What would the potential of a standard hydrogen electrode (s.h.e.) be under the given conditions? [h+]=0.70 mph2=2.4 atmt=298 k?

Answers

Answer 1
Constant = 8.314JK⁻¹mol⁻¹
T is for temperature which is 298K
Faraday constant value is 96500C/mol
n is the number of electrons which are transferred in the reaction.
Ecell = E₀cell - RT/nFiN [cathode]/[anode]
Ecell = E₀cell - RT/nF In [PH₂]/[H⁺]²
Ecell = 0.00-8.314 JK⁻¹ mol⁻¹ × 298k/ 2× 96500C/mol In [2.4atm]/ 0.70]²
Ecell = 0.00 - 0.0129 In (2.59)
Ecell = 0.00 - 0.0129 × 0.951
Ecell = -0.0122V
∴Ecell is = -o.0122v

Related Questions

Rebekah finds that a solution of sugar in water has a volume of 1.32 fl. oz. How should she report this amount using the metric system? (1 fl. oz. = 29.6 mL)

Answers

its D i just finished the test

39.1 mL is correct answer

How long can the body maintain an anaerobic burst of energy

Answers

The body can maintain anaerobic burst energy takes thirty seconds to around two minutes.
We have aerobic energy and anaerobic energy. Aerobic energy is used when there is a lot of intake of oxygen into the body. While anaerobic lacks oxygen to the body for example short sprint.
Aerobic respiration is being utilized in the body whenever oxygen cannot be delivered to the muscle when contraction in needed.

Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 9.0 m whose uniform depth is 1.9 m . express your answer using two significant figures.

Answers

The relative pressure at the bottom of a column of fluid is given by
[tex]p_r = \rho g h[/tex]
where
[tex]\rho[/tex] is the fluid density
g is the gravitational acceleration 
h is the height of the column of fluid

At the bottom of the swimming pool, h=1.9 m, and the water density is 
[tex]\rho = 1000 kg/m^3[/tex], therefore the relative pressure is
[tex]p_r = (1000 kg/m^3)(9.81 m/s^2)(1.9 m)=1.86 \cdot 10^4 Pa[/tex]

To find the absolute pressure, we must add to this the atmospheric pressure, [tex]p_a[/tex]:
[tex]p= p_r + p_a= 1.86 \cdot 10^4 Pa + 1.01 \cdot 10^5 Pa =1.2 \cdot 10^5 Pa[/tex]

Blow up a balloon and rub it against your shirt a number of times. In doing so you give the balloon a net electric charge. Now touch the balloon to the ceiling. On being released, the balloon will remain stuck to the ceiling. Why?

Answers

Balloons are blown up, and then rubbed against your shirt many times. The balloon then touches the ceiling. When released, the balloon remains stuck to the ceiling. The balloon is charged by contact. The ceiling has a neutral charge. The charged balloon induces a slight surface charge on the ceiling opposite to the charge on the balloon. Balloon and ceiling electric charges are opposite in sign, so they will attract each other. Since both the balloon and the ceiling are insulators, charge can not flow from one to the other. The charge on the balloon is fixed on the balloon and the charge on the ceiling remains fixed to the ceiling. It just so happens that the electrostatic force the ceiling exerts on the balloon is sufficient to hold the balloon in place (i.e. overcomes gravity, etc.).

Final answer:

When you rub a balloon against your shirt, electrons are transferred from your shirt to the balloon, giving the balloon a negative charge. The negative charge on the balloon attracts the positive charges in the ceiling, causing it to stick.

Explanation:

When you rub a balloon against your shirt, electrons are transferred from your shirt to the balloon, giving the balloon a negative charge. The balloon becomes negatively charged and the shirt becomes positively charged. When you touch the negatively charged balloon to the ceiling, the positive charges in the ceiling are attracted to the balloon, causing it to stick.

What did the early plants add to the atmosphere and why was that important? What else did they create?

Answers

Oxygen is the thing they added to the otmosphere

early plants added oxygen to the atmosphere. They did this by photosynthesis process by absorbing the carbon dioxide from the atmosphere and giving away oxygen in return.

This was important because life is not possible without oxygen present in the atmosphere.

They consumed the carbon dioxide from the atmosphere and reduced the temperature of the planet also.

Springfield's "classic rock" radio station broadcasts at a frequency of 102.1 mhz. what is the length of the radio wave in meters?

Answers

The frequency of the radio wave is:
[tex]f=102.1 MHz = 102.1 \cdot 10^6 Hz[/tex]

The wavelength of an electromagnetic wave is related to its frequency by the relationship
[tex]\lambda= \frac{c}{f} [/tex]
where c is the speed of light and f the frequency. Plugging numbers into the equation, we find
[tex]\lambda= \frac{3 \cdot 10^8 m/s}{102.1 \cdot 10^6 Hz}= 2.94 m[/tex]
and this is the wavelength of the radio waves in the problem.
Final answer:

Using the equation for the speed of light, we find that the wavelength of a radio wave broadcasting at 102.1 MHz frequency in Springfield is approximately 2.94 meters.

Explanation:

The length of a wave, often termed wavelength, can be deduced if the frequency is known, using the formula of the speed of light, which is wavelength times frequency (or c = λν). In this equation, 'c' signifies the speed of light (3 x 10^8 m/s), 'λ' is the wavelength, and 'ν' is the frequency. Given frequency = 102.1 MHz = 102.1 x 10^6 Hz, we can rearrange the formula to find the wavelength: λ = c/ν = 3 x 10^8 m/s / 102.1 x 10^6 Hz = 2.94 m. Therefore, the length of the wave is approximately 2.94 meters.

Learn more about Wavelength here:

https://brainly.com/question/32900586

#SPJ3

The electrons in the beam of a television tube have a kinetic energy of 2.20 10-15 j. initially, the electrons move horizontally from west to east. the vertical component of the earth's magnetic field points down, toward the surface of the earth, and has a magnitude of 3.00 10-5 t. (a) in what direction are the electrons deflected by this field component? due north due south due east due west (b) what is the magnitude of the acceleration of an electron in part (a)? m/s2

Answers

(a) The electrons move horizontally from west to east, while the magnetic field is directed downward, toward the surface. We can determine the direction of the force on the electron by using the right-hand rule:
- index finger: velocity --> due east
- middle finger: magnetic field --> downward
- thumb: force --> due north
However, we have to take into account that the electron has negative charge, therefore we have to take the opposite direction: so, the magnetic force is directed southwards, and the electrons are deflected due south.

b) From the kinetic energy of the electrons, we can find their velocity by using
[tex]K= \frac{1}{2}mv^2 [/tex]
where K is the kinetic energy, m the electron mass and v their velocity. Re-arranging the formula, we find
[tex]v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 \cdot 2.20 \cdot 10^{-15} J}{9.1 \cdot 10^{-31} kg} }=6.95 \cdot 10^7 m/s [/tex]

The Lorentz force due to the magnetic field provides the centripetal force that deflects the electrons:
[tex]qvB = m \frac{v^2}{r} [/tex]
where
q is the electron charge
v is the speed
B is the magnetic field strength
m is the electron mass
r is the radius of the trajectory
By re-arranging the equation, we find the radius r:
[tex]r= \frac{mv}{qB}= \frac{(9.1 \cdot 10^{-31} kg)(6.95 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19} C)(3.00 \cdot 10^{-5} T)}=13.18 m [/tex]

And finally we can calculate the centripetal acceleration, given by:
[tex]a_c = \frac{v^2}{r}= \frac{(6.95 \cdot 10^7 m/s)^2}{13.18 m}=3.66 \cdot 10^{14} m/s^2 [/tex]

A printer is connected to a 1.0 m cable. if the magnetic force is 9.1 × x10-5 n, and the magnetic field is 1.3 × 10-4 t, what is the current in the cable

Answers

The magnetic force on a current-carrying wire due to a magnetic field is given by
[tex]F=ILB[/tex]
where
I is the current
L the wire length
B the magnetic field strength

In our problem, L=1.0 m, [tex]F=9.1 \cdot 10^{-5} N[/tex] and [tex]B=1.3 \cdot 10^{-4}T[/tex], so we can re-arrange the formula to find the current in the wire:
[tex]I= \frac{F}{LB}= \frac{9.1 \cdot 10^{-5} N}{(1.0 m)(1.3 \cdot 10^{-4} T)} =0.7 A [/tex]

The spool has a mass of 50 kg and a radius of gyration of ko = 0.280 m. if the 20-kg block a is released from rest, determine the velocity of the block when it descends 0.5 m.

Answers

V₁ = (1/g)₁ = Way₁ = 20(9.81)(0) = 0
V₂ (Vg)₂ = -WAy₂ = -20(9.81)(0.5) = -98.1J
The kinetic energy because the pool rotates about a fixed axis 
W = VA/rA = VA/0.2 5VA
Mass momen of inertila about fixed axis which passes through point 0
I₀ = mko² = 50(0.280)² = 3.92 kg. m²
∴ The kinetic energy of the system is 
T = 1/2 I₀w² + 1/2mAVA²

= 1/2(3.92)(5VA)² + 1/2 (20) VA² = 59VA²
Now that the system is at rest then T₁ = 0
Energy conservation  is
T₁ +V₁ = T₂ + V₂
0+ 0 = 59VA² + (-98.1)
VA = 1.289 m/s
= 1.29 m/s
Final answer:

To find the velocity of a 20-kg block descending 0.5 m, use conservation of energy, equating the potential energy lost by the block to the kinetic energy gained by the block and the rotational kinetic energy of the spool. Determine kinetic energy and rotational energy using the block's mass, spool's radius of gyration, and their shared velocity.

Explanation:

To determine the velocity of the 20-kg block after it descends 0.5 m, we can use the principles of conservation of energy. The system consists of a spool and a block, and since the block is descending, gravitational potential energy is being converted into kinetic energy and rotational energy of the spool.

We know that the potential energy (PE) lost by the block is equal to the kinetic energy (KE) gained by the block plus the rotational kinetic energy (RKE) gained by the spool:

PE = KE + RKE

PE of the block = m·g·h, where m is the mass of the block, g is the acceleration due to gravity (9.81 m/s2), and h is the height descended (0.5 m).

KE of the block = 1/2 m·v2, where v is the velocity of the block we want to find.

RKE of the spool = 1/2 I·ω2, with I being the moment of inertia of the spool and ω the angular velocity. Since the spool and the block are connected, ω = v / r, where r is the radius of the spool.

Using the radius of gyration ko, the moment of inertia I for the spool is I = mspool·ko2. By substituting all these expressions into the energy conservation equation and solving for v, we can find the velocity of the block.

Learn more about Conservation of Energy here:

https://brainly.com/question/35373077

#SPJ3

Marisol and mimi walked the same distance from their school to a shopping mall. marisol walked 2 miles per hour, while mimi left 1 hour later and walked 3 miles per hour. if they reached the mall at the same time, how far from the mall is their school? answers

Answers

Marisol = 2 mph
Mimi = 3 mph and left 1 hour after Marisol had left

They arrived at the same time.
If Marisol took x hours to arrive, then Mimi took (x-1) hours. The distance was the same.

Distance, D = Speed*Time
Marisol: D = 2*x = 2x
Mimi: D = 3*(x-1) = 3x-3

then,
2x = 3x -3 => (2-3)x = -3 => -x = -3=> x = 3 hours

Therefore,
D =2x = 2*3 = 6 miles

The main organ of the respiratory system

Answers

the airway, lungs, and muscles
The airway, the lungs, and the muscles of respiration. The airway, which includes the nose, mouth, pharynx, larynx, trachea, bronchi, and bronchioles, carries air between the lungs and the body's exterior.

"the temperature of a student's skin is 33.0°c. at what wavelength does the radiation emitted from the skin reach its peak?"

Answers

The general expression relation wavelength and temperature:

Wavelength (m) * Temperature (K) = Constant = 2.898*10^-3
Where Temperature = 33.0°C = (33+273.15) K = 306.15 K

Therefore;
Wavelength = (2.898*10^-3)/306.15 = 9.466*10^-6 m = 0.009466 mm
Final answer:

The peak wavelength of radiation emitted from human skin at 33.0°C is approximately 9465.7 nm or about 9.465 microns, calculated using Wien's displacement law.

Explanation:

The student's question about the peak wavelength of radiation emitted from the skin at a certain temperature relates to Wien's displacement law. This law states that the peak wavelength of the radiation is inversely proportional to the temperature of the radiating body when the temperature is in Kelvin. Firstly, we need to convert the skin temperature from Celsius to Kelvin, which would be 33.0°C + 273.15 = 306.15 K. Using Wien's law (with a constant of approximately 2.898 x 10^6 nm·K), we can calculate the peak wavelength with the formula λ(max) = b / T. So, the peak wavelength would be λ(max) = 2.898 x 10^6 nm·K / 306.15 K, which gives us a peak wavelength of approximately 9465.7 nm or about 9.465 microns.

I will give you BRAINILIEST!!!!!!!!! AND 15 POINTS

Which of the following is a divergent boundary? 

      
 A. Rift valley   
B. Transform   
C. Oceanic-continental  
 D. Continental-continental

Answers

Hello.

The best answer would be A.Rift Valley.

It forms when l tectonical plates move away froem each other.


Have a nice day :)

A uniform magnetic field points upward, parallel to the page, and has a magnitude of 7.85 mt. a negatively charged particle (q=−3.32 μc, m=2.05 pg) moves through this field with a speed of 67.3 km/s perpendicular to the magnetic field, as shown. the magnetic force on this particle is a centripetal force and causes the particle to move in a circular path. what is the radius of the particle's circular path?

Answers

Final answer:

The magnetic force on a charged particle moving through a magnetic field perpendicular to its velocity can cause the particle to move in a circular path. The radius of this path can be calculated using the formula r = mv/qB, resulting in an approximate radius of 42 millimeters for the given parameters.

Explanation:

In physics, one of the forces that can cause a particle to undergo uniform circular motion is the magnetic force. This happens when a charged particle moves in a direction perpendicular to a magnetic field. The magnetic force, being perpendicular to the velocity of the particle, acts as a centripetal force, constantly changing the direction of the particle's velocity, thus causing the particle to move in a circular path. The radius of this circular path can be obtained using the equation for the magnetic force acting on a moving charged particle, F = qvB, where q is the charge of the particle, v is the speed of the particle, and B is the magnetic field strength.

So the magnetic force equals the centripetal force when qvB = mv²/r, which allows us to solve for r, the radius of the path: r = mv/qB.

Substituting the given values: r = (2.05*10^-12 kg * 67.3*10^3 m/s) / (3.32*10^-6 C * 7.85 T), we find the radius r is about 0.042 meters or 42 millimeters. Note we have included unit conversions for mass m from picograms (pg) to kilograms (kg), speed v from kilometers per second (km/s) to meters per second (m/s), and charge q from microcoulombs (μC) to coulombs (C).

Learn more about Magnetic Force here:

https://brainly.com/question/34649513

#SPJ12

The radius of the particle's circular path is 42 millimeters.

Given:

A uniform magnetic field with magnitude B = 7.85 mT

A negatively charged particle with charge q = -3.32 μC = -3.32 × 10⁻⁶ C and mass m = 2.05 pg = 2.05 × 10⁻¹⁵ kg

The particle moves with a speed of v = 67.3 km/s = 67.3 × 10³ m/s perpendicular to the magnetic field

The magnetic force on a charged particle moving in a magnetic field is given by the equation:

F = qvB sinθ

where θ is the angle between the velocity of the particle and the magnetic field. In this case, θ = 90°, so sinθ = 1. Therefore, the magnetic force on the particle is:

F = qvB = (-3.32 × 10⁻⁶ C)(67.3 × 10³ m/s)(7.85 × 10⁻³ T) = 1.75 × 10⁻² N

The magnetic force is also the centripetal force that keeps the particle moving in a circular path. Therefore, we can equate the magnetic force to the centripetal force to find the radius of the particle's circular path:

F = mv²/r

Solving for r, we get:

r = mv²/F = (2.05 × 10⁻¹⁵ kg)(67.3 × 10³ m/s)²/(1.75 × 10⁻² N) = 0.042 m = 42 mm

For similar question on radius

https://brainly.com/question/13126562

#SPJ3

Earth is closest to the sun at what part of its orbit?

Answers

Earth is closest to the sun at the point in its orbit called the "perihelion" .

Our planet passes that point in its orbit sometime during the first few days
of January.

Here the dates of perihelion passage in 2018 and the next few years.
The times are Central Daylight Time (Chicago & Dallas time).

2018  January 2, 2018  11:34 pm
2019  January 2, 2019  11:19 pm
2020  January 5, 2020   1:47 am
2021  January 2, 2021   7:50 am
2022  January 4, 2022  12:52 am

These are the moments when the Earth will be
CLOSEST to the sun in its orbit.

A proton and an electron are held in place on the x axis. The proton is at x = -d, while the electron is at x = +d. They are released simultaneously, and the only force that affects their motions is the electrostatic force of attraction that applies to the other. Which particle reaches the origin first? Give your reasoning.

Answers

The protons and electrons are held in place on the x axis.
The proton is at x = -d and the electron is at x = +d. They are released at the same time and the only force that affects movement is the electrostatic force that is applied on both subatomic particles. According to Newton's third law, the force Fpe exerted on protons by the electron is opposite in magnitude and direction to the force Fep exerted on the electron by the proton. That is, Fpe = - Fep. According to Newton's second law, this equation can be written as
                               Mp * ap = -Me * ae
where Mp and Me are the masses, and ap and ae are the accelerations of the proton and the electron, respectively. Since the mass of the electron is much smaller than the mass of the proton, in order for the equation above to hold, the acceleration of the electron at that moment must be considerably larger than the acceleration of the proton at that moment. Since electrons have much greater acceleration than protons, they achieve a faster rate than protons and therefore first reach the origin.
Final answer:

The electron will reach the origin first due to its greater acceleration, which is a result of its much smaller mass compared to the proton, despite the forces on both particles being equal in magnitude.

Explanation:

The question is asking which particle, a proton at x = -d or an electron at x = +d that are released simultaneously under the influence of electrostatic force, will reach the origin first. According to Newton's second law, force equals mass times acceleration (F = ma). Because the proton and the electron have equal and opposite charges, the magnitude of the force acting on them due to their electrical interaction will be the same. However, the mass of the proton is much greater than that of the electron, resulting in much smaller acceleration for the proton. Consequently, the electron, given its smaller mass and therefore larger acceleration, will reach the origin first.

Newton believed that time and space are absolute, while Einstein believed that the _______ is absolute.

Curvation of Space-time
Speed of light
4th dememtion
Dilation of time
4th dememtion

Answers

Speed of light 

According to Einstein, the speed of light is constant in all points of reference.  In addition, he pointed out the speed of light is the maximum speed known since in practice one can never catch up with the beam of light. This is explained by his theory of relativity. 

Answer:

The answer is B. speed of light

Explanation:

What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?

Answers

Momentum = mv
where m is the mass of an electron and v is the velocity of the electron.

v = momentum ÷ m
   = (1.05×10∧-24)÷(9.1×10∧-31) = 1,153,846.154 m/s

kinetic energy = (mv∧2)÷2
                       = (9.1×10∧-31 × 1,153,846.154∧2) ÷2
                      = (1.21154×10∧-18) ÷ 2
                      = 6.05769×10∧-19 J

Answer:

K = 6.02 × 10⁻¹⁹ J

Explanation:

The momentum (p) of an electron is its mass (m) times its speed (v).

p = m × v

v = p / m = (1.05 × 10⁻²⁴ kg.m/s) / 9.11 × 10⁻³¹ kg = 1.15 × 10⁶ m/s

We can find the kinetic energy (K) using the following expression.

K = 1/2 × m × v²

K = 1/2 × 9.11 × 10⁻³¹ kg × (1.15 × 10⁶ m/s)²

K = 6.02 × 10⁻¹⁹ J

A canister containing air has a volume of 85 cm 3 and a pressure of 1.45 atm when the temperature is 310 k. what is the pressure when the volume is increased to 180 cm 3 and the temperature is reduced to 280 k?

Answers

We can solve the problem by using the ideal gas law, which states:
[tex]pV=nRT[/tex]
where
p is the gas pressure
V is the volume
n is the number of moles
R is the gas constant
T is the absolute temperature

The initial conditions of the gas in the problem are:
[tex]p=1.45 atm =1.47 \cdot 10^5 Pa[/tex]
[tex]V=85 cm^3 = 85 \cdot 10^{-6} m^3[/tex]
[tex]T=310 K[/tex]
So we can use the previous equation to find the number of moles of the gas:
[tex]n= \frac{pV}{RT}= \frac{(1.47 \cdot 10^5 Pa)(85 \cdot 10^{-6} m^3)}{(8.31 J/mol K)(310 K)} =4.9 \cdot 10^{-3} mol [/tex]

The final conditions of the gas are:
[tex]V=180 cm^3 = 180 \cdot 10^{-6} m^3[/tex]
[tex]T=280 K[/tex]
and since the number of moles didn't change, we can find the final pressure by using again the ideal gas law:
[tex]p= \frac{nRT}{V}= \frac{(4.9 \cdot 10^{-3} mol)(8.31 J/mol K)(280 K)}{180 \cdot 10^{-6} m^3}=0.63 \cdot 10^5 Pa [/tex]

A girl is running toward the front of a train at 10 m/s. If the train is going 75 m/s on the Southbound tracks, what is the speed of the train relative to the girl?

Answers

Final answer:

The speed of the train relative to the girl is 65 m/s.

Explanation:

The speed of the train relative to the girl can be calculated by subtracting the girl's speed from the train's speed. In this case, the train is moving at 75 m/s and the girl is running towards the front of the train at 10 m/s. So the speed of the train relative to the girl would be 75 m/s - 10 m/s = 65 m/s.

Learn more about relative speed here:

https://brainly.com/question/14362959

#SPJ12

The correct option is B. 65 m/s, South.

The given problem can be solved using concepts of relative motion.

Given that the girl is running toward the front of a train at 10 m/s and the train is going 75 m/s on the Southbound tracks. Hence, both the girl and the train are moving in the same direction, i.e. southwards.

So, the speed of the train relative to the girl can be given as:

[tex]v_{tg} = v_t - v_g[/tex]

where, [tex]v_{tg}[/tex] is the speed of train with respect to the girl

[tex]v_t[/tex] is the speed of train

[tex]v_g[/tex] is the speed of the girl

[tex]\therefore v_{tg} = 75 \hspace{0.8mm} m/s - 10 \hspace{0.8mm} m/s[/tex]

or, [tex]v_{tg} = 65 \hspace{0.8mm} m/s[/tex]

Hence, the speed of the train relative to the girl is 65 m/s due south.

The complete question is:

A girl is running toward the front of a train at 10 m/s. If the train is going 75 m/s on the Southbound tracks, what is the speed of the train relative to the girl?

A. 10 m/s, South

B. 65 m/s, South

C. 65 m/s, North

D. 10 m/s, North

On a dry day, just after washing your hair to remove natural oils and drying it thoroughly, run a plastic comb through it. Small bits of paper will be attracted to the comb. Explain why.

Answers

When the surface of the comb rubs on your hair, the comb is electrically charged. When the comb comes close to the paper, the charge on the comb causes charge separation on the paper bits. Since paper is neutral, positive and negative charges are equivalent. The charge on the comb charges the area of the bit of paper nearest the comb to the opposite. Thus, the bits of paper become attracted to the comb.

Final answer:

A plastic comb can attract small bits of paper due to the electrostatic charge created by friction. This effect is reduced in moist air as humidity conducts the charge away.

Explanation:

When a plastic comb is run through hair, it can attract small bits of paper. This is due to the electrostatic charge that is created by friction when the comb is dragged against the hair. The comb becomes negatively charged as electrons are transferred from the hair to the comb, resulting in an electrostatic force that can attract neutral objects, such as pieces of paper.

If you repeat the experiment in a moist environment, such as a bathroom after a shower, you may observe that the electrostatic effect is reduced. This is because water molecules in the air increase the humidity, which conducts the charge away, thereby neutralizing the electrostatic effect more rapidly than in dry air.

Torn paper may be more effective than cut paper because the tearing process can create more irregularities and protrusions on the edges of the paper, providing more opportunities for the electric force to act upon these points compared to the relatively smooth edges of cut paper.

A satellite is in a circular orbit about the earth at a distance of one earth radius above the surface. what is the velocity of the satellite? (the radius of the earth is 6400 km and the mass of the earth is 5.98 * 1024 kg)

Answers

The gravitational attraction between the Earth and the satellite provides the centripetal force that keeps the satellite in circular motion:
[tex]m \frac{v^2}{r}= G \frac{Mm}{r^2} [/tex]
where
m is the satellite mass
v is its speed
r is its distance from the Earth's center
G is the gravitational constant
M is the Earth's mass

Re-arranging the formula, we get
[tex]v= \sqrt{ \frac{GM}{r} } [/tex]

The satellite orbits at a distance equal to one Earth's radius (R) above the surface. This means that its distance from the Earth's center is twice the Earth radius:
[tex]r=2R=2 \cdot 6400 km = 12800 km = 1.28 \cdot 10^4 m[/tex]

Therefore, its velocity is
[tex]v= \sqrt{ \frac{GM}{r} }= \sqrt{ \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.98 \cdot 10^{24} kg)}{1.28 \cdot 10^4 m} }=1.76 \cdot 10^5 m/s [/tex]

(a) an electron has kinetic energy 5.00 ev. find its wavelength.

Answers

First, we need to convert electron's kinetic energy into Joules. Keeping in mind that 
[tex]1 eV=1.6 \cdot 10^{-19}J[/tex]
we have
[tex]E=3 eV \cdot 1.6 \cdot 10^{-19} J/eV=4.8 \cdot 10^{-19} J[/tex]

The kinetic energy of the electron is equal to:
[tex]E= \frac{1}{2}mv^2 [/tex]
where m is the electron mass and v its speed. If we re-arrange this equation, we can find the electron speed:
[tex]v= \sqrt{ \frac{2E}{m} }= \sqrt{ \frac{2 \cdot 4.8 \cdot 10^{-19} J}{9.1 \cdot 10^{-31} kg} } =1.03 \cdot 10^6 m/s [/tex]

And now we can use De Broglie's relationship to find the electron's wavelength:
[tex]\lambda= \frac{h}{p} [/tex]
where h is the Planck constant and p=mv is the electron momentum. Substituting numbers, we get
[tex]\lambda= \frac{h}{mv}= \frac{6.6 \cdot 10^{-34} Js}{(9.1 \cdot 10^{-31}kg)(1.03 \cdot 10^6 m/s)}=7.04 \cdot 10^{-10} m [/tex]
Final answer:

The wavelength of an electron with a given kinetic energy of 5.00 eV can be found using the de Broglie wavelength formula and first converting the kinetic energy into joules.

Explanation:

To find the wavelength of the electron with kinetic energy of 5.00 eV, we will use the de Broglie wavelength formula, which links a particle's momentum to its wavelength. This is given by λ = h/p where λ is the wavelength, h is Planck's constant (6.626 x 10-34 Js), and p is the momentum of the particle.

First, we need to convert the kinetic energy into joules. The energy in joules (E) is given by E = K x q, where K is the kinetic energy in electronvolts (eV) and q is the electron charge (1.602 x 10-19 C). For the given energy of 5.00 eV, the energy in joules will be E = 5.00 eV x 1.602 x 10-19 C/eV = 8.01 x 10-19 J.

Now, we can calculate the electron's momentum using the relation p = √(2mE), where m is the electron's mass (9.109 x 10-31 kg). After solving, the momentum is used in de Broglie's formula to find the wavelength.

Solar radiation falls on earth's surface at a rate of 1900 w/m2 . assuming that the radiation has an average wavelength of 560 nm, how many photons per square meter per second fall on the surfaces? the speed of light is 3 × 108 m/s and planck's constant is 6.62607 × 10−34 j · s. answer in units of photon/m2 · s.

Answers

First, we need to calculate the energy of a single photon of this radiation.

The wavelength of the photons is:
[tex]\lambda=560 nm = 5.6 \cdot 10^{-7}m [/tex]
And their frequency is:
[tex]f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{5.6 \cdot 10^{-7} m}=5.36 \cdot 10^{14}Hz [/tex]
So the energy of one photon is
[tex]E_1=hf=(6.6 \cdot 10^{-34}Js)(5.36 \cdot 10^{14} Hz)=3.54 \cdot 10^{-19} J[/tex]

The intensity of the solar radiation on Earth's surface is [tex]1900 W/m^2[/tex]. This means that the power is P=1900 W. But the power is just the energy per second:
[tex]P= \frac{E}{t} [/tex]
So this means that the energy of the solar radiation per meter squared per second is E=1900 J. If we divide this number by the energy of a single photon, we find the number of photons per meter squared per second:
[tex]N= \frac{E}{E_1}= \frac{1900 J}{3.54 \cdot 10^{-19} J}=5.37 \cdot 10^{21}ph \cdot m^2 /s[/tex]
Final answer:

The number of photons per square meter per second falling on the earth's surface, given the solar radiation rate and average wavelength is calculated to be 5.36 x 10²¹ photons/m2·s.

Explanation:

The energy of the average visible photon is calculated using the formula E= hc/λ, where h is Planck's constant, c is the speed of light and λ is the wavelength. With the given values, we get the energy E by substituting h=6.62607 × 10⁻³⁴ J·s, c=3 × 108 m/s, and λ=560 × 10⁻⁹ m resulting in E= 3.546 × 10⁻¹⁹ J. The number of photons per meter square per second can be calculated by dividing the rate of solar radiation, 1900 W/m2 or 1900 J/s·m2 by the energy per photon, yielding 5.36 x 10²¹ photons/m2·s.

Learn more about Photon Count Calculation here:

https://brainly.com/question/29038909

#SPJ3

Which listed property of alternating current is the MOST LIKELY reason it was chosen over direct current to provide electricity across the country? A) can power devices B) can be used in houses C) current changes direction D) can be transformed to different voltages

Answers

The correct option is 
D) can be transformed to different voltages

In fact, transformers can be used in order to change the voltage of an alternating current. This feature is particularly useful, because it allows to transmit electricity through power lines using very high voltages, and this allows to reduce the power dissipated along the lines.

In fact, the power generated by a power station is the product between the current and the voltage:
[tex]P_{in}= VI[/tex]
So the current is:
[tex]I= \frac{P_{in}}{V} [/tex] (1)

The power dissipated along the transmission line, instead, is given by
[tex]P_{diss} = I^2 R[/tex]
and if we use (1) inside this, we find
[tex]P_{diss} = \frac{P_{in}^2}{V^2} R[/tex]
so we see that the higher the voltage, the lower the power dissipated along the transmission lines.

Then, transformers are also used at the end of the power lines, in order to convert these very high voltages into the standard voltage (e.g. 240 V) used by household appliances.

In a physics laboratory experiment, a coil with 250 turns enclosing an area of 10.5 cm2 is rotated during the time interval 3.10×10−2 s from a position in which its plane is perpendicular to earth's magnetic field to one in which its plane is parallel to the field. the magnitude of earth's magnetic field at the lab location is 5.30×10−5 t .

Answers

I guess the problem is asking for the induced emf in the coil.

Faraday-Neumann-Lenz states that the induced emf in a coil is given by:
[tex]\epsilon = -N \frac{\Delta \Phi}{\Delta t} [/tex]
where
N is the number of turns in the coil
[tex]\Delta \Phi[/tex] is the variation of magnetic flux through the coil
[tex]\Delta t[/tex] is the time interval

The coil is initially perpendicular to the Earth's magnetic field, so the initial flux through it is given by the product between the magnetic field strength and the area of the coil:
[tex]\Phi_i = BA=(5.30 \cdot 10^{-5}T)(10.5 \cdot 10^{-4} m^2)=5.57 \cdot 10^{-8} Wb[/tex]
At the end of the time interval, the coil is parallel to the field, so the final flux is zero:
[tex]\Phi_f = 0[/tex]

Therefore, we can calculate now the induced emf by using the first formula:
[tex]\epsilon = -N \frac{\Delta \Phi}{\Delta t}=- (250) \frac{5.57 \cdot 10^{-8} Wb - 0}{3.10 \cdot 10^{-2} s} = -4.5 \cdot 10^{-4} V[/tex]

a screwdriver with a 1-cm shaft and a 4-cm handle is used to tighten a screw. calculate the ideal mechanical advantage.

Answers

Ideal mechanical advantage = Effort distance/Resistance distance

In the current scenario,
Effort distance = 4 cm
Resistance distance = 1 cm

Therefore,
Ideal mechanical advantage = 4/1 = 4

Answer:

IMA = Distance of Effort/ Distance of resistance

Explanation:

M.A is the force amplification of a machine.

Ideally, a screw driver has varying diameters on two ends, the shaft and the handle, however, since the question does not provide those parameters, we will assume shaft and handle have the same diameter.

DE = 4

DR = 1

Therefore, IMA = [tex]\frac{4}{1} = 4[/tex]

If diameter is given, IMA is calculated by

Area of Effort/ Area of resistance i.e. AE/AR

When the angle of elevation of the sun is 64°, a pole that is tilted at an angle of 19° directly away from the sun casts a shadow 21 feet long on level ground. approximate the length of the pole to the nearest foot?

Answers

Angles at a point make 180° at a straight line.
Lx = 180° - (90+90)
Lx is 70°
Lx = 180° -(64+71)
= 180° - 13J°
= 45°
By using sine law
21/siny = length of pole/ sin 64
∴Length of pole = 21 sin 64/sin u5 = 26.69
Then the length of pole = 27ft

Answer:

Length of the pole is 27ft. ( rouding up to the nearest foot)

Explanation:

To solve this problem you need to understand that the the shadow cast by the pole on the ground connected to the pole itself and to the imaginary line of sun light forms a triangle with 3 different angles, please see the drawing to a better understanding.

* The sum of the internal angles of any triangle must be 180° then;

α: angle of the elevation of the sun= 64°

angle of the pole to the ground= (90-19)= 71°

β = 180 - ( 64+71) = 45°

*To find the length of the pole we can use the law of Sines;

|BC| / sin (α) = |AC| / sin (β)

|BC|= Length of the pole

|AC|= shadow of the pole on the ground which is known to be 21 ft

|BC| / sin (64°) = 21 / sin (45°)

|BC|= 21 x [sin (64°)/ sin (45°)]

|BC|= 21 x 1.27≅ 26.67 ft

A gravitational field vector points toward the earth; an electric field vector points toward an electron. why do electric field vectors point away from protons? 1. protons have much larger mass. 2. unlike electrons, protons will produce an electric field of their own. 3. protons have more net charge than electrons. 4. protons are positively charged. 5. none of these

Answers

The correct answer is
 4. protons are positively charged. 

In fact, the direction of the electric field of a charged particle depends on the sign of the charge of the particle. While a negatively charged particle (such as the electron) produces an electric field that points toward the charge, a positively charged particle (like a proton) produces an electric field that points away from the charge. This can be proofed by using a positive test charge: if we put a positive test charge near a proton, this test charge will move away from the proton (because it is repelled from it, since they have same charge), and the direction of its motion gives the direction of the electric field generated by the proton, so away from it.

Electric field vectors point away from protons because protons are positively charged, and electric field lines always point away from positive charges and toward negative charges.

The direction of electric field vectors is determined by the nature of the charge that produces them. Specifically, electric field lines point away from positive charges and toward negative charges. This is because the electric field vector always points in the direction of the force that would be exerted on a positive test charge.

1. Gravitational fields always point towards the source of the field (like toward Earth) because gravity is an attractive force.

2. On the other hand, electric fields can be either attractive or repulsive. For a positive charge, the electric field vectors radiate outward because like charges repel, meaning if you place a positive test charge near a proton, it will be repelled outward.

Therefore, the correct answer is: protons are positively charged (option 4).

A current of 5.0 a flows through an electrical device for 10 seconds. how many electrons flow through this device during this time?

Answers

1 Amp = 1 Coulomb/sec
1 Coulomb/sec = 6.25*10^18 electrons/sec

Therefore,
5.0 A = 5 C/s = 5*6.25*10^18 = 3.125*10^19 e/s

In 10 second, number of electrons are calculated as;
Number of electrons through the device = 3.125*10^19*10 = 3.125*10^20 electrons

Approximately [tex]\( 3.121 \times 10^{19} \)[/tex] electrons flow through the electrical device during the [tex]10\ seconds[/tex] when a current of [tex]5.0 \ A[/tex] is flowing.

To determine how many electrons flow through the electrical device, we can use the relationship between current, time, and the charge carried by electrons.

Given:

Current [tex]\( I = 5.0 \) A[/tex]

Time [tex]\( t = 10 \) seconds[/tex]First, calculate the total electric charge [tex]\( Q \)[/tex] that flows through the device using:

[tex]\[ Q = I \times t \][/tex]

Substitute the given values:

[tex]\[ Q = 5.0 \, \text{A} \times 10 \, \text{s} = 50 \, \text{C} \][/tex]

Now, we know that 1 Coulomb ([tex]C[/tex]) corresponds to approximately[tex]\( 6.242 \times 10^{18} \) electrons.[/tex]

To find out how many electrons [tex]\( N \)[/tex] flow through the device, convert the charge [tex]\( Q \)[/tex] into electrons:

[tex]\[ N = Q \times (6.242 \times 10^{18} \, \text{electrons/C}) \][/tex]

Substitute [tex]\( Q = 50 \, \text{C} \)[/tex]

[tex]\[ N = 50 \times 6.242 \times 10^{18} \, \text{electrons} \][/tex]

[tex]\[ N = 312.1 \times 10^{18} \, \text{electrons} \][/tex]

[tex]\[ N = 3.121 \times 10^{19} \, \text{electrons} \][/tex]

Other Questions
Should animals be used for medical research?Is it ethical or not?why or not? Think long and hard before answering. Give examples. Be detailed. Ponyboy states,"my dreams came true and I'm in the country." Why is this statement ironic? the outsiders A major depressive episode requires ________ of nine symptoms, including a depressed mood and/or diminished interest in activities for at least two weeks. On a skiing trip there are five people but only three pairs of skis how many different groups of three could ski (need help!) A dart is thrown at the board shown. It hits the board at a random point. Find the probability that it will land in the unshaded region. Round to the nearest percent.20%33%17%25% How do you divide fractions a garden patio is covered with grey slabs and yellow slabs. 1/5 is grey. 1/4 is yellow. theres 55 slabs in total. what is the number of yellow slabs what is the significance of the demographic transition in studies of human population aroumd the world? What did chief justice burger say about executive privilege? how does that justify his decision about nixon releasing the tapes? Daisy is Augusts dog,who has been sick for awhile.why hasnt August noticed this. Which allows medication to enter directly into the intestinal tract?endotracheal tubenasogastric tubegastrostomy tubejejunostomy tube Which statements accurately describe sound waves? Check all that apply.Sound waves are transverse waves.Sound waves require a medium to transfer energy.Sound is heard when a vibration strikes the ear.Sound waves can only travel through liquids and gases.When particles of a medium interact, part of the waves energy is lost.A waves energy can be distinguished from other movements of the medium. What is the leading cause of water pollution in the United States? Investment spending increases during periods of recession. a. True b. False How did nixon use his visit to china to improve relations with the soviet union? What does the presence of similar genes in very dissimilar organisms imply? a the organisms do not share a common ancestor. b the genes became identical through mutation. c they must be in the same family. d the organisms share a common ancestor? You move a 2.5 kg book from a shelf that is 1.2 m above the ground to a shelf that is 2.6 m above the ground. What is the change in potential energy of a system containing the book and Earth? Can you help me list the following stocks and bonds in order from highest default risk to lowest default risk?-A municipal bond in a city with a population of 150,000-A common stock in a company under federal investigation-A preferred stock in a 150-year old firm with good business practices Determine the ratio of the resistivity of pure water to silver? 3:1 1:3 3 x 1011:1 1:3 x 1011:1 Jimmy Carter seemed weak and uncertain because of his reversal ona.human rights.b.apartheid.c.economic policies.d.the trade deficit.Please select the best answer from the choices providedABCD