Which functional group is found in methyl ethanoate

Answer:

1.25 moles of Ba(NO3)2 will be formed.

Explanation:

Given data:

moles of AgNO3 = 2.50 mol

moles of Ba(NO3)2 = ?

Solution:

First of all we will write the balance chemical equation.

2AgNO3 + BaCl2 → Ba(NO3)2 + 2AgCl

Now we compare the moles of AgNO3 and  Ba(NO3)2.

   AgNO3   :    Ba(NO3)2

     2           :        1

     2.5        :        1/2 × 2.5 = 1.25 moles

so, 2.50 moles of AgNO3 will produce 1.25 moles of Ba(NO3)2.

The atom with 27 protons and 32 neutrons is represented as 59Co. The number is calculated by adding protons and neutrons which is the mass number, and the protons determine the element symbol.

The correct symbol for the atom is based on the number of protons it contains. The atomic number, which is what the number of protons is known as, identifies the element. In this case, 27 protons correspond to the element cobalt (Co). The mass number of an element is the sum of protons and neutrons, so in this atomic configuration, the total would be 27 protons + 32 neutrons = 59. Therefore, the correct symbol for this atom is 59Co.

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Answer:

The correct answer is C: A triglyceride

Explanation:

A carbohydrate is a biomolecule consisting of carbon (C), hydrogen (H) and oxygen (O) atoms. A carbohydrate is is a synonym of saccharide.

A triglyceride  is an ester derived from glycerol and three fatty acids. So not a saccharide. The other 3 options all are saccharides. Triglycerides are the main constituents of body fat.

Triglyceride is not a type of carbohydrate molecule. It's a type of fat found in the blood, while disaccharides, glucose molecules and polysaccharides represent different types of carbohydrates.

Among the choices A. A disaccharide, B. A glucose molecule, C. A triglyceride, and D. A polysaccharide, option C. A triglyceride is NOT a type of carbohydrate molecule. Instead, triglycerides are a type of fat found in the blood. A person's body converts calories it doesn't need for energy into triglycerides. On the other hand, disaccharides, glucose molecules and polysaccharides are all different types of carbohydrates, which are molecules consisting of carbon, hydrogen, and oxygen atoms.

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Answer:

Explanation:

Given the characteristics:

acetone is a non polar molecule

water, NaOH and HCl in water, the three of them are highly polar molecules

So then, the unknown compound is a non polar molecule.

Answer:

A rag contaminated with gasoline is considered a hazard waste. The question seems to be asked to ask for indications of rag disposal on a ship, and if so, the answer is d) Discard it on land BUT with special precautions

Explanation:

Gasoline is a highly flammable organic solvent that is used as fuel. For the above is a dangerous substance. while the ship reaches the mainland, the rag must be stored avoiding contact with environmental agents such as the sun, pets or food. Once in a dry land the rag can be delivery for accurate disposal.

I hope my answer helps you

Answer: 0.72 litres of water is wasted in one day.

Explanation:

First you need to find out how many minutes are in a day. Do this by multiplying the number of minutes in an hour (60) by the number of hours in a day (24). 24 x 60 = 1440. If the faucet is dripping at 5 drops per minute, then multiply 5 by the number of minutes in a day (1440) to see how many drops drip in one day. 5 x 1440 = 7200. Now we need to figure out how many mL fo water that is. if 10 drops is 1 mL, then we need to divide the total number of drops (7200) by 10. 7200 divided by 10 is 720. That means 720 mL of water is dripping per day. Finally, we must convert mL to litres. There are 1000 mL in one litre, so divide 720 by 1000. The final answer is 0.72

Final answer:

The limiting reactant is iron, which allows a maximum of 10.0 g of [tex]Fe_3O_4[/tex] to form from the reaction of 10.0 g of Fe and [tex]H_2O[/tex] according to the stoichiometry of the balanced equation.

Explanation:

Firstly, find the limiting reactant in the reaction between iron (Fe) and water [tex](H_2O)[/tex] to form iron(II,III) oxide [tex](Fe_3O_4)[/tex] and hydrogen gas [tex](H_2)[/tex].

The balanced chemical equation is: [tex]3 Fe(s) + 4 H_2O(l) \rightarrow Fe_3O_4(s) + 4 H_2(g)[/tex].

To find the limiting reactant, we convert the masses of the reactants into moles:

Using the stoichiometric coefficients from the balanced equation, we determine the ratio to find the limiting reactant:

For iron:

[tex]0.179 moles Fe \times (\frac{1 mol Fe_3O_4}{3 mol Fe})[/tex] = 0.0597 moles [tex]Fe_3O_4[/tex]

For water:

[tex]0.555 moles H_2O \times(\frac{1 mol Fe3O4}{4 mol H2O})[/tex] = 0.1388 moles [tex]Fe_3O_4[/tex]

Iron is the limiting reactant because it produces fewer moles of product. Now, we calculate the mass of [tex]Fe_3O_4[/tex] formed using the molar mass:

[tex]0.0597 moles Fe_3O_4 \times (231.55 g/mol)[/tex] = 13.82 g of [tex]Fe_3O_4[/tex]

However, since we cannot have a mass of product greater than the mass of our limiting reactant, the error must be in the significant figures. Taking into account significant figures, we have:

10.0 g Fe limit our product to a maximum of 10.0 g, so the real yield of [tex]Fe_3O_4[/tex] will be 10.0 g.

Answer:

The HNO3 solution has a concentration of 0.07 M

Explanation:

Step 1: find a balanced equation

HNO3 (aq) + NaOH (aq) → NaNO3 (aq) + H2O (l)

⇒ for 1 mole of HNO3 reacted, there will also react 1 mole of NaOH, and be produced 1 mole of NaNO3 and 1 mole of H2O, since the ratio is 1:1

Step 2: Calculating moles

Since we know that for 1 mole of HNO3 there will react 1 mole of NaOH, we can calculate the number of moleNaOH

⇒ Concentration = mole / volume

⇒ 0.210 = mole / ((20 + 7.23 ml) *10^-3)

mole = 0.005733 mole NaOH  = 0.005733 mole HNO3

Step 3: Calculating the concentration of HNO3

Concentration = mole / volume

C(HNO3) = 0.005733 mole / ((50 + 30 ml) *10^-3)

C(HNO3) = 0.07 M

The HNO3 solution has a concentration of 0.07 M

To control this we can calculate through the following formule:

0.02723L x 0.21 M x ( 1mol HNO3 / 1 mol NaOH) x (1/ 0.08L) = 0.07M

In a titration using phenolphthalein as an indicator, the concentration of HNO3 can be determined by considering the amount of NaOH used to reach the end point twice. The final concentration of the nitric acid (HNO3) solution is calculated to be approximately 0.0715 M.

We need to calculate the concentration of the HNO3 solution. In a titration of HNO3, we used a phenolphthalein indicator and added 20.00 mL of 0.210 M NaOH, passed the end point and reached a deep pink color solution. After erroneously overshooting the end point, you add 30.00 mL of HNO3 to the solution which then turns colorless. Finally, you add an additional 7.23 mL of NaOH to once again reach the end point.

Let's write out the balanced equation for the reaction:

HNO3 + NaOH → NaNO3 + H2O

From the complete balanced equation above, we can see that one mole of NaOH reacts with one mole of HNO3, so the same amount of moles of NaOH that react is the number of moles of HNO3 in the acid solution.

The total volume of NaOH solution used to neutralize the HNO3 is 20.00 + 7.23 = 27.23 mL, which is 0.02723 L.

We can find the number of moles of NaOH by multiplying the volume (in liters) by the molarity: 0.02723 L * 0.210 mol/L = 0.0057213 moles of NaOH

Since the total volume of HNO3 solution is 50.00 + 30.00 =80.00 ml or 0.080 L, the concentration of HNO3 can therefore be calculated as follows:

Concentration = mole / volume = 0.0057213 mol / 0.080 L = 0.0715 M.

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Answer:  The molar mass of the unknown gas is 59.8 g/mol

Explanation:

According to the ideal gas equation:-

[tex]PV=nRT[/tex]

P= Pressure of the gas = 706 mmHg = 0.93 atm    (760mmHg=1atm)

V= Volume of the gas = 1.64 L

T= Temperature of the gas = 59°C=(59+273)K=332 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

[tex]n=\frac{PV}{RT}=\frac{0.93\times 1.64L}{0.0821 \times 332}=0.056moles[/tex]

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

[tex]0.056=\frac{3.35g}{\text {Molar mass}}[/tex]

[tex]{\text {Molar mass}}=59.8g[/tex]

Thus the molar mass of the unknown gas is 59.8 g/mol

The molar mass of the unknown gas is calculated using the ideal gas law equation. After converting the pressure to atmospheres and temperature to Kelvin, the molar mass is found to be 57.46 g/mol.

To calculate the molar mass of the unknown gas, we will use the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is the amount of moles, R is the ideal gas constant, and T is temperature in Kelvin. We can rearrange the formula to solve for n (moles) and then use the mass of the gas to find its molar mass.

First, let's convert the given pressure and temperature to standard units. Pressure in atmospheres (atm) is 706 mmHg × (1 atm / 760 mmHg) = 0.9295 atm. Temperature in Kelvin (K) is 59 °C + 273 = 332 K.

Now we can use the ideal gas law equation:

PV = nRT

0.9295 atm × 1.64 L = n × 0.0821 L·atm·K¹·mol¹ × 332 K

Solving for n (moles), we get n = 0.0583 mol.

The molar mass (MM) is the mass of the gas divided by the number of moles:

Molar Mass = Mass / Moles

Molar Mass = 3.35 g / 0.0583 mol = 57.46 g/mol

Answer:

Cl2(g) (green/yellow mix) + 2KBr(s) (white) ---> 2KCl(s) (violet) + Br2(g) (reddish brown)

This chemical reaction is a redox type.

Explanation:

Look at the oxidation state, when the number increase your element gets oxidated, when the number decrease, the elements it's getting reduced.

Answer:

a. A non-competitive inhibitor of acetylcholinesterase.

Explanation:

The enzyme acetylcholinesterase breaks the molecule of acetylcholine, so to maintain the levels of this substance higher in the brain, the medication must act directly in the enzyme.

An enzyme can be inactivated by higher temperatures, changes in pH and changes in the osmotic pressure, but these things would probably damage other enzymes in the brain. So, the medication must be an inhibitor of acetylcholinesterase. It would be selective and would stop the actions of the enzyme.

But, this inhibitor can't be competitive because if this happens, it would break the acetylcholine, and wouldn't solve the problem.

Answer:

The molarity of the sulfuric acid is 0.018 M

Explanation:

The molarity of a solution is the number of moles of the solute (sulfuric acid in this case) in a 1-liter solution.

Every 100 g of the solution, we have 95 g sulfuric acid because its concentration is 95% w/w.

With the density, we can calculate how many liters are 100 g of solution:

density = mass / volume

1.85 g / ml = 100 g / volume

volume = 100 g / 1.85 g/ml

volume = 54.1 ml or 0.0541 l

Now, we know that we have 95 g sulfuric acid in 0.0541 l solution. In 1 l, we have then:

1 l * 95g / 0.0541 l = 1.756 g sulfuric acid.

But we want to know how many moles sulfuric acid we have per liter. Then, using the molar mass, we can calculate how many moles there are in 1.756 g sulfuric acid:

1.756 g * 1 mol / 98.08 g = 0.018 mol

The molarity is 0.018 M

Answer:

Explanation:

For very well describe a normal distribution, it is needed the mean and the standard deviation. We are only lacking the mean to properly describe the nitrogen levels emitted by the vehicles. He would like to measure the emitted NOX so he could properly model this phenomena.

Answer:

C11H25SO4

Explanation:

The total mass of the compound is 253.4 g, so, the mass of each element will be:

C: 52.14% of 253.4 = 0.5214x253.4 = 132.12 g

H: 9.946% of 253.4 = 0.09946x253.4 = 25.20 g

S: 12.66% of 253.4 = 0.1266x253.4 = 32.08 g

O: 25.26% of 253.4 = 0.2526x253.4 = 64.00 g

The molar mass are: C = 12 g/mol, H 1 g/mol, S = 32 g/mol, and O = 16 g/mol

So, to know how much moles will be, just divide the mass calculated above for the molar mass:

C: 132.12/12 = 11 moles

H: 25.20/ 1 = 25 moles

S: 32.08/32 = 1 mol

O: 64.00/16 = 4 moles

So the molecular formula is C11H25SO4

approximately [tex]\( 6.22 \times 10^5 \% \)[/tex] of the total red blood cell volume is taken up by [tex]\( \text{Fe}^{2+} \)[/tex] ions.

To find the percentage of the total red blood cell volume taken up by [tex]\( \text{Fe}^{2+} \)[/tex] ions, we first need to calculate the volume occupied by [tex]\( \text{Fe}^{2+} \)[/tex] ions and then express it as a percentage of the total volume of the red blood cell.

1. Calculate the Volume Occupied by [tex]\( \text{Fe}^{2+} \)[/tex] Ions:

  The volume occupied by [tex]\( \text{Fe}^{2+} \)[/tex] ions can be calculated based on the number of ions and their atomic radius.

  Each [tex]\( \text{Fe}^{2+} \)[/tex] ion can be considered as a sphere, and its volume [tex](\( V_{\text{Fe}^{2+}} \))[/tex] can be calculated using the formula for the volume of a sphere:

  [tex]\[ V_{\text{Fe}^{2+}} = \frac{4}{3} \pi r^3 \][/tex]

  where r is the atomic radius of [tex]\( \text{Fe}^{2+} \)[/tex] ions.

  Given that the atomic radius of [tex]\( \text{Fe}^{2+} \)[/tex] ions is [tex]\( 75.1 \, \text{pm} \)[/tex] [tex](or \( 75.1 \times 10^{-12} \, \text{m} \))[/tex], we can calculate the volume of one [tex]\( \text{Fe}^{2+} \)[/tex] ion.

  Then, multiply this volume by the number of [tex]\( \text{Fe}^{2+} \)[/tex] ions present in a single red blood cell to find the total volume occupied by [tex]\( \text{Fe}^{2+} \)[/tex] ions.

2. Calculate the Percentage of the Total Red Blood Cell Volume:

  After obtaining the volume occupied by [tex]\( \text{Fe}^{2+} \)[/tex] ions, divide it by the total volume of the red blood cell and multiply by 100 to express it as a percentage.

Let's perform the calculations:

1. Calculate the Volume Occupied by [tex]\( \text{Fe}^{2+} \)[/tex] Ions:

  [tex]\[ V_{\text{Fe}^{2+}} = \frac{4}{3} \pi (75.1 \times 10^{-12} \, \text{m})^3 \][/tex]

  [tex]\[ V_{\text{Fe}^{2+}} = \frac{4}{3} \pi (4.468 \times 10^{-10} \, \text{m}^3) \][/tex]

  [tex]\[ V_{\text{Fe}^{2+}} = 2.363 \times 10^{-9} \, \text{m}^3 \][/tex]

  Now, we need to find the total volume occupied by [tex]\( \text{Fe}^{2+} \)[/tex] ions in the red blood cell:

  [tex]\[ V_{\text{total Fe}^{2+}} = (2.50 \times 10^8 \, \text{molecules}) \times (2.363 \times 10^{-9} \, \text{m}^3/\text{ion}) \][/tex]

  [tex]\[ V_{\text{total Fe}^{2+}} = 5.908 \times 10^{-1} \, \text{m}^3 \][/tex]

2. **Calculate the Percentage of the Total Red Blood Cell Volume:**

  Given that the volume of the red blood cell is [tex]\( 95 \, \mu\text{m}^3 \) (or \( 95 \times 10^{-18} \, \text{m}^3 \))[/tex], we can calculate the percentage:

  [tex]\[ \text{Percentage} = \frac{V_{\text{total Fe}^{2+}}}{V_{\text{RBC}}} \times 100 \][/tex]

  [tex]\[ \text{Percentage} = \frac{5.908 \times 10^{-1} \, \text{m}^3}{95 \times 10^{-18} \, \text{m}^3} \times 100 \][/tex]

  [tex]\[ \text{Percentage} \approx 6.22 \times 10^5 \% \][/tex]

Therefore, approximately [tex]\( 6.22 \times 10^5 \% \)[/tex] of the total red blood cell volume is taken up by [tex]\( \text{Fe}^{2+} \)[/tex] ions.

Answer:

Robert

Explanation:

Paper chromatography is an analytical technique which is used to separate different components dissolved in a mixture depending on the time taken by each component to travel up the paper. The difference in time depends on the relative affinity of a particular component towards the paper (which acts as the stationary phase) and the solution carrying the mixture (which acts as the mobile phase).

This method is commonly used to separate colored systems like a dye mixture. The presence of more than one dye in a mixture shows up as a band of a color characteristic of that component.

Jim, Jill and Kim each have two bands in their paper chromatogram which suggests that they have two substances in their mixture. However, Robert has a single green band which indicates the presence of only one substance dissolved in water.

Answer:

A solid residue of limestone and some gypsum.

Explanation:

In step 2, some of the limestone and gypsum in the chalk dissolve in the water. When the mixture is filtered, the dissolved substances remain in the water. When the water is boiled off or evaporated, the solid substances remain behind.

Answer:

Q<K so N2(g) +3H2(g) → 2NH3(g)

Explanation:

Step 1: Data given

For the balanced equation N2(g)+3H2(g)⇌2NH3(g)   We have the following data:

⇒ Reaction quotient Q = 3.56 *10^-4

  Where Q is defined as Q = [NH3]^2/{[N2]*[H2]^3]

⇒ Equilibrium constant K = 6.02 * 10^-2

If we compare Q and K, there are 3 options

⇒ Q > K : The reaction favors the reactants. This means that in the  Q  equation, the ratio of the concentration or pressure of the products) to the concentration or pressure of the reactants is larger than that for  K.

This means that more products are present than there would be at equilibrium.

Following Le chatelier's principle reactions always tend toward equilibrium, this means the reaction will produce more reactants from the excess products, and will therefore cause the system to shift to the LEFT.

Doing this, it will allow   the system to reach equilibrium.

⇒ Q = K : The reaction  is already at equilibrium. There is no tendency to form more reactants or more products at this point. No side is favored and no shift will occur.

⇒ Q < K  : The reaction favors the products. The ratio of products to reactants is less than that for the system at equilibrium—the concentration or the pressure of the reactants is greater than the concentration or pressure of the products.

Following Le chatelier's principle reactions always tend toward equilibrium,  the system shifts to the RIGHT to make more products.

In this case K > Q since 6.02*10^-2 > 3.56*10^-4

This means that forward reaction will be favored or the reaction will shift to the right

N2(g) +3H2(g) → 2NH3(g)

As a result, the reaction will consume nitrogen gas (N2) and hydrogen gas (H2), and produce more ammonia (NH3).

The reaction will proceed in this direction until equilibrium is established

The reaction quotient (Q) is less than the equilibrium constant (K), indicating that the forward reaction is favored. Therefore, the reaction shifts towards the production of more ammonia (NH3) to achieve equilibrium.

The reaction quotient (Q) and the equilibrium constant (K) are critical in determining the direction of a chemical reaction. In this scenario, the reaction of nitrogen and hydrogen to generate ammonia is considered. The reaction quotient Q is 3.56×10-4, while the equilibrium constant K is 6.02×10-2.

In situations where Q < K, the reaction progresses in the forward direction to reach equilibrium, meaning the formation of ammonia (NH3) is favored. On the other hand, if Q > K, the reaction would proceed in the reverse direction, favoring the formation of nitrogen and hydrogen. Therefore, given Q is less than K in this case, the reaction will shift toward the production of ammonia to establish equilibrium.

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Answer: a) The substance is a silvery white, lustrous metal :physical property.  

b) It melts at 649°C and boils at 1105°C : physical property.  

c) Its density at 20°C is [tex]1.738 g/cm^3[/tex]: physical property.  

d)  The substance burns in air, producing an intense white light : chemical property

Explanation:

Chemical property is defined as the property of a substance which is observed during a reaction where the chemical composition identity of the substance gets changed.

Physical property is defined as the property which can be measured and whose value describes the state of physical system. For Example: State, density etc.

a) The substance is a silvery white, lustrous metal is a physical property

b) It melts at 649°C and boils at 1105°C is a physical property.  

c) Its density at 20°C is [tex]1.738 g/cm^3[/tex] is a physical property.  

d) The substance burns in air, producing an intense white light is a chemical property

Final answer:

Observations (a), (b), and (c) regarding the metal's appearance, melting and boiling points, and density are physical properties. Observation (d) describes a chemical property, as it involves the substance's ability to burn in air.

Explanation:

In the process of characterizing a substance, a chemist observes certain properties which can be classified as either physical properties or chemical properties.

Answer:

The answer to yourquestions is the last option

Explanation:

Cr(s) -------------------- Cr +3 (aq) + 3e-

Answer:

The answer to your question is: 6.8 g of water

Explanation:

Data

2.6 moles of HCl

1.4 moles of Ca(OH)2

                           2HCl     +     Ca(OH)2    →        2H2O    +      CaCl2

MW                   2(36.5)               74                       36 g               111 g

                          73g                

                            1 mol of HCl ----------------  36.5 g

                           2.6 mol           --------------    x

                              x = (2.6 x 36.5) / 1   = 94.9 g

                           1 mol of Ca(OH)2 --------------   74 g

                         1.4 mol                  ---------------   x

                            x = (1.4 x 74) / 1  = 103.6 g

Grams of water

                        73 g of HCl ------------------   36g of H2O

                        94.9 g        -------------------    x

                     x = (94.9 x 36) / 73 = 46.8 g of water

The amount of water is theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca(OH)₂ -  C) 46.8.

Given:

2HCl + Ca(OH)₂ -------------> CaCl₂ + 2H2O

in this reaction, 2 moles HCl reacts with 1 mole Ca(OH)₂

which means 2.6 moles of HCl reacts with 2.6 x = 1.3

but we have 1.4 moles Ca(OH)₂  it is the excess reagent

Solution:

HCl is a limiting reagent in this reaction as it allows producing the mole of water on the base of the number of moles it has,

=> 2 mole HCl - 2 moles of H₂O

Here, 2.6 moles of HCl would give 2.6 moles of H₂O only

=> convert moles to mass  

moles = mass / molar mass  

and,

mass = [tex]\frac{mass}{molar\ mass}[/tex]

mass = 2.6 x 18

= 46.8 g

Thus, the amount of water is theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca(OH)₂ -  C) 46.8.

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To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.

Then knowing volume of aluminum and the density of it, we can solve for the mass.

D = m/v

Dv = m

2.7 g/ml • 8 ml = 21.6 grams.

Answer: The mass of sample is 21.6 grams.

Explanation:

We are given:

Volume of cylinder without object, [tex]V_1[/tex] = 10 mL

Volume of cylinder with object, [tex]V_2[/tex] = 18 mL

Volume of object = [tex]V_2-V_1=18-10=8mL[/tex]

To calculate volume of a substance, we use the equation:

[tex]\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}[/tex]

We are given:

Density of sample (aluminum) = 2.7 g/mL

Volume of sample (aluminum) = 8 mL

Putting values in above equation, we get:

[tex]2.7g/mL=\frac{\text{Mass of a sample}}{8mL}\\\\\text{Mass of object}=21.6g[/tex]

Hence, the mass of sample is 21.6 grams.

To calculate the pKa of the second ionizable group in compound X, after NaOH addition that adjusted the pH to 6.72, one would typically use the Henderson-Hasselbalch equation within the buffering range. The exact pKa calculation requires detailed balance of species post-titration.

The student's question involves calculating the pKa of the second ionizable group in an unknown compound X. Given that 75 mL of 0.1 M NaOH was added to 100mL of a 0.1 M solution of X at pH 2.0, and the pH increased to 6.72, we approach this problem through a series of chemical equilibrium and titration calculations. The pKa of the second group indicates its acid dissociation constant, which is crucial for understanding the compound's behavior in solution.

To calculate the pKa of the second ionizable group, we need to consider the buffering region and the Henderson-Hasselbalch equation. Given that the pH after the addition of NaOH reached a point beyond the first pKa but before the second pKa, it suggests that the solution is acting as a buffer. The pKa of the buffering component can be determined when the pH is within one pKa unit range above or below its value. Since the question provides a range for the second pKa between 5 and 8, and a result of 6.72 falls within this range, we can estimate the second pKa by aligning it with the observed buffer pH, given the stoichiometric conversion of species in solution.

The calculations for finding the exact pKa would require detailed knowledge of the buffering system's dynamics and the concentration of species post-titration. Normally, the Henderson-Hasselbalch equation is used: pH = pKa + log([A−]/[HA]), where [A−] is the concentration of the conjugate base, and [HA] is the concentration of the acid. However, due to the complexity and variability of chemical systems, exact calculations exceed this response's scope.

Answer:

The answer is in the explanation

Explanation:

Single displacement reactions: In these reactions, a more reactive element kicks out a less reactive element from a compound.

Ex.  Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)

In this example, Zn is more reactive than H, then Zn displaces H from the compound.

Double displacement reactions: In these kind of reactions 2 elements are displaced from the different compounds, these elements interchange positions.

Ex. CuCl2(aq) + 2 AgNO3(aq) → Cu(NO3)2(aq) + 2 AgCl(s)

In the example, Cu displaces Ag and Ag displaces Cu, they interchange positions.

Single displacement reactions involve one element replacing another in a compound, whereas double displacement reactions involve the exchange of ions between two compounds, often forming a precipitate.

Single displacement reactions and double displacement reactions are two different types of chemical reactions. In a single displacement reaction, an element replaces another element in a compound, typically following the pattern A + BC → AC + B, where A is a single element and BC is a compound. By contrast, a double displacement reaction, also known as a metathesis, involves the exchange of ions between two compounds, conforming to the general form AB + CD → AD + CB, often resulting in the formation of a precipitate when one of the new compounds is insoluble.

Final answer:

Monosodium glutamate is a compound made up of sodium, carbons, hydrogen, nitrogen, and oxygen.

Explanation:

Monosodium glutamate is a compound.

It is the sodium salt of glutamic acid, a naturally occurring non-essential amino acid.

Compounds are substances made up of two or more elements that are chemically bonded together.

In this case, monosodium glutamate is made up of the elements sodium (Na), carbon (C), hydrogen (H), nitrogen (N), and oxygen (O).

Answer:

The answer to your question is : 16.9 g of Ag

Explanation:

Data

26 g Ag

10.8 g of Sn

2.4g Cu

0.8 Zn

Ag = ? in 26 g of sample

Total mass in the amalgam = 26 + 10.8 + 2.4 + 0,8 = 40 g

Rule of three

                              40 g of sample  -------------- 26 g of silver

                               26 g of sample --------------   x

                           x = (26 x 26) / 40

                          x = 16.9 g of Silver

Final answer:

A 26 g sample of amalgam contains 16.9 g of silver, which is calculated based on the proportion of silver in the original amalgam mixture.

Explanation:

The student's question pertains to the calculation of the amount of silver in a 26 g sample of amalgam, which is a mixture of several metals. The total mass of the original amalgam mixture consists of 26 g of silver, 10.8 g of tin, 2.4 g of copper, and 0.8 g of zinc, which adds up to a total of 40 g. To find the amount of silver in a 26 g sample of this amalgam, we use the concept of proportion.

First, we calculate the percentage of silver in the original amalgam:

(mass of silver / total mass of amalgam) × 100 = (26 g / 40 g) × 100 = 65%

Now, we can find the mass of silver in the given 26 g sample of amalgam by multiplying the total mass of the sample by the percentage of silver:

(percentage of silver / 100) × mass of sample = (65 / 100) × 26 g = 16.9 g

Therefore, a 26 g sample of amalgam contains 16.9 g of silver.

Answer:

c. The frequency of collisions between particles, the size of the particles.

Explanation:

The reaction among 2 substances could speed up if the size of particles is smaller, for example it is easier to dissolve the common sugar than a cube of sugar, the reason is because since the size is smaller, the total area that is exposed to react is bigger.

Also, the frequency of collisions between particles, can increase the rate of reaction, because if they collide faster, the probability of react is bigger.

Answer:

c

Explanation:

Answer:

E.

Explanation:

All answers other than E have the incorrect bonding capabilities or other incorrect information.

Final answer:

The true statement about hydrogen bonding is e. Hydrogen bonding arises from the dipole moment created by unequal sharing of electrons within certain covalent bonds within a molecule, making hydrogen bonds a special type of intermolecular force.

Explanation:

The correct statement about hydrogen bonding is that it arises from the dipole moment created by the unequal sharing of electrons within certain covalent bonds within a molecule. Therefore, the answer to the question is e. Hydrogen bonding arises from the dipole moment created by the unequal sharing of electrons within certain covalent bonds within a molecule. Hydrogen bonds are a significant intermolecular force found in molecules where a hydrogen atom is covalently bonded to a very electronegative atom, such as nitrogen (N), oxygen (O), or fluorine (F). These bonds are quite polar, leading to a strong dipole-dipole interaction that falls under a particular intermolecular force category referred to as hydrogen bonding. Hydrogen bonds are notably stronger than van der Waals interactions but are much weaker than covalent or ionic bonds. A typical hydrogen bond's strength is about 5% of a covalent bond's strength.

Answer:

See below.

Explanation:

Argon gas is a pure substance. It has nothing other than molecules of Argon gas.

Iron oxide is a compound with iron and oxygen as its components. It is a pure substance.

Answer:

The answer to your question is: letter D 10 l

Explanation:

Data

V1 = 5.8 l

P1= 760 mmHg

T 0 constant

P2 = 430 mmHg

V2 = ?

Formula

V1P1 = V2P2

and we clear V2 from the equation

V2 = V1P1/P2

V2 = (5.8)(760)/430)

V2 = 10.25 l

According to the Boyle's law, the final volume of the gas which is expanded till the pressure of 430 mm Hg  is 10.25 L.

Boyle's law is an experimental gas law which describes  how the pressure of the gas decreases as  the volume increases. It's  statement can be stated as, the absolute pressure which is exerted by a given mass of an ideal gas is inversely proportional to its volume provided temperature and amount of gas remains unchanged.

Mathematically, it can be stated as,

P∝1/V or PV=K. The equation states that the product of of pressure and volume is constant for a given mass of gas and the equation holds true as long as temperature is maintained constant.

According to the equation the unknown pressure and volume of any one gas can be determined if two gases are to be considered.That is,

P₁V₁=P₂V₂

∴V₂=5.8×760/430=10.25 L.

Therefore, the final volume of the gas is 10.25 L.

Learn more about Boyle's law,here:

https://brainly.com/question/1437490

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