What values of x must be excluded from the domain of

f(x) = x + 7
_____
x^2 - 5x -6


A ) x =1 and x =-6

B ) x = -1 and x=6

C ) x= -7

D ) x = 2 and x = 3

E ) x = -6 and x = -7

Answer:

19:00 or 7:00 PM

Step-by-step explanation:

Baby armadillos need to be fed every four hours.

Baby bats need to be fed every three hours.

So we need to figure out when will they be fed again at the same time:

Basically, we need to find the LCM of two numbers i.e. 4 and 3. And the reason why are we finding the LCM is because that time difference will is the least common multiple of both the time differences, it is the smallest non-zero number that is the multiple of both 4 and 3.

The LCM of 4 and 3 is 12. So the time when they will be fed again at the same time will be 12 hours after 7:00 AM that is 19:00 hours or 7:00 PM.

-20.04 because they are opposites

The opposite value of a number is a number that when added to the original number, results in zero. In this case, the opposite value of 20.04 is -20.04.

The question is asking for the opposite value of 20.04. In mathematics, the opposite value, also known as the additive inverse, is a number which when added to the original number, results in zero. In other words, it's the number you would have to add to a specific number to get a sum of zero. Therefore, the opposite value of 20.04 is simply -20.04.

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We are given

[tex]V=0.95h^2[/tex]

we can plug h=8

and then we can find volume

[tex]V=0.95(8)^2[/tex]

[tex]V=60.8ft^3[/tex]

so,

the amount of water in the container when h = 8 feet is 60.8 ft^3........Answer

Answer:

395.1

Step-by-step explanation:

Simplify  

0.95 ( 8 ) ^2.9= v

395.07956558

The missing number can be shown as the variable x.

6 + 10 - 2 = 11 + x  

So, you need to figure out what x is by getting it by itself. First, combine everything on the left side of the equation.

16 - 2 = 11 + x

14 = 11 + x  

Now, what you do to one side of an equation, you have to do to the other. Subtract 11 from both sides

14 - 11 = 11 - 11 + x   Cancel out the 11s and solve the left side.

3 = x  

There's your answer! Now you can check your work by trying the 3 in your original problem.

6 + 10 - 2 = 11 + 3

14 = 14

Your missing number is 3.

Invested amount (P) = $300.

Time in years (t) = 2 years.

Balance after 2 years (A) = $329.49.

Let us assume rate of interest = r % compounds annually.

We know, formula for compound interest

[tex]A=P(1+r)^t[/tex]

Plugging values in formula, we get

[tex]329.49=300(1+r)^2[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}300[/tex]

[tex]\frac{300\left(1+r\right)^2}{300}=\frac{329.49}{300}[/tex]

[tex]\left(1+r\right)^2=1.0983[/tex]

Taking square root on both sides, we get

[tex]1+r=\sqrt{1.0983}[/tex]

[tex]\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}[/tex]

[tex]1+r-1=\sqrt{1.0983}-1[/tex]

[tex]r=\sqrt{1.0983}-1[/tex]

[tex]r=1.048-1[/tex]

r=0.048.

Converting it into percentage by multiplying by 100.

r=0.048 × 100

r  = 4.8 %

Therefore, the rate of interest on the account is 4.8% compounds annually.

30%

3/10

0.3

I think these are the right answers if I am understanding you correctly. :)

30%  ✔

3/10  ✔

1/3  ✖

0.3  ✔

0.03  ✖

Hope i Helped ❤

Answer:

The equation of [tex]C_{1}[/tex] is:  [tex]x^2+y^2=4[/tex]

and the equation of [tex]C_{2}[/tex] is:  [tex]x^2+y^2-2\sqrt{2}x-2\sqrt{2}y+2=0[/tex]

Step-by-step explanation:

The standard form of circle equation: [tex](x-h)^2+(y-k)^2 = r^2[/tex] , where [tex](h,k)[/tex] is the center and  [tex]r[/tex] is the radius of the circle.

The center of the circle [tex]C_{1}[/tex] is at origin or at (0, 0)  and has radius of 2.

So, the equation of the circle [tex]C_{1}[/tex] will be........

[tex](x-0)^2+(y-0)^2=(2)^2\\ \\ x^2+y^2=4 ..........................................(1)[/tex]

Now, the center of [tex]C_{2}[/tex] is the point in the first quadrant, where the line [tex]y=x[/tex] intersects [tex]C_{1}[/tex]

Solving the equations  [tex]x^2+y^2=4[/tex] and [tex]y=x[/tex] , we will get......

[tex]x^2+x^2= 4[/tex]  (Substituting [tex]y[/tex] as [tex]x[/tex])

[tex]2x^2= 4\\ \\ x^2=2\\ \\ x=\pm \sqrt{2}[/tex]

So,  [tex]y=x = \pm \sqrt{2}[/tex]

Thus, the center of the circle [tex]C_{2}[/tex] will be at  [tex](\sqrt{2},\sqrt{2})[/tex]  (Negative value is ignored as the point is in first quadrant)

Now, the distance between the center of [tex]C_{2}[/tex] and the x-axis is [tex]\sqrt{2}[/tex] and the circle touches the x-axis only at one point.

That means, the radius of the circle [tex]C_{2}[/tex] will be also [tex]\sqrt{2}[/tex]

So, the equation of the circle [tex]C_{2}[/tex] will be......

[tex](x-\sqrt{2})^2+(y-\sqrt{2})^2= (\sqrt{2})^2\\ \\ x^2-2\sqrt{2}x+2+y^2-2\sqrt{2}y+2=2\\ \\ x^2+y^2-2\sqrt{2}x-2\sqrt{2}y+2=0[/tex]

The value of 2.704 is .004 because it is 3 spaces to the right of the decimal point.

The variation statement tells you that when the radius is multiplied by 5, the volume is multiplied by 5² = 25. When the height is multiplied by 1/2, the volume is multiplied by 1/2.

Both of these variations together will multiply the volume by 25·(1/2) = 25/2.

So, the revised volume is (2π in³)·25/2 = 25π in³.

If these are terms of a geometric sequence, they have a common ratio. That is, ...

... (k -1)/(2(1 -k)) = (k +8)/(k -1)

... (k -1)² = 2(1 -k)(k +8) . . . . . multiply by the product of the denominators.

... k² -2k +1 = -2k² -14k +16 . . . eliminate parentheses

... 3k² +12k -15 = 0 . . . . . . . . put in standard form (subtract the right side)

... 3(k +5)(k -1) = 0 . . . . . . . . . factor

Possible values of k are ... -5, +1. The solution k=1 is extraneous, as it makes the first two terms 0 and the third term 8. (It doesn't work.)

The value of k is -5.

_____

The three terms are 12, -6, 3. The common ratio is -1/2.

To work this problem, you must assume that Juan's pedaling speed adds to the wind speed when going downwind, and that the wind speed subtracts from Juan's pedaling speed going upwind. (In other words, Juan's pedaling speed is relative to the air, not the ground.)

Let w represent the wind speed in miles per hour.

... distance = speed × time

Juan's total distance is 40 miles, so we have ...

... 40 = (11.5 +w)×1.75 + (11.5 -w)×2.50

... 40 = 48.875 - 0.75w . . . . . simplify

... -8.875/-0.75 = w . . . . . . . . subtract 48.875, divide by -0.75

... w = 11.833... = 11 5/6

The wind was blowing 11 5/6 miles per hour.

_____

Compared with real-life experience, and working through the details, this problem makes no sense whatever. Pedaling a bicycle is not like rowing a boat, where the current of the medium directly affects speed.

If you work through the segments of the problem, you find that Juan traveled 40.833 miles with the wind in the first 1.75 hours, so actually finished the race and then some. He spent the next 2.5 hours being blown backward by the wind, even though he was pedaling forward at 11.5 mph. (How much sense does that make?)

x = [tex]\frac{3}{2}[/tex] ± [tex]\frac{1}{2}[/tex]i

the equation has no real zeros but instead has 2 complex zeros

the discriminant = b² - 4ac

with a = 2, b= - 6, c = 5

b² - 4ac = (-6)² - (4 × 2 × 5 ) = -4

since b² - 4ac < 0  there are no real zeros

using the quadratic formula

x = ( 6 ± √(- 4 ) )/4 = ( 6 ± 2i ) / 4

x = [tex]\frac{6}{4}[/tex] ± [tex]\frac{2}{4}[/tex] i

  = [tex]\frac{3}{2}[/tex] ± [tex]\frac{1}{2}[/tex] i

Answer: x=3+i/2 or x=3-i/2

APEX

Answer:

1. See below for the table

2a. Early Pay: y = 45

2b. Deposit Plus: y = 12 + 4x

2c. Daily Pay: y = 6x

3. See the second attachment for a graph.

Step-by-step explanation:

1. The deposit (Deposit Plus) and the flat rate (Early Pay) are paid whether or not any days are spent swimming. For Early Pay, there are no additional charges, so the total cost is the same regardless of the number of days spent swimming.

For Deposit Plus, the $4 per day cost will add $20 for each 5 swimming days.

For Daily Pay, the $6 per day cost will add $30 for each 5 swimming days.

2. As described above, the Early Pay and Deposit Plus have charges when the number of swimming days is zero. The Daily Pay does not. The Deposit is only paid once, not each day.

a. Early Pay: y = 45

b. Deposit Plus: y = 12 + 4x

c. Daily Pay: y = 6x

3. The above equations are graphed in the second attachment. You will note that the plan that results in a minimum charge depends on the number of swimming days.

Answer:

2a. Early Pay: y = 45

2b. Deposit Plus: y = 12 + 4x

2c. Daily Pay: y = 6x

Step-by-step explanation:

3 + 6i

multiply the numerator/ denominator by the conjugate of 2 + i

the conjugate of 2 + i = 2 - i

[tex]\frac{15(2-i)}{(2+i)(2-i)}[/tex]

= ( 30i - 15i² ) / (4 - i² ) → ( i² = (√-1 )² = -1 )

= [tex]\frac{30i+15}{5}[/tex] = 6i + 3

Answer:

3+6i

Step-by-step explanation:

[tex]\frac{15i}{2+i}[/tex]

To divide we multiply by the conjugate of denominator

conjugate of 2+i is 2-i

Multiply top and bottom by 2-i

[tex]\frac{(15i)(2-i)}{(2+i)(2-i)}[/tex]

Apply FOIL method to multiply. value of i^2 = -1

(15i)(2-i) = 30i - 15i^2 = 30i +15(-1)= 30i+15

(2+i)(2-i)= 4 - i^2 = 4+1= 5

[tex]\frac{30i+15)}{5}[/tex]

Divide each term by 5

6i+3

so its 3+6i

Answer: Option C) The midpoint of the segment.

Then, you draw a circle with radius the half of the distance between the center of the circle and the point outside the circle.

The tangency points are the points where this circle cuts the given circle.

Answer:

One isosceles triangle

Step-by-step explanation:

y - 2

You get 2 less than a value when you subtract 2 from that value.

Try this option (see the attachment, the answers are marked by red colour), note, the value of the left angle in not visible (task no. 3) >> solution not given.

Answer:

m - Meter - Length.

s - Second - Time.

K - Kelvin - Temperature.

kg - Kilogram - Mass.

Units you might use in these scenarios include meters or kilometers for distance, meters per second or kilometers per hour for speed, millimeters or inches for rainfall, gallons or liters for volume, gallons per minute or liters per second for flow rate, and calories for caloric intake.

In each of these scenarios, you would use different units to measure different things:

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Solution-

The original or cost price of the good = $21.00

Then, it is marked up 78.7%, i.e the price is 78.7% more than the initial price, which in this case is $21.

The new price is,

[tex]21+(21\times \frac{78.7}{100})=\$37.527[/tex]

Then, 10% profit must be earned after selling the good. Hence, the list price must be 10% more of 37.527,

So, the selling or list price is

[tex]37.527+(37.527\times \frac{10}{100})=\$41.279 \approx \$41.28[/tex]

∴ $41.28 is the selling price of the good and this is how you got it.

"Alternate" angles are on opposite sides off the transversal.

"Interior" angles are between the lines the transversal is crossing.

The appropriate choice for alternate interior angles is ...

... 5 and 3

Answer:

The pair of angles the are alternate interior angles are 5 and 3. Or C.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The wording in the problem statement is ...

... "less than 3 years"

... "at least 3. but less than 6 years"

so we expect the inequality symbols to look like ...

... 0 ≤ x < 3

... 3 ≤ x < 6

These match the second piecewise function.

option E) 30 is the answer for the square root of 75 times the square root of 12

We start by using the property of square roots that states the product of two square roots is the square root of the product of the numbers. This gives us:

[tex]\sqrt{75} \times \sqrt{12} = \sqrt {75 \times 12}[/tex]

Now we can simplify the expression by finding the product of 75 and 12. This gives us:

[tex]\sqrt {75 \times 12} = \sqrt{900} = 30[/tex]

Thus, the square root of 75 times the square root of 12 gives 30 as the answer. So, option E) 30 is the correct answer.

Correct question:

The square root of 75 times the square root of 12.

A. the square root of 63

B. 3 times the square root of 7

C. 3 times the square root of 3

D. 8 times the square root of 3

E. 30

3z = 5

To isolate the variable ( solve for z), you need to divide both sides by 3.

The answer is D.

To solve the given operation firat we take LCM for both terms.

As denominator of first term is 3 and second term is [tex] 12x-8 [/tex]

Therefore, the Lcm is [tex]3(12x-8) [/tex]

Now solving and making same denominator for each term

[tex]\frac{7}{3} [/tex] [tex]\times [/tex] [tex] \frac{12x-8}{12x-8} [/tex]

On multiplying we get

[tex]\frac{7(12x-8)}{3(12x-8)} [/tex] [tex]=\frac{84x-56}{3(12x-8)} [/tex]

Now solving other term

[tex]\frac{8}{12x-8} [/tex] [tex]\times [/tex] [tex]\frac{3}{3} [/tex]

On multiplying we get

[tex]\frac{24}{3(12x-8)} [/tex]

Now solving the expression by putting the values

[tex]\frac{84x-56-24}{3(12x-8)} [/tex]

[tex]\frac{84x-80}{12(3x-2)} [/tex]

[tex]\frac{4(21x-20)}{12(3x-2)} [/tex]

On solving we get

[tex]\frac{21x-20}{3(3x-2)} [/tex]

There denominator of the expression is

[tex]9x-6 [/tex]

Hope this will help

Find the number needs to be added to both sides of the equation in order to complete the square

x ^2+16x=18

In completing the square , we take the coefficient of x and divide it by 2

Then square it and add it on both sides.

The coefficient of x  is 16

Half of 16 is 8

Then we square it . [tex](8)^2 = 64[/tex]

Add 64 on both sides

[tex]x ^2+16x + 64=18+64[/tex]

Now we factor x^2 + 16x+64

[tex](x+8)(x+8)=18+64[/tex]

[tex](x+8)^2=82[/tex]

so 64 is added to both sides of the equation in order to complete the square.

Answer:

Step-by-step explanation:

a) There are 16 ounces in a pound, so 10 ounces is 10/16 = 5/8 lb. The total weight of the pigs is their number multiplied by their average weight:

... weight of pigs = 30 × 95 5/8 lb = ((30·95) + (30·5/8)) lb

... = (2850 + 150/8) lb = (2850 +18 3/4) lb = 2868 lb 12 oz

b) The truck tare weight is the gross weight less the weight of the pigs.

... truck tare = truck gross - truck load

... = (8×2000 lb) + (1123 lb) + (6/16 lb) - (2868 3/4 lb)

... = 17123 3/8 lb - 2868 3/4 lb = (17123 -2868) lb +(3/8 -3/4) lb

... = 14255 lb - 3/8 lb

... = 14254 5/8 lb

... = 14000 lb + 254 lb + 5/8 lb

... truck tare weight = 7 tons 254 lbs 10 oz

_____

Many graphing calculators will handle calculations with fractions very nicely.

It would equal 0.75 and as a fraction it is 3/4

Hi!

[tex]\frac{9}{34}* \frac{17}{6}[/tex]

[tex]\frac{9*17}{34*6}[/tex]

[tex]\frac{153}{34*6}[/tex]

[tex]\frac{153}{204}[/tex]

[tex]Answer---->\frac{3}{4}[/tex]

Explanation: First multiply by the fraction 9*17/34*6. Then multiply by the numbers 9*17=153, with 153/34*6. Next you can also multiply by 34*6=204, with 153/204 as a fraction. You can also cancel the common factor 51, and the answer is 3/4 is the right answer. Hope this helps! And thank you for posting your question at here on Brainly. And have a great day! -Charlie

The only equation that has 3 as the coefficient of x (a slope of 3) is ...

... d.) y = 3x+4

_____

Happily, it also goes through the given point.

... 5/2 = 3(-1/2) +4

... 5/2 = -3/2 + 8/2 . . . . true

The equation of the line with a slope of 3 that passes through the point (-1/2, 5/2) is y = 3x + 4, which corresponds to answer option (d.) y = 3x + 4.

To find the equation of a line with a given slope and that passes through a specific point, we can use the point-slope form of a line, which is y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the given point. So, for a line with a slope of 3 that goes through the point (-1/2, 5/2), we can plug in the values to get the equation.

Substituting into the point-slope form, we get y - 5/2 = 3(x + 1/2). Simplifying and solving for y will give us the equation of the line in the form of y = mx + b. After distributing and rearranging, the equation will be y = 3x + 4.

Therefore, the correct answer is (d.) y = 3x + 4.