bottom of the hill, which is twice its kinetic energy at the top.

The kinetic energy of the roller coaster at the bottom of the hill is twice its kinetic energy at the top of the hill.

To find the kinetic energy (KE) of the roller coaster, we use the formula:

[tex]\[ KE = \frac{1}{2}mv^2 \][/tex]

where [tex]\( m \)[/tex] is the mass of the object and [tex]\( v \)[/tex] is its velocity.

Given that the mass [tex]\( m \)[/tex] of the roller coaster car is 100 kilograms, and its speed [tex]\( v \)[/tex] at the top of the hill is 3 meters/second, we can calculate the kinetic energy at the top of the hill as follows:

[tex]\[ KE_{top} = \frac{1}{2} \times 100 \text{ kg} \times (3 \text{ m/s})^2 \] \[ KE_{top} = \frac{1}{2} \times 100 \text{ kg} \times 9 \text{ m}^2/\text{s}^2 \] \[ KE_{top} = 50 \text{ kg} \times 9 \text{ m}^2/\text{s}^2 \] \[ KE_{top} = 450 \text{ J} \][/tex]

Since the speed of the roller coaster car doubles at the bottom of the hill, its new speed [tex]\( v_{bottom} \)[/tex] is:

[tex]\[ v_{bottom} = 2 \times 3 \text{ m/s} = 6 \text{ m/s} \][/tex]

The kinetic energy at the bottom of the hill is:

[tex]\[ KE_{bottom} = \frac{1}{2} \times 100 \text{ kg} \times (6 \text{ m/s})^2 \] \[ KE_{bottom} = \frac{1}{2} \times 100 \text{ kg} \times 36 \text{ m}^2/\text{s}^2 \] \[ KE_{bottom} = 50 \text{ kg} \times 36 \text{ m}^2/\text{s}^2 \] \[ KE_{bottom} = 1800 \text{ J} \][/tex]

Therefore, the kinetic energy of the roller coaster at the bottom of the hill is 1800 joules, which is indeed twice the kinetic energy at the top of the hill (450 joules). This confirms the statement that the car has joules of kinetic energy at the bottom of the hill, which is twice its kinetic energy at the top.

Given that force applied due to tree on car is 6000 N

and during the stop the acceleration is given as 2 m/s^2.

So here we can say that As per Newton's II law

[tex]F = m*a[/tex]

here F = force on car = 6000 N

a = acceleration of car = 2 m/s^2

now we can plug in all values above in the given equation

[tex]6000 = 2*m[/tex]

[tex]m = 3000 kg[/tex]

So here the mass of the car will be 3000 kg

The mass of the car is 3000 kg.

To calculate the mass of the car, we can use Newton's second law of motion: F = ma.

In this case, the force exerted on the car is 6000 N and the acceleration is 2 m/s².

So, using the formula F = ma, we can rearrange it to solve for mass (m). Therefore, m = F/a = 6000 N / 2 m/s² = 3000 kg.

Given:

s(distance)= 20 meters

F(force)=200N

Now we know that

work done= Force applied x distance

Substituting the given values in the above formula we get

Work done= 20 x 200= 4000J

The work done by an elephant while moving a circus wagon 20 meters with a pulling force of 200N is calculated using the formula: Work = Force x Distance. Plugging the values into the formula gives us 4000 Joules.

The work done by the elephant pulling the circus wagon can be calculated using the formula for work, which is Work = Force x Distance. In this situation, the Force applied by the elephant is 200N and the Distance moved by the wagon is 20 meters.

So, the Work done would be: 200N x 20m = 4000 Joules.

This means the work done by the elephant is 4000 Joules.

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Gasoline fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.

Answer:

Hydrogen fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.

Answer:

 Length of displacement vector = 7.51 m

Explanation:

 Consider east as positive X axis and North as positive Y axis.

 Eric headed 6 meters east, Displacement = 6 i

 Then he headed X meters north, Displacement = X j

 Total displacement = 6 i + X j

  Angle it makes with horizontal axis, θ = tan⁻¹(X/6) = 37°

  X/6 = tan 37

   X = 4.52 m

Total displacement = 6 i + 4.52 j

Magnitude = [tex]\sqrt{6^2+4.52^2} =7.51m[/tex]

 Length of displacement vector = 7.51 m

The answer is A. 7.5.

Answer:

analyzing what data means

diagram showing the correlation between two quantities

Explanation:

Graph is the plot of two physical quantities and it describes the relation between both quantities. It gives a specific relation between the two physical quantities which is used to analyze the result.

Thus, the following options are correct,

analyzing what data means

diagram showing the correlation between two quantities

Answer: Analyzing what data means, diagram showing the correlation between two quantities, and predicting outcomes and patterns.

The first, third, and forth.

m = mass of the car = 1500 kg

we know that 1 mph = 0.45 m/s

hence

v = speed gained by the car = 40 mph = 40 x 0.45 m/s = 18 m/s

since the car is gaining speed here , hence the energy need is same as the kinetic energy gained by the car

kinetic energy is given as

KE = (0.5) m v²                     where m = mass , v = speed

inserting the above values in the formula

KE = (0.5) (1500) (18)²

KE = 2.43 x 10⁵ J

we know that , 1 J = 2.78 x 10⁻⁷ kwh

hence

KE = (2.43 x 10⁵) (2.78 x 10⁻⁷)

KE = 0.068 kwh

hence the energy needed is 0.068 kwh

i believe the answer is water vapor

hope this helps

Answer:

WATER VAPOR

Explanation:

I got a 100% on my test

The correct answer is constant and positive

The velocity is changing with respect to time at constant rate and we know that the change in velocity is known as acceleration so a constant change in velocity with respect to time will give us a constant acceleration. Similarly the velocity is gradually increasing that is why we will take the acceleration as positive .

Answer: constant and positive

Explanation:

Acceleration is the rate of change of velocity. It can be measured in meter per second square.

[tex]a = \frac{dv}{dt}[/tex]

It can be measured from the slope of velocity - time graph.

In the given velocity vs. time graph, the slope is a straight line in the first quadrant. This means the acceleration is uniform (constant) and positive.

Acceleration from the given graph is:

a = change in velocity /time interval = (5-0)m/s/(5-0)s = 1 m/s².

The new average pressure will be four times the original pressure when the wood is replaced by a sheet with half the diameter, i.e p' = 4p.

The pressure exerted by an object is given by the force applied divided by the area over which it is distributed.

The formula for pressure (p) is (p = F/A).

If the box exerts a pressure (p) on the original round sheet of wood, and the wood is replaced by a sheet with half the diameter, the new area will be (1/4) of the original (since area is proportional to the square of the diameter).

Therefore, the new pressure (p') can be expressed as:

p' = F ÷ (1/4)A = 4p

So, the new average pressure will be four times the original pressure when the wood is replaced by a sheet with half the diameter.

Answer

The answer to this question is [tex]30 ms^{-1}[/tex]

Explanation

As we know that accelartion is the rate of change of velocity. So, it can be write as

[tex]a = (V_f -V_i) /t[/tex]

where

[tex]V_f[/tex] is the final velocity

[tex]V_i[/tex] is the initial velocity

t is the time

a is the accelartion

as we konw

[tex]a = 3 ms^{-2}[/tex]

t = 10 s

From rest So,

[tex]V_i[/tex] = 0

[tex]V_f[/tex] = ?

Putting values

[tex]3 = (V_f - 0)/10[/tex]

[tex]3 * 10 = V_f[/tex]

[tex]30 = V_f[/tex]

[tex]V_f = 30 ms^{-1}[/tex]

So, the right answe is [tex]30 ms^{-1}[/tex]

(3 m/s²) x (10 s) = 30 m/s

His speed at the end of 10 sec is 30 m/s.  We can't describe his velocity, because we have no information about the direction he's moving.

I think its either sight or its your hands/sensory limbs because it takes babie a while to figure out how to use their hands. i would say speech but it is not a sense. hope this helps!

The least functional sense at birth is vision. Newborn babies have limited visual acuity and are unable to see clearly or focus on objects that are far away. Their vision gradually improves as they grow older.

The least functional sense at birth is vision. Newborn babies have limited visual acuity and are unable to see clearly or focus on objects that are far away. Their visual system is still developing, and it takes a few months for them to develop better visual skills.

Babies are born with the ability to hear, taste, and touch, but their vision is less developed at birth. They can detect light and motion, but their vision gradually improves as they grow older. By about 6 months of age, most babies have developed the ability to see more clearly.

During the early stages of development, babies rely on their other senses, such as touch and hearing, to explore and interact with the world. These senses are more functional at birth compared to vision.

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the answer youre looking for is (C

here tennis ball is accelerated from initial speed zero to final speed 50 m/s

In this accelerated motion the distance moved by the ball is 0.5 m

So here we can use kinematics to find the acceleration of the ball during this distance

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

here given that

vf = 50 m/s

vi = 0

d = 0.5 m

[tex]50^2 - 0 = 2*a*0.5[/tex]

[tex]2500 m/s^2 = a[/tex]

now if we have acceleration during its motion so we can find the applied force by using Newton's II law

[tex]F = ma[/tex]

[tex]F = 0.06*2500[/tex]

[tex]F = 150 N[/tex]

now the applied force will be 150 N on the ball by racket

As per Newton's II law we can say force applied on an object is product of mass and acceleration

[tex]F = ma[/tex]

given that

Force = 140 N

mass = 32.5 kg

now we can use above formula

[tex]140 = 32.5* a[/tex]

[tex]a = \frac{140}{32.5}[/tex]

[tex]a = 4.31 m/s^2[/tex]

so its acceleration must be 4.31 m/s^2