Which equation is in standard form and represents a line with slope 5 through the point (0, 2)?

We need to find the area of the regular polygon as shown in the image.

Now in a regular hexagon the line joining the center and the vertex of a hexagon have the same length as the length of each side. (Refer the attached image)

[tex]10 \sqrt3cm=10 \times 1.732=17.32 cm[/tex]

A regular hexagon is made up of 6 equilateral triangles inside which means all the sides are of the same length.

Now, we know that the length of a side of an equilateral triangle is [tex]10 \sqrt 3[/tex] cm. So the area of one equilateral triangle is:

[tex]\frac{\sqrt 3}{4} \times (a)^2[/tex]

Where, 'a' is the side length of the equilateral triangle.

Therefore,  area [tex]= \frac{\sqrt 3}{4} \times (10 \sqrt3)^2= \frac{\sqrt 3}{4} \times 100 \times 3=75 \sqrt3[/tex] square centimeters.

Now that we have the area of one equilateral triangle and there are 6 of them in a regular hexagon we can find the area of hexagon.

So, the area of given regular polygon is [tex]=6 \times 75 \sqrt 3=450 \sqrt 3 cm^2[/tex].

Answer:

the answer is: (x-4y)(x-6y)

Step-by-step explanation:

Answer:

The correct answer is 81

Step-by-step explanation:

Here are all the perfect squares.

1 2 1 × 1 1

2 2 2 × 2 4

3 2 3 × 3 9

4 2 4 × 4 16

5 2 5 × 5 25

6 2 6 × 6 36

7 2 7 × 7 49

8 2 8 × 8 64

9 2 9 × 9 81    81 Is a perfect square!

10 2 10 × 10 100

11 2 11 × 11 121

12 2 12 × 12 144

Can I have brainliest please?

A polynomial of one-variable is given by following expression :-

[tex] Ax^n + Bx^{n-1} +Cx^{n-2}+Dx^{n-3}+Ex^{n-4}+..... [/tex]

where A, B, C, D, E are the coefficients of terms in the polynomial and x is variable of the equation.

A is the leading coefficient and it can not be zero i.e. A≠0.

n is the degree of the polynomial.

It says to write a trinomial in one variable of degree 5.

Trinomial means only three terms with non-zero coefficients, and degree 5 means n = 5.

There could be many answers, but an example of "trinomial of degree 5" would be :-

[tex] Ax^5 + Bx^4 + Cx^3 [/tex]

[tex] 3x^5 + 5x^4 + 2x^3 [/tex]

A trinomial in one variable of degree 5 in standard form is [tex]\( ax^5 + bx^3 + cx \),[/tex] where [tex]\( a \), \( b \), and \( c \)[/tex] are non-zero coefficients and [tex]\( a \neq 1 \)[/tex].

A trinomial is a polynomial with three terms. The degree of a polynomial is the highest power of the variable that appears in the polynomial with a non-zero coefficient. Since we are asked to write a trinomial of degree 5, the highest power of the variable x must be 5.

The standard form of a polynomial lists its terms in descending order of their degrees. Therefore, the first term of our trinomial must be [tex]\( ax^5 \),[/tex] where a is a non-zero coefficient, and [tex]\( a \neq 1 \)[/tex] to ensure that the coefficient is explicit.

Since we want a trinomial, we need two more terms. The next term should have a lower degree, and since we're dealing with a degree 5 polynomial, the next possible lower odd degree is 3 (we choose an odd degree to maintain the trinomial structure with distinct powers). This gives us the second term [tex]\( bx^3 \),[/tex] where b is also a non-zero coefficient.

The third and final term of our trinomial must have a degree lower than 3. The next possible lower odd degree is 1, which gives us the term [tex]\( cx \),[/tex] where c is again a non-zero coefficient.

Putting it all together, we have the trinomial [tex]\( ax^5 + bx^3 + cx \)[/tex] as the standard form of a degree 5 polynomial with three terms.

To represent an earthquake that is 100 times more intense than a standard earthquake, an increase of 2 on the Richter scale is required due to the logarithmic nature of the scale.

The magnitude of an earthquake that is 100 times more intense than a standard earthquake would be represented by an increase of 2 on the Richter scale. This scale is logarithmic, meaning that each whole number increase on the Richter scale represents a tenfold increase in amplitude. To be 100 times more intense, we need a tenfold increase for each magnitude, so an increase from, for example, magnitude 3 to 5 would represent an earthquake that is 100 times more intense.

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Answer:

The answer is A

Answer: x=Y^2-6y+50

For APEX

Answer:

x=y^2-6y+50 i need to have more than characters so hdgyhejdufcyhgedhwbsnjdeufhdebwjnkdeufyhedgbw

we know that

A positive number minus a negative number is equal a positive number

so

we have

[tex]5,783-(-500,500)=5,783+500,500=506,283[/tex]

therefore

the answer is

A positive number

Answer:

Bottom Left.

Step-by-step explanation:

Did it got 100%! Thanks so much! Your welcome! Have a great week!

Final answer:

The surface area of a cylinder with a given radius of 3 cm and height of 18.2 cm is calculated using the formula 2πr(height + r), which results in approximately 400.1 square centimeters.

Explanation:

The question asks to find the surface area of a cylinder with a radius of 3 cm and a height of 18.2 cm, using 3.14 for pi. The formula for the surface area of a cylinder is 2πr(height + r), where r is the radius, and the height is the vertical dimension of the cylinder.

Plugging in the given values:

We get: Surface Area = 2 * 3.14 * 3 * (18.2 + 3) = 2 * 3.14 * 3 * 21.2 = 400.1 cm²

Therefore, the surface area of the cylinder, rounded to the nearest tenth, is 400.1 square cm.

Look at the picture.

Answer:

A'(-1, 1), B'(-2, 1), C'(-2, 2), D'(-1, 3)

Answer:

A' = (-1,3)   -  A = (3,11)

B' = (-2,2)  -  B = (2,2)

C' = (-2,1)  -  C = (1,2)

D' = (-1,1)  -   D = (1,1,)

Step-by-step explanation:

We have the polygon ABCD transformed to the polygon A'B'C'D' with the co-ordinates,

A' = (-1,3), B' = (-2,2), C' = (-2,1) and D' = (-1,1).

Since, the polygon is rotated 90 counterclockwise about the origin.

The co-ordinates (x,y) of ABCD will change to (-y,x) for A'B'C'D'.

So, we will change the co-ordinates (-y,x) of A'B'C'D' to (x,y) which gives the co-ordinates of ABCD.

That is,

Take the y-value to the 1st position and x-value to the second multiplied by negative sign.

Thus, we have,

A' = (-1,3)   ------------------  A = (3,1)

B' = (-2,2)   ------------------ B = (2,2)

C' = (-2,1)   ------------------ C = (1,2)

D' = (-1,1)   ------------------- D = (1,1,)

The correct answer is option B. -1.5.

To calculate the z-score for a wide receiver who dropped 13 footballs over the course of a season, we use the z-score formula:

z = (X - μ) / σ

where:

Substitute the values into the formula:

z = (13 - 16) / 2

This simplifies to:

z = -3 / 2 = -1.5

Therefore, the z-score for a wide receiver who dropped 13 footballs is B. -1.5.

To factor an expression, you need to analyze it and find a common variable or expression on the expression given. In this expression, you can observe that the expression x^2 – 7 is common to the two terms. You need to factor it out from the both of them.

4x (x^2 – 7) + 3 (x^2 – 7)

(x^2 – 7) (4x + 3)

This is already the complete factor of the expression.

The equation of a line that is perpendicular to the given line is                 y = -4/3x + c.

The equation of a line means an equation in x and y whose solution set is a line in the (x,y) plane. The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term.

For the given situation,

The equation of a line is y = 3/4x - 1/2 ------ (1)

The general form of equation of line in slope intercept form is

[tex]y=mx+c[/tex]

On comparing the equation 1 with general form,

Slope of the line, [tex]m=\frac{3}{4}[/tex]

Then, the slope of the line perpendicular to the given line is [tex]\frac{-1}{m}[/tex]

⇒ [tex]\frac{-1}{m}=\frac{-1}{\frac{3}{4} }[/tex]

⇒ [tex]\frac{-1}{m}=\frac{-4}{3}[/tex]

No points were defined that this 'normal' should pass through, so its intercepts are indeterminate.

Thus the equation of line in slope intercept form is

[tex]y=\frac{-4}{3}x+c[/tex]

Hence we can conclude that the equation of a line that is perpendicular to the given line is y = -4/3x + c.

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