What term refers to group behavior seen in animals of a similar type?

Answers

Answer 1
swarm behavior x))))))))))))))))))
Answer 2

Answer:

The correct answer is swarm behavior.

Explanation:

Swarming or swarm behavior is a collective behavior demonstrated by entities, mainly the animals of same size that accumulate together, specifically moving in masses or migrating in some direction or milling about the same spot. As a term, swarming is applicable mainly to insects, however, it can also be applied to any other animal or entity, which demonstrates swarm behavior.


Related Questions

Select the incorrect statement.
The physical properties of a compound are similar to those of its elements.
The boiling point of a compound is different from the individual elements.
The melting point of a compound is different from the individual elements.
Density is a physical property.

Answers

This is incorrect
The physical properties of a compound are similar to those of its elements.

Answer:

The incorrect statement is:

The physical properties of a compound are similar to those of its elements.

Explanation:

The physical properties of a compound depend on its elements but they are not similiar to the physical properties of individual elements.

Take water as an example. Water is made by oxygen and hydrogen (H₂O). At normal , water is liquid and both oxygen and hydrogen are gases.

What are three ways that carbon atoms can be arranged in hydrocarbon molecules?

Answers

Answer is: carbon atoms can be arranged straight chain, branched chain and ring.
Hydrocarbon is an organic compound consisting of hydrogen and carbon.
In straight chain carbon atoms are bonded with only two other carbon atoms in elongate chain.
In branched chain at least one carbon is bonded with more than two other carbon atoms.
Ring chain hydrocarbons are cyclic hydrocarbons.

This is for a study guide for my semester final, and I have no clue how to answer this, please help, and please at least try to help!
Besides the major types of radioactive decay, there are two others: positron emission and electron capture.
• Compare and contrast positrons with electrons.
• Explain how positron emission works and how it causes transmutations.
• Explain how electron capture works and how it causes transmutations.
• Compare the transmutations caused by positron emissions and electron capture.

Answers

Positron emission = emission of a positron and a neutrino when a proton is convert into a neutron. The total number of particles in the nucleus doesn't change, -1 proton +1 neutron

It's a spontaneous reaction for some nucleus.

eg:

Positron = e+

Neutrino=ve

O-15 --> N-15 + e+ +ve

Electron capture= A nucleus absorb an electron while a proton is convert in a neutron and emit a neutrino. The total number of particles in the nucleus doesn't change, -1 proton +1 neutron

eg:

Al-26 +e- --> Mg-26 + ve

Electron capture and positron emission are two mechanisms to explain the decay of some unstable isotopes. Electron capture is usually observed when the energy difference between the initial and final state is low. Mainly because of the larger amount of kinetic energy need for the expulsion two particles with the positron emission mechanism.


Determine the hydroxide ion concentration in a solution that is 0.0033 m hno3. answer in units of m.

Answers

Answer is: the hydroxide ion concentration is 3.03·10⁻¹² M.
Chemical dissociation of nitric acid in water: HNO₃(aq) → H⁺(aq) + NO₃⁻(aq).
c(HNO₃) = [H⁺] = 0.0033 M, because nitric acid is strong acid, nitric acid ionize completely so it percent ionization is 100%.
[H⁺] · [OH⁻] = 10⁻¹⁴ M².
[OH⁻] = 10⁻¹⁴ M² ÷ 0.0033 M.
[OH⁻] = 3.03·10⁻¹² M.

how many grams of lithium are needed to produce 45.0 grams of lithium nitride, according to the following process?

6 Li(s) + N2(g) → 2 Li2N(s)

Answers

Answer:
             33.41 g of Li

Solution:

The Balanced Chemical equation is ,

                              6 Li(s) + N₂ (g)    →    2 LiN (s)

According to equation,

      55.76 g (2 mole) Li₂N is produced from  =  41.4 g (6 mole) Li
So,
              45 g of Li₂N will be produced from  =  X g of Li

Solving for X,
                                X  =  (45 g × 41.4 g) ÷ 55.76 g

                                X  =  33.41 g of Li

What is the final pressure of a system (atm) that has the volume increased from 0.75 l to 1.1 l with an initial pressure of 1.25 atm? 1.1 0.85 1.8 1.2 none of the above?

Answers

Boyle's law states that pressure is inversely proportional to volume of gas at constant temperature 
PV = k
where P - pressure , V - volume and k - constant 
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting these values in the equation 
1.25 atm x 0.75 L = P x 1.1 L
P = 0.85 atm 
final pressure is B) 0.85 atm 

Final answer:

The final pressure of the system is 0.85 atm.

Explanation:

To determine the final pressure of the system, we can use the relationship between volume and pressure known as Boyle's Law. According to Boyle's Law, when the volume of a gas increases, the pressure decreases, and vice versa, at constant temperature and amount of gas.

In this case, the initial volume is 0.75 L and the final volume is 1.1 L. Since the volume increased, we can expect the pressure to decrease. The initial pressure is 1.25 atm. Using Boyle's Law, we can set up the equation:

P1 * V1 = P2 * V2

1.25 atm * 0.75 L = P2 * 1.1 L

Solving for P2, we get: P2 = 1.25 atm * 0.75 L / 1.1 L = 0.85 atm

Therefore, the final pressure of the system is 0.85 atm.

The ___ is the part of the solution that is dissolved and the ___ is the part of the solution that does the dissolving.

Answers

Answers: 
_______________________________________________________
1)   "solute" ; 
_______________________________________________________
2)  "solvent" .
_______________________________________________________
       "The   solute  is the part of the solution that is dissolved, and the   solvent  is the part of the solution that does the dissolving."
_______________________________________________________

What is the main difference between DNA and RNA? DNA contains ribose sugar, and RNA contains deoxyribose sugar instead. DNA contains cytosine, and RNA contains guanine instead. DNA contains deoxyribose sugar, and RNA contains ribose sugar instead. DNA contains adenine, and RNA contains guanine instead.

Answers

DNA contains deoxyribose sugar, and RNA contains ribose sugar

DNA contains ribose sugar, and RNA contains deoxyribose sugar instead. Therefore, the correct option is option A.

What are DNA and RNA?

The complex molecular structures deoxyribonucleic acid (DNA) consequently ribonucleic acid (RNA) regulate all genetic traits of cells, and hence of species. DNA, which makes up the genetic material of all free-living species, is the ultimate life-plan. In addition to being the genetic makeup of some viruses, RNA employs DNA to code out the molecular makeup of proteins made in cells.

The two structures differ chemically in a number of ways. The "backbone" of DNA, or deoxyribose, is a sugar, like the acronym deoxyribonucleic acid suggests. The sugar ribose, which is slightly different, is present in ribonucleic acid (RNA). DNA contains ribose sugar, and RNA contains deoxyribose sugar instead.

Therefore, the correct option is option A.

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What volume of 6.00 m naoh solution is required to prepare 0.50 ml of 0.15 m naoh solution

a. 12.5 ml of naoh

b. 25 ml of naoh

c. 30 ml of naoh?

Answers

M1V1 = M2V2

Molarity of Solution 1 x Volume of Solution 1 = Molarity of Solution 2 x Volume of Solution 2

First of all, I think you mean .5 Liters?

(6M)(V) = (.15M)(.5L)

V = .0125 L x 1000 mL / Liter = a. 12.5 mL

Final answer:

To prepare 0.50 mL of a 0.15 M NaOH solution from a 6.00 M NaOH solution, you would need 12.5 μL of the concentrated solution according to the dilution formula, which is not listed among the provided answer options.

Explanation:

The volume of 6.00 M NaOH solution required to prepare 0.50 mL of 0.15 M NaOH solution can be found using the dilution formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the concentrated solution, and M2 and V2 are the molarity and volume of the diluted solution, respectively. Plugging the known values into the equation: (6.00 M)(V1) = (0.15 M)(0.50 mL) ⇒ V1 = (0.15 M)(0.50 mL) / (6.00 M) = 0.0125 mL or 12.5 μL.

Since none of the provided answer choices (a) 12.5 mL, (b) 25 mL, or (c) 30 mL match this result, it seems there might be a typo or a misprint in the question. To prepare 0.50 mL of a 0.15 M solution from a 6.00 M solution, you would need substantially less than 1 mL of the concentrated solution. The likely correct volume needed, based on the question's data, would be 12.5 μL, which is not listed as an option in the question.

Determine the molecular formula of a compound having the empirical formula C9H17O and a molar mass of 847.56g/mol.

Answers

 The  molecular  formula of a compound  having  the empirical  formula  C9H17O  is calculated as below

(C9H17O)n =847.56

{(12 x9 + 1 x17 + 1 x16)}n= 847.56

147 n = 847.56
divide bot
h side by 147
n= 6

(C9H17O)6 therefore the molecular formula = C54H102O6

Which phase(s) would experience an increase in the rate of dissolution with an increase in temperature?

A. gases only
B. solids only
C. liquids only
D. both solids and liquids

Answers

D. both solids and liquids

We wish to dilute some 18.4 m h2so4 solution to make 600 ml of a 0.1 m h2so4 solution. how much of the 18.4 m solution should we start with?

Answers

we can use the following formula when making diluted solutions from concentrated solutions
c1v1 = c2v2
where c1 is concentration and v1 is volume of the concentrated solution 
and c2 is concentration and v2 is final volume of diluted solution 
substituting the values in the equation
18.4 M x V = 0.1 M x 600 mL 
V = 3.26 mL
volume of 3.26 mL of 18.4 M sulfuric acid solution should be taken and diluted upto 600 mL

We should start with approximately [tex]3.10 ml[/tex] of the [tex]18.4 M[/tex] [tex]H\(_2\)SO\(_4\)[/tex] solution to make [tex]600 ml[/tex] of a [tex]0.1 M[/tex] [tex]H\(_2\)SO\(_4\)[/tex] solution.

To solve this problem, we can use the dilution formula:

[tex]\[ C_1V_1 = C_2V_2 \][/tex]

where:

[tex]\( C_1 \)[/tex] is the concentration of the stock solution ([tex]18.4 M[/tex] [tex]H\(_2\)SO\(_4\)[/tex]).

[tex]\( V_1 \)[/tex] is the volume of the stock solution we need to use (unknown).

[tex]\( C_2 \)[/tex] is the concentration of the final solution ([tex]0.1 M[/tex] [tex]H\(_2\)SO\(_4\)[/tex]).

[tex]\( V_2 \)[/tex] is the volume of the final solution ([tex]600 ml[/tex] or [tex]0.6 L[/tex]).

We want to find [tex]\( V_1 \)[/tex], so we rearrange the formula:

[tex]\[ V_1 = \frac{C_2V_2}{C_1} \][/tex]

Now, plug in the values:

[tex]\[ V_1 = \frac{(0.1 \text{ M})(0.6 \text{ L})}{18.4 \text{ M}} \][/tex]

[tex]\[ V_1 = \frac{0.06}{18.4} \][/tex]

[tex]\[ V_1 =0.00326 \text{ L} \][/tex]

Since [tex]1 L = 1000 ml[/tex], we convert [tex]\( V_1 \)[/tex] to milliliters

[tex]\[ V_1 = 0.00326 \text{ L} \times 1000 \text{ ml/L} \][/tex]

[tex]\[ V_1 = 3.26 \text{ ml} \][/tex]

Rounding to two decimal places, we find that we need approximately [tex]3.10 ml[/tex] of the [tex]18.4 M[/tex] [tex]H\(_2\)SO\(_4\)[/tex] solution to make [tex]600 ml[/tex] of a [tex]0.1 M[/tex][tex]H\(_2\)SO\(_4\)[/tex] solution.

Write the balanced nuclear equation for alpha decay of polonium−218. include both the mass numbers and the atomic numbers with each nuclear symbol. use the "sup-subscript" button in the answer palette to enter these numbers correctly. greek letters can be accessed in the drop-down menu that says "-select−."

Answers

Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.
Nuclear reaction: ₈₄²¹⁸Po → ₈₂²¹⁴Pb + α (alpha particle).
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

Adding salt to water when boiling vegetables or pasta makes the water boil at a higher temperature. How much would the boiling point of water be increased if 49.2 g of NaCl is added to 500 mL of water? (Remember that the density of water is 1 g/mL and kb for water is 0.51 oC/m)

Answers

Adding a non-volatile solute in solvent, increases the boiling point of solvent. This is referred as elevation in boiling point. The increase in boiling point is mathematically expressed as
ΔTb = Kb X m    ....... (1)
where, Kb = molal elevation constant =  0.51 oC/m
m = molality of solution = [tex] \frac{\text{weight of solute (g)}}{\text{Molecular weight X Weight of solvent (Kg)}} [/tex]

Given: weight of solute = 49.2 g
volume of solution = 500 ml
Density of water = 1 g/ml

∴  weight of solvent = 500 g = 0.5 kg

Also,we know that molecular weight of NaCl = 58.5

∴m = molality of solution = [tex] \frac{\text{49.2}}{\text{58.5 X 0.5}} [/tex]
                                        =  1.68 m

The molality of solution is 1.68 m      ......  (2)

Substituting 2 in 1 we get 
ΔTb = Kb X m = 0.51 x 1.68 = 0.8568 oC

Thus, increase in boiling point of water is 0.8568 oC
Final boiling point of solution = 100 + 0.8565 = 100.8568 oC

The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 mc030-1.jpg N2 + 3I2 The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

Answers

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?


0.0136 

Answer:

0.0135 moles of iodine will be formed.

Explanation:

[tex]2NI_3\rightarrow N_2+3I_2[/tex]

Moles of nitrogen triiodide =[tex]\frac{3.58 g}{394.71 g/mol}=0.0090 mol[/tex]

According to reaction 2 moles of nitrogen triiodide gives 3 moles of iodione gas.

Then 0.0090 mol of nitrogen triiodide will give:

[tex]\frac{3}{2}\times 0.0090 mol=0.0135 mol[/tex]

0.0135 moles of iodine will be formed.

The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.

Answers

CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
                       CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial                Y                   -                 -
Change           -X                  +X              +X
Equilibrium      Y-X                 X                X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

                Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
                    X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
                                                     = 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
                                                 = 5.79 x 10⁻³ g/L

Final answer:

The solubility product constant (Ksp) of calcium carbonate is used to calculate the solubility of this compound in water. Considering the 1:1:1 molar ratio between CaCO3 and the ions it forms on dissolution, we derive the solubility as 0.0058 g/l.

Explanation:

The subject of your question is the solubility product constant (Ksp) of calcium carbonate (CaCO3). The Ksp is used to calculate the solubility of a compound, such as CaCO3, in a given solvent, which in this case is water. The Ksp is given as 3.36 × 10-9 M² and it is this value that we will use to determine the solubility.

As we know, for the dissolution of calcium carbonate into calcium and carbonate ions, the dissolution reaction can be written as: CaCO3(s) → Ca²+ + CO3²-. Here, it implies that there is a 1:1:1 molar ratio between CaCO3 and the ions it forms on dissolution. Thus, if 's' represents the molarity of CaCO3, then the Ksp expression can be written as Ksp = [Ca²+][CO3²-] = s².

Using the given Ksp value, we can solve the above equation for 's': s = sqrt(Ksp) = sqrt(3.36 × 10-9 M²) = 5.8 × 10-5 M. However, the question asks for the solubility in g/l. To convert molarity (M) to g/l, we multiply by the molecular weight of the compound. For CaCO3, the molecular weight is approximately 100 g/mol. Therefore, the solubility is 5.8 × 10-5 M x 100 g/mol = 0.0058 g/l.

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What volume, in milliliters, of 2.0 calcium chloride stock solution would you use to make 500 ml of 0.300 m of calcium chloride cacl2 solution?

Answers

we can use the following formula when making diluted solutions from more concentrated solutions.
c1v1 = c2v2 
where c1 is the concentration and v1 is the volume of the concentrated solution 
and c2 is concentration and v2 is volume of the diluted solution to be prepared 

substituting these values in the equation 
2.0 M x V = 0.300 M x 500 mL 
V = 75 mL

75 mL should be taken from the stock solution and diluted upto 500 mL to make the 0.300 M solution 

Which aqueous solution has the lowest freezing point c6h12o6, c2h5oh, ch3cooh, or nacl?

Answers

Depression of a freezing point of the solutions depends on the number of particles of the solute in the solution.
1 mol of C6H12O6 after dissolving in water still be 1 mol, because C6H12O6 does no dissociate in water.
1 mol of C2H5OH after dissolving in water still be 1 mol, because C2H5OH does no dissociate in water.
1 mol of NaCl after dissolving in water gives 2 mol of particles (ions), because NaCl is a strong electrolyte(as salt) and completely dissociates in water.
NaCl ----->Na⁺ + Cl⁻
1 mol of CH3COOH after dissolving in water gives more than 1 mol but less than 2 moles, because CH3COOH is a weak electrolyte (weak acid) and dissociates  only partially. 

So, most particles of the solute is going to be in the solution of NaCl, 
so the lowest freezing point has the aqueous solution of NaCl.

Among C₆H₁₂O₆, C₂H₅OH, CH₃COOH, and NaCl, NaCl is the one that will provide the aqueous solution with the lowest freezing point.

We have 4 aqueous solutions and we want to determine which has the lowest freezing point.

C₆H₁₂O₆C₂H₅OHCH₃COOHNaCl

What is the freezing point depression?

Freezing-point depression is a drop in the temperature at which a substance freezes, caused when a smaller amount of another, non-volatile substance is added.

We can calculate the freezing point depression (ΔT) using the following expression.

ΔT = Kf × b × i

where,

Kf is the cryoscopic constant for water.b is the molality of the solution.i is the Van't Hoff factor.

Assuming all the solutions have the same molality, the freezing point depression will be a function of the van't Hoff factor.

What is the van't Hoff factor?

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.

For non-electrolytes, such as C₆H₁₂O₆ and C₂H₅OH, i = 1. Comparing NaCl and CH₃COOH, we can determine that i(NaCl) > i(CH₃COOH) because NaCl is a strong electrolyte and CH₃COOH a weak one.

Thus, NaCl, with the highest Van't Hoff factor, will have the lowest freezing point.

Among C₆H₁₂O₆, C₂H₅OH, CH₃COOH, and NaCl, NaCl is the one that will provide the aqueous solution with the lowest freezing point.

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Ka for hcn is 4.9 ⋅ 10-10. what is the ph of a 0.068 m aqueous solution of sodium cyanide? ka for hcn is 4.9 10-10. what is the ph of a 0.068 m aqueous solution of sodium cyanide? 0.74 7.00 2.96 13.24 11.07

Answers

Answer is: pH of solution of sodium cyanide is 11.07.
Chemical reaction 1: NaCN(aq) → CN⁻(aq) + Na⁺(aq).
Chemical reaction 2: CN⁻ + H₂O(l) ⇄ HCN(aq) + OH⁻(aq).
c(NaCN) = c(CN⁻) = 0.068 M.
Ka(HCN) =  4.9·10⁻¹⁰.
Kb(CN⁻) = 10⁻¹⁴ ÷ 4.9·10⁻¹⁰ = 2.04·10⁻⁵.
Kb = [HCN] · [OH⁻] / [CN⁻].
[HCN] · [OH⁻] = x.
[CN⁻] = 0.068 M - x..
2.04·10⁻⁵ = x² / (0.068 M - x).
Solve quadratic equation: x = [OH⁻] = 0.00116 M.
pOH = -log(0.00116 M) = 2.93.
pH = 14 - 2.93 = 11.07.

The pH of the sodium cyanide solution is 11.56.

Let the cyanide ion be X

We have to set up the ICE table for the problem as follows;

     X^-(aq) + H2O(l)  ⇄ HX(aq) + OH^-(aq)

I    0.068                            x                 x

C   -x                                 + x                +x      

E   0.068 - x                      x                   x

But Kb = Kw/Ka = 1 × 10^-14/4.9 × 10-10

Kb = 2 × 10^-4

So;

Kb = [HX] [OH^-]/[X^-]

2 × 10^-4 = x^2/ 0.068 - x  

2 × 10^-4(0.068 - x) = x^2

1.36 × 10^-5 - 2 × 10^-4x = x^2

x^2 + 2 × 10^-4x - 1.36 × 10^-5 = 0

x= 0.0036 M

Since x = [OH^-] = 0.0036 M

pOH = - log(0.0036 M)

pOH = 2.44

pH = 14 - 2.44 = 11.56

The pH of the sodium cyanide solution is 11.56.

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What is the product when Bismuth (symbol Bi, atomic number 83, and radioisotope with mass number of 214) emit an alpha particle?
Give the name (or symbol) of the new element, its atomic number, and its mass.

Answers

Thallium is the new element
TI is its symbol
Atomic no. Is 81
Mass is 204.38

Answer : The correct answer is Name = Thallium (Th) , atomic mass = 210 and atomic number = 81 .

Alpha decay :

When atomic nucleus emits an alpha particle that process is known as alpha particle decay . The symbol of alpha particle is [tex] ^4_2He [/tex] . where 4 is atomic mass ( 2 protons + 2 neutrons ) and 2 atomic number .

When alpha particle is released the resultant nuclei (daughter nuclei) have 4 less atomic mass and 2 less atomic number .

Example for nuclear equation of alpha decay can be expressed as:

[tex] {_{90}^{230}Th} \rightarrow {_2^4He} + {_{88}^{226}Ra} [/tex]

Given :

Radioisotope = Bi Atomic mass = 214 Atomic number = 83

When it will release alpha particle , atomic mass will be decreased by 4 and atomic number by 2 .

Atomic mass = 214 - 4 = 210 Atomic number = 83-2 = 81

The atom with atomic number 81 is Thallium (Th) . Hence the daughter nuclei so produced is [tex] ^2^1^0_8_1Th [/tex]

The nuclear reaction can be written as :

[tex] ^{214}_{83}Bi \rightarrow _2^4He + _{81}^{210}Th [/tex]


When fracking liquid waste is left in pools on the surface, _ can evaporate into the air and contribute to pollution

Answers

When fracking liquid waste is left in pools on the surface, Toxic Waste or Toxic Chemicals can evaporate into the air and contribute to pollution. A new study shows that these spills have left surface waters in the area carrying radium, selenium, thallium, lead, and other toxic chemicals that can continue for years at unsafe levels. 

Volatile organic compounds (VOCs) can evaporate from fracking liquid waste pools, contributing to air pollution. These pools may also contain hazardous air pollutants and heavy metals, requiring careful handling to avoid environmental contamination.

When fracking liquid waste is left in pools on the surface, volatile organic compounds (VOCs) can evaporate into the air and contribute to pollution. These wastewater ponds can contain a variety of pollutants, including hazardous air pollutants such as benzene, toluene, ethylbenzene, and xylene. Moreover, fracking fluid, also known as flowback, can contain chemicals used in the drilling process, heavy metals, and radioactive materials. These substances pose a significant risk to both environmental and human health if they are not properly managed and treated.

The process of hydraulic fracturing or 'fracking' involves injecting high-pressure fluids to fracture shale deposits, which releases trapped gas and oil. The wastewater from this process may return to the water cycle, but the large volume of contaminated water requires careful handling to prevent land and water pollution. As a proactive measure, governments around the world have taken steps, in some cases banning the practice due to the severe risks associated with fracking.

Calculate the percent composition by mass of oxygen in litharge (gram formula mss=223.2 grams per mole)

Answers

The  %  composition  by mass  of oxygen in litharge ( grams formula mass=223.2 g/mol) is  calculated as  below

%  composition is   percentage  by mass  of  each   element  in a  compound
which  is  calculated  as follows

%composition = molar mass  of element/molar  mass  of  compound  x100

The  molar mass of oxygen = 16 g/mol

therefore the % composition  = 16 g/mol/ 223.2 g/ mol  x100 = 7.17 %  of oxygen
Litharge is a yellow oxide of lead with a formula of PbO, which is formed by heating lead metal in air. 
The mass of one mole of PbO is 223.2 grams
1 mole of PbO contains 16 g of oxygen
Therefore; the percentage of oxygen will be;
     (16/223.2) × 100 = 7.168 %

Increasing ratios of oxygen-18 to oxygen-16 in glacial ice indicate ________.
a. advancing ice sheets
b. warming temperatures
c. increased volcanic emissions
d. uplift of land surfaces

Answers

Final answer:

An increased ratio of oxygen-18 to oxygen-16 in glacial ice indicates warming temperatures as oxygen-18 is a heavier isotope and precipitates less readily in cold conditions.

Explanation:

The ratio of oxygen-18 to oxygen-16 in glacial ice is often used as an indicator of past climatic conditions. When this ratio is increasing, it typically indicates warming temperatures.

This is because oxygen-18 is a heavier isotope that precipitates less readily in cold conditions

Therefore, a higher ratio of oxygen-18 suggests that it was warm enough for more of this heavier isotope to precipitate. So, the correct answer is b. warming temperatures.

Learn more about Isotopes here:

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Identify the element that has a ground state electronic configuration of [ar]4s23d104p 3 .

Answers

The element is arsenic.

Is it possible to get the elliptic discriminate of an elliptic curve with characteristic 2?

Answers

yes, it is possible to get the elliptic discriminate of an elliptic curve with characteristic 2

Which of the following best describes the changes involved in a fission reaction?

The nucleus of an atom splits into fragments, releasing a large amount of energy.
The nucleus of an atom splits into fragments, absorbing a large amount of energy.
The nuclei of two small atoms combine to form one larger nucleus, releasing a large amount of energy.
The nuclei of two small atoms combine to form one larger nucleus, absorbing a large amount of energy.

Answers

The correct answer is this: THE NUCLEUS OF AN ATOM SPLITS INTO FRAGMENTS, RELEASING A LARGE AMOUNT OF ENERGY.
Nuclear fission is the process in which the nucleus of a radioactive element split into two different nucleic of smaller sizes of different elements with a large release of energy. Nuclear fission process is usually used to provide energy for electricity generation. 

In a fission reaction, the nucleus of an atom splits into fragments, releasing a large amount of energy. Nuclear fission occurs when a heavy nucleus like uranium absorbs a neutron and splits, emitting additional neutrons, gamma rays, and energy.

The correct description of the changes involved in a fission reaction is: The nucleus of an atom splits into fragments, releasing a large amount of energy. Nuclear fission is a nuclear reaction where the nucleus of an atom, such as uranium-235 or plutonium-239, splits into smaller nuclei after absorbing a neutron.

This process produces additional free neutrons, gamma radiation, kinetic energy of fission fragments, and releases a significant amount of energy. The process is exothermic, and the energy released can be harnessed for electricity generation in nuclear reactors or can be used in nuclear weapons.

Nuclear fission differs from nuclear fusion, which is the combining of two smaller atomic nuclei to form a larger nucleus, also releasing energy. In both processes, large amounts of heat and radiation are emitted. However, for fission, a fissile material like uranium or plutonium is necessary to sustain the reaction, and it involves the breakup of a heavy nucleus into lighter elements.

In the chemical reaction: 2 h 2 (g) o2 (g) → 2 h2o (g), with 8 grams of h 2 (2 grams/mole) and 16 grams of o2 (32 grams/mole) and the reaction goes to completion, what is the excess reactant and how much of that would remain

Answers

Use stoichiometric ratio to determine which is in excess and which is limiting

Which of the following are indicators of a chemical change? Select all that apply.

color change
temperature change
precipitate formation
gas formation
cutting a solid into smaller pieces

Answers

Which of the following are indicators of a chemical change? Select all that apply.

These are the answers:

color change
temperature change
precipitate formation
gas formation

Hope this helps.

Which is the best description of a chain of custody?
A) A list of all personnel entering the crime scene.
B) A log of which family member has ownership of the evidence.
C) A log of which agency controls the evidence so the case stays in the correct jurisdiction.
D) A log of who has handled the evidence and when so the integrity of the evidence is upheld.

Answers

D) A log of who has handled the evidence and when so the integrity of the evidence is upheld.

How many carbon atoms will be in the longest chain 3,3,4,4-tetramethylhexane

Answers

Just look at the name, it tells you the longest C chain. Ending with hexane means that the longest carbon chain is 6 C's long.
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