Answer:
E. Length and frequency of the commercial.
Remaining Details of the Question:
A study investigated the effect of the length and the repetition of TV advertisements on students' desire to eat at a Sub-U-Like sandwich franchise. Sixty students watched a 50- minute television program that showed at least one commercial for Sub-U-Like during advertisement breaks. Some students saw a 30-second commerical, some saw a 60-second commercial, others a 90-second commerical. The same commerical was shown one, three, or five times during the program. After the viewing, each student was asked to rate their craving for a Sub-U-Like sandwich from the set ("Don't want to eat", "Neutral", "Want to eat"}
Explanation:
During the course of an experimental study, it is important to identify the variables of interest. These variables are referred to as the factors. Factors are controlled independent variables in an experimental study that can be manipulated by the experimenter.
In this case, it was indicated that the study investigated the effect of the length and the repetition of TV advertisements on students' desire to eat at a Sub-U-Like sandwich franchise. Therefore, the factors in the "Sub-U-Like" study are length and frequency of the commercial.
Final answer:
The factors in the "Sub-U-Like" study include the length and frequency of the commercial, the number of students, and the number of commercials during the TV program. Factors in the "Sub-U-Like" study, while not explicitly defined in the examples provided, can generally include variables such as length and frequency of commercials and the number of commercials shown, all of which can influence viewers' behaviors and perceptions in psychological or marketing research.
Explanation:
Factors in the "Sub-U-Like" study:
Factor A: Length and frequency of the commercial
Factor B: The number of students
Factor F: One, three, or five commercials during the 50-minute television program
A firework rocket is shot upward at a rate of 640ft/sec. Use the projectile formula h= -16t^2 +v0t to determine the times when the height of the firework will be 1,200 feet. Round your answer to the nearest whole number.
Answer:
2 seconds and 38 seconds
Step-by-step explanation:
h=-16t²-vot
1,200=-16t²-640t
turn this into standard form
16t²-640t+1200=0
now plug thes numbers into the quadratice formula
a 16 b -640 c 1200
solve with quadratic formula to get ≅2 and ≅38 seconds
Answer:
t≈2 seconds,t≈38 seconds
Step-by-step explanation:
h=−16t2+ v0t
Step 1. Solve the equation.
1,200= −16t^2+ 640t
We know the velocity, v0, is 640 feet per second.
The height is 1,200 feet. Substitute the values.
This is a quadratic equation. Rewrite it in standard form. Solve the equation using the quadratic formula.
ax^2 + bx + c . = 0
16t^2 −640t + 1,200 = 0
Identify the values of a, b, and c.
a=16, b=−640, c=1,200
Write the quadratic formula.
t=−b± √b2−4ac‾‾‾‾‾‾‾‾
2a
640+ √332,800‾‾‾‾‾‾‾‾ t= √640− √332,800‾‾‾‾‾‾‾
32 32
Rewrite to show two solutions.
t=640+332,800‾‾‾‾‾‾‾‾√32,t=640−332,800‾‾‾‾‾‾‾‾√32
Approximate the answer with a calculator.
t≈2 seconds,t≈38 seconds
Step 2. Check the answer. The check is left to you.
Step 3. Answer the question.
The firework will go up and then fall back down. As the firework goes up, it will reach 1,200 feet after approximately 2 seconds. It will also pass that height on the way down at 38 seconds.
Find the volume of the rectangular prism
Answer:
40 and 1/2
Step-by-step explanation:
Multiply 4 1/2 by 1 1/2. Then multiply the product of 4 1/2 and 1 1/2 by 6.
A recent study conducted by the state government attempts to determine whether the voting public supports further increase in cigarette taxes. The opinion poll recently sampled 1500 voting age citizens. 1020 of the sampled citizens were in favor of an increase in cigarette taxes. The state government would like to decide if there is enough evidence to establish whether the proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66. At \alpha = .05, we would reject the null hypothesis.
a. True
b. False
Answer:
b) False
Calculated value Z = 1.635 < 1.96 at 0.05 level of significance.
The null hypothesis is accepted.
Step-by-step explanation:
Explanation:-
Step:- (1)
Given data the opinion poll recently sampled 1500 voting age citizens.
Given sample size 'n' = 1500
Given data the opinion poll recently sampled 1500 voting age citizens in selected 1020 of the sampled citizens were in favor of an increase in cigarette taxes.
The sample proportion[tex]'p' = \frac{1020}{1500} = 0.68[/tex]
Given data the state government would like to decide if there is enough evidence to establish whether the proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66
Population proportion 'P' =0.66
Q = 1-P
Q = 1-0.66 = 0.34
Null hypothesis :H₀: 'P' >0.66
Alternative hypothesis: H₀: 'P' <0.66
Level of significance ∝=0.05
Step:-(2)
The test statistic
[tex]Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }[/tex]
[tex]Z = \frac{0.68-0.66}{\sqrt{\frac{0.66 X 0.34}{1500} } }[/tex]
Z = 1.635
The calculated value Z = 1.635
The tabulated value Z = 1.96 at ∝=0.05 level of significance.
Therefore Z = 1.635 < 1.96 at 0.05 level of significance.
The null hypothesis is accepted.
The alternative hypothesis is rejected.
Conclusion:-
The null hypothesis is accepted at 0.05 level of significance.
The proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66
What is .54444 as a fraction?
Answer:
.54444 = .54444/1 = 5.4444/10 = 54.444/100 = 544.44/1000 = 5444.4/10000 = 54444/100000, any one of those works
Answer:
54/99
Step-by-step explanation:
A quality inspector inspect random box of 50 tablets. He discovers 2 are defective. In an order of 2,000 tablets,how many are likely to be defective
Answer:
80
Step-by-step explanation:
So if 50 tablets are made and 2 are defective then it’s 50:2. That means for every 50 tablets are made 2 are defective. And since 50 goes into 2000 40 times, you would multiply 40 x 2 to get 80, the number defective tablets
A computer program has a bug that causes it to fail once in every thousand runs, on average. In an effort to find the bug, independent runs of the program will be made until the program has failed six times. What is the standard deviation of the number of runs required?
Answer:
The standard deviation of the number of runs required is 2447.26
Step-by-step explanation:
For each run, there are only two possible outcomes. Either the program fails, or it does not. The probability of the computer failing during a run is independent of other runs. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The standard deviation for the expected number of trials for r sucesses is:
[tex]\sqrt{V(X)} = \sqrt{\frac{r(1-p)}{p^{2}}}[/tex]
A computer program has a bug that causes it to fail once in every thousand runs, on average.
This means that [tex]p = \frac{1}{1000} = 0.001[/tex]
In an effort to find the bug, independent runs of the program will be made until the program has failed six times. What is the standard deviation of the number of runs required?
This means that r = 6. So
[tex]\sqrt{V(X)} = \sqrt{\frac{6*0.999}{(0.001)^{2}}} = 2447.26[/tex]
The standard deviation of the number of runs required is 2447.26
a bag contains 3 red marbles, 8 blue marbles and 5 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 1000th. that both marbles drawn will be blue
Answer:
0.233
Step-by-step explanation:
There are a total of 16 marbles.
The probability the first marble is blue is 8/16.
Assuming the marble isn't replaced, the probability the second marble is blue is 7/15.
So the probability of both marbles being blue is 8/16 × 7/15 = 7/30 ≈ 0.233.
The probability of drawing two blue marbles without replacement is 0.233 to the nearest thousandth, calculated by multiplying the individual probabilities of the first and second draws.
Explanation:The probability of drawing two blue marbles from a bag without replacement involves a two-step calculation because the outcome of the first draw affects the second. Since there are 3 red, 8 blue, and 5 green marbles, the total number of marbles is 16. The probability of drawing a blue marble first is 8/16 or 1/2.
After drawing one blue marble, there would be 7 blue marbles left in a bag of 15 total marbles. The probability of drawing a blue marble on the second draw is then 7/15. To find the combined probability of both events occurring, we multiply the two probabilities: (1/2) × (7/15) = 7/30, which is approximately 0.233 to the nearest thousandth.
Thus, the probability of drawing two blue marbles in a row without replacement is 0.233 to the nearest thousandth.
A report on a certain fast food restaurant states that μ, the mean order total, is $9. The manager of the restaurant believes the mean is higher. A random sample of orders will be selected. The sample mean x¯ will be calculated and used in a hypothesis test to investigate the belief. Which of the following is the correct set of hypotheses?A. H0:x¯=$9Ha:x¯≠$9B. H0:x¯=$9Ha:x¯>$9 C. H0:μ=$9Ha:μ≠$9 D. H0:μ=$9Ha:μ>$9 E. H0:μ=$9Ha:μ<$9
Answer:
Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = $9
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $9
Step-by-step explanation:
We are given that a report on a certain fast food restaurant states that μ, the mean order total, is $9. The manager of the restaurant believes the mean is higher.
A random sample of orders will be selected. The sample mean x¯ will be calculated and used in a hypothesis test to investigate the belief.
Let [tex]\mu[/tex] = the mean order total
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = $9
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $9
Here, null hypothesis states that the mean order total is equal to $9 and the manager claim's is not correct.
On the other hand, alternate hypothesis states that the mean order total is higher than $9 and the manager claim's is correct.
So, this would be the correct set of hypotheses for testing.
Based on the null hypothesis, the mean order to total is $9, and the manager's belief is wrong. Based on alternate hypothesis, the mean order total is more than $9, and the manager is right.
Given information:
A report on a certain fast food restaurant states that μ, the mean order total, is $9.
The manager of the restaurant believes the mean is higher.
So, according to the null hypothesis, [tex]H_0[/tex]
[tex]\mu=9[/tex]
And, according to alternate hypothesis, [tex]H_a[/tex]
[tex]\mu>9[/tex]
Therefore, based on the null hypothesis, the mean order to total is $9, and the manager's belief is wrong. Based on alternate hypothesis, the mean order total is more than $9, and the manager is right.
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Multiply 2 and 1 half by 3 and 1 third
Answer:
8 1/3
Step-by-step explanation:
2 1/2 * 3 1/3
Change each to an improper fraction
2 1/2 = (2*2 +1)/2 = 5/2
3 1/3 = (3*3+1)/3 = 10/3
5/2 *10/3 = 50/6
Divide the top and bottom by 2
25/3
Change to a mixed number
3 goes into 25 8 times with 1 left over
8 1/3
Cards from an ordinary deck of 52 playing cards are turned face up one at a time. If the 1st card is an ace, or the 2nd a two, or the 3rd a three, or . . . , or the 13th a king, or the 14th an ace, or the 15th a two, and so on, we say that a match occurs. Compute the expected number of matches that occur.
Answer:
Expected number of matches that occur = 4 matches
Step-by-step explanation:
First of all, let X_i be the event that when we turn over card i if it matches the required cards face.
Thus, for example X_1 is the event that turning over one card results in an ace while X_2 is the event that turning over second card reveals a deuce.
The number of matched cards "N" is given by the sum of this indicator random variable as shown in the attached file;
The expected number of matches when cards are drawn from a standard 52-card deck is 4.
We define a match for each card position as X_i = 1 if a match occurs, and X_i = 0 otherwise. The expectation E(X_i) for each card is 1/13 because the probability of the ith card being an i-matched card (Ace in the 1st position, Two in the 2nd position, and so on up to King in the 13th, then repeat with Ace) is 1/13.
Given there are 52 cards, each having the same pattern of matching, the expected number of matches is computed as:
E(X) = E(X_1 + X_2 + ... + X_52) = E(X_1) + E(X_2) + ... + E(X_52)
Since E(X_i) = 1/13 for all i:
E(X) = 52 * (1/13) = 4
Therefore, the expected number of matches is 4.
A recent study reported that high school students spend an average of 94 minutes per day texting. Jenna claims that the average for the students at her large high school is greater than 94 minutes. She will conduct a study to investigate this claim.
(b) Based on a sample of 32 students, Jenna calculated a sample mean of 96.5 minutes and a sample standard deviation of 6.3 minutes. Assume all conditions for inference are met. At the significance level of α=0.05, do the data provide convincing statistical evidence to support Jenna’s claim? Complete an appropriate inference procedure to support your answer.
Answer:
We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.
Step-by-step explanation:
Jenna claims that the average time of texting at her larger high school is greater than 94 minutes per day.
From here we can see that we have to perform a hypothesis test about a sample mean. The null and alternate hypothesis will be:
Null Hypothesis: [tex]\mu \leq 94[/tex]
Alternate Hypothesis: [tex]\mu > 94[/tex]
Jenna collected data from a sample of 32 students. So, sample size will be:
Sample Size = n = 32
Sample Mean = x = 96.5
Sample Standard Deviation = s = 6.3
We have to perform a hypothesis test, to test Jenna's claim. Since, the value of Population Standard Deviation is unknown and the value of Sample Standard Deviation is known, we will use One Sample t-test in this case.
The formula to calculate the test statistic is:
[tex]t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}[/tex]
Using the values, we get:
[tex]t=\frac{96.5-94}{\frac{6.3}{\sqrt{32} } }=2.245[/tex]
The degrees of freedom will be:
df = n - 1 = 32 - 1 = 31
We have to convert the t-score 2.245 with 31 degrees of freedom to its equivalent p-value. From t-table this value comes out to be:
p-value = 0.0160
The significance level is:
[tex]\alpha =0.05[/tex]
Since, the p-value is lesser than the level of significance, we reject the Null Hypothesis.
Conclusion:
We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.
This p value the significant level 0.05 is given which is higher then the obtained p value. Thus we can reject the null hypothesis. Thus we have convincing statistical evidence to support Jenna’s claim.
Given-
Jenna claims that the average for the students at her large high school is greater than 94 minutes. The null hypothesis is [tex]\mu\leq 94[/tex] and alternate hypothesis [tex]\mu >94[/tex].
Now given that,
The value of sample size [tex]n[/tex] is 32, sample means [tex]x[/tex] is 96.5 and the sample standard deviation [tex]s[/tex] is 6.3.
Here one-sample t-test will be used for the as sample standard deviation is given. The formula for the test statics is,
[tex]t=\dfrac{x-\mu}{\dfrac{s}{\sqrt{n}} }[/tex]
[tex]t=\dfrac{96.5-94}{\dfrac{6.3}{\sqrt{32}} }[/tex]
[tex]t=2.245[/tex]
Now the degrees of freedom is n-1. thus,
[tex]D_f=n-1[/tex]
[tex]D_f=32-1=31[/tex]
Now from the t table the value of t score 2.245 having degree 31 is,
p value[tex]=0.0160[/tex]
For this p value the significant level 0.05 is given which is higher then the obtained p value. Thus we can reject the null hypothesis. Thus we have convincing statistical evidence to support Jenna’s claim.
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y=4x−2 (What does Y and X equal?
y=x+3
Answer:
x = 5/3
y = 14/3
Step-by-step explanation:
y=4x−2
y=x+3
Since they are both equal to y, we can set them equal to each other
4x-2 = x+3
Subtract x from each side
4x-2-x = x+3-x
3x-2 =3
Add 2 to each side
3x-2+2 = 3+2
3x =5
Divide each side by 3
3x/3 =5/3
x = 5/3
Now we need to find y
y = x+3
y =5/3+3
y = 5/3+9/3
y = 14/3
Answer:
x=5/3; y=14/3
Step-by-step explanation:
Subtract the following:
-4x+y=-2
-x+y=3
= -3x=-5
x=5/3
substitute x into one of the given equations.
y=5/3+3
y= 14/3
Casey has a total of 18 pens. Twelve of these pens are blue, and the rest are red.
What is the ratio of blue pens to red pens?
Answer: For every 12 blue pens, she has 6 red pens 12:6
Simplifying this would be: 2:1
Answer:
3 : 1
Step-by-step explanation:
18 : 6
simplified ratio is
3 : 1
Given the length of a word (wordLen) and the maximum number of consecutive vowels that it can contain (maxVowels), determine how many unique words can be generated. Words will consist of English alphabetic letters a through z only. Vowels are v: {a, e, i, o, u}; consonants are c: remaining 21 letters. In the explanations, v and c represent vowels and consonants.
Vowels are defined as sound repeated as a, e, i, o, u and the rest 21 letters are classified as consonants.
The given words are generated from English alphabet as a combination of Vowels and alphabets. Thus the combination of vowels and consonant help in the formation of words. There are n number of unique letters are formed.
1) Speed is fast = SPEEFAS
2) Minimum number of participants = MINIPART
3) Sum of excess = SUMCESS
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To find the number of unique words that can be generated with a given word length and maximum number of consecutive vowels, multiply the number of possible vowel arrangements by the number of possible consonant arrangements.
Explanation:To determine the number of unique words that can be generated given the length of a word (wordLen) and the maximum number of consecutive vowels (maxVowels), we need to consider the different possibilities for the arrangement of vowels and consonants in the word. Since vowels can be repeated consecutively up to maxVowels times, we can have up to maxVowels + 1 vowels in a row in any word. Similarly, we can have up to wordLen - maxVowels + 1 consonants in a row in any word. Therefore, the total number of unique words that can be generated is (maxVowels + 1) * (wordLen - maxVowels + 1).
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The diameter of a mason jar is 3 inches but can be as large as 3.03 inches and as small as 2.97 inches. Twenty-five samples of mason jars are taken and it is discovered that these components have a grand mean of 3.01 inches and a standard deviation of 0.02 inches. What is the probability of producing a bad product? (4pts)
Answer:
18.15% probability of producing a bad product
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 3.01, \sigma = 0.02[/tex]
What is the probability of producing a bad product?
Less than 2.97 or more than 3.03.
Less than 2.97
pvalue of Z when X = 2.97. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{2.97 - 3.01}{0.02}[/tex]
[tex]Z = -2[/tex]
[tex]Z = -2[/tex] has a pvalue of 0.0228
More than 3.03
1 subtracted by the pvalue of Z when X = 3.03. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{3.03 - 3.01}{0.02}[/tex]
[tex]Z = 1[/tex]
[tex]Z = 1[/tex] has a pvalue of 0.8413
1 - 0.8413 = 0.1587
Then
0.0228 + 0.1587 = 0.1815
18.15% probability of producing a bad product
Maryam showed the location of each vertex of a polygon on the grid below. On a coordinate plane, points are at (1, 3), (4, 1), (3, negative 3), (negative 1, negative 3), and (negative 2, 1). If the points are connected, which statements about the polygon are true? Check all that apply. The polygon has six sides. The polygon is a pentagon. The vertices of the polygon are (–2, 1), (1, 3), (4, 1), (3, –3), and (–1, –3). The polygon has five vertices. The polygon is a heptagon.
Answer:
bcd
Step-by-step explanation:
Answer:
B C D
Step-by-step explanation:
A poll is conducted the day before a state election for Senator. There are only two candidates running for this office. The poll results show that 59% of the voters favor the Republican candidate, with a margin of error of 4 percentage points. Should the Republican expect to win? Why or why not? Choose the correct answer below.
Answer:
The lower limit of the confidence interval is 55%, which is above 50%, so the Republican should expect to win.
Step-by-step explanation:
A confidence interval of proportions has two bounds, a lower bound and an upper bound.
These bounds depend on the sample proportion and the margin of error.
The lower bound is the sample proportion subtracted by the margin of error.
The upper bound is the margin of error added to the sample proportion.
In this problem, we have that:
Sample proportion 59%
Margin of error 4%
59 - 4 = 55%
59 + 4 = 63%
The lower limit of the confidence interval is 55%, which is above 50%, so the Republican should expect to win.
Final answer:
The Republican candidate can neither be certain of victory nor of defeat based on the poll with a margin of error of 3 percentage points. The poll suggests a favorable leaning towards the Republican, but the actual support could range from 53% to 59%, implying the election could be close. Historical examples illustrate that polls are not foolproof predictors of election outcomes.
Explanation:
Whether the Republican candidate should expect to win based on a poll showing 56% favoritism with a margin of error of 3 percentage points cannot be said with certainty. The margin of error indicates that the true support could theoretically range from 53% to 59%.
To understand the implication, consider that if the candidate's actual support is at the lower end of the margin of error (53%), then it is possible that the race is very close, depending on the percentage of voters favoring the Democratic candidate. If the Democratic candidate has close to 47% support, the election could go either way. Conversely, if the Republican candidate's support is at the higher end (59%), then it is more likely, though not guaranteed, that the Republican would win. Polls provide a snapshot of voter preferences at a particular time and have limitations, including potential sampling errors, nonresponse bias, and inability to predict who will actually turn out to vote.
Historical polls and election outcomes show that while polls can be predictive, they are not always accurate reflections of election results. An example is the 2000 election between George W. Bush and Al Gore, which was a toss-up based on polls but ended with a narrow victory. Similarly, in a hypothetical situation where a state's population is largely liberal, a conservative might still win if the liberal vote is split between two candidates.
Having issues solving
Answer:
Step-by-step explanation:
Labor: 40.55 x 4 = $162.20 for total Labor.
Total Charges: 25.75 + 38.75 + 162.20 = $226.70 Total charges.
A precision instrument is guaranteed to be accurate to within 2 units. A sample of four instrument readings on the same object yielded the measurements 352, 350, 350, and 353. Give the attained significance level for testing the null hypothesis σ = 0.7 versus the alternative hypothesis σ > 0.7. (Round your answer to six decimal places.)
Answer:
[tex]\chi^2 =\frac{4-1}{0.7^2} 1.5^2 =13.776[/tex]
[tex]p_v =P(\chi^2 >13.776)=0.0032[/tex]
In order to find the p value we can use the following code in excel:
"=1-CHISQ.DIST(13.776,3,TRUE)"
If we compare the p value and the significance level assumed we see that [tex]p_v <\alpha[/tex] so on this case we have enough evidence in order reject the null hypothesis. And we can conclude that the true deviation i significantly higher than 0.7
Step-by-step explanation:
Notation and previous concepts
A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"
[tex]n=4[/tex] represent the sample size
We can calculate the sample deviation with this formula:
[tex]s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
[tex]\alpha[/tex] represent the confidence level
[tex]s =1.5 [/tex] represent the sample variance obtained
[tex]\sigma^2 =0.7[/tex] represent the value that we want to test
Null and alternative hypothesis
On this case we want to check if the population deviation is higher than 0.7, so the system of hypothesis would be:
Null Hypothesis: [tex]\sigma \leq 0.7[/tex]
Alternative hypothesis: [tex]\sigma >0.7[/tex]
Calculate the statistic
For this test we can use the following statistic:
[tex]\chi^2 =\frac{n-1}{\sigma^2_0} s^2[/tex]
And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.
[tex]\chi^2 =\frac{4-1}{0.7^2} 1.5^2 =13.776[/tex]
Calculate the p value
In order to calculate the p value we need to have in count the degrees of freedom , on this case 3. And since is a right tailed test the p value would be given by:
[tex]p_v =P(\chi^2 >13.776)=0.0032[/tex]
In order to find the p value we can use the following code in excel:
"=1-CHISQ.DIST(13.776,3,TRUE)"
Conclusion
If we compare the p value and the significance level assumed we see that [tex]p_v <\alpha[/tex] so on this case we have enough evidence in order reject the null hypothesis. And we can conclude that the true deviation i significantly higher than 0.7
A marine sales dealer Önds that the average price of a previously owned boat is $6492. He decides to sell boats that will appeal to the middle 66% of the market in terms of price. Find the maximum and minimum prices of the boats the dealer will sell. The standard deviation is $1025, and the variable is normally distributed.
Answer:
The maximum price that the dealer will sell is $7471 and the minimum is $5513.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 6492, \sigma = 1025[/tex]
Middle 66%
50 - (66/2) = 17th percentile
50 + (66/2) = 83rd percentile
17th percentile
X when Z has a pvalue of 0.17. So X when Z = -0.955.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-0.955 = \frac{X - 6492}{1025}[/tex]
[tex]X - 6492 = -0.955*1025[/tex]
[tex]X = 5513[/tex]
83rd percentile
X when Z has a pvalue of 0.83. So X when Z = 0.955.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.955 = \frac{X - 6492}{1025}[/tex]
[tex]X - 6492 = 0.955*1025[/tex]
[tex]X = 7471[/tex]
The maximum price that the dealer will sell is $7471 and the minimum is $5513.
How much interest is earned on a principal of $9.02 invested at an interest
rate of 8% for three years?
Final answer:
The interest earned on $9.02 at an 8% interest rate for three years is $2.16.
Explanation:
To calculate the amount of interest earned on a principal of $9.02 at an interest rate of 8% for three years, we would use the formula for simple interest: Interest = Principal imes Rate imes Time. Plugging in the values we get:
Interest = $9.02 imes 0.08 imes 3
Interest = $2.166. Therefore, the interest earned on the principal amount of $9.02 invested at an 8% interest rate for three years would be $2.16, after rounding to the nearest cent.
Help nowwwwww ,pleaseee
Answer:
Step-by-step explanation:
One number is eight more than twice another. If their difference is 25, what is the larger number?
17
42
35
Answer: The largest number was 42
The product of three consecutive odd integers is 75.
1. Determine the variable.
x = first odd integer
2. Identify key words and translate their meanings.
1st odd integer = x
2nd odd integer = x + 2
3rd odd integer = x + 4
3. Write the multistep equation for the scenario.
What is the equation that represents the scenario?
Answer:
(D)
x (x + 2) × (x + 4) = 75
Answer:
D.)x (x + 2) · (x + 4) = 75
Step-by-step explanation:
Well, the easiest way to look at this is by first placing both the 2nd odd integer and the 3rd odd integer into parenthesis finally you simply add the 1st integer to the beginning of the equation. You simply just use the information given and piece it all together into an equation usually written in the same order that the information was given.
Also, to find out the operations in the equations you simply use the keywords given in the problem itself. In this problem, they used the phrase "The product of three consecutive odd integers is 75." since we know that product means to multiply then we also know that we are multiplying all of the integers together to give us our final answer of 75.
covert the units of weight 32IB 12oz = blank IB ? Help please as fast as you can
Answer:
32¾
Step-by-step explanation:
1 pound (lb) = 16 ounces
12 oz = 12/16 = 3/4 lb
32 pounds 12 oz
32 ¾ lb
HELP PLEASE
Find the are of the circle.Leave your answer in terms of pie
A.9pi ft
B.324pi ft
C.18pi ft
D.81 pi ft
Answer:
A = 81 pi ft^2
Step-by-step explanation:
The area of a circle is found by
A = pi r^2
The radius is 9
A = pi 9^2
A = 81 pi ft^2
You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately σ = 39.9 σ=39.9. You would like to be 99% confident that your estimate is within 2 of the true population mean. How large of a sample size is required?
Answer:
large of a sample size n = 2645
Step-by-step explanation:
Explanation:-
The population standard deviation 'σ' = 39.9
Given data the estimate is within 2 of the true population mean so given the margin of error = 2
we know that margin of error is determined by
Margin of error = [tex]\frac{z_{\alpha }S.D }{\sqrt{n} }[/tex]
cross multiplication , we get
[tex]\sqrt{n} = \frac{2.578 X S.D}{M.E}[/tex]
[tex]\sqrt{n} = \frac{2.578 X 39.9}{2}= 51.4311[/tex]
squaring on both sides , we get
n = 2645.15
n = 2645
Conclusion:-
large of a sample size n = 2645
Which are the solutions of the quadratic equation ? x ^ 2 = - 5x - 3 - 5, 0 (- 5 - sqrt(13))/2, (- 5 + sqrt(13))/2 (5 - sqrt(13))/2, (5 + sqrt(13))/2 5, 0
Answer: b
Step-by-step explanation:
The solutions to the quadratic equation x^2 = -5x - 3 are (-5 - sqrt(13))/2 and (-5 + sqrt(13))/2, calculated using the quadratic formula -b ± √(b² - 4ac) / (2a).
Explanation:The subject of this question is Mathematics, specifically, the solution of quadratic equations. A quadratic equation is in the form ax²+bx+c = 0. You can find the solutions or roots of any quadratic equation using the formula: -b ± √(b² - 4ac) / (2a).
Let's apply this formula to the quadratic equation, x^2 = -5x - 3. Here, a = 1, b = 5, and c = 3. Substituting these values into the formula, the solutions to this quadratic equation are (-5 - sqrt(13))/2 and (-5 + sqrt(13))/2. However, in the question, there seems to be multiple options. It's essential to note that the correct solutions match the ones derived from our calculations.
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In a group of 700 people, must there be 2 who have matching first and last initials? Why? (Assume each person has a first and last name.) Correct: Your answer is correct. . Let A be the set of 700 distinct people and let B be the 52 Incorrect: Your answer is incorrect. different unique combinations of first and last initials. If we construct a function from A to B, then by the Correct: Your answer is correct. principle, the function must be Correct: Your answer is correct. . Therefore, in a group of 700 people, it is Correct: Your answer is correct. that no two people have matching first and last initials.
Answer:
Yes, there are only 676 different possibilities, which is less than the number of people in the group.
Step-by-step explanation:
Assuming that the English alphabet has 26 different letters, the number of possible combinations of first and last name initials is:
[tex]n = 26*26\\n=676[/tex]
If we try to assign a different combination to each person in the group, it would only be possible to do it for the first 676 people, while the remaining 24 would have a repeated first and last initial. Therefore, the answer is yes, there must be 2 people who have matching first and last initials.
The Pigeonhole Principle in mathematics implies in a group of 700 people, there must be at least two people who have matching first and last initials.
Explanation:The concept of this problem involves understanding the Pigeonhole Principle in mathematics. Considering the English alphabet has 26 letters, we can have 26 possible first initials and 26 possible last initials. Therefore, there are 26x26=676 unique combinations of first and last initials. However, we have a group of 700 people which is more than 676. The Pigeonhole Principle states that if you try to distribute more items than there are containers, then at least one container must hold more than one item. Therefore, applying this principle, there must be at least two people among the group of 700 who have matching first and last initials because the number of people (700) is greater than the possible unique combinations of first and last initials (676).
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In a study of the relationship of the shape of a tablet to its dissolution time, 6 disk-shaped ibuprofen tablets and 8 oval-shaped ibuprofen tablets were dissolved in water. The dissolve times, in seconds, were as follows:
Disk: 269.0 249.3 255.2 252.7 247.0 261.6
Oval: 268.8 260.0 273.5 253.9 278.5 289.4 261.6 280.2
Can you conclude that the mean dissolve times differ between the two shapes?
Answer:
[tex]t=\frac{255.8-270.74}{\sqrt{\frac{(8.215)^2}{6}+\frac{(11.903)^2}{8}}}}=-2.788[/tex]
[tex]p_v =2*P(t_{(12)}<-2.788)=0.0164[/tex]
So the p value is a very low value and using any significance level for example [tex]\alpha=0.05, 0,1,0.15[/tex] always [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that we have significant difference in the means of the two groups
Step-by-step explanation:
Data given and notation
Disk:[269.0 249.3 255.2 252.7 247.0 261.6]
Oval:[ 268.8 260.0 273.5 253.9 278.5 289.4 261.6 280.2]
[tex]\bar X_{D}=255.8[/tex] represent the mean for the sample Disk
[tex]\bar X_{O}=270.74[/tex] represent the mean for the sample Oval
[tex]s_{D}=8.215[/tex] represent the sample standard deviation for the sample Disk
[tex]s_{O}=11.903[/tex] represent the sample standard deviation for the sample Oval
[tex]n_{D}=6[/tex] sample size for the group Disk
[tex]n_{O}=8[/tex] sample size for the group Oval
t would represent the statistic (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to check if the means are different, the system of hypothesis would be:
Null hypothesis:[tex]\mu_{D} = \mu_{O}[/tex]
Alternative hypothesis:[tex]\mu_{D} \neq \mu_{O}[/tex]
If we analyze the size for the samples both are less than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:
[tex]t=\frac{\bar X_{D}-\bar X_{O}}{\sqrt{\frac{s^2_{D}}{n_{D}}+\frac{s^2_{O}}{n_{O}}}}[/tex] (1)
t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.
Calculate the statistic
We can replace in formula (1) the results obtained like this:
[tex]t=\frac{255.8-270.74}{\sqrt{\frac{(8.215)^2}{6}+\frac{(11.903)^2}{8}}}}=-2.788[/tex]
Statistical decision
For this case we don't have a significance level provided [tex]\alpha[/tex], but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:
[tex]df=n_{D}+n_{O}-2=6+8-2=12[/tex]
Since is a bilateral test the p value would be:
[tex]p_v =2*P(t_{(12)}<-2.788)=0.0164[/tex]
So the p value is a very low value and using any significance level for example [tex]\alpha=0.05, 0,1,0.15[/tex] always [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that we have significant difference in the means of the two groups