What type of reaction is:

What Type Of Reaction Is:

Answers

Answer 1

Answer:

The answer to your question is Combustion

Explanation:

Chemical reaction

                 2C₄H₁₀  +  13 O₂  ⇒   8 CO₂  +  10 H₂O

A combustion reaction is a chemical reaction in which the reactants are always a molecule with carbon (organic molecule) and oxygen (O₂), and the products are always carbon dioxide (CO₂) and water (H₂O).

Conclusion

The chemical reaction of this problem is combustion


Related Questions

A mixture of H2 and water vapor is present in a closed vessel at 20°C. The total pressure of the system is 755.0 mmHg.

Partial pressure of water vapor at 20°C equals 17.5 mmHg.

What is the partial pressure of H2?

Answers

Final answer:

The partial pressure of H2 in a closed vessel at 20°C, when the total pressure is 755.0 mmHg and the partial pressure of water vapor is 17.5 mmHg, is 737.5 mmHg.

Explanation:

The total pressure of the system is a combination of the pressures from the individual gases within it - in this case, hydrogen (H2) and water vapor. According to Dalton's Law of partial pressures, the total pressure is equal to the sum of the partial pressures.

Given that the total pressure is 755.0 mmHg and the partial pressure of the water vapor is 17.5 mmHg at 20°C, we can calculate the partial pressure of H2 by subtracting the pressure of the water vapor from the total pressure. Therefore, the partial pressure of H2 is 755.0 mmHg - 17.5 mmHg = 737.5 mmHg.

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The successive ionization energies of a certain element are I1= 577.9 kJ/mol, I2 = 1820 kJ/mol, I3= 2750 kJ/mol, I4 = 11,600 kJ/mol, and I5 = 14,800 kJ/mol. This pattern of ionization energies suggests that the unknown element is _________.

Answers

Given question is incomplete. The complete question is as follows.

The successive ionization energies of a certain third-period element are I1 = 577.9KJ/mol, I2 + 1820 KJ/mol, I3 = 2750 KJ/mol, I4 = 11600 KJ/mol, I5 = 14800 KJ/mol. what element do these ionization energies suggest? Explain your reasoning.

Explanation:

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

Here, given ionization energies belong to an element present in third period.

We know that second ionization energy will always be greater than third ionization energy.

For the given ionization energies, there is a huge  difference between third and fourth ionization energy. This means that there are three valence electrons present in the element.

This is because after losing three electrons it is difficult for the given element to lose fourth electron. Hence, [tex]IE_{4}[/tex] is high as compared to [tex]IE_{3}[/tex].

Hence, this element has 3 valence electrons and it belongs to 3A group of the periodic table.

Thus, we can conclude that the given unknown element is aluminium (Al).

Final answer:

The unknown element, suggested by the provided pattern of ionization energies, most likely has 3 valence electrons, which fits the characteristics of aluminum (Al). The significant increase in the fourth ionization energy suggests the removal of an electron from a stable noble gas core.

Explanation:

The pattern in ionization energies indicates that the unknown element contains 3 valence electrons. The ionization energy increases with each successive removal of an electron, however, the energy required for the fourth ionization is significantly larger than the previous one. This dramatic increase indicates that electrons are being removed from a stable noble gas configuration. Therefore, the element must have 3 valence electrons in its outermost shell and the nearest noble gas core underneath. This property is characteristic of elements in group 13 of the periodic table, and considering the given ionization values, the unknown element is most likely aluminum (Al).

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En un depósito hay 800 litros de agua. Por la parte superior un tubo vierte en el depósito 25 litros por minuto, y por la parte inferior por otro tubo salen 30 litros por minuto. ¿Cuántos litros de agua habrá en el depósito después de 15 minutos de funcionamiento?

Answers

Answer:

Ninguno estará en el agua después de 15 minutos.

Explanation:

Tomar 25 + 30 = 55 por minuto de agua que sale. Como ahora sabemos eso, tómese 55 minutos por 15 minutos. Debe obtener 825, por lo tanto, no quedará agua.

- Avíseme si esto es incorrecto o si desea una explicación más detallada. Espero que esto haya ayudado!

According to unitary method, there will be 825 liters of water and hence there will be no water left .

What is unitary method?

Unitary method is a process by which we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit. It is a method that we use for most of the calculations in math.

Water coming out= 25+30=55 liters of water comes out in 1 minute, thus in 15 minutes 15×55=825 liters will come out and hence there will be no water left.

Thus, according to unitary method, there will be 825 liters of water and hence there will be no water left .

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There are 800 liters of water in a tank. A tube pours 25 liters per minute into the tank at the top, and 30 liters per minute comes out at the bottom through another tube. How many liters of water will be in the tank after 15 minutes of operation?

If a very complex closed system has 200 J of energy in it, then the energy converts from 1 form to another to another to another. How much energy should the system still have at the end?

Answers

At the end the energy of the system is the same as 200 J.

Explanation:

It is a closed complex system and it has 200 J of energy.

Here the system is converting from one form to another form and then to another form.

As we know that there is a conservation of energy when one form is converted to another form without losing or gaining energy, whereas it may convert from one form to another form with the energy being conserved.

So after there is a conversion of one form to another form but there is no loss or gain of energy and same energy must be retained.

A scientist makes a solution that contains 80 g of sugar per 200 ml of solution. What is the concentration that describes the solution

Answers

Answer:

40,000g/L

Explanation:

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By definition, the concentration that describes the solution is 400 [tex]\frac{grams}{L}[/tex].

Solute and solvent are two components of a solution. The solute is the substance (solid, liquid, or gas) that dissolves in the solvent to produce a homogeneous mixture known as a solution.

In the solution, the solute is usually found in a lower proportion than the solvent, while generally, the solvent is the component that is found in the greater proportion in the solution.

The concentration of a solution is the amount of solute (dissolved substance) in an amount of solvent or solution.

There are different ways to express the concentration of a solution.

In this case, the mass of solute per volume of solution is a measure of concentration that is determined by dividing the mass in grams of the solute present in the solution sample by the volume of the sample.

In this case, the solution contains 80 g of sugar per 200 ml (0.2 L, being 1000 mL= 1 L) of solution. Then, the mass of solute per volume of solution can be calculated as:

[tex]mass of solute per volume=\frac{80 grams}{0.2 L}[/tex]

Solving:

[tex]mass of solute per volume=400\frac{ grams}{ L}[/tex]

Finally, the concentration that describes the solution is 400 [tex]\frac{grams}{L}[/tex].

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The isomerization of cyclopropane to propylene is a first-order process with a half-life of 19 minutes at OC. The total time it takes for the partial pressure of cyclopropane to decrease from 1.0 atmosphere to 0.125 atmosphere at 500 °C is closest to:_______
(A) 38 minutes
(B) 28.5 38
(C) 76 minutes
(D) 152 minutes

Answers

Answer : The total time it takes is, 57 min

Explanation :

Half-life = 19 min

First we have to calculate the rate constant, we use the formula :

[tex]k=\frac{0.693}{19\text{ min}}[/tex]

[tex]k=0.0365\text{ min}^{-1}[/tex]

Now we have to calculate the time taken for decay.

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant

t = time taken top decay  = ?

a = initial pressure of the reactant  = 1.0 atm

a - x = pressure left after decay process  = 0.125 atm

Now put all the given values in above equation, we get

[tex]t=\frac{2.303}{0.0365}\log\frac{1.0}{0.125}[/tex]

[tex]t=57min[/tex]

Therefore, the total time it takes is, 57 min

Final answer:

For a first-order reaction with a constant half-life, three half-lives occur when the concentration goes from 1.0 atmosphere to 0.125 atmosphere. Each half-life is 19 minutes, totaling 57 minutes, leading to the closest total time being C) 76 minutes.

Explanation:

The question involves a first-order reaction where the half-life remains constant. To find the time it takes for the partial pressure of cyclopropane to decrease from 1.0 atmosphere to 0.125 atmosphere, we need to calculate the number of half-lives that occur in this change.

The concentration decreases by half for each half-life period. Since 1.0 atmosphere going down to 0.125 atmosphere is equivalent to halving the concentration three times (1.0 to 0.5 to 0.25 to 0.125), it takes three half-lives.

Given that the half-life is 19 minutes, the total time would be:
3 half-lives × 19 minutes/half-life = 57 minutes.

Thus, the closest answer to the total time taken for this process is:

(C) 76 minutes

why does a balloon expand when you add air to it

Answers

Answer:

Air molecules collide into the balloon with the same energy inside and outside the balloon. These molecules now collide into the balloon with more energy resulting in increased pressure. The increased pressure causes the balloon to expand.

Explanation:

Answered by -cutecrazy448 - Mariah Malave

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Mg (s) + 2HCl (aq) → H2 (g) + MgCl2 (aq)
A:
Moles Mg: 0.050
Moles HCl: 0.050

Mass of Hydrogen gas and the limiting reactant

Answers

Mass of hydrogen gas formed from the given reaction is 0.05 grams and the limiting reactant is HCl.

Explanation:

Data given:

moles of Mg = 0.050 moles

moles of HCl = 0.050 moles

mass of hydrogen gas formed =?

atomic mass of hydrogen gas = 2 grams/mole

limiting reactant = ?

Balanced chemical equation is given by:

Mg (s) + 2HCl (aq) → H2 (g) + Mg[tex]Cl_{2}[/tex] (aq)

from the reaction let us deduce the limiting reagent as

1 mole of Mg gave 1 mole of hydrogen gas

0.050 moles will give 0.050 moles of hydrogen gas

mass of hydrogen gas  = atomic mass x number of moles

mass of hydrogen gas = 2 x 0.050

                                       = 0.1 grams of hydrogen gas produced.

Now from 2 moles of HCl 1 mole of hydrogen gas is formed

so, 0.050 moles of HCl will give x moles of hydrogen gas

[tex]\frac{1}{2}[/tex] = [tex]\frac{x}{0.050}[/tex]

2x = 0.050

x = 0.025 moles

mass of hydrogen gas  = atomic mass x number of moles

mass of hydrogen gas  = 0.025 x 2

                                      = 0.05 grams

mass = atomic mass x number of moles

The limiting reactant is HCl as it produced less amount of product after getting fully consumed in the reaction.

the product formed depends on the limiting reagent and the value is 0.05 grams.

Final answer:

To determine the mass of hydrogen gas and the limiting reactant in the given reaction, we need to calculate the moles of each reactant and use stoichiometry.

Explanation:

The reaction given is:

Mg (s) + 2HCl (aq) → H2 (g) + MgCl2 (aq)

To determine the mass of hydrogen gas produced and the limiting reactant, we need to calculate the moles of each reactant and use stoichiometry.

Moles of Mg = 0.050 mol

Moles of HCl = 0.050 mol

Since the reaction ratio is 1:1 between Mg and H2, the moles of H2 produced is also 0.050 mol. To calculate the mass of hydrogen gas, we can use the molar mass of H2 which is 2 g/mol. Therefore, the mass of hydrogen gas produced is:

Mass of H2 = Moles of H2 × Molar mass of H2 = 0.050 mol × 2 g/mol = 0.100 g

The limiting reactant is the reactant that is fully consumed and determines the maximum amount of product that can be formed. In this case, since both Mg and HCl have the same number of moles and both are fully consumed, neither is the limiting reactant.

What does pH measure? number of hydrogen atoms in an acid number of hydroxide atoms in a base concentration of hydrogen ions in solution concentration of hydroxide ions in solution

Answers

Answer:

Concentration of hydrogen ions in solution

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Final answer:

pH measures the concentration of hydrogen ions in a solution and indicates its acidity or basicity. The pH scale ranges from 0 to 14, with lower values being acidic and higher values alkaline. The pH value represents the negative logarithm of the hydrogen ion concentration.

Explanation:

pH measures the concentration of hydrogen ions (H+) in a solution. In pure water, a small percentage of water molecules dissociate into equal numbers of hydrogen ions (H+) and hydroxide ions (OH−), which is a source of hydrogen ions in solutions. The pH scale, which ranges from 0 to 14, determines a solution's acidity or basicity; a pH less than 7 indicates acidity, greater than 7 indicates alkalinity, and a pH of 7 is neutral. The pH value is a negative logarithm of the hydrogen ion concentration, meaning that each whole number on the pH scale represents a tenfold increase or decrease in hydrogen ion concentration.

The pH of a solution provides a quick way to determine its acidity or basicity. High concentrations of hydrogen ions yield a low pH, whereas low concentrations result in a high pH. The relative acidity or alkalinity of a solution can significantly impact various chemical and biological processes, making pH an essential parameter in science and various industries.

in a second experiment, the total pressure is observed to be 58 atm. what is the partial pressure of the water vapor produced?

Answers

This is an incomplete question, here is a complete question.

Nitroglycerine (C₃H₅N₃O₉) explodes with tremendous force due to the numerous gaseous products. The equation for the explosion of Nitroglycerine is:

[tex]4C_3H_5N_3O_9(l)\rightarrow 12CO_2(g)+O_2(g)+6N_2(g)+10H_2O(g)[/tex]

A scientist conducts an experiment to characterize a bomb containing nitroglycerine. She uses a steel, ridge container for the test.

Volume of rigid steel container: 1.00 L

Molar mass of Nitroglycerine: 227 g/mol

Temperature: 300 K

Amount of Nitroglycerine tested: 227 g

Value for ideal gas constant, R: 0.0821 L.atm/mol.K

In a second experiment, the total pressure is observed to be 58 atm. what is the partial pressure of the water vapor produced?

Answer : The partial pressure of the water vapor is, 20.01 atm

Explanation :

First we have to calculate the moles of [tex]C_3H_5N_3O_9[/tex]

[tex]\text{Moles of }C_3H_5N_3O_9=\frac{\text{Given mass }C_3H_5N_3O_9}{\text{Molar mass }C_3H_5N_3O_9}=\frac{227g}{227g/mol}=1mol[/tex]

Now we have to calculate the moles of [tex]CO_2,O_2,N_2\text{ and }H_2O[/tex]

The balanced chemical reaction is:

[tex]4C_3H_5N_3O_9(l)\rightarrow 12CO_2(g)+O_2(g)+6N_2(g)+10H_2O(g)[/tex]

From the balanced chemical reaction we conclude that,

As, 4 moles of [tex]C_3H_5N_3O_9[/tex] react to give 12 moles of [tex]CO_2[/tex]

So, 1 moles of [tex]C_3H_5N_3O_9[/tex] react to give [tex]\frac{12}{4}=3[/tex] moles of [tex]CO_2[/tex]

and,

As, 4 moles of [tex]C_3H_5N_3O_9[/tex] react to give 1 moles of [tex]O_2[/tex]

So, 1 moles of [tex]C_3H_5N_3O_9[/tex] react to give [tex]\frac{1}{4}=0.25[/tex] moles of [tex]O_2[/tex]

and,

As, 4 moles of [tex]C_3H_5N_3O_9[/tex] react to give 6 moles of [tex]N_2[/tex]

So, 1 moles of [tex]C_3H_5N_3O_9[/tex] react to give [tex]\frac{6}{4}=1.5[/tex] moles of [tex]N_2[/tex]

and,

As, 4 moles of [tex]C_3H_5N_3O_9[/tex] react to give 10 moles of [tex]H_2O[/tex]

So, 1 moles of [tex]C_3H_5N_3O_9[/tex] react to give [tex]\frac{10}{4}=2.5[/tex] moles of [tex]H_2O[/tex]

Now we have to calculate the mole fraction of water.

[tex]\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }CO_2+\text{Moles of }O_2+\text{Moles of }N_2}[/tex]

[tex]\text{Mole fraction of }H_2O=\frac{2.5}{2.5+3+0.25+1.5}=0.345[/tex]

Now we have to calculate the partial pressure of the water vapor.

According to the Raoult's law,

[tex]p_{H_2O}=X_{H_2O}\times p_T[/tex]

where,

[tex]p_{H_2O}[/tex] = partial pressure of water vapor gas  = ?

[tex]p_T[/tex] = total pressure of gas  = 58 atm

[tex]X_{H_2O}[/tex] = mole fraction of water vapor gas  = 0.345

Now put all the given values in the above formula, we get:

[tex]p_{H_2O}=X_{H_2O}\times p_T[/tex]

[tex]p_{H_2O}=0.345\times 58atm=20.01atm[/tex]

Therefore, the partial pressure of the water vapor is, 20.01 atm

The partial pressure exerted by a gas in a mixture, depends on the mole

fraction of the gas and the pressure exerted by the mixture.

The partial pressure  of H₂O is 20 atm.

Reasons:

Given parameters are;

Explosion equation is 4C₃H₅N₃O₉ → 12CO₂(g) + O₂(g) + 6N₂(g) + 10H₂O(g)

Amount of nitroglycerine = 227 g

Molar mass of nitroglycerine = 227 g/mol

Required:

Partial pressure of the water vapor

Solution:

Number of moles of nitroglycerine in the reaction = 1 mole

Therefore;

Number of moles of CO₂ = 12/4 = 3 moles

Number of moles of O₂ = 0.25 moles

Number of nitrogen, N = 1.5 moles

Number of moles of H₂O = 2.5 moles

[tex]Mole \ fraction \ of \ H_2O, \ X_{H_2O} = \dfrac{2.5}{2.5 + 1.5 + 0.25 + 3} = \dfrac{10}{29}[/tex]

According to Raoults law, we have;

The partial pressure of H₂O = [tex]X_{H_2O} \times P_[/tex]

Therefore,  partial pressure  of H₂O = [tex]\dfrac{10}{29} \times 58[/tex] = 20 atm.

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Propane (C3 H8 (g), Delta.Hf = –103.8 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Delta.Hf = –393.5 kJ/mol ) and water (H2 O, Delta.Hf = –241.82 kJ/mol) according to the equation below. Upper C subscript 3 upper H subscript 8 (g) plus 5 upper O subscript 2 (g) right arrow 3 upper C upper O subscript 2 (g) plus 4 upper H subscript 2 upper O (g). What is the enthalpy of combustion (per mole) of C3 H8 (g)? Use Delta H r x n equals the sum of delta H f of all the products minus the sum of delta H f of all the reactants.. –2,044.0 kJ/mol –531.5 kJ/mol 531.5 kJ/mol 2,044.0 kJ/mol

Answers

Answer: -2044.0 kJ/mol

Explanation:

Answer on Edg 2020

Answer:

-2044.0 kJ/mol

Explanation:

Predict which of the following will be formed at the anode in the electrolysis of an aqueous solution of KI. Predict which of the following will be formed at the anode in the electrolysis of an aqueous solution of:
KI.
O2
H2
K
I2

Answers

During the electrolysis of an aqueous solution of KI, I₂ will be formed at the anode.

What is Electrolysis ?

It is process by which electric current is passed through a substance to effect a chemical change.

The chemical change is one in which the substance loses or gains an electron (oxidation or reduction).

In order for KI to undergo electrolysis it has to be in its molten state or aqueous state because this will enhance the migration of ions.

The following reactions and observations occur during the electrolysis of aqueous solution of KI.

At the anode,

Two reactions are like to occur that the one in which the I⁻ is oxidized to give I₂ and the one in which oxygen is formed from water but in both above only the case in which I₂ is produced is the one that is been observed because of the presence of the violet colour.

The equation of Reaction is given below;

2 I⁻ (aq) -------> I₂ (g) + 2 e⁻

Note that the I₂ is in gaseous form.

Hence, During the electrolysis of an aqueous solution of KI, I₂ will be formed at the anode.

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During the electrolysis of an aqueous solution of KI, iodine (I₂) will be produced at the anode due to the oxidation of iodide ions. Option D is correct.

This process involves the oxidation of iodide ions (I−), which can be represented by the half-reaction: 2I⁻(aq) → I₂(s) + 2e⁻. This indicates that iodide ions are oxidized to iodine solid and electrons are released in the process.

It is important to note that while water can also undergo oxidation to produce oxygen gas, the formation of iodine at the anode takes precedence over oxygen evolution because iodide ions are more easily oxidized than water molecules in this scenario.

Hence, D. is the correct option.

The complete question is:

content loaded

Predict which of the following will be formed at the anode in the electrolysis of an aqueous solution of KI. Predict which of the following will be formed at the anode in the electrolysis of an aqueous solution of KI.

A) O₂

B) H₂

C) K

D) I₂

Which units are used to measure both velocity and speed? Select three options.
m/s
d/t
km/h
mph
lph

Answers

The correct answers are:
m/s
Km/h
mph

Answer:

hi! the answer is:

m/s

Km/h

mph

Explanation:

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Classify the carbohydrate tagatose by both the carbonyl group and the number of carbon atoms. There is a Fischer projection for D-tagatose. The carbon chain is depicted vertically, with a CH2OH group bonded to a CO group at the top and a CH2OH group at the bottom, while the three remaining carbon atoms are represented by the center of crossing lines. The tagatose molecule has all hydroxyls but the third one (from top to bottom) on the left and hydrogens opposite to them.

Answers

Final answer:

Tagatose is a ketohexose, a type of carbohydrate with a ketone group in the middle of its six-carbon chain and considered to be a D-sugar due its hydroxyl group orientation on the fifth carbon.

Explanation:

The carbohydrate tagatose can be classified by both the type of carbonyl group present and the number of carbon atoms in the molecule. Since tagatose has a carbonyl group in the middle of the carbon chain, it is classified as a ketose. Furthermore, because tagatose has six carbon atoms, it is called a hexose.

In the Fischer projection of D-tagatose, the presence of the carbonyl group linked to two other carbon atoms indicates that it is a ketonic sugar, hence a ketose. Additionally, since the molecule is a six-carbon sugar, it can further be categorized as a hexose. The D- configuration designation comes from the orientation of the hydroxyl group on the fifth carbon, and in the case of D-tagatose, this group is positioned on the right, confirming its D-configuration.

Why is melting an ice cube a reversible physical change?

Answers

Answer:

Because you can freeze the water you melted back into a ice cube.

Explanation:

Final answer:

Melting an ice cube is a reversible physical change because it involves a change in state (from solid to liquid) that can be reversed (from liquid back to solid). No new substances are formed in this process, hence, it's a physical change, not a chemical one. The substance, water, maintains its identity throughout the process.

Explanation:

Melting an ice cube is a reversible physical change because the process can be reversed by freezing. When an ice cube melts, it changes its state from solid (ice) to liquid (water) due to an increase in temperature. This is a physical change, not a chemical change because no new substances are formed - water (H2O) remains water in both solid and liquid states.

When the temperature drops, the liquid water can freeze back to become ice - this is the reverse of the melting process. Hence, it's considered a reversible physical change since we can revert the material (water) back to its original state (ice) under standard conditions. The key here is that the basic identity of the substance (water, in this case) does not change throughout this process.

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help meee pleaseeeee

Answers

Answer:

see explanation

Explanation:

Using the periodic table, look at the top of each column => These are group numbers ... Typically (for american tables) the numbers are divided into A-Groups and B-Groups... For this post, you need to focus on the A-Groups, or 'Main Group Elements'... Now, the numbers also represent the number of valence (outer shell) electrons in the elements listed below that number. For example, under Group IA, all elements ( H, Li, Na, K, Rb, Cs & F) all have one (1) outer shell electron. All elements under IIA have two outer shell electrons, IIIA, 3 outer shell electrons and so on. The exception is Helium (He) which has only 2 outer shell electrons and is typically listed under Group VIIIA.

So ...

X· => H, Li & Na

X: => He(noble gas exception), Be & Mg

·X: => B & Al

:X: => C & Si

X(5 dots) => N  

X(6 dots) => O

X(7 dots) => F & I

X(8 dots) => Ne

Dominic made the table below to organize his notes about mixtures.
Properties of Mixtures
has no set composition
must have more than one state of matter
must have more than one substance
What mistake did Dominic make?
The title should read "Properties of Solutions" because some mixtures do not have all of the properties listed,
There is a definite recipe to make each mixture, so the composition of a mixture is set.
Although it is possible to have more than one state, it is also possible to have only one state.
A single substance can be used to make a mixture if the substance is composed of more than one element.
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Save and Exit
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Answers

Answer:

Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Read the lines about space, then answer the question. Jupiter is a gaseous planet. It is not made up of rocks and metal, but is mostly hydrogen and helium. According to context clues, which best defines the underlined word? Not solid solid windy not windy

Answers

Answer:

The correct option is;

Not solid

Explanation:

Here we have that Jupiter is a planet of gas and that it is not made up of solid rocks or of metal.

According to the hint provided that defined the physical property of Jupiter, we have that Jupiter is not a solid

However, to say that Jupiter is windy planet is an overstatement because, the paragraph only describe the static physical substance condition of the planet Jupiter.

Answer:

A or Not Solid

Explanation:

Jupiter is entirely made of gas.

This cold river of air travels from west to east in the northern hemisphere. In winter, it dips south helping to bring cooler air to most parts of the United States. This is the _________ jet stream.

Answers

Answer:

Polar Jet stream

Explanation:

Polar Jet stream is also called the polar front jet or mid latitude jet steam, it is a very powerful belt of the upper level winds which sits above the polar front. It is the strongest wind in the tropopause, it's movement is towards the westerly direction of the mid latitude.

Carbon disulfide burns in oxygen to yield carbon dioxide and sulfur dioxide according to the chemical equation cs2(ℓ) + 3 o2(g) −→ co2(g) + 2 so2(g). if 1.25 mol of cs2 is combined with 0.57 mol of o2, identify the limiting reactant.

Answers

Final answer:

To find the limiting reactant between carbon disulfide and oxygen, one evaluates the stoichiometric requirements of the reaction. Given 1.25 mol CS2 and 0.57 mol O2, oxygen is determined to be the limiting reactant as it is insufficient to react with all the CS2.

Explanation:

To determine the limiting reactant in the reaction between carbon disulfide (CS2) and oxygen (O2), where the products are carbon dioxide (CO2) and sulfur dioxide (SO2), the stoichiometric ratios from the balanced equation must be considered. The balanced chemical equation is CS2(l) + 3O2(g) → CO2(g) + 2SO2(g).

Given: 1.25 mol of CS2 and 0.57 mol of O2. We should calculate the theoretical amount of O2 needed to completely react with 1.25 mol of CS2. According to the equation, 1 mol of CS2 requires 3 mol of O2. Thus, 1.25 mol of CS2 would require 3.75 mol of O2 (1.25 mol × 3 mol/mol = 3.75 mol). Since only 0.57 mol of O2 is available and 3.75 mol is needed, oxygen is the limiting reactant because there is not enough oxygen to completely react with all of the carbon disulfide present.

can someone help me?

Answers

Answer:

oh sorry i cant but i might think the answer is adaptive but if not someone correct me and ill change this response hope that i could help

Explanation:

A gas in an engine cylinder expands from a volume of 10.0 L to 15.0 L against an external pressure of 1 atm and the system absorbs 300 J of heat in the process. Determine the work done by the system and the change in the system's internal energy, both in joules. Use this conversion scale to calculate the work done in joules: 1 L * atm

Answers

Answer: The work done by the system is -506.5 Joules and change in the system's internal energy is -206.5 Joules

Explanation:

According to first law of thermodynamics:

[tex]\Delta E=q+w[/tex]

[tex]\Delta E[/tex]=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system= [tex]-P\Delta V[/tex]  {Work is done by the system as the final volume is greater than initial volume and is negative}

w =[tex]-1atm\times (15.0-10.0)L=-5.00Latm=-506.5Joules[/tex]  {1Latm=101.3J}

q = +300J   {Heat absorbed by the system is positive}

[tex]\Delta E=+300+(-506.5)=-206.5J[/tex]

Thus the work done by the system is -506.5 Joules and change in the system's internal energy is -206.5 Joules

The work done by the system during expansion is -506.625 joules, and the change in internal energy is 806.625 joules.

The work done by the system when a gas expands from a volume of 10.0 L to 15.0 L against an external pressure of 1 atm can be found using the formula work (W) = -pressure (P) × change in volume (ΔV). First, we need to convert the pressure to joules by using the conversion 1 L·atm = 101.325 J. The change in volume (ΔV) is 15.0 L - 10.0 L = 5.0 L. Thus, the work done by the system can be calculated as W = -(1 atm) × (5.0 L) × (101.325 J/L·atm) = -506.625 J.

The change in the internal energy (ΔU) of the system can be found using the first law of thermodynamics, which is ΔU = Q - W, where Q is the heat absorbed by the system. In this case, Q = +300 J and the work done by the system, W, is -506.625 J. Therefore, the change in internal energy is ΔU = 300 J - (-506.625 J) = 806.625 J.

An ionic compound has a solubility of 30 g per 100 mL of water at room temperature. A solution containing 70 g of the compound in 300 mL of water at the same temperature is:

A. unsaturated.
B. saturated.
C. a suspension.
D. supersaturated.

Answers

Answer: A. unsaturated.

Explanation:

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

Supersaturated solution is defined as the solution in which more amount of solute particles is present than the solvent particles.

Given:  Solubility = 30g/100ml

If 100 ml can dissolve ionic compound = 30 g

300 ml can dissolve ionic compound  =[tex]\frac{30}{100}\times 300=90g[/tex]

Thus solubility is 90g/300 ml and dissolved salt is only 70 g , the solution is said to be unsaturated.

Final answer:

When 70 g of an ionic compound is dissolved in 300 mL of water, which is less than the 90 g required to saturate it, the solution is considered unsaturated.

Explanation:

The solubility of an ionic compound is given as 30 g per 100 mL of water at room temperature. If a solution contains 70 g of the compound in 300 mL of water at the same temperature, we need to determine whether the solution is unsaturated, saturated, or supersaturated.

To do this, we calculate the amount of compound that would saturate 300 mL of water, which would be 3 times the solubility in 100 mL of water:

30 g/100 mL x 3 = 90 g/300 mL

Since the solution has only 70 g in 300 mL of water, which is less than the 90 g needed to saturate it, the solution is unsaturated.

What are the correct mass and charge numbers for the following five products of radioactive decay: (a) a neutron (b) an α- particle (c) a positron (d) a photon (e) a β- ray

Answers

Answer:

Radioactive decay is defined as the disintegration of an unstable nucleus accompanied by the release of energy.

The different types of radioactive decay are: alpha decay, beta decay, gamma decay; which are accompanied by the release of photons or other subatomic particles.

The mass number (A) and charge number (Z) of the following products of radioactive decay are:

(a) a neutron : [tex]_{0}^{1}\textrm{n}[/tex]

A - 1

Z - 0

(b) an α- particle: [tex]_{2}^{4}\textrm{He}[/tex]

A - 4

Z - (+2)

(c) a positron : [tex]_{+1}^{0}\textrm{\beta }[/tex][tex]\beta[/tex]

A - 0

Z - (+1)

(d) a photon

A - 0

Z - 0

(e) a β- ray: [tex]_{-1}^{0}\textrm{\beta }[/tex][tex]\beta[/tex]

A - 0

Z - (-1)

Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2h2o2(aq)⟶2h2o(l)+o2(g) the activation energy for this reaction is 75 kj·mol−1. the enzyme catalase, found in blood, lowers the activation energy to 8.0 kj·mol−1. at what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °c?

Answers

Answer:

the temperature of the non- catalyzed reaction is = 2793.75 K

Explanation:

The reaction of the spontaneous decomposition of hydrogen peroxide to give water and oxygen is given as:

[tex]2H_2O_{2(aq)} ----> 2H_{2(l)} + O_2_{(g)}[/tex]

The activation energy of non-catalyzed reaction [tex]E{a_1} = 75 kJ/mol[/tex]

The activation energy of metal catalyzed reaction [tex]E{a_2} = 8 kJ/mol[/tex]

The temperature of metal catalyzed reaction [tex]T_2 = 25^0C[/tex] = (25+273)K = 298 K

The rate constant of the non-catalyzed reaction can be expressed as:

[tex]k_1 = Ae^{{-Ea_1}/RT_1}[/tex] ----- equation (1)

The rate constant of the metal catalyzed reaction can be expressed as:

[tex]k_2 = Ae^{{-Ea_2}/RT_2}[/tex]

Then [tex]k_1 = k_2[/tex]

[tex]Ae^{{-Ea_1}/RT_1}=Ae^{{-Ea_2}/RT_2}[/tex]

[tex]e^{{-Ea_1}/RT_1}=e^{{-Ea_2}/RT_2}[/tex]

[tex]\frac{Ea_1}{RT_1}}=\frac{Ea_2}{RT_2}}[/tex]

[tex]T_1 = \frac{Ea_1*T_2}{Ea_2}[/tex]

[tex]T_1 = \frac{75*298}{8}[/tex]

[tex]\\T_1 = 2793.75 \ K\\[/tex]

Thus; the temperature of the non- catalyzed reaction is = 2793.75 K

What are the reproductive structures of gymnosperms

Answers

Answer:

Reproduction in Gymnosperms: Gymnosperms are heterosporous and sexual reproduction is oogamous type. In living gymnosperms the reproductive structures are arranged in the form of strobili or cones (except the ovulate structures of Cycas).

Explanation:

Answer:

Cones are the reproductive structures of gymnosperms.

Explanation:

A voltaic cell is constructed with two silver-silver chloride electrodes, each of which is based on the following half-reaction: AgCl(s)+e−→Ag(s)+Cl−(aq). The two cell compartments have [Cl−]= 1.51×10−2 M and [Cl−]= 2.90 M , respectively. A) Which electrode is the cathode of the cell?B) What is the standard emf of the cell?C) What is the cell emf for the concentrations given?D) For the anode compartment, predict whether [Cl−] will increase, decrease, or stay the same as the cell operates.E) For the cathode compartment, predict whether [Cl−] will increase, decrease, or stay the same as the cell operates.

Answers

Final answer:

In this voltaic cell, the cathode is the electrode with less Cl- concentration, and the Cl- concentration will remain constant during the operation of the cell. The anode will have the higher Cl- concentration and will increase during cell operation. The standard emf will be zero, but the actual emf can be calculated using the Nernst equation.

Explanation:

In a voltaic cell with two silver-silver chloride electrodes, the half-reaction given is: AgCl(s)+e−→Ag(s)+Cl−(aq). The electrode with the higher concentration of Cl- ions (2.90 M) will function as the anode, where oxidation occurs and [Cl−] will increase. Conversely, the electrode with the lesser concentration of Cl- ions (1.51×10−2 M) will act as the cathode, where reduction takes place and [Cl−] will stay the same as the cell operates.

The standard emf of the cell would be zero, because the anode and cathode are made of the same material, and thus have the same reduction potential. The cell emf however can be calculated using the Nernst equation, where the cell's emf will shift from the standard emf based on the natural logarithm of the quotient of reactants over products.

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Calculate the new molarity that results when 250.mL of water is added to each of the following solutions.

a) 125 mL of 0.251 M HCI

B) 445 mL of 0.499 M H2SO4

C) 5.25L of 0.101 M HCO3

Answers

Answer:

The answer to your question is 1) 0.037 M  2) 0.32 M  3)  0.096 M

Explanation:

a) 125 ml of 0.251 M HCl

-Calculate the moles of HCl

Molarity = moles/volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 0.251 x 0.125

           = 0.0314

-Calculate the new molarity

Molarity = 0.0314/ (0.125 + 0.250)

-Simplification

Molarity = 0.014/0.375

-Result

Molarity = 0.037 M

2.-

445 ml of 0.499 M of H₂SO₄

-Calculate the number of moles

moles = 0.499 x 0.445

moles = 0.222

-Calculate the new molarity

Molarity = 0.222/(0.445 + 0.25)

Molarity = 0.222/0.695

Molarity = 0.32

3)

5.25 l of HCO₃ 0.101 M

Calculate the number of moles

moles = 0.101 x 5.25

moles = 0.53

-Calculate the Molarity

Molarity = 0.53 / (0.25 + 5.25)

Molarity = 0.53 / 5.5

Molarity = 0.096

The new molarity of each question is: (a): 0.0835 M, (b): 0.3194 M, and (c) 0.0964 M.

The new molarities after adding 250 mL of water to each solution are: a) 0.0835 M for the first solution (HCI) b) 0.3194 M for the second solution (H2SO4) c) 0.0964 M for the third solution (HCO3).

To calculate the new molarity after dilution, we can use the dilution equation:

[tex]\[ C_1V_1 = C_2V_2 \][/tex]

where [tex]\( C_1 \)[/tex] is the initial concentration, [tex]\( V_1 \)[/tex] is the initial volume, [tex]\( C_2 \)[/tex] is the final concentration, and [tex]\( V_2 \)[/tex] is the final volume.

Let's solve for each case:

a) For the first solution:

- Initial concentration [tex](\( C_1 \))[/tex] = 0.251 M

- Initial volume [tex](\( V_1 \))[/tex] = 125 mL

- Final volume [tex](\( V_2 \))[/tex] = 125 mL + 250 mL = 375 mL

We need to find the final concentration [tex](\( C_2 \))[/tex]. Using the dilution equation:

[tex]\[ C_1V_1 = C_2V_2 \][/tex]

[tex]\[ 0.251 \text{ M} \times 125 \text{ mL} = C_2 \times 375 \text{ mL} \][/tex]

[tex]\[ C_2 = \frac{0.251 \text{ M} \times 125 \text{ mL}}{375 \text{ mL}} \][/tex]

[tex]\[ C_2 = \frac{31.375 \text{ mL} \cdot \text{M}}{375 \text{ mL}} \][/tex]

[tex]\[ C_2 = 0.0835 \text{ M} \][/tex]

So, the new molarity for solution A is 0.0835 M.

b) For the second solution:

- Initial concentration [tex](\( C_1 \))[/tex] = 0.499 M

- Initial volume [tex](\( V_1 \))[/tex] = 445 mL

- Final volume [tex](\( V_2 \))[/tex] = 445 mL + 250 mL = 695 mL

Using the dilution equation:

[tex]\[ C_1V_1 = C_2V_2 \][/tex]

[tex]\[ 0.499 \text{ M} \times 445 \text{ mL} = C_2 \times 695 \text{ mL} \][/tex]

[tex]\[ C_2 = \frac{0.499 \text{ M} \times 445 \text{ mL}}{695 \text{ mL}} \][/tex]

[tex]\[ C_2 = \frac{222.005 \text{ mL} \cdot \text{M}}{695 \text{ mL}} \][/tex]

[tex]\[ C_2 = 0.3194 \text{ M} \][/tex]

So, the new molarity for solution B is approximately 0.3194 M.

c) For the third solution:

- Initial concentration [tex](\( C_1 \))[/tex] = 0.101 M

- Initial volume [tex](\( V_1 \))[/tex] = 5.25 L = 5250 mL

- Final volume [tex](\( V_2 \))[/tex] = 5250 mL + 250 mL = 5500 mL

Using the dilution equation:

[tex]\[ C_1V_1 = C_2V_2 \][/tex]

[tex]\[ 0.101 \text{ M} \times 5250 \text{ mL} = C_2 \times 5500 \text{ mL} \][/tex]

[tex]\[ C_2 = \frac{0.101 \text{ M} \times 5250 \text{ mL}}{5500 \text{ mL}} \][/tex]

[tex]\[ C_2 = \frac{530.25 \text{ mL} \cdot \text{M}}{5500 \text{ mL}} \][/tex]

[tex]\[ C_2 = 0.0964 \text{ M} \][/tex]

So, the new molarity for solution C is approximately 0.0964 M.

Which best compares AC and DC?

a
AC flows in one direction, and DC repeatedly switches direction.
b
AC is used only in generators, and DC is used only in motors.
c
DC is used only in generators, and AC is used only in motors.
d
DC flows in one direction, and AC repeatedly switches direction.
Please Help me, I have no clue what I'm reading, and I'm trying to make a good grade on this formative assesement

Answers

Answer: B) DC flows in one direction, and AC repeatedly switches directions.

Explanation:

DC stands for direct current, which is a current that constantly flows in only one direction.

AC stands for alternating current, which is a current that repeatedly changes directions.

GOOD LUCK! :)

Final answer:

Direct Current (DC) flows in one direction while Alternating Current (AC) flows by continuously changing its direction.

Explanation:

The difference between Alternating Current (AC) and Direct Current (DC) lies in the direction in which the electrons flow. In DC, the electrons flow steadily in a single direction, or 'directly'.

AC is a bit different; electrons keep swapping directions, sometimes going forwards and then going backwards.

Therefore, the answer to your question 'Which best compares AC and DC?' would be option D: DC flows in one direction, and AC repeatedly switches direction.

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Which types of organisms are required to complete the nitrogen cycle

Answers

Here you go your welcome
B
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