Which diagram BEST represents the light waves of a bright red brake light on the left side to a dim violet night light on the right side?
A)
B)
C)
D)

The frequency of the ocean waves is approximately 0.261 Hz, and the period is approximately 3.83 seconds, calculated based on the observation that 12 wave crests passed the observer in 46 seconds.

To calculate the wave frequency and period of ocean waves that a girl floating in the ocean observes, you can use the following definitions and formulas:

Given that 12 wave crests pass the observer in 46 seconds, the frequency (f) can be calculated as:

f = Number of waves / Time = 12 waves / 46 s
≈ 0.261 Hz

To find the period (T), you can use the formula:

T = 1 / f
≈ 1 / 0.261 Hz
≈ 3.83 s

Therefore, the frequency of the waves is approximately 0.261 Hz, and the period is approximately 3.83 seconds.

Final answer:

The two forms of electromagnetic energy that mainly pass through Earth's atmosphere are visible light and certain microwaves, which are crucial for life and climate balance.

Explanation:

The two forms of electromagnetic energy that mostly pass through the Earth's atmosphere to reach the surface are visible light and certain microwave frequencies. While our atmosphere acts as a shield, it selectively filters out most other wavelengths of incoming solar radiation. However, it allows the transmission of the majority of visible light and certain bands of the infrared spectrum, while absorbing harmful ultraviolet rays and other frequencies. This filtering is crucial for protecting life on Earth and for the climate balance by controlling the energy received at the surface.

Answer:

D) exerts a gravitational pull on the star it orbits

Explanation:

When light from a distant star appears to slightly red shift or slightly blue shift i.e., it seems to sometimes move away from us and sometimes move towards us, it is most likely to have planets around it. This method is known as Doppler spectroscopy.

This happens because of the unequal masses of the planet and the star the center of gravity does not lie in between them but rather in the star itself. Around this center of gravity the planet and the star will move. This causes the star to wobble.

The force acting on objects connected by a string results in a tension in the string

The tension in the string is approximately 36.2208 N

The reasons why the above values are correct are as follows:

The given parameters are;

Mass of the block, m₁ = 4.50 kg

Mass of the ball, m₂ = 7.70 kg

Path over which the string connecting the two blocks passes = Frictionless pulley

Coefficient of friction between the block and the surface, μ = 0.300

Required:

(a) To find the acceleration of the two objects and the tension in the string

Solution:

The motion of the system is due to the weight of the ball, m₂·g

The opposing force to motion of the system is due to friction of the block, m₁·g·μ

The block and the ball connected by the string have a common acceleration given as follows;

(m₁ + m₂) × a = m₂·g - m₁·g·μ

Where;

a = The acceleration of the two objects

Therefore, we get;

[tex]a = \dfrac{g\cdot (m_2 - m_1\cdot \mu_k)}{m_1 + m_2}[/tex]

Which gives;

[tex]a = \dfrac{9.81 \times (7.70 - 4.50\times 0.300)}{4.50 + 7.70} \approx 5.106 \ m/s^2[/tex]

The acceleration of the two objects, a ≈ 5.106 m/s²

Tension in the string:

Tension in the string, T = m₂×(g - a)

∴ T = 7.70 × (9.81 - 5.106) ≈ 36.2208

The tension in the string, T ≈ 36.2208 N

(b)  The force due tension in the string is given as follows

The force due to friction = 4.50 × 9.81 × 0.300 = 13.2435

Force due to friction, [tex]F_f[/tex] = 13.2435 N

Net force acting on block, F = T - [tex]F_f[/tex]

∴ F  = 36.2208 N - 13.2435 N = 22.9773 N

The acceleration of the block, a, is given as follows;

[tex]a = \dfrac{22.9773}{4.5} \approx 5.106[/tex]

Therefore, the acceleration, a is correct as a ≈ 5.106 m/s²

(c) From the equation for acceleration, we have;

[tex]a = \dfrac{g\cdot (m_2 - m_1\cdot \mu_k)}{m_1 + m_2}[/tex]

When the acceleration is increased by 60%, we get

60% increase of a = 1.6·a, and the new mass of the ball = m₃, which gives;

[tex]1.6 \cdot a = \dfrac{g\cdot (m_3 - m_1\cdot \mu_k)}{m_1 + m_3}[/tex]

Plugging in the known values of a, m₁, g, and [tex]\mu_k[/tex] gives;

[tex]1.6 \times 5.106 = \dfrac{9.81\times (m_3 - 4.5\times 0.300)}{4.50 + m_3}[/tex]

1.6 × 5.106 × (4.50 + m₃) = 9.81 × (m₃ - 4.5×0.300)

8.1696·m₃ + 36.7632 = 9.81·m₃ - 13.2435

9.81·m₃ - 8.1696·m₃ = 36.7632 + 13.2435 = 50.0067

1.6404·m₃ = 50.0067

[tex]m_3 = \dfrac{50.0067}{1.6404} \approx 30.48[/tex]

The added mass Δm = m₃ - m₂

∴ Δm = 30.48 kg - 7.70 kg = 22.78 kg

The required additional mass to increase the downward acceleration by 60%, Δm = 22.78 kg

Learn more about motion of connected bodies or objects here:

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a) they have higher reproductive rates

Answer: The correct answer is Option C.

Explanation:

Energy of the Electromagnetic Spectrum is given by the Planck's equation:

[tex]E=h\nu[/tex]

Where,

E = Energy of the wave

h = Planck's constant

[tex]\nu[/tex] = Frequency of the wave

And we know that,

[tex]\nu=\frac{c}{\lambda}[/tex]

where,

c = Speed of light

[tex]\lambda[/tex] = Wavelength of the wave

Putting the value of frequency in energy equation, we get:

[tex]E=\frac{hc}{\lambda}[/tex]

From the above relation, we get that energy is inversely related to wavelength of the wave.

From the spectra, we know that order of wavelength follows:

Infrared > Visible > UV

So, the order of energy gets reversed and the order becomes:

Infrared < Visible < UV

From the above information, we conclude that the correct option is Option C.

The squirrel is sitting at a height of 7.35 m.

The energy possessed by a body by virtue of its position is called potential energy.

If the squirrel has a mass m and if it sits at a height h then, the potential energy E of the squirrel is given by,

[tex] E=mgh [/tex]

here, g is the acceleration due to gravity.

Given:

[tex] m=0.5 kg;E=36 J [/tex]

Take the value of acceleration due to gravity [tex] g=9.8 m/s^2 [/tex]

Rewrite the equation for energy in terms of h.

[tex] h=\frac{E}{mg} [/tex]

Substitute the given values and calculate the value of h.

[tex] h=\frac{E}{mg} \\ =\frac{36 J}{(0.5 kg)(9.8 m/s^2)} \\ =7.35 m [/tex]

The squirrel is at a height of 7.35 m

Final answer:

To calculate acceleration, determine the change in velocity and the change in time, then use the formula a = ∆v/∆t where 'a' is acceleration, ∆v is the change in velocity, and ∆t is the change in time.

Explanation:

To find the acceleration in a problem, follow these general steps:

Determine the change in velocity (Δv), which is the difference between the final velocity (Vf) and the initial velocity (Vo).

Identify the change in time (Δt) over which the velocity change occurs.

Use the formula for average acceleration, which is a = Δv/Δt, where 'a' represents the acceleration, Δv is the change in velocity, and Δt is the change in time.

For instance, if a train starts at rest (Vo = 0) and reaches a velocity of 30.0 km/h (Vf) in 20.0 seconds (Δt), convert the velocity to meters per second (since 1 km/h is equal to approximately 0.27778 m/s), calculate Δv, and then divide by Δt to find acceleration.

Answer:

It will exert a force on the electric current.

Explanation:

Answer: Option (a) is the correct answer.

Explanation:

Chemical properties are defined as the properties that show chemical nature of a substance or compound.

For example, toxicity, reactivity, combustion etc are all chemical properties.

Properties in which there is no change in chemical nature of a substance is known as physical property.

For example, solubility, density, volume, mass etc are all physical properties.

When a substance becomes corrosive in nature then it means oxidation of substance has occurred.

When concentration of hydrogen ions increases then it means acidity of a substance increases.

When an acid comes in contact with a metal then it releases hydrogen atoms.

For example, [tex]2HCl + Mg \rightarrow MgCl_{2} + H_{2}[/tex]

When we add an acid to a base then it will result in the formation of salt and water.

For example, [tex]HCl + NaOH \rightarrow NaCl + H_{2}O[/tex]

An acid does not feel slippery but a base feels slippery on touch.

Thus, we can conclude that chemical properties of an acid include corrosive, increases the concentration of hydrogen ions when added to water, forms hydrogen gas when it comes in contact with a metal, and forms salt and water when added to a base.

Answer:

definitely A) it will not be able to be seen

Explanation:

More work was done on the baseball that went out of the park because it traveled a greater distance. Work in physics is determined by applying a force over a distance.

In physics, work is defined as the amount of energy transferred by a force over a distance. The equation for work is 'W = Fd' where 'W' is work, 'F' is force, and 'd' is distance. In the question given, the force applied to both baseballs was the same but the distances they traveled were different. The baseball that went out of the park traveled a greater distance. Therefore, more work was done on the ball that went out of the park, because the same force moved it over a greater distance. So the correct answer is 'c. The ball that went out of the park shows more work because the distance was greater.'

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Answer:

The following are bases:  baking soda, bleach, soap, and ammonia.

The other items are acidic.

Explanation:

Bases have four different properties. They are bitter, feel slippery, do not react with carbonates, and turn red litmus paper blue.

In comparison, an acid tastes sour, reacts with metal and carbonates, and turns blue litmus paper red.

If a droplet has 3 extra electrons, the measured charge will be three elementary charges.

Therefore, if a droplet has 3 extra electrons, the measured charge will be three elementary charges.

Learn more about Elementary charges:

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Answer:

I'm not sure if this is true but I think that gravity depends on weight is not true