What NaCl concentration results when 309 ml of a 0.690 m NaCl solution is mixed with 467 ml of a 0.330 m NaCl solution?

Answer:

c = 0.25 j/g.°C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of metal = 50.0 g

Heat needed = 314 j

Initial temperature = 25°C

Final temperature = 50 °C

Specific heat = ?

Solution:

ΔT  = 50 °C - 25°C = 25°C

Q = m.c. ΔT

c = Q / m. ΔT

c = 314 j /  50.0 g . 25°C

c = 314 j / 1250 g. °C

c = 0.25 j/g.°C

Final answer:

The specific heat of the metallic element is calculated using the formula q = m x c x ΔT and for the provided values, it is found to be 0.2512 J/g°C.

Explanation:

To calculate the specific heat of a metallic element, we use the formula q = m × c × ΔT, where q is the heat energy transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. Given 50.0 g of the metal, 314 joules of heat, and a temperature change from 25°C to 50°C, we can rearrange the formula to solve for c: c = q / (m × ΔT).

The change in temperature (ΔT) is 50°C - 25°C = 25°C. Thus, the specific heat (c) can be calculated as follows:

c = 314 J / (50.0 g × 25°C)
= 314 J / (1250 g°C)
= 0.2512 J/g°C

Therefore, the specific heat of the metallic element is 0.2512 J/g°C.

Answer:

Heat flows from the reactor to the water

Explanation:

The thermal energy mentioned in the description is another way to say heat. The energy that is produced by the nuclear reactions leaves the reactor and enters the water, warming it.

The passage does not say that heat flows in the form of electricity, but rather that the turbines turned by the steam produce electricity.

The passage does not say that the steam produces the heat, but rather that the boiling of the water (caused by the heat) produces steam.

Answer:

B

Explanation:

Answer:

D. 182

Explanation:

right on e2020

Answer:

182 grams of oxygen gas must react to form 3.80 mol of aluminum oxide.

Explanation:

[tex]4Al + 3O_2\rightarrow 2Al_2O_3[/tex]

Moles of aluminum oxide = 3.80 mole

According to reaction, 2 moles of aluminum oxide is obtained from 3 moles of oxygen gas.

Then 3.80 moles of aluminum oxide will be obtained from:

[tex]\frac{3}{2}\times 3.80 mol=5.7 mol[/tex] of oxygen gas.

Mass of 3.80 moles of oxygen = 5.7 mol × 32 g/mol = 182.4 g ≈ 182 g

182 grams of oxygen gas must react to form 3.80 mol of aluminum oxide.

Answer:

P = 28.2 Kpa

Explanation:

Given data:

Volume = 35.5 L

Temperature = 223 K

Number of moles = 0.540 mol

R = 8.314 Kpa. L/mol.K

Pressure = ?

Solution:

PV = nRT

P = nRT / V

P = 0.540 mol . 8.314 Kpa. L/mol.K .223 K / 35.5 L

P = 1001.2 Kpa . L /35.5 L

P = 28.2 Kpa

Answer:c

Explanation:

Answer:

i believe its A

Explanation:

Answer:

B

Explanation:

Answer:

After 5th half life the remaining mass is 31.25 g.

Explanation:

Given data:

Total mass of carbon-14 = 1000 g

Mass remain after 5 half lives = ?

Solution:

At time zero = 1000 g

At first half life = 1000 g/2 = 500 g

At second half life =  500 g/ 2= 250 g

At third half life = 250 g/ 2 = 125 g

At 4th half life = 125 g/2 = 62.5 g

At 5th half life = 62.5 g/2 = 31.25 g

Thus after 5th half life the remaining mass is 31.25 g.

Answer:

The pOH of the solution is 13.176

Explanation:

The concentration of [tex]H_{3}PO_{4}[/tex] solution is 0.05 M

[tex]H_{3}PO_{4}[/tex] produces [tex]3\:H^{+}\:ions\:[/tex].

[tex]H_{3}PO_{4}\longrightarrow3H^{+}+PO_{4}^{3-}[/tex]

If the concentration of [tex]H_{3}PO_{4}[/tex] is 0.05 M, then the concentration of [tex]H^{+}\:ions\:[/tex] is three times that of [tex]H_{3}PO_{4}[/tex].

[tex][H^{+}]=3\times0.05=0.15M[/tex]

pH =-㏒([tex][H^{+}][/tex])= -㏒(0.15) =0.824

pOH = 14 - pH = 13.176

Answer:

D) speed

Explanation:

Reaction rates can be affected by several factors, including concentration, temperature, surface area and presence of a catalyst. Increasing concentration increases the number of effective collisions. Increasing temperature increases the kinetic energy of the particles, leading to more effective collisions

Answer:

D

Explanation:

Speed

Answer:

5

Explanation:

The full electronic configuration of the element is

1s²2s²2p63s²3p³

The total number of electrons = addition of the index

That is number of electrons = 2+2+6+2+3 = 15

Therefore the atomic number of the element is 15.

Name of element with atomic number 15 is Phosphorus with symbol P

Number of electrons in the atom of the element is 15.

Using KLMN configuration = 2:8:5

Therefore number of valence electrons is 5

I hope this was helpful, please mark as brainliest

The atom has 5 valence electrons.

The electron configuration provided indicates the arrangement of electrons in the atom's energy levels and sublevels. The last two energy levels are 3s and 3p. In this case, the 3s2 represents the filled s sublevel, and 3p3 represents the partially filled p sublevel. The valence electrons are those in the outermost energy level, so the atom in question has 5 valence electrons.

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Transistors

A(n) transistor can either amplify an electronic signal or switch a current on and off.

Explanation:

The main component of a transistor is a semiconductor. A transistor has at least three terminals. Voltage application through a pair of terminals affects the voltage of the other terminal. In addition, the controlling voltage can be lower than the controlled voltage, hence the amplification (gain) property of transistors. This same principle can be applied to switch on and off larger currents. If a controlling current surpasses a particular saturation point –specific to that transistor-, then it switches on the larger currents (controlled currents).

Transistors have much application in the world from being significant components in the electric circuits for speakers, hearing aids, calculators, computers, and most other digital gadgets.

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Answer:

Substances generate a smell when their molecules land on so-called olfactory neurones in our noses (which, for some things, is a pretty unpleasant thought). ... But this fails to explain why some molecules with similar shapes can smell completely different, while others with quite different shapes can have a similar scent.

Explanation:

I took chemistry

Different substances have different odors because they release unique molecular compounds into the air that are detected by olfactory receptors in the nose. Humans can distinguish a vast number of scents due to the variety of olfactory receptors we possess. Our sense of smell, tightly linked to our sense of taste, is crucial for our interactions with the environment and can evoke strong emotional responses.

Why Do Different Substances Have Different Odors?

Different substances have different odors because each releases unique molecules into the air, which interact with the olfactory receptors in the nose. Humans have approximately 350 olfactory receptor subtypes that combine to distinguish roughly 10,000 different odors. In contrast, animals like mice have around 1,300 receptor types, indicating a possibly broader range of detectable scents. When odor molecules, also known as odorants, enter the nose, they dissolve in the olfactory epithelium, stimulating the receptors, and send signals directly to the olfactory bulb of the brain. The complexity of the sense of smell is sophisticated enough that humans can differentiate an estimated 1.72 trillion different detectible smells according to research by Bushdid et al. (Science, 343, 2014).

Our sense of taste is also closely connected to our olfactory sense. Taste buds and odor receptors collaborate to create the perception of flavor, and when our ability to smell is inhibited, such as with congested nasal passages, our perception of taste is similarly diminished. Substances with different molecular structures stimulate different receptors, accounting for the wide array of smells we can detect, ranging from pleasant scents to the objectionable odors of thiols, such as those found in skunk spray. Odorants can evoke powerful emotional responses and memories, making our sense of smell an important aspect of our daily experiences and interactions with the world around us.

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Answer:

Empirical formula: CH₃O

Empirical formula mass = 31 g/mol

Explanation:

Data Given:

Molecular Formula = C₁₀H₃₀O₁₀

Empirical Formula = ?

Empirical Formula mass =

Solution

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

The ratio of the molecular formula should be divided by whole number to get the simplest ratio of molecule

As

C₁₀H₃₀O₁₀ Consist of  10 Carbon (C) atoms, 30 Hydrogen (H) atoms, and 10 Oxygen (O) atoms.

Now

Look at the ratio of these three atoms in the compound

                         C : H : O

                        10 : 30 : 10

Divide the ratio by two to get simplest ratio

                          C      :   H      :    O

                         10/10 : 30/10 : 10/10

                             1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

                     Empirical formula of C₁₀H₃₀O₁₀ =  CH₃O

Now

To find the empirical formula mass in g/mol

Formula mass:

Formula mass is the total sum of the atomic masses of all the atoms present in a formula unit.

**Note:

if we represent the molar mass of the empirical formula for one mol in grams then it is written as g/mol

So,

As the empirical formula of C₁₀H₃₀O₁₀ is CH₃O

Then Its empirical formula mass will be

CH₃O

Atomic Mass of C = 12

Atomic Mass of H = 3

Atomic Mass of O = 16

Total Molar mass of CH₃O

CH₃O = 12 + 3(1) + 16

CH₃O = 12 + 3 + 16

CH₃O = 31 g/mol

The empirical formula for C10H30O10 is C5H15O5 with an empirical formula mass of 151.15 g/mol.

Empirical formula: The empirical formula for C10H30O10 is C5H15O5.

Empirical formula mass: The empirical formula mass can be calculated by summing the atomic masses of the elements in the empirical formula: C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol. Therefore, the empirical formula mass is (5*12.01) + (15*1.008) + (5*16.00) = 151.15 g/mol.

Answer:

x = 5.9

Explanation:

Using Charles' Law, the new volume of a 2.5 L sample of gas at STP when the temperature is raised to 273°C (546 K), keeping pressure constant, is found to be 5.0 L.

The subject of this question is Chemistry, specifically related to gases and their behavior under different conditions of temperature and pressure. The question is asking for the new volume of a gas when its temperature is raised from the standard temperature and pressure (STP), which is 0°C or 273 K and 1.00 atm, to 273°C, given that the pressure remains constant.

To solve this, we use the Charles' Law, which states that, assuming the amount of gas remains the same and the pressure is constant, the volume of the gas is directly proportional to its temperature in Kelvins. Mathematically, Charles' Law is expressed as:

V1/T1 = V2/T2

Here, V1 is the original volume, T1 is the original temperature, V2 is the new volume, and T2 is the new temperature. Substituting in the given values:

V1 = 2.5 L (original volume)

T1 = 273 K (original temperature in Kelvins, which is the same as 0°C)

T2 = 273°C + 273 = 546 K (we convert the new temperature to Kelvins by adding 273)

The pressure remains constant, so the only variable that changes is temperature. To find the new volume (V2), the equation is rearranged to solve for V2:

V2 = (V1 \\times T2) / T1

After calculating, we get:

V2 = (2.5 L \\times 546 K) / 273 K

V2 = 5.0 L

Thus, when the temperature of the gas is increased to 273°C at constant pressure, the new volume of the gas will be 5.0 liters.

Answer:

i added this table for some help

Explanation:

here are some examples

metals:They are hard and shiny, strong, and easy to shape. They are used for many industrial purposes. This group includes iron, gold, silver, chromium, nickel, and copper, some of which are also noble metals.

non-metals:a chemical element (as boron, carbon, or nitrogen) that lacks the characteristics of a metal and that is able to form anions, acidic oxides, acids, and stable compounds with hydrogen.

metalloids:Physical properties are usually those that can be observed using our senses such as color, luster, freezing point, boiling point, melting point, density, hardness and odor. Metalloids have mixed properties which are difficult to characterize.

The sections of the periodic table are

Metals - are present at the center of the periodic table.

Non-metals - They are present on the right side of the periodic table.

Metalloids - They are present on the left side of the periodic table.

Metals are the elements which are present in the center of the periodic table. Metals are malleable, soft, and ductile, and they're used for causing many other matters.

Metals - They serve a variety of industrial functions. Iron, gold, silver, chromium, nickel, copper, and several other metals in this category are also noble metals.

Non-metals - Chemical elements that lack the properties of metals but may nevertheless produce anions, acidic oxides, acids, and stable compounds with hydrogen are referred to as non-metals. Examples include boron, carbon, and nitrogen.

Metalloids: Visually perceptible characteristics such as color, luster, melting temperature, freezing point, hardness, density, and odor are considered physical characteristics. Metalloids have complex features that make them challenging to categorize.

Thus, the position of metals, non-metal, and metalloids are given s the picture below.

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Answer:

[tex]\large \boxed{\text{1.38 g}}[/tex]

Explanation:

Two important formulas in radioactive decay are

[tex](1) \qquad t_{\frac{1}{2}} = \dfrac{\ln 2}{k}\\\\(2) \qquad \ln \left(\dfrac{N_{0}}{N}\right) = kt[/tex]

1. Calculate the decay constant k

[tex]\begin{array}{rcl}t_{\frac{1}{2}} &=& \dfrac{\ln 2}{k}\\\\\text{12.32 yr} &= &\dfrac{\ln 2}{k}\\\\k & = & \dfrac{\ln 2}{\text{12.32 yr}}\\\\& = & \text{0.056 26 yr}^{-1}\\\end{array}[/tex]

2. Calculate the mass remaining

[tex]\begin{array}{rcl}\ln \left(\dfrac{A_{0}}{A}\right) &= &kt \\\\\ln \left(\dfrac{\text{3.20 g}}{A}\right) &= &\text{0.056 26 yr}^{-1}\times \text{15 yr} \\\\\ln \left(\dfrac{\text{3.20 g}}{A}\right) &= &0.8439 \\\\\dfrac{\text{3.20 g}}{A} &= &e^{0.8439} \\\\\dfrac{\text{3.20 g}}{A}&= &2.325 \\\\A &= &\dfrac{\text{3.20 g}}{2.325}\\\\&= & \textbf{1.38 g}\\\end{array}\\\text{The final mass of the sample will be $\large \boxed{\textbf{1.38 g}}$}[/tex]

Answer: n = 1.30g

Explanation:

Answer:

D.

Explanation:

Energy is released after reaction, so this is exothermic reaction. D

Answer:

D

Explanation:

First of all, the reaction is exothermic. The equation is not normally written this way. The way it is written shows that energy is given off: the heat is a product. The only answer that is described is D

Exothermic (but oddly presented) and energy given off.

Answer:

3.2043 x 10²³

Explanation:

No. of Mole of lead (Pb) = 0.532 mol

No. of atoms of lead = ?

Solution:

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So,

The formula could be written as

no. of atoms of lead Pb = no. of moles x 6.023 x10²³

Put the values in above formula

no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³

no. of atoms of lead Pb = 3.2043 x 10²³

so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.

Answer:

The correct annswer is D)31p has 16 neutrons whereas 32p has 17 neutrons

Explanation:

An isotope is an atom of an element with the same atomic number (Z) but a different mass number (A). That is, one isotope differs from another by the number of neutrons

Z = number of protons

A = number of protons + number of neutrons.

For the phosphorus example (P), whose Z = 15:

31P -> A = 31 = number of protons + number of neutrons

Z = 15 = number of protons

A = 31 = number of protons + number of neutrons ->

31 = 15 + number of neutrons -> number of neutrons = 31-15 = 16

In the case of 32P:

A = 32 = number of protons + number of neutrons

32 = 15 + number of neutrons -> number of neutrons = 32-15 = 17

Answer:

D) 31p has 16 neutrons whereas 32p has 17

Explanation:

Apex Gang

Answer:

25 pancakes can be made.

Explanation:

This is a question based on the concept on of limiting reagent or limiting factor.

The pancakes can be kept on making till one of the item gets exhausted.

Let's, check which item gets exhausted first-

5 cups of flours are sufficient for making- [tex]\frac{5}{1}[/tex] × 5  ie. 25 pancakes considering we have 5×2 ie. 10 eggs and 5×1/2 ie. e 2.5 tsp of baking powder.

We can see that, we have all the required material needed and only the flour gets exhausted first.

But, still for our satisfaction we can check once, 12 eggs will make [tex]\frac{12}{2}[/tex]  × 5 ie. 30 pancakes, but we don't have flour for 30 of them.

Similarly, 4 tsp of baking powder will yield 40 pancakes but we neither have enough flour nor we have enough eggs for it.

Therefore, the maximum number of pancakes that can be made are is 25.

Final answer:

The maximum number of pancakes that can be created with 5 cups of flour, 12 eggs, and 4 teaspoons of baking powder is 25. Flour is the limiting ingredient in this scenario, determining the final count of pancakes.

Explanation:

When considering how many pancakes can be made with given amounts of ingredients, we must determine the limiting reactant, much like in a stoichiometric calculation in chemistry. The original pancake recipe calls for 1 cup of flour, 2 eggs, and  rac{1}{2} teaspoon of baking powder to make 5 pancakes.

We are provided with 5 cups of flour, 12 eggs, and 4 teaspoons of baking powder. To find out the maximum number of pancakes we can make, we identify the ingredient that will run out first when making batches of 5 pancakes. Here are the calculations based on the recipe proportions:

The ingredient that limits us here is the flour, which will only allow for the creation of 25 pancakes before it is used up. Therefore, the maximum number of pancakes that can be made with the ingredients on hand is 25.

Answer:

0.5583  g/L[/tex]

Explanation:

Since boron trifluoride ( B[tex]F_{3}[/tex] ) Is an ideal gas , we can apply IDEAL GAS EQUATION which is ,

PV  = nRT

Where ,

P - the pressure at which it is present (20 atm)

V - volume of the gas (needed)

n - number of moles of the gas taken (1 mol)

R - universal gas constant which is 8.314 [tex]JK^{-1} mol^{-1}[/tex]

T - temperature of the gas ( 273 + 20 = 298 K )

thus ,

[tex]20*V = 1*8.314*293\\V= 121.8001 L[/tex]

density ρ = [tex]\frac{mass}{volume}[/tex]

mass of  B[tex]F_{3}[/tex] is :

B : 11

F : 19

therefore , mass = 11 + [tex]3*19[/tex]

=68 g

density = [tex]\frac{68}{121.8001}  = 0.5583  g/L[/tex]

Boron has a very high melting point of 4,000 degrees Fahrenheit and a very low density of 2.37 grams per cubic centimeter.

To Calculate Density using the Density Formula.

The density calculation formula is p = m/V,

= 0.5583 g/L

An ideal gas, boron trifluoride (B) can be estimated by utilizing the ideal gas equation, which exists,

PV = nRT

Where, P stands for the pressure at which it exists.

V exists the gas's volume.

N exists the quantity of moles of gas consumed.

R exists the 8.314 universal gas constant.

T exist the gas's temperature (273 + 20 = 298 K).

If density = mass of B, then:

B : 11 and F : 19

Consequently, mass = 11 + = 68 g.

Boron has a very high melting point of 4,000 degrees Fahrenheit and a very low density of 2.37 grams per cubic centimeter.

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The ground state electron configuration of a neutral atom of titanium (atomic number 22) is represented as 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d², where electrons are filling up the energy levels and sublevels in sequence from lowest to highest according to the Aufbau Principle.

The ground state electron configuration of a neutral atom of titanium, which is a transition metal with an atomic number of 22, can be determined using the principle that electrons fill the lowest energy levels first. This principle is expressed in the Aufbau Principle.

Commonly, we start with hydrogen, which has the electron configuration of 1s¹. We progress with the filling of each electron in succeeding energy levels and sublevels until we get to the number of electrons equal to the atomic number of titanium, which is 22.

In this case, the ground state electron configuration of titanium will be as follows: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d².

This means that the innermost shell (n=1) has 2 electrons in the 's' sublevel, the next shell (n=2) has 2 electrons in the 's' sublevel and 6 in the 'p' sublevel, and so on.

Crucially, you can note that the last shell in the configuration is the third shell where we find 'd' electrons. The fourth shell fills with 's' electrons, and then the 'd' sublevel in the third shell begins to fill - this is a special feature of transition metals.

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C)

C)

D)...... ..........

Answer:

Explanation:

First one is C. It is not using chemicals to break in half, instead she is physically cutting the apple herself. Therefore , she is physically cutting the apple. Not sure on number two sorry. Hope this helps!

~ HAZEL360

Metals are identified using precipitation, visible-evidenced redox reactions, and complexation reactions.

Various tests, such as the spark test, flame test, chip test, fracture test, file test, hammer test, and plain observation, can be used to identify metals.

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Qualitative analysis of metals involves various methods such as flame tests, colorimetry, and chelation titration to identify metals.

Qualitative analysis: In addition to precipitatiokn, other means of qualitative analysis used to identify metals include flame tests, colorimetry, and chelation titration. Flame tests involve heating a sample of the metal and observing the characteristic color of the flame. Colorimetry uses the absorption or transmission of light by the metal ions to determine their concentration. Chelation titration involves the formation of a complex between the metal ion and a chelating agent, which can be detected using indicators or spectrophotometry.

Answer:

Air is a mixture of carbon dioxide, hydrogen and oxygen so it's a MIXTURE and NOT a COMPOUND.

Final answer:

The statement is false as water is the compound essential for all forms of life, not air.

Explanation:

The statement 'Air, not water, is the compound of life' is false. Water is a compound made up of hydrogen and oxygen and is essential for all forms of life on Earth. Water's unique properties, such as its polarity and its ability to stabilize temperature, make it indispensable for living organisms. For instance, it participates in chemical reactions within cells, helps with temperature regulation, and is a solvent for nutrients. While air is also important, providing oxygen for respiration, it is not considered a compound. Moreover, water, not air, is the most abundant molecule in Earth's atmosphere.

Answer:

1.1 x 10^4 J

Explanation:

Final answer:

The heat gained by the water when a metal sample is dropped into it can be determined using the formula q = mcΔT. For the given scenario, the water gains approximately 11000 J of heat.

Explanation:

To calculate the amount of heat gained by the water when a sample of metal is dropped into it, we can use the formula q = mcΔT, where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

For water, the specific heat capacity (c) is typically 4.184 J/g°C.

In this case, the water's mass (m) is 400.0 g and the change in temperature (ΔT) is 28.0 °C - 21.4 °C = 6.6 °C.

Using the formula, we get q = 400.0 g × 4.184 J/g°C × 6.6 °C, which equals approximately 11016 J.

Since the question specifies to use the correct number of significant figures, we report the answer as 11000 J of heat gained by the water.

Answer:

P(total) = 94.4 kpa

Explanation:

Given data:

Pressure of hydrogen gas = 3.0 kpa

Pressure of water vapors = 91.4 kpa

Total pressure =?

Solution:

According to Dalton law of partial pressure,

The total pressure exerted by mixture of gases is equal to the sum of partial pressure of the individual gas.

This expression can be written as,

P(total) = P₁ + P₂ + P₃ + ...... Pₙ

Now we will put the values in formula:

P(total) = P₁ + P₂

P(total) = 3.0 kpa + 91.4 kpa

P(total) = 94.4 kpa

Answer:

[tex]E=2052.8 kJ[/tex]

Explanation:

The energy absorbed by the water is the energy it requires to evaporate. So:

[tex] Heat of .vap= 40.65 kJ/mol[/tex]

The moles of water:

[tex]n_w=m_w *\frac{1000g}{2.2lbs}*\frac{1}{M}[/tex]

M is the water molecular weight

[tex]n_w=2 lbs *\frac{1000g}{2.2lbs}*\frac{1}{18g/mol}[/tex]

[tex]n_w=50.5mol[/tex]

The energy absorbed:

[tex]E=n_w*Heat of vap.=50.5mol *40.65 kJ/mol[/tex]

[tex]E=2052.8 kJ[/tex]

69.918 g

We are given;

We are supposed to determine the maximum theoretical yield of Iron from the blast furnace;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

Moles = Mass ÷ Molar mass

Molar mass of Fe₂O₃ = 159.69 g/mol

Therefore;

Moles of Fe₂O₃ = 100 g ÷ 159.69 g/mol

                          = 0.626 moles

From the equation;

1 mole of Fe₂O₃ reacts to produce 2 moles of Fe

Therefore;

Moles of Fe = Moles of Fe₂O₃ × 2

                    = 0.626 moles × 2

                    = 1.252 moles

Mass = Moles × molar mass

Molar mass of Fe = 55.845 g/mol

Therefore;

Mass of Fe = 1.252 moles × 55.845 g/mol

                  = 69.918 g

Therefore, the maximum theoretical mass of Iron metal obtained is 69.918 g

Final answer:

The maximum theoretical mass of iron from 100g of iron oxide can be calculated using stoichiometry, converted to moles, applied ratios from the chemical reaction, and then converted back to grams to get the iron mass.

Explanation:

The maximum theoretical mass of iron that can be made from 100g of iron oxide can be calculated using stoichiometry based on the balanced chemical equation for the reduction of iron oxide with carbon:

2Fe2O3 + 3C → 4Fe + 3CO2

To perform this calculation, you need the molar masses of iron (Fe) and iron oxide (Fe2O3). One mole of iron oxide has a mass of approximately 159.69 g/mol, and one mole of iron has a mass of approximately 55.85 g/mol. Using the equation:

Apply the stoichiometry to calculate the moles of Fe that can be produced.

Convert the moles of Fe back to grams to get the mass of iron.

The stoichiometry shows that from one mole of Fe2O3, you get two moles of iron. Therefore, from 100 g of iron oxide, you can theoretically produce:

100g Fe2O3
-------------  x 2 mol Fe x 55.85 g/mol Fe
159.69 g/mol Fe2O3

This will give the maximum theoretical mass of iron that can be produced from 100g of iron oxide. Keep in mind that the actual yield may be lower due to practical losses and inefficiencies in the reaction process in the blast furnace.

Answer:

[tex]2Mg+O_{2} \rightarrow 2MgO[/tex]

Explanation:

Synthesis reaction:

In the synthesis reaction, two reactants combined to form a single product.

For example,

"A" and "B" are two reactants then combined to form a "AB" product.

The chemical reaction is as follows.

[tex]A+B \rightarrow AB[/tex]

The product "MgO" is formed by magnesium reacts with oxygen to form Magnesium oxide.

The chemical reaction is as follows.

[tex]2Mg+O_{2} \rightarrow 2MgO[/tex]

In a synthesis reaction to create MgO, magnesium and oxygen combine, each molecule of magnesium combining with half a molecule of oxygen to produce a molecule of magnesium oxide. The MgO product is a white crystalline solid at room temperature. This follows the general AB form synthesis reaction.

The synthesis reaction to create MgO from its elemental components is represented by the simple equation:

In this reaction, magnesium (Mg) combines with oxygen (O₂) to form magnesium oxide (MgO). To balance the equation, we use 0.5 moles of oxygen for every mole of magnesium. The principle of conservation of mass requires that the number of each type of atom is consistent on both sides of the equation.

The product, magnesium oxide, is a white crystalline solid at room temperature. When considering the general form of a synthesis reaction, AB, magnesium (A) and oxygen (B) come together to form magnesium oxide (AB).

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