Which chemical reaction absorbs energy

After the initial push, the rock will keep moving forever at constant velocity (constant speed in a straight line)

Explanation:

We can answer this question by using Newton's first law of motion:

"An object at rest (or in motion at constant velocity) will stay at rest (or will keep moving at constant velocity) unless acted upon unbalanced forces" (Law of inertia)

In this problem, we have a rock in a place very far from any force that can act on it. This means that there are no unbalanced force acting on it, so the rock will keep its state of motion forever.

In this situation, the rock is initially thrown by the astronaut. After the initial push, which accelerates the rock up to a certain velocity, there will be no more forces acting on the rock. This means that the rock will continue moving at a constant velocity forever, so at a constant speed in a straight line.

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The work done by the brakes is [tex]-3.0\cdot 10^5 J[/tex]

Explanation:

According to the work-energy theorem, the work done by the brakes on the car is equal to the change in kinetic energy of the car. Therefore:

[tex]W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]

where

W is the work done

m is the mass of the car

v is the final speed

u is the initial speed

For the car in this problem, we have:

m = 1500 kg

u = 20 m/s

v = 0 (the car comes to a halt)

Substituting, we find the work done:

[tex]W=0-\frac{1}{2}(1500)(20)^2=-3.0\cdot 10^5 J[/tex]

And the work is negative because the brakes apply a force in the opposite direction to the motion of the car.

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The time taken is approximately 26 minutes

Explanation:

The motion of the body in this problem is a uniform motion (= at constant velocity), therefore we can use the following equation:

[tex]v=\frac{d}{t}[/tex]

where

v is the speed

d is the distance covered

t is the time taken

In this problem, we have

v = 75 km/h is the speed

d = 32 km is the distance to be covered

Solving for t, we find the time needed:

[tex]t=\frac{d}{v}=\frac{32}{75}=0.43 h[/tex]

Converting into minutes,

[tex]t=0.43 h \cdot 60 = 25.8 min \sim 26 min[/tex]

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Answer:

(C) The positive charge of the alpha particles and the negative charge of the electrons  are the properties Rutherford used in his experiment

Explanation:

In his scattering experiment, scientist Ernest Rutherford used the property of positively charged alpha particles and negatively charge electrons. He performed this experiment by passing some of the alpha particles through a gold foil. The result was that the some alpha particles scattered while some passed through the gold foil without collision.

He concluded that the alpha particles are centrally positively charged and needed a large amount repelling force. This experiment of Rutherford is also known as Rutherford model of atom. This experiment helped him in doing so many other discoveries.

Answer:

90km

Explanation:

every hour you travel 30km and you are traveling 3 hours 30×3

Answer:

C

Explanation:

The car is considered as an open system, because an external force is applied to the car that causes constant acceleration of car. Hence, option (B) is correct.

The system isolated from its surrounding is known as closed-system. While, in an open system, the flow of information between the system and surrounding takes place, to cause any change in the system.

As per the concept of open and closed system:

Hence, the car must be considered an an open system, because the acceleration of car is related with the force, which is being applied from the outside of frame of reference.

Thus, we can conclude that considering only car is an open system because external force is applied to the car that causes it to accelerate. Hence, option (B) is correct.

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Answer:

it will cover 195km in 3 hours

1) The acceleration is [tex]0.96 m/s^2[/tex]

2) The time taken is 39.6 s

Explanation:

1)

Since the motion of the truck is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the truck in this problem,

u = 0 (it starts from rest)

v = 38 m/s

s = 755 m

Solving for a, we find the acceleration:

[tex]a=\frac{v^2-u^2}{2s}=\frac{38^2-0}{2(755)}=0.96 m/s^2[/tex]

2)

For this part we can use the following suvat equation

[tex]v=u+at[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken for the velocity to change from u to v

In this problem,

u = 0

v = 38 m/s

[tex]a=0.96 m/s^2[/tex]

Solving for t,

[tex]t=\frac{v-u}{a}=\frac{38-0}{0.96}=39.6 s[/tex]

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The truck's acceleration, starting from rest to a velocity of 38 m/s over 755 m, is approximately 0.956 m/s². It takes about 39.75 seconds to cover this distance.

a. To determine the acceleration of the truck, we can use the kinematic equation:

v^2 = u^2 + 2as

where:

v = final velocity (38 m/s),

u = initial velocity (0 m/s since the truck was initially at rest),

a = acceleration,

s = displacement (755 m).

Rearranging the equation to solve for acceleration (a), we get:

a = (v^2 - u^2) / (2s)

Substitute the given values:

a = (38^2 - 0^2) / (2 * 755)

a = 1444 / 1510

a ≈ 0.956 m/s^2

b. To find the time taken (t), we can use the kinematic equation:

v = u + at

Since the truck started from rest (u = 0), this simplifies to:

t = v / a

Substitute the values:

t = 38 / 0.956

t ≈ 39.75 s

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The question probable may be:

A Truck accelerates to a velocity of 38 m/s over 755 m of road.

a. If the truck was initially at rest, what was its acceleration?

b. How long willthe truck take to travel this distance?

Answer:

The combination of foods and beverages that constitute an individual’s complete dietary intake over time is known as Eating pattern.

So, option A is the correct answer.

Explanation:

The Eating pattern  is also called Dietary Pattern. Normal eating pattern may be three meals a day, may increased or changed according to the individual, and may refer to overeating.

Dietary guidelines are nutritional guidelines which advice an individual, greater than 2 years, consume a healthy and nutritional diet.

Mediterranean diet is the diet typical to Mediterranean countries, in which there is high consumption of vegetables, fruits, seeds, legumes, nuts and olive. It consists of moderate amounts of carbohydrates and proteins and a moderate to high amount of fats.

A healthy intake is a healthy diet in which the energy from sugars is less than 10% of the total energy intake.

Hence, Option A is the correct answer.

The magnitude of the air drag is 784 N

Explanation:

An object falling down reaches the terminal velocity when the magnitude of the air drag acting on it becomes equal to the weight of the object. Mathematically, this condition can be written as:

[tex]F_D = mg[/tex]

where

[tex]F_D[/tex] is the magnitude of the air drag

m is the mass of the object

g is the acceleration of gravity

In this problem, we have

m = 80 kg is the mass of the airman

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

Substituting into the formula, we find:

[tex]F_D = (80)(9.8)=784 N[/tex]

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Answer: Line graph

Explanation:

Allison needs to graph the yearly average snowfall in Alaska. She should use a:

pie chart

pictograph

bar graph

line graph

Answer:

change in temperature

Answer:

Change in temperature

Explanation:

did this on edge yesterday and that was the answer

1) The initial height of the roller coaster must be 5.1 m

2) The height of the roller coeaster must be 5.5 m

Explanation:

1)

We can solve this problem by using the law of conservation of energy.

In fact, in absence of frictional force, the total mechanical energy must be conserved, so we can write:

[tex]KE+PE = KE'+PE'[/tex]

where

KE = 0 is the initial kinetic energy, at the top (the car starts from rest, so it has zero speed and so zero kinetic energy)

PE = mgh is the initial potential energy, where

m = 8000 kg is the mass of the car

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

h is the initial height

[tex]KE'=\frac{1}{2}mv'^2[/tex] is the kinetic energy of the car at the bottom, where

v' = 10 m/s is the speed of the car at the bottom

PE' = 0 is the potential energy at the bottom (where h = 0)

Re-writing the equation with all the values and solving for h, we find the initial height of the track:

[tex]h=\frac{v^2}{2g}=\frac{10^2}{2(9.8)}=5.1 m[/tex]

2)

In this case, we also have to take into account the energy lost due to friction. So the equation of conservation of energy becomes

[tex]KE+PE = KE'+PE'+W[/tex]

where

W = 32,000 J is the work done by friction

Re-arranging the equation and solving again for h, we find:

[tex]mgh = \frac{1}{2}mv'^2 + W\\h=\frac{v^2}{2g}+\frac{W}{mg}=5.1+\frac{32,000}{(8000)(9.8)}=5.5 m[/tex]

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the answer is b,c, and e

Answer:

BCE

Explanation:

B. A car slowing as it reaches a stop light

Explanation:

According to Newton's second law, the net force exerted on an object is equal to the product between its mass and its acceleration:

[tex]F=ma[/tex]

where

F is the net force

m is the mass of the object

a is its acceleration

This means that when an object is experiencing unbalanced forces ([tex]F\neq 0[/tex]), it must have a non-zero acceleration. Therefore, let's analyze the different options:

A. A box resting on a horizontal floor  --> FALSE. Here the acceleration is zero, so no unbalanced forces.

B. A car slowing as it reaches a stop light  --> TRUE. Since the car is slowing down, its velocity is changing, so the acceleration is non-zero and there are unbalanced forces.

C. A car with its cruise control set to 50 mph  --> FALSE. Here the velocity is constant, so no acceleration and no unbalanced forces.

D. A rocket sitting on the launch pad --> FALSE. Here the rocket is stationary, so no acceleration, and no unbalanced forces.

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An object experiences unbalanced forces when the resultant force on it is non-zero. A car slowing as it reaches a stop light experiences unbalanced forces due to the brakes exerting a force, causing it to decelerate. Hence, the correct answer is B. A car slowing as it reaches a stop light.

In the question, we are asked to determine in which situation an object is experiencing unbalanced forces. An object experiences unbalanced forces when the resultant force acting on it is non-zero, leading to a change in its motion. If we analyze the options given:

Therefore, the correct answer is B. A car slowing as it reaches a stop light, because this is when it is experiencing a net force that is causing a change in its motion.

Explanation:

Use the Ideal Gas Law:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is the universal gas constant,

and T is absolute temperature.

First, identify which variables in the problem are constant (note that R is always a constant).

Next, solve for the constants and use that equation to write a proportion.

Finally, plug in the given values and solve for the unknown variable.

For example, if n and R are the constants:

nR = PV/T

Therefore:

P₁V₁/T₁ = P₂V₂/T₂

Most of the Earth's volume is contained in the "mantle". The correct answer would be option (A).

The mantle is a layer of semi-solid rock that lies between the Earth's thin crust and its liquid outer core. The mantle is approximately 2,900 kilometers (1,800 miles) thick and makes up about 84% of the Earth's total volume.

The crust, mantle, and core are the three coatings of the Earth. The crust is made up of minerals and solid rocks. The mantle lies under the crust and is largely made up of solid rocks and minerals, but it is punctured by pliable patches of semi-solid magma.

It is composed primarily of silicate rocks and is considered to be the source of the Earth's heat and most of its volcanic activity.

The mantle also plays a key role in plate tectonics, which is the theory that explains the movement of the Earth's continents and ocean floor.

Thus, the correct answer would be option (A) mantle.

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Answer:

The current in the circuit will be [tex]5\times 10^{-3}\ Ampere[/tex].

Explanation:

Given:

Voltage difference = V = 5 V

Resistance              = R = 1000 ohms

To Find:

Current, I = ?

Solution:

Ohm's Law:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

i.e  I ∝ V

∴ V = I × R

Where, I = current

           V = voltage

           R = resistance

Substituting the values of V and R we get

∴ 5 = I × 1000

[tex]I = \frac{5}{1000} \\I=0.005\ Ampere\\I=5\times 10^{-3}\ Ampere[/tex]

Therefore, the current in the circuit will be [tex]5\times 10^{-3}\ Ampere[/tex].

The current in the circuit can be found using Ohm's Law (I=V/R). The given values for voltage and resistance result in a current of 5 milliamperes.

The subject matter in the question falls under the field of Physics, particularly Electricity. The problem is asking for the current in a circuit, based on given values for voltage and resistance. One can solve this by employing Ohm's Law, which describes the relationship between voltage (V), resistance (R), and current (I). Ohm's Law is represented by the formula I = V/R.

Substituting the given values into the formula, the current I is calculated as 5V / 1000Ω, which equals 0.005 Amperes, or 5 Milliamperes (mA). Thus, the current flowing in the circuit is 5 mA.

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Answer:

18N & 360W

Explanation:

Here,

Velocity of car (v) = 72 ∗ 1000 / 60∗60 = 20m/s

weight of car = 1200N

We have,

μr = Fs / R

Fs = μr ∗ R = 0.015 ∗ 1200 = 18N

Power developed by the engine = 18 ∗ 20 =360W

Answer:

Nichrome has __High__melting piont​

Hope this helps

Answer:

high melting point

Nichrome is consistently silvery-grey in colour, is corrosion-resistant, and has a high melting point of about 1,400 °C (2,550 °F).

Explanation:

Answer:

Kinetic Energy

Explanation:

In relation to the question, as the sheriff rides a horse, the sheriff is in motion and a body in motion is said top possess kinetic energy.

Kinetic energy is that energy of the body that it gains due to the motion or speed of the body which it gains and maintains.

In other words, we can say that the amount of work needed to accelerate an object from its position of rest and set it into motion at some certain velocity.

Answer:

Snell's law tells us the degree of refraction and relation between the angle of incidence, the angle of refraction and refractive indices of given pair of media. We know that light experiences the refraction or bending when it travels from one medium to another medium. Snell's law predicts the degree of the bend.

Explanation:

Final answer:

Snell's law expresses the relationship between the incidence and refraction angles and the indices of refraction of two media, represented by the equation n₁ sin θ₁ = n₂ sin θ₂.

Explanation:

Snell's law describes the relationship between angles and indices of refraction when light passes from one transparent medium to another.

It is an essential concept in the study of optics and can be mathematically expressed as n₁ sin θ₁ = n₂ sin θ₂, where n₁ and n₂ are the refractive indices of the first and second medium, respectively, and θ₁ and θ₂ are the angles of incidence and refraction.

This law is named after the Dutch mathematician Willebrord Snell who described it in 1621, but it was also discovered by the Arabian physicist Ibn Sahl in the 10th century.

Through thorough experiments, it became evident that light rays change direction due to the differing speeds of light in various media, a concept Snell himself was not aware of but was able to confirm through the refractive indices.

The object on Earth has greater mass

Explanation:

The weight of an object is given by

[tex]W=mg[/tex]

where

W is the weight

m is the mass of the object

g is the strength of the gravitational field at the location of the object

The strength of the gravitational field on Jupiter ([tex]g_J[/tex]) is much larger than that on Earth ([tex]g_E[/tex]), so we can write

[tex]g_J > g_E[/tex]

The weight of the first object on Jupiter is

[tex]W_J = m_1 g_J = 50 N[/tex] (1)

where [tex]m_1[/tex] is the mass of the first object, while the weight of the second object on Earth is

[tex]W_E = m_2 g_E = 50 N[/tex] (1)

while [tex]m_2[/tex] is the mass of the second object.

By dividing eq.(1) by (2), we get

[tex]\frac{m_1 g_J}{m_2 g_E}=1\\\frac{m_1}{m_2}=\frac{g_E}{g_J}[/tex]

And since [tex]g_J > g_E[/tex], this means that [tex]m_2 > m_1[/tex], so the object on Earth has greater mass.

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1) Yes, it is a conservative force

2) The potential energy at (5m, 5m) is 20 J

Explanation:

1)

A force is defined to be conservative if the work done by the force when moving an object does not depend on the path taken, but only on the initial and final position of the object.

Let's verify if this condition is met for the force in this problem:

- For going from (0 m, 0 m) to (5 m, 5 m), the work done is 20 J (A)

Then we can go from (0 m, 0 m) to (5 m, 5 m) through a different path:

- from (0 m, 0 m) to (5 m, 0 m) (work done: 25 J)

- from (5 m, 0 m) to (5 m, 5 m) (work done: -5 J)

Total work done in the second path: 25 J + (-5 J) = 20 J --> same as (A)

We can also go from (0 m, 0 m) to (5 m, 5 m) through a different path:

- from (0 m, 0 m) to (0 m, 5 m) (work done: 35 J)

- from (0 m, 5 m) to (5 m, 5 m) (work done: -15 J)

Total work done in the third path: 35 J + (-15 J) = 20 J --> same as (A)

So, the force is conservative, since the work done does not depend on the path taken.

2)

For a conservative force, the change in potential energy of the object moved by the force is equal to the work done by the force in moving the object from A to B.

Here have:

Point A: (0m, 0m)

Point B: (5m, 5m)

So, the change in potential energy is equal to the work done from A to B:

[tex]W=\Delta U = U_B-U_A[/tex]

where

[tex]U_B[/tex] is the potential energy in point B

[tex]U_A[/tex] is the potential energy in point A

In this problem, the potential energy at the origin (point A) is zero, so

[tex]U_A = 0[/tex]

Also we know that the work done is

W = 20 J

So, we find

[tex]U_B = W+U_A = 20 + 0 = 20 J[/tex]

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The force exerted is not conservative as different amounts of work are being done to move the particle along different paths between the same points. Potential energy isn't defined in the usual sense because the force isn't conservative, but if taken as the average of the works done, the potential energy at (5,5) could be taken as 20J.

A conservative force is defined as one in which the work done on a particle by the force as the particle moves from one point to another is independent of the path taken. Specifically, in the case of a conservative force, the work done is only dependent on the initial and final positions. In the given scenario, different amounts of work are being done to move the particle along different paths between the same points. This indicates that the force is not a conservative one.

The potential energy at a point in a field due to a conservative force is equal to the work done by the force to move the particle from a reference point (in this case, the origin point) to that point. Since the force in this scenario isn't conservative, potential energy isn't defined in the usual sense. Nevertheless, if we insist on measuring it, we could take the average of the works done: for instance, between (0,0) and (5,5) the works done are 35+(-15)=20 and -5+25=20, so we could say the potential energy at (5,5) is 20J considering the origin as the reference point with zero potential energy.

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Answer:

Action - Pulling up the train.

Reaction - Friction on the locomotive

Explanation:

Locomotive is pulling the train upwards ,

Which is the action force applied by the locomotive,

As a reaction locomotive will be pulled by the train which is the reaction of pulling

Now, considering it as a action on locomotive , friction force will act on it as a reaction upwards which will result to move it upwards.

For train action is pulling up by locomotive and reaction will be friction acting on it downwards.

1) The force on the wire is 1.5 N

2) The force on the wire is zero

Explanation:

1)

The force experienced by a current-carrying wire in a magnetic field is given by

[tex]F=ILB sin \theta[/tex]

where

I is the current in the wire

L is the length of the wire

B is the magnetic flux density

[tex]\theta[/tex] is the angle between the direction of the wire and of the field

In this part of the problem we have

I = 10 A

L = 2 m

B = 0.15 T

[tex]\theta=30^{\circ}[/tex]

Substituting, we find

[tex]F=(10)(2)(0.15)(sin 30^{\circ})=1.5 N[/tex]

2)

As before, the force experienced by the wire is

[tex]F=ILB sin \theta[/tex]

where

I is the current in the wire

L is the length of the wire

B is the magnetic flux density

[tex]\theta[/tex] is the angle between the direction of the wire and of the field

In this case, however, the angle between the wire and the field is

[tex]\theta=0^{\circ}[/tex]

And therefore

[tex]sin 0^{\circ} = 0[/tex]

which means that the wire does not experience any force. In fact, the force experienced by the wire is zero when the wire is parallel to the field (such as in this case) and maximum when the wire is perpendicular to the field.

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3) The boulder travelled for a distance of 10 m

4) The work done on the car is zero

Explanation:

3)

The work done by a force on an object is given by:

[tex]W=Fd cos \theta[/tex]

where

F is the magnitude of the force

d is the displacement

[tex]\theta[/tex] is the angle between the direction of the force and of the displacement

In this problem we have:

F = 24 N

W = 240 J

[tex]\theta=0^{\circ}[/tex], assuming that the force is applied in the same  direction as the displacement

Therefore, we can find d, the displacement of the boulder:

[tex]d=\frac{W}{F cos \theta}=\frac{240}{(24)(cos 0)}=10 m[/tex]

4)

As in the previous exercise, the work done is

The work done by a force on an object is given by:

[tex]W=Fd cos \theta[/tex]

In this problem, we have:

F = 9000 N is the force applied

d = 0 is the displacement, since the car has not moved

Therefore, the work done on the car is

[tex]W=(9000)(0)(cos 0)=0[/tex]

So, no work is done on the car.

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