Final answer:
Removing the lid from a separatory funnel after extraction allows air to enter, replaces the displaced liquid to avoid negative pressure, releases built-up pressure for safety, and prevents re-mixing of the layers for a cleaner separation.
Explanation:
There are several reasons why it is a good idea to remove the lid from the separatory funnel after each extraction. Firstly, removing the stopper allows air to enter and replace the displaced liquid, preventing the formation of negative pressure inside the funnel, which could hinder the proper drainage of liquids. Secondly, when solutions are mixed, pressure may build up inside the separatory funnel, and venting by opening the stopcock releases this pressure, making the process safer and preventing potential hazards. Lastly, keeping the funnel open minimizes the risk of re-mixing the layers as each layer can be separated cleanly without the liquid touching the stem of the funnel if the layers are undisturbed.
A boy is pushing on a heavy door, trying to slide it open. His friend stands behind him and helps him push.
How have the forces changed?
A.
The net force applied will increase.
B.
The net force will decrease.
C.
There will be less friction.
D.
The applied force will not change.
_________ is amount of “ground” an object moves from its starting point and __________ is how much “ground” and object covers in total.
The melting of ice cream is an example of which of the following?
Chemical change
Chemical property
Physical change
Physical property
Answer:
Answer is physical change
Explanation:
I took the test and got the answer right
Why aren't any of the pictures a good representation of hc2h3o2(aq)?
The question involves a chemistry concept (HC2H3O2(aq)), which signifies acetic acid in a water solution. Pictures have a difficult time representing the molecular dynamics of such concept.
Explanation:HC2H3O2(aq) refers to a solution of acetic acid in water. This is a chemical concept, and any graphical representation or picture would typically have difficulty capturing the molecular level of the substances involved. If we were to attempt a representation, it would involve a model of the acetic acid molecule (C2H4O2) in a water environment, but details like the hydrogen bonding or ionization process would be very complex to show. Therefore, it's hard for pictures to accurately portray this concept.
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The compound HC2H3O2 is an aqueous solution of acetic acid, which makes it difficult to graphically depict because it involves several atoms and is not in a pure form but rather mixed with water. Chemical equations or molecular structures are preferred to accurately portray these kinds of scenarios.
Explanation:The compound HC2H3O2 represents an aqueous (water based) solution of acetic acid. It's difficult to accurately portray acetic acid in an image because it's a molecular structure involving numerous atoms and the 'aqueous' notation ('aq') signifies that it's dissolved in water.
An important concept to understand is that HC2H3O2(aq) specifies that the acetic acid is not in its pure form, but rather mixed with water or another solvent. This would be very difficult to express visually without showing individual molecules and their arrangements within the solution, which is not usually feasible in simple diagrams. Instead, chemical equations or molecular structures are used to accurately depict these scenarios.
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Why does manganese, atomic number 25, have a less favorable e ea than its neighbors on either side?
Manganese has a lower electron affinity (EA) compared to its neighbours due to its half-filled d-orbitals. The symmetrical electron distribution in half-filled and fully-filled orbitals have higher stability, hence adding an electron to them is less favorable.
Explanation:The electron affinity (EA) of an atom is the energy change when an electron is added to a neutral atom to form a negative ion. Manganese, with an atomic number of 25, is located in the middle of the transition metals in the periodic table. In general, elements in the middle of transition series like manganese have a less favorable EA compared to their neighbours. This is because of the half-filled d-orbitals in these elements. For manganese, the electron configuration ends with 3d5 4s2, indicating a half-filled d-subshell.
It's widely recognized that half-filled and fully-filled orbitals have higher stability due to their symmetrical electron distribution. As a result, adding an electron to a half-filled orbital is less favorable, resulting in a lower EA for manganese compared to its neighbours.
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Manganese has a less favorable electron affinity than its neighbors due to its electron configuration and atomic radius.
Explanation:Manganese (atomic number 25) has a less favorable electron affinity (ea) than its neighbors on either side due to its electron configuration and atomic radius. Manganese has an electron configuration of [Ar]3d54s2, which means it has one less electron than its neighbors.
The atomic radius of manganese is larger than its neighbors, which makes it more difficult for the nucleus to attract additional electrons. This results in a less favorable electron affinity.
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Use the given molar solubilities in pure water to calculate ksp for each compound. part a bacro4; molar solubility =1.08×10−5m
To calculate the Ksp for barium chromate (BaCrO₄), we use the given molar solubility of 1.08 × 10⁻⁵ M. The equilibrium concentrations of the ions are equal to the molar solubility, and the Ksp is calculated as (1.08 × 10⁻⁵)², resulting in 1.1664 × 10⁻¹⁰
To determine the solubility product constant (Ksp) for barium chromate (BaCrO₄), we need to use the given molar solubility in pure water, which is 1.08 × 10⁻⁵ M.
The dissociation equation for BaCrO₄ in water is: BaCrO₄ (s) ⇌ Ba²⁺ (aq) + CrO₄²⁻(aq)At equilibrium, the concentration of Ba²⁺ ions is equal to the molar solubility, s, and the concentration of CrO₄²⁻ ions is also s.
Thus, the Ksp expression is given by: Ksp = [Ba²⁺][CrO₄²⁻] = s × s = s²Plugging in the given molar solubility:
Ksp = (1.08 × 10−5)²Ksp = 1.1664 × 10⁻¹⁰Therefore, the solubility product constant (Ksp) for barium chromate (BaCrO₄) is 1.1664 × 10⁻¹⁰
Correct question is: Use the molar solubility 1.08×10⁻⁵M in pure water to calculate Ksp for BaCrO₄
A radioactive nuclide that is used for geological dating has an atomic number of 19 and mass number 40. Which is the symbol of this nuclide?
Answer:
C. 40/19 K
Explanation:
What are the best techniques to remove the insoluble binder/filler materials from hcl - treated calcilum enriched tablet?
A compound with the empirical formula SiH3 was found to have a molar mass of approximately 62 g. What is the molecular formula of the compound?
The molecular formula of a compound with the empirical formula SiH3 and a molar mass of 62 g is Si2H6.
Explanation:The subject of the question is the molecular formula of the compound with the empirical formula SiH3 and a molar mass of 62 g. The empirical formula mass of this compound can be calculated from its components: Si stands for silicon, with an atomic mass of roughly 28 g/mol, and H stands for hydrogen, with an atomic mass of roughly 1 g/mol. So the total atomic mass of SiH3 would be 31 g/mol. Comparing this with the given molar mass of 62 g/mol, we can deduce that the molecule contains two empirical formula units. Therefore, the molecular formula should be Si2H6.
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Determine the number of atoms in a 48.3-g sample of zinc. express your answer in zinc atoms using scientific notation.
Explain how a chemist would use the difference method in measuring the mass of a liquid
A chemist would use the difference method to measure the mass of a liquid by weighing an empty container and then the container with the liquid, and subtracting the two measurements.
Explanation:A chemist would use the difference method to measure the mass of a liquid by first weighing an empty container, such as a beaker or flask. Then, the liquid is added to the container and the combined mass of the container and liquid is measured. The difference in mass between the two measurements represents the mass of the liquid.
For example, if an empty beaker weighs 50 grams and the beaker with the liquid weighs 75 grams, then the mass of the liquid would be 25 grams (75 grams - 50 grams).
2NH4Cl(s)+Ba(OH)2⋅8H2O(s)→2NH3(aq)+BaCl2(aq)+10H2O(l) The ΔH for this reaction is 54.8 kJ . How much energy would be absorbed if 24.7 g of NH4Cl reacts?
The amount of energy absorbed when 24.7 g of NH4Cl reacts according to the given balanced equation is 12.6 kJ.
Explanation:To calculate the amount of energy absorbed when 24.7g of NH4Cl reacts, we need to first convert grams to moles. The molar mass of NH4Cl is 53.49 grams/mole, therefore, 24.7g of NH4Cl in moles is (24.7 / 53.49) = 0.462 mol.
The given balanced equation tells us that 54.8 kJ of energy is absorbed during the reaction of 2 moles of NH4Cl with Ba(OH)2·8H2O, so the amount of energy absorbed when 0.462 mol react is (0.462/2) * 54.8 kJ = 12.6 kJ.
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The energy absorbed is 25.2 kJ.
Given ΔH = 54.8 kJ, determine the moles of NH₄Cl from 24.7 g, then use stoichiometry to find the energy absorbed.
Calculation: 24.7 g NH₄Cl (molar mass 53.49 g/mol) = 0.46 mol NH₄Cl. Energy absorbed = 54.8 kJ/mol * 0.46 mol = 25.2 kJ.
What is the mass of 3.00 moles of magnesium chloride, MgCl2? Express your answer with the appropriate units.
The mass of 3.00 moles of magnesium chloride (MgCl2) is calculated by multiplying the number of moles by the molar mass of MgCl2, giving a result of 285.63 grams.
Explanation:To calculate the mass of 3.00 moles of magnesium chloride (MgCl2), we will use the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 grams per mole. Therefore, to find the mass, multiply the number of moles by the molar mass:
Mass = moles × molar mass
Mass = 3.00 moles × 95.21 g/mol = 285.63 grams of MgCl2
The mass of 3.00 moles of magnesium chloride is thus 285.63 grams.
Consider the hydrocarbon below.
What is the name of this hydrocarbon?
1-ethyne
1-pentyne
1-ethane
1-butyne
Answer: Option (b) is the correct answer.
Explanation:
The given hydrocarbon has five carbon atoms. Also, there is a triple bond at the extreme right end, therefore it is an alkyne.
Since there is only a triple bond in the give hydrocarbon chain. So, numbering will be started from extreme right end in order to give least number to the triple bond.
Hence, name of the given hydrocarbon is 1-pentyne.
What are the three most abundant elements found on the earths crust that combine to form minerals?
A. Silicon, Iron, Aluminum
B. Oxygen, Silicon, Aluminum
C. Iron, Aluminum, Magnesium
D. Oxygen, Silicon, Iron
Answer:
B. Oxygen, Silicon, Aluminum is the correct answer.
Explanation:
The three most abundant elements found on the earths crust that combine to form minerals are Oxygen, Silicon, Aluminum.
oxygen is the first most abundant element found in the earth's crust, it is present in the main compound of silicate minerals that combines to produce minerals.
The second most abundant element present in the earth's crust is silicon.It combines with oxygen to make silicate minerals.
The third abundant element is aluminum in the earth's crust. The rich compounds of Aluminum contain potassium aluminum sulfate, aluminum hydroxide, and aluminum oxide.
Which of the following is an example of a conversion from electrical energy to sound energy? microphone radio generator windmill
Answer:
radios
Explanation:
do free electrons exist under normal conditions
The image formed by a lens may be real or virtual. The image formed by a lens is always virtual.
The image formed by a lens can be either real or virtual, depending on the position of the object relative to the lens and the type of lens used. Real images are formed when light rays converge at a point after passing through the lens, while virtual images are formed when the extended light rays appear to diverge from a point behind the lens.
The statement is not accurate. The image formed by a lens can be either real or virtual, depending on the position of the object relative to the lens and the type of lens used.
Real Image: A real image is formed when light rays converge at a point after passing through the lens. This image can be captured on a screen because the light rays converge at a specific location. Real images are formed by convex lenses when the object is placed beyond the focal point and by concave lenses when the object is placed within the focal point.Virtual Image: A virtual image is formed when the extended light rays appear to diverge from a point behind the lens. This image cannot be captured on a screen because the light rays only appear to converge when extended backward. Virtual images are typically formed by convex lenses when the object is placed within the focal point and by concave lenses when the object is placed beyond the focal point.So, the statement that the image formed by a lens is always virtual is incorrect. The nature of the image (real or virtual) depends on the specific conditions and the type of lens used.
Answer:
Convex and Concave
Explanation:
Took Test
Look at the diagram of an electrochemical cell below.
(picture below)
Which part of the cell is the anode?
Na+
SO42-
nickel electrode
platinum electrode
What is the molarity of a naoh solution if 11.9 ml of a 0.220 m h2so4 solution is required to neutralize a 25.0-ml sample of the naoh solution?
Answer : The concentration of the [tex]NaOH[/tex] is, 0.209 M
Explanation :
Using neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1[/tex] = basicity of an acid [tex]H_2SO_4[/tex] = 2
[tex]n_2[/tex] = acidity of a base (NaOH) = 1
[tex]M_1[/tex] = concentration or molarity of [tex]H_2SO_4[/tex] = 0.220 M
[tex]M_2[/tex] = concentration or molarity of NaOH = ?
[tex]V_1[/tex] = volume of [tex]H_2SO_4[/tex] = 11.9 ml
[tex]V_2[/tex] = volume of NaOH = 25.0 ml
Now put all the given values in the above law, we get the concentration of the [tex]NaOH[/tex].
[tex]2\times 0.220M\times 11.9ml=1\times M_2\times 25.0ml[/tex]
[tex]M_2=0.209M[/tex]
Therefore, the concentration of the [tex]NaOH[/tex] is, 0.209 M
Is there a relationship between the range of accessible oxidation states and sulfur's position on the periodic table?
Classify these compounds as strong electrolytes, weak electrolytes, or nonelectrolytes k3po4
According to solubility, potassium phosphate is weak electrolyte.
Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.
The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.
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H3c6h5o7(aq) + 3nahco3(aq) → 3co2(g) + 3h2o(l) + na3c6h5o7(aq) calculate the number of grams of baking soda (nahco3; molar mass 84.00661 g/mol) that will react with 30.0 ml of 1 m citric acid.
Final answer:
7.560595 grams of baking soda are required to react with 30.0 mL of 1 M citric acid, calculated using the stoichiometry of the reaction where 1 mole of citric acid reacts with 3 moles of baking soda.
Explanation:
To calculate the number of grams of baking soda (NaHCO3) that will react with 30.0 mL of 1 M citric acid (H3C6H5O7), we first use the balanced chemical equation:
H3C6H5O7(aq) + 3NaHCO3(aq) → 3CO2(g) + 3H2O(l) + Na3C6H5O7(aq)
From the equation, 1 mole of citric acid reacts with 3 moles of baking soda. Since we have 30.0 mL of a 1 M solution of citric acid, which is equivalent to 0.030 liters, the number of moles of citric acid is 0.030 moles (1 M × 0.030 L).
Knowing the moles of citric acid, we can find the moles of baking soda needed:
0.030 moles H3C6H5O7 × (3 moles NaHCO3 / 1 mole H3C6H5O7) = 0.090 moles NaHCO3To find the mass of 0.090 moles of baking soda:
Mass = moles × molar massMass = 0.090 moles × 84.00661 g/mol = 7.560595 gTherefore, 7.560595 grams of baking soda are required to react with 30.0 mL of 1 M citric acid.
If 2.4 g of n2 gas has a volume of 0.40 l and a pressure of 6.6 atm , what is its kelvin temperature?
To solve for the absolute temperature, we assume ideal gas behaviour so that we use the equation:
PV = nRT
or T = PV / nR
So calculating:
T = [6.6 atm * 0.40 L] / [(2.4g / 28g/mol) * 0.08205746 L atm / mol K]
T = 375.35 K
If an organism reproduces quickly, its population can ________ faster.
Answer:
EVOLVE_
Explanation:
If an organism reproduces quickly, its population can ___EVOLVE_____ faster.
Evolution and Reproduction go hand in hand. The more the reproduction the better will be evolution.
- Reproduction causes genetic variation in the off spring
-The species can adopt to new environment due to variation in the genes.
-Offsprings are less prone to diseases.
-therefore, more survival advantage.
How many moles of gas were added to a balloon that started with 2.3 moles of gas and a volume of 1.4 l given that the final volume was 7.2 l?
a.12
b.0.085
c.4.4
d.9.5
e.none of the above?
The number of moles of gas were added to a balloon that started with 2.3 moles of gas and a volume increases from 1.4L to 7.2L is 11.82 moles.
How do we calculate moles?Number of moles of any gas will be calculated by uisng the ideal gas equation PV = nRT, for the given question equation becomes as:
V₁/n₁ = V₂/n₂, where
V₁ = initial volume = 1.4L
n₁ = initial moles = 2.3mol
V₂ = final volume = 7.2L
n₂ = final moles = ?
On putting values, we get
n₂ = (7.2)(2.3) / (1.4) = 11.82 moles
Hence required moles of gas is 11.82 mol.
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For the element barium, which wavelength of light is produced by the largest drop in energy for an electron? Which represents the smallest drop? Explain.
Answer:
The wavelength decreases in the order:
Red, orange, yellow, green, blue, indigo, violet
Because a larger transition in electron state releases a larger amount of energy, it will produce light of lower wavelength. Conversely, a smaller change in energy will release light with a higher wavelength.
Explanation:
Got this question incorrect and no matter how hard I try I can't figure it out!
Aqueous aluminum bromide and solid zinc are formed by the reaction of aqueous zinc bromide and solid aluminum . write a balanced chemical equation for this reaction.
The balanced chemical equation for the reaction between solid aluminium and aqueous zinc bromide to produce aqueous aluminium bromide and solid zinc is 3 ZnBr₂(aq) + 2 Al(s) → 2 AlBr₃(aq) + 3 Zn(s).
Explanation:The student's question involves a single-replacement reaction where aluminium (Al) displaces zinc (Zn) in a compound, specifically in zinc bromide (ZnBr₂), resulting in aluminium bromide (AlBr₃) and solid zinc (Zn). The balanced chemical equation for this reaction is:
3 ZnBr₂(aq) + 2 Al(s) → 2 AlBr₃(aq) + 3 Zn(s)
Solid aluminium reacts with aqueous zinc bromide in this equation, and the products formed are aqueous aluminium bromide and solid zinc. It is important to use the correct formulas for the reactants and products and to balance the equation according to the law of conservation of mass.
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Will ag2so4 precipitate when 100 ml of 5.0×10−2 m agno3 is mixed with 10 ml of 5.0×10−2mna2so4 solution?
Silver sulfate (Ag₂SO₄) does not precipitate when 100 mL of 5.0×10⁻² M AgNO3 is mixed with 10 mL of 5.0×10⁻² M Na₂SO₄ because the reaction quotient is less than the solubility product constant.
Precipitation of Ag₂SO₄ When Mixing Solutions:
To determine if silver sulfate (Ag₂SO₄) will precipitate when mixing 100 mL of 5.0×10⁻² M AgNO₃ with 10 mL of 5.0×10⁻² M Na₂SO₄, we need to calculate the concentrations of Ag⁺ and SO₄ ²⁻ ions after mixing.
First, calculate the moles of each ion:
Ag⁺: 0.1 L × 5.0×10⁻² M = 5.0×10⁻³ molesSO₄²⁻: 0.01 L × 5.0×10⁻² M = 5.0×10⁻⁴ molesWhen mixed, the total volume is 110 mL (0.110 L), so the new concentrations are:
[Ag⁺] = 5.0×10⁻³ moles / 0.110 L ≈ 4.55×10⁻² M[SO₄²⁻] = 5.0×10⁻⁴ moles / 0.110 L ≈ 4.55×10⁻³ MThe solubility product (Ksp) of Ag₂SO₄ is 1.2×10⁻⁵. To check for precipitation:
Q = [Ag⁺]² [SO₄²⁻] ≈ (4.55×10⁻²)² × 4.55×10⁻³ = 9.45×10⁻⁷
Since Q < Ksp (9.45×10⁻⁷ < 1.2×10⁻⁵), Ag₂SO₄ does not precipitate.