Which function represents a reflection of f(x) = 2(0.35)x over the y-axis? h(x) = 2(0.35)x h(x) = –2(0.35)x h(x) = 2(0.35)–x h(x) = 2(–0.35)–x

Answers

Answer 1
the answer is h(x) = 2(0.35)-x 
Answer 2

Answer:

Step-by-step explanation:

c


Related Questions

If a piece of licorice is to be cut into 10 equal-side pieces. If the length of the piece of licorice is 2/3 yard, how long will each piece of licorice be?

Answers

This is the term used to describe economic systems in which the basic economic questions are answered based on a socially, pre-established way.

The area of the large cylinder’s piston in this hydraulic system is 3.14m2 . What is the output force

Answers

the complete question in the attached figure

see the attached drawing to better understand the problem

Part A)
we know that
Area small piston=0.0020 m²
Force=100 N
[Pressure]=[Force]/[Area]
[Pressure]=[100 N]/[0.0020 m²]=50000 Pa

the answer part A is 50000 Pa

Part B)
Pressure=50000 Pa
Area large piston=3.14 m²
[Force]=[Pressure]*[Area}
[Force]=50000 Pa]*[3.14 m²]=157000 N

the answer part B) is 157000 N

A scout troop planned to take a bus for an overnight trip to a campground in a nearby state. The bus will cost $360 to rent. The bus company told them that if they could get 3 more troop members to join in the trip each person could pay $6 less to go on the trip. If the troop was able to find the 3 additional people to join the trip, which answer is the most reasonable for the number of members that went on the trip?

Answers

Let x represent the number originally signed up.
.. 360/x -6 = 360/(x +3)
.. 360*(x +3) -6x(x +3) = 360x . . . . . multiply by the product of denominators
.. 360x +1080 -6x^2 -18x = 360x
.. x^2 +3x -180 = 0
.. (x +15)(x -12) = 0
Solutions are x = {-15, 12}

12 members went on the trip.
_____
The problem wording does not make clear whether the original number (12) or the number suggested by the bus company (15) went on the trip. It would be most reasonable for 15 to go, if the troop had people who were willing.

In 2008 Melvin thought that he was making a sound investment by buying $100,000 worth of Alpha Biotechnology stock. Unfortunately, his investment has depreciated, losing 13% of its current value each year.

Answers

The current value of an invested of $100, 000 that has lost a value of 13% will be:
current value in percent=100-13=87%
The value of $100,000 investment will be:
87/100*100000
=$87,000

Create three polynomials. Each must contain at least two terms. Choose three of the following properties:

Answers

Polynomial means 3 terms 
 
1. 3x + 4c - 3
2. 9x + 7y - 6/2
3.4r^2 + 9y -5t

PLEASE HELP
7.01

1. Find the first six terms of the sequence.
a1 = 4, an = an-1 + 8


A) 0, 8, 16, 24, 32, 40
B) 12, 20, 28, 36, 44, 52
C) 4, 12, 20, 28, 36, 44
D) 4, 8, 16, 24, 32, 40

2. Find the first six terms of the sequence.
a1 = -8, an = 5 an-1

A) -8, -40, -200, -1000, -5000, -25,000
B) -8, -40, -35, -30, -25, -20
C) 0, 5, -40, -35, -30, -25
D) -40, -200, -1000, -5000, -25,000, -125,000

3. Find an equation for the nth term of the arithmetic sequence.
8, 6, 4, 2, ...


A) an = 8 + -2(n)
B) an = 8 - 2
C) an = 8 + -2(n + 1)
D) an = 8 + -2(n - 1)

4. Find an equation for the nth term of the arithmetic sequence.
-17, -12, -7, -2, ...


A) an = -17 + 5(n + 2)
B) an = -17 + 5(n + 1)
C) an = -17 + 5(n - 1)
D) an = -17 x 5(n - 1)

5. Find an equation for the nth term of the arithmetic sequence.
a19 = -58, a21 = -164

A) an = 896 - 53(n - 2)
B) an = 896 - 53(n - 1)
C) an = 896 + 53(n + 1)
D) an = 896 - 53(n + 1)

6. A certain species of tree grows an average of 0.5 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 200 centimeters tall.

Answers

1. Find the first six terms of the sequence.a1 = 4, an = an-1 + 8
 For this case, the first thing you should do is replace the values ​​given one by one.
 We have then:
 a1 = 4
 a2 = a1 + 8 = 4 + 8 = 12
 a3 = a2 + 8 = 12 + 8 = 20
 a4 = a3 + 8 = 20 + 8 = 28
 a5 = a4 + 8 = 28 + 8 = 36
 a6 = a5 + 8 = 36 + 8 = 44
 Answer:
 C) 4, 12, 20, 28, 36, 44


 2. Find the first six terms of the sequence.
a1 = -8, an = 5 an-1
 
 For this case, the first thing you should do is replace the values ​​given one by one.
 We have then:
 a1 = -8,
 a2 = 5 ^ (- 8) = -40
 a3 = 5 ^ (- 40) = -200
 a4 = 5 ^ (- 200) = -1000
 a5 = 5 ^ (- 1000) = -5000
 a6 = 5 ^ (- 5000) = -25000
 answer:
 A) -8, -40, -200, -1000, -5000, -25,000

 3. Find an equation for the nth term of the arithmetic sequence.
8, 6, 4, 2, ...
 What you must do for this case is to verify which sequence is best suited to the problem.
 For this case we have:
 8, 6, 4, 2,
 The sequence is:
 an = 8 + -2 (n - 1)
 a1 = 8 + -2 (1 - 1) = 8
 a2 = 8 + -2 (2 - 1) = 6
 Answer:
 An equation for the nth term of the arithmetic sequence is
 D) an = 8 + -2 (n - 1)

 4. Find an equation for the nth term of the arithmetic sequence.
-17, -12, -7, -2, ...
 What you must do for this case is to verify which sequence is best suited to the problem.
 For this case we have:
 -17, -12, -7, -2,
 The sequence is:
 an = -17 + 5 (n - 1)
 a1 = -17 + 5 (1 - 1) = - 17
 a2 = -17 + 5 (2 - 1) = - 12
 Answer:
 Answer:
 An equation for the nth term of the arithmetic sequence is
 C) an = -17 + 5 (n - 1)



 5. Find an equation for the nth term of the arithmetic sequence.
a19 = -58, a21 = -164
 What you must do for this case is to verify which sequence is best suited to the problem.
 For this case we have:
 a19 = -58, a21 = -164
 The sequence is:
 an = 896 - 53 (n - 1)
 a19 = 896 - 53 (19 - 1) = - 58
 a21 = 896 - 53 (21 - 1) = - 164
 Answer:
 An equation for the nth term of the arithmetic sequence is
 B) an = 896 - 53 (n - 1)

 6. A certain species of tree grows an average of 0.5 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 200 centimeters tall.

 For this case, what you should do is to write the equation step by step to find the correct result.
 We have then:
 the measurements begin when the tree is 200 centimeters tall
 200
 tree grows an average of 0.5 cm per week
 200 + 0.5n
 Where
 n: number of weeks.
 answer:
 An equation for the sequence that represents the weekly height of this tree in centimeters is
 an = 200 + 0.5n
Final answer:

The answers identified are: (C) for the first sequence question, (A) for the second sequence question, (D) for the arithmetic sequence with a start of 8 and difference -2, (C) for the arithmetic sequence starting from -17, (B) for the arithmetic sequence question with given a19 and a21, and finally an = 200 + 0.5n for the tree growth question.

Explanation:

The correct answers are as follows:

For the first question, you start with 4 (a1 = 4) and each subsequent term is the previous term plus 8 (an = an-1 + 8). This gives the sequence 4, 12, 20, 28, 36, 44, which matches option (C).For the second question, starting at -8 (a1 = -8) and then multiplying the previous term by 5 gives you -8, -40, -200, -1000, -5000, -25,000, which matches option (A).For the third question, the common difference between consecutive terms is -2 and the first term is 8, which gives an = 8 - 2(n - 1) (option D)For the fourth question, the common difference is +5 and the first term is -17, so the equation for the nth term is an = -17 + 5(n - 1) (option C). For the fifth question, the common difference can be calculated from the problem as 53. Hence the equation for the nth term is an = 896 - 53(n - 1) (option B).For the last question, if the tree grows at a rate of 0.5 cm per week and the initial height is 200 cm, the height of the tree each week is represented by an = 200 + 0.5n.

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if the measures of the angles of a triangle are represented by (x+30), (4x+30), and (10x-30), the triangle must be

Answers

The sum of angle measures is 15x+30 = 180, so x=10.

The angles are 40°, 70°, and 70°.

The triangle is isosceles.
We know triangles equal 180. Add all angles equal to 180. Then plug in the answer for x in each angle expression.

(x+30)+(4x+30)+(10x-30)= 180
combine like terms
15x+30=180
subtract 30 from both sides
15x= 150
divide both sides by 15
x=10

Angle 1:
=(x+30)
=10+30
=40

Angle 2:
=(4x+30)
=4(10)+30
=40+30
=70

Angle 3:
=(10x-30)
=10(10)-30
=100-30
=70

ANSWER: Since there are two equal angles, this is an Isosceles Triangle.

Hope this helps! :)

Find the volume of the composite solid if the diameter is 8.7 yards. Round your answer to the nearest hundredth.


A.
220.76 yd3
B.
429.88 yd3
C.
535.02 yd3
D.
693.55 yd3

Answers

The closest answer is D. 693.55 yd3 
H
   O
      P
        E
             T
                H
                    I
                      S
                           H
                               E
                                  L
                                      P
                                         S 
                                              =)

Answer: D.    693.55 yd3

Step-by-step explanation:

Given: The diameter of the composite solid = 8.7 yards

Then , the radius of the composite solid = [tex]\dfrac{8.7}{2}=4.35\ \text{yards}[/tex]

Height of cylinder = 9 yards

Height of cone = 8 yards

The volume of cylinder is given by :-

[tex]V_1=\pi r^2h\\\\\Rightarrow V_1=(3.14159265359)(4.35)^2(9)\\\\\Rightarrow V_1=535.021082888{ yards}^3[/tex]

The volume of cone is given by :-

[tex]V_2=\dfrac{1}{3}\pi r^2h\\\\\Rightarrow V=\dfrac{1}{3}(3.14159265359)(4.35)^2(8)\\\\\Rightarrow V=158.5247653\text{ yards}^3[/tex]

Now, Volume of the composite figure will be :

[tex]V=V_1+V_2\\\\\Rightarrow\ V=535.021082888+158.5247653\\\\\Rightarrow\ V=693.545848188\approx693.55\text{ yards}^3[/tex]

An airplane has a maximum capacity of 118 passengers. The flight attendant has loaded 40 passengers. Which inequality represents the solution set that shows the number of passengers, p, that can still load the plane? A) p ≥ 68 B) p ≤ 68 C) p ≤ 78 D) p ≥ 78

Answers

Answer:

Its C

Step-by-step explanation:

It is C because you can only load 78 more passengers

Answer:

c

Step-by-step explanation:

If p = the number of passengers that can still load the plane, then p + 40 ≤ 118.

Therefore,

p + 40 ≤ 118

p + 40 − 40 ≤ 118 − 40

p ≤ 78

Given the geometric sequence where a_1 = 3 and r = √2 find a_9
A.] 48
B.] 48√2
C.] 64
D.] 64√2

Answers

To find n-therm of a geometric sequence, we are going to use the formula [tex]a_{n} =a _{1} r^{n-1} [/tex]
where:
[tex]a_{n} [/tex] is the term we are looking for
[tex]a _{1} [/tex] is the first term 
[tex]r[/tex] is the ratio 
[tex]n[/tex] is the position of the number in the sequence 

From the question we now that [tex]a _{1} =3[/tex], [tex]r= \sqrt{2} [/tex], and [tex]n=9[/tex]. Lets replace those values into our formula to get:
[tex]a _{9} =3( \sqrt{2} )^{9-1} [/tex]
[tex]a_{9} =3 \sqrt{2} ^{8} [/tex]
[tex]a_{9} =48[/tex]

We can conclude that in our geometric sequence [tex]a_{9} =48[/tex]; therefore, the answer is A.

jami can now mow 1/6 acre in 8 minutes. if her rate is constant, can jami mow 1 and 1/2 acres in one hour? explain ur reasoning.

Answers

we have that
 1 1/2 acres-------------> 1.5 acres
one hour----------------> 60 minutes

Step 1
I proceed to make a rule of three
if Jami can now mow 1/6 acre -----------------------> in 8 minutes
1.5 acres----------------------------------------------> X
X=1.5*8/(1/6)=72 minutes

72 minutes > 60 minutes

therefore
Jami can not mow 1 1/2 acres in an hour
The time required by jami to mow 1 1/2 acres is 72 minutes

Which of the following ordered pairs is a solution of x + 1/2 y = 1?

(-2, 6)
(2, -6)
(-2, -6)

Answers

x+y/2=1
-2+6/2=1

-2 + 3 =1   true

( -2, 6) is the solution

The  correct ordered pairs are (-2, 6)

What is equation?

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Parts of an Equation

There are different parts of an equation which include coefficients, variables, operators, constants, terms, expressions, and an equal to sign. When we write an equation, it is mandatory to have an "=" sign, and terms on both sides. Both sides should be equal to each other. An equation doesn't need to have multiple terms on either of the sides, having variables, and operators.

An equation can be formed without these as well, for example, 5 + 10 = 15. This is an arithmetic equation with no variables.

Given:

x + 1/2 y = 1

Now, we will take the ordered pairs (-2, 6)

So, substitute x= -2 and y= 6 in the given equation we get

x+ 1/2y

=-2 + 1/2(6)

=-2 + 3

=+1

Hence, the correct ordered pairs are (-2, 6)

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Which table of ordered pairs represents a proportional relationship

Answers

Your answer is (B.) because 2 times 5 is 10. 4 times 5 is 20. and 6 times 5 is 30, these make proportional relationships.

Answer:

The second table.

Step-by-step explanation:

In this case, "a proportional relationship" refers to the presence of a constant of variation between variables, that is, variables must variate at the same rate, where such rate is call the constant of proportionality.

Notice that the second table fulfils this definion, because x-variable variates 2 units, while y-variable variates ten units. To find the constant of proportionality, we just need to divide

[tex]k=\frac{10}{2}=5[/tex]

Which means that y-variable represents five times x-variable, let's evalute to prove this

[tex]2 \times 5=10\\4 \times 5 = 20\\6 \times = 30[/tex]

Notice that we got all y-values.

Therefore, the right table is the second one, it presents a proportional relationship.

helpppppppppppppppppppppppp

Answers

Remember that
 you must do in this case is composition of both functions: 
 a (x) = 3x + 1 
 b (x) = root (x-4) 
 Making the composition we have: 
 b (a (x)) = root ((3x + 1) -4) 
 Rewriting: 
 b (a (x)) = root (3x-3) 
 b (a (x)) = root (3 (x-1)) 
 Answer: 
 The domain of the function is: x> = 1 
 Equivalently we have [1, inf)

The main arena hall has dimensions 200 m by 85 m. On a large diagram on the office wall the scale is 1:40. What are the dimensions of the floor space on the diagram?

Answers

Answer:

500 cm by 212.5 cm

Step-by-step explanation:

Using the scale 1:40 on the 200 m dimension, we have 200/40 = 5 m.  Each meter is 100 cm; this makes this 5(100) = 500 cm.

Using the scale on the 85 m dimension, we have 85/40 = 2.125 m.  Each meter is 100 cm; this makes this 2.125(100) = 212.5 cm.

Answer:

500 cm by 212.5 cm

Step-by-step explanation:

Given :

The main arena hall has dimensions 200 m by 85 m.

On a large diagram on the office wall the scale is 1:40.

To Find: What are the dimensions of the floor space

Solution :

Length of arena hall = 200 m

Scale is 1:40

So, the length of the floor = [tex]\frac{200\times 1}{40}[/tex]

                                           =  [tex]5m[/tex]

Since 1 m = 100 cm

So, 5 m = 100*5 = 500 cm

Width of arena hall  = 85 m

So, width of floor = [tex]\frac{85\times 1}{40}[/tex]

                             =  [tex]2.125m[/tex]

Now 1 m = 100 cm

So, 2.125 m = 212.5 cm

Thus the dimensions of floor is 500 cm by 212.5 cm

The ratio of the measures of the sides of a triangle is 9:15:5. If the perimeter of the triangle is 130 feet, find the measures of the sides.

Answers

5x + 9x +15x = 130
29x = 130
x = 4.4827586207
So the triangle sides =
22.4137931034
40.3448275862
67.2413793103


helpppppppppppppppppppppppp

Answers

We make the composition of both functions:
 f (x) = x ^ 2-1
 g (x) = 2x-3
 Then:
 f (g (x)) = (2x-3) ^ 2-1
 Rewriting:
 f (g (x)) = 4x ^ 2-12x + 8
 The domain of this function is all real numbers.
 Equivalently
 x: (-inf, inf)
 answer:
 x: (-inf, inf)
 option 1.

559 tickets were sold 59 more student tickets were sold than adult tickets how many adult tickets were sold

Answers

Let s = number of student tickets and a = number of adult tichets;
We have the equation: s + a = 559 and s = 59 + a;
Then, we solve the equation: 59 + a + a = 559;
59 + 2a = 559;
2a = 500;
a = 500/2;
a = 250;
s = 59 + 250;
s = 309;

The number of adult tickets sold will be 250.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Suppose the number of student tickets is S while adult tickets are A.

As per the given,

59 more student tickets were sold than adult tickets.

S = A + 59

S - A = 59

Total tickets S + A = 559

Add both equations as

S - A + S + A = 559 + 59

2S = 618

S = 309

A = 309 - 59 = 250

Hence "The number of adult tickets sold will be 250".

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Which equation is quadratic in form 2(x+5)^2+8x+5+6=0, x^6+6x^4+8=0, 7x^6+36x^3+5=0, 4x^9+20x^3+25=0?

Answers

Equation 2(x+5)² + 8x + 5 + 6 = 0 or 2x² + 28x + 61 = 0 is the equation in quadratic form.

What is a quadratic equation?

A quadratic equation is an equation of second order. Quad implies the square power, it is also called equation of degree 2.

The standard form of a quadratic equation is ax² + bx + c = 0.

Where a, b and c are constants.

In the given equation,

2(x+5)² + 8x + 5 + 6 = 0

2 (x² + 25 + 10x) + 8x + 11 = 0

2x² + 50 + 20x + 8x + 11 = 0

2x² + 28x + 61 = 0

This is the quadratic equation.

Rest of the equation are in the higher degree power, only equation 2x² + 28x + 61 = 0 is second power equation.

Hence, 2x² + 28x + 61 = 0 is a quadratic equation.

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SIMPLIFY the radical expression: square root of 75 + square root of 3

Answers

I believe the answer would be 10.39, since the square root of 75 is 8.66 and the square root of 3 is 1.73. Adding them both would give you 10.39. Hope this helped!

Toys R us is having a 38% off sale on all of their backpacks. If a backpack normally cost $22 how much will it be on sale

Answers

38% = 38/100 = 0.38

22*0.38 = 8.36, so we know that the sale takes $8.36 off.

22 - 8.36 = 13.64.

The discounted price after the sale is $13.64


Joaquim is baking giant cookies for the school bake sale. They will be sold for $20 for one large cookie or $20 for three small cookies. Which offer is the better buy? Explain your reasoning.

Answers

Small i believe
Because sure the large is bigger but you get more with the small cookies

Three small cookies for $20 is a better buy than one large cookie for $20 because the cost per small cookie is cheaper ($6.67 per small cookie). You get more cookies for the same price.

To determine which offer is the better buy, let's compare the cost in terms of cookies:

One large cookie: $20 for 1 large cookie.Three small cookies: $20 for 3 small cookies.

Next, let's find the cost per small cookie:

For the large cookie: $20 / 1 large cookie = $20 per large cookie.For the small cookies: $20 / 3 small cookies = $6.67 per small cookie (approximately).

Therefore, since $6.67 per small cookie is less than $20 for 1 large cookie, the offer of three small cookies for $20 is the better buy. This way, you get three cookies for the same price as one large cookie.

Substitute

-3x-8y=4
-2x+7y=15

Answers

-2x=15-7y
x=-7.5+3.5y

-3x-8y=4
-3(7.5+3.5y)-8y=4
-22.5-10.5y-8y=4
-22.5-18.5y=4
-18.5y=4+22.5
-18.5y=26.5
y=-53/35

the fraction might not be in lowest terms.

What is the solution to the equation g(x) = 3?

x = 3

3 < x < 5

3 ≤ x ≤ 4

3 ≤ x < 5

Answers

The correct answer is:  [A]:  " x = 3 " .
__________________________________________________

❤️ Kinda fuzzy but can anyone help?

Answers

The answer would be B.

Answer:

thats to hard

Step-by-step explanation:

get a calculater

In the diagram, KL ≅ NR and JL ≅ MR. What additional information is needed to show ΔJKL ≅ ΔMNR by SAS?
A. ∠J ≅ ∠M
B. ∠L ≅ ∠R
C. ∠K ≅ ∠N
D.∠R ≅ ∠K

Answers

B. Angle L=angle R. To prove congruence of triangles by SAS, we need two pairs of sides to be equal, and the included angle equal. We are given KL=NR and JL=MR (the two pairs of sides), then we only need that the angle between KL and JL equals to the angle between NR=MR, so L=R.

Answer:

B. <L=<R  

Step-by-step explanation:

^^^Just too test got 100%

A scale drawing of an automobile has a scale of 1 in.
The actual width of the car is 8 ft. What is the width on the scale drawing?

Answers

the correct question in the attached figure

we know that
the scale is 1 in (scale drawing)= (1/2) foot (actual)-----> 1/(1/2)=2 in/ft
[scale]=[scale drawing]/[actual]
then
[scale drawing]=[scale]*[actual]
therefore
for  actual width of the car  8 ft
[scale drawing]=[2 in/ft]*[8 ft]=16 in

the answer is 16 in

If you have 240 homies and the Crips rolls up on your block poppin 128 of yo homies, how many homies do ya got left?

Answers

you will only have 112 homies left.

Answer:

You'll have 112 blood homies left

240b-128b=112b

112

Write the equation of a circle with a center at (15, –35) and a diameter of 100.

(x – 15)2 + (y + 35)2 = 250

(x – 15)2 + (y + 35)2 = 50

(x – 15)2 + (y + 35)2 = 2500

(x – 15)2 + (y + 35)2 = 100

Answers

(x-15)2+ (y+35)2=2500. for sure without a doubt.

The newspapers cover page is 3/8 text and photographs filled the rest if 2/5 of the text is an article about endangered species, what fraction of the cover page is the article about endangered species

Answers

The fraction of text -3/8 of the cover page
From this fraction of text only 2/5 of the text is about endangered species
We are asked to find out what the fraction of the cover page is that covers endangered species
In this 2/5 of 3/8 is about endangered species
Therefore to obtain the answer we need to multiply the two fractions
2/5 * 3/8
Fraction of the cover page about endangered species is therefore = 2/5 * 3/8
= 0.15

The article about endangered species is  ³/₂₀ of the cover page

Further explanation

Order of Operations in Mathematics follow this following rule :

ParenthesesExponentsMultiplication and DivisionAddition and Subtraction

This rule is known as the PEMDAS method.

In working on a mathematical problem, we first calculate operation that is in parentheses, follow by exponentiation, then multiplication or division, and finally addition or subtraction.

Let us tackle the problem !

Given:

Total Area of Cover Page = X

Text Section is 3/8 the newspapers cover page

[tex]\texttt{Text Section Area} = \frac{3}{8} \times \texttt{Total Area of Cover Page}[/tex]

[tex]\texttt{Text Section Area} = \boxed {\frac{3}{8}X}[/tex]

The rest of cover page is Photographs Section

[tex]\texttt{Photographs Section Area} = (1 - \frac{3}{8}) \times \texttt{Total Area of Cover Page}[/tex]

[tex]\texttt{Photographs Section Area} = \boxed {\frac{5}{8}X}[/tex]

2/5 of the text is an article about endangered species.

[tex]\texttt{Endangered Species Article Section Area} = \frac{2}{5} \times \texttt{Text Section Area}[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \frac{2}{5} \times \frac{3}{8}X[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \frac{2 \times 3}{5 \times 8}X[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \frac{6}{40}X[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \frac{6 \div 2}{40 \div 2}X[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \boxed {\frac{3}{20}X}[/tex]

Learn moreInfinite Number of Solutions : https://brainly.com/question/5450548System of Equations : https://brainly.com/question/1995493System of Linear equations : https://brainly.com/question/3291576

Answer details

Grade: Middle School

Subject: Mathematics

Chapter: Percentage

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS , percentange , percent

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