Answers
The more metallic an atom is the less amount of energy is needed to remove an electron.
Related Questions
Draw one of the isomeric c5h12o alcohols that can be prepared by lithium aluminum hydride reduction of a ketone.
Answers
The Lithium Aluminum hydride (LiAlH₄) reduction of a ketone is a process in which the ketone is reduced and the Lithium Aluminum hydride is oxidized. The general chemical reaction for this kind of reduction is:
1)LiAlH₄
R(C=O)R ---------→R(C-OH)R
2)H₃O⁺
The structure for one of the isomeric C₅H₁₂O alcohols that can be prepared by lithium aluminum hydride reduction of a ketone is shown in the attached image, the compound is called 3-Pentanol:
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Select all that apply. According to scientists, the distribution of volcanoes throughout the world… Is fairly even and widespread Forms a specific pattern across fault lines Corresponds to plate boundaries Is constantly changing and shifting
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According to scientists, the distribution of volcanoes throughout the world corresponds to plate boundaries.
Also called "divergent boundaries", plate boundaries have many volcanoes. These volcanoes and volcanic eruptions are caused by the movement of plates, which causes lava and magma to seep in the gaps of the plates.
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What is the conjugate acid of hpo22− ? express your answer as a chemical formula?
Answers
The conjugate acid of HPO2- is H2PO4-.
Explanation:The conjugate acid of HPO2- is H2PO4-.
Wade thinks it would be really cool to become a radiologist. Which two skills are important for him to have in order to excel in this career?
A-leadership skills to help oversee the members of the staff within the hospital
B- physical strength to lift heavy equipment and machinery
C-interpersonal skills to talk to patients and help them feel comfortable
D-technical skills to know how to use the machinery and equipment needed for the job
E-public speaking skills to announce research findings in conferences
Answers
Final answer:
To excel in radiology, Wade needs to develop strong interpersonal skills to communicate effectively with patients and excellent technical skills for using and understanding complex radiological equipment and procedures. So the correct options are C and D.
Explanation:
For Wade to excel as a radiologist, there are two essential skills that are particularly important. One of these skills is interpersonal skills, which would allow him to communicate effectively with patients, help them to relax, and explain procedures to provide a comfortable experience. The other key skill is technical skills relating to the use of radiological machinery and equipment. These skills are necessary for accurately performing and interpreting medical imaging, such as computed tomography (CT), magnetic resonance imaging (MRI), and mammography which involves complex operation of medical devices and analysis of the resulting images for diagnostic purposes.
While leadership skills and public speaking abilities can be beneficial in any profession, they are not as central as interpersonal and technical skills for the day-to-day responsibilities of a radiologist. Physical strength is generally less critical, given that lifting heavy equipment is not a common task for radiologists.
If the equilibrium constant kc for the reaction below is 1.71 × 10–1, what will be the equilibrium pressure of no if the initial partial pressures of the three gases are all 1.96 × 10–3 atm? $$
Answers
N₂ + O₂ ⇄ 2NO
We can write an expression for the equilibrium constant. We are given the value of Kc, but we must use Kp if we are dealing with partial pressures. However, since 2 moles of gas are formed from 2 moles of gas, the value of Kc is equal to Kp so we do not need to change anything.
Kc = (Pno)²/(Pn2)(Po2) = 1.71 x 10⁻¹
We must first use the initial pressures to find the reaction quotient to decide which way the equilibrium will shift:
Q = (1.96 x 10⁻³)²/(1.96 x 10⁻³)(1.96 x 10⁻³) = 1
Since Q > Kp, the equilibrium will shift to the left. Now we can prepare an ICE table to find the equilibrium pressures:
N₂ O₂ NO
I 1.96 x 10⁻³ 1.96 x 10⁻³ 1.96 x 10⁻³
C +x +x -2x
E 0.00196 + x 0.00196 + x 0.00196 - 2x
We enter these equilibrium pressures into the equilibrium expression and solve for x:
0.171 = (0.00196 - 2x)²/(0.00196 + x)²
Expand the equation and simplify to a quadratic function:
3.829x² - 0.00851x + 3.183·10⁻⁶ = 0
x = ((0.00851) +/- sqrt((0.00851)² - 4(3.829)(3.183 x 10⁻⁶)))/2(3.829)
x = 0.000476 atm
Now we can solve for the equilibrium partial pressures:
Pno = 0.00196 - 2(0.000476) = 0.00101 atm
Pn2 = 0.00196 + 0.000476 = 0.00244 atm
Po2 = 0.000196 + 0.000476 = 0.00244 atm
Therefore, the equilibrium partial pressure of NO is 0.00101 atm.
Final answer:
To determine the equilibrium pressure of NO, set up an ICE table using the values of the equilibrium constant (Kc) and initial partial pressures. Assume the increase in NO pressure is 'x' and the decrease in N2O and O2 pressures is '2x' and 'x', respectively. Calculate the equilibrium pressures by adding the initial pressures to their corresponding changes.
Explanation:
To determine the equilibrium pressure of NO, we need to set up an ICE table and use the values of the equilibrium constant (Kc) and initial partial pressures of the three gases. Let's assume the increase in the pressure of NO is 'x'. Since the stoichiometric coefficient of NO is 2, the decrease in the pressures of N2O and O2 will be '2x' and 'x', respectively. The equilibrium partial pressures of the three gases can be calculated by adding the initial pressures to their corresponding changes.
Initial pressures:
N2O: 1.96 × 10-3 atmO2: 1.96 × 10-3 atmNO: 1.96 × 10-3 atmChange in pressures:
N2O: -2xO2: -xNO: xEquilibrium pressures:
N2O: (1.96 × 10-3 - 2x) atmO2: (1.96 × 10-3 - x) atmNO: (1.96 × 10-3 + x) atmSince the equilibrium constant (Kc) is given as 1.71 × 10-1, which represents the ratio of the equilibrium concentrations of products to reactants, we can set up the following equation:
Kc = [NO]2 / ([N2O] * [O2])
Substituting the equilibrium pressures into this equation:
1.71 × 10-1 = ([1.96 × 10-3 + x]2 / ([1.96 × 10-3 - 2x] * [1.96 × 10-3 - x]))
Now, solve this equation to find the value of 'x', which represents the equilibrium increase in the pressure of NO.
Once 'x' is determined, substitute it back into the equations for the equilibrium pressures to calculate the final equilibrium pressures of N2O, O2, and NO.
Determine the mass of lithium hydroxide produced when 0.83g of lithium nitride reacts with water
Answers
The mass of Lithium hydroxide that is produced when 0.83g of lithium nitride reacts with water is 1,7122 g.
The reaction between water and lithium nitride is the following:
Li₃N(s) + 3H₂O(l) → NH₃(g) + 3LiOH(aq)
From this reaction we can calculate the mass of lithium hydroxide produced when 0,83 g of Lithium Nitride reacts with water, using the following conversion factor to go from grams of Li₃N to grams of LiOH using the reaction coefficients and molar masses:
[tex]0,83gLi_3N* \frac{1 mol Li_3N}{34,83 g Li_3N}* \frac{3 mol LiOH}{1 mol Li_3N}* \frac{23,95 g LiOH}{1 mol LiOH}= 1,7122 g LiOH [/tex]
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When 0.83g of lithium nitride reacts with water, 1.7g of lithium hydroxide is produced according to the balanced chemical equation and stoichiometry.
Explanation:To determine the mass of lithium hydroxide (LiOH) produced, we first need to understand the balanced chemical equation of the reaction.
Lithium nitride (Li₃N) reacts with water (H₂O) to form lithium hydroxide and ammonia (NH₃), which can be represented as:
Li₃N + 3H₂O → 3LiOH + NH₃
From the equation, we can see that 1 mole of lithium nitride reacts with 3 moles of water to produce 3 moles of lithium hydroxide.
Next, we need to convert the mass of lithium nitride to moles using the molar mass of lithium nitride, which is approximately 34.83 g/mol.
0.83 g Li₃N * (1 mol/34.83 g) = 0.0238 mol
Since the molar ratio of Li₃N to LiOH is 1:3, we multiply this mole by 3 to get the moles of lithium hydroxide produced.
Moles of LiOH = 0.0238 mol * 3 = 0.0714 mol
Finally, we convert the moles of LiOH to grams using the molar mass of LiOH, which is 23.95 g/mol.
Mass of LiOH = 0.0714 mol * 23.95 g/mol = 1.7 g
So, when 0.83g of lithium nitride reacts with water, 1.7g of lithium hydroxide is produced.
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Thorium-234 undergoes beta decay to form a daughter nuclide and a beta particle. what are the mass number and atomic number for the daughter nuclide?
Answers
Beta particles are β⁻, a neutron in the nucleus is converted to a proton and an electron is released. Beta particles are therefore negatively charged and have no mass.
from the parent nuclide to daughter nuclide, there is no change in mass number , however in the parent a neutron converted to proton so there's an additional proton, this means that atomic number also increases by 1. then the daughter nuclide is the element with the corresponding atomic number
²³⁴₉₀Th -------> ²³⁴₉₁Pa + ₋₁⁰β
Th atomic number - 90 , after beta decay proton increases by 1, atomic number of daughter nuclide is 91, the element with atomic number 91 is protactinium.
As neutron converts to proton no net change in mass.
The volume of an automobile air bag was 66.8 l when inflated at 25 °c with 77.8 g of nitrogen gas. what was the pressure in the bag in kpa
Answers
PV = nRT
P - pressure
V - volume - 66.8 / 1000 m³
n - number of moles - 77.8 g/ 28 g/mol = 2.77 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - 25 °C + 273 = 298 K
substituting these values in the equation
P x 0.0668 m³ = 2.77 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 102.7 kPa
Consider the unbalanced equation for the combustion of hexane: αc6h14(g)+βo2(g)→γco2(g)+δh2o(g) part a balance the equation. give your answer as an ordered set of numbers α, β, γ, ... use the least possible integers for the coefficients. α, β, γ, δ = request answer part b determine how many moles of o2 are required to react completely with 6.4 moles c6h14. express your answer using two significant figures. n = mol
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Answer :
Part A : The value of [tex]\alpha, \beta, \gamma \text{ and }\delta[/tex] are 2, 19, 12 and 14 respectively.
Part B : [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].
Solution :
Part A :
The given unbalanced equation is,
[tex]\alpha C_6H_{14}(g)+\beta O_2(g)\rightarrow \gamma CO_2(g)+\delta H_2O(g)[/tex]
The balanced equation is,
[tex]2C_6H_{14}(g)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(g)[/tex]
Part B :
From the balanced equation, we conclude that
2 moles of [tex]C_6H_{14}[/tex] react with 19 moles of [tex]O_2[/tex]
6.4 moles of [tex]C_6H_{14}[/tex] react with [tex]\frac{19moles}{2moles}\times 6.4moles=60.8moles=6.0\times 10^1moles[/tex] of [tex]O_2[/tex]
Therefore, [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].
The balanced equation is 2C3H7(g) + 9O2(g) → 6CO2(g) + 7H2O(g), therefore the coefficients α, β, γ, δ are 2,9,6,7, respectively. And 29 moles of O2 are required to react completely with 6.4 moles of C6H14.
Explanation:For part a, to balance the equation for the combustion of hexane, we have to adjust the coefficients in the equation C6H14(g) + αO2(g) → βCO2(g) + γH2O(g) such that the number of atoms of each element on both sides of the equation are equal. The balanced equation becomes: 2C3H7(g) + 9O2(g) → 6CO2(g) + 7H2O(g) . It means that α, β, γ, δ = 2, 9, 6, 7 respectively.
For part b, according to the balanced equation, 9 moles of O2 are required to react completely with 2 moles of C6H14. So, if there are 6.4 moles of C6H14, you will need: (6.4 moles C6H14 * 9 moles O2) / 2 moles C6H14 = 28.8 ≈ 29 moles of O2. In this case 'n' equals 29 moles.
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a lemon with mass 0.3 kg falls out of a tree from a height of 18 m. how much mechanical energy does the lemon have just before it hits the ground?
Answers
Answer
is: the objects mechanical energy is 52,92 J.
m(object) = 0,3 kg.
h(object) = 18 m.
g = 9,8 m/s².
E(object) = m·g·h.
E(object) = 0,3 kg · 9,8 m/s² · 18 m.
E(object) = 52,92 N·m = 52,92 J..
g - the acceleration of free fall.
mg - weight of the object.
ben helps his dad make chicken soup. their recipe makes 15 cups of soup. if they each eat 2 cups and freeze the rest will the leftovers fit in a 64 ounce container? 1 cup = 8 ounces
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Consider this reaction: 2al(s) + 3 cucl2(aq) → 2alcl3(aq) + 3 cu(s) if the concentration of cucl2 drops from 1.000 m to 0.655 m in the first 30.0 s of the reaction, what is the average rate of reaction over this time interval?
Answers
The average rate of reaction for CuCl₂ is found by dividing the concentration change (0.345 M) by the time interval (30.0 s), resulting in an average reaction rate of 0.0115 M/s for both the disappearance of CuCl₂ and the formation of Cu.
The student is asking about calculating the average rate of reaction using changes in the concentration of a reactant over a given time interval. The average rate of reaction can be calculated by dividing the change in concentration of a reactant by the time period over which the change occurred. In this case, the concentration of CuCl₂ drops from 1.000 M to 0.655 M over 30.0 seconds.
To find the average rate at which CuCl₂ has reacted, we can use the formula:
Calculate the change in concentration of CuCl₂:(Initial concentration) - (Final concentration) = 1.000 M - 0.655 M = 0.345 M. Divide the change in concentration by the time interval:
0.345 M / 30.0 s = 0.0115 M/s.
The average rate of reaction for the disappearance of CuCl₂ is 0.0115 M/s. Since the reaction stoichiometry shows 3 moles of CuCl₂ produces 3 moles of Cu, the average rate of formation of Cu is also 0.0115 M/s.
During respiration, a plant uses glucose (sugar) and oxygen to give it the energy it needs to survive. During this process ______ and _____ are released.
Question 6 options:
hydrogen and oxygen
sunlight and water
water and carbon dioxide
nitrogen and carbon dioxide
Answers
Answer:
water carbon dioxide
Explanation:
_____________ means that animals within a population have a variety of strengths.
Answers
how many moles are there in 78.3g of CO2?
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CO2 — 12 + (16x2) = 12+ 32 = 44 g
Therefore molar mass of CO2 is 44 g/mol
In 44 g of CO2 there’s 1 mol of CO2
Then 1 g of CO2 there’s 1/44 mol of CO2
Therefore in 78.3 g of CO2 there’s — 1/44 x 78.3 =1.78 mol of CO2
Determine the molecular formula of a compound that has a molar mass of 183.2 g/mol and an empirical formula of c2h5o2.
Answers
Good luck and don't forget to rate or mark Brainliest :)
Answer:
[tex]C_6H_{15}O_6[/tex]
Explanation:
Hello,
In this case, one computes the molar mass for the given empirical formula as follows:
[tex]M_{empirical}=12*2+1*5+16*2=61g/mol[/tex]
In such a way, one computes how many times the molecular formula's molecular mass is contained into the empirical formula's molecular mass in order to determine the whole number relating them as shown below:
[tex]\frac{183.2g/mol}{61g/mol}=3[/tex]
Finally, the molecular formula is three times the empirical formula, hence:
[tex]C_6H_{15}O_6[/tex]
Best regards.
Wade thinks it would be really cool to become a radiologist. Which two skills are important for him to have in order to excel in this career?
A-leadership skills to help oversee the members of the staff within the hospital
B- physical strength to lift heavy equipment and machinery
C-interpersonal skills to talk to patients and help them feel comfortable
D-technical skills to know how to use the machinery and equipment needed for the jobE-public speaking skills to announce research findings in conferences
Answers
and I think the second skill should be B or C
Consider the fructose-1,6-bisphosphatase reaction. calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 24.3, and the temperature is 37.0 °c? δg°\' for the reaction is –16.7 kj/mol. the constant r = 8.3145 j/(mol·k)
Answers
A car travels 31.2 miles in 36.0 minutes. What is the average speed of the car during this trip, in miles per hour (mph)?
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in this instance, distance traveled - 31.2 miles
time taken to travel this distance - 36 minutes
time is given in minutes, we need to convert minutes to hours
60 minutes - 1 hour
Therefore 1 minute - 1/60 hr
36 minutes - 1/60 hr/minutes x 36 minutes
- 0.6 hr
speed = distance travelled / time taken
= 31.2 miles / 0.6 hr
= 52 mph (miles per hour)
average speed means that on average the car has been travelling at 52 mph speed. within one hour on average the car can cover 52 miles distance.
Answer:
0.8 mph
Explanation:
divide distance by time
31.2/ 36 = 0.866..
What is the total number of valence electrons for cesium??
Answers
One Valence electron
The key on a pie chart represents...
Answers
Answer:
data that adds up to 100%
Explanation:
An analysis reveals that a substance consists of 26.7% of carbon, 2.24% of hydrogen and 71.1% of oxygen, If the molar mass of the compound is 270.1 g/mol, what is the MOLECULAR Formula?
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find the mole of each molecule
that is for carbon = 26.7/12= 2.23 moles
hydrogen= 2.24/1=2.24 moles
oxygen= 71.1/16=4.44 moles
find the mole ratio of each element
that is divide all moles by the smallest mole( 2.23)
for carbon=2.23/2.23=1,
hydrogen = 2.24/2,23=1
oxygen= 4.44/2.23= 2
the empirical formula = CHO2
therefore the molecular formula=(CHO2)n=270.1
{ ( 12x 1) + 1x1) +(16x2)}n=270.1
45n=270.1
n=6
molecular formula is therefore=(CHO2)6=C6H6O12
The thermodynamic law that explains the movement of heat energy during the refrigeration cycle is the first/zeroth/second.
Answers
is the answer to this queston
What are the 3 parts of the modern cell theory
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2. Cells are the basic unit of life.
3. All cells come from pre-existing cells.
What is the empirical formula of a substance that contains 5.28 g of c, 0.887 g of h, and 3.52 g of o?
Answers
Final answer:
The empirical formula of the compound is CH2O.
Explanation:
To determine the empirical formula of a substance, we need to find the ratio of the number of atoms of each element in the compound.
Step 1: Convert the given masses of each element to moles. Using the molar mass of each element (C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol), we have 5.28 g C = 0.44 mol C, 0.887 g H = 0.877 mol H, and 3.52 g O = 0.22 mol O.
Step 2: Divide each element's mole value by the smallest mole value to get the simplest ratio. In this case, the smallest mole value is 0.22 mol O. Dividing the other mole values by 0.22 gives us 0.44 mol C, 0.877 mol H, and 1 mol O.
The empirical formula of the compound is CH2O.
_____ is the process where the female reproductive cell (egg) is united with the male reproductive cell (sperm).
growth
fertilization
pollination
germination
Answers
The part of the flower responsible for producing pollen (sperm) is the _______.
filament
anther
stigma
style
Answers
Here is your answer:
The proper answer to this question is option C "stigma".
Here is how:
The stigma is responsible for producing pollen in a plant.
Your answer is C.
If you need anymore help feel free to ask me!
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Determine the limiting reactant. 2al(s)+3br2(g)→2albr3(s)
Answers
m(Al) = 25 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 25 g ÷ 27 g/mol.
n(Al) = 0,926 mol.
m(Br₂) = 25 g.
n(Br₂) = 25 g ÷ 160 g/mol.
n(Br₂) = 0,156 mol.
Bromine is the limiting reactant, because it has less amount of substance.
The limiting reactant in a chemical reaction is determined by calculating the amount of product (AlBr3 in this case) that would be produced from the complete reaction of each of the reactants separately. The reactant yielding the lesser amount of product is the limiting reactant.
Explanation:To determine the limiting reactant in a chemical reaction, you can use a method where you compare the amount of each reactant to the amount of product expected from its complete reaction. Taking the given equation, 2Al(s)+3Br2(g)→2AlBr3(s), we would calculate the amount of the product AlBr3 that would be formed from the complete reaction of each reactant, Al and Br2, separately. The reactant that yields the lesser amount of the product AlBr3 is the limiting reactant. This concept can be understood using a simple analogy. Let's think of making a sandwich: 2 slices of bread + 1 slice of cheese yields 1 sandwich. If you have an excess of bread but only one slice of cheese, you can only make one sandwich. The cheese is the limiting reactant as it limits the yield of sandwich and the amount of bread left unreacted is the excess reactant. Similarly, in the chemical reaction given above, the reactant that produces less amount of product (AlBr3) acts as the limiting reactant.
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Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate the mass of helium that it would take to fill the balloon
Answers
In other words in 1 mL there's 1.79 x 10⁻⁴ g of He.
To fill a volume of 6.3 L the mass of He required
= 1.79 x 10⁻⁴ g/mL * 6300 mL
= 11 277 * 10⁻⁴ g
Therefore mass of He required = 1.1277 g of He
Answer:
1.1 x 10-3 g
Explanation:
Write the atomic cores for potassium and chloride ions
Answers
The target is to determine the Lewis structer for the ionic compound KCl.
The atomic cores are the electrons but the outermost shell (i.e. valence electrons).
Potassium has atomic number (Z) 19.
So, its electron distribution is 1s2 2s2 2p6 3s2 3p6 4s
The valence electron is 4s, so the atomic core is 1s2 2s2 2p6 3s2 3p6.
Potassium ion, K+, has lost one electron, the outermost electron, so it has the same electrons as the atomic core of K.
Chlorine has atomic number 17.
The electron distribution of chlorine is 1s2 2s2 2p6 3s2 3p5.
The valence eletrons are 3s2 3p5, so the atomic core of chlorine is 1s2 2s2 2p6.
The ion Cl- has gained one electron so its electron configuration is 1s2 2s2 2p6 3s2 3p6.
To represent the Lewis structure you only use the valence electrons, so the representation is:
**
K(+) +*Cl(-) **
**
Where the * marks represent the 7 valence electrons of chloride atom and the + mark represent the electron gained by chloride and released by potassium.
So, the ion K(+) has lost its only valence electron and the ion Cl(-) has increased its valence electrons to 8. In this way both have the stable configuration of a noble gas.
The atomic core for a potassium ion (K+) is [Ar]4s¹ without the one electron it loses to become an ion. The atomic core for a chloride ion (Cl-) is [Ne]3s² 3p⁵ with an extra electron gained to fill its 3p orbital.
Explanation:The atomic cores for potassium and chloride ions are represented by their respective electron configurations and their charges after ion formation. Potassium (K) has an atomic number of 19, which means it has 19 electrons. The electron configuration is [Ar]4s¹. When potassium forms an ion, it loses one electron to achieve a noble gas configuration, making it a potassium ion with a charge of +1, represented as K⁺.
Chlorine (Cl) has an atomic number of 17, which means it has 17 electrons. The electron configuration is [Ne]3s² 3p⁵. When chlorine forms an ion, it gains one electron to fill its 3p orbital, becoming a chloride ion with a charge of -1, represented as Cl⁻.
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