whats the sum of two rational numbers

Answers

Answer 1

Answer:

The sum of two rational numbers is always a rational number.

Step-by-step explanation:

Rational Number is the number of the form [tex]\frac{p}{q}[/tex], q≠0 and p and q are integers.

Further, when we add or subtract two rational number it is always a rational number. Example:

[tex]\dfrac{4}{64} +\dfrac{25}{4} = \dfrac{4+25\times 16}{64} \\= \dfrac{4+400}{64} = \dfrac{404}{64} =\dfrac{101}{16}[/tex]

which is also a rational number.

Thus, the sum of two rational numbers is always a rational number.


Related Questions

A lab technician is tested for her consistency by taking multiple measurements of cholesterol levels from the same blood sample. The target accuracy is a variance in measurements of 1.2 or less. If the lab technician takes 16 measurements and the variance of the measurements in the sample is 2.2, does this provide enough evidence to reject the claim that the lab technician’s accuracy is within the target accuracy? Compute the value of the appropriate test statistic

Answers

Answer and Explanation:

Given : A lab technician is tested for her consistency by taking multiple measurements of cholesterol levels from the same blood sample.

The target accuracy is a variance in measurements of 1.2 or less. If the lab technician takes 16 measurements and the variance of the measurements in the sample is 2.2.

To find :

1) Does this provide enough evidence to reject the claim that the lab technician’s accuracy is within the target accuracy?

2)Compute the value of the appropriate test statistic ?

Solution :

1) n=16 number of sample

The target accuracy is a variance in measurements of 1.2 or less i.e. [tex]\sigma_1^2 =1.2[/tex]

The variance of the measurements in the sample is 2.2 i.e. [tex]\sigma_2^2=2.2[/tex]

According to question,  

We state the null and alternative hypotheses,

Null hypothesis [tex]H_o : \text{var}^2 \geq 1.2[/tex]

Alternative hypothesis [tex]H_a : \text{var}^2<1.2[/tex]

We claim the alternative hypothesis.

2) Compute the value of the appropriate test statistic.

Using Chi-square,

[tex]\chi =\frac{(n-1)\sigma_2^2}{\sigma_1^2}[/tex]

[tex]\chi =\frac{(16-1)(2.2)}{(1.2)}[/tex]

[tex]\chi =\frac{(15)(2.2)}{1.2}[/tex]

[tex]\chi =\frac{33}{1.2}[/tex]

[tex]\chi =27.5[/tex]

Therefore, The value of the appropriate test statistic is 27.5.

Final answer:

To determine if the lab technician's accuracy is within the target accuracy, a one-sample variance test can be performed using the chi-square statistic.

Explanation:

To determine if the lab technician's accuracy is within the target accuracy, we can perform a hypothesis test. We will use a one-sample variance test to compare the sample variance to the target variance.

The appropriate test statistic for a one-sample variance test is the chi-square statistic. The chi-square statistic is calculated by taking the sample variance and dividing it by the target variance, then multiplying by the degrees of freedom.

In this case, we have 16 measurements and a target variance of 1.2. The sample variance is 2.2. We can calculate the test statistic using the formula chi-square = (n-1) * (sample variance / target variance). Plugging in the values, we get chi-square = (16-1) * (2.2 / 1.2) = 29.67.

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use the binomial theorem to expand the expression :
(3x + y)^5 and simplify.
(b) find the middle term in the expansion of
(1/x+√x)^4 and simplify your unswer.
(c) determine the coefficient of x^11 in the expansion of (x^2 +1/x)^10, simplify your answer.

Answers

Answer:

a) [tex](3x+y)^5=243x^5+405x^4y+270x^3y^2+90x^2y^3+15xy^4+y^5[/tex].

b) The middle term in the expansion is [tex]\frac{6}{x}[/tex].

c) The coefficient of [tex]x^{11}[/tex] is 120.

Step-by-step explanation:

Remember that the binomial theorem say that [tex](x+y)^n=\sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^{k}[/tex]

a) [tex](3x+y)^5=\sum_{k=0}^5\binom{5}{k}3^{n-k}x^{n-k}y^k[/tex]

Expanding we have that

[tex]\binom{5}{0}3^5x^5+\binom{5}{1}3^4x^4y+\binom{5}{2}3^3x^3y^2+\binom{5}{3}3^2x^2y^3+\binom{5}{4}3xy^4+\binom{5}{5}y^5[/tex]

symplifying,

[tex](3x+y)^5=243x^5+405x^4y+270x^3y^2+90x^2y^3+15xy^4+y^5[/tex].

b) The middle term in the expansion of [tex](\frac{1}{x} +\sqrt{x})^4=\sum_{k=0}^{4}\binom{4}{k}\frac{1}{x^{4-k}}x^{\frac{k}{2}}[/tex] correspond to k=2. Then [tex]\binom{4}{2}\frac{1}{x^2}x^{\frac{2}{2}}=\frac{6}{x}[/tex].

c) [tex](x^2+\frac{1}{x})^{10}=\sum_{k=0}^{10}\binom{10}{k}x^{2(10-k)}\frac{1}{x^k}=\sum_{k=0}^{10}\binom{10}{k}x^{20-2k}\frac{1}{x^k}=\sum_{k=0}^{10}\binom{10}{k}x^{20-3k}[/tex]

Since we need that 11=20-3k, then k=3.

Then the coefficient of [tex]x^{11}[/tex] is [tex]\binom{10}{3}=120[/tex]

Estimate the sum. Use benchmarks with decimal parts of 0, 0.25, 0.50, or 0.75.
8.94+0.72

A. 9.25
B. 9.50
C. 9.75

Answers

Answer:

the estimated answer is A: 9.75.

(the actual answer is 9.66, so rounding up makes it 9.75)

3/4x -1/2y= 8 and 2x +y=40

Answers

Answer:

The value of x is 16 and the value of y is 8.

Step-by-step explanation:

Consider the provided equation.

[tex]\frac{3}{4}x -\frac{1}{2}y= 8\ and\ 2x +y=40[/tex]

Isolate x for [tex]\:\frac{3}{4}x-\frac{1}{2}y=8[/tex]

[tex]\frac{3}{4}x-\frac{1}{2}y+\frac{1}{2}y=8+\frac{1}{2}y[/tex]

[tex]\frac{3}{4}x=8+\frac{1}{2}y[/tex]

Multiply both side by 4 and simplify.

[tex]3x=32+2y[/tex]

[tex]x=\frac{32+2y}{3}[/tex]

Substitute the value of x in [tex]2x +y=40[/tex]

[tex]2\cdot \frac{32+2y}{3}+y=40[/tex]

[tex]\frac{64}{3}+\frac{7y}{3}=40[/tex]

[tex]64+7y=120[/tex]

[tex]7y=56[/tex]

[tex]y=8[/tex]

Now substitute the value of y in [tex]x=\frac{32+2y}{3}[/tex]

[tex]x=\frac{32+2\cdot \:8}{3}[/tex]

[tex]x=16[/tex]

Hence, the value of x is 16 and the value of y is 8.

- Meredith picked 4 times as many green
peppers as red peppers. If she picked a total
of 20 peppers, how many green peppers did
she pick?

Answers

Let g=green peppers
Let r =red peppers
1.creat two equations
20=g+r
G=4r
Substitute equation 2 into equation 1 for g
20=(4r) +r
20=5r
4=r
She picked 4 red peppers
Sub 4 into equation 1 for r
20=g+ (4)
16=g
She picked 16 green peppers.

Answer:

16.

Step-by-step explanation:

The ratio is 4:1 so 4 / (4 + 1) = 4/5 of the total is green peppers.

So it is 20 * 4/5 = 16 .

A recent study found a correlation between gum disease and heart disease. This result indicates that gum disease causes people to develop heart disease.
True or False?

Answers

Answer:

False

Step-by-step explanation:

Correlation measures the strength of the relation between two variables.

Further, Correlation is said to be positive if increasing/decreasing the one variable, also increases/decreases the values of another variable.

Correlation is said to be negative if increasing/decreasing the one variable, also decreases/increases the values of another variable.

Since we don't know here exists a positive correlation or negative correlation.

So here are two possible conditions:

The person who has Gum disease also has heart disease.

And, the person has Gum disease can never have heart disease.

Thus, the given statement is false.

Final answer:

The statement is false because a correlation found in a study does not necessarily mean one factor (gum disease) is the cause of the other (heart disease). The cause and effect relationship must be established through further studies.

Explanation:

The statement 'A recent study found a correlation between gum disease and heart disease. This result indicates that gum disease causes people to develop heart disease.' is False. A correlation implies a relationship between two elements, but it does not indicate a cause and effect relationship.

This means although the study shows a link or association between gum disease and heart disease, it does not mean gum disease causes heart disease. It could be that people with poor gum health also tend to have poor overall health including heart health. Alternatively, there could be a third underlying factor that leads to both conditions. Therefore, the cause and effect relationship must be established through further studies.

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Compute the exact interest on $5,870 at 12% if the money is borrowed from June to December of the same year.

Answers

Answer:

The exact interest on $5,870 at 12% is $58.70.

Step-by-step explanation:

Given information:

Principal = $5870

Interest rate  = 12% = 0.12

Time = June-December = 7 months.

We know that

1 year = 12 months

1/12 year = 1 month

7/12 year = 7 month

Time = 7/12 year

Formula for simple interest:

[tex]I=P\times r\times t[/tex]

where, P is principal, r is rate of interest and t is time in years.

Substitute P=5870, r=0.12 and t=7/12 in the above formula.

[tex]I=5870\times 0.12\times \frac{1}{12}[/tex]

[tex]I=5870\times 0.01[/tex]

[tex]I=58.70[/tex]

Therefore the exact interest on $5,870 at 12% is $58.70.

8/3(z+11)=y solve for z.

Answers

Answer:

  z = (3/8)y - 11

Step-by-step explanation:

Undo what has been done to z, in reverse order. Here, 11 is added and the sum is multiplied by 8/3.

To undo the multiplication, multiply the equation by the inverse, 3/8:

  (3/8)(8/3)(z+11) = (3/8)y

  z +11 = (3/8)y . . . . . . . . . simplify

To undo the addition of 11, add the opposite of 11 to the equation.

  z +11 -11 = (3/8)y -11

  z = (3/8)y -11 . . . . . . . . . simplify


Solve the following problems manually or using the MS Excel

Mohamed has enough wood to make 24 small chairs or 6 large tables. In other words, the large tables require 4 times the amount of wood as the small chairs. He only has enough of a special glazing compound to glaze 16 of the small chairs or 8 of the large tables. Let X1 the number of small chairs and X2 the number of large tables. The smaller chairs sell for $3 each, while the larger tables would bring $9 each.

(a) Formulate the Problem.

(b) Solve the Linear Programming Problem.

(c) Solve also graphically

Answers

Answer:

(a) in the step-by-step explanation

(b) The optimal solution is 8 chairs and 4 tables.

(c) Graph attached

Step-by-step explanation:

(a)

C: number of small chairs

T: number of large tables

Maximize Income = 9T + 3C

Restrictions:

Wood: 4T+C<=24

Glazing: 2T+C<=16

In the graph its painted in green the "feasible region" where lies every solutions that fit the restrictions.

One of the three points marked in the graph is the optimal solution.

Point 1 (C= 16, T= 0)

Income = 9*0+3*16=$ 48

Point 2 (C=8, T=4)

Income = 9*4+3*8 = $ 60

Point 3 (C=0, T=6)

Income = 9*6+3*0 = $ 54

The optimal solution is 8 chairs and 4 tables.

Margo borrows $900, agreeing to pay it back with 7% annual interest after 9 months. How much interest will she pay? Round your answer to the nearest cent, if necessary.

Answers

Answer:

[tex]I=\$47.25[/tex]

Step-by-step explanation:

we know that

The simple interest formula is equal to

[tex]I=P(rt)[/tex]

where

I is the Final Interest Value

P is the amount of money borrowed

r is the rate of interest  

t is Number of Time Periods

in this problem we have

[tex]t=9/12\ years\\ P=\$900\\r=0.07[/tex]

substitute in the formula above

[tex]I=900(0.07(9/12))[/tex]

[tex]I=\$47.25[/tex]

Final answer:

Margo will pay $47.25 in interest on a $900 loan with a 7% annual interest rate after 9 months, after converting the rate to a decimal and the time to years for the calculation.

Explanation:

The question asks how much interest Margo will pay on a $900 loan with an annual interest rate of 7% after 9 months. To calculate this, we need to know that Interest = Principal × Rate × Time, where the principal is the amount borrowed, the rate is the annual interest rate (as a decimal), and the time is the period of the loan in years

First, convert the annual interest rate from a percentage to a decimal by dividing by 100: 7% / 100 = 0.07. Next, convert the loan period from months to years since the interest rate is annual. There are 12 months in a year, so 9 months is equal to 9/12 or 0.75 years.

Now, calculate the interest: $900 (Principal) × 0.07 (Rate) × 0.75 (Time) = $47.25. Therefore, Margo will pay $47.25 in interest.

An FM radio station broadcasts at 98 MHz. what is the energy of each photon in Joule? Use h= 6.6 X10^-34 J*s for Planck constant.

Answers

Answer:

The energy of each photon is [tex]6.468 \times 10^{-26}[/tex] Joule.

Step-by-step explanation:

Consider the provided information.

According to the plank equation:

[tex]E=h\nu[/tex]

Where E is the energy of photon, h is the plank constant and [tex]\nu[/tex] is the frequency.

It is given that [tex]h= 6.6 \times10^{-34}[/tex] and [tex]\nu=98MHz[/tex]

98Mhz = [tex]98\times 10^6Hz[/tex]

Substitute the respective value in plank equation.

[tex]E=6.6\times 10^{-34}\times 98\times 10^6[/tex]

[tex]E=6.6\times 98\times 10^{-34+6}[/tex]

[tex]E=646.8 \times10^{-28}[/tex]

[tex]E=6.468 \times 10^{-26}[/tex]

Hence, the energy of each photon is [tex]6.468 \times 10^{-26}[/tex] Joule.

In a biathalon race you first ride a bicycle at an average speed of 21.8 mi/h for 16.5 miles, then you must run for another 5.5 miles. With what average speed, in miles per hour, must you run if your average speed for the entire race is to be 13.8 mi/h?

Answers

The average speed for this additional distance is 6.57 mi/h

The given parameters include;

the average speed on bicycle = 21.8 mi/hthe distance traveled on bicycle = 16.5 milesadditional distance to be covered = 5.5 mileslet the average speed for this additional distance = vthe average speed for the entire race = 13.8 mi/h

To find:

the average speed for this additional distance,  v

The average speed formula is given as;

[tex]average\ speed = \frac{total \ distance }{total \ time} \\\\average\ speed = \frac{16.5 \ miles \ +\ 5.5 \ miles}{\frac{16.5 \ mi}{21.8 \ mi/h}\ \ +\ \ \frac{5.5 \ mi}{v} } \\\\13.8 \ mi/h = \frac{(16.5 \ miles \ +\ 5.5 \ miles)}{(\frac{16.5 \ mi}{21.8 \ mi/h}\ \ +\ \ \frac{5.5 \ mi}{v} ) }\\\\13.8 = \frac{(16.5 \ +\ 5.5 )}{(\frac{16.5 }{21.8 }\ \ +\ \ \frac{5.5 }{v} ) }\\\\13.8 = \frac{22 }{0.757\ \ +\ \ \frac{5.5 }{v} }\\\\13.8 (0.757\ \ +\ \ \frac{5.5 }{v} ) = 22\\\\[/tex]

[tex]10.446 + \frac{75.9}{v} = 22\\\\\frac{75.9}{v} = 22-10.446\\\\\frac{75.9}{v} = 11.554\\\\v = \frac{75.9}{11.554} \\\\v = 6.57 \ mi/h[/tex]

Thus, the average speed for this additional distance is 6.57 mi/h

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Final answer:

The runner must run at an average speed of 6.57 mi/h to achieve the overall average speed of 13.8 mi/h for the entire biathlon race.

Explanation:

To solve for the average running speed needed to achieve an overall average speed of 13.8 mi/h in the biathlon, we will use the concept of weighted averages. The total time for both cycling and running can be expressed in terms of the distances traveled and the speeds for each segment.

First, we calculate the time taken to complete the cycling portion, which is 16.5 miles at an average speed of 21.8 mi/h. The formula for time is distance divided by speed:


Time (cycling) = Distance (cycling) / Speed (cycling) = 16.5 miles / 21.8 mi/h = 0.7565 hours

Next, we need to find the running speed. Let's call the average running speed 'R'. Using the same formula for time:


Time (running) = Distance (running) / Speed (running) = 5.5 miles / R

The overall average speed for the entire race is the total distance divided by the total time. The total distance is 16.5 miles + 5.5 miles = 22 miles. Let 'T' represent the total time for the race.

Average speed for the entire race = Total distance / Total time = 22 miles / T

Given that the overall average speed must be 13.8 mi/h, we set up the equation:

13.8 mi/h = 22 miles / T

Now we can express 'T' as the sum of the cycling time and running time:

T = Time (cycling) + Time (running) = 0.7565 hours + (5.5 miles / R)

Substitute this into our average speed equation:

13.8 mi/h = 22 miles / (0.7565 hours + (5.5 miles / R))

Now, we solve for 'R', which represents the average running speed. We cross multiply and isolate 'R' to obtain:

(13.8 mi/h) (0.7565 hours + (5.5 miles / R)) = 22 miles

This simplifies to:

10.4469 hours + 75.9 miles / R = 22 miles

Subtract 10.4469 hours from both sides:

75.9 miles / R = 11.5531 miles

Finally, divide 75.9 by 11.5531 to find the average running speed 'R':

R = 6.57 mi/h

The runner must run at an average speed of 6.57 mi/h to have an overall average speed of 13.8 mi/h for the biathlon.

Harper has $15to spend at the grocery store.She is going to buy bags of fruit that cost $4.75 each and one box of crackers that costs$3.50.Write and solve an inequality that models this situation and could be used to determine the maximum number of bags of fruit Harper can buy

Answers

Answer:

The maximum number of fruits bag Harper can buy are 3.

Step-by-step explanation:

Let there be x bags of fruits.

Let there be y boxes of chocolates

Cost of 1 bag of fruit = $4.75

So, cost of x bags = $4.75x

Cost of one box of crackers costs = $3.50

As per the given situation, the inequality forms:

[tex]4.75x+3.50y\leq 15[/tex]

So, the maximum number of bags of fruit Harper can buy, is when she buys no box of cracker.

So, putting y = 0 in above inequality , we have,

[tex]4.75x+3.50(0)\leq 15[/tex]

=> [tex]4.75x+0\leq 15[/tex]

=> [tex]4.75x \leq 15[/tex]

[tex]x\leq 3.15[/tex] rounding to 3.

Hence, the maximum number of fruits bag Harper can buy are 3.

Beginning with Newton's second law of motion, derive the equations of motion for a projectile fired from altitude h above the ground at an angle e to the horizontal and with initial speed equal to vo.

Answers

Answer:

Considering the fire point at (0,h), x-direction positive to the right (→) and y-direction positive to up (↑) and the only force acting after fire is the projectile weight = -mg in the y-direction.

[tex]\\ x(t)=Vo*cos(e)*t\\ v_x(t)=Vo*cos(e)\\ a_y(t)=0\\ y(t)=h+Vo*sin(e)*t-\frac{g}{2}t^{2}\\ v_x(t)=Vo*sin(e)-gt\\ a_y(t)=-g[/tex]

Step-by-step explanation:

First, we apply the Second Newton's Law in both x and y directions:

x-direction:

[tex]\sum F_x= m\frac{dv_x}{dt} =0[/tex]

Integrating we have

[tex]\int\limits^{V_x} _{V_{0x}}{}\, dV_x =\int\limits^{t} _0{0}\, dt\\ V_{0x}=Vo*cos(e)\\ V_x(t)=Vo*cos(e)[/tex]

Taking into account that a=(dv/dt) and v=(dx/dt):

[tex]a_x(t)=\frac{dV_x(t)}{dt}=0\\V_x(t)=\frac{dx(t)}{dt}-->\int\limits^x_0 {} dx = \int\limits^t_0 {Vo*cos(t)} \, dt \\x(t)=Vo*cos(e)*t[/tex]

y-direction:

[tex]\sum F_y= m\frac{dv_x}{dt} =-mg[/tex]

Integrating we have

[tex]\int\limits^{V_y} _{V_{0y}}{}\, dV_y =\int\limits^{t} _0 {-g} \, dt\\ V_{0y}=Vo*sin(e)\\ V_y(t)=Vo*sin(e)-g*t[/tex]

Taking into account that a=(dv/dt) and v=(dy/dt):

[tex]a_y(t)=\frac{dV_y(t)}{dt}=-g\\V_y(t)=\frac{dy(t)}{dt}-->\int\limits^y_h {} dy = \int\limits^t_0 {(Vo*sin(t)-g*t)} \, dt \\y(t)=h+Vo*sin(e)*t-\frac{g}{2}t^{2}[/tex]

Consider the differential equation y'+\lambda y=e^{-t}, when \lambda is some constant.

(a) Find all values of \lambda such that all solutions tend to zero as t \rightarrow infinity .

(b) At least one solution goes to zero as t \rightarrow infinity .

Answers

Answer:

Part a) value of [tex]\lambda [/tex] such that all the solutions tend to zero equals 1.

Part b)

For a particular solution to tend to 0 will depend on the boundary conditions.

Step-by-step explanation:

The given differential equation is

[tex]y'+\lambda y=e^{-t}[/tex]

This is a linear differential equation of first order of form [tex]\frac{dy}{dt}+P(t)\cdot y=Q(t)[/tex] whose solution is given by

[tex]y\cdot e^{\int P(t)dt}=\int e^{\int P(t)dt}\cdot Q(t)dt[/tex]

Applying values we get

[tex]y\cdot e^{\int \lambda dt}=\int e^{\int \lambda dt}\cdot e^{-t}dt\\\\y\cdot e^{\lambda t}=\int (e^{(\lambda -1)t})dt\\\\y\cdot e^{\lambda t}=\frac{e^{(\lambda -1)t}}{(\lambda -1)}+c\\\\\therefore y(t)=\frac{c_{1}}{\lambda -1}(e^{-t}+c_{2}e^{-\lambda t})[/tex]

here [tex]c_{1},c_{2}[/tex] are arbitrary constants

part 1)

For all the function to approach 0 as t approaches infinity we have

[tex]y(t)=\lim_{t\to \infty }[\frac{c_{1}}{\lambda -1}(e^{-t}+c_{2}e^{-\lambda t})]\\\\y(\infty )=\frac{c_{1}}{\lambda -1}=0\\\\\therefore \lambda =1[/tex]

Part b)

For a particular solution to tend to 0 will depend on the boundary conditions as [tex]c_{1},c_{2}[/tex] are arbitrary constants

R1 R3 in an electric instrument called a Wheatstone bridge electric resistances are related byR1/R2=R3/R4. Find R 2 if R1 = 10.00 Ω R3-6470, and R2 = R4-15.0 . If necessary, round to two decimal places.

Answers

Answer:

R2 = 43.03 ohms

Step-by-step explanation:

If R2=R4-15, then R4 = R2+15

According to the Wheastone bridge equation we have:

[tex]\frac{R1}{R2} =\frac{R3}{R4}\\\frac{10}{R2} =\frac{6470}{R2+15}\\\\10*(R2+15) = 6470*R2\\10*R2+150 = 6470*R2\\150=(6470-15)*R2\\R2=\frac{6455}{150}= 43.03333[/tex]

Which expressions are equal to 11x10^3? Select all that apply.

A. 11x100
B. 11,000
C. 11x10x10x10
D. 33,000
E. 11x11x11

Answers

Answer: A,B,C all apply since they all equal 11000 :)

The required simplified expression for 11 x 10³ is 11,000. Option B is correct.

Given that,
A simplified expression form of the expression 11 x 10³, is to be determined.

What is simplification?

The process in mathematics to operate and interpret the function or expression to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
= 11 x 10³
Since 10³ = 10 x 10 x 10 = 1000
= 11 x 1000
= 11,000

Thus, the required simplified expression for 11 x 10³ is 11,000. Option B is correct.

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Show that n+1C = nCr-1 + nr.

Answers

Answer:  The proof is given below.

Step-by-step explanation:  We are given to show that the following equality is true :

[tex]^{n+1}C_r=^nC_{r-1}+^nC_r.[/tex]

We know that

the number of combinations of n different things taken r at a time is given by

[tex]^nC_r=\dfrac{n!}{r!(n-r)!}.[/tex]

Therefore, we have

[tex]R.H.S.\\\\=^nC_{r-1}+^nC_r\\\\\\=\dfrac{n!}{(r-1)!(n-(r-1))!}+\dfrac{n!}{(r)!(n-r)!}\\\\\\=\dfrac{n!}{(r-1)!(n-r+1)!}+\dfrac{n!}{(r)!(n-r)!}\\\\\\=\dfrac{n!}{(r-1)!(n-r+1)(n-r)!}+\dfrac{n!}{r(r-1)!(n-r)!}\\\\\\=\dfrac{n!}{(r-1)!(n-r)!}\left(\dfrac{1}{n-r+1}+\dfrac{1}{r}\right)\\\\\\=\dfrac{n!}{(r-1)!(n-r)!}\left(\dfrac{r+n-r+1}{(n-r+1)r}\right)\\\\\\=\dfrac{n!}{(r-1)!(n-r)!}\times\dfrac{n+1}{(n-r+1)r}\\\\\\=\dfrac{(n+1)!}{r!(n-r+1)!}\\\\\\=\dfrac{(n+1)!}{r!((n+1)-r)!}\\\\\\=^{n+1}C_r\\\\=L.H.S.[/tex]

Thus, [tex]^{n+1}C_r=^nC_{r-1}+^nC_r.[/tex]

Hence proved.

Which of the following sets are equal to {x | x < 9 and x >2}

Question 5 options:

{3, 4, 5, 6, 7, 8}

{2, 3, 4, 5, 6, 7, 8, 9}

{8, 7, 6, 5, 3}

{ }

{2, 3, 4, 5, 6, 7}

Answers

Answer:

  {3, 4, 5, 6, 7, 8}

Step-by-step explanation:

Integers that are less than 9 and greater than 2 include the integers 3 through 8.

The correct set equal to {x | x < 9 and x > 2} is {3, 4, 5, 6, 7, 8}, as it includes all the integers that satisfy the given condition.

The given set is {x | x < 9 and x > 2}, which translates to all numbers greater than 2 and less than 9. When comparing this to the options provided, we need to ensure that the numbers within the set are all and only the integers that satisfy these conditions, regardless of their order. The set {3, 4, 5, 6, 7, 8} matches this description exactly, as it includes all the integers that are greater than 2 and less than 9. Sets in mathematics do not consider the order of elements; they only consider the presence of elements. Therefore, the correct option that is equal to the given set is {3, 4, 5, 6, 7, 8}.

The height, h, of a ball that is tossed into the air is a function of the time, t, it is in the air. The height in feet for t seconds is given by the function h(t)=−16t2+96t

What is the domain of the function?

Question 8 options:

a)

[0, [infinity] )

b)

(-[infinity], [infinity])

c)

(0, [infinity])

d)

(0, 5)

e)

none

Answers

Answer:

e) none

Step-by-step explanation:

The first thing that we need to realise is that this question is set to a practical example of a ball being tossed into the air for a period of time. Thus, we know that:

a) time cannot be negative

b) a ball cannot travel a negative distance in height from where it was tossed it into the air (given that this starting position is also the ground)

In the context of what the problem asks us to achieve, which is to find the domain, we now know that:

a) t ≥ 0

b) the function h(t) is only practical when h(t) ≥ 0

In other words, we know that the domain starts at t = 0, however we need to find when the ball drops back onto the ground. We can do this by solving h(t) = 0:

h(t) = -16t^(2) + 96t

0 = -16t^(2) + 96t

0 = -16t(t - 6) (Factorise -16t^(2) + 96t)

So, now we get:

-16t = 0, therefor t = 0

or

t - 6 = 0, therefor t = 6

Thus, the ball is on the ground at t = 0 seconds and t = 6 seconds; it is between these two values of t that the domain exists and that the problem is practical.

Now, looking at the multiple choice options, it seems as though none of them are correct, therefor the answer would be e) none.

The other way to work through this question (particularly if it is just multiple choice) is that, after realising that the ball is tossed into the air at t = 0 seconds and then drops at some point later, we could already discount a), b) and c) as answers since they include infinity in the domain, which is not practical for this problem.

Then, we could substitute t = 5 into the equation to get:

h(t) = -16(5)^2 + 96*5

h(t) = -16*5*5 + 96*5

h(t) = -80*5 + 96*5

Since we need h(t) to be 0 at the end value of the domain, this is not the correct answer. Thus, the answer is e) none.

A small business owner converts 120 J of her internal energy to electricity by peddling a bike for 1 second, which for a conversion efficiency of 40 percent, amounts to a power output of 48 watts. if she peddles a bike for 8 hours each day about how much money can she in one day assuming she sells for the electricity for 10.43 cents/ kWh

Answers

Answer:

4.00512 cents

Step-by-step explanation:

Given:

Power output = 48 Watts

Time for which owner paddles = 8 hours

Selling price of the electricity = 10.43 cents/kWh

Now,

Power = Energy × Time

or

Power generated = 48 × 8 = 384 Wh = 0.384 kWh

now,

Money earned will be = Power generated × selling price per kWh

or

Money earned = 0.384 kWh ×  10.43 cents/ kWh = 4.00512 cents

A business magazine conducted a survey of 751 employees who had been at their current employer for 5 or more years. Of these employees, 295 responded that they were bored in their current position. Create a 99% confidence interval for the proportion of employees who have been with their current employer for 5 or more years and reported being bored in their current position. Use Excel to create the confidence interval, rounding to four decimal places.

Answers

Answer:

the [tex]95\%[/tex] confidence interval for the population proportion is:

[tex]\left [0.3469, \hspace{0.1cm} 0.4387\right][/tex]

Step-by-step explanation:

To solve this problem, a confidence interval of [tex](1-\alpha) \times 100\%[/tex] for the population proportion will be calculated.

[tex]$$Sample proportion: $\bar P=0.3928$\\Sample size $n=751$\\Confidence level $(1-\alpha)\times100\%=99\%$\\$\alpha: \alpha=0.01$\\Z values (for a 99\% confidence) $Z_{\alpha/2}=Z_{0.005}=2.5758$\\\\Then, the (1-\alpha) \times 100\%$ confidence interval for the population proportion is given by:\\\\\left [\bar P - Z_{\frac{\alpha}{2}}\sqrt{\frac{\bar P(1- \bar P)}{n}}, \hspace{0.3cm}\bar P + Z_{\frac{\alpha}{2}}\sqrt\frac{\bar P(1- \bar P)}{n} \right ][/tex]

Thus, the [tex]95\%[/tex] confidence interval for the population proportion is:

[tex]\left [0.3928 - 2.5758\sqrt{\frac{0.3928(1-0.3928)}{751}}, \hspace{0.1cm}0.3928 + 2.5758\sqrt{\frac{0.3928(1-0.3928)}{751}} \right ]=\left [0.3469, \hspace{0.1cm} 0.4387\right][/tex]

A three inch diameter pulley on an electric motor that runs at 1800
revolutions per minute is connected by a belt to a six inch
diameter pullley on a saw arbor.
angular speed = central angle/time, arc length = (central
angle)(radius)

a. Find the angular speed (in radians per minute) of each. ( 3 in
and 6 in pully)

b. find the revolutions per minute of the saw.

Answers

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ.  Then the tangential speed V is related to angular speed  ω as:

[tex]V=R\omega[/tex]

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

[tex]\omega_1 R_1 = \omega_2 R_2\\[/tex]

[tex]\omega_2 = \omega_1 \frac{R_1}{R_2} =1800RPM* \frac{3}{6}= 900RPM[/tex]

We need to convert RPM to radias per minute. One revolution is 2π radians, then:

[tex]\omega_1 = 1800*2\pi \frac{radians}{min} = 11,309.7\frac{radians}{min}[/tex]

[tex]\omega_2 = 5654.7 \frac{radians}{min}[/tex]

The saw rotates with the same angular speed as the 6 inch pulley: 900RPM

Final answer:

a. The angular speed of the 3 inch pulley is 3600π radians/min and the angular speed of the 6 inch pulley is 7200π radians/min. b. The revolutions per minute of the saw is 900.

Explanation:

a. To find the angular speed in radians per minute, we need to convert the revolutions per minute to radians per minute. Since 1 revolution is equal to 2π radians, we can calculate the angular speed of the 3 inch pulley as follows:

Angular speed = (Revolutions per minute) x (2π radians per revolution)

Angular speed = (1800 rev/min) x (2π radians/rev) = 3600π radians/min

Similarly, for the 6 inch pulley:

Angular speed = (Revolutions per minute) x (2π radians per revolution)

Angular speed = (1800 rev/min) x (2π radians/rev) = 7200π radians/min

b. To find the revolutions per minute of the saw, we need to use the ratio of the diameters of the two pulleys. Since the diameter of the 6 inch pulley is twice the diameter of the 3 inch pulley, the revolutions per minute of the saw will be half of the revolutions per minute of the motor. Therefore, the revolutions per minute of the saw is 900.

Find the equation of the line that pass through the points (4,8) and (6,2

Answers

Answer:

3x + y = 20

Step-by-step explanation:

The equation of line passing through two points is determined by formula:

[tex]y-y_{1}=\frac{y_{2}-y_{1}}{x_{2} - x_{1}}(x - x_{1})[/tex]

Here, (x₁ , y₁) = (4, 8)

and (x₂, y₂) = (6, 2)

Putting these value in above formula. We get,

[tex]y-8=\frac{2-8}{6 - 4}(x - 4)[/tex]

⇒ [tex]y-8=\frac{-6}{2}(x - 4)[/tex]

⇒ ( y - 8) = -3 (x - 4)

⇒ y - 8 = -3x + 12

⇒ 3x + y = 20

which is required equation.

Approximately 0.02% of a 100-mg dose of the drug miglitol (Glyset) has been shown to appear in human breast milk. Calculate the quantity of drug detected, in milligrams, following a single dose.

Answers

Approximately 0.02 mg of the drug miglitol (Glyset) would be detected in human breast milk.

Given that, approximately 0.02% of a 100-mg dose appears in human breast milk.

To calculate the quantity of drug detected in milligrams following a single dose, we can use the given information that approximately 0.02% of a 100-mg dose appears in human breast milk.

Step-by-step calculation:

1. Convert 0.02% to a decimal by dividing it by 100: 0.02/100 = 0.0002.

2. Multiply the decimal by the dose of the drug: 0.0002 * 100 mg = 0.02 mg.

Therefore, following a single dose, approximately 0.02 mg of the drug miglitol (Glyset) would be detected in human breast milk.

To learn more about the percentage;

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Calculate: ( Round two decimal places for final answer)

1880 Milliliters(mL)=___pints(pts)

Answers

Answer:

1880 Milliliters(mL) = 3.97 pints

Step-by-step explanation:

This can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

Each ml has 0.002 pints. How many pints are there in 1880mL. So:

1ml - 0.002 pints

1880ml - x pints

[tex]x = 1800*0.002[/tex]

[tex]x = 3.97[/tex] pints

1880 Milliliters(mL) = 3.97 pints

elena has 60 colored pencils, and lucy has 26 colored pencils. howmany pencils must elena give to lucy so that elena will have 4 more colored pencils than lucy?

Answers

Answer:  15

Step-by-step explanation:

Given : Elena has 60 colored pencils, and Lucy has 26 colored pencils.

Total colored pencils = [tex]60+26=86[/tex]

Let 'x' denotes the number of pencils Lucy has when she get pencils from Elena , and Elena left with 'y' pencils.

Then, by considering the given information we have the following system :-

[tex]\text{Total pencils : }x+y=86-----(1)\\\\\text{Colored pencils left with Elena : }y=4+x-----(2)[/tex]

We can rewritten the equation (2) as

[tex]y-x=4[/tex]

Now, add equation (1) and (2), we get

[tex]2y=90\\\\\Rightarrow\ y=\dfrac{90}{2}=45[/tex]

Put the value of y in (2), we get

[tex]45=4+x\\\\\Rightarrow\ x=45-4=41[/tex]

It means, the number of pencils Lucy has now =41

The number of pencils Elena give to Lucy= [tex]41-26=15[/tex]

Hence, Elena must give 15 pencils to lucy so that elena will have 4 more colored pencils than Lucy.

list the steps that you could use to solve?

x 4
— = —
3 9

Answers

Answer:

multiply by 3

Step-by-step explanation:

[tex]\dfrac{x}{3}=\dfrac{4}{9} \qquad\text{has x-coefficient $\frac{1}{3}$}[/tex]

Multiply by the reciprocal of the x-coefficient. Then you have ...

[tex]x=\dfrac{4}{3}[/tex]

Indicate which of the following are propositions (assume that x and y are real numbers).

a) The integer 36 is even.

b) Is the integer 315 − 8 even?

c) The product of 3 and 4 is 11.

d) The sum of x and y is 12.

e) If x > 2, then x 2 > 3.

f) 52 − 5 + 3

Answers

Answer:

a) It is a proposition .

b) It is not a proposition.

c) It is a proposition.

d) It is a proposition.

e) It is a proposition.

f) It is not a proposition.

Step-by-step explanation:

a) The integer 36 is even: It is a proposition, since this statement can be assigned a true value. If 36 is an even number, the statement is true, but if 36 is an odd number, the statement is false.

b) Is the integer 315 - 8 even ?: It is not a proposition, since this question cannot be assigned a true value.

c) The product of 3 and 4 is 11: It is a proposition, since this statement can be assigned a true value. If 3x4 = 11, the statement is true, but if 3x4 is not 11, the statement is false.

d) The sum of x and y is 12: It is a proposition, since, this statement can be assigned a true value. If x + y = 12, the statement is true, but if x + y is not 12, the statement is false.

e) If x> 2, then x 2> 3: It is a proposition, since, this statement can be assigned a truth value.

f) 52 - 5 + 3: It is not a proposition, since this statement cannot be assigned a true value.

Solve the linear equation: 3.4 + 2(9.7 – 4.8x) = 61.2 What are the possible steps involved in solving this equation? Check all that apply. Add 3.4 and 2. Distribute 2 to 9.7 and −4.8x. Combine 3.4 and 19.4. Divide both sides by 22.8. Subtract 22.8 from both sides. Divide both sides by −9.6.

Answers

Answer:

Distribute 2 to 9.7 and −4.8x. Combine 3.4 and 19.4. Subtract 22.8 from both sides. Divide both sides by −9.6

Step-by-step explanation:

Here is the recommended solution method:

  3.4 + 2(9.7 – 4.8x) = 61.2 . . . . . given

  3.4 + 19.4 - 9.6x = 61.2 . . . . . . . distribute 2 to 9.7 and -4.8x

  22.8 - 9.6x = 61.2 . . . . . . . . . . . . combine 3.4 and 19.4

  -9.6x = 38.4 . . . . . . . . . . . . . . . . . subtract 22.8 from both sides

  x = -4 . . . . . . . . . . . . . . . . . . . . . . divide both sides by -9.6

_____

Alternate solution method using different steps

You can also "undo" what is done to the variable, in reverse order. The variable has these operations performed on it:

multiply by -4.8add 9.7multiply that sum by 2add 3.4 to the product

So, another possible solution method is this:

  3.4 + 2(9.7 – 4.8x) = 61.2 . . . . . given

  2(9.7 -4.8x) = 57.8 . . . . . . . . . . . add the opposite of 3.4 (undo add 3.4)

  9.7 -4.8x = 28.9 . . . . . . . . . . . . . divide by 2 (undo multiply by 2)

  -4.8x = 19.2 . . . . . . . . . . . . . . . . . add the opposite of 9.7 (undo add 9.7)

  x = -4 . . . . . . . . . . . . . . . . . . . . . . divide by -4.8 (undo multiply by -4.8)

Linear equation solutions are indeed the points where the lines or planes describing various linear equations intersect or connect. The candidate solution of a set of linear equations is indeed the collection of all feasible solution' values again for variables, and further calculation can be defined as follows:

Given:

[tex]\to \bold{3.4 + 2(9.7 -4.8x) = 61.2}\\\\[/tex]

To find:

Solve the linear equation=?

Solution:

[tex]\to \bold{3.4 + 2(9.7 -4.8x) = 61.2}\\\\\to \bold{3.4 + 19.4 -9.6x = 61.2}\\\\\to \bold{22.8 -9.6x = 61.2}\\\\\to \bold{ -9.6x = 61.2- 22.8}\\\\\to \bold{ -9.6x = 38.4}\\\\\to \bold{ x =- \frac{38.4}{9.6}}\\\\\to \bold{ x =- 4}\\\\[/tex]

Therefore, the steps are:

Distribute 2 to [tex]\bold{9.7\ and\ -4.8x}[/tex].    

Combine [tex]\bold{3.4\ and \ 19.4}[/tex].              

Subtract [tex]22.8[/tex] from both sides.      

Divide both sides by[tex]-9.6[/tex].            

Learn more:

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