Answer:
celulares por que tienen una fuente de energiq
You are using a pressure cooker to make rice. After 10 minutes, you hear a loud “BANG.” You walk into the kitchen to find that the pressure cooker has exploded. Which gas law explains this?
(Keep in mind that you set the temperature of the cooker one time and you do not change it again)
A) Avogadro’s Law (relationship between number of moles of a gas and volume) B) Boyle’s Law (relationship between pressure and volume)
C) Charles Law (relationship between temperature and volume)
D) Dalton’s Law (looks age partial pressures of gases in a container)
E) Gay-Lussac’s Law (relationship between pressure and volume)
An explosion in a pressure cooker can be explained by Boyle's Law, which states that pressure and volume are inversely related at constant temperature.So,option B is correct.
The explosion of a pressure cooker while making rice can be explained by Boyle's Law, which relates the volume and pressure of a gas under conditions of constant temperature. According to Boyle's Law, if a gas is compressed to a smaller volume without changing the temperature, the pressure of the gas increases. In a pressure cooker, when the steam cannot escape, the pressure continues to rise, and if the volume is constricted, the cooker may not be able to withstand the increased pressure, leading to an explosion. Therefore, the correct answer to the question is B) Boyle’s Law (relationship between pressure and volume).
A metal salt with the formula MSO4 crystallizes from water to form a solid with the composition MSO4⋅3H2O. At 298 K, the equilibrium vapor pressure of water above this solid is 14.7 Torr. MSO4⋅3H2O(s)↽−−⇀MSO4(s)+3H2O(g) What is the value of ΔG for the reaction when the vapor pressure of water is 14.7 Torr?
To find the value of ΔG for the reaction MSO4⋅3H2O(s)↽−−⇀MSO4(s)+3H2O(g) at the given vapor pressure of water, use the equation ΔG = -RTln(K), where ΔG is the change in Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.
Explanation:The reaction can be represented as: MSO4·3H2O(s) <--> MSO4(s) + 3H2O(g)
The equilibrium vapor pressure of water above the solid is 14.7 Torr.
Since we are given the equilibrium condition, we can use the equation ΔG = -RTln(K), where ΔG is the change in Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.
By plugging in the given values, we can calculate the value of ΔG at the equilibrium condition.
The value of [tex]\Delta G[/tex] for the reaction when the vapor pressure of water is 14.7 Torr is approximately 2.005 kJ/mol.
The value of [tex]\Delta G[/tex] for the reaction at 298 K when the vapor pressure of water is 14.7 Torr is given by the equation:
[tex]\[ \Delta G = -RT \ln \left( \frac{P_{H_2O}^3}{P_{H_2O}^{eq}} \right) \][/tex]
where:
- [tex]\( \Delta G \)[/tex] is the change in Gibbs free energy,
- [tex]R[/tex] is the universal gas constant (8.314 J/(mol·K)),
- [tex]T[/tex] is the temperature in Kelvin (298 K in this case),
- \[tex]\( P_{H_2O}^3 \)[/tex] is the partial pressure of water raised to the power of the moles of water in the reaction (which is 3),
- [tex]\( P_{H_2O}^{eq} \)[/tex] is the equilibrium vapor pressure of water (14.7 Torr).
First, we need to convert the equilibrium vapor pressure of water from Torr to atmospheres to match the units of the gas constant [tex]R[/tex]. The conversion factor is 1 atm = 760 Torr.
[tex]\[ P_{H_2O}^{eq} = \frac{14.7 \text{ Torr}}{760 \text{ Torr/atm}} = 0.01934 \text{ atm} \][/tex]
Now we can plug in the values into the equation:
[tex]\[ \Delta G = -(8.314 \text{ J/(mol·K)}) \times (298 \text{ K}) \times \ln \left( \frac{(0.01934 \text{ atm})^3}{(0.01934 \text{ atm})} \right) \][/tex]
[tex]\[ \Delta G = -8.314 \times 298 \times \ln \left( (0.01934)^2 \right) \][/tex]
[tex]\[ \Delta G = -8.314 \times 298 \times \ln \left( 0.000373 \right) \][/tex]
[tex]\[ \Delta G = -8.314 \times 298 \times (-7.936) \][/tex]
[tex]\[ \Delta G = 8.314 \times 298 \times 7.936 \][/tex]
[tex]\[ \Delta G = 2004.8 \text{ J/mol} \][/tex]
[tex]\Delta G = 2.005 kJ/mol[/tex]
Consider the following four pairs of molecules. You may use 1H-NMR, 13C-NMR, or IRspectroscopyto differentiate the structures, but you may use a technique only once on this page(i.e. each pair mustuse a different technique).For each pair, pick one of the above forms of spectroscopy and describe the single clearest difference between the two compounds by that analytical technique.
Answer:
The question is incomplete. The structures were not added to the question. Find attached of the structure and the given answer.
Explanation:
See the attached file for explanation
Three buffers are prepared using equal concentrations offormic acid (HCOOH) and sodium formate, hydrofluoric acid (HF) andsodium fluoride, and acetic acid (CH3COOH)and sodium acetate. Rank the three buffers from highest to lowest pH.
The question given is incomplete because the Ka of the acids were not provided. I got the complete question from google as below:
Three buffers are prepared using equal concentrations offormic acid (HCOOH) and sodium formate, hydrofluoric acid (HF) andsodium fluoride, and acetic acid (CH3COOH)and sodium acetate. Rank the three buffers from highest to lowest pH.
According to the text, the Ka of the acids are as follows:
HCOOH: 1.77 × 10–4
HF: 6.8 × 10–4
CH3COOH: 1.76 × 10–5
Answer:
Based on the Ka values of the acids given, the arrangement of the acids given from the highest to lowest pH is as below:
HF > HCOOH > CH3COOH
Explanation:
For acids, the higher the pH, the higher the pK , also, the lower the pH, the lower the pK.
then
pKa = -log(Ka)
So,
The acid with the highest pH will have the highest Ka value , while the acid with the lowest pH will have the lowest Ka value.
Thus, based on the Ka values of the acids given, the arrangement of the acids given from the highest to lowest pH is as below:
HF > HCOOH > CH3COOH
The buffers are ranked from highest to lowest pH based on the pKa values of the weak acids: acetic acid (highest pH), formic acid, and hydrofluoric acid (lowest pH).
To rank the buffers from highest to lowest pH, we can refer to the pKa values of the corresponding weak acids, since the buffers are prepared using equal concentrations of the weak acids and their conjugate bases. The higher the pKa, the weaker the acid, and therefore the higher the pH of its buffer when the concentrations of the acid and its conjugate base are equal.
The pKa of acetic acid (CH₃COOH) is approximately 4.76.
The pKa of formic acid (HCOOH) is approximately 3.75.
The pKa of hydrofluoric acid (HF) is approximately 3.17.
Therefore, the acetic acid and sodium acetate buffer will have the highest pH, followed by the formic acid and sodium formate buffer, with the hydrofluoric acid and sodium fluoride buffer having the lowest pH.
Calculate Δ H rxn for the reaction: 5 C ( s ) + 6 H 2 ( g ) → C 5 H 12 ( l ) Use the following reactions and given ΔH’s: C 5 H 12 ( l ) + 8 O 2 ( g ) → 5 CO 2 ( g ) + 6 H 2 O ( g ) Δ H = − 3244.8 kJ C ( s ) + O 2 ( g ) → CO 2 ( g ) Δ H = − 393.5 kJ 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( g ) Δ H = − 483.5 kJ
Answer: The enthalpy of reaction is, -173.2 kJ
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
[tex]5C(s)+6H_2(g)\rightarrow C_5H_{12}(l)[/tex] [tex]\Delta H=?[/tex]
The intermediate balanced chemical reaction will be,
(1) [tex]C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(g)[/tex] [tex]\Delta H_1=-3244.8kJ[/tex]
(2) [tex]C(s)+O_2(g)\rightarrow CO_2(g)[/tex] [tex]\Delta H_2=-393.5[/tex]
(3) [tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex] [tex]\Delta H_3=-483.5kJ[/tex]
Reversing (1) , Multiply (2) by 5 , (3) by 3 and add
[tex]\Delta H=\Delta H_1+5\times \Delta H_2+3\times \Delta H_3[/tex]
[tex]\Delta H=(+3244.8)+(5\times -393.5)+(3\times -483.5)[/tex]
[tex]\Delta H=-173.2kJ[/tex]
Therefore, the enthalpy of reaction is, -173.2 kJ
Explain how the atom is a part of the electrical current process.
When an area has a net flow of electric charge, an electric current is considered to be present. Electrons traveling via a wire in electric circuits frequently carry this charge.
What is electric current?
One or more of the electrons from each atom are only weakly connected to the atom in metals, allowing them to move around freely inside the metal. Electric current is a term used to describe how much electricity flows across a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A). The more electricity flowing across the circuit, the higher the ampere value.
If you imagine electricity as the flow of water in a river, it will be simple to understand. When the electrons collide, the current is the number of electrons flowing per second.
Like current, voltage is a word that is frequently used in relation to electrical circuits. Volts are used to measure voltage (V). Voltage and the movement of electrons in a circuit are connected, just like current and current are. Voltage is the amount of force driving the flowing electrons, whereas the current is the flow of electrons.
Therefore, when there is a net flow of electric charge through an area, an electric current is said to exist. In electrical circuits, electrons traveling over a wire frequently carry this charge.
Read more about electric current, here
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Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachloride would be produced by this reaction if 1.1 mL of chlorine were consumed? Be sure your answer has the correct number of significant digits.
Answer:
0.55mL of carbon tetrachloride
Explanation:
CH4(g) + 2Cl2(g) -------> CCl4(g) + 2H2(g)
From the balanced reaction equation
44800mL of chlorine produces 22400 ml of carbon tetrachloride
If 1.1mL of chlorine were consumed, volume of carbon tetrachloride= 1.1×22400/44800
=0.55mL of carbon tetrachloride
Note: 1 mole of a gas occupies 22.4L volume or 22400mL
Which of the following acid/base pairs would be best for making a buffer with a pH of 8.00?
1.Acid Formula Ka1 Ka2 Ka3 Acetic acid CH3COOH 1.8×10-5
2.Ascorbic acid H2C6H6O6 7.9×10-5 1.6×10-12
3.Carbonic acid H2CO3 4.2×10-7 4.8×10-11
4.Hydrocyanic acid HCN 4.0×10-10
5.Hydrofluoric acid HF 7.2×10-4
6.Hypochlorous acid HClO 3.5×10-8
7.Phosphoric acid H3PO4 7.5×10-3 6.2×10-8 4.8×10-13
8.Sulfurous acid H2SO3 1.7×10-2 6.4×10-8
Answer:
7. Phosphoric acid H₃PO₄ 7.5×10⁻³ 6.2×10⁻⁸ 4.8×10⁻¹³
3. Carbonic acid H₂CO₃ 4.2×10⁻⁷ 4.8×10⁻¹¹
Explanation:
Their blend will result to the closest pH of 8.00
research to obtain more information about where we get our fuel supply.Evaluate and communicate how technology affects the supplies of nonrenewable resource.
Answer:
hola como estas
Explanation:
Which statement below correctly describes how amino acids join?
Amino acids join by linking the amino groups of the two compounds together.
Amino acids join by formation of amino bonds between them.
Amino acids join by forming an ester linkage.
Amino acids form bonds via E1 elimination reactions.
Amino acids join by linking the acid group of one amino acid to the amino group of another.
Answer:
Amino acids join by linking the acid group of one amino acid to the amino group of another.
Explanation:
Amino acids are organic molecules that form the basic molecules for making proteins and there are. An amino acid comprises of an acidic carboxyl (-COOH) functional group and an amino group (-NH2) as well as a side an organic side chain (R group).
In the formation of proteins, several amino acids join together by the formation of peptide bonds between each amino acids to form a long polypeptide. These peptide bods are formed by the linking of the acidic carboxyl group of one amino acid to the amino group of another amino acid, during this process water is removed.
The pressure in a bicycle tire is __55.0__psi at __30.0__˚C in Phoenix. You take the bicycle up to Flagstaff, where the temperature is _5.0___˚C. What is the pressure, in kPa, in the tire?(Volume and Amount of moles is held constant)
Answer:
[tex]p_2=347.9kPa[/tex]
Explanation:
Hello,
In this case, we use the Gay-Lussac's law which allows us to understand a gas' pressure-temperature behavior as a directly proportional relationship:
[tex]\frac{p_1}{T_1}= \frac{p_2}{T_2}[/tex]
Whereas it is convenient to use the pressure in kPa and the temperature in kelvins in order to compute the required resulting pressure, therefore:
[tex]p_1=55.0psi*\frac{6.89476kPa}{1psi} =379.2kPa\\T_1=30.0+273.15=303.15K\\T_2=5.0+273.15=278.15K[/tex]
Thus, we obtain:
[tex]p_2= \frac{p_1T_2}{T_1}=\frac{379.2kPa*278.15K}{303.15K}\\ \\p_2=347.9kPa[/tex]
Best regards.
Answer:
The pressure in the tire at 5.0 °C is 347.91 kPa
Explanation:
Step 1: Data given
The pressure in a bicycle tire is 55.0 psi
Temperature = 30.0 °C = 303 K
Temperature decreases to 5.0 °C = 278 K
Volume and Amount of moles are held constant
Step 2: Calculate the pressure at the new temperature
P1/T1 = P2 / T2
⇒with P1 = the initial pressure of the bicycle tire is 55.0 psi
⇒with T1 = the initial temeprature = 303 K
⇒with P2 = the pressure at the new temperature
⇒with T2 = the decreased temperature = 278 K
55.0 psi / 303 K = P2 / 278 K
P2 = (55.0 psi / 303 K) * 278 K
P2 = 50.46 psi
Step 3: Convert pressure from psi to kPa
50.46 psi = 50.46 * 6.895 = 347.91 kPa
The pressure in the tire at 5.0 °C is 347.91 kPa
Be sure to answer all parts. One reason spectroscopists study excited states is to gain information about the energies of orbitals that are unoccupied in an atom's ground state. The following electron configuration represents an atom in an excited state. Identify the element and write its condensed ground-state configuration: 1s2 2s2 2p6 3s1 3p1
Answer:
The element is magnesium
[Ne]3s2
Explanation:
When an atom is excited, electrons move from a lower to a higher energy level. These higher energy levels are called excited states. The ground state is the lowest energy arrangement of electrons.
Excited states are important in spectroscopy. It gives scientists an idea of the unoccupied orbitals in the ground state. This is easily deduced from the fact that the specie has twelve electrons in all.
Magnesium has ground state configuration as shown in the answer but has an excited state as shown in the question.
A catalyst increases the reaction rate of a reaction by (3 points)
Answer:
A catalyst increases the rate of reaction by decreasing activation energy. ... Enzymes are highly substrate specific and catalyze reactions by providing an alternate pathway of lower activation energy.
Explanation:
I hope this helps :)
The law of conservation of mass states that
A chemist prepares a solution of sodium bromide by measuring out of into a volumetric flask and filling to the mark with distilled water.Calculate the molarity of anions in the chemist's solution.Be sure your answer is rounded to significant digits.
Answer:
The molarity of the Br anion is 0.00136 M = 0.0014 M to 2 s.f
Explanation:
Complete full question
A chemist prepares a solution of sodium bromide (NaBr) by measuring out 14. mg of NaBr into a 100 mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Br anions in the chemist's solution. Be sure your answer is rounded to 2 significant digits.
To do this, we first calculate the molarity of the aqueous solution of NaBr.
Molarity = (Concentration in g/L) ÷ (Molar Mass)
(Concentration in g/L)
= (Mass of solute in g) ÷ (Volume of solution in L)
Mass of solute = 14 mg = 0.014 g
Volume = 100 mL = 0.10 L
(Concentration in g/L)
= (Mass of solute in g) ÷ (Volume of solution in L)
(Concentration in g/L) = (0.014/0.1) = 0.14 g/L
Molarity = (Concentration in g/L) ÷ (Molar Mass)
Molar Mass = 102.894 g/mol
Molarity = (0.14/102.894) = 0.0013606236 M = 0.00136 M
Assuming complete dissociation, NaBr dissociates into
NaBr → Na⁺ + Br⁻
1 mole of NaBr gives 1 mole of Br⁻
0.00136 M of NaBr will give 0.00136 M of Br⁻
So, the molarity of the Br anion is 0.00136 M = 0.0014 M to 2 s.f
Hope this Helps!!!
A papermaking factory releases waste into a local lake. Soon, many fish in the lake begin to die. How might this hurt the economy of the area?
a Local fishermen will lose their jobs.
B. The papermaking factory will make less paper.
C. This won’t harm the economy in any way.
Answer:
Local fishermen will lose their jobs
How does the molecular motion of a sustance change when it goes from liquid to solid?
A) The molecules lose energy, and their relative motion decreases
B) The molecules gain energy,and their relative motion decreases
C)The molecules gain energy, and their relative motion increases
D) The molecules lose energy, and their relative motion increases
Answer:
B) The molecules gain energy, and their relative motion decreases
The change in the molecular motion should be option B.
Change in molecular motion:The molecular motion refers to the movement of constituent particles or molecules in a specific direction. It should be impacted by heat and temperature. When there is the transformation from liquid to solid so the change in the molecular motion of the substance should be that the molecular gained the energy and there should be a decrease in the relative motion.
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Group the following electronic configurations of neutral elements in sets according to those you would expect to show similar chemical properties.
a. 1s^22s^22p^63s^23p^3
b. 1s^22s^22p^63s^23p^63d^104s^24p^5
c. 1s^22s^22p^63s^23p^6
d. 1s^22s^22p^3
Answer:
Option A and D
Explanation:
The element with electronic configuration 1s^22s^22p^63s^23p^3 and the element with electronic configuration 1s^22s^22p^3 will show similar chemical properties as they both have the same valence electrons of 5 each. The valence electron of the two elements shows that they both belong to the same group. Elements in the same group naturally have the same chemical properties because they have the same combining power i.e valence electron.
The pair of elements that tend to show the same chemical properties are a and d.
The elements belonging to the same group tend to show the same chemical properties. Based on the electronic configuration, the element having the same number of valence electrons belongs to the same group.
The valence electrons in the given configurations are:
a. [tex]\rm 1s^2\;2s^2\;2p^6\;3s^2\;3p^3[/tex] = 5
b. [tex]\rm 1s^2\;2s^2\;2p^6\;3s^2\;3p^6\;3d^1^0\;4s^2\;4p^5[/tex] = 7
c. [tex]\rm 1s^2\;2s^2\;2p^6\;3s^2\;3p^6[/tex] = 8
d. [tex]\rm 1s^2\;2s^2\;2p^3[/tex] = 5
The element a and d tend to show the same number of valence electrons. Thus both the elements will show the same chemical properties.
The pair of elements that tend to show the same chemical properties are a and d.
For more information about electronic configuration, refer to the link:
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Statements: (1) In the tripeptide Gly-Ala-Ser, the amino acid at the N-terminal end is Ser. (2) More than one polypeptide chain may be present in a conjugated protein but not in a simple protein. (3) In solution at physiological pH, the side chain of a polar basic amino acid bears a negative charge. a. All three statements are true. b. Two of the three statements are true. c. Only one of the statements is true. d. None of the statements are true.
In the tripeptide Gly-Ala-Ser, the amino acid at the N-terminal end is Ser. More than one polypeptide chain may be present in a conjugated protein but not in a simple protein. In solution at physiological pH, the side chain of a polar basic amino acid does not bear a negative charge.
Explanation:A tripeptide is a chain consisting of three amino acid units. In the tripeptide Gly-Ala-Ser, the amino acid at the N-terminal end is Ser. This is because the N-terminal end is the end of a peptide or protein whose amino group is free, while the C-terminal end has a free carboxyl group. Therefore, statement (1) is true.
Conjugated proteins can consist of more than one polypeptide chain, while simple proteins consist of only one polypeptide chain. Therefore, statement (2) is true.
In solution at physiological pH, the side chain of a polar basic amino acid does not bear a negative charge. Instead, it is positively charged. Therefore, statement (3) is false.
You are examining decomposition of corn leaves following the growing season on a farm. To do this, you place 33 g of corn leaves in a mesh bag and measure decomposition over time. In a literature search, you find that the decay constant of corn leaves is typically 0.04. Given this, use the equation mt =moe−kt to predict the leaf mass remaining in the bag after 30 days.
a. 0.009 g
b. 23.3 g
c. 9.94 g
d. 1.7 g
e. 14.8 g
Answer:
c. 9.94 g
Explanation:
From the question,
Using
mt = m₀e⁻kt.................... Equation 1
Where mt = mass of the leaf remaining in the bag, m₀ = original mass of leave that was placed in the bag, k = decay constant, t = time.
Given: m₀ = 33 g, k = 0.04, t = 30 days.
Substitute into equation 1
mt = 33(e⁻(0.04ˣ30))
mt = 33e⁻¹²/¹⁰
mt = 33/e¹²/¹⁰
mt = 33/3.320
mt = 9.94 g.
Hence the right answer is c. 9.94 g
The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium process described by the equation: C6H5CH2OH(g) ⇆ C6H5CHO(g) + H2(g) At 523 K, the value of its equilibrium constant is K = 0.558. (a) Suppose that 1.20 g of benzyl alcohol is placed into a 2.00 L vessel and heated to 523 K. What is the partial pressure of benzaldehyde when equilibrium is attained? (b) What fraction of benzyl alcohol is dissociated into products at equilibrium?
Answer:
pC6H5CHO = 0.180 atm
Fraction dissociated = 0.756
Explanation:
Step 1: Data given
Temperature = 523 K
the value of its equilibrium constant is K = 0.558
Mass of benzyl alcohol = 1.20 grams
Molar mass of benzyl alcohol = 108.14 g/mol
Volume = 2.00 L
heated to 523 K
Step 2: The balanced equation
C6H5CH2OH(g) ⇆ C6H5CHO(g) + H2(g)
Step 3: Calculate moles benzyl alcohol
Moles benzyl alcohol = Mass / molar mass
Moles benzyl alcohol = 1.20 grams / 108.14 g/mol
Moles benzyl alcC6H5CH2OHohol = 0.0111 moles
Step 4: Initial moles
Moles C6H5CH2OH = 0.0111 moles
Moles C6H5CHO = 0 moles
Moles H2O = 0 moles
Step 5: moles at the equilibrium
Moles C6H5CH2OH = 0.0111 - X moles
Moles C6H5CHO = X moles
Moles H2O = X moles
Step 6: Calculate the total number of moles at equilibrium
Total number of moles = (0.0111 - X moles) + X moles + X moles
Total number of moles = 0.0111 + X moles
Step 7: Calculate the total pressure at the equilibrium
p*V = n*R*T
p = (n*R*T) / V
⇒with p = the total pressure at the equilibrium = TO BE DETERMINED
⇒with n = the total number of moles = 0.0111 + X moles
⇒with R = the gas constant = 0.08206 L*atm / mol * K
⇒with T = the temperature = 523 K
⇒with V = the volume of the vessel = 2.00 L
p = (0.0111 - X moles ) * 0.08206*523 / 2.00
p = 21.46(0.0111 - X moles)
Step 8: Define the equilibrium constant K
K = 0.558 = (pC6H5CHO)*(pH2) / (pC6H5CH2OH)
0.558 = (X / (0.0111 + X)*P)² / ((0.0111-X)/(0.0111+X)*P)
0.558 = (X²(21.46 * (0.0111+X))) / ((0.0111 + X) (0.0111-X))
X = 0.00839
Step 9: Calculate the equilibrium partial pressure
pC6H5CHO = X / (0.0111 + X) * (21.46 * (0.0111 +X))
pC6H5CHO = 0.180 atm
Step 10: What fraction of benzyl alcohol is dissociated into products at equilibrium?
Fraction dissociated = Δn / n°
Fraction dissociated = X / 0.0111
Fraction dissociated = 0.00839 / 0.0111
Fraction dissociated = 0.756
The decarboxylation of lysine catalyzed by lysine decarboxylase has a kcat value of 500 s-1 at 298K, and loss of CO2 is the rate-determining step. What is the free energy of activation for the CO2 loss step? The half-life for the uncatalyzed reaction under the same conditions is 4 billion years (1017 seconds). How much does the enzyme lower the free energy of activation for this reaction? Show your work.
Answer:
The decrease in free energy is 113.299kJ
Explanation:
K for enzyme catalyzed reaction = 500s^-1
Temperature (T) =298k
ΔG =?
ΔG = - 2.303 RT log k
ΔG = (-2.303)(8.314)(298) log 500
ΔG = - 15399.9 J
ΔG catalyzed = - 15. 399kJ
The first order reaction is given as:
t1/2= 0.693/k
or k= 0.693/t1/2
0.693/10^17
Therefore,
K= 0.693 × 10^-17
Now,
K= 0.693 × 10^-17
T= 298k
ΔG uncatalyzed =?
ΔG uncatalyzed = - 2.303 RT log k
ΔG uncatalyzed = (-2.303)(8.314)(298) log0.693 × 10^-17
= 97908.1J
ΔG uncatalyzed = 97.9081kJ
Therefore,
The decrease in free energy is:
ΔG uncatalyzed - ΔG catalyzed
97.908 - (-15.399)
= 113.299KJ
The decrease in free energy is 113.299kJ
Final answer:
The free energy of activation for the CO2 loss step can be calculated using the Arrhenius equation. The enzyme lowers the free energy of activation by comparing the activation energies of the catalyzed and uncatalyzed reactions.
Explanation:
The free energy of activation for the CO2 loss step can be calculated using the Arrhenius equation:
k = Ae^(-Ea/RT)
Where k is the rate constant, A is the frequency factor, Ea is the activation energy, R is the gas constant (8.314 J/mol·K), and T is the temperature in Kelvin.
Since the rate-determining step is the loss of CO2, we can use the kcat value (500 s-1) as the rate constant for this step. To find the activation energy, we need to rearrange the Arrhenius equation:
Ea = -RT ln(k/A)
Now we can substitute the given values into the equation:
Ea = -(8.314 J/mol·K)(298 K) ln(500 s-1/A)
To calculate the value of A, we can use the half-life for the uncatalyzed reaction:
t1/2 = ln(2)/(kuncat)
Replacing kuncat with the appropriate value, we can solve for A:
A = e^(ln(2)/(kuncat) - ln(2)/(kcat))/t1/2 = e^(ln(kcat/kuncat))/t1/2
Finally, we can substitute the values of kcat, kuncat, and t1/2 into the equation to find A.
To calculate how much the enzyme lowers the free energy of activation, we can compare the activation energies of the uncatalyzed and catalyzed reactions:
∆∆G (ΔEa) = ∆Ga - ∆Ga,uncat
Where ∆Ga is the activation energy of the catalyzed reaction and ∆Ga,uncat is the activation energy of the uncatalyzed reaction.
Describe at least two factors that can affect the rate of a chemical reaction.
Answer: Concentration or pressure of a reactant and temperature
Explanation: The two major factors that can affect the rate of a chemical change are concentration or pressure of a reactant and temperature.
17-61 Nucleophilic aromatic substitution provides one of the common methods for making phenols. (Another method is discussed in Section19-17 .) Show how you would synthesize the following phenols, using benzene or toluene as your aromatic starting material, and explain why mixtures of products would be obtained in some cases. p-nitrophenol 2,4,6-tribromophenol
Answer:
Explanation:
find the solution below
What is the amount of heat required to raise the temperature of 200.0 g of aluminum by 10°C? (specific heatof aluminum = 0.21 cal/g°C)
4,200 cal
420 cal
42, 00 cal
420,000 cal
Answer:
We need 420 cal of heat
Explanation:
Step 1: Data given
Mass of the aluminium = 200.0 grams
Temperature rises with 10.0 °C
Specific heat of aluminium = 0.21 cal/g°C
Step 2: Calculate the amount of heat required
Q =m * c* ΔT
⇒with Q = the amount of heat required= TO BE DETERMINED
⇒with m = the mass of aluminium = 200.0 grams
⇒with c = the specific heat of aluminium = 0.21 cal/g°C
⇒with ΔT = the change of temperature = 10.0°C
Q = 200.0 grams * 0.21 cal/g°C * 10.0 °C
Q = 420 cal
We need 420 cal of heat (option 2 is correct)
Answer:
420 cal of heat
Explanation:
Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that is a weak acid. mol of is added to of a solution.
Answer: seen below
Explanation:
HCH3CO2 + NaOH --------------> CH3CO2- + H2O
Acid specie- HCH3CO2
base- NaOH
Neutral- Na+
CH3COOH + KOH ----------> CH3COOK + H20
Acid- CH3COOH
Base- KOH
Neutral- K+
1. Determine if the following statements are true or false (each question is worth one point). The rate law for an overall reaction can be written using the coefficients from the overall reaction The rate determining step of the reaction is alwaysthe first step of the reaction A catalyst is a species that is added to the reaction, lowers the activation energy of a reaction, shows up in the rate law (most of the time), and will be in the overall balanced equation Tries 0/45
Answer:
1. F
2. F
3. F
Explanation:
Determine if the following statements are true or false.
The rate law for an overall reaction can be written using the coefficients from the overall reaction. FALSE. The rate law includes the reaction orders, which have to be determined experimentally and may or may not be equal to the coefficients of the overall reaction.The rate-determining step of the reaction is always the first step of the reaction. FALSE. The rate-determining step is always the slowest step.A catalyst is a species that is added to the reaction, lowers the activation energy of a reaction, shows up in the rate law (most of the time), and will be in the overall balanced equation. FALSE. A catalyst does lower the activation energy of the reaction, but it doesn't show up in the rate law nor the overall balanced equation.Final answer:
The statements regarding the rate law being written using coefficients from the overall equation and the rate-determining step always being the first step of the reaction are both false. A catalyst does lower activation energy but is not included in the rate law nor in the overall balanced equation.
Explanation:
Determining the rate law of a chemical reaction and the rate-determining step is a critical part of understanding reaction kinetics in chemistry. The first statement, 'The rate law for an overall reaction can be written using the coefficients from the overall reaction,' is false. The rate law cannot be directly inferred from the stoichiometric coefficients in the balanced chemical equation; it is determined empirically and often depends on the mechanism and the slowest, rate-determining step of the reaction.
The second statement, 'The rate-determining step of the reaction is always the first step of the reaction,' is also false. While the rate-determining step can be the first step, this is not always the case. It is the slowest step with the highest activation energy, and not necessarily the first step in the reaction mechanism.
The third statement about a catalyst being a species that lowers the activation energy and shows up in the rate law (most of the time) is partly correct. A catalyst does lower the activation energy and speeds up the reaction but does not appear in the rate law and is not present in the overall balanced equation because it is not consumed in the reaction; thus, this statement is false in the context given.
Draw the structure of the major organic product of the following reaction.
NaOCH2CH3
------------------------------→
95% aq. ethanol, 20°
Predict whether the product will be an aldol or an enone.
You do not have to consider stereochemistry.
You do not have to explicitly draw H atoms.
Do not include lone pairs in your answer.
They will not be considered in the grading.
If no reaction occurs, draw the organic starting material.
Answer:
Aldol
Explanation:
The reaction will be an aldol.
What is stoichiometry used for?
A. To determine the shape of a molecule
B. To determine the amount of a substance
C. To determine the molar mass of a molecule
D. To determine the atoms in a formula
Answer:
b
Explanation:
For the reaction: 2 H2 + 2 NO → N2 + 2 H2O the observed rate expression, under some conditions, is: rate = k[H2][NO]2 Which of the following mechanisms are consistent with these data? Select all that are True. step 1 H2 + 2 NO → N2O + H2O (slow) step 2 N2O + H2 → N2 + H2O (fast) step 1 2 H2 + 2 NO → N2 + H2O step 1 NO + NO ⇌ N2O2 (fast) step 2 N2O2 + H2 → N2 + H2O + O (slow) step 3 O + H2 → H2O (fast) step 1 H2 + NO ⇌ H2ON (fast) step 2 H2ON + NO → N2 + H2O2 (slow) step 3 H2O2→ H2O + O (fast) step 4 O + H2 → H2O (fast)
Answer:
Step 1 H2 + 2 NO → N2O + H2O (slow)
step 2 N2O + H2 → N2 + H2O (fast)
Explanation:
It is known that the slowest step in a reaction is the rate determining step in a sequence of reactions (reaction mechanism).
We have two important pieces of information in the question to guide our decision making process.
The overall reaction equation, and the rate expression. The two;
2 H2 + 2 NO → N2 + 2 H2O and rate = k[H2][NO]2 all support the answer given above.
The best matching mechanism to the given rate law is 'H2 + 2 NO → N2O + H2O (slow)' followed by 'N2O + H2 → N2 + H2O (fast)'. This mechanism results in first-order dependence on H2 and second-order dependence on NO, matching the observed rate law.
Explanation:To find a mechanism that matches the given rate law (rate = k[H2][NO]²), we need to find one where NO is involved in the slow (rate-determining) step twice (which will make the overall reaction second-order with respect to NO), and H2 is involved once (making it first-order with respect to H2). From the proposed mechanisms, we can agree that the first one:
H2 + 2 NO → N2O + H2O (slow) N2O + H2 → N2 + H2O (fast)
is most likely because the slow step involves one H2 and two NO molecules.
Learn more about Reaction Mechanism here:https://brainly.com/question/34268569
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