What momentum of a 50kilogram ice skater gliding across the ice at a speed of 5m/s?

Answers

Answer 1
Momentum (P) = Mass (kg) * Velocity (m/s)

P = M * V
P = 50 * 5
P = 250

So momentum is 250 kgm/s

Answer 2

Answer:

Momentum (P) = Mass (kg) * Velocity (m/s)

P = M * V

P = 50 * 5

P = 250

So momentum is 250 kgm/s

Explanation:


Related Questions

Please help! A net force of 2.0 N acts on a 2.0-kg object for 10 seconds. What is the object’s kinetic energy after that 10 seconds (assuming the object starts from rest and there is no friction)?

Answers

For Newton's second law, the force F applied to the object of mass m will cause an acceleration a of the body:
[tex]F=ma[/tex]
So, the acceleration is 
[tex]a= \frac{F}{m}= \frac{2.0 N}{2.0 kg}=1 m/s^2 [/tex]

The object undergoes through this acceleration for 10 seconds, t=10 s. Since it is an accelerated motion, we can find its final velocity after 10 seconds:
[tex]v_f = v_i + at=0 m/s+(1m/s^2)(10 s)=10 m/s[/tex]
where [tex]v_i[/tex] is the initial velocity of the object, which is zero since it starts from rest.

Finally we can calculate the final kinetic energy of the object, which is given by
[tex]K= \frac{1}{2}mv^2= \frac{1}{2}(2.0 kg)(10 m/s)^2=100 J [/tex]

What is the velocity of the object at 20.0s

Answers

So notice that at the beginning of the motion, the object moves to 16m in a span of about 10 seconds. You should know that the velocity in a pvt graph is the slope, so here the v = 1.6 m/s more or less. At 20 seconds, the object doesn't seem to be moving and you see it stays still from 10-26ish seconds. From observing you can tell that there is no velocity, but the slope of this segment is zero so you can be sure of it. 

what is the net electrical charge on a magnesium ion that is formed when a neutral atom loses two electrons?

Answers

Recall that an electron has a charge of –1. Losing two electrons is a decrease by –2, which is the same as saying –(–2), which means a net charge of +2.

Calculate δe, if the system absorbs 7.24 kj of heat from the surroundings while its volume remains constant (assume that only p−v work can be done). express your answer using three significant figures.

Answers

I believe the answer is 7.24 kJ.
From the equation ΔE = dW + dQ; where W is the work done on/by the system and Q is the heat the system absorbs/loses.
Therefore; ΔE = 72.4 kJ since the system has bot done any p-v work (dV= zero) and has absorbed heat.

Answer:

[tex]\delta Q = \delta E = 7.24 kJ[/tex]

Explanation:

Heat absorbed by the system is given as

[tex]\delta Q = 7.24 kJ[/tex]

now from first law of thermodynamics we know that

[tex]\delta Q = \delta E + W[/tex]

here

W = work done by the system

[tex]\delta E[/tex] = change in internal energy

also we know that when volume of the system remains same then work done by the system must be zero

[tex]W = 0[/tex]

so from above equation

[tex]\delta Q = \delta E = 7.24 kJ[/tex]

Why is a small crescent of light often observed on the moon when it is exactly in the new phase?

Answers

Este suceso se llama Plenilunio. Es cuando la tierra esta en medio del sol y la luna.

Which platform did Mr. Ray’s marketing team advise him to use for the launch of a new product?
Mr. Ray is looking for a platform to launch his product. His marketing team advises him to launch the product via_____ as it is free advertising and improves_____.
1. A. Newspapers A. Product Quality
B.social Media B. Consumer Welfare
C.Billboards C. Brand Reconition

Answers

The answers are in answer B

Social Media and Brand Recognition

A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the electric field

Answers

The magnitude of the electric force exerted on a charge in an electric field is given by

[tex] F=qE [/tex]

where

q is the charge

E is the magnitude of the electric field


In this problem, we have a charge of [tex] q=6.0 \cdot 10^{-4} C [/tex], while the force exerted on it is [tex] F=4.5 \cdot 10^{-4}N [/tex], so we can rearrange the previous formula to calculate the magnitude of the electric field:

[tex] E=\frac{F}{q}=\frac{4.5 \cdot 10^{-4} N}{6.0 \cdot 10^{-4} C}=0.75 N/C [/tex]


Answer:

0.75

Explanation:

The Clean Air Act of 1963 was an improvement over the Air Pollution Control Act of 1955 because it _____.

Answers

Was the first act to actually set emissions towards factory smoke and pollution

How much does it cost to operate a 25-w soldering iron for 8.0 hours if energy costs 8.0¢/kwh?

Answers

The power P is defined as the energy E per unit of time t:
[tex]P= \frac{E}{t} [/tex]
In our problem, the power is P=25 W and the total time is t=8.0h, so we can calculate the total energy used during this time:
[tex]E=Pt=(25 W)(8.0 h)=200 Wh=0.2 kWh[/tex]
The energy costs 8€ per each kwh, so we can write the following proportion:
[tex]8€: 1kwh = x:0.2 kWh[/tex]
where x is the price corresponding to 0.2 kWh. Solving the proportion we find x:
[tex]x= \frac{(8€)(0.2 kWh)}{1kWh}=1.6 [/tex]€
Final answer:

To find the cost of operating a 25-watt soldering iron for 8 hours at an energy cost of 8.0 cents per kWh, first convert the iron's wattage to kilowatts, then multiply by the hours to get kWh, and finally multiply by the cost per kWh. The total cost comes to 1.6 cents.

Explanation:

To calculate the cost of operating a 25-watt soldering iron for 8.0 hours with electricity costing 8.0 cents per kilowatt-hour, we first need to convert the power usage into kilowatts and then multiply by the number of hours used to find the total energy consumed in kilowatt-hours (kWh). Finally, we multiply the energy consumed by the cost per kWh to find the total cost.

First, we convert watts to kilowatts:
25 watts = 0.025 kilowatts (kW).

Next, we multiply the power consumption by the number of hours used:
0.025 kW × 8.0 hours = 0.2 kWh.

Lastly, we calculate the total cost:
0.2 kWh × $0.08 per kWh = $0.016.

So, operating a 25-watt soldering iron for 8 hours would cost 1.6 cents.

Select all that apply. Greenhouse gases _____. absorb solar energy absorb carbon dioxide release carbon dioxide are released during the combustion of fossil fuels

Answers

Gases that trap heat in atmosphere are called Greenhouse gases (GHGs). Examples are carbon dioxide, water vapour, nitrous oxides etc.

The selected choices are that Greenhouse gases-

1. absorb solar energy

2. are released during combustion of fossil fuels.

A hydraulic jack is used to lift a car in order to change a tire. The car exerts a force of 9,800 N toward the ground due to the force of gravity.

1. To begin to lift the car, a hydraulic jack must produce ______ of force.

A. more than 9,800 N
B. less than 9,800 N
C. exactly 9,800 N

2. To keep the car in position once it is lifted, the jack must produce _____ of force.
A. more than 9,800 N
B. less than 9,800 N
C. exactly 9,800 N

Answers

To begin to lift the car, a hydraulic jack must produce
more than 9,800 N of force. (A)

To keep the car in position once it is lifted, the jack must
produce exactly 9,800 N of force. (C)

Force is defined as the product of mass and acceleration or gravity. Force is calculated in Newton.

The force required to lift the car should be more than 9,800 N, and, to keep the car in position, the force should be exactly same as 9,800 N.

The force is a vector quantity, calculated as the product of mass and acceleration (sometimes gravity.) In order to lift the car, Jack must apply a force greater than the weight of the car.

As given in the question,  the weight of the object is 9,800 N. The weight is equal to the force when the object is at rest.

Also, once the car is lifted, Jack must maintain the force exactly 9,800 N. The less force of the car will cause the gravity to pull the car downwards.

Therefore, the force should be exactly 9,800 N while lifting and should be more than 9,800 N, when beginning to lift the car.

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A 0.40 kg ball is suspended from a spring with spring constant 12 n/m . part a if the ball is pulled down 0.20 m from the equilibrium position and released, what is its maximum speed while it oscillates?

Answers

The total mechanical energy of the system at any time t is the sum of the kinetic energy of motion of the ball and the elastic potential energy stored in the spring:
[tex]E=K+U= \frac{1}{2}mv^2+ \frac{1}{2}kx^2 [/tex]
where m is the mass of the ball, v its speed, k the spring constant and x the displacement of the spring with respect its rest position.

Since it is a harmonic motion, kinetic energy is continuously converted into elastic potential energy and vice-versa.

When the spring is at its maximum displacement, the elastic potential energy is maximum (because the displacement x is maximum) while the kinetic energy is zero (because the velocity of the ball is zero), so in this situation we have:
[tex]E=U_{max}= \frac{1}{2}k(x_{max})^2 [/tex]

Instead, when the spring crosses its rest position, the elastic potential energy is zero (because x=0) and therefore the kinetic energy is at maximum (and so, the ball is at its maximum speed):
[tex]E=K_{max}= \frac{1}{2}m(v_{max})^2 [/tex]

Since the total energy E is always conserved, the maximum elastic potential energy should be equal to the maximum kinetic energy, and so we can find the value of the maximum speed of the ball:
[tex]U_{max}=K_{max}[/tex]
[tex] \frac{1}{2}k(x_{max})^2 = \frac{1}{2}m(v_{max})^2 [/tex]
[tex]v_{max}= \sqrt{ \frac{k x_{max}^2}{m} }= \sqrt{ \frac{(12 N/m)(0.20 m)^2}{0.4 kg} }=1.1 m/s [/tex]

The maximum speed of the 0.40 kg ball while it oscillates is approximately 1.10 m/s. This is found using the conversion of potential energy into kinetic energy at the equilibrium position. The mechanical energy principles of simple harmonic motion are applied.

To determine the maximum speed of a ball oscillating on a spring, we can use principles from simple harmonic motion. Given:

Mass of the ball, m = 0.40 kgSpring constant, k = 12 N/mDisplacement from equilibrium, x = 0.20 m

We start by calculating the total mechanical energy when the ball is at maximum displacement. The potential energy at maximum displacement is given by:

U = 0.5 * k * x2 = 0.5 * 12 N/m * (0.20 m)2 = 0.24 J

Since there is no damping, this total mechanical energy converts entirely into kinetic energy at the equilibrium position where the speed is maximum. The kinetic energy K at this point is:

K = 0.5 * m * [tex]v_{max}^2[/tex] = 0.24 J

Solving for [tex]v_{max}[/tex] :

[tex]v_{max}[/tex] = √((2 * K) / m) = √((2 * 0.24 J) / 0.40 kg) = √(1.2) ≈ 1.10 m/s

Therefore, the maximum speed of the ball while it oscillates is approximately 1.10 m/s.

. The penalties for a person's second DUI conviction include completion of __________ hours of DUI school.

Answers

The penalties for a person's second DUI conviction include completion of 21 hours of DUI school.


Please I need help with this I'll give medal.

Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is traveling in the same direction at 25 km/hr. Which of the following statements is true?


The momentum before the collision is equal to the momentum after the collision.

The momentum before the collision is greater than the momentum after the collision.

The momentum before the collision is less than the momentum after the collision.,

Answers

In this problem, we will be using the formula p=mv. Momentum equals mass times velocity. We need to first get km/hr into m/s as that is how velocity is measured. So, 1 kilometer is equal to 0.278 m/s. So we multiply 22 to get 6.116 m/s for Car A. Car B is 6.95 m/s. Take Car A now. p=1200 times 6.115 to get 7,338. Car B now is 1900 times 6.95 to get 13,205. Momentum stays the same. Therefore, the answer would be that the momentum before the collision is equal to the momentum after the collision.

Which best describes the current atomic theory?
A since it is only a theory it shouldn’t be used in practice
B it has not been tested enough to be useful for developing technology
C it is the most powerful explanation scientist have to offer at this time
D there is very lil change it will be changed in the future

Answers

Choice-C is a correct statement.

C. it is the most powerful explanation scientists have to offer at this time. I am 100% right, I just finish the test and got it right.

Which best explains what happens to the motion of the pendulum?
A.The mechanical energy transforms to thermal energy as the pendulum slows and eventually stops moving.
B.The mechanical energy disappears as the pendulum slows and eventually stops moving.
C.The pendulum will continue moving at the same speed until someone stops it because energy cannot be destroyed.
D.The pendulum will slow down but will never stop moving because energy cannot be destroyed.

Answers

The answer is A, I just learned about this a few days ago!
I think the answer is A

Holding a book while walking means i am doing work on the book. true or false

Answers

False, while holding the book it means there is no work done on the book.

Which has more thermal energy: lake or a cup of hot chocolate?

Answers

Though the hot cocoa would have a higher temperature, the lake would have more thermal energy because it has more molecules with a greater total internal energy.

Answer:

A cup of hot chocolate

Explanation:

A cup of hot chocolate will have more thermal energy has the hot cocoa would have a higher temperature, the lake would have more thermal energy because it has more molecules with a greater total internal energy.

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Which of the following always increases as a system becomes less organized? A. Entropy B. Heat C. Energy D. Temperature

Answers

Heat, because the particles are moving faster

Entropy, the measure of randomness or disorder in a system, increases when a system becomes less organized, such as when ice melts into water.

When a system becomes less organized, the measure of randomness or disorder that increases is known as entropy.

Entropy is a concept in thermodynamics representing the degree of disorder within a system. As energy disperses and becomes more random, entropy increases. This increase in entropy follows the second law of thermodynamics, which states that entropy of any isolated system not in equilibrium almost always increases; it can be thought of as a natural tendency for systems to move towards disorder and spread out energy. For instance, when ice melts into water, entropy increases because the ordered solid structure gives way to a more disordered liquid state, which requires energy input to maintain.

High-voltage power lines are a familiar sight throughout the country. the aluminum (resistivity = 2.82 x 10-8Ï m) wire used for some of these lines has a cross-sectional area of 4.1 x 10-4 m2. what is the resistance of 8.2 kilometers of this wire?

Answers

The formula that relates the resistance R of a wire with the resistivity [tex]\rho[/tex] of the material of the wire is
[tex]R= \frac{\rho L}{A} [/tex]
where L is the length of the wire (in our problem, [tex]L=8.2 km=8200 m[/tex]) and A is the cross sectional area (in our problem, [tex]A=4.1 \cdot 10^{-4} m^2[/tex]).
For the aluminim wire ([tex]\rho =2.82 \cdot 10^{-8} \Omega \cdot m[/tex]) of the problem, the resistance is
[tex]R= \frac{(2.82 \cdot 10^{-8}\Omega m)(8200 m)}{4.1\cdot 10^{-4}m^2}=0.564 \Omega [/tex]

With a quarter-turn flick of the wrist, a student sets the frisbee rotating at 570 rpm . what is the magnitude of the torque, assumed constant, that the student applies?

Answers

Due to missing information such as the time of the wrist flick or the frisbee's moment of inertia, we cannot calculate the exact torque that the student applied to the frisbee. To find the torque, we would need to determine the angular acceleration based on the provided angular velocity and the additional data.

To answer the question about the magnitude of the torque applied by a student to a frisbee rotating at 570 revolutions per minute (rpm), we need to consider several factors, including the angular velocity, the moment of inertia, and the time during which the torque was applied. However, the problem statement does not provide all the necessary information (like the time duration and the moment of inertia of the frisbee).

Typically, to calculate the torque, you would use the formula: torque (\(\tau\)) = moment of inertia (I) \(\times\) angular acceleration (\(\alpha\)). The angular acceleration could be found if we had the time duration for the quarter-turn and the final angular velocity.

Since these key pieces of data are missing in the student's problem, we cannot calculate the exact torque without additional information. If the time duration of the wrist flick or the moment of inertia of the frisbee were provided, we could find the angular acceleration using \(\alpha = \Delta\omega / \Delta t\), where \(\Delta\omega\) is the change in angular velocity and \(\Delta t\) is the change in time. From there, the torque could be calculated.

The torque applied by the student on the frisbee can be calculated using the formula torque = moment of inertia x angular acceleration. The primary force acting on the student when flicking the frisbee is the force applied perpendicular to the frisbee's radius.

Calculating the torque: To find the torque applied by the student on the frisbee, we can use the formula for torque, which is given by torque = moment of inertia × angular acceleration. First, convert the frisbee's initial angular velocity of 570 rpm to radians per second by multiplying by 2π/60.

Forces acting on the student: The primary force acting on the student when flicking the frisbee is the force applied perpendicular to the frisbee's radius. This force creates a torque and initiates the rotational motion of the frisbee.

HELP PLZ!!!
Which describes the difference between a bowling ball sitting in the rack waiting to be used and the bowling ball knocking pins down? A. In the rack, the bowling ball has only potential energy. As it knocks pins down, its potential energy has decreased, while its kinetic energy has increased. B. In the rack, the bowling ball has no energy at all. As it knocks down the pins the energy is 75% kinetic and 25% potential. C. In the rack and when knocking down pins, the potential energy and the kinetic energy of the bowling ball are equal. D. In the rack, the bowling ball has only kinetic energy. As it knocks pins down, its potential energy has increased, while its kinetic energy has decreased.

Answers

The answer would be A. In the rack, the bowling ball has only potential energy. As it knocks down pins, it’s potential energy has decreased while it’s kinetic increased.

Kinetic energy is the energy of motion and potential energy is stored energy when and object is not in motion

I hope this helped! :-)

Johnny was playing baseball with his friends and they noticed a bolt of lightning. They heard thunder seven seconds later. How far away is the storm?

Answers

To estimate the distance to a lightning strike, divide the number of seconds between seeing lightning and hearing thunder by five. With a 7-second delay, the storm is approximately 1.4 miles away.

The storm that Johnny and his friends experienced is associated with lightning and thunder. Light from lightning travels much faster than sound from thunder. This difference can be used to estimate the distance to a lightning strike. Since light travels at 3 × 108 meters per second, we see the lightning almost immediately. However, sound travels much slower, and for every 5 seconds we count after seeing lightning before hearing thunder, the storm is approximately 1 mile away.

In Johnny's case, they heard thunder 7 seconds after seeing lightning. Using the rule of thumb that every 5 seconds corresponds to about 1 mile, we can estimate the distance to the storm. 7 seconds divided by 5 gives us 1.4, so the storm is about 1.4 miles away from Johnny and his friends. This is a practical application of basic physics and the differences between light and sound velocity.

Highway curves are marked with a suggested speed. If this speed is based on what would be safe in wet weather, estimate the radius of curvaure for a curve marked 50km/h?The coefficient of static friction of rubber on wet concrete is .7, the coefficient of kinetic friction of rubber on wet concrete is .5 .

Answers

Radial (aka centripetal) acceleration keeps cars on an unbanked road in a curve. This acceleration is given by

[tex]a_{rad}= \frac{v^2}{r} [/tex]

The force required to keep in going in a circle is given by Newton's second law, F=ma.  Here a is the radial acceleration from the above equation, so we get a radial force:

[tex]F_{rad}=m \frac{v^2}{r} [/tex]

This force is mediated by the friction force between the tires of the car and the road.  For friction force we use the coefficient of friction and the normal force of the road on the car (which will also be the force of the car on the road).  On an unbanked road this is just the weight of the car, mg.  

The question now is, which coefficient of friction to use?  It might surprise you to find that although the car is moving relative to the road, we should use the static coefficient.  To see why this is the case, think about what the wheel's surface is doing as it meets the road.  As a wheel rotates around and comes into contact with the road surface, it's bottom section is moving in a direction opposite to the car's forward movement.  The point that actually touches the road is moving backward at the same speed that the car moves forward and so it is at rest with the street.  If this were not the case, your tires would always be skidding on the road.  (If you're having trouble seeing this, there are plenty of animations of this phenomenon on the internet). Once a car is skidding it is no longer in control and cannot turn like one that is not skidding.

So now the friction force is just

[tex]F_{fric}= \mu_s F_n=\mu_smg[/tex]

We now have to set these equal and solve for r, the radius of the circle we are traveling in.  Note that mass will cancel and so we don't need to worry about the mass of the cars involved:

[tex]m \frac{v^2}{r}=\mu_smg \\ \\ \frac{v^2}{r}=\mu_sg \\ \\ \frac{v^2}{\mu_sg}=r \\ \\ \frac{(13.89m)^2}{0.7*9.8 \frac{m}{s^2} } =28.12m[/tex]

Where I have converted the speed to m/s for unit consistency. 

The radius of curvature for wet weather is required.

The radius of curvature would be 28.1 m.

[tex]\mu_s[/tex] = Coefficient of static friction for wet concrete = 0.7

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

m = Mass of car

v = Velocity of car = 50 km/h

The force balance is

[tex]\dfrac{mv^2}{r}=\mu_s mg\\\Rightarrow r=\dfrac{v^2}{\mu_s g}\\\Rightarrow r=\dfrac{(50\times \dfrac{1000}{3600})^2}{0.7\times 9.81}\\\Rightarrow r=28.1\ \text{m}[/tex]

The radius of curvature would be 28.1 m.

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Which has a higher acceleration: a 10-kg object acted upon with a net force of 20 N or an 18-kg object acted on by a net force of 30 N?

A. Both accelerate at the same rate.

B. the 10-kg object

C. the 18-kg object

Answers

the first one accelerate at 2m/s
the second one accelerates at 1.6666m/s

therefore statement b. the 10kg object is your answer

hope this helps :)

Answer:

the answer is B, 10-kg object

Explanation:

Because of Newton we know that if a force is applied to an object, it will have an acceleration on the same direction of the force applied.

[tex]F=m*a\\\\where:\\m=mass\\a=acceleration[/tex]

in order to obtain the acceleration we have to reordenate the formula:

[tex]a=\frac{F}{m}[/tex]

The acceleration of the 10 kg object is:

[tex]a=\frac{20N}{10kg}=2\frac{m}{s^2}[/tex]

The acceleration of the object of 18 kg is:

[tex]a=\frac{30N}{18kg}=1.67\frac{m}{s^2}[/tex]

The biggest acceleration was for the object with less mass.

The mass of a bucket full of water is 15 Kg. It is being pulled up from a 15m deep well. Due to a hole in bucket 6 Kg of water flows out. Find the work done in pulling it out of the well.,

Answers

Solution:
workdone = change in potential energy 
W = Force times distance

= ( m -dm)g • ( x)
= mgx -(dm(gx))
= (15 × 10 × 15) -(6/15 gx.dx)
=2250 - (6/15 x10x 225/2)
=2250 -  (3 x 15x 10)
= 2250 - 450
= 1800 Joule
The answer is  1800 Joules.

The work done in pulling a bucket full of water with a weight of 15 kg that lost 6 kg of it from the hole from a well 15 m deep is 1350 Joules

Further Explanation;Work done Work done refers to the measure of energy when a body is moved by a force through a certain distance.Work done is therefore equivalent to energy transferred.Work done is given by the product of force acting on an object and distance moved by the object.Therefore; Work done = Force × distanceForce refer to a pull or a push and is measured in Newtons, N.Distance is measured in meters, m.

Thus; Work done is measured in Joules, J, or Nm

In this case;

Mass of the bucket is 15 Kg

However, 6 kg of water flew out due to the whole, therefore the remaining mass is 9 kg.

Force or Weight = Mass (kg) × 10 N/kg

Therefore;

Force = 90 Newtons

Distance = 15 m

Therefore;

Work done = 90 N × 15 m

                  = 1350 Joules

Hence; Work done pulling out the bucket from the well is 1350 Joules.

Key words: Work done, Force, Distance

Learn more about;Work done; https://brainly.com/question/12029835Force: https://brainly.com/question/11368524Example of work done: https://brainly.com/question/12029835

Level: High school

Subject: Physics

Topic: Work, power and simple machines

Which statements are correct? Check all that apply. A. An insulator slows the flow of heat. B. A conductor increases the flow of heat. C. A conductor decreases the flow of heat. D. An insulator speeds up the flow of heat.

Answers

A. An insulator slows the flow of heat. 
and 
B. A conductor increases the flow of heat.
are both correct!

Which statements are correct? Check all that apply.

A compass is used to make circles and arcs in geometric constructions.

A rough sketch by hand is considered a geometric construction.

Geometric constructions are created with a compass and straightedge.

Protractors are used in geometric constructions to measure degree measures.

Rulers are used in geometric constructions to measure segment lengths.

the answer is 1&3

You hear the engine roaring on a race car at the starting line. Predict the changes in the sound as the race starts and the car approaches the camera. A) The sound of the engine will get louder and the pitch lower. Eliminate B) The sound of the engine will get louder and the pitch higher. C) The sound is determined by the car and it will not change in any way. D) The sound of the engine will get louder but the pitch will not change.

Answers

B. The sound of the engine will get louder and the pitch higher.

Answer: The correct option is B.

Explanation:

Doppler effect is the phenomenon in which there is an apparent change in the frequency when there is relative motion between source and listener.

When the source and the listener are approaching each other then the frequency increases. The loudness depends on the amplitude. The energy of the wave is directly proportional to the square of the amplitude.

In the given problem, the engine is roaring on a race car at the starting line. There is change in the sound as the race starts and the car approaches the camera.

Pitch depends on the frequency.

Therefore, the sound of the wave will get louder and the pitch will get higher.

A 10-kilogram bicycle is traveling at a speed of 2m/s. what is the bike's kinetice energy?

Answers

The kinetic energy of an object of mass m moving with speed v is given by:
[tex]K= \frac{1}{2}mv^2 [/tex]
For the bicycle in our problem, [tex]m=10 kg[/tex] and [tex]v=2 m/s[/tex], so the kinetic energy is
[tex]K= \frac{1}{2}(10 kg)(2 m/s)^2=20 J [/tex]

What is the frequency of a microwave that has a wavelength of 0.050 m?

Answers

Answer:

[tex]6x10^9Hz[/tex]

Explanation:

we use a formula that relates the frequency and the wavelength:

[tex]f=\frac{c}{\lambda}[/tex]

where [tex]f[/tex] is the frequency of the wave, [tex]c[/tex] is the speed of light [tex]c=3x10^8m/s[/tex], and [tex]\lambda[/tex] is the wavelength.

We know that the wavelength is: [tex]\lambda=0.050m[/tex], so substituting the known values in the equation for the frequency we get:

[tex]f=\frac{3x10^8m/s}{0.05m} \\f=6x10^9s^{-1}=6x10^9Hz[/tex]

The frequency is:

[tex]6x10^9Hz[/tex]

Final answer:

The frequency of a microwave with a wavelength of 0.050 m is [tex]6*10^9[/tex] Hz, or 6000 MHz, calculated using the speed of light and the wavelength-to-frequency formula.

Explanation:

To calculate the frequency of a microwave that has a wavelength of 0.050 m, you can use the formula

c = λf, where c is the speed of light in a vacuum (approximately [tex]3*10^8[/tex] m/s), λ is the wavelength, and f is the frequency. Solving for f, the equation becomes

f = c / λ.

Let’s plug in the values:

f = ([tex]3*10^8[/tex] m/s) / (0.050 m)

After calculating, the frequency f is [tex]6*10^9[/tex] Hz, or 6000 MHz.

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