What part of a tidal power plant is the tidal water pushed through to generate electricity a.Turbine b.Barrage c.Boat d.Dam

The answer to the question on Edge is,

A. two

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The initial speed of the bolt is not 58.86 m/s.  

Let a be the acceleration of the rocket.  

During the 4 sec lift off, the rocket has reached a height of  

h = (1/2)*a*t^2  

with t=4,  

h = (1/2)*a^16  

h = 8*a  

Its velocity at 4 sec is  

v = t*a  

v = 4*a  

The initial velocity of the bolt is thus 4*a.  

During the 6 sec fall, the bolt has the initial velocity V0=-4*a and it drops a total height of h=8*a. From the equation of motion,  

h = (1/2)*g*t^2 + V0*t  

Substituting h0=8*a, t=6 and V0=-4*a into it,  

8*a = (1/2)*g*36 - 4*a*6  

Solving for a  

a = 5.52 m/s^2

Answer:

The stopping car has negative acceleration.

Explanation:

 We know acceleration is the rate of change of velocity. That is

            Acceleration(a) = ( Final velocity - Initial velocity )/ Time taken.

            Here Final velocity = 0 km/h( car stops) and initial velocity = 30 km/h

             So acceleration = (0-30)/time = -30/ time

             Time is always positive , so -30/time is negative, so the stopping car has negative acceleration.

Answer:

Incident rays parallel to the principle axis of a concave mirror will reflect through the focal point.

Explanation:

Answer:

Reference point

Explanation:

To explain the position of an object, we have to choose some location or point from where we start to observe the position of the object. This point is called reference point.

As we move leftwards from the reference point, the position of the object is taken as negative and if we move rightwards from the reference point, the position of the object is taken as positive.

By definition of average acceleration,

[tex]\bar a=\dfrac{\Delta v}{\Delta t}[/tex]

[tex]\implies15.0\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{160.0\,\frac{\mathrm m}{\mathrm s}-100.0\,\frac{\mathrm m}{\mathrm s}}{\Delta t}[/tex]

[tex]\implies\Delta t=4.00\,\mathrm s[/tex]

To extract 100.0 kg of titanium (Ti) from rutile (TiO2), we would need approximately 166.5 kg of rutile. This is calculated using the molar masses of Ti and TiO2 and the stoichiometry of the extraction process.

The extraction of titanium from rutile (titanium dioxide, TiO2) involves calculating the molar mass of the substances involved. The molar mass of Ti is approximately 47.87 g/mol, and the molar mass of TiO2 is approximately 79.87 g/mol. The stoichiometry of the extraction process indicates that 1 mol of TiO2 yields 1 mol of Ti. Therefore, the mass of TiO2 required to make a specific mass of Ti can be calculated as follows:

Mass of TiO2 = (Mass of Ti / Molar mass of Ti) * Molar mass of TiO2

Converting 100.0 kg of Ti to grams (since the molar mass is in grams per mol) gives 100,000 grams. Now we can substitute into the equation: (100,000 g Ti / 47.87 g/mol Ti) * 79.87 g/mol TiO2 = approximately 166,500 g of TiO2 or 166.5 kg. Therefore, we would need about 166.5 kg of rutile to produce 100.0 kg of Ti.

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To produce 100.0 kg of titanium (Ti) from rutile (TiO2), approximately 2089.67 moles of rutile are needed.

In order to determine how many kilograms of rutile are needed to produce 100.0 kg of titanium (Ti), we need to consider the molar ratio between the two substances. From the chemical formula of rutile (TiO2), we can see that there is a 1:2 ratio of titanium to oxygen. This means that for every 1 mole of titanium, there are 2 moles of oxygen.

To find the number of moles of titanium in 100.0 kg of Ti, we need to convert the mass to moles using the molar mass of titanium. The molar mass of titanium is approximately 47.87 g/mol. Therefore, 100.0 kg of Ti is equal to

100.0 kg × 1000 g/kg / 47.87 g/mol = 2089.67 mol of Ti.

Since there is a 1:1 ratio between titanium and rutile, we can conclude that 2089.67 mol of rutile are needed to produce 100.0 kg of Ti.

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Answer : Speed is 4.2 m/s

Explanation :

The combined mass of the boy and the skateboard is 65 kg

The momentum of the boy and the skateboard is 275 kg m/s

The momentum is given by:

p = m v

where m is the combined mass of boy and the skateboard.

v is the speed of both boy and the skateboard.

[tex]v=\dfrac{p}{m}[/tex]

[tex]v=\dfrac{275\ kg\ m/s}{65\ kg}[/tex]

[tex]v=4.23\ m/s[/tex]

The speed of the boy and the skateboard is 4.2 m/s

So, the correct option is (C).

Hence, this is the required solution.

Answer:

What is the wavelength in nm of a light whose first order bright band forms a diffraction angle of 19.0°, and the diffraction grating has 600.0 lines per mm?

543 nm

Explanation:

The wavelength in nm of a light whose first order bright band forms a diffraction angle of 19.0° is 543 nm.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave.

Using Huygen's principle of light, we have an expression

nλ =d sinθ

where, n is the order of maximum

           λ is the wavelength of light

           d is the distance between the lines on diffraction grating

           θ is the angle.

The distance between the lines on diffraction grating  is

d = 1 / (600 x 1000) or 0.00000167 m

For first order bright band, n = 1

Then, the wavelength will be

1 x λ = 0.00000167 x sin19.0°,

λ    = 0.000000543 m

 λ   = 543 nm

Thus, the wavelength of the first order bright band is 543 nm .

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Yes, how can I help you?

The IB Physics course, similar to AP Physics, provides high school students with an in-depth introduction to physics at a college level. Though these courses can prove challenging, as evidenced by a 30% withdrawal rate at ABC High School, they cover critical topics of physics and lay the groundwork for more advanced studies.

The question asks if anyone is taking IB Physics. The International Baccalaureate (IB) Physics course is similar to the Advanced Placement (AP) Physics course. Like AP Physics, the IB Physics course is a challenging program that provides high school students an in-depth study of physics similar to a college introductory course. However, these courses can be quite demanding, as denoted by the withdrawal rate from an elementary physics course in ABC High School being 30 percent for any given term.

In an IB Physics or AP Physics course, you will cover topics such as mechanics, thermodynamics, waves and sound, light and optics, and nuclear physics. The curriculum promotes depth of understanding over breadth of content, and organizes concepts around seven major themes known as the 'Big Ideas'. Despite a fear amongst many of difficult equations or memorizing formulas, these courses serve as a good foundation for future advanced physics courses at the college level.

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Neglecting air resistance, the horizontal speed of the package just before it hits the ground is <A) zero. B) less than 30 m/s but larger than zero.

I think the correct answer is true :)

Answer:

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

Explanation:

As shown in the figure, let point O is the starting point of Sosa. She travels 361 ft at an angle 50 degree with the horizontal.

sin 50 = [tex]\frac{OM}{OP}[/tex]

0.7660 = h / 361

h = 276.526 ft

h = 84.28 meter

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

Answer:

Option A is the correct answer.

Explanation:

The instantaneous acceleration = Change in velocity in velocity/Time taken

The slope of the graph should give instantaneous acceleration.

 Slope of a graph = Change in value of Y -axis / Change in values of X -axis

 Comparing both the equations

   Change in value of Y -axis = Change in velocity in velocity

   Change in values of X -axis = Time taken

So velocity values should be on the Y axis and Time values should be on the X axis.

Option A is the correct answer.

It depends on what is the reference frame where the velocity of the leaf (6 m/s) is measured.

If it is measured with respect to the creek, then the answer is simply "6 m/s south".

If it is measured with respect to the observer moving toward the leaf, then the velocity of the leaf relative to the ground is actually the sum between the velocity of the leaf relative to the observer (6 m/s south, so 6 m/s) and the velocity of the observer relative to the ground (2 m/s north, so -2 m/s):

[tex]v=v_l +v_o =6 m/s +(-2 m/s)=4 m/s[/tex]

and the direction is south.

The vertical position of the rock is given by:

[tex]y(t)=h+v_0 t -\frac{1}{2} gt^2[/tex]

where

h=75 m is the initial height

v0=20 m/s is the initial vertical velocity

g=9.81 m/s^2 is the acceleration due to gravity

The problem asks to find the time t at which the rock hits the ground, so the time t at which y(t)=0, so the equation above becomes:

[tex]75 + 20 t - 4.9t^2 =0[/tex]

Which has two solutions:

t=-2.37 s

t=6.45 s

The first solution is a negative time so it has no physical meaning, therefore the correct answer is t=6.45 s.

Answer:

  At time 6.45 seconds rock will hit ground.  

Explanation:

We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 Let us take up direction as positive, so displacement = -75 m, initial velocity = 20 m/s, acceleration = acceleration due to gravity = -9.8[tex]m/s^2[/tex]

 Substituting

    [tex]-75= 20*t-\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2-20t-75=0[/tex]

    t = 6.45 seconds or t =-2.37 seconds

    Since negative time is not possible, t = 6.45 seconds.

    So at time 6.45 seconds rock will hit ground.

Answer:

Option B, 11 m is the correct answer.

Explanation:

We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case u = 0 m/s , t = 1.5 seconds , a = acceleration due to gravity = [tex]9.8m/s^2[/tex], we need to find displacement

Substituting

     [tex]s= 0*1.5+\frac{1}{2}*9.8*1.5^2\\ \\ s=11.025m[/tex]

So option B, 11 m is the correct answer.

The type of circuit the situation models is: C) a parallel circuit because there is more than one path

After hearing about an accident on his normal route, Mr. Gujral checks for alternate routes to get to work, a parallel circuit because there is more than one path. Therefore, the correct option is option C.

Series and parallel circuits are the two basic categories into which circuits can be divided. Because the components of a series circuit are connected end to end, current travels through each component along the same path. The components of a parallel circuit, on the other hand, are connected side by side, creating several channels for the current to flow. Circuits are based on fundamental physical principles like Kirchhoff's Law and Ohm's Law. According to Ohm's Law, the current flowing through a conductor (such as a wire) is inversely proportional to its resistance and directly proportional to the voltage applied across it.

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6.

Basically, all of these questions use F = ma

m = 80 kg

a = 1.62

Weight = F = 80*1.62 = 129.6

The closest answer is B

7.

Step One

Find the mass here on earth

m = F/a

F = 40 kg

a = 9.2

F = 40/9.2 = 4.34

Now take everything to the moon

F = 20 kg

a = ??

m = 4.34

a = F/m = 20/4.34 = 4.6 m/s^2

8

m = 40 kg

F = 20 N

a = ??

a = F/m = 20N/40kg = 1/2 m/s^2

Comment

All of these depend on F = m*a.  None but the first one talk about vertical forces where gravity would play a part. Moving horizontally means that there is no gravitational force if there is no friction.  a = 9.8 has nothing to do with the problem.

The answer is B. Increases and here is why:

The Earth, the Sun, Trees, and basically everything has weight, but why does it have weight? Gravity is why it is hard to lift objects and move around, and the more mass that any object has will be subject to gravity and thus increase its gravitational pull.

The reason that lighting tends to strike bigger and taller objects is simply because the bigger objects draw the electricity in the lightning bolt to themselves due to their increased magnetic and gravitational pulls.

when heat is supplied to the the system then as per law of thermodynamics we can say

[tex]Q = \Delta U + W[/tex]

here we can say that heat is converted into the internal energy of gas and some work is done by the system after absorbing this heat.

So here when ice is melting the energy is supplied to the ice which converts into the internal energy of the ice.

Here this internal energy is used to break the bond of ice molecules so that its phase will convert from solid to liquid

So here we can say this heat or this internal energy as Latent heat of fusion of ice

So its formula is given as

[tex]Q = mL[/tex]

so here correct answer is

B) Energy is used to break bonds between molecules in ice.

The correct answer is B) Energy is used to break bonds between molecules in ice.

When ice melts, it undergoes a phase transition from solid to liquid at a constant temperature, which is 0°C (32°F) for water at standard atmospheric pressure.

During this process, the kinetic energy of the molecules (which is related to the temperature of the substance) does not increase because the added energy is not going into increasing the speed at which the molecules move.

Once all the ice has melted and the phase change is complete, any additional energy transferred as heat will then go into increasing the kinetic energy of the water molecules, resulting in an increase in temperature.

Therefore, the statement that Energy is used to break bonds between molecules in ice correctly explains why the temperature of melting ice does not change even though energy is being transferred as heat to the ice. The other options do not accurately describe the process occurring during the melting of ice:

A) The potential energy of the molecules does change as the ice melts; it increases as the molecules move further apart.

C) Kinetic energy is not being converted to chemical energy; rather, energy is being used to overcome the potential energy associated with the intermolecular forces.

D) The heat energy is not absorbed and then disappears; it is used to break the intermolecular bonds and is stored as potential energy in the separated molecules.

when object is placed on inclined plane then we will have net force along the inclined plane which is due to the component of weight along the incline

so we can say that

[tex]F_x = W sin\theta[/tex]

[tex]F_x = mgsin24[/tex]

now in order to find the acceleration we can use Newton's II law

[tex]F_{net} = ma[/tex]

[tex]mgsin24 = ma[/tex]

[tex]a = g sin24[/tex]

[tex]a = 4 m/s^2[/tex]

and the direction is along the inclined plane downwards as weight always pull downwards

So correct answer will be

B)4.0m/s2, directed down the slope

density (P) Mass (M) volume (V)

P=M/V

The relation that exists between the density (D), mass (M), and volume (V) body are related as follows -

D = M/V

The density (D), mass (M), and volume (V) of any body are use to give information about the physical properties of body.

Given is the density (D), mass (M), and volume (V) of a body.

The following relation exist between the density (D), mass (M), and volume (V) body are related as follows -

density (D) = mass (M) / volume (V)

D = M/V

Density is the measurement of amount of mass per unit volume of the body. Volume is the measurement of total space occupied by the body and mass is the measurement of amount of matter inside body.

Therefore, the relation that exists between the density (D), mass (M), and volume (V) body are related as follows -

D = M/V

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b 29 newtons

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

have to have a certain amount of letters

Answer:

B) 29 N

Explanation:

Weight is a vector quantity. Weight have both magnitude and direction. The weight of an object is the force of attraction towards the object. it might be gravity or reaction force.  The SI unit of weight is Newton . Weight can be can be calculated when you multiply the mass of an object and the gravitational acceleration. The weight of a particular object varies with location but the mass of the an object is same in any location. The weight of an object is measured with a scale.

Since the mass of the object is given , the weight can be calculated.

W = mass ×  gravitational acceleration

W = mg

m = 3.0 kg

g = 9.8 m/s²

w = 3.0 × 9.8

w = 29.4  N

Internal energy includes all the energies which are inside the system.  It includes kinetic energy, potential energy, chemical energy, nuclear energy and as well as the thermal energy. So, thermal energy is the portion of the internal energy and since, the thermal energy can be transferred from one body to another.

Hence, the answer is "Thermal energy is the portion of internal energy that can be transferred."

The inclusion of every form of energy is known as internal energy. The statement best describes internal energy is that "thermal energy is the portion of internal energy that can be transferred."

The total energy enclosed by a closed system is known as the internal energy of the system. It includes all forms of energy whether it is mechanical energy or thermal energy.

As per the concept of thermodynamics, "The energy is stored in the form of internal energy, after doing the subsequent amount of work". Moreover, Internal energy includes all the energies which are inside the system.  It includes kinetic energy, potential energy, chemical energy, nuclear energy, and as well as thermal energy. So, thermal energy is the portion of the internal energy since thermal energy can be transferred from one body to another.

Thus we can conclude that the statement best describes the internal energy is that "thermal energy is the portion of internal energy that can be transferred."

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The problem corresponds to the motion of a projectile (the salmon), with initial speed [tex]v_0[/tex], initial direction [tex]\theta=37.6^{\circ}[/tex] and vertical acceleration [tex]g=9.81 m/s^2[/tex] downward. The two equations which gives the horizontal and vertical position of the salmon at time t are

[tex]S_x (t) = v_0 cos \theta t[/tex] (1)

[tex]S_y (t) = v_0 sin \theta t - \frac{1}{2}gt^2[/tex] (2)

We can solve the problem by requiring Sx=3.16 m and Sy=0.379 m, the data of the problem.

Solving eq.(1) for t:

[tex]t=\frac{S_x}{v_0 cos \theta}[/tex]

And substituting this expression of t into eq.(2), we get the following expression for [tex]v_0[/tex]:

[tex]v_0 =\sqrt{\frac{g S_x^2}{2(tan \theta S_x -S_y)cos^2 \alpha}}[/tex]

And substituting the numbers into the equation, we find

[tex]v_0 = 6.16 m/s[/tex]

The main distinction between Newton's laws and Einstein's theory of relativity relates to the scenarios they describe accurately. Newton's laws function well in our daily experiences but fall short in extreme conditions. Einstein's theory, based initially on his hypotheses, covers these extreme conditions.

The primary difference between Newton's laws of motion and Einstein's theory of relativity relates to their scope and the types of scenarios they can accurately describe. Newton's laws of motion are based on common experiences and observations in our everyday world, such as explaining why an apple falls from a tree to the ground or why we move forward when a car suddenly stops. However, when it comes to very high speeds (close to the speed of light) or strong gravitational fields, Newton's laws become less accurate.

On the other hand, Einstein's theory of relativity, which was initially based on his hypotheses, expands upon Newton's laws and provides a comprehensive framework for understanding how space, time, and gravity interact in such extreme scenarios like the event horizon of black holes, or how time slows down when we move at high speeds.

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