If the particle is under the Simple Harmonic Motion, the wave is considered to be sinusoidal wave.
Explanation:
A body is considered to be performing the Simple Harmonic Motion if it repeats its motion in a particular path with a specific time period. The two and fro motion of the pendulum about a fixed mean position is termed as the Simple Harmonic Motion.
The motion of the simple pendulum repeats itself after a particular time period and it continuously retraces its path during the motion. Therefore, it is termed as the simple harmonic motion.
The wave depicting the motion of a body performing the simple harmonic motion is shown in the sinusoidal manner. The motion of the body from its mean position to its extreme and then from extreme position to its mean position shows the positive cycle of the sinusoidal waveform.
The motion of the pendulum on the other side of the mean position of the pendulum represents the other half of the sinusoidal waveform.
Thus, If the particle is under the Simple Harmonic Motion, the wave is considered to be sinusoidal wave.
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A property is a characteristic of a substance that can be observed and does not change the identity of the substance brainly.com/question/859623The amount of kinetic energy an object has depends on its brainly.com/question/137098Choose the 200 kg refrigerator. Set the applied force to 400 n (to the right). Be sure friction is turned off. What is the net force acting on the refrigerator brainly.com/question/4033012Answer Details:
Grade: High School
Chapter: Simple Harmonic Motion
Subject: Physics
Keywords:
simple, harmonic, SHM, motion, pendulum, oscillates, mean position, extreme, repeats, time period, sinusoidal.
Three people are pushing a 500 kg of box in the same direction. applied forces are 30 n, 20 n, and 10 n respectively. if the acceleration of the box is 0.02 m/s2, what is the magnitude of a force created by friction?
A circular disk has surface charge density 24 nc/cm2 what will the surface charge density be if the radius of the disk is doubled?
While parachuting, a 66.0-kg person experiences a downward acceleration of 2.60 m/s2. 1) what is the downward force on the parachute from the person? (express your answer to three significant figures?
Final answer:
The downward force on the parachute from the 66.0 kg person experiencing a downward acceleration of 2.60 m/s2 is 171.6 newtons, calculated using Newton's second law of motion (F = ma).
Explanation:
The question asks for the downward force on the parachute from a person with a mass of 66.0 kg experiencing a downward acceleration of 2.60 m/s2. To find this force, we use Newton's second law of motion, which states that force (F) equals mass (m) times acceleration (a), or F = ma.
To calculate the force, we multiply the person's mass (66.0 kg) by the given acceleration (2.60 m/s2):
F = 66.0 kg × 2.60 m/s2
= 171.6 N
The downward force exerted on the parachute by the person is therefore 171.6 newtons, expressed to three significant figures.
A Geiger counter is like an electroscope that discharges whenever ions formed by a radioactive particle produce a conducting path. A typical Geiger counter consists of a thin conducting wire of radius 0.002 cm stretched along the axis of a conducting cylinder of radius 2.0 cm. The wire and the cylinder carry equal and opposites charges of 8.0 x 10-10 C all along their length of 10.0 cm. What is the magnitude of the electric field at the surface of the wire
The magnitude of the electric field at the surface of the wire in the Geiger counter can be found using the charge per unit length and the formula E = (1/(2πε0)) * (λ/r). Substituting the given values into the formula will yield the electric field at the wire's surface.
The student asked about calculating the magnitude of the electric field at the surface of the wire in a Geiger counter. To solve this, we will employ the formula for the electric field (E) generated by an infinitely long charged wire, which is given by E = (1/(2πε0)) * (λ/r), where λ is the charge per unit length and r is the radial distance from the wire. In this case, the charge per unit length λ is the total charge divided by the length of the wire, and r is the radius of the wire.
Given: Charge (Q) = 8.0 x 10-10 C, Length (L) = 10.0 cm = 0.1 m, and Wire radius (a) = 0.002 cm = 0.00002 m.
First, calculate the charge per unit length: λ = Q/L = (8.0 x 10-10 C) / (0.1 m) = 8.0 x 10-9 C/m.
Next, calculate the electric field using the radius of the wire (a) as radial distance (r): E = (1/(2πε0)) * (λ/a).
Using the value for the vacuum permittivity ε0 (approximately 8.854 x 10-12 C2/N·m2), the electric field on the surface of the wire is computed to be:
E = (1/(2π(8.854 x 10-12))) * (8.0 x 10-9 / 0.00002) N/C.
Simplifying this expression gives us the electric field at the surface of the wire.
Using the given values, the magnitude of the electric field at the surface of the wire (r = 0.002 cm or 0.00002 m) and L = 10 cm or 0.1 m is calculated as follows:
Convert the radius to meters: r = 0.002 cm = 0.00002 m.
Plugging in the values: E = (8.0 x 10-10 C) / (2π * 8.854 x 10-12 C2/Nm2 * 0.00002 m * 0.1 m).
Calculate the electric field: E = 2.87 x 106 N/C.
The magnitude of the electric field at the surface of the wire in the Geiger counter is therefore 2.87 x 106 Newtons per Coulomb (N/C).
The magnitude of the electric field at the surface of the wire is approximately [tex]\( 7.19 \times 10^{6} \, \text{N/C} \)[/tex].
The magnitude of the electric field at the surface of the wire is given by the formula:
[tex]\[ E = \frac{\sigma}{\varepsilon_0} \][/tex]
where [tex]\( \sigma \)[/tex] is the surface charge density of the wire, and [tex]\( \varepsilon_0 \)[/tex]is the vacuum permittivity [tex](\( 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \)).[/tex]
The surface charge density [tex]\( \sigma \)[/tex] can be calculated by dividing the total charge [tex]\( Q \)[/tex] by the surface area [tex]\( A \)[/tex] of the wire. The surface area of a cylinder is given by [tex]\( A = 2\pi r h \)[/tex], where [tex]\( r \)[/tex] is the radius and [tex]\( h \)[/tex] is the height (or length in this case) of the cylinder.
Given:
- Radius of the wire, [tex]\( r = 0.002 \, \text{cm} = 2 \times 10^{-5} \, \text{m} \) (since 1 cm = 0.01 m)[/tex]
- Length of the wire, [tex]\( h = 10.0 \, \text{cm} = 0.1 \, \text{m} \)[/tex]
- Total charge on the wire, [tex]\( Q = 8.0 \times 10^{-10} \, \text{C} \)[/tex]
First, we convert the radius from centimeters to meters for consistency in units:
[tex]\[ r = 0.002 \, \text{cm} \times \frac{1 \, \text{m}}{100 \, \text{cm}} = 2 \times 10^{-5} \, \text{m} \][/tex]
Now, we calculate the surface area of the wire:
[tex]\[ A = 2\pi r h = 2\pi (2 \times 10^{-5} \, \text{m})(0.1 \, \text{m}) \][/tex]
[tex]\[ A = 4\pi \times 10^{-6} \, \text{m}^2 \][/tex]
Next, we calculate the surface charge density [tex]\( \sigma \)[/tex]:
[tex]\[ \sigma = \frac{Q}{A} = \frac{8.0 \times 10^{-10} \, \text{C}}{4\pi \times 10^{-6} \, \text{m}^2} \][/tex]
[tex]\[ \sigma = \frac{8.0 \times 10^{-10} \, \text{C}}{4\pi \times 10^{-6} \, \text{m}^2} \approx \frac{8.0 \times 10^{-10}}{12.56637 \times 10^{-6} \, \text{m}^2} \][/tex]
[tex]\[ \sigma \approx 6.3662 \times 10^{-5} \, \text{C/m}^2 \][/tex]
Finally, we calculate the magnitude of the electric field at the surface of the wire:
[tex]\[ E = \frac{\sigma}{\varepsilon_0} = \frac{6.3662 \times 10^{-5} \, \text{C/m}^2}{8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2} \][/tex]
[tex]\[ E \approx 7.19 \times 10^{6} \, \text{N/C} \][/tex]
Therefore, the magnitude of the electric field at the surface of the wire is approximately [tex]\( 7.19 \times 10^{6} \, \text{N/C} \)[/tex].
A bolt is dropped from a bridge under construction, falling 80 m to the valley below the bridge. (a) how much time does it take to pass through the last 17 % of its fall? what is its speed (b) when it begins that last 17 % of its fall and (c) just before it reaches the ground?
Referring to the map of the temperature field in the room, where was the warmest field found?
The warmest field on a temperature map is indicated by warmer colors such as red or orange. On maps like those from the WMAP spacecraft, red represents higher temperatures. In thermographic maps of buildings, warmer areas show where heat transfer is most severe.
Explanation:The warmest field on a map showing temperature variations can typically be found in regions marked with a warmer color, such as red or orange, indicating higher temperatures. In the context of the map used by the WMAP spacecraft to show fluctuations in the cosmic microwave background, red represents areas of higher temperature and higher density. Similarly, thermographic maps of buildings, like Figure 1.32, use color to indicate variations in temperature, with warmer areas potentially signifying regions where heat transfer is most severe, such as through windows.
It's important to carefully analyze the colors and legends provided on the map to determine the precise locations of the warmest fields. When maps show global temperature changes, such as Figure 24.9.5, the land areas and the Arctic are noted for having experienced the greatest increases in temperature relative to mid-20th-century baseline values.
how did the world form
Why is it important to know the direction of the force applied to a moving object and the direction in which the object is moving when determining the work done on the object?
A. Only the component of the force perpendicular to the motion is used to calculate the work.
B. If the force acts in the same direction as the motion, then no work is done.
C. When there is an angle between the two directions, the cosine of the angle must be considered.
D. A force at a right angle to the motion requires the use of the sine of the angle.
Answer:
C. When there is an angle between the two directions, the cosine of the angle must be considered.
Explanation:
I can confirm answer is C.
After watching an advertisement for hand sanitizer on television, Ben decided to see just how effective the advertised hand sanitizer really was. Ben used warm water as his control. He compared the advertised sanitizer with two brands of hand soap. In all four trials he rubbed his hands together for two minutes. After using the three products and the control, he cultured the bacteria on his hands. He recorded the number of bacterial cultures that appeared on each culture plate. Ben's results can be seen in the data table. Ben concluded that both brands of soap were more effective in killing bacteria than the advertised hand sanitizer. What term BEST describes Ben's results for all four trials? A) biased B) inconclusive C) qualitative D) quantitative ASAPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Here Ben checked the quality of three sanitizer
He took all three and checked how much effective each soap is to kill the bacteria
He analyzed and find out that both brands of soap were more effective in killing bacteria than the advertised hand sanitizer
He took his decision on the basis of quality so this is qualitative analysis
option C is correct
Answer:
It is C
Explanation:
Which of these best explains the ability of small insects to walk on the surface of still water?
The ability of small insects to walk on water is due to surface tension, which results from cohesive forces among water molecules. This tension creates a thin 'skin' at the water's surface that can support the weight of light objects, such as insects.
The ability of small insects to walk on the surface of still water can be best explained by the phenomenon of surface tension. Surface tension is created due to the cohesive forces between water molecules at the liquid-air interface. This cohesion results in a thin 'skin' forming at the surface, which can support the weight of small insects like water striders. These insects distribute their weight over their long legs, ensuring that the force they exert is less than the surface tension holding the water molecules together, allowing them to effectively 'walk' on water.
An example of this can be seen when a paper clip or a thin razor blade is carefully placed on the surface of water without sinking, demonstrating the strength of surface tension.
Latent heat of fusion refers to which changes of state?
Answer:
Explanation:
The amount of energy required to change the state of matter at constant temperature is called latent heat.
There are two types of latent heat.
1. Latent heat of fusion: The amount of heat required to convert 1 kg of ice at 0 degree Celsius into 1 kg water at 0 degree Celsius is called latent heat of fusion.
2. Latent heat of vaporization: The amount of heat required to convert 1 kg of water at 100 degree Celsius into 1 kg steam at 100 degree Celsius is called latent heat of vaporization.
It takes Harry 34 s to walk from x1 = -11 m to x2 = -54 m .
Manuel is holding a 5kg box. How much force is the box exerting on him?In what direction
The box that Manuel is holding would exert a force of 49 N, directed downwards due to gravity. This calculation is done using the mass of the box and the acceleration due to gravity. According to Newton's third law, the force exerted by the box on Manuel would be in the opposite direction to which he lifts it.
Explanation:The box that Manuel is holding exerts a force equal to its weight due to gravity. The weight can be calculated using the formula F = mg, where F is the force, m is the mass of the object, and g is the acceleration due to gravity. In this case, the mass of the box is 5 kg and assuming the acceleration due to gravity to be approximately 9.8 m/s², we can calculate the force as F = (5 kg) * (9.8 m/s²) = 49 N.
As for the direction, the direction of the force is always directed downwards or towards the center of the Earth because gravity is the force involved in this situation. To be more specific, the force that the box exerts on Manuel is in the opposite direction to which he lifts it, according to Newton's third law of motion which states that for every action, there is an equal and opposite reaction. Therefore, the box exerts a downward force of 49 Newtons on Manuel.
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If you were creating an electrical circuit and ran out of wire what materials would you use
A:yarn
B:licorice strings
C:plastic knitting needle
D:tin foil
Solid-state storage is quickly replacing forms of _____ on small devices like the ipod.
A bag of sports equipment has a mass of 10.0 kilograms and a weight of
The weight of the bag of sports equipment is 98N
From the question,
We are to determine the weight of a bag of sports equipment that has a mass of 10.0 kg
The weight of an object with a given mass can be determined by using the formula
W = mg
Where
W is the weight
m is the mass
and g is the acceleration due to gravity (g = 9.8 m/s²)
From the given information,
m = 10.0 kg
∴ Weight of the bag of sports equipment,
W = 10.0 × 9.8
W = 98 N
Hence, the weight of the bag of sports equipment is 98N
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Andy has two strong magnetic marbles of equal size. What will happen when he puts the two marbles about 2 centimeters apart?
List at least 3 physical properties that the professor describes of his newly discovered flubber
Answer:
Flubber is a combination of two words Fluid+ Rubber. It means flubber has physical properties of both fluid and rubber(solid).
Physical properties of Flubber are as follows
1. It has elasticity like rubber
2. It can take the shape of the container in which it is filled. It does not have any particular shape like fluid.
3.It has viscoplastic nature
4. It is gelatinous
5. It flows under low pressure and can break when high pressure is applied on it.
If the kinetic energy of an electron is 4.1e-18 j, what is the speed of the electron? (you can use the approximate (nonrelativistic) formula here.)
Final answer:
To find the speed of an electron with a given kinetic energy of 4.1e-18 J, use the non-relativistic kinetic energy formula. The calculation reveals the speed is approximately 2.7 x 10⁶ m/s, validating the use of the classical formula.
Explanation:
If the kinetic energy of an electron is 4.1e-18 J, calculating the speed of the electron involves using the non-relativistic kinetic energy formula, KE = ½mv², where KE is the kinetic energy, m is the mass of the electron (9.11 x [tex]10^-^3^1[/tex] kg), and v is the speed of the electron.
First, rearrange the formula to solve for v, resulting in v = √(2KE/m). Substituting the given kinetic energy and the mass of an electron, we get v = √([tex]2*4.1e^-^1^8[/tex] J / (9.11 x [tex]10^-^3^1[/tex] kg)). Calculating this provides a numerical value for the electron's speed.
After calculating, you'll find that the electron's speed is approximately 2.7 x 10⁶ m/s, which is fast but still less than the speed of light, indicating that using the non-relativistic formula is justified in this scenario.
If you mix equal amounts of cyan pigments and magenta pigments on a sheet of white paper, what color will you see on the paper?
A. Red
B. Blue
C. Black
D. Yellow
E. Cyan
F. Magenta
A box is initially sliding across a frictionless floor toward a spring which is attached to a wall. the box hits the end of the spring and compresses it, eventually coming to rest for an instant before bouncing back the way it came. the work done by the spring on the box as the spring compresses is:
HURRY The compressed spring of a dart gun has potential energy of 50 J. If the spring constant is 200 N/m, what is the displacement of the spring?
A. 0.5 m
B. 0.2 m
C. 0.7 m
D. 0.4 m
Answer: its C on edge 2023. =0.7
Explanation: He's right just putting it in a quicker format.
A 0.55-kg ball, attached to the end of a horizontal cord, is revolved in a circle of radius 1.3 m on a frictionless horizontal surface. if the cord will break when the tension in it exceeds 75 n, what is the maximum speed the ball can have?
The force act on the body tries to attract the body inward towards the circle when the body is executing circular motion. The maximum value of speed will be 13.3 m/sec.
What is centripetal force?The force operating on an object in curvilinear motion directed toward the axis of rotation or center of curvature is known as centripetal force.
Newton is the unit of centripetal force.
The centripetal force is always perpendicular to the direction of displacement of the item. The centripetal force of an item traveling on a circular route always works towards the center of the circle.
Due to rotation, the tension is act in the chord which is equal to the centripetal force act the ball.
[tex]\rm T = F_c= \frac{mv^2}{r}[/tex]
Tension in the cord = T= 75 N
Centripetal force = [tex]F_c[/tex]
Mass of the ball= m= 0.55 Kg
Linear speed =v= ?
The radius of the circle.= r = 1.3 m
T is the maximum tension before the cord breaks. So according to the condition the obtained velocity will be ;
[tex]\rm v = \sqrt{\frac{Tr}{m} } \\\\ \rm v = \sqrt{\frac{75\times1.3}{0.55} }\\\\ \rm v = 13.3 \;m/sec[/tex]
Hence the maximum value of speed will be 13.3 m/sec.
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A wave travels through water at a speed of 3 m/s and has a frequency of 10 Hz. What is the wavelength of the wave?
V=wavelength*frequency
3 m/s=wavelength*10 Hz
3m/s=10 Hz
wavelength= .3
Answer:
Wavelength of the wave, λ = 0.3 m
Explanation:
It is given that,
The speed of the wave, v = 3 m/s
The frequency of the wave, f = 10 Hz
We know the relationship between the frequency, wavelength and the speed of the wave. Mathematically, it can be written as :
[tex]speed=frequency\times lambda[/tex]
or
[tex]v=f\times \lambda[/tex]
[tex]\lambda=\dfrac{v}{f}[/tex]
[tex]\lambda=\dfrac{3\ m/s}{10\ Hz}[/tex]
[tex]\lambda=0.3\ m[/tex]
Hence, the wavelength of the wave is 0.3 m
The pilot of an airplane traveling 180km/h wants to drop supplies to flood victims isolated on a patch of land 160 m below. The supplies should be dropped how many seconds before the plane is directly overhead?
To calculate the time the supplies should be dropped before the plane is directly overhead, use the equation for free-fall motion and plug in the values given. The supplies should be dropped approximately 5.06 seconds before the plane is directly overhead.
Explanation:To determine how many seconds before the plane is directly overhead the supplies should be dropped, we need to calculate the time it takes for the supplies to fall 160 m. We can use the equation for free-fall motion:
Time = sqrt((2 * distance) / g)
where distance is the height the supplies need to fall and g is the acceleration due to gravity. Plugging in the values, we get:
Time = sqrt((2 * 160 m) / 9.8 m/s²) ≈ 5.06 seconds
Therefore, the supplies should be dropped approximately 5.06 seconds before the plane is directly overhead.
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On a beautiful night in Washington D.C., you see a mirror image of the Washington Monument and surrounding scenery. What causes this mirror image?
A. Absorbed light
B. Reflected light
C. White light
D. Refracted light
when you squeeze the rubber bulb of a perfume atomizer how do you change the air pressure at the top of the tube
the record for a ski jump is 180 m set in 1989. Assume the jumper comes off the end of the ski jump horizontally and falls 90 m vertically before contacting the ground . what was the initial horizontal speed of the jumper?
On its own, a certain tow-truck has a maximum acceleration of 3.0 m/s2. what would be the maximum acceleration when this truck was towing a bus of twice its own mass?
The maximum acceleration would be 1.0 m/s² when this truck was towing a bus of twice its own mass
[tex]\texttt{ }[/tex]
Further explanationNewton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
[tex]\boxed {F = ma }[/tex]
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
initial acceleration = a₁ = 3.0 m/s²
mass of tow-truck = m₁ = m
mass of bus = m₂ = 2m
Asked:
final acceleration = a₂ = ?
Solution:
[tex]\texttt{Initial Force of Tow-Truck = Final Force of Tow-Truck }[/tex]
[tex]F_1 = F_2[/tex]
[tex]m_1 a_1 = m_2 a_2[/tex]
[tex]m (3.0) = (m + 2m) a_2[/tex]
[tex]3m = 3m (a_2)[/tex]
[tex]a_2 = 3m \div 3m[/tex]
[tex]\boxed{a_2 = 1.0 ~ \mathtt{ m/s^2}}[/tex]
[tex]\texttt{ }[/tex]
Conclusion :The maximum acceleration would be 1.0 m/s²
[tex]\texttt{ }[/tex]
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Answer detailsGrade: High School
Subject: Physics
Chapter: Dynamics
The cone cells of the human eye are sensitive to three wavelength ranges, which the eye interprets as blue (419nm), green (531 nm), and red(558nm). if the optic nerve in the eye requires 2.0x10^-17j of energy to initiate the sight impulses to the brain, how many photons of blue light, green light, and red
The number of photons of blue light required is 42 photons of blue light
The number of photons of green light required is 53 photons of green light
The number of photons of red light required is 56 photons of red light
The energy of one photon of light is calculated using the formula:
E = h * c / λ
where h, Planck's constant = 6.63 * 10⁻³⁴ Js
speed of light c = 3 * 10⁸ m/s
λ = wavelength of light
wavelength of blue light = 419 nm = 4.19 * 10⁻⁷ m
wavelength of green light = 531 nm = 5.31 * 10⁻⁷ m
wavelength of red light = 558 nm = 5.58 * 10⁻⁷ m
Number of photons of light = Energy of light / Energy of one photon of light
Energy of light required by optic nerve = 2.0 * 10⁻¹⁷ J
Energy of one photon of blue light,
E = (6.63 * 10⁻³⁴ Js * 3 * 10⁸ m/s) / 4.19 * 10⁻⁷ m = 4.74 * 10⁻¹⁹ J
Number of photons of blue light = 2.0 * 10⁻¹⁷ J / 4.74 * 10⁻¹⁹ J
Number of photons of blue light = 42 photons of blue light
Energy of one photon of green light,
E = (6.63 * 10⁻³⁴ Js * 3 * 10⁸ m/s) / 5.31 * 10⁻⁷ m = 3.74 * 10⁻¹⁹ J
Number of photons of green light = 2.0 * 10⁻¹⁷ J / 3.74 * 10⁻¹⁹ J
Number of photons of green light = 53 photons of green light
Energy of one photon of red light,
E = (6.63 * 10⁻³⁴ Js * 3 * 10⁸ m/s) / 5.58 * 10⁻⁷ m = 3.56 * 10⁻¹⁹ J
Number of photons of red light = 2.0 * 10⁻¹⁷ J / 3.56 * 10⁻¹⁹ J
Number of photons of red light = 56 photons of red light
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