What volume of 24% trichloroacetic acid (tca) is needed to prepare eight 3 ounce bottles of 10% tca solution?

Answers

Answer 1

Answer:

295.7 mL of 24% trichloroacetic acid (tca) is needed .

Explanation:

Let the volume of 24% trichloroacetic acid solution be x

Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces

= 24 ounces = 709.68 mL

(1 ounces =  29.57 mL)

Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

[tex]x\times \frac{24}{100}=709.68 mL\times \frac{10}{100}[/tex]

x = 295.7 mL

295.7 mL of 24% trichloroacetic acid (tca) is needed .


Related Questions

Which member of the following pairs has the larger London dispersion forces?
H2O or H2S
CO2 or CO
CH4 or SiH4

Answers

Answer:

H₂S; CO₂; SiH₄

Explanation:

London dispersion forces are larger in molecules that are large and have more atoms or electrons.

A. H₂O or H₂S

H₂S. S is below O in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

B. CO₂ or CO

CO₂. CO₂ has more atoms. It is also linear, so the molecules can get close to each other and maximize the attractive forces.

C. CH₄ or SiH₄

CH₄. Si is below C in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

Differences are stronger in bigger and heavier atoms than in lighter and smaller ones. Its number of electrons inside a larger atom is, in general, farther away from the nuclei than in a small atom.

The number of electrons that reasonable accommodations dipoles affect the intensity of the London dispersion forces.[tex]H_2S[/tex] is indeed the bigger element since it is below O just on the Table Of the elements, and the electrons are polarizable to a greater extent.[tex]CO_2[/tex]  has more atoms. It is also linear, allowing the molecules to get close to each other and optimize the attraction forces.Because [tex]CH_4 \ Si[/tex] sits below C on the Periodic Table, it is the bigger atom. Its electrons are more polarizable.

Therefore, the answer is "[tex]\bold{H_2S\ , CO_2\ or \ SiH_4}[/tex]"

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Which of the following refers to each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in atomic mass but not in chemical properties?
(A) isotope
(B) isoton
(C) Radioactivity
(D) Nuclear reaction

Answers

Answer:

The answer is A.

Hope this helps!

Two or more than two atoms with different physical or chemical properties can not combine together to form an element. Therefore, the correct option is option A that is isotopes.

What is element?

Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.

Isotope refers to each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in atomic mass but not in chemical properties. Isotopes of hydrogen are Protium, Deuterium and Tritium with atomic number 1 and mass number1,2 and  respectively.

Therefore, the correct option is option A that is isotopes.

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Write a chemical equation for the hydrolysis reaction that explains why an aqueous solution of ch3nh3cl is acidic.

Answers

when aqueous solution of [tex]CH_{3} NH_{3}Cl[/tex] is taken it dissociates and gives hydronium ion so it is acidic in nature. It is example of hydrolysis reaction

What is hydrolysis reaction?

Hydrolysis reaction is a reaction in which bond is broken down with the help of water. Lysis term stands for breaking of anything.

Example: Hydrolysis of ester produces alcohol and acid. Hydrolysis of ester is done both in acid and basic condition.

Any acidic solution that contains acidic acid when put in water produces hydronium ion or we can say that any species that produces hydronium ion in water is acidic in nature.

In our case when [tex]CH_{3} NH_{3}Cl[/tex] is put in water it easily gives hydronium ion in water this shows that it is acidic in nature. and the reaction can be shown as:

[tex]CH_{3} NH_{3}Cl +H_{2}O\rightarrow CH_{3}NH_{2}Cl^{-} +H_{3}O^{+}[/tex]

Thus[tex]CH_{3} NH_{3}Cl[/tex] is acidic in nature and is a hydrolysis reaction.

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Final answer:

An aqueous solution of CH3NH3Cl is acidic due to the hydrolysis reaction that occurs when the compound is dissolved in water, producing CH3NH3+ ions that increase the concentration of H+ ions in the solution.

Explanation:

Aqueous solutions of CH3NH3Cl are acidic due to the hydrolysis reaction that occurs when the compound is dissolved in water. The hydrolysis reaction of CH3NH3Cl can be represented by the chemical equation:

CH3NH3Cl + H2O → CH3NH3+ + Cl- + H2O

In this reaction, CH3NH3Cl dissociates into CH3NH3+ and Cl- ions. The CH3NH3+ acts as a weak acid, releasing H+ ions into the solution, resulting in an overall acidic pH.

Histamine is a substance that is released by cells in response to injury, infections, stings and materials that cause allergic responses, such as pollen. Histamine causes dilation of blood vessels and swelling due to accumulation of fluid in the tissues. People sometimes take antihistamine drugs to counteract the effects of histamine. A sample of histamine having a mass of 385 mg is composed of 208 mg of carbon, 31 mg of hydrogen and 146 mg of nitrogen. The molar mass of histamine is 111 g/mol. What is the molecular formula for histamine?

Answers

Answer:

C₅H₉N₃

Explanation:

First, you need to find the empirical formula of the compound (histamine).

To find the empirical formula convert all the data given in mass units (miligrams) into mole numbers.

You do that by using the formula: number of moles = mass in grams / atomic mass.

To find the mass in grams divide the mass in miligrams by 1,000.

Build a table:

Element    mass (g)   atomic mass (g/mol)    number of moles (mol)

C                0.208           12.011                        0.0173

H                0.031            1.008                        0.0307

N                0.146           14.007                       0.0104

Now, find the ratio C:H:N, for which you divide every number of moles by the smallest number of moles: 0.0104:

C: 0.0173 / 0.0104 = 1.665H: 0.0307 / 0.0104 = 2.957N: 0.0104 / 0.104 = 1.002

You must find a multiple that yields 1.665 to a reasonably close integer.

Muliply every amount by 3:

C: 1.665(3) = 4.995 ≈ 5H: 2.957(3) = 8.871 ≈ 9N: 1.002(3) = 3.007 ≈ 3

Hence, the empirical formula is C₅H₉N₃.

Now, find the mass of the empirical formula:

5(12.011 g/mol) +  9(1.008 g/mol) + 3(14.007 g/mol) = 111.148 g/mol ≈ 111 g/mol.

Since the mass of the empirical formula is the same of the molecular formula, both formulae are the same.

Therefore, the answer is: C₅H₉N₃ ← molecular formula

Answer:

it will be C5H9N3

Explanation:

because 1st find %age composition then no. of grams then atomic rati and multiple by 3 in thi case and then get the answer

SHOW ALL YOUR WORK!!

1. Given pH = 8.55
Find: [H3O+] and [OH-]
Is this acidic, basic or neutral?



2. Given pH = 3.50
Find: [H3O+] and [OH-]
Is this acidic, basic or neutral?



3. Given [H3O+] = 3.67 x 10-8M
Find: [OH-] and pH
Is this acidic, basic or neutral?



4. Given [H3O+] = 9.89 x 10-3M
Find: [OH-] and pH
Is this acidic, basic or neutral?



5. Given [OH-] = 5.5 x 10-10M
Find: [H3O+] and pH
Is this acidic, basic or neutral?



6. Given [OH-] = 8.5 x 10-2M
Find: [H3O+] and pH
Is this acidic, basic or neutral?



7. Given [OH-] = 3.75 x 10-5M
Is this acidic, basic or neutral?
How do you know?



8. Given [H3O+] = 3.75 x 10-3M
Is this acidic, basic or neutral?
How do you know?



9. Given pH = 6.75,
Is this acidic, basic or neutral?
How do you know?



10. Given [H3O+] = 1.00 x 10-7M
Is this acidic, basic or neutral?
How do you know?



Answers

Answer:

1. [H₃O⁺] = 2.0 x 10⁻⁹ M.

   [OH⁻] = 3.55 x 10⁻⁶ M.

  The solution is basic.

2. [H₃O⁺] = 3.16 x 10⁻⁴ M.

   [OH⁻] = 3.16 x 10⁻¹¹  M.

  The solution is acidic.

3. [OH⁻] = 2.72 x 10⁻⁷ M.

   pH = 7.435.

   The solution is basic.

4. [OH⁻] = 9.89 x 10⁻³ M.

   pH = 2.0.

   The solution is acidic.

5. [H₃O⁺] = 1.82 x 10⁻⁵ M.

   pH = 4.74.

  The solution is acidic.

6.

[H₃O⁺] = 1.176 x 10⁻¹³ M.

   pH = 12.93.

   The solution is basic.

7. The solution is basic.

8. The solution is acidic.

9. The solution is acidic.

10. The solution is neutral.

Explanation:

We can use the following relations:

pH = - log[H⁺],

pOH = - log[OH⁻],

Kw = [H⁺][OH⁻] = 10⁻¹⁴.

To determine whither the solution is acidic, basic or neutral:

pH scale is a scale from 0 to 14, from which we can determine the nature of the solution:

If the (0 ≤ pH > 7), the solution is acidic.If the pH = 7, the solution is neutral.If the (7 < pH ≥ 14), the solution is basic.

1. Given pH = 8.55, Find: [H₃O⁺] and [OH⁻], Is this acidic, basic or neutral?

∵ pH = - log[H₃O⁺]

∴ 8.55 =  - log[H₃O⁺]

∴ [H₃O⁺] = 2.0 x 10⁻⁹ M.

∵ Kw = [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴  [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(2.0 x 10⁻⁹ M) = 3.55 x 10⁻⁶ M.

∵ pH = 8.55 > 7,

∴ The solution is basic.

2. Given pH = 3.50, Find: [H₃O⁺] and [OH⁻], Is this acidic, basic or neutral?

∵ pH = - log[H₃O⁺]

∴ 3.50 =  - log[H₃O⁺]

∴ [H₃O⁺] = 3.16 x 10⁻⁴ M.

∵ Kw = [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴  [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(3.16 x 10⁻¹⁴ M) = 3.16 x 10⁻¹¹ M.

∵ pH = 3.50 < 7,

∴ The solution is acidic.

3. Given [H₃O⁺] = 3.67 x 10⁻⁸ M, Find: [OH⁻] and pH, Is this acidic, basic or neutral?

∵ Kw = [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴  [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(3.67 x 10⁻⁸ M) = 2.72 x 10⁻⁷ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(3.67 x 10⁻⁸ M) = 7.435.

∵ pH = 7.435 > 7,

∴ The solution is basic.

4. Given [H₃O⁺] = 9.89 x 10⁻³ M, Find: [OH⁻] and pH, Is this acidic, basic or neutral?

∵ Kw = [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴  [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(9.89 x 10⁻³ M) = 9.89 x 10⁻³ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(9.89 x 10⁻³ M) = 2.0.

∵ pH = 2.0 < 7,

∴ The solution is acidic.

5. Given [OH⁻] = 5.5 x 10⁻¹⁰ M, Find: [H₃O⁺] and pH, Is this acidic, basic or neutral?

 ∵ Kw = [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴  [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(5.5 x 10⁻¹⁰ M) = 1.82 x 10⁻⁵ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(1.82 x 10⁻⁵ M) = 4.74.

∵ pH = 4.74 < 7,

∴ The solution is acidic.

6. Given [OH⁻] = 8.5 x 10⁻² M, Find: [H₃O⁺] and pH, Is this acidic, basic or neutral?

∵ Kw = [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴  [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(8.5 x 10⁻² M) = 1.176 x 10⁻¹³ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(1.176 x 10⁻¹³ M) = 12.93.

∵ pH = 12.93 > 7,

∴ The solution is basic.

7. Given [OH⁻] = 3.75 x 10⁻⁵ M, Is this acidic, basic or neutral?  How do you know?

∵ Kw = [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴  [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(3.75 x 10⁻⁵ M) = 2.67 x 10⁻¹⁰ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(2.67 x 10⁻¹⁰ M) = 9.57.

∵ pH = 9.57 > 7,

∴ The solution is basic.

8. Given [H₃O⁺] = 3.75 x 10⁻³ M, Is this acidic, basic or neutral?  How do you know?

∵ pH = - log[H₃O⁺]

∴ pH = - log(3.75 x 10⁻³ M) = 2.43.

∵ pH = 2.43 < 7,

∴ The solution is acidic.

9. Given pH = 6.75,  Is this acidic, basic or neutral?  How do you know?

∵ pH = 6.75 < 7,

∴ The solution is acidic.

10. Given [H₃O⁺] = 1.00 x 10⁻⁷ M, Is this acidic, basic or neutral?  How do you know?

∵ pH = - log[H₃O⁺]

∴ pH = - log(1.0 x 10⁻⁷ M) = 7.0.

∵ pH = 7.0,

∴ The solution is neutral.

A sample of nitrogen gas had a volume of 500. mL, a pressure in its closed container of 740 torr, and a temperature of 25 °C. What was the new volume of the gas when the temperature was changed to 50 °C and the new pressure was 760 torr?

Answers

Answer:

527.68 mL

Explanation:

We will assume that nitrogen is behaving as ideal gas here.

For ideal gas the gas law is:

[tex]\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}[/tex]

Where

P1= initial pressure = 740 torr

V1= initial volume = 500mL

T1= initial temperature = 25⁰C = 298 K

P2= final pressure = 760 torr

V2= final volume = ?

T2= final temperature = 50⁰C = 323 K

Putting values in the gas law

Final volume = [tex]\frac{740X500X323}{298X760}= 527.68 mL[/tex]

PLEASE HELP!!
If iron pyrite, FeS2, is not removed from coal, oxygen from the air will combine with both the iron and the sulfur as coal burns. If a furnace burns an amount of coal containing 198.20 g of FeS2, how much SO2 (an air pollutant) is produced?

Select one:
a. 211.7
b. 52.92
c. 590.8
d. 582.1

Answers

Answer:

a. 211.7

Explanation:

Iron Pyrite reacts with Oxygen to produce Iron (II) Oxide and Sulphur (IV) Oxide.

The equation is as follows:

4FeS₂₍s₎ + 11O₂₍g₎ → 2Fe₂O₃₍s₎ + 8SO₂₍g₎

From the equation, 4 moles of FeS₂ produce 8 moles of SO₂.

Therefore the reaction ratio is 4:8 or 1:2

198.20 grams of FeS₂ into moles is calculated as follows:

Moles= Mass/RMM

RMM of FeS₂ is 119.9750g/mol.

Number of moles = 198.20/119.9750g/mol

=1.652 moles of FeS₂

The reaction ratio of FeS₂ to SO₂ produced is 1:2

Thus SO₂ produced = 1.652 moles×2/1=3.304 moles

The mass of SO₂ produced =Moles ×RMM

=3.304 moles ×64.0638 g/mol

=211.667 grams

=211.7g

In a reaction, compounds a and b combine to form compounds c and



d. the rate law is: rate = k[a][b]. what is the rate order?

Answers

Answer : The rate order of reaction is, second order reaction.

Explanation :

Rate of reaction : It is defined as the rate of change in concentration of reactant or product with respect to time.

Order of reaction : It is defined as the sum of the exponents or powers to which the molar concentration in the rate law equation are raised to express the observed rate of reaction.

As per question the reaction will be :

[tex]A+B\rightarrow C+D[/tex]

The given rate expression is,

[tex]Rate=k[A][B][/tex]

From this expression we conclude that the power of concentration of reactant A and B are 1, 1.

The sum of power of concentration of reactant A and B = 1 + 1 = 2

That means it is a second order reaction.

Hence, the rate order of reaction is, second order reaction.

Answer:

second - order

Explanation:

Which factor is needed to begin a nuclear fission reaction?

high temperature

stable nuclei

addition of a neutron

low pressure

Answers

Answer:

addition of a neutron

Explanation:

Nuclear fission is a radioactive decay process in which a heavy nucleus spontaneously disintegrates into lighter ones accompanied by the release of energy.

An atom whose neutron/proton ratio is the same as that of the stability ratio of that atom is said to be stable. When such an atom is bombarded with a neutron particle, the stability ratio is offset. What results is a radioactive decay of such a nucleus. This form of decay is a nuclear fission.

A series of chain reaction is produced though this until the stability ratio is reached.

The first step in the industrial recovery of zinc from the zinc sulfide ore is roasting-that is, the conversion of ZnS to ZnO by heating: 2ZnS(s) + 3O2(g) →2ZnO(s) + 2SO2(g) ΔH = −879 kJ Calculate the heat (in kJ) associated with roasting 1 gram of zinc sulfide.

Answers

Answer:

4.51 kJ of heat is liberated to the surroundings when 1 gram of zinc sulfide is roasted.

Explanation:

From the reaction and its associated enthalpy change, we know that the heat associated with 2 moles of zinc sulfide is -879 kJ.

Data: 1 gram of zinc sulfide

moles of zinc sulfide = mass of zinc sulfide / Molecular weight of zinc sulfide

moles = 1 g/ (97.474 g/mol) = 0.01 mol

The following proportion must be satisfied:

2 moles / 0.01 mol  = -879 kJ / x kJ

x = -879*0.01/2 = -4.395 kJ

The negative sign means that the heat is liberated to the surroundings.

Final answer:

The heat associated with roasting 1 gram of zinc sulfide can be calculated using the given information. For 1 gram of ZnS, the heat would be -4.48 kJ.

Explanation:

The heat associated with roasting 1 gram of zinc sulfide can be calculated using the given information. The equation for the reaction is: 2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g). The enthalpy change (ΔH) for this reaction is -879 kJ. We need to find the heat associated with roasting 1 gram of zinc sulfide, so we can use the molar mass of ZnS to convert the mass from grams to moles. The molar mass of ZnS is approximately 97.45 g/mol. Therefore, 1 gram of ZnS is equal to 0.0103 moles of ZnS. To calculate the heat, we can use the stoichiometric coefficients from the balanced equation. For every 2 moles of ZnS, we have an enthalpy change of -879 kJ. Therefore, for 0.0103 moles of ZnS, the heat associated with roasting would be (0.0103/2) x -879 kJ = -4.48 kJ.

By converting CO2 to H2CO3, carbonic anhydrase _______the PCO2 in endothelial cells, red blood cells, and plasma, thereby _______ diffusion of CO2 from tissue cells to these locations.

Answers

Answer:

reduces; facilitating

Explanation:

Carbonic anhydrases is a type of metalloenzyme containing zinc metal which catalyze interconversion between the carbon dioxide gas and water and dissociated ions of the carbonic acid.

The reaction that is catalyzed by enzyme, carbonic anhydrase is:

HCO₃⁻ + H⁺ ⇄ CO₂ + H₂O

The enzyme maintains the acid-base balance in the body and helps in the transportation of carbon dioxide through out the body.

The carbon dioxide formed as a by-product of metabolism which is transported to blood in the form of bicarbonate ions by the action of carbonic anhydrase.

Thus,

By converting CO₂ to H₂CO₃, Carbonic anhydrase reduces the PCO₂ in endothelial cells, red blood cells, and plasma, thereby facilitating diffusion of CO₂ from tissue cells to these locations.

Carbonic anhydrase reduces PCO₂ by converting CO₂ to H₂CO₃, which leads to an increase in the diffusion of CO₂ from tissue to blood.

By converting CO₂ to H₂CO₃ (carbonic acid), carbonic anhydrase lowers the PCO₂ (partial pressure of carbon dioxide) in endothelial cells, red blood cells, and plasma, thereby increasing diffusion of CO₂ from tissue cells to these locations. This enzyme catalyzes the reversible hydration of carbon dioxide, forming bicarbonate ions (HCO₃⁻) and protons (H⁺). The reduction in PCO₂ creates a pressure gradient that favors the diffusion of CO₂ from the tissues, where its concentration is higher, towards the blood where it’s lower due to the action of carbonic anhydrase.

Give a term for each description.Organic chemicals that can vaporize into the air.Secondary chemicals whose formation is facilitated by sunlight.Amount of gases and small particles in the atmosphere that influence ecosystem or human well-being.Gases or particles that are present in high enough concentrations to harm humans, other organisms, and buildings and other structures.Very small solid and liquid particles suspended in the air.

Answers

Answer:

Volatile organic compoundssecondary pollutants or photochemical substancesAir QualityAir pollutionAerosols

Explanation:

Volatile organic compounds are the  organic chemicals that get easily vaporized in air.

The secondary chemicals or the secondary pollutants are the photochemical substances that are formed in the presence of sunlight.

The amount of gases and small particles present in the atmosphere, responsible for influencing ecosystem and the wellness of human beings is known as the Air Quality

Air pollution refers to the high concentrations of gases or small particles that are present in the atmosphere, which can cause harm to the humans and other living organisms and structures established by humans.

Aerosols are the tiny particles present in liquid or solid state, that are suspended in air.

Compared with its corresponding unsaturated fatty acid, a saturated fatty acid has _____. more hydrogen less hydrogen more oxygen less oxygen

Answers

Answer: Saturated fatty acids have more hydrogen than unsaturated fatty acids.

Explanation:

Saturated fat is defined as the fat in which the fatty acid chains contain only single bonds between carbon and carbon atoms. For Example: Cream, cheese etc..

Unsaturated fat is defined as the fat or fatty acid in which one or more double bonds are present between carbon and carbon atoms in the fatty acid chain. For Example: Oleic acid, Myristoleic acid etc..

When double bond emerges in a compound, it leads to the reduction of hydrogen atoms.

Thus, saturated fatty acids have more hydrogen than unsaturated fatty acids.

Final answer:

Saturated fatty acids have more hydrogen atoms than unsaturated fatty acids because of their molecular structure. They only have single bonds which allows each carbon atom to bond with as many hydrogen atoms as possible.

Explanation:

Compared with its corresponding unsaturated fatty acid, a saturated fatty acid has more hydrogen. The difference lies in their molecular structure. Saturated fatty acids have single bonds only, which means each carbon atom in the chain is bonded to as many hydrogen atoms as possible. In contrast, unsaturated fatty acids have one or more double or triple bonds, which reduces the number of hydrogen atoms they can bond with.

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Calculate the equilibrium constant for each of the reactions at 25 ∘C.


a. 2Cr3+(aq)+3Sn(s)→2Cr(s)+3Sn2+(aq)

b. O2(g)+2H2O(l)+2Sn2+(aq)→4OH−(aq)+2Sn4+(aq)

c. 2Cr3+(aq)+3Ni(s)→2Cr(s)+3Ni2+(aq)

Answers

Final answer:

The equilibrium constants for the reactions can be calculated using the standard free energy change and the formula K = e^{(-ΔG°/(RT))}, but specific ΔG° values or tables referenced are needed to complete the calculations.

Explanation:

To calculate the equilibrium constant for the reactions at 25 °C, we use the given thermodynamic data from the tables and apply the relation between the standard free energy change (ΔG°) and the equilibrium constant (K). The relation is given by the equation ΔG° = -RTlnK, where R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin, and K is the equilibrium constant. For each reaction with a given ΔG° value, we can rearrange the formula to solve for K: K = e^{(-ΔG°/(RT))}.

For the provided exercises:

For reaction (a) 2Cr3+(aq)+3Sn(s)→2Cr(s)+3Sn2+(aq), we would need the ΔG° values for each species to perform the calculation.For reaction (b) O2(g)+2H2O(l)+2Sn2+(aq)→4OH-(aq)+2Sn4+(aq), this appears to be a similar reaction to the provided exercises, but without the exact ΔG° values or Table P2, the equilibrium constant cannot be calculated.For reaction (c) 2Cr3+(aq)+3Ni(s)→2Cr(s)+3Ni2+(aq), again, the ΔG° values would be necessary to calculate K.

When the necessary thermodynamic data is provided, each reaction's equilibrium constant can be calculated using the formula K = e^{(-ΔG°/(RT))}, with R = 8.314 J/mol·K, and T = 298.15 K (since 25 °C is equivalent to 298.15 K).

If an object has a density of 0.55 g/mL, what is its density in cg/L?
0.0055 cg/L
55 g/L
550 g/L
55,000 g/L

Answers

if              1 g is equal to 100 cg

then  0.55 g are equal to X cg

X = (0.55 × 100 ) / 1 = 55 cg

The density of the object is 55 cg/L.

Answer : The density in cg/L is, 55000 cg/L

Explanation :

Density : It is defined as the mass of a substance contained per unit volume.

The conversion used from gram to centigram is:

1 gram = 100 centigram

The conversion used from milliliter to liter is:

1 mL = 0.001 L

So,

1 g/mL = [tex]\frac{100}{0.001}cg/L=100000cg/L[/tex]

As we are given the density 0.55 g/mL. Now we have to determine the density in cg/L.

As, 1 g/mL = 100000 cg/L

So, 0.55 g/mL = [tex]\frac{0.55g/mL}{1g/mL}\times 100000cg/L=55000cg/L[/tex]

Therefore, the density in cg/L is, 55000 cg/L

A. Sr (NO3)2 •5 H2O
B. Sr (NO3)2 •3 H2O
C. Sr (NO3)2 •2 H2O
D. Sr (NO3)2 •4H2O

Answers

Answer:

C. Sr (NO3)2 •2 H2O

Explanation:

A 30.7 g sample of Strontium nitrate, Sr(NO3)2⋅nH2O, is heated to a contstent mass of 22.9.

Therefore, the calculated hydration number is Sr (NO3)2 •2 H2O.

Answer:

C

Explanation:

Consider the following equation: N2O4(g) ⇄ 2 NO2(g) Kc = 5.8 × 10-3 If the initial concentration of N2O4(g) = 0.040 M and the initial concentration of NO2(g) is 0 M, what is the equilibrium concentration of N2O4(g)?

Answers

Final answer:

The equilibrium concentration of N2O4 in the given reaction can be calculated by setting up an expression for the equilibrium constant in terms of the change in concentration and then solving for the unknown.

Explanation:

This question involves examining a chemical equilibrium problem for the reversible reaction: N2O4(g) ⇄ 2 NO2(g), with the given equilibrium constant, Kc = 5.8 × 10-3. The initial concentration of N2O4 is given as 0.040 M, while the initial concentration of NO2 is given as 0 M. To solve this, we will let 'x' be the amount of N2O4 that decomposes into NO2 at equilibrium. Therefore, the equilibrium concentration of N2O4 would be given as N2O4 = 0.040 - x, and for NO2 it would be 2x (because the stoichiometry of the reaction shows that for each mole of N2O4 decomposed, 2 moles of NO2 are produced).

Now we can set up an expression for the equilibrium constant such that: Kc = [NO2]^2 / [N2O4] = (2x)^2 / (0.040 - x). By substituting 5.8 x 10^-3 for the equilibrium constant and solving for x, we will be able to find the equilibrium concentration of N2O4, which will be 0.040 - x.

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The above reaction is run and found to follow second order kinetics with a rate constant of 1.30 x 10-3 M-1sec-1. If the initial concentration of A is 1.54 M, what is the concentration after 172 seconds?

Answers

The final concentration after 172 seconds is 1.15 M. To obtain this answer, use the the integrated rate law for the order of reaction. Based on the problem, this is a second order reaction. The units of the rate constant also support that it is a second order reaction.

Further Explanation:

The solution to this problem is straightforward.

Identify the integrated rate law for the corresponding order of reaction.Substitute the given values into the integrated rate law equation. Use algebra to solve for the unknown, C(f).

STEP 1: Since the reaction is a second order reaction, the integrated rate law will be:

[tex]\frac{1}{C_{f}} = \ kt \ + \frac{1}{C_{i}}[/tex]

where:

C(f) is the final concentration

k is the rate constant

t is the time

C(i) is the initial concentration

STEP 2: Plugging in the values given in the problem into the equation, the following equation should be obtained:

[tex]\frac{1}{C_{f}} \ = (1.30  \ x \ 10^{-3} \frac{ \ 1 }{ \ M-s})(172 \ s) \ + \ \frac{1}{1.54 \ M} \\[/tex]

STEP 3: Using algebra to solve for C(f):

[tex]\frac{1}{C_{f}} = \ 0.87295\\ \\C_{f} = \ 1.14554 \ M[/tex]

Since the given values only have 3 significant figures, the final answer must be expressed with 3 significant figures as well.

Therefore,

[tex]\boxed {C_{f}\ =  \ 1.15 \ M}[/tex]

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Keywords: rate law, second order, integrated rate law

What is the charge of the nucleus in an atom of oxygen-17

Answers

Answer:

8 proton and 9 neutron.

Explanation:

there are 17 total of protons and neutron

Taking into account the constitution of an atom and the definition of atomic number, the charge of the nucleus in an atom of oxygen-17 is +8.

All atoms are made up of subatomic particles: protons and neutrons, which are part of their nucleus, and electrons, which revolve around them. Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged (electrons).

In other words, the atomic nucleus is the central part of the atom that is made up of protons and neutrons, while the orbitals or peripheral region is an area where electrons are found.

The neutron is an electrically neutral subatomic particle, while the proton has a positive electrical charge. Electrons have a negative charge, move around the nucleus at different energy levels and are attracted to protons, positive in the atom through electromagnetic force.

Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z.

The periodic table is an arrangement in which chemical elements are arranged by increasing atomic number.

In the periodic table you can see that oxygen has an atomic number of 8. This indicates that in the nucleus of this atom there are 8 protons. Like neutrons, another particle found in the nucleus, has a neutral charge, and protons have a positive charge, the oxygen nucleus has a charge of +8.

In summary, the charge of the nucleus in an atom of oxygen-17 is +8.

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A compound has a percent composition of 54.5% carbon, 9.3% hydrogen and 36.2 % oxygen.If its molar mass is 88 g/mol, what is its molecular formula?

Complete the following:

Answers

Answer:

C₄H₈O₂.

Explanation:

Firstly, we can calculate the no. of moles (n) of each component using the relation:

n = mass/atomic mass,

mol C = mass/(atomic mass) = (54.5 g)/(12.0 g/mol) = 4.54 mol.

mol H = mass/(atomic mass) = (9.3 g)/(1.0 g/mol) = 9.3 mol.

mol O = mass/(atomic mass) = (36.2 g)/(16.0 g/mol) = 2.26 mol.

To get the empirical formula, we divide by the lowest no. of moles (2.26 mol) of O:

∴ C: H: O = (4.54 mol/2.26 mol) : (9.3 mol/2.26 mol) : (2.26 mol/2.26 mol) = 2: 4: 1.

∴ Empirical formula mass of (C₂H₄O) = 2(atomic mass of C) + 4(atomic mass of H) + 1(atomic mass of O) = 2(12.0 g/mol) + 4(1.0 g/mol) + (16.0 g/mol) = 44.0 g/mol.

∴ Number of times empirical mass goes into molecular mass = (88.0 g/mol)/(44.0 g/mol) = 2.0 times.

∴ The molecular formula is, 2(C₂H₄O), that is; (C₄H₈O₂)

The table shows the relationship between the masses of two objects, the distance between the two objects, and the gravitational force between the objects. Which conclusion is supported by the data in the table? An increase in the mass of an object causes the same decrease in the gravitational force. An increase in the distance between the objects causes the same decrease in the gravitational force. An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass. An increase in the mass causes a greater change in the gravitational force than the same increase in the distance between the objects.

Answers

Answer:

An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass.

F= G^m1m2/r^2

G is universal constant m₁ and m₂ are the masses and r is the distance between them

the gravitational force is directly proportional to the product of masses and indirectly proportional to the square of the distance between them.

Focus on the top part if you do not understand. That is the correct answer

Answer:

An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass.

Explanation:

You are performing an experiment in your lab. To compare with other experiments you need your results to be in moles. During your final step you collect your product and weigh it. You have 600 grams of Mg(H2PO4)2 (magnesium dihydrogen phosphate). How should you enter your results?

Answers

To be able to compare the result with other experiments it has to be reported in moles.

number of moles = mass / molecular weight

number of moles of Mg(H₂PO₄)₂ = 600 / 218 = 2.75 moles

Answer: 2.75 moles of magnesium dihydrogen phosphate

Explanation:   We have been given 600 gm of Mg(H2PO4)2 .

The molecular mass of Mg(H2PO4)2 is 218 gm.

As it is given that the answer should be in moles so that it can become comparable with other experiments, thus number of moles can be calculated by dividing the given mass by molecular mass of the given salt.

number of moles (n) = given mass(m) / molecular mass of the salt (M)

n= 600 gm  / 218 gm = 2.75

Thus 2.75 moles of magnesium dihydrogen phosphate(Mg(H2PO4)2) will be recorded.

Standard temperature is exactly
a. 100ºC. b. 273ºC. c. 0ºC. d. 0 K.

Answers

Answer:

  c.  0 °C

Explanation:

Standard temperature is 273.15 K, or 0 °C, or 32 °F, as defined by the International Union of Pure and Applied Chemistry (IUPAC) in 1982.

Answer:

Standard temperature is exactly (C) 0ºC

Explanation:

STP means standard temperature pressure at which

T = 0℃ or 273K and Pressure = 1 atm

NTP means Normal temperature pressure which means room temperature and  pressure at which

T = 20℃ or 293 K and Pressure = 1 atm

SATP means standard Ambient temperature pressure at which

T = 25℃ or 298K and P = 1atm

In tropical countries, the climate will be warm and hence room temperature usually  considered as

T = 25℃ or 298K and P = 1 atm  

Lab temperature is same as that of room temperature.

The accepted value is 1.43. Which correctly describes this student’s experimental data?

TrialMeasurement11.2921.9330.88

Question 17 options:

accurate but not precise

precise but not accurate

both accurate and precise

neither accurate nor precise​

Answers

Answer:

Neither accurate nor precise

Explanation:

The values were not near or even the same as the accepted value thus making it neither accurate nor precise.

Answer: neither accurate nor precise​

Explanation:

Accuracy is defined as how close the measured value is to a standard value. For example if the given volume of water is 20 ml and the two measured values are 19 ml and 18 ml then the former measured value is more accurate than the later.  

Precision is defined as how measured values are close to each other. For example, if the length of the wire of 10 m. If the first person measures the length of the same wire thrice and got values 9.7, 9.8 and 9.75 m whereas the second person got values 9.5 , 9.6 and 9.8. In such a case the first person’s measured value is more precise.

Thus as the accepted value is 1.43 and measured values are 1.29 , 1.93 and 0.88 , the experimental data is neither accurate nor precise.

The decomposition of N2O5 can be described by the equation.


2N2O5 (soln) ---> 4NO2 (soln) + 2 (g)

Given this data for the reaction at 45 degrees C in carbon tetrachloride solution, calculate the average rate for each successive time interval.

t(s) [N2O5] (M)


0 2.10

195 1.86

556 1.48

825 1.25

Interval: 0 s to 195 s

Reaction rate= _____M/s

195 s to 556 s

Reaction rate= _____M/s

556 s to 825 s

Reaction rate= _____M/s

Answers

Final answer:

The average rate of decomposition of N2O5 over each time interval was calculated using changes in concentration over time, resulting in rates of 0.00123 M/s, 0.00105 M/s, and 0.00085 M/s for the respective intervals of 0-195 s, 195-556 s, and 556-825 s.

Explanation:

The average rate of a reaction is calculated by the change in concentration of a reactant or a product over a certain time period. For the decomposition of N2O5, the average rate over each time interval can be found using the formula: rate = -(Δ[N2O5])/(Δt), where Δ represents the change in concentration or time.

For the interval from 0 s to 195 s, the average rate is:
rate = - (1.86 M - 2.10 M) / (195 s - 0 s) = - (-0.24 M) / 195 s = 0.00123 M/s

For the interval from 195 s to 556 s, the average rate is:
rate = - (1.48 M - 1.86 M) / (556 s - 195 s) = - (-0.38 M) / 361 s = 0.00105 M/s

For the interval from 556 s to 825 s, the average rate is:
rate = - (1.25 M - 1.48 M) / (825 s - 556 s) = - (-0.23 M) / 269 s = 0.00085 M/s

For the first five steps of glycolysis, the appropriate sequence of enzymes is: A. phosphofructokinase-1 (PFK-1). B. hexokinase / glucokinase. C. fructose bisphosphate aldolase. D. Phosphoglucoisomerase. E. triose phosphate isomerase (TPI). a. B, D, C, A, E b. D, B, A, C, E c. B, D, E, C, A d. B, C, D, E, A e. A, C, B, E, D

Answers

Answer:

B,D,A,C,E

Explanation:

The first five steps of glycolysis are explained below:

Step -1 :The food we eat contains glucose which is converted to glucose-6-phosphate in the presence of enzyme hexokinase/ glucokinase. One ATP molecule is consumed in this step.

Step-2: Glucose-6- phosphate is converted to fructose-6- phosphate by the action of enzyme Phosphoglucose isomerase.

Step-3: Fructose-6- phosphate is converted to fructose-1,6-biphosphate in the presence of enzyme phosphofructokinase-1 (PFK-1) . One more ATP molecule is consumed in this step.

Step-4: Fructose 1,6-bisphosphate in the presence of fructose-bisphosphate aldolase is converted to D-glyceraldehyde 3-phosphate (GADP) and dihydroxyacetone phosphate (DHAP)

Step-5: Dihydroxyacetone phosphate (DHAP) in the presence of triosephosphate isomerase (TPI)  is converted to D-glyceraldehyde 3-phosphate (GADP).

Hence, the order it follows is:

B. hexokinase / glucokinase

D. Phosphoglucoisomerase

A. Phosphofructokinase-1 (PFK-1)

C. fructose bisphosphate aldolase

E. triose phosphate isomerase (TPI)

The trend is : B,D,A,C,E

Final answer:

The correct sequence of enzymes for the first five steps of glycolysis is: hexokinase/glucokinase, phosphoglucoisomerase, phosphofructokinase-1, fructose bisphosphate aldolase, and triose phosphate isomerase. This corresponds to answer choice B, D, A, C, E.

Explanation:

In the first step of glycolysis, hexokinase/glucokinase (B) phosphorylates glucose to produce glucose-6-phosphate. This molecule is then converted into fructose-6-phosphate by the enzyme phosphoglucoisomerase (D). The enzyme phosphofructokinase-1 (A) then phosphorylates fructose-6-phosphate to create fructose-1,6-bisphosphate. Fructose bisphosphate aldolase (C) breaks down fructose-1,6-bisphosphate into two three-carbon molecules: glyceraldehyde-3-phosphate and dihydroxyacetone phosphate. Lastly, triose phosphate isomerase (E) converts dihydroxyacetone phosphate into a second glyceraldehyde-3-phosphate molecule.

So the correct order of the enzymes for the first five steps of glycolysis is: hexokinase/glucokinase, phosphoglucoisomerase, phosphofructokinase-1, fructose bisphosphate aldolase, and triose phosphate isomerase. This corresponds to the answer choice B, D, A, C, E.

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Suppose you calibrate a thermistor by inserting it first in ice water, then in boiling water. In ice water, the thermistor reads -45 mV and in boiling water it reads 204 mV. Next you measure the temperature of an unknown sample and read 116 mV. What is the temperature in C°?

Answers

Answer: The temperature of the unknown sample is 64.65 °C

Explanation:

To calculate the temperature of the unknown sample, we use the following equation:

[tex]T=\frac{(V-V_1)}{(V_2-V_1)}\times (T_2-T_1)+T_1[/tex]

where,

T = temperature of the unknown sample = ?

V = thermistor reading of the unknown sample = 116 mV

[tex]T_1[/tex] = melting point of ice = 0°C

[tex]V_1[/tex] = thermistor reading of ice = -45 mV

[tex]T_1[/tex] = boiling point of water = 100°C

[tex]V_1[/tex] = thermistor reading of water = 204 mV

Putting values in above equation, we get:

[tex]T=\frac{(116-(-45))}{(204-(-45))}\times (100-0)+0\\\\T=64.65^oC[/tex]

Hence, the temperature of the unknown sample is 64.65 °C

The temperature of the unknown sample in C° is approximately 45.00°C.

To find the temperature of the unknown sample, we first need to establish a relationship between the voltage read by the thermistor and the temperature in degrees Celsius. We have two calibration points: ice water and boiling water, which correspond to 0°C and 100°C, respectively.

Let's denote the voltage read by the thermistor as \( V \) and the temperature as \( T \). We can then set up two equations based on the calibration points:

1. For ice water (0°C), the thermistor reads -45 mV:

[tex]\[ V_{ice} = -45 \text{ mV} \] \[ T_{ice} = 0°C \][/tex]

2. For boiling water (100°C), the thermistor reads 204 mV:

[tex]\[ V_{boiling} = 204 \text{ mV} \] \[ T_{boiling} = 100°C \][/tex]

We can assume a linear relationship between voltage and temperature for the thermistor, which allows us to use a simple linear interpolation formula:

[tex]\[ T = T_{ice} + \frac{(V - V_{ice}) \times (T_{boiling} - T_{ice})}{V_{boiling} - V_{ice}} \][/tex]

Now, we need to find the temperature \( T \) when the thermistor reads 116 mV for the unknown sample:

[tex]\[ T = 0°C + \frac{(116 \text{ mV} - (-45 \text{ mV})) \times (100°C - 0°C)}{204 \text{ mV} - (-45 \text{ mV})} \] \[ T = 0°C + \frac{(116 \text{ mV} + 45 \text{ mV}) \times 100°C}{204 \text{ mV} + 45 \text{ mV}} \] \[ T = 0°C + \frac{161 \text{ mV} \times 100°C}{249 \text{ mV}} \] \[ T = 0°C + \frac{161}{2.49} \times 100°C \] \[ T = 0°C + 64.6586345 \times 100°C \] \[ T = 64.6586345°C \][/tex]

Rounding to two decimal places, the temperature of the unknown sample is approximately 45.00°C.

Which of the following have their valence electrons in the same shell? Which of the following have their valence electrons in the same shell? N, As, Bi He, Ne, F B, Si, As Li, N, F

Answers

Answer:

N, Ne, F, B, Li

Explanation:

Valence electrons are the electrons that are found in the outermost shell in a neutral atom. These five elements are the only one whose valence electrons fall on the same shell. The second shell. Their electronic configurations are as follows:

N: 2,5

Ne:2,8

F:2,7

B:2,5

Li: 2,3

Final answer:

The elements in each of these sets: Nitrogen (N), Arsenic (As), Bismuth (Bi) and Boron (B), Silicon (Si), Arsenic (As) belong to the same group hence their valence electrons are in the same shell. Elements Helium (He), Neon (Ne), Fluorine (F) and Lithium (Li), Nitrogen (N), Fluorine (F) don't belong to the same period, therefore, their valence electrons are not in the same shell.

Explanation:

Looking at the given elements, we can determine which groups have their valence electrons in the same shell by referring to the periodic table. Elements on the same period (row) have their valence electrons in the same shell. Here, the elements are:

Nitrogen (N), Arsenic (As), Bismuth (Bi) belong to group 15 (VA), and hence have valence electrons in the same shell.

Helium (He), Neon (Ne), Fluorine (F) do not belong to the same period and hence their valence electrons are not in the same shell.

Boron (B), Silicon (Si), Arsenic (As) belong to group 13 (IIIA), hence, their valence electrons are present in the same shell.

Lithium (Li), Nitrogen (N), Fluorine (F) do not belong to the same period and hence their valence electrons are not in the same shell.

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Nickel can be planted from aqueous solution according to the following half reaction. How long would it take (in min) to plate 29.6 g of nickel at 4.7 A?

Answers

Using Faraday's laws of electrolysis, it takes approximately 344.91 minutes to electroplate 29.6 grams of nickel using a current of 4.7 A.

The student is asking how long it would take to electroplate 29.6 grams of nickel using a current of 4.7 amps. To calculate the time required for electroplating, we'll use Faraday's laws of electrolysis, which relate the chemical amount of substance produced at an electrode to the amount of electricity used.

The half-reaction for nickel plating is [tex]Ni^{+2}[/tex] + 2e-
ightarrow Ni(s) and the molar mass of nickel is approximately 58.69 g/mol. Nickel has a valency of 2, which means it requires 2 moles of electrons (2 Faradays) to deposit one mole of nickel. Based on Faraday's law, the charge (Q) in coulombs required to deposit a substance is Q = n x F, where n is the number of moles and F is Faraday's constant (96485 C/mol).


First, we need to convert the mass of nickel to moles using the molar mass: 29.6 g / 58.69 g/mol
gives approximately 0.504 moles of Ni. Thus, the total charge needed will be 0.504 moles x 2 x 96485 C/mol, which equals 97262.2 C.

Next, we find how long it takes for this charge to pass through the solution using the current (I) given: Time (t) = Q / I, where
t = time in seconds. So, t = 97262.2 C / 4.7 A
gives approximately 20694.51 seconds. Converting that to minutes, we divide by 60, resulting in about 344.91 minutes.

Which of the following questions could most likely be answered using molecular clocks? (2 points) Which species of beetles are most closely related? How many species of beetles existed in the past? What processes cause beetles to become extinct? How long have beetles existed on Earth?

Answers

Answer:

Which species of beetles are most closely related.

Explanation:

Molecular clocks are often used to determine where species diverge. This helps scientists determine the different mutations that had occurred to cause the separation of species. It can help find common ancestors within different species, so it can also determine how closely related species are.

Answer:

Which species of beetles are most closely related.

Explanation:

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