Which graph represents the function on the interval [−3, 3] ?

The sixth term of an arithmetic sequence, with a fifth term of 11 and a common difference of 4, is calculated to be 15.

The student's question is about determining the sixth term of an arithmetic sequence when the fifth term and the common difference are given. The fifth term is 11, and the common difference is 4. To find the sixth term, we follow the definition of an arithmetic sequence where each term is equal to the previous term plus the common difference.

Arithmetic sequence formula

:

Tn = T(n-1) + d

Where:

Applying this formula to find the sixth term:

Sixth term = Fifth term + Common difference

= 11 + 4

= 15

Therefore, the sixth term of the sequence is 15.

Answer:

If this is right then yw :)

Step-by-step explanation:

Answer: GH =25 in.

Step-by-step explanation:

Given: [tex]ABCD\sim EFGH[/tex]

We know that if two polygons are similar then their corresponding sides are proportional.

Thus, [tex]\frac{AB}{EF}=\frac{BC}{FG}=\frac{CD}{GH}=\frac{AD}{EH}[/tex]

Since, AD=30 in. , EH=50 in. , and CD=15 in.

Then we have ,

[tex]\frac{CD}{GH}=\frac{AD}{EH}\\\\\Rightarrow\frac{15}{GH}=\frac{30}{50}\\\\\Rightarrow\ GH=\frac{50\times15}{30}\\\\\Rightarrow\ GH=25\ in.[/tex]

Answer:

[tex]296^{\circ}[/tex]

Step-by-step explanation:

It is given that figure shows circle C with diameter LM and inscribed ∠LMN and    m∠LMN=32° .

We know that the angle formed at the center is double the angle formed on the vertex that is an inscribed angle, thus on joining NC, we have

[tex]{\angle}NCL=2({\angle}LMN)[/tex]

Substituting the given values, we have

[tex]{\angle}NCL=2(32^{\circ})[/tex]

[tex]{\angle}NCL=64^{\circ}[/tex]

Now, [tex]minor{\angle}LCN+major{\angle}LCN=360^{\circ}[/tex] (complete angle)

[tex]major{\angle}LCN=296^{\circ}[/tex]

Therefore, the measure of the arc LMN is [tex]296^{\circ}[/tex].

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Answer:

For [tex]2log2x=4[/tex] , x = 50

Step-by-step explanation:

Given : [tex]2log2x=4[/tex]

We have to find the value of x.

Consider the given [tex]2log2x=4[/tex]

Divide both side by 2, we have,

[tex]\frac{2\log _{10}\left(2x\right)}{2}=\frac{4}{2}[/tex]

Simplify, we have,

[tex]\log _{10}\left(2x\right)=2[/tex]

[tex]\mathrm{Apply\:log\:rule}:\quad \:a=\log _b\left(b^a\right)[/tex]

[tex]2=\log _{10}\left(10^2\right)=\log _{10}\left(100\right)[/tex]

[tex]\log _{10}\left(2x\right)=\log _{10}\left(100\right)[/tex]

When log have same base, we have,

[tex]\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\quad \Rightarrow \quad f\left(x\right)=g\left(x\right)[/tex]

We have,

[tex]2x=100[/tex]

Divide both side by 2, we have,

[tex]x=50[/tex]

Thus, For [tex]2log2x=4[/tex] , x = 50

Answer:

Option D is correct

[tex]y = 9.50x[/tex]

Step-by-step explanation:

Here, y represents total earnings in dollars and  x represents hours worked.

As per the statement:

To find which equation models the wages of someone who makes $9.50 an hour.

[tex]\text{"\$9.50 an hour"}[/tex] translated to 9.50x

then;

the total earning in dollars we get;

[tex]y = 9.50x[/tex]

Therefore, an equation [tex]y = 9.50x[/tex] models the wages of someone who makes $9.50 an hour

Riya is applying mulch at a rate of 0.025 m^3/m^2 after converting the original rate of 25,000 cm^3/m^2 to cubic meters per square meters.

To find out the rate at which Riya is applying mulch in m^3/m^2, you first need to convert the given value from cubic centimeters (cm^3) to cubic meters (m^3). We know that 1 m = 100 cm, so 1 m^3 = 100 cm * 100 cm * 100 cm = 1,000,000 cm^3. Therefore, we need to divide the given value by 1,000,000 to convert it from cm^3 to m^3. So, if Riya applies 25,000 cm^3 of mulch for every m^2 of garden space, this is equivalent to 25,000/1,000,000 = 0.025 m^3/m^2.

In conclusion, Riya is applying mulch at a rate of 0.025 m^3/m^2.

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By calculating the total earnings per day and earnings per hour for Worker A and Worker B, we deduce that Worker A earns more per day than Worker B but earns less per hour than Worker B.

To answer this question, we first need to calculate the total earnings per day and then the earnings per hour for both Worker A and Worker B.

For Worker A, the total earnings per day can be calculated as: 10 widgets/day * $8.10/widget = $81/day. For Worker B, the total earnings per day can be calculated as: 8 widgets/day * $8.40/widget = $67.20/day.

Therefore, we can see that Worker A earns more per day than Worker B.

Next, we calculate the earnings per hour. For Worker A, the earnings per hour amount to: $81/day ÷ 9 hours/day = $9/hour. For Worker B, the earnings per hour amount to: $67.20/day ÷ 7 hours/day = $9.60/hour.

Thus, Worker B earns more per hour than Worker A.

Given the calculations, the correct statement is B. Worker A earns more per day than Worker B but less per hour than Worker B.

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Answer:

Just took the test the answers are -6 and 4 for anyone else wondering! :)

Step-by-step explanation:

PS. Use the site called "Desmos" and type your function in the box and just find where it crosses the x axis!

You can minimize the risk from your investments by investing in a variety of investment options. The variety of your investments will reduce the overall risk from your investments by purchasing variety of investments in different sectors of the economy. Your investment portfolio should contain different types of investments so that the risk would be spread to these investments.

By investing in a variety of investment options will minimize the risk from your investments.

Investment is the dedication of money to purchase of an asset to attain an increase in value over a period of time

We need to find in which way we can  minimize the risk from your investments.

Before you begin to invest, think about what returns you’re realistically expecting and be clear on what your investment goals are.

The greater the potential returns, the higher the level of risk.  

The variety of your investments will reduce the overall risk from your investments by purchasing variety of investments in different sectors of the economy.

So one can minimize the risk from your investments by investing in a variety of investment options. Your investment should contain different types of investments so that the risk would be spread to these investments.

Hence, By investing in a variety of investment options will minimize the risk from your investments.

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The sum of the finite arithmetic series 26 + 29 + ... + 44 is 245. The sum of the series 7.6 + 6.3 + ... + (-1.5) is 24.4.

To solve these problems, we will use the formula for the sum of a finite arithmetic series, which is given by S = n÷2  × (a₁ + aₙ), where S represents the sum of the series, n is the number of terms, a₁ is the first term, and aₙ is the last term.

Problem 1:

The series is: 26, 29, 32, 35, 38, 41, 44. First, we find the number of terms (n). Since the common difference (d) is 3, we have n = (44 - 26)÷3 + 1 = 7. Now, apply the formula to find the sum: S = 7÷2 × (26 + 44) = 245.

Problem 2:

The series is: 7.6, 6.3, 5, 3.7, 2.4, 1.1, -0.2, -1.5. Here, d = -1.3 and n = 8. So the sum is: S = 8÷2 × (7.6 - 1.5) = 24.4.

Answer:

0.989

Step-by-step explanation:

A conservationist determines that a particular beach is eroding at a rate of 1.1% each year. When writing an explicit formula to represent the amount of beach remaining each year, the common ratio is 0.989

The required explicit formula to represent the amount of beach remaining each year will be y = a(0.011)^x

Exponential functions are inverse of trigonometry functions. The standard form of exponential function is expressed as:

y = ab^x

b is the rate

Given;

Rate = 1.1% = 0.011

The required explicit formula to represent the amount of beach remaining each year will be y = a(0.011)^x

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The measure of line segment EG is 13 cm.

Given that, F is between E and G, EF=7 and FG=6.

We need to find the measure of EG.

A line segment is a part of a line that has two endpoints and a fixed length. It is different from a line that does not have a beginning or an end and which can be extended in both directions. In this lesson, we will learn more about a line segment, its symbol, and the way to measure a line segment.

Now, EG=EF+FG

⇒EG=7+6=13 cm

Therefore, the measure of line segment EG is 13 cm.

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The required total bill would be $64.134 including of 18% tip.

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

Here,

According to the question,

To leave an 18% tip for a waiter on a $54.35 meal,
Total bill = 54.35 + 18% of 54.35
              = 54.35 [1 + 0.18]
              = 54.35 (1.18) = 64.134

Thus, the required total bill would be $64.134.

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Answer:

Effect of ingrediant R on freshness

Effect of Ingredient S on freshness

Effect of ingrediant T on freshness

Step-by-step explanation:

X Effect of ingrediant P on freshness

X Effect of ingrediant Q on freshness

* Effect of ingrediant R on freshness

* Effect of Ingredient S on freshness

* Effect of ingrediant T on freshness

Answer on edge

Answer:

a , b, c are only applicable in graph.

Step-by-step explanation:

Given : The function  [tex]f(x)=3sin(\frac{x}{4}+1)-\frac{1}{2}[/tex]

To find : Which of the following are correctly represented in the graph?

Solution :

General form of sin function is [tex]y=A sin(B(x-C)+D[/tex]

Where A is the amplitude

[tex]B=\frac{2\pi}{\text{Period}}[/tex]

D is the vertical shift.    

C is the horizontal shift or phase shift.

Comparing with the general form:      

[tex]f(x)=3sin(\frac{x}{4}+1)-\frac{1}{2}[/tex]

Transform little bit we get,

[tex]f(x)=3sin(\frac{1}{4}(x-(-4)))-\frac{1}{2}[/tex]

a. Amplitude is [tex]A=3[/tex]

It is correct.

b. Vertical shift is [tex]D= -\frac{1}{2}[/tex]

it is correct.

c. Horizontal shift [tex]C=-4[/tex]

It is correct.

d. Period is [tex]P=\frac{2\pi}{B}[/tex]

[tex]P=\frac{2\pi}{\frac{1}{4}}[/tex]    

[tex]P=8\pi[/tex]    

It is not correct .

Actual period in graph is [tex]2\pi[/tex]

e. The horizontal expansion or compression

It also not correct because period is not correct.

The expansion and compression depends on the period.

Therefore, a , b, c are only applicable in the graph.