When you balance a chemical reaction, you are making sure that the law of conservation of matter is obeyed?

Answer:

False.

Explanation:

Entrée is a culinary term used for a course during a meal service. In parts of the US and Canada, the word entrée is often used to refer to the main dish that is served while in other parts of the world, it usually means the starter or the simple meal that is served before the main dish / course. Entrées can be made of any component but the content of the natural ingredients does not define its healthy status. Thus, it is false to say that any entrée can be labelled "healthy" on a menu as long as it contains natural ingredients.

Candles burn because it gets enough oxygen from open space.  When the jar is closed it didn't get oxygen to burn. Thus, the candle  will distinguish.

Oxygen is 8th element in periodic table. It is the most abundant element in  earth crests. Oxygen is precious because, it is used to respire by all livings things.

Biospheres is interconnected with the atmosphere.  The changes in atmosphere  affects the biosphere. Thus, the composition of gases will definitely affects the living in biosphere.

The gas which burn in atmosphere is hydrogen. But the gas which helps to burn is oxygen.  Substances get oxidised  when reacting with oxygen. Thus combustion of matter is aided by oxygen.

Open air oxidation aids substance to burn. Thus, the burning of candles is aided with the circulation oxygen gases. Hence, when the jar closes the air circulation gets off and it will stop burning.

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Answer:

Oxygen is needed to maintain this type of combustion reaction. The jars prevent oxygen in the surrounding air from reaching the flames, so the flames go out.

Explanation:

This is the correct answer

Although your question is incomplete I have provide more general answer is provided

The  Reaction equation between sulfur dioxide and solid calcium oxide :

[tex]SO_{2}_{(g)} + CaO_{(s)} ---> CaSO_{3}_{(s)}[/tex]

Given that your question is vague I have provided the reaction equation between the Sulphur dioxide and calcium oxide, and the chemical conversion equation of Sulphur to Sulphur dioxide ( gas )

conversion of Sulphur to Sulphur dioxide

= [tex]S_{(s)} + O_{(2)}_{(g)} ----> SO_{2}_{(g)}[/tex]

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The net-ionic equation for hydrolysis of ZnCl₂ in water typically produces zinc hydroxide and hydrogen ions, but the equation provided incorrectly represents a neutralization reaction.

The net-ionic equation for the hydrolysis of zinc chloride (ZnCl₂) in water involves the hydrolysis reaction where the Zn²+ cation reacts with water to produce a weak acid and the Zn(OH)₂ solid as the product.

However, the net-ionic equation presented here is incorrect for hydrolysis, as it represents a neutralization reaction.

In hydrolysis, the relevant products would involve zinc hydroxide as a precipitate and hydrogen ions or hydronium ions depending on the pH of the solution.

Answer:

The new radius of the balloon is 17.8 cm.

Explanation:

Initial pressure of the air in the balloon =[tex]P_1[/tex] 1.0 atm

Radius of the balloon ,r= 17 cm

Volume of the spherical volume balloon = [tex]V_1=\frac{4}{3}\pi r^3[/tex]

Final pressure of the air in balloon =[tex]P_2[/tex]=0.87 atm

Radius of the balloon be R

Volume of the balloon be = [tex]V_2=\frac{4}{3}\pi R^3[/tex]

New radius of the balloon= R

According Boyle's Law:

[tex]P_1V_1=P_2V_2[/tex]

[tex]1.0 atm\times \frac{4}{3}\pi r^3=0.87 atm\times \frac{4}{3}\pi R^3[/tex]

R =17.80 cm

The new radius of the balloon is 17.8 cm.

Answer:forward

Explanation:

If CO2 levels are low and O2 levels are high, RuBisCO adds an O2 molecule to RuBP, not CO2. This process is known as photorespiration, which reduces the overall efficiency of photosynthesis by consuming plant energy and releasing CO2. It's a wasteful process compared to usual photosynthesis.

RuBisCO is an enzyme that plays a pivotal role in the process of photosynthesis by catalyzing a reaction between CO₂ and RuBP. However, when CO₂ levels are low and O₂ levels are high, RuBisCO adds an O₂ molecule to RuBP instead of CO₂. This process is known as photorespiration and leads to consequences in the Calvin cycle of photosynthesis.

In the scenario of low CO₂ and high O₂ levels, RuBisCO's oxygenase activity increases, reducing the amount of CO₂ that is fixed and thus reducing the overall efficiency of photosynthesis. The production of 3-phosphoglycerate (3-PGA) decreases, subsequently affecting the production of glucose. Instead of facilitating the production of valuable energy-rich compounds, photorespiration consumes energy and releases CO₂. Thus, it is a wasteful process for the plant.

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A calorie of heat causes a relatively little change in the temperature of water because most of the heat is consumed to break down hydrogen bonds before water molecules can start moving more quickly.

The exchange of "thermal" energy brought on by a temperature differential is known as heat. Think of an isolated system with two subsystems that are initially operating at two distinct temperatures.

Since water has a higher specific heat than other substances, it requires more energy to raise its temperature. This is why using water as a coolant in your car's radiator and in several sectors is beneficial.

The heat required to raise the temperature of liquid water is considerable because hydrogen bonds between the molecules must be broken.

Thus, Heat is absorbed and released as hydrogen bonds form.

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Answer:

Point C

Explanation:

To find the final equilibrium temperature of the water-tin mixture, we use the principle of heat transfer. Equating the heat lost by the tin to the heat gained by the water and solving for the final temperature allows us to find the value.

Given the mass, initial temperature and specific heat capacity of the tin and initial temperature of the water, we can calculate the final equilibrium temperature of the water-tin mixture using the principle of heat transfer: when two bodies of different temperatures come into contact, heat transfers from the hotter body to the cooler body until they reach thermal equilibrium, i.e., they have the same temperature.

Assuming no heat loss to the surroundings, the heat lost by the tin equals the heat gained by the water (as the tin cools down and the water heats up). The formula for heat transfer is Q=mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity and ΔT is the temperature change.

So, for the tin: Qtin = mtinctin(Tinitial,tin-Tfinal) and for the water: Qwater = mwatercwater(Tfinal-Tinitial,water). Since Qtin = Qwater, equating these two yields, mtinctin(Tinitial,tin-Tfinal) = mwatercwater(Tfinal-Tinitial,water).

This equation allows us to solve for Tfinal, the final equilibrium temperature of the tin-water mixture.

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The molarity of the given solution is  [tex]\boxed{{\text{0}}{\text{.0174 mol/L}}}[/tex].

Further explanation:

Blood alcohol concentration:

The term BAC is also known as blood alcohol concentration. Blood alcohol concentration is a measure of the concentration of alcohol in blood. The BAC is expressed in terms of grams of alcohol present in 100 mL of blood. For example, if BAC is 0.12 % that means 0.12 g of alcohol present in 100 mL of blood.

Molarity:

The molarity of the solution can be defined as the concentration of the solution and is equal to the number of moles of the solute dissolved in 1 liter of the solution.

The expression of molarity (M), volume (V), and number of moles (n) is as follows:

[tex]{\text{M}}=\dfrac{{{\text{n}}\left({{\text{mol}}} \right)}}{{{\text{V}}\left({\text{L}}\right)}}[/tex]           ...... (1)

Here, V is a volume of solution in liters and n is a number of moles of solute.

The given BAC is 0.08 that means 0.08 g of alcohol is present in 100 mL of blood.

The molar mass of alcohol (ethanol) is 46.068 g/mol. Therefore, the number of moles of alcohol present in 0.08 g of alcohol is,

[tex]\begin{aligned}{\text{Mole}}&=\frac{{{\text{given mass}}\left( {\text{g}}\right)}}{{{\text{molar mass}}\left({{\text{mol/g}}}\right)}}\\&=\frac{{0.08{\text{ g}}}}{{46.068{\text{g/mol}}}}\\&=0.0017366{\text{ mol}}\\\end{aligned}[/tex]

The molarity of the alcohol solution in blood can be calculated by dividing the number of moles (0.0017366 mol) with the volume of solution (100 mL or 0.1 L).

[tex]\begin{aligned}{\text{M}}&=\frac{{{\text{n}}\left( {{\text{mol}}}\right)}}{{{\text{V}}\left( {\text{L}} \right)}}\\&=\frac{{0.0017366{\text{ mol}}}}{{0.1{\text{ L}}}}\\&= 0.017366{\text{ mol/L}}\\\end{aligned}[/tex]

Therefore the molarity of solution is [tex]{\mathbf{0}}{\mathbf{.0174 mol/L}}[/tex] .

Learn more:

1. Salts produced from neutralization reaction: https://brainly.com/question/10528663

2. Complete equation for the dissociation of [tex]{\text{N}}{{\text{a}}_2}{\text{C}}{{\text{O}}_3}\left({aq} \right)[/tex] : https://brainly.com/question/5425813

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Solutions

Keywords: Concentration of alcohol, BAC, blood alcohol concentration, molarity, number of moles, 0.08 bac, 0.0174 mol/L.

We have that the concentration of alcohol, in terms of molarity is

M=0.017366mol/L

Question Parameters:

in blood if the bac is 0.08

Generally the equation for the mol  is mathematically given as

[tex]Mole=\frac{given mass}{molar mass}[/tex]

Therefore

[tex]Mole=\frac{0.08}{46.06}[/tex]

Mole=0.0017366mol

The molarity of the alcohol solution in blood

M=n/V

M=0.0017366mol/0.1

M=0.017366

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Answer:

3. They are formed by ions that have the opposite charges.

Explanation:

Ionic compounds are formed when two oppositely charged ions react. Ionic bonds are formed when an atom has tendency to loose its valence electron/electrons and another atom has tendency to accept them. All the atoms on this earth want to be stable but they can be stable only when they have stable electronic configuration. Some atoms like noble gases have stable electronic configuration already so they don't need to react with any other atom of any other element but others do not have stable electronic configuration and in order to achieve this stable electronic configuration they need to react with atoms of other elements through various kind of bonds/interactions like ionic bond.

An example of ionic bond is interaction between magnesium ion (Mg2+) and chloride (Cl-) to form magnesium chloride (MgCl2).

Apart from ionic bonds there are other type of interactions too like covalent bonds, hydrogen bonds, hydrophobic interactions etc.

Answer: The magnesium ion formed is [tex]Mg^{2+}[/tex]

Explanation:

Magnesium is the 12th element of the periodic table having electronic configuration: [tex]1s^22s^22p^63s^2[/tex]. This element will easily loose 2 electrons and form [tex]Mg^{2+}[/tex] ion.

Sulfur is the 16th element of the periodic table having electronic configuration: [tex]1s^22s^22p^63s^23p^4[/tex]. This element will easily gain 2 electrons and form [tex]S^{2-}[/tex] ion.

Sulfur and magnesium will form ionic compound, which means that a complete transfer of electrons takes place from one element to another.The compound formed will be MgS (Magnesium sulfide).

Hence, the magnesium ion formed is [tex]Mg^{2+}[/tex]

Final answer:

The EPA's maximum concentration of lead in drinking water is 15 ppb, which is equivalent to 0.015 mg/L. To consume 1.0 µg of lead at this concentration, one would need to drink about 0.067 liters of water.

Explanation:

The maximum concentration for lead in drinking water, as set by the U.S. Environmental Protection Agency (EPA), is 15 parts per billion (ppb). To convert this concentration to milligrams per liter (mg/L), we use the relationship that 1 ppb is equivalent to 1 microgram per liter (1 ppb = 1 µg/L). Since 1 milligram (mg) is equal to 1,000 micrograms (µg), the maximum concentration of lead in drinking water is 0.015 mg/L (15 µg/L).

To find out how many liters of water one must drink to consume 1.0 microgram (µg) of lead at this maximum level, we set up a proportion using the maximum concentration: If 15 µg is in 1 liter of water, then 1 µg would be in 1/15 liters of water. Thus, one would need to drink 1/15 liters, or approximately 0.067 liters, of water to consume 1.0 µg of lead.

To find the number of grams of methane gas produced, use the enthalpy change and stoichiometry of the reaction. Assuming the reaction is the combustion of methane, calculate the moles of methane using the enthalpy change and convert it to grams.

To determine the number of grams of methane gas produced, we need to use the enthalpy change and stoichiometry of the reaction. From the given information, we know that the enthalpy change is 82.3 kJ. Since the reaction is not specified, we'll assume it's the combustion of methane:

CH4 + 2O2 -> CO2 + 2H2O

The stoichiometry of the reaction tells us that for every 1 mol of methane, we produce 1 mol of CO2. Therefore, the number of grams of methane can be calculated as follows:

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Given an enthalpy change of 82.3 kJ during a reaction involving methanol (CH3OH), approximately 1.47 grams of methane (CH4) would be produced. This is derived by applying the principles of stoichiometric calculations and enthalpy changes, and considering the exothermic nature of the combustion reaction of methane.

To answer your question about how many grams of methane gas are produced given a sample of ch3oh (methanol) and an enthalpy change of 82.3 kJ, we need to apply the principles of stoichiometric calculations and enthalpy changes. In this problem, we can use a similar approach to what we would use in a stoichiometry problem.

First, it's important to note that the combustion reaction of methane (CH₄) is exothermic, meaning it releases energy. Specifically, the combustion of 1 mole of methane releases approximately 890.4 kJ of energy, as shown by the chemical reaction:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g) + 890.4 kJ

Given that the enthalpy change is 82.3 kJ, we can calculate the amount of methane combusted. We can convert the energy change from kJ to mol, using the known energy/reaction ratio of 890.4 kJ/mol, which gives us approximately 0.092 mol of CH₄. Subsequently, we can convert moles into grams using the molar mass of methane (16 g/mol). This gives the final answer of approximately 1.47 grams of methane.

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The answer is: No, because his information is subjective.

Survey about whether or not people like something is not objective (fact) and cannot be published.

The laws of science are statements that describe or predict a range of phenomena as they appear in nature.

Laws explain facts determined by experiment.

Laws do not have absolute certainty and be changed by future experiments and observations.

When ketone is reacted with phosphorous pentachloride, chlorination takes place at the carbonyl carbon with substitution of the oxygen atom to give a geminal dichloride (with 2 Cl atoms on same carbon) according to the following equation: 

so we can say that acetone is converted into 2,2-dichloropropane by action of PCl₅

Answer:  The masses of [tex]Ca(NO_3)_2.4H_2O[/tex] and [tex]KIO_3[/tex] required to make 10.0 g of [tex]Ca(IO_3)_2[/tex] is 5.9 and 10.7 grams respectively.

Explanation: To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}[/tex]

[tex]\text{Number of moles}=\frac{10.0g}{390 g/mol}=0.025moles[/tex]

[tex]Ca(NO_3)_2.4H_2O(s)+2KIO_3(s)\rightarrow Ca(IO_3)_2+2KNO_3+4H_2O[/tex]

1 mole of [tex]Ca(IO_3)_2[/tex] is formed from 1 mole of [tex]Ca(NO_3)_2.4H_2O[/tex] and 2 moles of [tex]KIO_3[/tex]

Thus 0.025 moles of [tex]Ca(IO_3)_2[/tex] is formed from 0.025 moles of [tex]Ca(NO_3)_2.4H_2O[/tex] and 0.05 moles of [tex]KIO_3[/tex]

Mass of [tex]Ca(IO_3)_2.4H_2O=moles\times {\text {Molar mass}}=0.025\times 236=5.9 grams[/tex]

Mass of [tex]KIO_3=moles\times {\text {Molar mass}}=0.05\times 214=10.7grams[/tex]

This reaction practically goes to completion as AgCN is nearly insoluble, using up almost all of the Ag+, so practically no Ag+ remains.

The reaction between AgNO3 and NaCN results in the formation of AgCN, which is nearly insoluble. Due to this, the reaction practically goes to completion, consuming almost all the Ag+ ions.

The initial number of moles of Ag+ can be calculated as follows: volume (L) × molarity = 0.130 × 3.0×10−3 = 3.9×10−4 moles.

The initial number of moles of CN- (from NaCN) is: 0.225 × 0.14 = 0.0315 moles.

Since the reaction between Ag+ and CN- is in a 1:1 ratio, all the Ag+ will react until one of the reactants runs out. In this case, it's Ag+ since it's present in a smaller amount. Therefore, practically, no Ag+ remains after the reaction.

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To achieve a buffer solution with a pH of 9.0 using NH₃, the required concentration of NH₄Cl is approximately 0.55 M.

This is determined using the Henderson-Hasselbalch equation.

Key calculations involve finding the pKa and using logarithmic functions.

To determine the concentration of NH₄Cl required to achieve a buffer solution with a pH of 9.0, we use the Henderson-Hasselbalch equation. Given:

First, calculate pKb:

pKb = -log(1.8 x 10⁻⁵) ≈ 4.74

Then, calculate pKa:

pKa = 14 - pKb = 14 - 4.74 = 9.26

Using the Henderson-Hasselbalch equation:

pH = pKa + log([NH₃]/[NH₄Cl])

We need a pH of 9.0, so:

9.0 = 9.26 + log(0.30/[NH₄Cl])

Simplifying, we get:

-0.26 = log(0.30/[NH₄Cl])

Taking the antilog, we find:

0.30/[NH₄Cl] = 10^-0.26 ≈ 0.55

Therefore:

[NH₄Cl] = 0.30/0.55 ≈ 0.55 M

To achieve a buffer solution with a pH of 9.0, the concentration of NH₄Cl required is approximately 0.55 M.

The correct question is:

A solution is 0.30 m in NH₃. what concentration of NH₄Cl would be required to achieve a buffer solution with a final ph of 9.0? recall the hh equation can be written using pH and pkₐ or pOH and pkb. The kb of NH₃ is 1.8 x 10⁻⁵.

Final answer:

Graphite and iodine are shiny nonmetals due to their structure; graphite's free-moving electrons within layers give it a luster, while iodine's crystalline form reflects light. Both have unique bonding arrangements contributing to their reflective properties.

Explanation:

Graphite and iodine are both nonmetals that exhibit a shiny, lustrous appearance, which is a characteristic more typically associated with metals. The reason behind this lies in their unique structures and bonding arrangements.

Graphite, an allotrope of carbon, has a layered structure with delocalized electrons. These electrons are able to move freely within the layers, which not only gives graphite its electrical conductivity but also contributes to its shine. The carbon atoms within each layer are strongly bonded, but the layers themselves are held together by weaker forces, allowing them to slip past one another and giving graphite its lubricating properties.

Iodine, on the other hand, has a shiny surface due to its crystalline solid form. The structure allows it to reflect light, which gives the appearance of a metallic luster.