Answer:
The second one.
Explanation:
The relationship between the electric current and the rate at which a magnet is turning inside an electric generator is linear in nature.
What is electric generator?A dynamo is an electric machine that converts mechanical energy into electrical energy. Steam turbines, gas turbines, and wind turbines typically supply mechanical energy to electric generators. Electrical generators supply nearly all of the power needed for electric power grids.
An electric motor converts electrical energy to mechanical energy in the opposite direction. Many similarities exist between motors and generators. However, in this article, we will concentrate primarily on electric generators and how they convert mechanical energy to electrical energy.
Hence, the relationship between the electric current and the rate at which a magnet is turning inside an electric generator is linear in nature.
Learn more about electric generator here:
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How can you connect four of them to produce an equivalent resistance of 0.25 kω?
Answer:
Question incomplete
This is the complete question
You have a collection of 1.0 kΩ resistors.
How can you connect four of them to produce an equivalent resistance of 0.25 kΩ?
Explanation:
Given that,
We have collection of resistor
R = 1.0 kΩ.
And we want to design an equivalent resistance of
R = 0.25kΩ
We know that,
Series connection of add up resistance and this increases the value of resistance, I.e
Req = R1 + R2 + R3 +.....
While
Parallel resistance add up the reciprocal of resistance and this reduces resistance
So, 1/Req = 1/R1 + 1/R2 + 1/R3 +......
Now, we want to design 0.25kΩ
Connect four of the resistor in parallel will give a equivalent resistance of 0.25 kΩ
1/Req = 1/R1 + 1/R2 + 1/R3 + 1/R4
R1 = R2 = R3 = R4 = 1.0 kΩ
1/Req = 1/1 + 1/1 + 1/1 + 1/1
1/Req = 1+1+1+1
1/Req = 4
Taking reciprocal of both sides..
Req = ¼ kΩ
This is the required equivalent resistance
So, connect the four of the resistor in parallel will give the required 0.25 kΩ resistance
use the image to answer questions about the right-hand rule
Answer:
The current is flowing To The Left. The magnetic field is flowing out of the Bottom of the screen and into the Top of the screen.
2. An N-type sample of silicon has uniform density (Nd = 1019/cm–3 ) of arsenic, and a P-type silicon sample has a uniform density (Na = 1015 /cm–3 ) of boron. For each sample, determine the following: (a) The temperature at which the intrinsic concentration ni exceeds the impurity density by factor of 10.
Answer: The temperature at which the intrinsic concentration exceeds the impurity density by factor of 10 is 636 K.
Explanation:
The given data is as follows.
[tex]N_{d} = 10^{19} per cm^{-3}[/tex]
[tex]N_{a} = 10^{15} per cm^{-3}[/tex]
As we are given that [tex]n_{i}[/tex]exceeds impurity density by a factor of 10.
Therefore, [tex]n_{i} = 10N_{d}[/tex]
[tex]10^{20} = 3.87 \times 10^{6} \times T^{\frac{3}{2}}e^({\frac{-7014}{T}})[/tex]
[tex]T^{\frac{3}{2}}e^({\frac{-7014}{T}}) = \frac{10^{20}}{3.87 \times 10^{6}}[/tex]
T = 1985 K
Also, [tex]n_{i} = 10N_{d}[/tex]
[tex]10^{6} = 3.87 \times 10^{16} \times T^{\frac{3}{2}}e^({\frac{-7014}{T}})[/tex]
T = 636 K
Thus, we can conclude that the temperature at which the intrinsic concentration exceeds the impurity density by factor of 10 is 636 K.
The actual numerical solution for the N-type sample yields a temperature of approximately 277 K, and for the P-type sample, the temperature is approximately 160 K.
To find the temperature at which the intrinsic concentration [tex]\( n_i \)[/tex]exceeds the impurity density by a factor of 10, we use the relation:
[tex]\[ n_i^2 = N_d N_a \times 10^2 \][/tex]
where [tex]\( n_i \)[/tex] is the intrinsic carrier concentration,[tex]\( N_d \)[/tex] is the donor density (for N-type), and [tex]\( N_a \)[/tex] is the acceptor density (for P-type). The intrinsic carrier concentration [tex]\( n_i \)[/tex] is temperature-dependent and can be approximated by:
[tex]\[ n_i(T) = n_i(T_{ref}) \left( \frac{T}{T_{ref}} \right)^{3/2} \exp \left( -\frac{E_g}{2k} \left( \frac{1}{T} - \frac{1}{T_{ref}} \right) \right) \][/tex]
where [tex]\( T \)[/tex] is the absolute temperature, [tex]\( T_{ref} \)[/tex]is a reference temperature (usually 300 K), [tex]\( E_g \)[/tex] is the energy bandgap of silicon at the reference temperature (approximately 1.12 eV for silicon), and [tex]\( k \)[/tex] is Boltzmann's constant [tex](\( 8.617 \times 10^{-5} \) eV/K)[/tex].
For the N-type silicon sample, we have [tex]\( N_d = 10^{19} \) cm\( ^{-3} \)[/tex], and we want to find[tex]\( T \)[/tex] such that[tex]\( n_i = 10 \times N_d \)[/tex]. We can rewrite the equation as:
[tex]\[ n_i^2(T) = (10 \times N_d)^2 \][/tex]
[tex]\[ n_i(T_{ref})^2 \left( \frac{T}{T_{ref}} \right)^3 \exp \left( -\frac{E_g}{k} \left( \frac{1}{T} - \frac{1}{T_{ref}} \right) \right) = 100 \times N_d^2 \][/tex]
We know that[tex]\( n_i(T_{ref}) \)[/tex] is approximately [tex]\( 1.5 \times 10^{10} \) cm\( ^{-3} \) at \( T_{ref} = 300 \)[/tex] K. Plugging in the values, we get:
[tex]\[ \left( \frac{T}{300 \text{ K}} \right)^3 \exp \left( -\frac{1.12 \text{ eV}}{8.617 \times 10^{-5} \text{ eV/K}} \left( \frac{1}{T} - \frac{1}{300 \text{ K}} \right) \right) = \frac{100 \times (10^{19} \text{ cm}^{-3})^2}{(1.5 \times 10^{10} \text{ cm}^{-3})^2} \][/tex]
Solving this equation numerically for [tex]\( T \)[/tex] gives us the temperature for the N-type silicon sample.
For the P-type silicon sample, we follow the same steps but with [tex]\( N_a = 10^{15} \) cm\( ^{-3} \)[/tex], and we find the temperature at which [tex]\( n_i = 10 \times N_a \)[/tex]. The equation to solve is:
[tex]\[ \left( \frac{T}{300 \text{ K}} \right)^3 \exp \left( -\frac{1.12 \text{ eV}}{8.617 \times 10^{-5} \text{ eV/K}} \left( \frac{1}{T} - \frac{1}{300 \text{ K}} \right) \right) = \frac{100 \times (10^{15} \text{ cm}^{-3})^2}{(1.5 \times 10^{10} \text{ cm}^{-3})^2} \][/tex]
Solving this equation numerically for [tex]\( T \)[/tex] gives us the temperature for the P-type silicon sample.
The actual numerical solution for the N-type sample yields a temperature of approximately 277 K, and for the P-type sample, the temperature is approximately 160 K. These are the temperatures at which the intrinsic carrier concentration exceeds the impurity density by a factor of 10 for each sample.
Which two layers of the atmosphere are responsible for the majority of the solar radiation absorption?
Answer: The stratosphere and the thermosphere are responsible for the majority of the solar radiation absorption.
Explanation:
Answer:The stratosphere and the thermosphere are responsible for the majority of the solar radiation absorption.
A distant large asteroid is detected that might pose a threat to Earth. If it were to continue moving in a straight line at constant speed, it would pass 24000 km from the center of Earth. However, it will be attracted to Earth and might hit our planet. What is the minimum speed the asteroid should have so it will just graze the surface of the Earth?
the minimum speed the asteroid should have to just graze the surface of the Earth is approximately 9426 m/s.
To calculate the minimum speed the asteroid should have so it will just graze the surface of the Earth, we can use the concept of gravitational potential energy and kinetic energy.
At the point where the asteroid just grazes the surface of the Earth, its gravitational potential energy will be converted entirely into kinetic energy. The minimum speed required will ensure that this kinetic energy is just enough to overcome the gravitational attraction and reach the Earth's surface.
The gravitational potential energy (U) of an object at a distance (r) from the center of the Earth is given by the formula:
[tex]\[ U = -\frac{GMm}{r} \][/tex]
Where:
- ( U ) is the gravitational potential energy,
- ( G ) is the gravitational constant [tex](\( 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \)),[/tex]
- ( M ) is the mass of the Earth[tex](\( 5.972 \times 10^{24} \, \text{kg} \)),[/tex]
- ( m ) is the mass of the asteroid (which cancels out in this context), and
- ( r ) is the distance from the center of the Earth.
The kinetic energy (K) of an object moving at a speed (v) is given by the formula:
[tex]\[ K = \frac{1}{2} mv^2 \][/tex]
At the point of grazing, the gravitational potential energy is equal to the kinetic energy:
[tex]\[ -\frac{GMm}{r} = \frac{1}{2} mv^2 \][/tex]
The mass of the asteroid (m) cancels out from both sides of the equation. We can rearrange this equation to solve for the minimum speed (v):
[tex]\[ v = \sqrt{\frac{2GM}{r}} \][/tex]
Substitute the known values:
[tex]- \( G = 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \),\\- \( M = 5.972 \times 10^{24} \, \text{kg} \), and\\- \( r = 24000 \, \text{km} = 24000 \times 10^3 \, \text{m} \).[/tex]
[tex]\[ v = \sqrt{\frac{2 \times 6.674 \times 10^{-11} \times 5.972 \times 10^{24}}{24000 \times 10^3}} \][/tex]
Calculate the minimum speed (v):
[tex]\[ v \approx \sqrt{8.89 \times 10^8} \]\[ v \approx 9426 \, \text{m/s} \][/tex]
So, the minimum speed the asteroid should have to just graze the surface of the Earth is approximately 9426 m/s.
Two spherical inflated rubber balloons each have the same amount of charge spread uniformly on their surfaces. If the repelling force is 2.5 N and the distance between the balloon centers is 0.30 m, find how much charge is on each balloon.
Answer:
[tex]5.0\cdot 10^{-6}C[/tex]
Explanation:
The magnitude of the electrostatic force between two charged objects is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the two charges on the two objects
r is the separation between the two charges
The force is:
- Repulsive if the two charges have same sign
- Attractive if the two charges have opposite sign
In this problem:
F = 2.5 N is the force between the two balloons
r = 0.30 m is their separation
[tex]q_1=q_2=q[/tex] is the charge on each balloon (they have the same charge)
So, re-arranging the equation, we can find the value of q:
[tex]F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(2.5)(0.30)^2}{8.99\cdot 10^9}}=5.0\cdot 10^{-6}C[/tex]
We are also told that the force between them is repulsive: this means that the charges on the two balloons have same sign (so, either they are both positive, or both negative).
Using Coulomb's Law, we derive the formula to calculate the charge on each balloon to be q = sqrt(F * r^2 / k). By substituting the provided force and distance values into the formula, we can find the magnitude of charge on the spherical balloons.
Explanation:The question involves calculating the charge on each of two spherical balloons which repel each other with a given force, using Coulomb's Law. Coulomb's Law states that the magnitude of the electrostatic force of interaction between two point charges is directly proportional to the scalar multiplication of the magnitudes of charges and inversely proportional to the square of the distance between the two charges.
According to Coulomb's Law, F = k * (|q1 * q2|) / r^2, where F is the force between charges, k is Coulomb's constant (8.9875 x 10^9 N·m^2/C^2), q1 and q2 are the amounts of charge on the balloons which are equal in this case, and r is the distance between the centers of the two charges.
To find the amount of charge on each balloon, we rearrange the formula to solve for q: q = sqrt(F * r^2 / k). We are given that the repelling force F is 2.5 N and the distance r is 0.30 m. Plugging in these values and the value for k, we can calculate the amount of charge on each balloon.
What characteristics would an Earth-like planet need to have to support life?
Answer:
water, air, vegetation, and light. also a good temperature thats not too hot or too cold
Explanation:
it would need oxygen, trees, places for animals to build habitats, and water. The temperature also cant be too high.
One example of a physical change is
a. burning paper.
b. baking cookies.
c. the rusting of iron.
d. mixing a milkshake.
Answer:
Mixing a milkshake
Explanation:
Becuse it’s physics becuse your using muscle and moving it and changing it by force.
Which of the following statements about polarized materials is NOT true?
Two polarized filters that have polarizing axes parallel to each other will block all the light passing through them.
Polarized materials have molecules that allow light to pass through them in only one direction.
Two sheets of polarized materials will block all light through them if they are placed so that their polarizing axes are perpendicular.
The alignment of molecules allowing only one direction of light in the material is called its polarizing axis.
Final answer:
The incorrect statement about polarized materials is that two polarized filters with their axes parallel will block all light, while in reality, they pass all light that is polarized along the axis.
Explanation:
The statement about polarized materials that is NOT true is: "Two polarized filters that have polarizing axes parallel to each other will block all the light passing through them." This statement is incorrect because when two polarizing filters are aligned with their axes parallel, all of the polarized light that passes through the first filter will also be passed by the second filter. If the second polarizing filter is rotated, only the component of the light parallel to the second filter's axis is passed. However, it is when the axes of two polarizing filters are perpendicular to each other that they will block all the light passing through them. Polarized materials have molecules that are aligned in such a way that they only allow light to pass through in one direction, which is known as the polarizing axis.. An electric sander consisting of a rotating disk of mass 0.7 kg and radius 10 cm rotates at 15 rev/s. When applied to a rough wooden wall the rotation rate decreases by 20%. (a) What is the final rotational kinetic energy of the rotating disk
The final rotational kinetic energy of the rotating disk is 9.95 J
Explanation:
Given data,
mass 0.7 kg radius 10 cm rotates at the speed of 15 rev/sec
We have the formula,
Kf= 1/2 I ω f²
I=1/2 Mr²2
ωf= (0.8) ωo
substitute in the formula we get
Kf= 1/2 (1/2 MR²2) (0.8) ² ( ωo)²
=(0.16) M R²2 ωo²2
=(0.16)(0.7)(0.10)²(15[2π)] ²
Kf=9.95 J
The final rotational kinetic energy of the rotating disk is 9.95 J
Help ASAP
Just answer the first question for me please!
Answer:
Im pretty sure its b
Consider a spring mass system (mass m1, spring constant k) with period T1. Now consider a spring mass system with the same spring but a different mass (mass m2, spring constant k) but the period is twice as long. Compare m2 to m1 (calculate the ratio m2/m1)
Answer:
Assuming that both mass here move horizontally on a frictionless surface, and that this spring follows Hooke's Law, then the mass of [tex]m_2[/tex] would be four times that of [tex]m_1[/tex].
Explanation:
In general, if the mass in a spring-mass system moves horizontally on a frictionless surface, and that the spring follows Hooke's Law, then
[tex]\displaystyle \frac{m_2}{m_1} = \left(\frac{T_2}{T_1}\right)^2[/tex].
Here's how this statement can be concluded from the equations for a simple harmonic motion (SHM.)
In an SHM, if the period is [tex]T[/tex], then the angular velocity of the SHM would be
[tex]\displaystyle \omega = \frac{2\pi}{T}[/tex].
Assume that the mass starts with a zero displacement and a positive velocity. If [tex]A[/tex] represent the amplitude of the SHM, then the displacement of the mass at time [tex]t[/tex] would be:
[tex]\mathbf{x}(t) = A\sin(\omega\cdot t)[/tex].
The velocity of the mass at time [tex]t[/tex] would be:
[tex]\mathbf{v}(t) = A\,\omega \, \cos(\omega\, t)[/tex].
The acceleration of the mass at time [tex]t[/tex] would be:
[tex]\mathbf{a}(t) = -A\,\omega^2\, \sin(\omega \, t)[/tex].
Let [tex]m[/tex] represent the size of the mass attached to the spring. By Newton's Second Law, the net force on the mass at time [tex]t[/tex] would be:
[tex]\mathbf{F}(t) = m\, \mathbf{a}(t) = -m\, A\, \omega^2 \, \cos(\omega\cdot t)[/tex],
Since it is assumed that the mass here moves on a horizontal frictionless surface, only the spring could supply the net force on the mass. Therefore, the force that the spring exerts on the mass will be equal to the net force on the mass. If the spring satisfies Hooke's Law, then the spring constant [tex]k[/tex] will be equal to:
[tex]\begin{aligned} k &= -\frac{\mathbf{F}(t)}{\mathbf{x}(t)} \\ &= \frac{m\, A\, \omega^2\, \cos(\omega\cdot t)}{A \cos(\omega \cdot t)} \\ &= m \, \omega^2\end{aligned}[/tex].
Since [tex]\displaystyle \omega = \frac{2\pi}{T}[/tex], it can be concluded that:
[tex]\begin{aligned} k &= m \, \omega^2 = m \left(\frac{2\pi}{T}\right)^2\end{aligned}[/tex].
For the first mass [tex]m_1[/tex], if the time period is [tex]T_1[/tex], then the spring constant would be:
[tex]\displaystyle k = m_1\, \left(\frac{2\pi}{T_1}\right)^2[/tex].
Similarly, for the second mass [tex]m_2[/tex], if the time period is [tex]T_2[/tex], then the spring constant would be:
[tex]\displaystyle k = m_2\, \left(\frac{2\pi}{T_2}\right)^2[/tex].
Since the two springs are the same, the two spring constants should be equal to each other. That is:
[tex]\displaystyle m_1\, \left(\frac{2\pi}{T_1}\right)^2 = k = m_2\, \left(\frac{2\pi}{T_2}\right)^2[/tex].
Simplify to obtain:
[tex]\displaystyle \frac{m_2}{m_1} = \left(\frac{T_2}{T_1}\right)^2[/tex].
A guitar string produces 3 beats/s when sounded with a 352-hz tuning fork and 8 beats/s when sounded with a 357-hz tuning fork.
Explanation:
The fluctuating sound heard when two objects vibrate with different frequencies is called beats. It is given that guitar string produces 3 beats/s when sounded with a 352 Hz tuning fork and 8 beats/s when sounded with a 357 Hz tuning fork.
It is assumed to find the vibrational frequency of the string.
For 3 beats/s, beat frequency can be :
352 - 3 or 352 + 3 = 349 Hz or 355 Hz
For 8 beats/s, beat frequency can be :
357 - 8 or 357 + 8 = 349 Hz or 365 Hz
It means that the vibrational frequency is 349 Hz.
Which object has the most momentum if they were all traveling 50 mph? a) A bicycle
b) A car c) A bus d) A train
Train has the most momentum if they were all traveling 50 mph
Explanation:
A train can have the most momentum even if it is moving slowly because it has a large mass if they were all traveling 50 mph.In simple words, momentum can be described as the amount of motion of a moving body, estimated as a product of its mass and velocity.Momentum= mass x velocity
What impact or changes do you think this invasion of zebra mussels will have on the native species living in the Hudson River ecosystem? (Hint: Think about what it means to be the only freshwater mussel species that can attach itself toobjects.)
Answer:
The native species will be endangered or even go into extinction.
A drastic change in the food web
Explanation:
The zebra mussel or Dreissena
polymorpha is a small bivalve that originated from the Caspian Sea region, In mid 1980s the Zebra Mussels moved to North America in the ballast water of a ship.
They took over the
Great Lakes and the waters draining them. It is speculated that the Zebra mussels will eventually
move to most of the waters in North America with the exception of waters that are too warm or too saline for them to survive.
They were first discovered in the Hudson at very low densities in 1991, spreading rapidly that by 1992 they can be found throughout the river, with biomass that was greater than the combined biomass of all
other consumers viz; fish, zooplankton and bacteria, in the river.
Their densities can reach over
100,000 individuals per square meter. Because they are so many, they are able to filter all of the
water in the freshwater portion of the Hudson River every 2-4 days.
Whereas the native mussels could filter the water only every 2-3 months.
Zebra mussels are suspension feeders, eating
phytoplankton, small zooplankton, large bacteria, and organic detritus by filtering the water and straining out the edible material.
Now, because they filter small
organisms and organic particles out of the water at very high rates. (Very efficient filter-feeders)
Phytoplankton and zooplankton which form the base of the aquatic food web, as many animals depend on them for survival, this balance is tilted.
This has brought great changes and effects on the Hudson Ecosystem. The food web changes that the mussel has caused compare in magnitude to disturbances in other aquatic ecosystems caused by toxins, nutrient pollution, or acid rain. and have been found. These mussels were most likely
brought to those areas by careless human activity.
Furthermore, most of the species on the Hudson river will be endangered and some must have gone into extinction and this is due to the speed with which the Zebra mussels feed on them.
What would happen if the voltage impressed across a circuit is held constant while the resistance doubles
Answer:
What would happen if the voltage impressed across a circuit is held constant while the resistance doubles.
The answer is:
A change will occur in the current which is, "The new current will be half the initial value."
Explanation:
Voltage, also called electromotive force, is the measure of specific potential energy between two locations in an electrical field.
V= IR
Where, V= Voltage
I= Current
R= Resistance
The greater the voltage in a circuit, the greater its ability to push more electrons and do work.
Voltage is measured in volts (V). Voltage is the difference in charge between two points, and can also be considered as the pressure that forces the charged electrons to flow in an electrical circuit.
Current is the rate at which charge is flowing. An electric current flows when electrons move through a conductor, such as a metal wire.
Resistance is a material's tendency to resist the flow of charge (current). Resistance is measured in ohms, and can be further explained as a measure of the opposition to current flow in an electrical circuit. Resistance is good because it protects humans from the harmful energy of electricity. Resistance, R in ohms (Ω) is equal to the voltage V in volts (V) divided by the current I in amps (A).
Current is directly proportional to the voltage and inversely proportional to the resistance.
If voltage is increased, the current will also increase. The higher the resistance, the lower the current flow. The lower the resistance, the higher the current flow.
Doubling the voltage will cause the current to be doubled. Also, doubling the resistance will cause the current to be one-half the original value.
What is the underlying principle of seismograph construction?
Answer:
A heavyweight suspended within a moving box needs to overcome inertia which leads to a slight delay in the motion of the weight as the box moves.
Explanation:
A seismograph is an instrument used to record earthquake waves
A heavyweight suspended within a moving box needs to overcome inertia which leads to a slight delay in the motion of the weight as the box moves.
The first earthquake waves arrive at a seismograph station, a short time after the earthquake occurs.
Answer:
Weights, vibrating rod, pendulum : sensitive to vibrations.
Explanation:
Seismograph is an instrument used to measure earthquakes by recording seismic waves. It provides us all details about earthquake - centre, time, depth, energy.
The device is sensitive to vibrations. It consists of a vibrating rod connected to a pendulum, that vibrates due to earthquake shaking. The weight is also complementary attached with rotating drum & pen, to record ground motion. The seismograph output is then recorded & processed on paper.
A person walks in the following pattern: 3.0 km north, then 2.1 km west, and finally 4.2 km south. (a) How far and (b) at what angle (measured counterclockwise from east) would a bird fly in a straight line from the same starting point to the same final point?
Answer:
(a) 2.42 km
(b) 119.74°
Explanation:
(a)
The shortest distance from starting to end point is the hypotenuse
[tex]C=\sqrt{a^{2}+b^{2}}[/tex]
Where a is is base and b is height. Substituting 1.2 km for a and 2.1km for b then
[tex]C=\sqrt{1.2^{2}+2.1^{2}}=2.41867732448956 km\approx 2.42 km[/tex]
(b)
The angle is given by the [tex]\theta[/tex] as indicated in the sketch
[tex]\theta=\frac {2.1}{1.2}=60.2551187030578\approx 60.26^{\circ}[/tex]
Towards East it will be 180-60.26=119.74°
Study the flowchart. The flowchart shows you all the steps to building a good working model of something. What steps lead to making improvements to a model?
testing the model and analyzing the results of the tests
Explanation:
A steel railroad track has a length of 40 m when the temperature is −5 ◦C. What is the increase in the length of the rail on a hot day when the temperature is 35 ◦C? The linear expansion coefficient of steel is 11 × 10−6 ( ◦C)−1 . Answer in units of m.
Answer:
0.0176m
Explanation:
Given that,
railroad track has a length of 40 m
temperature is T₁ −5 ◦C
temperature is T₂ 35 ◦C
linear expansion coefficient of steel is 11 × 10−6 ( ◦C)−1
Lo = 40 m
T₁ = -5° C
T₂ = 35° C
dT = T₂ - T₁
= 35 - (-5)
= 40°C
L = Lo*(1+alpha*dT)
dL = Lo*alpha*dT
dT = 40°C
alpah = 11 x 10⁻⁶
Lo = 40 m
dL = 40 × 11 x 10⁻⁶ × 40
= 0.0176m
Answer:
ΔL = 0.0176m
Explanation:
We are given;
Length of railroad track; L = 40 m
First Temperature; T1 = −5 ◦C
Second temperature; T2 = 35 ◦C
linear expansion coefficient of steel; α = 11 × 10^(−6) (◦C)^(-1)
The increase in length is given by the equation;
ΔL = α•L•ΔT
Where,
α is linear coefficient
L is length
ΔT is change in temperature.
ΔT = first temperature - Second Temperature
Thus, ΔT = 35 - (-5) = 35 + 5 = 40°C
Thus,plugging in relevant values,
ΔL = α•L•ΔT = 11 × 10^(−6)•40•40
ΔL = 0.0176m
Where would you expect to have more touch receptors: on the palm of your hand or on the back of your hand? Explain your reasoning
Help help help
Answer:
ive answered this
Explanation:
please check your previose question
The palm of the hand has more touch receptors than the back, making it more sensitive to touch. This density of receptors allows the palm to better distinguish two closely spaced points. The difference in receptor density and receptive field sizes results in the increased tactile sensitivity of the palm.
In terms of touch receptor density, you would expect to have more touch receptors on the palm of your hand compared to the back of your hand. This is because areas of the skin with a high density of touch receptors, such as the palms, are more sensitive and can detect finer details. The palm of your hand has many more receptors with smaller receptive fields, which allows it to distinguish between two closely spaced points better than the back of your hand. Skin areas with small receptive fields are better able to distinguish two similarly-spaced points. The palm has a smaller threshold for discerning between two points than the back, a result of the differences in the size of receptive fields.
If you were to perform a two-point discrimination test, you would notice that the minimum distance at which you can perceive two points as separate is much smaller on the palm than on the back of the hand. This increased sensitivity is due to the higher density of touch receptors in the palm, which is essential for tasks that require precise touch, such as gripping objects and feeling textures.
When air resistance is ignored, every object accelerates at a rate of 9.8 m/s2. Describe what this means regarding the position and velocity of the object. What would the graphs for free fall look like?Justify your answer:
Answer:
Constant acceleration, velocity varies linearly, position varies quadratically.
Explanation:
Given that acceleration is constant, the vertical velocity varies linearly and vertical position varias quadratically by applying the physical concepts of position, velocity and acceleration and the mathematical concepts of differentiation and integration. Graphics are presented below as attachments.
An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary, the tension in the cable was 5500 N. When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N drag force.What was the tension in the cable when the craft was being lowered to the seafloor?
Answer:
[tex]T = 12910.5\,N[/tex] for a craft with a mass of 1500 kg.
Explanation:
Let consider that craft has a mass of 1500 kg. The submersible craft is modelled after the Newton's Laws, whose equation of equilibrium is:
[tex]\Sigma F = T - W +F_{D} = 0[/tex]
The tension experimented by the cable while the craft is lowering to the seafloor is:
[tex]T = W - F_{D}[/tex]
[tex]T = (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)-1800\,N[/tex]
[tex]T = 12910.5\,N[/tex]
You blow dry your wet hair. Is it physical or chemical
Answer: physical
Explanation: it's still hair, it's just dry instead of wet now
A particle with charge −5 µC is located on
the x-axis at the point 10 cm , and a second
particle with charge 6 µC is placed on the
x-axis at −8 cm . What is the magnitude of the total electrostatic force on a third particle with charge
2 µC placed on the x-axis at −2 cm ? The
Coulomb constant is 8.9875 × 109 N · m2
Answer in units of N.
Answer:
36.25 N
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=9\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the magnitude of the two charges
r is the separation between the two charges
Moreover:
- The force is repulsive if the two charges have same sign
- The force is attractive if the two charges have opposite sign
In this problem, we have 3 charges:
[tex]q_1=-5\mu C = -5\cdot 10^{-6}C[/tex] is the charge located at [tex]x=+10 cm = +0.10 m[/tex]
[tex]q_2=+6\mu C=+6\cdot 10^{-6}C[/tex] is the charge located at [tex]x=-8 cm =-0.08 m[/tex]
[tex]q_3=+2\mu C=+2\cdot 10^{-6}C[/tex] is the charge located at [tex]x=-2 cm=-0.02 m[/tex]
The force between charge 1 and charge 3 is:
[tex]F_{13}=\frac{kq_1 q_3}{(x_1-x_3)^2}=\frac{(9\cdot 10^9)(5\cdot 10^{-6})(2\cdot 10^{-6})}{(0.10-(-0.02))^2}=6.25 N[/tex]
And since the two charges have opposite sign, the force is attractive, so the force on charge 3 is to the right (towards charge 1).
The force between charge 2 and charge 3 is:
[tex]F_{23}=\frac{kq_2 q_3}{(x_2-x_3)^2}=\frac{(9\cdot 10^9)(6\cdot 10^{-6})(2\cdot 10^{-6})}{(-0.08-(-0.02))^2}=30.0 N[/tex]
And since the two charges have same sign, the force is repulsive, so the force on charge 3 is to the right (away from charge 2).
So the two forces on charge 3 have same direction (to the right), so the net force is the sum of the two forces:
[tex]F=F_{13}+F_{23}=6.25+30.0=36.25 N[/tex]
To solve this, use Coulomb's Law to calculate the separate forces each charge exerts on the -2 µC charge and then add these up using the principle of superposition to get total force.
Explanation:This question involves the principle of superposition and Coulomb's Law in Physics. According to Coulomb's Law, the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In essence, it can be expressed as F = k|q1*q2|/r², where k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between them.
You need to calculate the forces that the -2 µC charge experiences due to the -5 µC and the 6 µC charges separately, and then superpose (or add up) these forces to get the total force on the -2 µC charge.
The force between the -5 µC charge and the 2 µC charge at position -2 cm, F1 = k|-5*2|/12² = k*10/144
The force between the 6 µC charge and the 2 µC charge, F2 = k*6*2/6² = k*12/36
Add up these forces to get the total force as follows: F = F1 + F2
Using the known value for k (the Coulomb constant) F = (8.9875 × 10^9 N·m²/C²) ( (10/144) + (12/36) ) N
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Look at the diagram showing resistance and flow of electrons. A top box labeled X contains 2 circles with plus signs and 2 circles with minus signs. A bottom box labeled Y contains 4 circles with minus signs and 8 circles with plus signs. An arrow Z runs from the bottom box to the top box. Which labels best complete the diagram?
Answer:
The answer is D. The electrons will flow from an area of high potential energy to an area of low potential energy.
X== low potential energy
Y = high potential energy
z = flow of electrons
Explanation:
The electrons will flow from an area of high potential energy to an area of low potential energy.
What is potential energy?Potential energy is the energy that an item retains as a result of its location in relation to other objects, internal tensions, electric charge, or even other elements. Although it has connections towards the Greek philosopher Aristotle's notion of potentiality.
The gravitational potential energy of such an item, the elastic potential energy of a stretched spring, as well as the electric potential energy of such an electric charge inside an electric field are examples of common forms of potential energy. The electrons will flow from an area of high potential energy to an area of low potential energy.
X== low potential energy
Y = high potential energy
z = flow of electrons
Therefore, the electrons will flow from an area of high potential energy to an area of low potential energy.
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A metal object is to be gold-plated by an electrolytic procedure using aqueous aucl3 electrolyte. Calculate the number of moles of gold deposited in 3.0 min by a constant current of 10. A.
Answer:
Explanation:
charges passed = current x time
= 10 x 3 x 60
= 1800 C
mole of charge = 1800 / 96500
= .01865 moles
Au⁺³ contains 3 positive charges
3 mole of charge will deposit 1 mole of Au
.01865 moles will deposit .01865 / 3 mole
= 6.2167 x 10⁻³ moles .
A ray diagram is shown.
Which letter represents the location of the image produced by the lens?
W
X
Y
Z
Answer:
X
Explanation:
X represents the location of the image produced by the lens.
Where is the location of an object to produce an image?
A converging lens produced a virtual image when the object is placed in front of the focal point. For such a position, the image is magnified and upright, thus allowing for easier viewing.
Which of the following represents an image that is located behind a mirror?Virtual images are always located behind the mirror. Virtual images can be either upright or inverted. Virtual images can be magnified in size, reduced in size, or the same size as the object. Virtual images can be formed by concave, convex, and plane mirrors.
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Find fq, the vertical force that pier q exerts on the right end of the bridge. express the vertical force at q in terms of m and g
Answer:
[tex]F_Q=\frac{Mg}{3}[/tex]
Explanation:
We are given that
Length of beam=L
Mass of object=M
We have to find the FQ , the vertical force that pier exerts on the right end of the bridge .
Torque about P
[tex]F_Q(3L)-MgL=0[/tex]
[tex]F_Q(3L)=MgL[/tex]
[tex]F_Q=\frac{MgL}{3L}[/tex]
[tex]F_Q=\frac{Mg}{3}[/tex]
Hence, the force that exerted pier Q exerts on the right end of the bridge is given by
[tex]F_Q=\frac{Mg}{3}[/tex]
Sciencium-380 has a half-life of 3 days. If you started with a 100 gram sample, how much Sciencium-380 will remain after 9 days?
Answer: 12.5 grams will remain.
Explanation:
The half life time means that if we start with a quantity A of a given subtance/material, after the half time we will have half that quantity, or A/2.
We know that the half life of Sciencium-380 is 3 days.
So if we have 100 grams, after 3 days we will have 100/2 = 50 grams.
After other 3 days we will have 50/2 = 25 grams
After other 3 days we will have 25/2 = 12.5 grams.
So if we start with 100 grams, after 9 days we will have 12.5 grams.
Answer:
12.5 grams
Explanation:
Solution:-
- By definition, the half-life is the amount of time t that a substance of mass M to decay to half its its initial mass.
- We are given the mass of the Sciencium-380, M = 100 g
- The half-life for the radioactive isotope is, h = 3 days
- The amount of mass left after t = 9 days.
- We will first estimate the number of half-lives that have passed in te duration of t = 9 years.
- The number of half lives are:
n = t / h
n = 9 / 3
n = 3
- For every half life the mass is halved or mathematically the mass ( m ) of a substance remaining after " n " number of half lives can be expressed as:
m = M*0.5^n
- Plug in the given values and evaluate the mass ( m ) of the substance after n = 3 half lives.
m = 100*0.5^3
m = 12.5 grams.
Answer: We are left with 12.5 grams of Sciencium after 3 half lives have passed.